When the following reaction is balanced, there are _____ atoms of oxygen and _____ atoms of hydrogen on each side. (NH4)2SO4 (aq) + Ba(C2H3O2)2 (aq) → BaSO4 (s) + NH4C2H3O2 (aq)

Answer:

0.7μM = 0.6 μM = 0.5 μM > 0.4 μM > 0.3 μM > 0.2 μM

Explanation:

An enzyme solution is saturated when all the active sites of the enzyme molecule are full.  When an enzyme solution is saturated, the reaction is occurring at the maximum rate.

From the given information, an enzyme concentration of 1.0 μM Y can convert a maximum of 0.5 μM AB to the products A and B per second means that a 1.0 M Y solution is saturated when an AB concentration of 0.5 M or greater is present.

The addition of more substrate to a solution that contains the enzyme required  for its catalysis will generally increase the rate of the reaction. However, if the enzyme is saturated with substrate, the addition of more substrate will have no effect on the rate of reaction.

Therefore the reaction rates at substrate concentrations of 0.7μM, 0.6 μM, and 0.5 μM are equal. But the reaction rate at substrate concentrations of  0.2 μM is lower than at 0.3 μM, 0.3 μM is lower than 0.4 μM and 0.4 μM is lower than 0.5 μM, 0.6 μM and 0.7 μM.

The solutions in decreasing order of reaction rate will be:

0.7μM = 0.6 μM = 0.5 μM > 0.4 μM > 0.3 μM > 0.2 μM

It is saturated when all the active sites of the enzyme molecule are full.  When an enzyme solution is saturated, the reaction is occurring at the maximum rate.

From the given information, an enzyme concentration of 1.0 μM Y can convert a maximum of 0.5 μM AB to the products A and B per second means that a 1.0 M Y solution is saturated when an AB concentration of 0.5 M or greater is present. If the enzyme is saturated with substrate, the addition of more substrate will have no effect on the rate of reaction.

Therefore, the reaction rates at substrate concentrations of 0.7μM, 0.6 μM, and 0.5 μM are equal. But the reaction rate at substrate concentrations of  0.2 μM is lower than at 0.3 μM, 0.3 μM is lower than 0.4 μM and 0.4 μM is lower than 0.5 μM, 0.6 μM and 0.7 μM.

Thus, the solutions in decreasing order of reaction rate will be:

0.7μM = 0.6 μM = 0.5 μM > 0.4 μM > 0.3 μM > 0.2 μM

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Answer:

Here's what I get  

Explanation:

(i) Voltaic cell

A voltaic cell is a device that uses a chemical reaction to produce electrical energy.

(ii) Overall Cell Potential

The standard reduction potentials for the half-reactions are

                               ℰ°/V

Cu²⁺ + 2e⁻ ⇌ Cu    0.34

Zn²⁺ + 2e⁻ ⇌ Zn   -0.76

The half-reaction with the more positive potential is the reduction half-reaction. It is the reaction that occurs at the cathode.

The half-reaction with the more negative potential is the oxidation half-reaction. It is the  reaction that occurs at the anode.

We reverse that half-reaction and subtract the voltages to get the cell reaction.

                                                          ℰ°/V

Cathode:  Cu²⁺ + 2e⁻ ⇌ Cu              0.34

Anode:     Zn ⇌ Zn²⁺ + 2e⁻              -0.76

Cell:          Zn +  Cu²⁺ ⇌ Zn²⁺ + Cu    1.10

\(\mathcal{E}_{\text{cell}}^{\circ} = \mathcal{E}_{\text{cat}}^{\circ} - \mathcal{E}_{\text{an}}^{\circ} = \text{0.34 V} - \text{(-0.76 V)} = \text{0.34 V} + \text{0.76 V} = \textbf{1.10 V}\)

(iii) Diagram

The specific labels will depend on your textbook.

They are often as follows.

a. Electron flow

b. Voltmeter or lightbulb

c. Electron flow

d. Cathode or Cu

e. Cu²⁺(aq) and NO₃⁻(aq)

f. Salt bridge

g. Zn²⁺(aq) and NO₃⁻(aq)

h. Anode or Zn

The salt bridge enables ions to flow in the internal circuit and to maintain electrical neutrality in the two compartments.

It often consists of a saturated solution of KCl.

As Zn²⁺ ions form in the anode compartment, Cl⁻ ions move in to provide partners for them.

As Cu²⁺ ions are removed from the cathode compartment, K⁺ ions move in to replace them.

Answer:a. Electron flow

b. Voltmeter or lightbulb

c. Electron flow

d. Cathode or Cu

e. Cu²⁺(aq) and NO₃⁻(aq)

f. Salt bridge

g. Zn²⁺(aq) and NO₃⁻(aq)

h. Anode or Zn

Explanation:

The molecular structures of sugars and alcohols are similar due to the presence of the -OH group.

This is a substance which has a sweet taste and is a form of simple carbohydrate.

They are however not similar due to the different numbers of Carbon atoms attached to the -OH group..

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Answer:

0.136mol

Explanation:

Using the general gas law equation as follows:

PV = nRT

Where;

P = pressure (atm)

V = volume (Litres)

n = number of moles (mol)

R = gas constant (0.0821 Latm/mol K)

T = temperature (K)

K = °C + 273

K = 50°C + 273

K = 323K

According to this question, P = 3.6atm, T = 323K, V = 1.00L, R = 0.0821 Latm/mol K, n = ?

3.6 × 1 = n × 0.0821 × 323

3.6 = 26.52n

n = 3.6/25.52

n = 0.1357

n = 0.136mol

Answer:

Option 1. K and MgBr2

Explanation:

From the question given above, we obtained the following data:

2K + MgBr2 —> 2KBr + Mg

In a chemical reaction, the reactants are located on the left side of the equation while the products are located on the right side.

The reactants are separated from the products by an arrow sign.

Considering the question given above,

Element /compound >>> location

K, MgBr2 >>>>>>>>>>>>> Left

KBr, Mg >>>>>>>>>>>>>> Right

From the illustration above, the reactants (i.e element/compound on the right side) are K and MgBr2

Answer:

To solve this problem and calculate the grams of Ni, we need to use the molar mass of Ni₂0₃ and the stoichiometry of the reaction.

The balanced chemical equation for the reaction between Ni₂0₃ and H₂ is:

Ni₂0₃ + 2H₂ → 2Ni + 3H₂0

From this equation, we can see that 1 mole of Ni₂0₃ reacts to produce 2 moles of Ni. Therefore, we can use the following conversion factor:

1 mole Ni₂0₃ = 2 moles Ni

We can also use the molar mass of Ni₂0₃ to convert grams of Ni₂0₃ to moles of Ni₂0₃:

54.3 g Ni₂0₃ x (1 mole Ni₂0₃ / 165.38 g Ni₂0₃) = 0.3284 moles Ni₂0₃

Now, we can use the conversion factor to find moles of Ni:

0.3284 moles Ni₂0₃ x (2 moles Ni / 1 mole Ni₂0₃) = 0.6568 moles Ni

Finally, we can use the molar mass of Ni to convert moles of Ni to grams of Ni:

0.6568 moles Ni x (58.69 g Ni / 1 mole Ni) = 38.53 g Ni

Therefore, the grams of Ni in 54.3 g Ni₂0₃ is 38.53 g Ni.

Explanation:

The net charge of the ion that consists of 7 protons, 9 neutrons, and 10 electrons will be -3.

HOW TO CALCULATE NET CHARGE:

net charge = no. of protons - no. of electrons

net charge: 7 - 10

net charge = -3

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There is only one pKa value for a monoprotic acid.

A monoprotic acid is an acid that has a single acidic proton, \(H^+\). In other words, a monoprotic acid is an acid that can donate only one proton or hydrogen ion to a base or a solution of water. Because of this characteristic, monoprotic acids have only one acid dissociation constant (Ka) and one pKa value.

This pKa value is a measure of the acid's strength. The lower the pKa value of an acid, the stronger it is. For example, acetic acid has a pKa value of 4.76, while hydrochloric acid has a pKa value of -8.

However, because pKa values are negative logarithms, the more negative the pKa value, the stronger the acid.

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The sample of helium gas must be cooled to approximately -220°C to reduce its volume from 5.9 L to 0.2 L at constant pressure.

According to the ideal gas law, the relationship between the volume (V), temperature (T), and pressure (P) of a gas can be expressed as PV = nRT, where n is the number of moles of the gas and R is the ideal gas constant. In this case, the pressure is constant, so we can simplify the equation to V/T = constant.

To find the final temperature required to reduce the volume from 5.9 L to 0.2 L, we can set up the following ratio:

(V1 / T1) = (V2 / T2)

Where V1 is the initial volume (5.9 L), T1 is the initial temperature (119°C + 273.15 = 392.15 K), V2 is the final volume (0.2 L), and T2 is the final temperature that we need to find.

Rearranging the equation, we have:

T2 = (V2 / V1) * T1

= (0.2 L / 5.9 L) * 392.15 K

≈ 13.28 K

Converting 13.28 K back to Celsius, we get:

T2 ≈ -259.87°C

Therefore, the sample of helium gas must be cooled to approximately -220°C (or -259.87°C) to reduce its volume from 5.9 L to 0.2 L at constant pressure.

The question should be:

To what temperature must a sample of helium gas be cooled from 119°C to reduce its volume from 5.9 L to 0.2 L at constant pressure?

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Answer:

Commensalism is a relationship between two organisms in which one organism benefits, and the other one is left unaffected.

Examples:

1. Barnacles on a sea turtle

2. Tree frogs and plants (they use them as protection)

1. Barnacles on a sea turtle

2. Tree frogs and plants (they use them as protection)

hope this helps

Answer

crush the cubes of broth, add warm water and stir the container.

Explanation

The FASTEST way to make the chicken broth with the cubes you have will be to increase the surface area of the cubes broth by crushing and raise the temperature of the cubes broth by adding warm water and by stirring the container.

Hence, the correct answer to your question is:

crush the cubes of broth, add warm water and stir the container.

Answer:

True.

Explanation:

An element is a pure substance and is made of only one type of atom

Answer: True.

Explanation:

An element is exactly that definition, composed of only one type of atom, which is why chemical elements are all different from each other.

Gas molecules will move from an area of higher partial pressure to an area of lower partial pressure.

The partial pressure of a gas (e.g. carbon dioxide in the lungs) allows the movement of molecules during physiological processes.

For example, during gas exchange, oxygen and carbon dioxide move in the respiratory system and circulatory system due to differences in the partial pressure of these gases.

In conclusion, gas molecules will move from an area of higher partial pressure to an area of lower partial pressure.

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A carbocation is all of the following, except a nucleophile.A carbocation is a positively charged species, a reactive intermediate, and an electrophile, but it is not a nucleophile.

Nucleophiles are species that donate electrons to form a new covalent bond, while electrophiles are species that accept electrons to form a new covalent bond. Carbocation have a positive charge and therefore it is an electrophile.A carbocation is a type of organic cation in which a carbon atom has a positive charge. Carbocations are formed by the removal of a leaving group from an organic molecule, such as an alkane, alkyl halide, or alkyne, creating a positively charged carbon atom. Carbocations are typically intermediate species in organic reactions and are highly reactive, as the positive charge on the carbon atom creates a high degree of electron deficiency.

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Answer:

A base releases OH~ in a solution, so the answer is B

I am sorry I don't know, points are points though

The molarity (M) of a solution is 11.5 M that contains 0.75 moles of lithium fluoride, LiF in a 65 ml of solution.

Molarity (M) is defined as the number of moles of solute dissolved in 1L of solution. Molarity is also known as Molar concentration. The S.I Unit of Molarity is molar (M) or mol/L.

Molarity (M) = \(\frac{\text{Number of moles of solute}}{\text{Volume of solution (in liters)}}\)

From the above definition it is clear that the volume of solution is in liter. In question the volume of solution is given in ml.

So, convert 65 ml into l.

65 ml = \(\frac{65}{1000}\) = 0.065 l

Now, put the values in above formula, we get that

(M) = \(\frac{0.75}{0.065}\) = 11.5 M

Thus, the molarity of a solution is 11.5 M that contains 0.75 moles of lithium fluoride, LiF in a 65 ml of solution.

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The reaction which displays an example of an arrhenius base is

NaOH(s) → Na⁺(aq) + OH⁻(aq).

According to the Arrhenius theory, those substance which gives H⁺ ion to the aqueous solution is acid and which gives OH⁻ ion to the aqueous solution is known as base.

All given chemical reactions will display an arrhenius acid, but only one reaction display as a arrhenius base as they gives OH⁻ ion to the aqueous solution and that reaction will be:
NaOH(s) → Na⁺(aq) + OH⁻(aq)

Hence option (1) is correct.

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Answer:

A: NaOH(s) ---> Na+(aq) + OH–(aq)

Explanation:

Gas mixes can be regarded as ideal gas mixtures for the purpose of calculation at low pressure or high temperature.

The ability of the gas particles to interact with one another depends on the system's temperature and pressure, and these interactions severely limit the precision of the Ideal Gas Law.Because the volume occupied by the gas is relatively small and the intermolecular distance between the molecules shrinks at low temperature and high pressure, the ideal gas law fails in these conditions. Real gases have lower pressure than the ideal gas equation because attraction forces between molecules do occur in real gases. The van der Waals equation takes this condition into account. As it is assumed that perfect gas molecules have no volume, the volume that they can move in is always the same as the volume of the container. In contrast, the volumes of the molecules in a genuine gas are minuscule but measurable.

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Answer:

The theoretical yield of sulfur trioxide is 88.0 Litres

Explanation:

The chemical reaction occurring between oxygen and sulfur dioxide is given in the chemical equation below :

2SO₂ + O₂ ----> 2SO₃

From the equation of reaction, 2 moles of sulfur dioxide reacts with 1 mole of oxygen to produce 2 moles of sulfur trioxide.

Volume of 1 mole of a gas at STP is 22.4 L

Number of moles of gas in 44.0 L = 44.0/22.4 moles

1 mole of oxygen reacts with 2 moles sulfur dioxide to produce 2 moles of sulfur trioxide;

44/22.4 moles of oxygen will react with excess sulfur dioxide to produce 2 × 44/22.4 moles of sulfur trioxide = 88/22.4 moles of sulfur trioxide

88/22.4 moles of sulfur trioxide will have a volume of 88/22.4 × 22.4 Litres = 88.0 Litres

Therefore, the theoretical yield of sulfur trioxide is 88.0 Litres

If the hydrogen gas is combusted and produces 645L of water vapor at 400 kelvin and 1.75 atm, 2796.96 g mass of the zinc is produced .

Using the ideal gas law equation:

PV = nRT

n = (PV) / (RT)

= (1.75 atm * 645 L) / (0.0821 atm·L/(mol·K) * 400 K)

= 42.71 moles

the balanced equation for the reaction between zinc and hydrochloric acid:

Zn + 2HCl -> \(ZnCl_{2}\)  + \(H_{2}\)

1 mole of zinc produces 1 mole of hydrogen gas. Therefore, the moles of zinc are also 42.71.

The molar mass of zinc is 65.38 g/mol.

Mass of zinc = moles of zinc * molar mass of zinc

= 42.71 moles * 65.38 g/mol

= 2796.96 g

Therefore, the mass of the zinc is 2796.96 grams.

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Relative humidity is the ratio of the actual amount of water vapor in the air to the maximum amount of water vapor that the air can hold at a given temperature.

The first step is to determine the maximum amount of water vapor that the air can hold at  20°C. This is known as the saturation vapor pressure, which can be found using a psychrometric  chart or an equation. For simplicity, the equation for the saturation vapor pressure of water at  20°C, which is 2.34  kPa.
The vapor pressure of water at 20°C is approximately 2.33  kPa.
RH = (actual vapor pressure / saturation vapor pressure) x 100%
RH = (2.33 kPa / 2.34 kPa) x 100%
RH = 99.57%

The relative humidity of 1m3 of air containing 10g/m3 at 20°C is approximately 99.57%.

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The molecule for further use in the citric acid cycle is NAD+.

In the absence of oxygen after glycolysis cells undergo fermentation without the citric acid cycle or oxidative phosphorylation. The citric acid cycle requires oxygen. This is because the electron transport chain requires an electron acceptor to regenerate her NAD, which is the role of oxygen.

Some of this is considered an aerobic pathway because the NADH and FADH2 produced must transfer electrons to the next pathway in the system using oxygen. Without oxygen, this transfer would not occur. Two carbon atoms from each acetyl group enter the citric acid cycle. Oxygen is the terminal electron acceptor of the mitochondrial electron transport chain and is therefore required for energy production via oxidative phosphorylation.

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Answer: B- Isotopes are often used for dating artifacts and fossils is incorrect.

Explanation: I hope that helped

Answer: C

Explanation: Edge

Launching a projectile over a significant distance, such as several hundred miles, presents a range of complex challenges that must be carefully addressed. The success of achieving such a long range relies on accounting for various factors that influence the projectile's trajectory, including aerodynamics, atmospheric conditions, Earth's curvature, and external forces.

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The equation of the function for the given graph is y=(x−5)²+3

The given graph is a parabola which is a plane curve and is approximately U– Formed. A parabola may be a conic area that's obtained when the proper circular cone surface and plane cross. In other words, a parabola may be a locus of focus in a plane surface that ought to be equidistant from the locus and the directrix.

In the graph, we can see the vertex which is  (5,3). The formula we are referring for  the vertex form of a parabola with vertex (h,k) is

y=a(x−h)²+k

So for this graph, it will be ( h=5 and k=3)

y=a(x−5)²+3

As we substitute the desired value of x and y  in order to find a-

=> 12=a(8−5)²+3

=> a(3)² =9

=> 9a =9

Therefore the value of a =1

And the equation will be y=(x−5)²+3

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Answer:

. 8 CO(g) + 17 H2(g) 1 C8H18(l) + 8 H2O

Explanation:

To convert from mass of A to moles of B in a stoichiometry problem is c. mass A → mass B → moles B.

Coefficient elements are the numbers that get written at the left of reactants and merchandise in chemical equations. They suggest the range of moles wished for a positive reactant or the range of moles that get produced through a reaction. They are used to narrate the molar amount of the chemical species concerned in a reaction.The mass of the given substance is transformed into moles through use of the molar mass of that substance from the periodic table. Then, the moles of the given substance are transformed into moles of the unknown through the usage of the mole ratio from the balanced chemical equation.

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