Which energy stored between plates of capacitor?

The Art Forger Who Tricked the Nazis:

Schrenker crashed his plane and made a fake call. He mail his friend. It is harder to create a fake ID now because of increased security features. With all of the security features, it is not an easy thing to master. To take a legitimate one.

Mr. Abagnale believes that all that is required to obtain a birth certificate is a child's death record from a courthouse. A birth certificate and some white-out on an apartment lease gets you a driver's license, which gets you a passport.

He despised what he was doing and became lonely. He was eventually imprisoned for everything.

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Answer:

371.2

Explanation:

Answer:

d

Explanation:

since it is much convenient since the email will not get lost and it's contents will not be forgotten

we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.

To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.

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Answer:

the process by which green plants and some other organisms use sunlight to synthesize foods from carbon dioxide and water. Photosynthesis in plants generally involves the green pigment chlorophyll and generates oxygen as a byproduct.

Explanation: You can put this in your own words. How? Well, try to find the most important stuff in your own words and write it down.

Answer:

12.0 grams of hydrogen would produce 12.0 grams of water.

Explanation:

The reaction between hydrogen and oxygen to form water can be represented as follows:

2H2(g) + O2(g) -> 2H2O(l)

From the equation, it can be seen that for every 2 grams of hydrogen, 1 gram of oxygen is required to produce 2 grams of water. Therefore, if 12.0 grams of hydrogen reacts with oxygen, 12.0/2 = 6.0 grams of oxygen would be required. This amount of oxygen would produce 2 * 6.0 = 12.0 grams of water.

Answer:

Explanation:

the grams of water produced= 44 grames  

Based on the ti_tration experiment shown, the volume of the NaOH ti_trant is determined from subtracting the final and initial volumes.

Ti_tration is a method in volumetric analysis in which a given volume of a solution of known concentration is used to determine the unknown concentration of another solution.

The ti_trant is the solution of known concentration.

The ti_trand is the solution of unknown concentration.

The volume of the ti_trant required is obtained as follows:

Therefore, in the the given titration, the volume of the NaOH ti_trant is determined from subtracting the final and initial volumes.

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Answer:

Initial NaOH volume - 0.05 mL

Final NaOH volume - 12.54 mL

Final Initial - 12.49 mL

Explanation:

It's because of Avagadro's number.

where

\(\\ \sf\longmapsto n=6.022\times 10^{23}\)

Answer:

C6H12O2 is the formula for Methyl pentanoate

Answer:

0.25M

Explanation:

The formula of concentration is c=m/M•V

c=1.85g/74g.mol•0.10L

c=0.25 M

Explanation:

tbh I really don't know but

B. The movement of basketball players on a court of the following is an example of quantization

The process of translating continuously infinite values to a more manageable collection of discontinuous finite values is known as quantization. It involves estimating real-world values with a digital representation that places restrictions on a value's precision and range in the context of simulation and embedded computing.

As a general guideline, quantize to the note you've played that is the shortest; for example, if the phrase contains both eighth and quarter notes, use eighth note resolution. Keep in mind that many rhythms may really employ triplets; if things aren't working out, you may try utilising a triplet resolution.

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Answer:

9.77 × 10⁹ molecules

Explanation:

Since the density of water is 1 g/cm³ = 1000 g/L

So, we find the mass of sea water in 250 mL = 0.250 L

We know density = mass/volume

mass = density × volume = 1000 g/L × 0.250 L = 250 g

Now we calculate the number of moles of sea water in 250 g, 250 mL of sea water.

number of moles n = mass of sea water,m/molar mass of water, M

molar mass of water, M = 18 g/moL

n = m/M = 250 g/18 g/mol = 13.89 mol

We now calculate the number of molecules present in the 250 mL of sea water.

n = N/N' where N = number of molecules, N' = avogadro's number = 6.022 × 10²³/mol

So,N =nN' = 13.89 mol × 6.022 × 10²³/mol = 8.36 × 10²⁴ molecules

Now, the volume of the ocean is 1.337 × 10¹⁸ m³ = 1.337 × 10¹⁵ L

Since the 250 mL sea water is mixed with the ocean, the number of molecules per liter is 8.36 × 10²⁴ molecules/1.337 × 10¹⁵ L = 6.25 × 10⁹ molecules/L

If we now take 250 mL out of the ocean, the number of molecules in this 250 mL will be 6.25 × 10⁹ molecules/L × 250 mL =  6.25 × 10⁹ molecules/L × 0.250 L = 9.77 × 10⁹ molecules.

So, we have 9.77 × 10⁹ molecules of pink molecules in the 250 mL after mixing in the ocean.

Answer:

2.59

x

1024

=

C

O

2

=

Explanation:

Answer: False

Explanation:

The solubility of the salts is affected by the temperature changes. 1. NaCl is least affected by temperature. 2. supersaturated. 3. 60 grams KBr. 4. Ethanol has both polar and non-polar groups. 5. Mixing and shaking.

A KBr solution with 90 gm solute in 100 grams of water at 50 degrees is classified as supersaturated. 60 grams of KBr are needed to make a saturated solution in 100 gm of water at 30 degrees.

Ethanol is a general solvent due to the presence of both the polar and the non-Polar groups. As a result, it is easier to dissolve both polar molecules and non-Polar molecules. The dissolving rate can be increased by mixing or shaking the solution. Also, the sugar dissolves faster in hot than cold tea.

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Answer:

d is right hope this helps:)

Answer:

The fourth one is correct ( D/ number 4).

The reason why a separate dropper is used for each stock solution in reagent bottle is so as to prevent contamination of the reagents.

This is referred to as a short glass or plastic tube fitted with a rubber bulb which are found in reagents and is used to measure liquids by drops in the laboratory.

It is best for a separate dropper to be used for each stock solution in reagent bottle so as to prevent contamination of the reagents. This helps to ensure that the experiments which are performed are very accurate which is therefore the reason why it was chosen as the correct choice.

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4.10×10⁻¹L/mol is the final result for the given calculation. Calculation, which converts one or more inputs within one or even more outputs.

Calculation, which converts one or more inputs within one or even more outputs or outcomes, is a conscious mathematical process. The phrase has several different meanings.

From the precise mathematical calculations required to use an algorithm to the nebulous heuristics used to determine a competition strategy or the likelihood that two individuals will have a successful relationship. For instance, multiplying 7 times 6 may be done using a straightforward method.

2.79×10⁻⁴× 3.3×10⁻³/7.69 ×10⁻⁵×2.89× 10⁻²

=9.2×10⁻⁷/ 22.2×10⁻⁷

=4.10×10⁻¹L/mol

Therefore, 4.10×10⁻¹L/mol is the final result.

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Answer:

\(C_3H_8+5O_2\rightarrow 3CO_2+4H_2O\)

Explanation:

Hello there!

In this case, when coming across combustion reactions whereby hydrocarbons as fuels are burnt in the presence of oxygen, the main products are said to be carbon dioxide and water in agreement to the breaking and rearrangement of bonds due to the collisions among molecules. Thus, for the reaction between propane and oxygen we have the following balanced reaction:

\(C_3H_8+5O_2\rightarrow 3CO_2+4H_2O\)

Best regards!

Answer:

protons and electrons

Explanation:

because two atoms of the same elements have different(mass)isotope so the answer is B

Answer:

D

Explanation:

The ratio of C6H12O6 (which will be referred to as "the carb") to oxygen is 1 to 6, so if we find an answer which has the same ratio, it should be chosen. A is 1:3
B is even worse with a ratio of the carb to oxygen of 1:2
C is the same as B, 1:2
D has a ratio of the carb to oxygen of 1:6, which is what we are looking for.

Initially, we will consider only solutions of a solid in ... (d) Calculate the volume (in mL) of 0.1065 M Sr(OH)2 required to titrate 25.00 mL of 0.2465 M.

:

Explanation:

Answer: 404.71 ML

Explanation:

We can use Boyle's Law to solve this problem, which states that the pressure and volume of a gas are inversely proportional at a constant temperature.

Boyle's Law equation: P1V1 = P2V2

Where:

P1 = initial pressure

V1 = initial volume

P2 = final pressure

V2 = final volume

Given:

P1 = 3.6 atm

V1 = 95 mL

P2 = 0.85 atm

We can rearrange the equation to solve for V2:

V2 = (P1V1)/P2

V2 = (3.6 atm * 95 mL)/(0.85 atm)

V2 = 404.71 mL

Therefore, the final volume of the gas is approximately 404.71 mL. Hopefully this helps gang fasho

We can use Boyle's law to solve this problem, which states that the pressure of a gas is inversely proportional to its volume when temperature and amount are held constant. The formula is:

P1V1 = P2V2

Where:

P1 = 3.6 atm (initial pressure)

V1 = 95 mL (initial volume)

P2 = 0.85 atm (final pressure)

V2 = ? (final volume)

Substituting the given values, we get:

(3.6 atm)(95 mL) = (0.85 atm)(V2)

Simplifying, we get:

V2 = (3.6 atm)(95 mL) / (0.85 atm)

V2 = 404.7 mL

Therefore, the final volume of the gas is 404.7 mL.

The molar mass of a gas with a density of 1.02 g/L at 2.13 atm and a temperature of 20°C is 47.9 g/mol.The molar mass of an element or compound is the mass of one mole of that substance. A mole is the SI unit for the amount of a substance.

It's defined as the amount of a substance that contains the same number of entities as there are atoms in 12 grams of carbon-12.Molar mass (M) = mass (m) ÷ amount of substance (n)So, M = m/n

Where m is the mass in grams and n is the number of moles. The unit of molar mass is grams per mole (g/mol).

The ideal gas law is used to calculate the molar mass of a gas. The ideal gas law is:P V = n R T,Where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

Convert the density to grams per liter: 1.02 g/L.

The density is mass/volume, thus 1.02 g/L means that 1 liter of the gas weighs 1.02 g.

This means that 1 mole of gas will occupy 22.4 L (at standard temperature and pressure, STP).Calculate the number of moles of gas using PV = nRT.P = 2.13 atmV = 22.4 L (at STP)R = 0.0821 L·atm/K·molT = 273.15 K + 20 K = 293.15 K

Thus, n = PV/RT = (2.13 atm × 22.4 L)/(0.0821 L·atm/K·mol × 293.15 K) = 0.973 mol

Calculate the molar mass (M) using M = m/n.m = density × volume = 1.02 g/L × 22.4 L = 22.848 gM = m/n = 22.848 g/0.973 mol = 23.5 g/mol Convert to units of grams per mole: 23.5 g/mol

The molar mass of a gas with a density of 1.02 g/L at 2.13 atm and a temperature of 20°C is 47.9 g/mol.

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The lethal dose and how ounces of soda in a can of soda is not given, however, the standard lethal dose and volume of soda are given as below:

Lethal dose: 10 gm of caffeine

The volume of soda per can =  12oz/can

Answer:

The correct answer is - 324.254 cans or round up to 325 cans. Ans.

Explanation:

Given:

2.57 mg caffeine / 1oz

12oz / 1can

Lethal dose: 10.0g or 10,000mg of caffeine

Solution:

Caffeine per soda can = (2.57 mg caffeine / 1oz) * (12oz / 1can) = 30.84 mg caffeine / 1can.

lethal dose would be in =

(10,000mg caffeine) * (1can / 30.84 mg caffeine) = 324.254 cans or round up to 325 cans. Ans.

The following are categorized into polar or nonpolar molecules:

a) Beryllium chloride (BeCl₂) is a nonpolar molecule. The Be-Cl bond is polar due to the electronegativity difference between beryllium and chlorine, but the molecule is linear with the two polar bonds pointing in opposite directions, resulting in a net dipole moment of zero.

b) Hydrogen sulphide (H₂S) is a polar molecule. The H-S bond is polar due to the electronegativity difference between hydrogen and sulfur, and the molecule has a bent shape, resulting in a net dipole moment that is not zero.

c) Sulphur trioxide (SO₃) is a nonpolar molecule. The S-O bonds are polar due to the electronegativity difference between sulfur and oxygen, but the molecule is trigonal planar with the three polar bonds pointing in different directions, resulting in a net dipole moment of zero.

d) Water (H₂O) is a polar molecule. The H-O bond is polar due to the electronegativity difference between hydrogen and oxygen, and the molecule has a bent shape, resulting in a net dipole moment that is not zero.

e) Trichloromethane (CHCl₃) is a polar molecule. The C-Cl bonds are polar due to the electronegativity difference between carbon and chlorine, and the molecule has a tetrahedral shape, resulting in a net dipole moment that is not zero.

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