Answers
Answer:
The diagonal or the inclined lines shows the changes in terms of temperature, and the horizontal lines shows the changing of phases.
Explanation:
hope it is useful
Related Questions
The Sun radiates energy at a rate of about 4×1026W. At what rate is the mass decreasing?
Answers
4.44×\(10^{9}\) kg/s is the rate at which the sun mass is decreasing.
The Sun radiates energy through a process called nuclear fusion, where hydrogen atoms combine to form helium, releasing a tremendous amount of energy in the process. According to Einstein's mass-energy equivalence principle (E=mc²), this energy release corresponds to a decrease in mass.
To calculate the rate at which the Sun's mass is decreasing, we can use the formula ΔE = Δmc², where ΔE is the change in energy, Δm is the change in mass, and c is the speed of light.
Given that the Sun radiates energy at a rate of 4×10^26 W, we can substitute this value into the equation as ΔE and solve for Δm.
ΔE = 4×10^26 W
c = 3×10^8 m/s (speed of light)
Using the equation ΔE = Δmc² and rearranging it, we get Δm = ΔE / c².
Substituting the values, we have:
Δm = (4×10^26 W) / (3×10^8 m/s)²
Evaluating this expression, we find that the rate at which the Sun's mass is decreasing is approximately 4.44×10^9 kg/s.
This calculation demonstrates that the Sun's mass is gradually decreasing as it continuously radiates energy into space, primarily through the process of nuclear fusion in its core.
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a
The
is a point that lies along a vertical line drawn from the suspension point of an object when the object is at
a standstill.
centripetal force
b. center of mass
c. equilibrium
d. center point
Answers
(L
In a series circuit, which of these is true?
A
B
C
D
There are exactly three resistors.
Voltage is shared across all resistors.
One resistor may burn out without affecting the other resistors.
There is more than one conductive path for the current to take
Answers
What’s the subject
The rainbow of visible colors in the electromagnetic spectrum varies continuously from the longest wavelengths (the reddest colors) to the shortest wavelengths (the deepest violet colors) our eyes can detect. Wavelengths near 655 nm are perceived as red. Those near 515 nm are green and those near 475 nm are blue. Calculate the frequency of light (in Hz) with a wavelength of 655 nm, 515 nm, and 475 nm.
Answers
The frequency of light with a wavelength of 655 nm is\(4.57 x 10^14 Hz\) and 515 nm is \(5.82 x 10^14\) Hz and 475 nm is\(6.31 x 10^14 Hz\)
The equation that links the speed of light to wavelength and frequency is
c = λν
Where, c = speed of lightλ = wavelengthν = frequency c is a constant of 2.998 x 10^8 m/s.
Calculating the frequency of light with a wavelength of
655 nm:λ = 655 nm = \(6.55 x 10^-7m\)
Using the above equation, we get
c = λνν = c/λ = \((2.998 x 10^8 m/s)/(6.55 x 10^-7m)ν = 4.57 x 10^14 Hz\)
Therefore, the frequency of light with a wavelength of 655 nm is 4.57 x \(10^14 Hz.\)
Calculating the frequency of light with a wavelength of 515 nm:λ = 515 nm = \(5.15 x 10^-7m\)
Using the above equation, we get
c = λνν = c/λ =\((2.998 x 10^8 m/s)/(5.15 x 10^-7m)ν = 5.82 x 10^14 Hz\)
Therefore, the frequency of light with a wavelength of 515 nm is 5.82 x \(10^14 Hz\).
Calculating the frequency of light with a wavelength of 475 nm:λ = 475 nm = \(4.75 x 10^-7\)m Using the above equation, we get
c = λνν = c/λ = \((2.998 x 10^8 m/s)/(4.75 x 10^-7m)ν = 6.31 x 10^14 Hz\)
Therefore, the frequency of light with a wavelength of 475 nm is 6.31 x \(10^14 Hz.\)
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What is the formula of energy
Answers
Answer:
Hey Buddy!
Explanation:
This is ur answer....
E = mc^2Hope it helps!
Brainliest pls!
Have a good day ~
Answer:
The formula for energy is E = mc²,where E is energy, m is mass, and c is the speed of light.
◉‿◉
An artillery shell is fired at a target 200 m above the ground. When the shell is 100 m in the air, it has a speed of 100 m/s. What is its speed when it hits its target?
Answers
The speed of the artillery shell when it hits its target is 100 m/s.
Given:
Initial vertical displacement (y) = 200 m
Vertical displacement at 100 m in the air (y') = 100 m
Final velocity in the vertical direction (vy') = 0 m/s (at the highest point of the trajectory)
Using the equation for vertical displacement in projectile motion:
y' = vy^2 / (2g),
where g is the acceleration due to gravity (approximately 9.8 m/s^2), we can solve for the initial vertical velocity (vy).
100 m = vy^2 / (2 * 9.8 m/s^2),
vy^2 = 100 m * 2 * 9.8 m/s^2,
vy^2 = 1960 m^2/s^2,
vy = sqrt(1960) m/s,
vy ≈ 44.27 m/s.
Now, since the horizontal motion is independent of the vertical motion, the horizontal speed of the shell remains constant throughout its trajectory. Therefore, the speed of the shell when it hits its target is 100 m/s.
Hence, the speed of the artillery shell when it hits its target is 100 m/s.
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can someone help me :(
Answers
Answer:
1. This is a speed graph.
2. The slope represents how much the item/ thing is moving at how much distance it moved and the minutes it takes it too move how much distance, but the slope is representing the decrease and increase of it.
3. Increasing, kind of rapidly going up since the slope is rising not falling.
A force of 525 N is applied to a stationary couch of mass 100 kg, where μs = 0.40 and μk = 0.32. What is the acceleration of the couch
Answers
Answer:
Approximately \(2.11\; \rm m\cdot s^{-2}\) (assuming that \(g = 9.81\; \rm m\cdot s^{-2}\), the floor is horizontal, and that the external force is applied horizontally.)
Explanation:
The mass of this couch is \(m = 100\; \rm kg\). Calculate the weight of the couch:
\(W = m \cdot g = 100\; \rm kg \times 9.81\; \rm m \cdot s^{-2} = 981\; \rm N\).
Assume that the floor is horizontal. The magnitude of the normal force between the floor and the couch would be equal to the size of the weight of this couch.
Therefore, the normal force between the floor and the couch would be \(N = 981\; \rm N\).
The first step is to find out whether the couch would move at all.
The question has provided two constants of friction: \(\mu_\text{s}\) (coefficient of static friction) and \(\mu_\text{k}\) (coefficient of kinetic friction.)
The coefficient of static friction applies when the couch is stationary relative to the floor: \(f_\text{s} = \mu_\text{s} \cdot N = 0.40\times 981\; \rm N \approx 313.92\; \rm N\). In other words, while the couch isn't moving, the maximum (horizontal) external force that friction could resist would be \(f_\text{s} = 313.92\; \rm N\).
Assume that the external force in this question is horizontal. The size of the external force (\(525\; \rm N\)) exceeds that of \(f_\text{s}\). Hence, the couch would start to move after the \(525\; \rm N\!\) external force is applied.
Once the couch starts to move, the coefficient of static friction would no longer be relevant. Instead, the coefficient of kinetic friction (\(\mu_\text{k}\)) would give size of the friction between the floor and the couch. The size of that friction would be \(f_\text{k} = \mu_\text{k} \cdot N = 0.32\times 981\; \rm N \approx 313.92\; \rm N\).
This friction would counteract the horizontal external force on the couch. Hence, the net force on the couch in the horizontal direction would be:
\(\begin{aligned}& F(\text{external}) - f_\text{k} \\ &\approx 525\; \rm N - 313.92\; \rm N \\ &\approx 211.08\; \rm N \end{aligned}\).
Apply Newton's Second Law of motion to find the acceleration of the couch:
\(\begin{aligned}a &= \frac{(\text{Net Force})}{m} \\ & \approx \frac{211.08\; \rm N}{100\; \rm kg} \approx 2.11\; \rm m \cdot s^{-2}\end{aligned}\).
In a ballistic pendulum, a spring pushes a ball from rest. It flies through the air and sticks in the base of a pendlum that swings upwards.
Given that the ball and pendulum reach a maximum angle of 45º, the pendulum is 30 cm long, the mass of the ball is 76 g, and the mass of the pendulum is 250 g, calculate the speed of the ball after it has left the spring but before it hits the pendulum. Do not include the units in your response.
Answers
Answer: EASY BROOOOOOOOOOOOOOOOOOOOOOOOO
Take a look inside your heart
Is there any room for me?
I would have to hold my breath
'Til you get down on one knee
Because you only want to hold me
When I'm looking good enough
Did you ever fault me?
Would you ever picture us?
Every time I pull my hair out
Was only out of fear
That'd you find me ugly
And one day you'll disappear
Because what's the point of crying?
It was never even love
Did you ever want me?
Was I ever good enough?
What is the speed of sound in air with a temperature of 25 degrees Celsius?
Answers
Answer:
346.18 m/s
Explanation:
Please give brainliest
One out of every 92 tax returns that a tax auditor examines requires an audit. If 50
returns are selected at random, what is the probability that less than 2 will need an audit?
O 0.0109
O 0.8971
O 0.9828
O 0.9999
Answers
Answer:
I think it's 0.8971-??correct me if I'm wrong because thats what my note said
Would you rather live but never be treated right or pass away and let others you love be treated right and have a good life?
Answers
Answer:I would say live but not be treated right.
Explanation: My opinion.
Answer:
I would rather pass away and let my love ones have a good life
Explanation:
1. Calculate the electric field due to a single +1nC point charge at a distance of lm, 2m, and 3m
Answers
Answer:
Approximately \(9.0\; \rm N \cdot C^{-1}\) at \(1\; \rm m\) from this charge, pointing away from the point charge.Approximately \(2.2\; \rm N \cdot C^{-1}\) at \(\rm 2\; \rm m\) from this charge, pointing away from the point charge.Approximately \(1.0\; \rm N \cdot C^{-1}\) at \(3\; \rm m\) from this charge, pointing away from the point charge.Assumption: there is no object between this point charge and the observer.
Explanation:
The electric field of a point charge is inversely proportional to the square of the distance from that point charge.
Let \(k\) denote Coulomb's constant (\(k \approx 8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-1}\).) Let the magnitude of that point charge be \(q\). At a distance of \(r\) from this charge, the electric field due to this charge would be:
\(\displaystyle E = \frac{k \cdot q}{r^{2}}\).
Convert the magnitude of the point charge in this question to standard units:
\(q = 1\; \rm nC = 10^{-9}\; \rm C\).
Apply that equation to find the magnitude of the electric field due to this point charge:
\(r = 1\; \rm m\):
\(\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(1\; \rm m)^{2}} \\ &\approx 9.0\; \rm N \cdot C^{-1}\end{aligned}\).
\(r = 2\; \rm m\):
\(\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(2\; \rm m)^{2}} \\ &\approx 2.2\; \rm N \cdot C^{-1}\end{aligned}\).
\(r = 3\; \rm m\):
\(\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(3\; \rm m)^{2}} \\ &\approx 1.0\; \rm N \cdot C^{-1}\end{aligned}\).
The direction of the electric field at a point is the same as the direction of a force from this field onto a positive point charge at this point.
Because the \((+1\; \rm nC)\) point charge here is positive, the electric field of this charge would repel other positive point charges. Hence, the electric field around this \((+1\; \rm nC)\!\) point charge at any point in the field would point away from this charge.
Which best describes most covalent compounds? resilient brittle cold warm
Answers
Answer:
B) brittle
Explanation:
This describes most covalent compounds.
Answer:
B.)
Explanation:
The atoms can be of the same element or different elements. In each molecule, the bonds between the atoms are strong but the bonds between molecules are usually weak. This makes many solid materials with covalent bonds brittle.
When acted upon by an unbalanced force, an object at rest will do what?
Answers
Answer:
When unbalanced forces act on an object at rest, the object will move. In the two examples mentioned earlier, the net force on the object is greater than zero. Unbalanced forces produced change in motion (acceleration) and the receivers of the forces - the piano and the rope - moved.
Which of the following is a disadvantage of hybridization? 1.offspring are genetic copies of the parent 2.offspring are stronger and larger than the parents 3.offspring have a combination of traits from both parents 4.offspring often have health problems and are sterile
Answers
Answer:
Explanation:
4 is right
give four example of fluid statics
Answers
Answer:
See the explanation below
Explanation:
First example
The water contained in a lake or tank is in equilibrium there is no movement of the fluid and the water exerts pressure on the bottom of the tank or lake.
Second example
A floating buoy that is on the high seas, the buoy is in static equilibrium and these developed forces allow the buoy not to sink.
Third example
A hydraulic press which uses the principle of pascal and the mechanical advantage due to the relation of areas, where applying a smaller force, you can obtain a much greater force, communicating the energy through a fluid such as oil.
Fourth Example
The atmospheric pressure, which depends on the height of a place above sea level, in this case the fluid is the air. Although the air cannot be seen, it exerts a pressure column on the bodies on the Earth's surface.
Which of the following could possibly be predicted? Earthquakes Landslides Foreshocks Volcanic eruptions
Answers
Answer:
Volcanic Eruptions
Explanation:
The volcano can start showing signs that it may be about to explode.
Answer:
Volcanic eruptions.
Explanation:
I had the same question on an assignment and I got it right.
A train leaving the station accelerates from a full stop at a rate of 0.250 meters per second squared for 45.0 seconds. How far does the train travel during this time?
Answers
Answer:
\(\boxed {\boxed {\sf 253 \ meters}}\)
Explanation:
We are asked to find the distance a train travels.
We are given the acceleration, initial velocity, and time. Therefore, we will use the following kinematic equation:
\(d=v_it+\frac{1}{2}at^2\)
The train starts at a full stop or a velocity of 0 meters per second. It accelerates at a rate of 0.250 meters per second squared for 45.0 seconds.
\(v_i\)= 0 m/s a= 0.250 m/s²t=45.0 sSubstitute the values into the formula.
\(d= (0 \ m/s)(45.0 \ s) + \frac{1}{2} (0.250 \ m/s^2)(45.0 \ s)^2\)
Multiply the first two numbers. The units of seconds cancel.
\(d= 0 \ m + \frac{1}{2} (0.250 \ m/s^2)(45.0 \ s)^2\)
Solve the exponent.
(45.0 s)² = 45.0 s *45.0 s = 2025 s²\(d= 0 \ m +\frac{1}{2} (0.250 \ m/s^2)(2025 \ s^2)\)
Multiply the numbers in parentheses. The units of seconds squared cancel.
\(d= 0 \ m +\frac{1}{2} (0.250 \ m/s^2 * 2025 \ s^2)\)
\(d= 0 \ m +\frac{1}{2} (0.250 \ m * 2025 )\)
\(d= 0 \ m + \frac{1}{2} (506.25 \ m)\)
Multiply by 1/2 or divide by 2.
\(d=0 \ m + 253.125 \ m \\d= 253.125 \ m\)
The original measurements of acceleration and time both have 3 significant figures, so our answer must have the same. For the number we found, that is the ones place. The 1 in the tenths place tells us to leave the 3.
\(d \approx 253 \ m\)
The train travel approximately 253 meters.
Convert 560 kilometers into miles
Answers
Answer:
347.967868
Explanation:
Electrons and protons travel from the Sun to the Earth at a typical velocity of 3.99 ✕ 105 m/s in the positive x-direction. Thousands of miles from Earth, they interact with Earth's magnetic field of magnitude 2.93 ✕ 10−8 T in the positive z-direction. Find the magnitude and direction of the magnetic force on a proton. Find the magnitude and direction of the magnetic force on an electron.
Answers
The magnitude of the magnetic force on a proton is 1.68 ✕ 10^−16 N, directed towards the negative y-direction. The magnitude of the magnetic force on an electron is also 1.68 ✕ 10^−16 N, but directed towards the positive y-direction.
Begin by using the formula for the magnetic force on a charged particle moving in a magnetic field:
F = q * v * B * sin(θ)
where F is the magnetic force, q is the charge of the particle, v is the velocity of the particle, B is the magnetic field strength, and θ is the angle between the velocity vector and the magnetic field vector.
For a proton, the charge is +e, where e is the elementary charge (1.6 ✕ 10^−19 C). The velocity of the proton is given as 3.99 ✕ 10^5 m/s in the positive x-direction. The magnetic field strength is 2.93 ✕ 10^−8 T in the positive z-direction.
The angle θ between the velocity vector and the magnetic field vector is 90 degrees since the velocity is perpendicular to the magnetic field.
Substituting the values into the formula, we get:
F_proton = (+e) * (3.99 ✕ 10^5 m/s) * (2.93 ✕ 10^−8 T) * sin(90°)
F_proton ≈ 1.68 ✕ 10^−16 N
Since the proton has a positive charge, the magnetic force is directed opposite to the direction of electron flow, which is in the negative y-direction.
Repeat the steps for an electron, but note that the charge is -e. The direction of the force on an electron will be opposite to that of a proton.
F_electron = (-e) * (3.99 ✕ 10^5 m/s) * (2.93 ✕ 10^−8 T) * sin(90°)
F_electron ≈ -1.68 ✕ 10^−16 N
The force on an electron is also 1.68 ✕ 10^−16 N, but directed towards the positive y-direction.
Remember to consider the proper units and take into account the directions of charge, velocity, and magnetic field when calculating the magnetic force on a charged particle.
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An object moving 20 m/s
experiences an acceleration of 4 m/s' for 8
seconds. How far did it move in that time?
Variables:
Equation and Solve:
Answers
Answer:
We are given:
initial velocity (u) = 20m/s
acceleration (a) = 4 m/s²
time (t) = 8 seconds
displacement (s) = s m
Solving for Displacement:
From the seconds equation of motion:
s = ut + 1/2 * at²
replacing the variables
s = 20(8) + 1/2 * (4)*(8)*(8)
s = 160 + 128
s = 288 m
How does sleep affect your ability to handle stress?
Answers
Answer: Stress can adversely affect sleep quality and duration, while insufficient sleep can increase stress levels. Both stress and a lack of sleep can lead to lasting physical and mental health problems.
Explanation:
Many report that there stress increases when the length and quality of their sleep decreases. When you do not get enough sleep, 21 percent of adults report feeling more stressed.
define capacitance of a capacitor and state its SIbunit
Answers
Answer: what I know that the unit is farad
Explanation:
Which of the filling is a fossil fuel?
Answers
4. A ski jumper starts at the top of a 400m high hill before skiing down to the bottom. The ski jumper has a mass of 75kg. If after 10 seconds the skier is going 15m/s how much kinetic energy would the skier have?
A. 16,875.0 J
B. 8,437.5 J
C. 112.5 J
D. 562.5 J
Answers
Answer:
B. 8,437.5 J
Explanation:
Given the following data;
Height = 400m
Mass = 75kg
Velocity = 15m/s
Time = 10 secs
To find the kinetic energy of the skier?
Kinetic energy can be defined as an energy possessed by an object or body due to its motion.
Mathematically, kinetic energy is given by the formula;
\( K.E = \frac{1}{2}MV^{2}\)
Where;
K.E represents kinetic energy measured in Joules. M represents mass measured in kilograms. V represents velocity measured in metres per seconds square.Substituting into the equation, we have;
\( K.E = \frac{1}{2}*75*15^{2}\)
\( K.E = 37.5*225\)
K.E = 8,437.5 Joules.
Rotation axis. Big disk on the bottom M2 and small disk on the top M1 or mass1. Angular frequency of M₁ is zero. M₂ initial angular frequency is Wi = 6π rad/s. Two objets both can spine freely in the axis someone is holding M1 and M2 is fixed on the axis. So M1 can slide down the axis and M₂ is fixed its rotating. Surface of M₂ is rough like sand paper but bottom of M1 surface is soft and it can rub on M₂ rough surface. then M1 disk is dropped on M2. then both disks are rotating and M1 cant slipe because of M2 rough surface. find wf final anular frequency of the system
Answers
The final angular frequency of the system is 3π/2 rad/s. Moment of inertia increased, frictional torque decreased angular momentum, conservation of energy equation used.
At the point when M1 is dropped onto M2, the two circles will be coupled together and pivot as a solitary framework. The complete precise force of the framework should be saved. At first, just M2 was turning with a precise recurrence of Wi = 6π rad/s, while M1 was very still, so the underlying rakish force was L = I2 * Wi, where I2 is the snapshot of dormancy of M2.
At the point when M1 is dropped onto M2, the snapshot of latency of the framework expands, so to preserve rakish energy, the precise recurrence of the framework should diminish. The last rakish recurrence can be tracked down utilizing the preservation of precise force condition: L = I1 * wf + I2 * wf, where I1 is the snapshot of dormancy of M1 and wf is the last rakish recurrence of the framework.
Since M1 is sliding on the unpleasant surface of M2, there is frictional power that goes against its movement. This frictional power creates a force on the framework, which makes the precise energy decline. The last precise recurrence can be determined utilizing the preservation of energy condition, which compares the underlying active energy of the framework to the last dynamic energy of the framework:
0.5 * I1 * 0^2 + 0.5 * I2 * (6π)^2 = 0.5 * (I1 + I2) * wf^2
Improving on the situation and tackling for wf, we get:
wf = 3π/2 rad/s
Thusly, the last rakish recurrence of the framework is 3π/2 rad/s.
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2. What does SCA stand for? (1 Point) Student Conservation Association h Securities Class Action Sudden Cardiac Arrest Solar Cell Array:',)
Answers
Answer:
sudden cardiac arrest
Explanation:
The compass of an airplane indicates that the airplane is heading north. The airplane is moving at an airspeed of 230 km/h. The wind is blowing east at 55 km/h.
1.What is the speed of the plane with respect to the ground?
2.How many degrees east of north is the plane’s velocity with respect to the ground?
Answers
Answer:
Explanation:
airspeed is speed with respect to air .
Let speed of airplane with respect to ground be V .
wind is blowing east at 55 km/h
airplane is heading north with speed V
Resultant of V and 55 km /h is 230 km/h
V² + 55² = 230²
V² = 52900 - 3025
V = 223.32 km/h
Let θ be the required angle
Tanθ = 55 / 223.32 = .246
θ = 14⁰ .
PLEASE HELP!! A TOTAL OF 50 POINTS WHEN GIVEN BRAINLIEST!!
Part A: Find the work done in lifting 1 L of blood (mass 1 kg ) from the foot to the head of a 1.9 m -tall person.
Part B: If blood circulates through the body at the rate of 5.0 L/min , estimate the heart's power output. (Your answer underestimates the power by a factor of about 5 because it neglects fluid friction and other factors.)
Answers
Explanation:
for part A:
work done is equal to change in potential energy which is
MgH
so the answer is 1.9 × 1 × 9.81
ANSWER FOR PART A: 18.639
FOR PART B:
power = flow rate x gh
= 5×9.81×1.9
93.195 watts