When the line of action of an external force acts directly through the axis of rotation, which of the following must be true: The moment arm of the external force is at its maximum length this external force is a centric force an increase in the magnitude of this external force will increase its moment of force (i.e. torque) applied None of the above answers are correct
Answers
When the line of action of an external force acts directly through the axis of rotation, the following must be true: this external force is a centric force.
A centric force is a force that passes through the center of mass of an object, and when the line of action of an external force acts directly through the axis of rotation, it implies that the force is acting at the center of mass of the object.
Hence, the force is a centric force.
Below are explanations for the other options:
The moment arm of the external force is at its maximum length:
When the moment arm of the external force is at its maximum length, the force has the greatest effect in rotating an object, but this is not necessarily true when the line of action of an external force acts directly through the axis of rotation.
An increase in the magnitude of this external force will increase its moment of force (i.e. torque) applied:
The moment of force applied by an external force is given by the product of the force and the perpendicular distance from the axis of rotation to the line of action of the force.
However, when the line of action of an external force acts directly through the axis of rotation, the perpendicular distance is zero, and hence, the moment of force is also zero.
None of the above answers are correct:
The correct option is that this external force is a centric force.
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Related Questions
Q1 (a) Identify and explain by giving an example what are the factors that consequence the ability of industrial plant functionality? (b) Illustrate the relation of manufacturing in terms of technology and economy aspects. (c) For a new plant, the management have decided to produce at least 50,000 units of products annually. On the other hand, the plant will produce variety types of products for different purposes. There were five processes involved to produce the product. As a Plant and Process Engineer, you were requested to propose an appropriate plant layout for the production purposes. Your proposal should be supported by: i. The illustration of the layout. ii. The explanation of the production operation based on the process involved. iii. The justification of your decision.
Answers
Factors influencing industrial plant functionality include technology, personnel, materials, and plant layout. Technology and economy intertwine in manufacturing, with technology enabling efficient production and the economy driving demand.
Technology availability dictates the processes and methods employed in the plant, and trained personnel ensure smooth operation. Reliable material supply enables steady production. In the economy-technology relation, technological advancements enhance manufacturing efficiency and product quality, thus improving economic returns. For the new plant, considering the varied products and multiple processes, a Cellular layout, grouping similar processes together, is proposed. This layout enhances flexibility and efficiency, critical for diverse production. The production operation follows a logical, efficient sequence per each product group.
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The purification of hydrogen gas is possible by diffusion through a thin palladium sheet. Calculate the number of kilograms of hydrogen that pass per hour through a 8.2-mm-thick sheet of palladium having an area of 0.13 m2 at 500°C. Assume a diffusion coefficient of 2.9 x 10-8 m3/s, that the concentrations at the high- and low-pressure sides of the plates are 2.8 and 0.67 kg/m3 of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained. M= i kg/h
Answers
6.77 kg/h of hydrogen will pass through the palladium sheet at steady-state conditions, based on the given diffusion coefficient, concentrations, and area.
Using Fick's Law of diffusion, we can calculate the mass flow rate of hydrogen through the palladium sheet:
J = -D (dC/dx)
where J is the flux of hydrogen, D is the diffusion coefficient, and dC/dx is the concentration gradient across the sheet.
The concentration gradient can be expressed as:
dC/dx = (C1 - C2) / L
where C1 is the concentration of hydrogen on the high-pressure side of the sheet, C2 is the concentration on the low-pressure side, and L is the thickness of the sheet.
Plugging in the given values, we get:
dC/dx = (2.8 - 0.67) / (8.2 x 10⁻³ m) = 267.07 kg/m⁴
J = - (2.9 x 10⁻⁸ m³/s) x (267.07 kg/m4) = -7.79 x 10⁻⁶ kg/m²s
To find the mass flow rate, we need to multiply the flux by the area of the sheet:
M = - (7.79 x 10^-6 kg/m²s) x (0.13 m²) x (3,600 s/h) = 3.13 kg/h
Therefore, the number of kilograms of hydrogen that pass per hour through the palladium sheet is 3.13 kg/h.
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.Which layer deals with how humans interact with computers?
Software
Operating System
Hardware
User
Answers
The layer that deals with how humans interact with computers is the user layer.
This layer focuses on the interface between the user and the computer system, including the design and usability of the software and hardware components. The user layer involves the use of input devices, such as keyboards and mice, to interact with the computer system and output devices, such as screens and printers, to receive information from the system. The user layer also includes the software applications that are designed to meet the needs of the user, such as productivity software, games, and communication tools. The software applications in the user layer are designed with the user in mind, providing an easy-to-use interface and intuitive features.
Furthermore, the user layer also deals with the user experience, including factors such as accessibility, ease of use, and user satisfaction. The goal of the user layer is to create a seamless and efficient interaction between the human user and the computer system. In conclusion, the user layer is an essential component of the computer system, as it deals with how humans interact with computers, and it is essential to ensure that the software and hardware components are designed with the user in mind.
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what is the preferred method of bleeding the brake system
Answers
It keeps the brake system under pressure and is the best brake bleeding method for flushing dirty fluid from the system
TWO students are discussing quality multimeters fuses.
Student A states fuses used in higher category meters
are sometimes filled with a sand type material that will
change to glass when exposed to high temperatures
(overload situations). Student B states ceramic fast blow
fuses have a much higher "breaking capacity" or the
fuse's ability to interrupt current flow without being
destroyed or arched over. Which student is wrong
Answers
Answer: 2nd Student (Ceramic student)
Explanation: Ceramic is reliable for fuses more than the paragraph in this states they are. Hence it would be the 2nd student who is wrong.
A town has two fire engines operating independently. The probability that a
specific engine is available when needed is 0.96.
a. What is the probability that neither is available when needed?
b. What is the probability that a fire engine is available when needed?
Answers
If town has two fire engines operating independently. The probability that a specific engine is available when needed is 0.96. The probability that neither is available when needed is 0.0016 and the probability that a fire engine is available when needed is 0.9984 .
Probability
A. Probability that neither is available
Probability that a fire engine is unavailable when needed= 1−0.96
Probability that a fire engine is unavailable when needed=0.04
Hence,
P (A’ ∩ B’) = P (A’) P(B’)
P (A’ ∩ B’) =0.04×0.04
P (A’ ∩ B’) =0.0016
b. Probability of fire engine available when needed
P(atleast one engine is available )=1−P(Engine unavailable )
Or
1 – P(A’ ∩ B’) = 1 – P (A’) P(B’)
1 – P(A’ ∩ B’)= 1− (0.04×0.04)
1 – P(A’ ∩ B’)= 1−0.0016
1 – P(A’ ∩ B’)= 0.9984
Therefore If town has two fire engines operating independently. The probability that a specific engine is available when needed is 0.96. The probability that neither is available when needed is 0.0016 and the probability that a fire engine is available when needed is 0.9984 .
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QUICKK PLEASE WILL MARK BRAINIEST
When the pressure plate pushes down on the clutch disc, what initially happens?
Answers
Answer:
it gives pressure this makes it stay where it has to be and lock it
Explanation:
yan llng alam ko
Discuss on forced convection heat transfer with real examples.
Answers
Answer:
forced convection
Explanation:
When a fan, pump or suction device is used to facilitate convection, the result is forced convection. Everyday examples of this can be seen with air conditioning, central heating, a car radiator using fluid, or a convection oven.
Using the table below, draw the network diagram and answer the questions. 1. How many paths are in the network, and what are they? (1 mark) 2. What is the critical path and its duration? (1 mark) 3. What is the float on activity U? (1 mark) 4. What is the impact to the project if activity B takes three weeks longer than planned? (1 mark) Activity Predecessor Estimate in Weeks Start - 0 C Start 6 B Start 4 P Start 3 A C,B,P 7 U P 4 T A 2 R A 3 N U 6 End T,R,N 9 Question 2 Your group was tasked to produce a research manual and listed the activities that must be completed, and the time estimates for each activity as shown in the table below: Note: You are required to use the last non-zero digit of your group leader’s student ID number for A,B,C,D,E. (where relevant based on your group size. Crash value cannot be ‘0’. Thus use the next bigger non zero digit from your ID number. Activity Immediate Predecessor Time (weeks) Cost (RM) Normal Crash Normal Crash A - a *a-1 700 800 B - 2 or b *b-1 1200 1900 C A 8 or c *c-2 1600 2200 D B 5 or d *d-2 1500 2300 E C 6 or e *e-2 2000 2800 F C,D 6 5 800 1200 G E,F 2 1 500 1000 (a) Draw a project network diagram. (1 mark) (b) Find the critical path.(1 mark) (c) What is the normal expected project completion time? (1 mark) (d) What is the total project cost using the normal time? (1 mark) (e) If the project is to be completed 2 weeks faster, determine which activities to crash at a minimum cost. What additional cost is incurred? What is the total cost? (3 marks) Question 3 Diddy Corp would like to develop an order quantity and reorder policy that would minimize their total costs of their inventory of printers. The probability distribution for demand for ace drill on a daily basis is shown below. Demand 0 1 2 3 4 5
Answers
The number of paths in the network is six.
The paths are:
C - A - T - N - EndC - A - T - R - N - EndC - B - P - U - N - EndC - B - P - U - T - R - N - EndC - B - P - A - T - N - EndC - B - P - A - T - R - N - End
2. The critical path is C - A - T - N - End with a duration of 24 weeks.
3. The float on activity U is 1 week.
4. If activity B takes three weeks longer than planned, it will affect the duration of path 3 and the entire project. It will elongate the project duration to 29 weeks.
2. b) The critical path is A-C-E-G with a duration of 18 weeks.
(c) The normal expected project completion time is 18 weeks.
(d) The total project cost using normal time is RM 7600.
(e) To complete the project two weeks faster, activities C and E can be crashed for the minimum cost.
The additional cost incurred will be RM 600.
The total cost is RM 8200.
3 The inventory cost that will minimize the total cost of inventory is obtained using the formula,
TAC = IC + OC + HCS
Where TAC
= Total Annual CostIC = Inventory CostOC = Ordering CostHCS = Holding and Carrying Cost.
The probability distribution is shown below. Demand 0 1 2 3 4 5Probability 0.20 0.15 0.25 0.20 0.10 0.10
To determine the optimal order quantity and reorder policy that would minimize total cost,
the EOQ (Economic Order Quantity) model will be used.
The EOQ can be determined using the formula,
Q = √((2DCO)/CH')
Where Q = Economic Order Quantity
D = Demand'
C0 = Cost per order
H = Holding cost
C = IC per unit
Let’s assume the cost per unit, C = RM 500,
the holding cost, H = 0.2,
and demand, D = 3 units per day.
Hence,CO = RM 800 (C0 = Cost per order, which is the same as ordering cost)
Then,Q = √((2 x 3 x RM 800)/RM 100)Q = 24 units per order
Then, the reorder level can be determined using the formula,
ROL = d * LWhere L = Lead time
ROL = 3 x 5 = 15 units
The total annual cost can be determined by substituting the values into the formula,
TAC = IC + OC + HCS
where IC = 0.5 x RM 500
= RM 250OC
= (365/EOQ) x C0OC
= (365/24) x RM 800OC
= RM 12133.33HCS
= (Q/2) x H x dHCS
= (24/2) x 0.2 x 3HCS
= RM 7.20
TAC = RM 250 + RM 12133.33 + RM 7.20TAC = RM 12390.53
Hence, the order quantity that will minimize the total cost of inventory is 24 units.
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does chlorination of chlorobenzene require the use of a lewis acid? Explain why or why not.
Answers
The chlorination of chlorobenzene does require the use of a Lewis acid because the chlorination reaction involves the substitution of a chlorine atom for a hydrogen atom on the benzene ring, and this process requires activation of the chlorobenzene molecule.
A Lewis acid is needed to coordinate with the chlorine molecule, increasing its electrophilicity and making it more reactive towards the benzene ring. The Lewis acid also helps to stabilize the intermediate carbocation that is formed during the reaction. Without a Lewis acid, the chlorination of chlorobenzene would be much slower and less efficient. Chlorination of chlorobenzene involves the substitution of one or more hydrogen atoms on the benzene ring with chlorine atoms. This reaction is typically carried out using a chlorinating agent such as iron(III) chloride (FeCl3) or aluminum chloride (AlCl3) as a catalyst.
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Q1: You have to select an idea developing an application like web/mobile or industrial, it should be based on innovative idea, not just a simple CRUD application. After selecting the idea do the following: 1) How your project will be helpful and what problem this project addresses. (10-Marks) 2) Write down the requirements. (10Marks) 3) List the functional and non-functional requirements of your project. (10marks) 4) Which process model you will follow for this project and why? (10marks) 5) Draw the Level 0, and level 1 DFD of your application. (20marks)
Answers
Answer:
Creating an app is both an expression of our self and a reflection of what we see is missing in the world. We find ourselves digging deep into who we are, what we would enjoy working on, and what needs still need to be fulfilled. Generating an app idea for the first time can be extremely daunting. Especially with an endless amount of possibilities such as building a church app.
The uncertainty has always spawned a certain fear inside creators. The fear of creating something no one will enjoy. Spending hundreds of dollars and hours building something which might not bring back any real tangible results. The fear of losing our investment to a poor concept is daunting but not random. But simple app ideas are actually pretty easy to come by.
Great app idea generation is not a gift given to a selected few, instead, it is a process by which any of us are able to carefully explore step by step methods to find our own solution to any problem. Whether you are a seasoned creator or a novice, we have provided a few recommendations to challenge and aid you as you create your next masterpiece.
if I am right then make me brainliest
11. Two technicians are discussing tire rotation. Technician A says that you always follow the tire-rotation procedure outlined in the owner's manual or online service information. Technician B says that the modified "X" rotation pattern is seldom used. Which technician is correct? A. Both Technicians A and B B. Technician B only C. Neither Technician A nor B D. Technician A only
Answers
Answer:
Technician A
Explanation:
Technician A is correct. Technician B is wrong, as different drive vehicles (FWD, RWD, AWD, 4WD) each require a certain rotation for optimal tire wear.
Pleas help. The dimensions of this figure are changed so that the new surface area is exactly 12 what it was originally. What is the new surface area? Enter your answer as a decimal in the box. Answer. Yd²
Answers
Decision Variables
Parameters/Data
The Objective Function (in English words)
The Constraints (in English words)
Design Situation A
A contractor can sell several classes of concrete at a different price per-ton for each class. The materials specification for each class of concrete allows the percentage by weight of cement, sand, and gravel to range between certain upper and lower bounds. The contractor knows the unit cost (cost per-pound) to the company for each of the three components of concrete, and how much of each component that is available for the company to purchase. The amount of concrete of each type that the contractor can sell is limited but known. (Hint: This problem has a maximization objective function, not minimization.)
Answers
Decision variables are the values that the decision maker can control and choose in a decision-making problem. Parameters are fixed values that affect the outcome of a decision-making problem but are not under the control of the decision maker.
What are the Decision variables, Parameters, Objective Function and Constraints in the given problem?
Decision Variables:
Number of tons of each class of concrete to be sold.Parameters/Data:
Price per ton for each class of concrete.Upper and lower bounds for the percentage by weight of cement, sand, and gravel for each class of concrete.Unit cost (cost per pound) of cement, sand, and gravel.Available amount of cement, sand, and gravel for the company to purchase.Limitations on the amount of concrete of each type that the contractor can sell.Objective Function:
Maximize the total profit, which is the sum of the profits from selling each class of concrete.Constraints:
The total amount of cement, sand, and gravel used in producing each class of concrete cannot exceed the available amount of each material.The percentage by weight of cement, sand, and gravel used in producing each class of concrete must fall within the specified upper and lower bounds.The total amount of each class of concrete sold cannot exceed the limitation on the amount that can be sold.To learn more about Parameters, visit: https://brainly.com/question/30655786
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A 45o reducing elbow can be found in many piping systems. Crude oil (r = 52.5 lbm/ft3) flows into the elbow with a velocity of 5.5 ft/s and is deflected through an angle of 45o. The inlet diameter is 6-in, and the outlet diameter is 4-in. The inlet and outlet gage pressures are 35 psig and 32.5 psig, respectively. If the elbow is located in a horizontal plane, determine the restraining forces in the x and y-directions in lb
Answers
Answer:
the restraining forces in the x and y-directions are :
\(\mathbf{ F_x =1510.63 \ lbf}\)
\(\mathbf{F_y =6242.17 \ lbf}\)
Explanation:
From the given information;
Let us first calculate the outlet velocity by using continuity equation.
\(A_1v_1= A_2v_2\)
\(\dfrac{\pi}{4}D_1^2 *v_1 = \dfrac{\pi}{4}D_2^2 *v_2\)
where;
\(D_1\) = inlet diameter = 6 - In
\(D_2 =\) outlet diameter = 4 -In
inlet velocity \(v_1 = 5.5 \ ft/s\)
outlet velocity = ???
\(\dfrac{\pi}{4}*6^2 *5.5 = \dfrac{\pi}{4}*4^2 *v_2\)
\(36*5.5= 16 v_2\)
\(198 = 16 v_2\)
\(v_2 = \dfrac{198}{16}\)
\(v_2 = 12 .375 \ ft/s\) to In; we have
Since 1 ft = 12 inches; thus
12.375 ft/s = (12.375 × 12 ) inches = 148.5 In/s
\(v_1 =\) 5.5 ft/s = 66 In/s
By using the linear momentum in x-direction for the volume ; we have the relation:
\(\sum F_x = \sum \dfrac{mdv}{dt}x \\ \\ P_1A_1 - P_2A_2 * \ cos 45 + F_x = (m_2)V_2* \ cos 45 - ( m_1)v\)
where;
\(m = \rho AV\)
\(P_1A_1 - P_2A_2 * \ cos 45 + F_x = (\rho A_2 V_2)V_2* \ cos 45 - ( \rho A_1 V_1)v\)
\(35*\dfrac{\pi}{4}*6^2 - 32.5*\dfrac{\pi}{4}*4^2 * \ cos 45 + F_x = \dfrac{52.5}{12^3}( \dfrac{\pi}{4}*4^2*(148.5)^2 * cos 45 - \dfrac{\pi}{4}*6^2*66^2)\)
\(700.81 + F_x = 2211.44\)
\(F_x = 2211.44-700.81\)
\(\mathbf{ F_x =1510.63 \ lbf}\)
\(\sum F_y =\dfrac{m dvy}{dt}\)
\(- P_2A_2 * \ Sin \ 45 + F_y = (\rho A_2 V_2 )V_2* \ sin 45 - 0\)
\(F_y = (\rho A_2 V_2 )V_2* \ sin 45 + P_2A_2 * \ Sin \ 45 +\)
\(F_ y = 32.5 * \dfrac{\pi}{4}*4^2* sin 45 + \dfrac{52.5}{12^3} *\dfrac{\pi}{4}*4^2*148.5^2*sin45\)
\(F_y = 288.79 +5953.38\)
\(\mathbf{F_y =6242.17 \ lbf}\)
Therefore; the restraining forces in the x and y-directions are :
\(\mathbf{ F_x =1510.63 \ lbf}\)
\(\mathbf{F_y =6242.17 \ lbf}\)
Which electrode uses a whip technique and why
Answers
Answer:
STICK SKILL DRILL...
Explanation:
The skill drill uses a Whip and Pause technique.The reason for whip and pause is that 6010 electrodes are fast freezing electrodes and the momentary whips allow the puddle to solidify a bit ..Length of Art..Too long an arc causes problems so try to keep the arc equal to or shorter than diameter of electrode.
The input impedance of a network is 12−8jΩ at a frequency of ω=10 4
r/s. Determine R and C.
Answers
The values of R and C are: R = 12 Ω and C = 0.0272 F or 0.0072 F. We can calculate it in the following manner.
We can use the impedance formula for a series RL circuit to solve for R and C:
Z = R + j(ωC - 1/ωC)
where Z is the impedance, R is the resistance, C is the capacitance, and ω is the angular frequency.
Given that Z = 12 - 8j Ω and ω = 10⁴ r/s, we can solve for R and C as follows:
12 - 8j = R + j(10⁴C - 1/10⁴C)
Equating the real and imaginary parts:
12 = R
-8 = 10⁴C - 1/10⁴C
Multiplying both sides by 10⁴C:
-8(10⁴C) = 10⁸C² - 1
Rearranging:
10⁸C² + 8(10⁴)C - 1 = 0
Using the quadratic formula:
C = [-8(10⁴) ± √((8(10⁴))² + 4(10⁸))] / 2(10⁸)
C = [-8(10⁴) ± √(6.56 x 10¹²)] / 2(10⁸)
C = [-8(10⁴) ± 2.56 x 10⁶] / 2(10⁸)
C = [-0.04 ± 0.0128] F
C = 0.0272 F or 0.0072 F
Therefore, the values of R and C are:
R = 12 Ω
C = 0.0272 F or 0.0072 F
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Instructions given by traffic police or construction flaggers _____. A. Are sometimes important to follow B. Are usually not important to follow C. Don't overrule laws or traffic control devices D. Overrule any other laws and traffic control devices
Answers
Answer:
D. Overrule any other laws and traffic control devices.
Explanation:
Laws and traffic control devices are undoubtedly compulsory to be followed at every point in time to control traffic and other related situations. However, there are cases when certain instructions overrule these laws and traffic control devices. For example, when a traffic police is giving instructions, and though the traffic control devices too (such as traffic lights) are displaying their own preset lights to control some traffic, the instructions from the traffic police take more priority. This is because at that point in time, the instructions from the traffic control devices might not be just applicable or sufficient.
Also, in the case of instructions given by construction flaggers, these instructions have priority over those from controlling devices. This is because during construction traffic controls are redirected from the norms. Therefore, the flaggers such be given more importance.
Answer:
D. Overrule any other laws and traffic control devices.
Explanation:
Can space debris take out a whole state
Answers
using a diagram, explain five(5) factors that shift the aggregate demand and aggregate supply. (10 marks)
Answers
Refer to the attachments
Answer:
Refer to attachements hope its help
Technician A says that a body-over-frame vehicle may have front upper rails.
Technician B says that a body-over-frame vehicle usually has the body welded to the frame.
Who is right?
A)
A only
B)
B only
C)
Both A and B
D) Neither A nor B
Answers
Control points are areas of the vehicle structure that are used to monitor the precision of the vehicle body's dimensions as they are being assembled. Thus, option B is correct.
What frame vehicle usually has the body welded?In a full frame car, the body is independent of the frame and fastened by bushings and bolts. The unibody is a structure made up of integrated panels that are welded, bonded, and riveted together.
Therefore, In a full frame car, the body is independent of the frame and fastened by bushings and bolts. The unibody is a structure made up of integrated panels that are welded, bonded, and riveted together.
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the control circuit must produce an output of 1 if at least two of the conditions 1,2 and 3 are true. design the simplest circuit that can be used for this purpose.
Answers
The simplest circuit that can be used for the control circuit must produce an output of 1 if at least two of the conditions 1,2 and 3 are true is given below.
What is control circuit?A special kind of circuit known as a control circuit is used to regulate the performance of a totally independent power circuit. Think about a water pump being driven by a 1,000 horsepower, large industrial motor. A high voltage electrical source with a 2,400 volt output is connected to the motor.
For the safety of the operator and the machinery, a control circuit is used to ensure that the motor is started and stopped safely.
The thermostat for a home's air conditioner is an illustration of a control circuit that is frequently used. The thermostat is a component of a low-voltage control circuit that manages a relay that actually activates and deactivates the power circuit to the air conditioner compressor.
See the given attachment below for the simplest circuit↓↓
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Determine the horsepower required to compress 1 lbm/min of ethylene oxide from 70 oF and 1 atm to 250 psia. The compressor has an efficiency of 75%. The molar heat capacity of ethylene oxide is given by Cp
Answers
Complete Question:
Problem 8 Determine the horsepower required to compress 1 lbm/min of ethylene oxide from 70 °F and 1 atm to 250 psia. The compressor has an efficiency of 75%. The molar heat capacity of ethylene oxide is given by
C_p=10.03+0.0184T C_p[=]Btu/lbmole- "F ; T[=] °F C,
Answer:
\(P'=0.377hp\)
Explanation:
From the question we are told that:
Initial Temperature T_1=70 F
Final Temperature \(T_2=250pisa =114.94F\)
Efficiency \(E=75\%=0.75\)
Generally the equation for Work-done is mathematically given by
\(W=\int C_pT\)
\(W=10.03(114.94-70 )+0.0184((114.94)^2-70^2 )\)
\(W=527.21btu/ibmole\)
\(W=11.982btu/ibm\)
Generally the equation for Efficiency is mathematically given by
\(E=\frac{isotropic Power}{Actual P'}\)
\(E=\frac{P}{P'}\)
Since
Isotropic Power
\(P=0.0167*11.982btu/ibm\)
\(P=0.2btu/s\)
Therefore
\(P'=\frac{0.2}{0.75}\)
\(P'=0266btu/s\)
Since
\(1btu/s=1.4148hp\)
Therefore
\(P'=0.377hp\)
If you go to a restaurant and they offer 5 entrees, 4 vegetables, and 6 desserts, how many different combinations must the kitchen staff be ready to serve? all people must choose one from each category.
Answers
The kitchen staff must be ready to serve 120 different combinations.
How many combinations must the kitchen staff prepare?To calculate the number of different combinations the kitchen staff must be ready to serve, we can multiply the number of options in each category together:
Number of entrees = 5
Number of vegetables = 4
Number of desserts = 6
Total number of different combinations = Number of entrees × Number of vegetables × Number of desserts
Total number of different combinations = 5 × 4 × 6
Total number of different combinations = 120
Therefore, the kitchen staff must be ready to serve 120 different combinations.
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Give one example of each of the following structures. Your answer should include relevant
sketches, loads (no numerical values required), equations, and calculations. (a) A statically determinate beam. (b) A statically determinate truss or frame. (c) A truss statically indeterminate to degree 1. (d) A beam statically indeterminate to degree 2. (e) An unstable beam with two spans
Answers
Answer:
The above three conditions are commonly referred to as the equations of equilibrium for planar structures. ∑ Fx and ∑ Fy are the summation of the x and y components of all the forces acting on the structure, and ∑ Mz is the summation of the couple moments and the moments of all the forces about an axis z, perpendicular to the plane xy of the action of the forces.
Explanation:
(single pipe — determine pressure drop) determine the pressure drop per 290-m length of a new 0.20-m-diameter horizontal cast-iron water pipe when the average velocity is 1.9 m/s.
Answers
The pressure drop per 290-m length of a 0.20-m-diameter horizontal cast-iron water pipe with an average velocity of 1.9 m/s is approximately 3.94 kilopascals (kPa).
What is the pressure drop in a 290-m cast-iron water pipe?To determine the pressure drop, we need the value of the Darcy friction factor (f) specific to the pipe and flow conditions. Without that information, we cannot provide an exact numerical answer. The Darcy friction factor depends on factors such as pipe roughness and Reynolds number, and it can be obtained from reference tables or calculated using empirical correlations.
Once you have the Darcy friction factor (f), you can substitute it into the Darcy-Weisbach equation:
ΔP = (f * (L / D) * (ρ * V²)) / 2
By plugging in the values of L = 290 m, D = 0.20 m, ρ = 1000 kg/\(m^3\) (density of water at around 20 degrees Celsius), and V = 1.9 m/s (average velocity), along with the specific value of f, you can calculate the pressure drop per 290-meter length of the water pipe accurately.
Using the Darcy-Weisbach equation:
ΔP = (f * (L / D) * (ρ * V²)) / 2
Substituting the given values and the assumed Darcy friction factor:
ΔP = (0.025 * (290 m / 0.20 m) * (1000 kg/\(m^3\) * (1.9 m/s)²)) / 2
Calculating this expression yields:
ΔP ≈ 3.94 kPa
Therefore, the pressure drop per 290-meter length of the new 0.20-meter-diameter horizontal cast-iron water pipe, with an average velocity of 1.9 m/s, is approximately 3.94 kilopascals (kPa).
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2. 17 Calculate the tension in the cable at B required to support the load of 200 kg. The cable passes over a frictionless pulley located at C. Neglect the size of this pulley and the weight of the boom. No 60 30 T 200 kg
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The tension in the cable at point B required to support the load of 200 kg is 1960 N.
What is the tension required to support the cable?To calculate the tension in the cable at point B, we can start by analyzing the forces acting on the system.
If the load is at equilibrium, then the weight or gravitational force exerted by the load is equal to the tension or force required to support the load.
T_B - W_Boom = 0
Solving for T_B, we get:
T_B = W_Boom
T_B = mg
where;
g is acceleration due to gravitym is the mass of the loadT_B = 200 kg x 9.8 m/s²
T_B = 1960 N
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The impeller shaft of a fluid agitator transmits 20 kW at 430 rpm. If the allowable shear stress in the impeller shaft must be limited to 65 MPa, determine (a) the minimum diameter required for a solid impeller shaft. (b) the maximum inside diameter permitted for a hollow impeller shaft if the outside diameter is 36 mm. (c) the percent savings in weight realized if the hollow shaft is used instead of the solid shaft. (Hint: The weight of a shaft is proportional to its cross-sectional area.)
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Given :
Power, P = 20 kW
Speed, N = 430 rpm
Allowable shear stress, τ = 65 MPa
Torque in the shaft is given by :
\($P=\frac{2 \pi NT}{60}$\)
\($T=\frac{60 \times 20 \times 10^3}{2 \pi \times 430}$\)
T = 444.37 N.m
Diameter of the solid shaft is
\($d=\sqrt[3]{\frac{16 T}{\pi \tau}}\)
\($d=\sqrt[3]{\frac{16 \times 444.37}{3.14 \times 65}}\)
\($d=\sqrt[3]{34.83} $\)
d = 3.265 m
d = 326.5 mm
Internal diameter of the hollow shaft is :
\($\frac{T}{\frac{\pi}{32} \left( d_0^4 - d_i^4 \right)}=\frac{\tau}{d_0/2}$\)
\($\frac{444.37}{\frac{3.14}{32} \left( 0.036^4 - d_i^4 \right)}=\frac{65 \times 10^6}{0.036/2}$\)
\($\frac{444.37}{0.09 \left( 1.6 \times 10^{-6} - d_i^4 \right)}=\frac{65 \times 10^6}{0.018}$\)
\($\frac{7.99}{ \left( 1.6 \times 10^{-6} - d_i^4 \right)}=5850000$\)
\($1.3\times 10^{-6} = 1.6 \times 10^{-6} - d_i^4 \right)}$\)
\($d_i^4=300000$\)
\($d_i = 23.40$\) mm
Percentage savings in the weight is given by :
Percentage saving = \($\frac{W_{solid}-W_{hollow}}{W_{solid}}\times100$\)
\($=\frac{V_{solid}-V_{hollow}}{V_{solid}}\times100$\)
\($=\frac{d^2 - (d_0^2 - d_i^2)}{d^2} \times 100$\)
\($=\frac{(326.5)^2 - (0.036^2 - (32.40)^2)}{(326.5)^2} \times 100$\)
\($=\frac{106602 - \left(1.29 \times 10^{-3} - 1049.76 \right)}{106602} \times 100$\)
\($=\frac{106602 - 1049 }{106602} \times 100$\)
\($=\frac{105553 }{106602} \times 100$\)
= 99.01 %
substances that degrade the metals that make up storage tanks or equipment are called __________.
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Substances that degrade the metals that make up storage tanks or equipment are called corrosive agents.
Corrosive agents refer to chemicals or environmental factors that cause the gradual deterioration or destruction of metals through oxidation or other chemical reactions. When these substances come into contact with metals, they can initiate a process known as corrosion, which leads to the breakdown and weakening of the metal structure over time. Corrosion can result in leaks, structural failure, and contamination of the stored materials, posing significant safety and environmental risks. Preventive measures such as selecting corrosion-resistant materials, applying protective coatings, and implementing regular maintenance and inspection procedures are essential to mitigate the detrimental effects of corrosive agents on storage tanks and equipment.
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The spiral grooves in a drill body are used to do all of the following except?