When we double the quantities of reactants and products in a reaction, what happens to the value of the equilibrium constant?.

Explanation:

Thermosetting plastic are made up of long chain of molecules which are cross-linked and can be moulded into different shape and size.

Answer:

Hey!

THERMOSETTING PLASTICS are plastics or polymers that become IRREVESIBLY SET/RIGID when it has been heated and cooled...

Explanation:

This means that if you heat up a thermosetting plastic, you only have one chance to mould it or shape it before it cools down...if not you cannot correct this and will have to start again! Which WILL be sad!

AKA : THERMOSET

HOPE THIS HELPS!!

Answer:

by watching and writing down the information that is provided

Explanation:

Answer:

1.20 mole

Explanation:

1 Mole of Cu reacts to form  =  1 Mole of Hg

(1.20 mol × 1 mol) ÷ 1 mol

1.20 mol of Hg

Answer:

2C2H6(g)+7O2(g)→4CO2(g)+6H2O(l)

Explanation:

When ethane is burned in presence of oxygen, it produces carbon dioxide (CO_2)(CO2) and water (H_2O)(H2O) .

According to law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of reactants must be equal to the mass of products.

In order to get the same mass on both sides, the number of atoms of each element on product side must be same as the number of atoms of each element on reactant side.Thus the equations are balanced.

2C_2H_6(g)+7O2(g)\rightarrow 4CO_2(g)+6H_2O(l)2C2H6(g)+7O2(g)→4CO2(g)+6H2O(l)

Ionization energy increases as we move across the period from left to right.

order of ionization energy across period 2

Li < B < Be < C < O < N < F < Ne

What is Ionization energy?

Trends for Ionization energy

order of ionization energy across period 2

Li < B < Be < C < O < N < F < Ne

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Answer:

B.) Experimental

Explanation:

in an experimental investigation you have control over different variables you are testing so that makes this the most accurate answer.

The kind of investigation that allows for the control of variables is an experimental investigation.

In an experimental investigation, researchers manipulate or control certain variables while keeping others constant. This allows them to determine the cause-and-effect relationship between variables.

To conduct an experimental investigation, researchers typically follow these steps:

1. Formulate a hypothesis: A hypothesis is a testable statement that predicts the relationship between variables. It provides the basis for the experiment.

2. Identify variables: Variables are the factors or conditions that can be manipulated or measured in an experiment. In an experimental investigation, researchers typically have an independent variable and a dependent variable .

3. Control variables: In order to isolate the effect of the independent variable on the dependent variable, researchers need to control or keep constant other variables that could potentially influence the results. This ensures that any changes observed in the dependent variable can be attributed to the independent variable.

4. Design the experiment: Researchers design an experiment that allows them to manipulate the independent variable and measure the dependent variable. They may use control groups, randomization, and other techniques to minimize bias and ensure reliable results.

5. Collect and analyze data: Researchers collect data by conducting the experiment and measuring the dependent variable. They then analyze the data using statistical techniques to determine if there is a significant difference between groups or conditions.

By controlling variables in an experimental investigation, researchers can draw valid conclusions about the relationship between the independent and dependent variables. Thus, the correct answer is experimental investigations.

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Answer:

To test if a lipid is saturated or unsaturated iodine is added. If the iodine changes from brown to clear the lipid is unsaturated. If the iodine does not change colors the lipid is saturated. To test for the degree of lipid saturation iodine is added to the unsaturated lipid.

Explanation:

Induced dipole intermolecular force is mainly responsible for the boiling point difference between cyclohexane and decalin. Correct answer: letter D.

The difference in boiling point between cyclohexane and decalin is due to the fact that decalin has a longer chain of carbon atoms and therefore has a larger surface area. This larger surface area allows for more intermolecular forces to be formed, specifically induced dipole forces.

These dipole forces are created when the electrons of one molecule are attracted to the nucleus of another molecule, giving rise to a temporary dipole. This attraction between molecules is much stronger than the London dispersion forces that exist in cyclohexane, thus creating a higher boiling point in decalin.

Which intermolecular force do you think is primarily responsible for the difference in boiling point between cyclohexane and decalin?

A) Dipole-Dipole

B) Hydrogen bonding

C) Covalent

D) Induced Dipole

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If the pressure contributed by CH4 is 111.2 atm, the pressure due to NH3 would be 109.1 atm.

To solve the problem, we can use the ideal gas law equation:

PV = nRT

where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature.

We need to find the pressure due to NH3, so let's start by finding the number of moles of each gas:

Now, we can use the pressure contributed by CH4 to find the total pressure:

Ptotal = PCH4 + PNH3

111.2 atm = PCH4 + PNH3

Finally, we can solve for the pressure due to NH3:

Therefore, the pressure due to NH3 is 109.1 atm.

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The standard enthalpy change for reaction (3) is 117.1 kJ.

The standard enthalpy change for reaction (3) can be calculated by using the enthalpy changes of reactions (1) and (2) and applying Hess's Law.

To do this, we need to manipulate the given equations so that the desired reaction (3) can be obtained.

First, we reverse reaction (1) to get the formation of C2H4(g) from C2H6(g):

C2H4(g)C2H6(g) ΔH° = -52.3 kJ

Next, we multiply reaction (2) by 2 and reverse it to obtain 2 moles of C2H6(g) reacting to form 3 moles of H2(g):

2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

Now, we add the two modified equations together:

C2H4(g)C2H6(g) ΔH° = -52.3 kJ
2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

When adding these equations, the C2H6(g) on the left side cancels out with the C2H6(g) on the right side, leaving us with the desired reaction (3):

C2H4(g) + H2(g)C2H6(g) ΔH° = -52.3 kJ + 169.4 kJ = 117.1 kJ

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Answer:

which parts electrical charges you are asking ??

A. The order of nucleotide bases within a gene determines the arrangement of amino acids in a protein. The genetic code, which is made up of the bases in DNA, dictates the order in which the amino acids will be combined to form proteins.

The DNA nucleotide base sequence is translated into a complementary sequence of bases in mRNA during the protein production process. Then, using the mRNA as a template, a protein chain is put together, with each triplet of bases (known as a codon) designating a certain amino acid. The ribosomes, which are in charge of protein synthesis, assemble the amino acids in the order dictated by the mRNA rather than choosing the amino acid sequence of a protein. Although necessary for protein synthesis, the availability of amino acids in the cell cytoplasm does not affect the precise amino acid sequence of a protein.

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Answer 12.2g is the answer

Answer:

Explanation:

i think c

Answer:

17000 joules.

Explanation:

Explanation:

With knowledge of the specific heat capacity of a substance, its mass, and the temperature change, we can convert this to the energy required for this temperature change using:

ΔH=mCΔT, where

ΔH=change in enthalpy (J)

m= mass of substance being heated (g) i.e. water in this question

C= specific heat capacity (J/g°C)

ΔT= change in temperature (°C)

We know mass=65g and ΔT=76°C−12°C=64°C

The specific heat capacity of water is 4.18J/g°C

Therefore, ΔH=65g⋅4.18Jg°C⋅64°C

=17388.8J

=17000J (2 significant figures)

Answer:-2.0

Explanation:

If an automobile slows from 26 m/s to 18 m/s in a period of 4.0 s, the average acceleration is 2.0

Acceleration can be defined as  the vector quantity  and has both magnitude and direction, it is a second derivative of position with respect to time  and it is the first derivative of velocity with respect to time.

The change in the velocity of an object called as acceleration and the Velocity is a vector quantity with both magnitude and direction.

Acceleration can be a change in the direction of an object. For example, while pressing the accelerator of car makes the car go faster.

Acceleration(a)= final velocity(v) –initial velocity(u) time(t)

The velocity at the beginning was ‘u′, and the increased to velocity, ‘v′,  after "t"  time .

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Answer:

\(\boxed {\boxed {\sf 6.4 \ atm}}\)

Explanation:

We are asked to find the pressure of a gas in a can given a change in temperature. We will use Gay-Lussac's Law, which states the pressure of a gas is directly proportional to the temperature. The formula for this law is:

\(\frac {P_1}{T_1}= \frac {P_2}{T_2}\)

Initially, the gas in the aerosol can has a pressure of 3.10 atmospheres at a temperature of 25 degrees Celsius.

\(\frac { 3.10 \ atm}{25 \textdegree C}=\frac{P_2}{T_2}\)

The temperature is increased to 52 degrees Celsius, but the pressure is unknown.

\(\frac { 3.10 \ atm}{25 \textdegree C}=\frac{P_2}{52 \textdegree C}\)

We are solving for the new pressure, so we must isolate the variable \(P_2\). It is being divided by 52 degrees Celsius. The inverse operation of division is multiplication, so we multiply both sides of the equation by 52 °C.

\(52 \textdegree C *\frac { 3.10 \ atm}{25 \textdegree C}=\frac{P_2}{52 \textdegree C} * 52 \textdegree C\)

\(52 \textdegree C *\frac { 3.10 \ atm}{25 \textdegree C}=P_2\)

The units of degrees Celsius cancel.

\(52 *\frac { 3.10 \ atm}{25}=P_2\)

\(52 *0.124 \ atm = P_2\)

\(6.448 \ atm = P_2\)

The original values of pressure and temperature have 2 and 3 significant figures. Our answer must be rounded to the least number of sig figs, which is 2. For the number we calculated, that is the tenths place. The 4 in the hundredth place tells us to leave the 4 in the tenths place.

\(6.4 \ atm \approx P_2\)

The gas pressure in the can at 52 degrees Celsius is approximately 6.4 atmospheres.

Answer:

C. The dissolving reaction of A was exothermic and the dissolving of reaction B was endothermic

Explanation:

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The names of the compounds differ by the type of metal present in them, which are Calcium (Ca) and Cadmium (Cd)

From the question,

We are to determine the how the name of CaS differ from the name of CdS

First, we will determine the identities of the elements in the given compounds

Ca represents calcium

and

S represents sulfur

∴ The compound is named Calcium sulfide

Cd represents the element Cadmium

and

S represent the element Sulfur

∴ The compound is named Cadmium sulfide

Hence, the names of the compounds differ by the type of metal present in them, which are Calcium (Ca) and Cadmium (Cd)

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The temperature, at which it occupies 15.0 litres at the same pressure is,  269°C.

A temperature is a unit used to represent hotness or coolness on any of a number of scales, including Fahrenheit and Celsius. According to temperature, heat energy will naturally move from a hotter (body with a higher temperature) to a colder (body with a lower temperature) (one at a lower temperature).

The definition of pressure is "force applied per unit area." It can be calculated mathematically using P=FA, where F is the force acting perpendicular to surface area A. The pascal (Pa), or one newton per square meter (N/m²), is the common unit of pressure.

Calculations:

At the same pressure,

volume is directly proportional to temperature.

i.e., V ∝ T

⇒V₁/V₂ = T₁/T₂

here, V₁ = 5.5 litres , T₁ = 25°C = 298K

V₂ = 10 litres, T₂ = ?

now, 5.5/10 = 298/T₂

⇒T₂ = 298 × 10/5.5 ≈ 542 K

Temperature in degree Celsius = 542 - 273 = 269°C

Hence, the temperature, at which it occupies 15.0 litres at the same pressure is,  269°C.

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Answer:

The extraction is done by electolysis but first the aluminium oxide must be melted so that electricity can pass through it...The use of molten cryolite as a solvent reduces some of the Energy

costs involved in extracting aluminum by allowing the ions in aluminum oxide to move freely at low temperature ..

The final molarity is 74.03 mM.

What is molarity?
Molar concentration, also known as molarity, amount concentration, or substance concentration, is a unit used to describe the amount of a substance in a solution expressed as a percentage of its volume. The number of moles per litre, denoted by the unit symbol mol/L as well as mol/dm3 in SI units, is the most widely used unit for molarity in chemistry. One mol/L of a solution's concentration is referred to as one molar, or 1 M.

Molar mass of KBr = 119.00 g/mol
Mass of KBr = 1.76 g
Moles of KBr = 1.76 g / 119.00 g/mol = 0.0148 mol
Initial molarity of AgNO3 = 74.0 mM
Molarity of AgNO3 = 74.0 mM = 74.0 mol/L
Volume of AgNO3 = 350 mL = 0.35 L
Moles of AgNO3 = 74.0 mol/L x 0.35 L = 25.9 mol
Total moles in solution = 0.0148 mol KBr + 25.9 mol AgNO3 = 25.91 mol
Total volume of solution = 0.35 L
Final molarity of KBr = 25.91 mol KBr / 0.35 L = 74.03 mM

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Answer:

8moles

Explanation:

1 mole of N2 gives 2 moles of NH3

4 moles of N2 gives>( 4*2)/1

= 8moles of NH3

The electron-pushing mechanism for the decarboxylation reaction involves the addition of three curved arrows. The reaction starts with a carboxylic acid, which undergoes a proton transfer to form a carboxylate anion. The carboxylate anion then experiences nucleophilic attack by a base, leading to the formation of a cyclic intermediate. The cyclic intermediate undergoes ring opening, resulting in the expulsion of carbon dioxide and the formation of a new bond. The electron-pushing mechanism helps illustrate the movement of electrons throughout the reaction, highlighting the formation and breaking of bonds.

In the decarboxylation reaction, we start with a carboxylic acid, which is represented by the structure: C(O)OH. The first step involves the proton transfer, where a curved arrow is drawn from one of the lone pairs on the oxygen of the carboxylic acid to the hydrogen atom attached to the same oxygen. This proton transfer leads to the formation of a carboxylate anion, depicted as C(O)O-.

The second step involves nucleophilic attack by a base. Draw a curved arrow from the lone pair on the oxygen of the carboxylate anion to the carbon atom adjacent to the carbonyl group. This movement of electrons results in the formation of a cyclic intermediate. The cyclic intermediate is represented by a ring structure formed by the interaction between the carbon atom and the oxygen atom of the carboxylate group.

The third step involves ring opening. Draw a curved arrow from the carbon atom of the cyclic intermediate to the oxygen atom of the carboxylate group. This movement of electrons breaks the bond between the carbon atom and the oxygen atom, resulting in the expulsion of carbon dioxide (CO2). Simultaneously, a new bond is formed between the carbon atom and the neighboring atom (not specified in the given question).

The overall reaction can be summarized as the decarboxylation of a carboxylic acid, leading to the removal of a carbon dioxide molecule and the formation of a new bond. The electron-pushing mechanism helps visualize the flow of electrons during the reaction, highlighting the formation and breaking of bonds at each step.

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Answer:

The correct answer is - due to the movement of plates it is relocated.

Explanation:

Antarctica is a very cold part of the earth, it is so cold that there is no growth of trees or such vegetation. Even though there are no or less vegetation scientists found fossils of the trees.

It is relocated from the north where the conditions were warmer and easy for tree growth. It is then moved due to plate movements to the south pole. This is the reason behind the fossils scientist found.

Two precautions to avoid protonation or reaction with acidic compounds are ensuring anhydrous conditions and controlling pH and temperature.

To avoid the problem of protonation or reaction with acidic compounds like water, alcohols, and carboxylic acids during a specific reaction, two precautions that can be taken are:

1. Anhydrous conditions: One precaution is to ensure anhydrous conditions, meaning that any water or moisture is removed or excluded from the reaction environment. This can be achieved by using drying agents such as molecular sieves, desiccants, or using techniques like vacuum or inert gas purging. By keeping the reaction environment dry, the presence of water is minimized, reducing the chances of unwanted protonation or reaction with acidic compounds.

2. Controlled pH and temperature: Another precaution is to carefully control the pH and temperature of the reaction. By maintaining the reaction at a specific pH range and temperature, the reactivity of acidic compounds can be minimized. This can involve using suitable buffers or adjusting the pH with weak bases to maintain a less acidic environment. Additionally, controlling the temperature within a suitable range can help avoid excessive protonation or reaction with acidic compounds.

By implementing these precautions, it is possible to minimize the unwanted protonation or reaction with acidic compounds, allowing for a more controlled and specific reaction.

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Answer:

Carbon is released back into the atmosphere when organisms die, volcanoes erupt and even when fossils are buried