When showing a blind drilled hole (a hole ending within the feature) it is customary to show the slant at the end of the hole at 45 degrees. T/F

Answer:

desire to make money that motivates people to produce and sell goods and services. ... rivalry among producers or sellers of similar goods and services to win more business. economic efficiency. wise use of available resources so that costs do no exceed benefits.

Answer:

Tech A

Explanation:

To find the equation of the slope at the free end of the beam, we need to first determine the reactions at the supports using the equations of statics. Once we know the reactions, we can use the moment-area method to calculate the slope at the free end.

Let's start by drawing the free-body diagram of the beam, showing the forces and moments acting on it:

          |------10 ft-----|

          A               B

          |----------------|

                      8 kips

Here, A and B are the supports, and the distributed load of 8 kips/ft is acting on the beam between A and B.

Using the equations of statics, we can write:

ΣFy = 0: Ay + By - 8(10) = 0 (sum of vertical forces is zero)

ΣM(A) = 0: -Ay(10) + M = 0 (sum of moments about A is zero)

ΣM(B) = 0: -8(10)(5) - By(10) - M = 0 (sum of moments about B is zero)

Solving these equations simultaneously, we get:

Ay = 20 kips

By = 60 kips

M = 100 kip-ft

Now we can use the moment-area method to find the slope at the free end of the beam. To do this, we need to first calculate the moment of the area between the loading and the free end of the beam, which is given by:

M1 = ∫(x-10)(-8x)dx, from x=10 to x=20

M1 = -8 ∫(x^2 - 10x)dx, from x=10 to x=20

M1 = -8 [(1/3)(20^3 - 10^3) - (1/2)(20^2 - 10^2)]

M1 = -240 kip-ft

Next, we need to calculate the moment of the area between the loading and the support at A, which is given by:

M2 = ∫(x-0)(-8x)dx, from x=0 to x=10

M2 = -8 ∫(x^2)dx, from x=0 to x=10

M2 = -8 [(1/3)(10^3 - 0^3)]

M2 = -266.67 kip-ft

Finally, we can use the moment-area method to find the slope at the free end of the beam:θf = (M1 + M2)/(EI)where E is the modulus of elasticity of the beam material and I is the moment of inertia of the cross-section of the beam. Since we do not have information about the material or the cross-section, we cannot calculate the slope. Therefore, the answer to this part of the question is: "The equation of the slope at the free end cannot be determined without additional information about the material and the cross-section of the beam."

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Answer:

The key to bieng a good engineer

1. Define Your Goals

2. Commit Yourself To Continuous Professional Development

3. Work On Improving Soft Skills

4. Understand Business

5. Embrace Change

6. Work Hard

7. Be Optimistic

8. Identify Role Models And Mentors

9. Stay Flexible

10. Focus On The Long-Term

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Answer:

When a loss of charge exists, There is not a sufficient force to throttle the value open to it's correct position.

Answer:

There are six conditions

1. Poles should contain some residual flux.

2. Field and armature winding must be correctly connected so that initial mmm adds residual flux.

3. Resistance of field winding must be less than critical resistance.

4. Speed of prime mover of generator must be above critical speed.

5. Generator must be on load.

6. Brushes must have proper contact with commutators.

Explanation:

Answer:

Work to develop software and related documents that respect the privacy of those who will be affected by that software.

Explanation:

In the Software Engineering Code of Ethics and Professional Practice, under Principle, which is section three (3) of the document, it is stated in clause 12 on what information should a professional Engineer keep private.

In it, it is stated that professionals engineers should keep private information relating to "Work to develop software and related documents that respect the privacy of those who will be affected by that software."

Answer: how far is the school?

Explanation:

Answer:dimples

Explanation:

The option that is not designed to absorb collision energy is Reinforcements.

Thus option D (reinforcements)  is correct.

Here,

Reinforcements are designed to strengthen and support the structure of the vehicle, and not to absorb collision energy.

Automobiles have several safety features designed to protect drivers and passengers in the event of a collision. These safety features include airbags, seat belts, crumple zones, and several other components.

Among these safety features, the ones designed to absorb collision energy are dimples, slots, and crush zones. They are made to absorb the force of the impact during a collision and help prevent serious injuries to the occupants of the vehicle.

Therefore, the correct answer is D, reinforcements, which are not designed to absorb collision energy.

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A movement that I am familiar is  a religious movement known as Heavenly conscious movement and the things i want them to gain additional knowledge about a performance on:

A movement is known to be one that make use of  planning as well as unpredictability. The movement is one that is given identity, leadership, as well as  coordination by one or more organizations.

Therefore, A movement that I am familiar is  a religious movement known as Heavenly conscious movement and the things i want them to gain additional knowledge about a performance on:

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Answer:

i need points 425677

Explanation:

yurrrrrr  awnser C

Answer:

A: density and gravity

Explanation:

The Froude Number is defined as a dimensionless parameter that measures the ratio of the force of inertia on an element of fluid to the weight of the fluid element. In simple terms, it's the force of inertia divided by the gravitational force.

Froudes number is usually expressed as;

Fr = v/√(gd)

Where;

Fr = froude number

v = velocity

g = gravitational acceleration = specific weight/density

d = depth of flow

Now, to calculate the corresponding speed and force in the prototype, it means we have to use equal froude number and thus this will mean that it has to be dominated by gravity and density.

Answer:

350×305π{^ not sure my answer please follow me

Answer:

3 m/s²

Explanation:

Acceleration is calculated as :

a= Δv/ t

where ;

Δv = change in velocity

Δv = 45 - 0 = 45  m/s

t= 15 s

a= 45 /15

a= 3 m/s²

The heat generated within the wire is 1.05 x 10¹⁰ W/m³ with a maximum temperature of  589.5 K.

Heat is the energy that has a correlation with the resistivity of the material. Resistivity depends on the resistance and wire dimension where the resistance of the material can be written as

R = ρ.L/A

where R is resistance, ρ is resistivity, L is the length of the wire and A is surface area.

The given parameters from this question are

σ = 14 W/m.K

ρ = 45 x 10¯⁸ Ωm

I = 120 A

d = 1 mm

r = 0.5 mm = 5 x 10¯⁴ m

Calculate the surface area

A = πr²

A = π(5 x 10¯⁴)²

A = 7.86 x 10¯⁷ m²

In 1 m³, the length of wire should be

V = A . L

1 = 7.86 x 10¯⁷ . L

L = 1272727.273 m

Find the resistance of wire per m³

R/V = ρ.L/A

R/V = 45 x 10¯⁸ . 1272727.273 / 7.86 x 10¯⁷

R/V = 728925.62 Ω/m³

Find the heat generated per m³ by using power

P/V = I² . R

P/V = 120² . 728925.62

P/V = 1.05 x 10¹⁰ W/m³

Find the heat generated per m by using power

P/L = P/V

P/L = P/V . A

P/L = 1.05 x 10¹⁰ . 7.86 x 10¯⁷

P/L = 8253 W/m

Find the maximum temperature

T = (P/L) / σ

T = 8253 / 14

T = 589.5 K

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The total present worth is $19,783.01

The present worth of a series of cash flow is the value of the cash flows in year 0 (today)

Cash flow in year 0 = 5330

Cash flow in year 1 = 0

Cash flow in year 2 = 0

Cash flow in year 3 = 13075 / (1.02)^3 = 12,320.86

Cash flow in year 4 = 2308 / (1.02)^4 = 2,132.24

Present worth = $19,783.01

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Answer:

See explanation.

Explanation:

Since no figure was given I solved a problem that was similar to the one you described that I worked in my mechanics of materials class. The method should be very similar for your figure. See attached image for my work.

If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.

We need to perform a two step process to obtain the maximum shear stress on the shaft. For the solid shaft,

P=2×pi×N×T/60 or T=60×p/2×pi×N

Where P=power transmitted by the shaft=50×10³W

N=rotation speed of the shaft in rpm=730rpm

Pi=3.142

T is the twisting moment

By substituting the values for pi, N and P, we get

T=654Nm or 654×10³Nmm

Also, T=pi×rho×d³/16 or rho=16×T/pi×d³

Where rho=maximum shear stress

T = twisting moment=654×10³Nmm

d= diameter of shaft= 40mm

By substituting T, pi and d

Rho=52Mpa

b. For a hollow shaft, the value for rho is unknown

T=pi×rho(do⁴-di⁴/do)/16

Rho=T×16×do/pi×(do⁴-di⁴)

Where

T= twisting moment=654×10³Nmm gotten above

do=outside shaft diawter=40mm

di= inside shaft diameter =30mm

Pi=3.142

Substituting values for pi, do, di and T.

Rho=76Mpa

Therefore, If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.

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The component of an air conditioner or heat pump that collects heat from the indoor air is called the evaporator coil.

The evaporator coil is specifically located in the air handler of your air conditioner or, if you have a combined heating and air conditioning system, inside the furnace. Air is cooled and transferred to the evaporator coils of HVAC systems by refrigerant that has evaporated inside the coils.

The component of a heat pump or air conditioner that collects heat from the indoor air is called an evaporator coil. Either the furnace is connected to it or it is housed inside the air handler.

On the air intake side of the fan coil or the furnace's outlet side, respectively, is where the evaporator coil—also known as the cooling coil—is positioned within the house. Its role is to chill interior air so the blower fan can provide cool, refreshing air back into the space.

Therefore, the correct answer is option c) A single-family home.

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An extremum is a point where the function has its highest or lowest value, and at which the slope is zero.

The dimensions to be used if the volume is fixed and the cost of construction is to be kept to a minimum is as follows;

Reason:

The given parameters are;

Form of silo = Cylinder surmounted by a hemisphere

Cost of construction of hemisphere per square unit = 2 × The cost of of construction of the cylindrical side wall

Required:

The dimensions to be used if the volume is fixed and the cost of construction is to be kept to a minimum

Solution:

The fixed volume of the silo, V, can be expressed as follows;

\(V = \pi \cdot r^2 \cdot h + \dfrac{2}{3} \cdot \pi \cdot r^3\)

Where;

h = The height of the cylinder

r = The radius of the cylinder

The surface area is, Surface Area = 2·π·r·h + 2·π·r²

The cost, C = 2·π·r·h + 2×2·π·r² = 2·π·r·h + 4·π·r²

Therefore;

\(C = 2 \times \pi \times r\times \dfrac{V - \dfrac{2}{3} \cdot \pi \cdot r^3 }{\pi \cdot r^2 } + 4 \cdot \pi \cdot r^2 = \dfrac{8 \cdot r^3 \cdot \pi + 6 \cdot V}{3 \cdot r}\)

At the minimum value, we have;

Which gives;

16·π·r³ = 6·V

Which gives;

\(h = \dfrac{\dfrac{8 \cdot \pi \cdot r^3}{3} - \dfrac{2}{3} \cdot \pi \cdot r^3 }{\pi \cdot r^2 } = 2 \cdot r\)

h = 2·r

The height of the silo, h = 2 × The radius, 2

Therefore, the dimensions to be used if the volume is fixed and the cost is to be kept to a minimum is, height, h = 2 times the radius

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If an engine fails during rollout or just before takeoff, immediately shut both throttles and land the aircraft safely. Before reaching a safe single engine speed right away after takeoff, drop your nose to increase velocity.

Closing the throttle, turning off the fuel pump, setting the mixture control to idle cutoff, and simply cranking the engine is the most reliable hot start method I've found.

If an engine fails during rollout or just before takeoff, immediately shut both throttles and land the aircraft safely. Before reaching a safe single engine speed right away after takeoff, drop your nose to increase velocity. If you are unable to climb, close both throttles and land straight ahead.

The typical practice for the majority of aircraft would be to abandon takeoff if an engine failed during takeoff. In small aircraft, the pilot should turn the throttles down to idle, activate the speed brakes (if provided), and apply the brakes as needed if the engine fails before VR (Rotation Speed).

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def calculate_expected_increase_in_nose_length(probabilities):

 """

 Calculates the expected increase in the length of Pinocchio's nose, given the probabilities of him telling different lies.

 Args:

   probabilities: A list of probabilities, where each probability corresponds to the probability of Pinocchio telling a certain lie.

 Returns:

   The expected increase in the length of Pinocchio's nose.

 """

 # Calculate the expected number of times Pinocchio has to tell a lie.

 expected_number_of_lies = 1 / probabilities[2]

 # Calculate the expected increase in the length of Pinocchio's nose.

 expected_increase_in_nose_length = expected_number_of_lies * sum(probabilities[0] * 1 + probabilities[1] * 2 + probabilities[2] * 3 + probabilities[3] * 4)

 return expected_increase_in_nose_length

if __name__ == '__main__':

 # Set the probabilities of Pinocchio telling different lies.

 probabilities = [0.4, 0.3, 0.2, 0.1]

 # Calculate the expected increase in the length of Pinocchio's nose.

 expected_increase_in_nose_length = calculate_expected_increase_in_nose_length(probabilities)

 print('The expected increase in the length of Pinocchio\'s nose is', expected_increase_in_nose_length, 'inches.')

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Answer:

=$A$3*$B$1

Explanation:

Since cells involved in the formula are absolute row and column because of the $ sign on the row letter and column number for both, this formula will not changed when it is copied to any new location on the worksheet

False. The data hazard between the third and first instructions cannot be resolved using forwarding alone.

The data hazard between the third and first instructions cannot be resolved using forwarding. Forwarding allows data to be transferred directly from the execution stage of one instruction to the execution stage of another instruction to avoid stalls or hazards. However, in this case, the value produced by the third instruction (which is a store instruction) needs to be written back to the register file before it can be forwarded to the first instruction. Therefore, forwarding alone cannot resolve this data hazard. Instead, other techniques like stalling or reordering instructions may be required to handle the hazard and ensure correct execution.

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Answer:

the  half answer is pretty easy just look at it really really good hope this helps..

Explanation:

Answer:

The annualized cost is:

$299,272.

Explanation:

a) Data and Calculations:

Year 0  Capital cost of road construction = $6 million

Year 10 Major improvements cost = $17 million

Year 25 Replacement and upgrade cost = $29 million

Year 40 Federal government one-time tax credit = $12 million

Period of project analysis = 50 years

Cost of capital (discount rate) = 10%

Annualized cost at present value costs:

Amount spent  Discount Factor     Present value

$6 million           1                               $6,000,000

$17 million         0.386                          6,562,000

$29 million       0.092                          2,668,000

($12 million)      0.0222                         (266,400)

Total cost                                          $14,963,600

Annualized cost = $14,963,600/50 =  $299,272

b) The annualized cost for the road construction project, which is the annualized value of the net present costs of $14,963,600, is divided by 50.  Before obtaining the net present costs, the cash outflows, including the tax credit, are discounted to their present values, using the discount rate of 10%.  And then, the average of the cost is obtained by dividing the total net present cost into 50 years.

1. Total Social Security benefits without the time value of money considered at 85 years of age:Plan A: Early Retirement at 62Brad will receive $168,000 ($1,400/month * 12 months/year * 10 years)Sheryl will receive $168,000 ($1,400/month * 12 months/year * 10 years)Total $336,000

Plan B: Full Retirement at 67Brad will receive $216,000 ($2,000/month * 12 months/year * 9 years)Sheryl will receive $216,000 ($2,000/month * 12 months/year * 9 years)Total $432,000Plan C: Late Retirement at 70Brad will receive $297,600 ($2,480/month * 12 months/year * 5 years)Sheryl will receive $297,600 ($2,480/month * 12 months/year * 5 years)Total $595,200Plan D: Combined StrategyBrad will receive $216,000 ($2,000/month * 12 months/year * 9 years)Sheryl will receive $117,600 ($1,000/month * 12 months/year * 9 years) plusBrad will receive $357,840 ($2,480/month * 12 months/year * 8 years)Total $691,4402. Future worth at 6% per year of each plan at age 85:Plan A: $336,000Plan B: $432,000Plan C: $595,200Plan D: $691,4403

. Economically, the best combination of plans for Brad and Sheryl, assuming they both live to be 85 years old is Plan D (Combined Strategy) as it provides the highest total benefit of $691,440.4. Develop at least one additional question that you think Sheryl and Brad may have. Answer the question.The couple may want to know how Social Security benefits will be taxed and if they should delay withdrawing them to avoid or minimize taxes on their benefits. The taxation of Social Security benefits is dependent on the couple’s income. If the total income (which includes 50% of Social Security benefits) is more than $32,000 for couples filing jointly.

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False.  When traveling on a forklift, it is not necessary to have the carried load at the highest position.

Maintaining a lower position for the carried load during travel ensures better stability, visibility, and adherence to the forklift's load capacity limits.

When traveling on a forklift, the carried load should not be at the highest possible position during travel.

It is recommended that the load be kept as low as possible, close to the ground, and tilted back slightly for stability. This is because a high load center of gravity can make the forklift unstable and increase the risk of tipping over.

Additionally, a high load can obstruct the operator's view, making it difficult to see potential hazards and obstacles in the forklift's path.

It is essential to follow safe load handling procedures and the manufacturer's guidelines when operating a forklift to prevent accidents and ensure the safety of the operator and others in the surrounding area.

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This question is incomplete, the complete question is;

For a steel alloy it has been determined that a carburizing heat treatment of 11.3 h duration at Temperature T1 will raise the carbon concentration to 0.44 wt% at a point 1.8 mm from the surface. A separate experiment is performed at T2 that doubles the diffusion coefficient for carbon in steel.

Estimate the time necessary to achieve the same concentration at a 4.9 mm position for an identical steel and at the same carburizing temperature T2.

Answer:

the required time to achieve the same concentration at a 4.9 is 83.733 hrs

Explanation:

Given the data in the question;

treatment time t₁ = 11.3 hours

Carbon concentration = 0.444 wt%

thickness at surface x₁ = 1.8 mm = 0.0018 m

thickness at identical steel x₂ = 4.9 mm = 0.0049 m

Now, Using Fick's second law inform of diffusion

\(x^2\) / Dt = constant

where D is constant

then

\(x^2\) / t = constant

\(x^2_1\) / t₁ = \(x^2_2\) / t₂

\(x^2_1\) t₂ = t₁\(x^2_2\)

t₂ = t₁\(x^2_2\) / \(x^2_1\)

t₂ = (\(x^2_2\) / \(x^2_1\))t₁

t₂ = \((\) \(x_2\) / \(x_1\) \()^2\) × t₁

so we substitute

t₂ = \((\) 0.0049  / 0.0018  \()^2\) × 11.3 hrs

t₂ = 7.41 × 11.3 hrs

t₂ = 83.733 hrs

Therefore, the required time to achieve the same concentration at a 4.9 is 83.733 hrs