Answer:
slowing down.
Explanation:
acceleration points in the same direction as the velocity, the object will be speeding up. And if the acceleration points in the opposite direction of the velocity, the object will be slowing down
If you begin with 40 grams of a radioactive isotope and end with 10 grams, how many half-lifes of the radioactive isotope have passed ?
An example of absolute brightness (its use)
Absolute Brightness: The apparent brightness of a star at a standard distance of 10 parsecs from Earth. Example: Sirius.
What is Absolute Brightness?
The apparent brightness of a star at a standard distance of 10 parsecs from Earth. If you look at the night sky on Earth, you can see that some stars are much brighter than others. However, the brightness of a star depends on its composition and distance from the planet.
Astronomers define the magnitude of a star in terms of its:
Apparent magnitude (how bright the star appears from Earth) Absolute magnitude (how bright the star appears at a standard distance of 32.6 light-years or 10 parsecs).For example, Sirius is the brightest star in our sky (it has the highest apparent brightness), so it would be relatively easy to find it.
Hence, the apparent brightness of a star at a standard distance of 10 parsecs from Earth is defined as Absolute Brightness. Example: Sirius.
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Railroad car A of mass 320.0 kg moving with a velocity VA collides and sticks with another railroad car (B) of mass 100.0 kg moving with velocity 3.00 m/s in the opposite direction as shown in the figure. B (a) (b) Find VÀ such that both cars now have a final velocity which is half-VA in the direction of car A as shown in the figure. Submit Answer Tries 0/40 What is the kinetic energy (in Joules) lost in the collision? Submit Answer Tries 0/40
The kinetic energy of an object is given by the formula KE = 0.5 * mass * velocity^2. To find the value of VA such that both cars have a final velocity equal to half of VA in the direction of car A, we need to apply the principle of conservation of momentum. Additionally, we can calculate the kinetic energy lost during the collision.
According to the principle of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. Mathematically, we can express this as:
(mass of car A * velocity of car A before collision) + (mass of car B * velocity of car B before collision) = (mass of car A * velocity of car A after collision) + (mass of car B * velocity of car B after collision)
Since car A and car B stick together after the collision, their final velocities will be equal and can be denoted as VAf. We also know that the final velocity of car A and car B is half of VA in the direction of car A, so we can write:
VAf = 0.5 * VA
VBf = 0.5 * VA
By substituting these values into the momentum conservation equation and solving for VA, we can find the value of VA that satisfies the given conditions.
To calculate the kinetic energy lost in the collision, we can subtract the total kinetic energy after the collision from the total kinetic energy before the collision. The kinetic energy of an object is given by the formula KE = 0.5 * mass * velocity^2. By calculating the kinetic energy before and after the collision and taking their difference, we can determine the amount of kinetic energy lost.
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what class lever is a can opener?
Answer:
second class lever
Explanation:
because in bottle opener the load lies between effort and fulcrum
thus answer may help u
Which of the above would double the wavelength of the fundamental resonant mode on the string? Select the correct answer A. None of these options would double the wavelength of the fundamental mode. B. Decrease the linear mass density by a factor of 2 C. Decrease the linear mass density by a factor of 4 D. Increase the linear mass density by a factor of 2 E. Increase the linear mass density by a factor of 4
Answer:
Correct option A. None of these options would double the wavelength of the fundamental mode.
Explanation:
The wavelength of the fundamental resonant mode on a string is given by the formula: λ = 2L/n
where L is the length of the string, n is the harmonic number, and λ is the wavelength.
To double the wavelength of the fundamental resonant mode on the string, we need to increase the length of the string to twice its original length or decrease the harmonic number to half its original value.
Changing the linear mass density of the string would not directly affect the length or harmonic number, so option A is incorrect.
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The correct answer is B, decreasing the linear mass density by a factor of 2 would double the wavelength of the fundamental resonant mode on the string.
To double the wavelength of the fundamental resonant mode on the string, we need to decrease the frequency of vibration by half. This can be achieved by increasing the length of the string or decreasing the linear mass density of the string.
Option A states that none of the options would double the wavelength, which is incorrect as we know that changing the linear mass density would affect the frequency and thus the wavelength of the string.
Option B suggests decreasing the linear mass density by a factor of 2, which would decrease the frequency and thus double the wavelength of the string's fundamental resonant mode. Option C suggests decreasing the linear mass density by a factor of 4, which would decrease the frequency even more, resulting in a wavelength that is four times longer.
Option D suggests increasing the linear mass density by a factor of 2, which would increase the frequency and make the wavelength half of what it was initially. Option E suggests increasing the linear mass density by a factor of 4, which would further increase the frequency and make the wavelength even shorter.
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Two students are watching a person riding a skateboard up and down a ramp. Each student shares what they think about the energy of the skateboarder as they ride up and down the ramp.
Elisa: I think the skateboarder has the more total energy at the top bottom of the ramp than the bottom of the ramp.
Raymond: I think the skateboarder has the same total energy at all points on the ramp.
Which student do you agree with? Why?
Answer:
The correct option is;
Raymond: I think the skateboarder has the same total energy at all points on the ramp
Explanation:
The total energy, also known as the total mechanical energy, is the sum of the kinetic and potential energies of the skateboarder
Given that the potential energy is the energy gained due to elevation, the maximum potential energy is obtained at the top of the ramp, while the maximum kinetic energy, which is the energy due to motion, is at the bottom of the ramp where the skateboarder moves fastest.
However, by the energy conservation principle, the kinetic energy of he skateboarder comes from the conversion of the potential energy, such that the total energy is the same at any particular point on the ramp.
four resistance of resistance 1 resistance, 2 resistance,3 resistance are connected in series and afterwards in parallel. Calculate the combined resistance in each case.
In series: The combined resistance is equal to the sum of the individual resistances (R_total = R1 + R2 + R3).
In parallel: The combined resistance is the reciprocal of the sum of the reciprocals of the individual resistances (1/R_total = 1/R1 + 1/R2 + 1/R3).
When resistors are connected in series, their resistances add up to give the total resistance. In this case, the combined resistance in series would be the sum of the individual resistances: R_total = R1 + R2 + R3.
On the other hand, when resistors are connected in parallel, their reciprocals sum up to give the inverse of the total resistance. In this case, the formula for calculating the combined resistance in parallel is: 1/R_total = 1/R1 + 1/R2 + 1/R3.
Let's assume the resistance values are R1 = 1 ohm, R2 = 2 ohms, and R3 = 3 ohms.
For the series connection: R_total = R1 + R2 + R3 = 1 + 2 + 3 = 6 ohms.
For the parallel connection: 1/R_total = 1/R1 + 1/R2 + 1/R3 = 1/1 + 1/2 + 1/3 = (6 + 3 + 2) / 6 = 11 / 6. Taking the reciprocal of both sides, we get R_total = 6 / 11 ohms.
Therefore, the combined resistance in the series connection is 6 ohms, while in the parallel connection, it is 6/11 ohms.
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Cobalt (Co) has an atomic mass of 59 and an atomic number of 27. Which statement correctly describes an atom of cobalt?
O A. An atom of cobalt contains more neutrons than protons.
B. An atom of cobalt contains more electrons than protons.
O C. An atom of cobalt contains the same number of neutrons and protons.
O D. An atom of cobalt contains the same number of neutrons, electrons and protons.
Answer:
Option A. An atom of cobalt contains more neutrons than protons.
Explanation:
From the question given above, the following data were obtained:
Mass number = 59
Atomic number = 27
Next, we shall determine the number of protons in the atom. This is illustrated below:
Atomic number of an element is simply defined as the number of protons in the atom of the element. Thus,
Atomic number = proton number
Atomic number = 27
Therefore,
Proton number = 27
Next, we shall determine the neutron number. This can be obtained as follow:
Mass number = 59
Proton number = 27
Neutron number =?
Mass number = Proton + Neutron
59 = 27 + Neutron
Collect like terms
Neutron = 59 – 27
Neutron number = 32
Next, we shall determine the number of electrons. This can be obtained as follow:
Since the atom is neutral i.e it has no charge, then, the number of protons and electrons are equal. Thus,
Electron number = Proton number
Proton number = 27
Therefore,
Electron number = 27
Summary:
Mass number = 59
Atomic number = 27
Proton number = 27
Neutron number = 32
Electron number = 27
From the above, we can see that the atom of cobalt contains:
1. More neutrons than protons.
2. The same number of protons and electrons.
Therefore, option A gives the correct answer to the question.
The ____ is a line drawn at a right angle to a barrier. a. normal c. node b. ray d. wave front
Answer:
a. normal
Explanation:
In the field of physics the normal is a line drawn at a right angle to a barrier. In other words the normal line is the line that is drawn perpendicular (right angle, 90 degrees) to the reflective surface of a mirror, or the particular boundary in which refraction occurs at the point of incidence of a light ray. This can be seen in the picture attached below.
a waterwheel built in hamah
☁️ Answer ☁️
annyeonghaseyo!
Your answer is:
"A waterwheel built in Hamah, Syria, has a radius of 20.0 m. If the tangential velocity at the wheel’s edge is 7.85 m/s" -Ggle
Hope it helps.
Have a nice day noona/hyung!~  ̄▽ ̄❤️
In workplaces where there is continuous noise e.g. mines, workers are encouraged to wear protective gears such as ear muffs provided by the company. This will reduce the noise going into workers ears hence reducing compensation costs. These protective gears have limitations in that they are damaged upon usage, as nothing lasts forever. Workers on the other hand tend to remove their protective gears with the view that they are uncomfortable or they want to hear their colleagues clearly.
Explain the likely reasons for weakening muffs effectiveness.
In workplaces with continuous noise, such as mines, the use of protective gear like ear muffs is encouraged to reduce the amount of noise entering workers' ears. This not only protects their hearing but also helps decrease compensation costs associated with hearing-related injuries.
However, it is important to recognize that these protective gears have limitations. Over time and with extensive use, they can become damaged and less effective at reducing noise exposure. Despite the importance of wearing protective gear, some workers may choose to remove their ear muffs due to discomfort or the desire to hear their colleagues more clearly. This poses a challenge as it increases their risk of being exposed to excessive noise levels, which can lead to hearing damage or loss.
To address this issue, employers should focus on providing comfortable and properly fitting protective gear that minimizes discomfort. Additionally, regular training and awareness programs can emphasize the importance of consistent use of protective gear and educate workers about the potential long-term consequences of noise exposure. Encouraging an open dialogue between workers and management can also help address any concerns or misconceptions related to the use of protective gear.
Ultimately, striking a balance between comfort and safety is crucial. Employers should strive to provide effective and comfortable protective gear, while workers need to understand the importance of consistent usage to safeguard their hearing health in noisy work environments.
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if a volume of air at 375 k increases from 10.0 l to 15.0 l, what is the final kelvin temperature? assume pressure remains constant.
To determine the final Kelvin temperature, we can use the combined gas law equation, which states that (P1V1/T1) = (P2V2/T2), assuming constant pressure.
Given:
Initial volume (V1) = 10.0 L
Final volume (V2) = 15.0 L
Initial Kelvin temperature (T1) = 375 K
Rearranging the equation to solve for the final temperature (T2), we have:
T2 = (P2 * V2 * T1) / (P1 * V1)
Since the pressure (P) is assumed to remain constant and not given, we can cancel it out from both sides of the equation.
Therefore, the final Kelvin temperature (T2) would be:
T2 = (V2 * T1) / V1
Substituting the given values, we get:
T2 = (15.0 * 375) / 10.0
T2 = 5625 / 10
T2 = 562.5 K
Thus, the final Kelvin temperature is 562.5 K.
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Two packing crates of masses 10.0kg and 5.00kg are connected by a light string that passes over a frictionless pulley as shown in Figure. The 5.00kg crate lies on a smooth incline of angle 40.0 degree . Find the acceleration of the crates and the tension in the string.
The acceleration of the string is 4.3 m/s2.
What is Acceleration?We regard the positive direction for the vertical motion of mass m1 to be downward and the positive direction for the motion of mass m2 on the incline to be to the right and parallel to the incline.
There are only two ways to accelerate: changing your speed or changing your direction, or changing both. This is because velocity is both a speed and a direction.
Changing the speed at which an object is travelling is what acceleration is all about. A substance is not accelerating if its velocity is not changing. The information on the right depicts an object that is speeding as it moves northward.
Therefore, The acceleration of the string is 4.3 m/s2.
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.
How does sound travel? *
Air molecules move in a straight line in one direction.
Air molecules move in waves that sometimes bounce back.
Air molecules move in waves in one direction.
None of the above.
Answer: 2 i think
Explanation:
Answer:Im pretty sure its the second one because sound sometimes bounces back and that causes echo and it doesnt travel in one line or direction
Explanation:
Let h : Z → R be the point mass function of some distribution.
a) Let Ω = Z × Z. Show that if we define each ω = (ω1, ω2) ∈ Ω,
pω = hω1 hω2, then (pω)ω∈Ω is the point mass function of some distribution.
b) Consider the random variable X : Ω → Z, X(ω) = ω1 + ω2. Show that X's
the point mass function of the distribution, i.e. PX, is

Hints: the a) point is largely a repetition of the old one, but the latter point may require some thought. In particular, you should think about why it is enough to calculate
probability P({ω ∈ Ω : X(ω) = x}). For this, you should think about
that what this event has to do with the event
x - n}
and why it can be applied to calculate the probability of this event
definition of probability distribution.
We have demonstrated that (pω)ω∈Ω is the point mass function of some distribution, and that the random variable X has a point mass function PX equal to (pω)ω∈Ω.
In order to show that (pω)ω∈Ω is the point mass function of some distribution, we need to demonstrate that it satisfies the properties of a probability distribution.
a) Let's consider the properties of a probability distribution. Firstly, the values of pω must be non-negative for all ω ∈ Ω. This is true since pω is defined as the product of two non-negative values hω1 and hω2.
Secondly, the sum of probabilities over all possible outcomes must be equal to 1. In this case, we need to show that the sum of (pω)ω∈Ω over all possible ω in Ω is equal to 1. To do this, we can consider the sum:
Σ(pω)ω∈Ω = Σ(hω1 hω2)ω∈Ω
By the properties of the point mass function h, we know that Σhω1 = 1 and Σhω2 = 1. Therefore, the above expression becomes:
Σ(pω)ω∈Ω = Σ(hω1 hω2)ω∈Ω = 1 * 1 = 1
Thus, we have shown that (pω)ω∈Ω satisfies the properties of a probability distribution.
b) Now let's consider the random variable X(ω) = ω1 + ω2 and show that its point mass function PX is equal to (pω)ω∈Ω.
To calculate PX(x) = P({ω ∈ Ω : X(ω) = x}), we need to consider the event where the sum of the components ω1 and ω2 is equal to x. This can be expressed as:
{ω ∈ Ω : X(ω) = x} = {(ω1, ω2) ∈ Ω : ω1 + ω2 = x}
Now, notice that this event is equivalent to the event {ω1 = n, ω2 = x - n} for any fixed n. The probability of this event is given by pω1 pω2 = hω1 hω2, which matches the point mass function (pω)ω∈Ω.
By considering all possible values of n, we can cover all the cases for X(ω) = x, and therefore, we have shown that PX(x) is equal to (pω)ω∈Ω.
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If the merry-go-round starts at rest, what is its angular speed after the person has rotated it through an angle of 32.5
Angular speed after the person has rotated it through an angle of 32.5 is 0.361rad/s.
According to the given information :Tangential force applied to the merry-go-round,
F = 35.1 N
Radius of merry-go-round,
R = 2.94 m
mass of merry-go-round,
m = 207kg
initial angular speed of merry-go-round,
ωi=0rad/s
angular displacement of the merry-go-round,
θ = 32.5∘
The moment of inertia of the disc-shaped merry-go-round is expressed as
I = m×R22
Taking the angular acceleration of the merry-go-round as α
Since the applied force is tangential to the rim, its angle with the radius is
θ = 90∘
Applying Newton's second law of rotation
Net external torque = Moment of inertia x angular acceleration
R × F × sinθ = I×α
R × F × sinθ = m×R22×αα
= 2 × F × sinθ / m × R
= 2 × 35.1N × sin90∘
207kg × 2.94
m = 0.115rad/s2
The angular displacement in radians is calculated as:
θ = 32.5∘ / 180∘ × π rad
≈ 0.567rad
Applying the equation of motion for rotation, the angular speed is calculated as:
ω2 = ω2i +2 × α × θ
ω =√ω2i+2×α×θ
= √(0rad/s)2 + 2 × 0.115rad / s2 × 0.567rad
≈ 0.361rad/s
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I understand the question you are looking for :
A person exerts a tangential force of 35.1 N on the rim of a disk-shaped merry-go-round of radius 2.94 m and mass 207 kg. If the merry-go-round starts at rest, what is its angular speed after the person has rotated it through an angle of 32.5 degrees?
Would Lincoln, Nebraska or San Diego, California have a smaller range in average monthly temperatures
Answer: San diego
Because it is closer to the ocean
a battery with a 15 v emf has a terminal voltage of 5.5 v when it delivers a current of 5.3 a to the starter of a car. what is the internal resistance of the battery? answer in units of ω.
The internal resistance of the battery is approximately 1.79 Ω.
Resistance is a measure of the opposition to current flow in an electrical circuit. Resistance is measured in ohms, symbolized by the Greek letter omega (Ω). Ohms are named after Georg Simon Ohm (1784-1854), a German physicist who studied the relationship between voltage, current and resistance.
A battery with a 15 V emf has a terminal voltage of 5.5 V when it delivers a current of 5.3 A to the starter of a car. To find the internal resistance of the battery, use the formula:
Internal resistance (R) = (EMF - Terminal voltage) / Current
R = (15 V - 5.5 V) / 5.3 A
R = 9.5 V / 5.3 A
R ≈ 1.79 Ω
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What does this graph (EQ) tell us about humans compared to other animals? A. Humans have the most massive brains of any animal. B. Humans have a brain mass
This graph (EQ) tell us about humans compared to other animals is B. Humans have a brain mass that is unusually large for an animal of our body mass.
The encephalization quotient (EQ) is a comparative tool that is used to assess brain development and to predict intelligence or abilities in animals. It compares the brain mass of a particular animal with that of other animals of the same weight. The higher the EQ of an animal, the greater the degree to which its brain has evolved. Humans, who have the most developed brains, have an EQ of 7.5, which is significantly higher than other primates and most other animals.
Humans are the only animals with an EQ of 7.5, indicating that their brains are unusually large for their body weight. While elephants and dolphins have larger brains than humans, their brains are not as developed or complex as human brains, and their EQs are lower. Hence, the graph shows that humans have a brain mass that is unusually large for an animal of our body mass. So the correct option is B. Humans have a brain mass that is unusually large for an animal of our bodymass.
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does a stiff material have a larger or smaller bulk modulus?
The materials such as rubber or foam are considered to be less stiff and have lower bulk moduli.
What is material bulk modulus?A stiff material has a larger bulk modulus.
Bulk modulus is a measure of a material's resistance to uniform compression. It is defined as the ratio of the applied pressure to the resulting relative volume change. A higher bulk modulus indicates that a material requires a higher pressure to achieve a given volume change.
Stiffness is a measure of a material's resistance to deformation under an applied force. A stiffer material requires a higher force to achieve a given amount of deformation.
The bulk modulus and stiffness of a material are related, as the bulk modulus describes how the material behaves under compression, which is related to stiffness. In general, a stiffer material will have a larger bulk modulus, as it requires more pressure to achieve the same volume change compared to a less stiff material.
For example, metals such as steel or titanium are considered to be very stiff and have high bulk moduli, while materials such as rubber or foam are considered to be less stiff and have lower bulk moduli.
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convert as indicated step by step 1)1 sec into day 2) 1 week into sec (3) 50cm into meter
Answer:
1) 1,157*10⁻⁵ day; 2) 604800 sec.; 3) 0.5 m.
Explanation:
1) 1 second into one day:
one day consists of 24 hours, it means 24*3600=86400 seconds. Then 1 second is 1/86400 day or 1,157*10⁻⁵ day.
2) 1 week into seconds:
1 day consists of 3600*24=86400 seconds, then the week is 7*86400=604800 seconds.
3) 50 cm into meter:
100 cm is one meter, then 50 cm is 0.5 meter.
PS. note, there is not the only way to perform conversion.
What is the difference between Newtonian Science (AKA Classical science) and Quantum Science (AKA Quantum Physics/ Quantum Mechanics)
The main difference between Newtonian Science (Classical Science) and Quantum Science (Quantum Physics/Quantum Mechanics) lies in their fundamental principles and the scales at which they apply. Newtonian Science describes the motion of macroscopic objects in a deterministic manner using classical mechanics, while Quantum Science deals with the behavior of microscopic particles and is characterized by probabilistic predictions and wave-particle duality.
Newtonian Science (Classical Science): Newtonian Science is based on the laws of classical mechanics formulated by Sir Isaac Newton. It describes the motion of macroscopic objects, such as planets, projectiles, and everyday objects. It assumes that objects have definite positions and velocities, and their behavior is deterministic. The laws of motion, such as Newton's laws, provide precise predictions of the behavior of objects.
Quantum Science (Quantum Physics/Quantum Mechanics): Quantum Science is a branch of physics that deals with the behavior of particles at the atomic and subatomic level. It was developed in the early 20th century to explain phenomena that classical physics couldn't account for. Quantum mechanics introduces the concept of wave-particle duality, where particles exhibit both wave-like and particle-like properties. It uses mathematical formalism, such as wave functions and probability distributions, to describe the behavior of particles. Quantum mechanics is probabilistic in nature, providing predictions of the likelihood of different outcomes rather than precise deterministic predictions.
The main difference between Newtonian Science (Classical Science) and Quantum Science (Quantum Physics/Quantum Mechanics) lies in the scales at which they apply and their fundamental principles. Newtonian Science describes the motion of macroscopic objects using classical mechanics and provides deterministic predictions. On the other hand, Quantum Science deals with the behavior of microscopic particles, introduces wave-particle duality, and provides probabilistic predictions. Quantum mechanics revolutionized our understanding of the microscopic world, challenging the deterministic worldview of classical mechanics and laying the foundation for many modern technological advancements.
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a force that tries to slow things down when two things are rubbed together
Answer:
Friction
Explanation:
friction is the force that tries to slow things down when two things are rubbed together.
Answer:
That is friction don't know
Explanation:
how I know that
A 25.2 kg gazelle moving 2.33 m/s
sees a lion, and exerts a 113 N
force to accelerate. How fast is
it moving 2.00 s later?
The velocity of the gazelle after 2 seconds is equal to 11.3 m/s.
What is the equation of motion?The equations of motion have described the relationship between the time, velocity, acceleration, and displacement of a moving object.
The equations of motions can be described as shown below:
\(v = u + at\\S = ut +\frac{1}{2}at^2 \\ v^2-u^2 = 2aS\)
Given the mass of the gazelle, m = 25.2 Kg
The force acting to accelerate, F = 113N
The acceleration in the speed of gazelle is given by: a = F/m
a = 113/ 25.2
a = 4.48 m/s²
The initial speed of the gazelle, u = 2.33 m/s
From the first equation of motion we can calculate the final velocity of the gazelle:
v = u + at
v = 2.33 + (4.48) (2)
v = 11.3 m/s
Therefore, the velocity of the gazelle 2 seconds later is 11.3 m/s.
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The asteroid Ida has a tiny moon named Dactyl, enabling Ida's
mass to be determined using Kepler's 3rd law of 4.3x1016
kg. The average radius of Ida is 15.7 km. Calculate the density of
Ida in g/cm3.
By plugging in the values and performing the calculations, we can determine the density of Ida is approximately 0.0057 g/cm^3.
To calculate the density of Ida, we need to find its volume first and then divide its mass by the volume. We are given the mass of Ida as 4.3x10^16 kg and the average radius as 15.7 km.
Step 1: Convert the radius to meters (1 km = 1000 meters).
Radius of Ida (r) = 15.7 km = 15.7 x 1000 meters = 15,700 meters.
Step 2: Calculate the volume of Ida using the formula for the volume of a sphere.
Volume (V) = (4/3) x π x r^3
V = (4/3) x 3.14159 x (15,700)^3
V ≈ 7.52 x 10^12 m^3
Step 3: Convert the volume to cubic centimeters (1 m^3 = 1,000,000 cm^3).
Volume (V) ≈ 7.52 x 10^12 m^3 = 7.52 x 10^12 x 1,000,000 cm^3 ≈ 7.52 x 10^18 cm^3
Step 4: Calculate the density of Ida by dividing its mass by its volume.
Density = Mass / Volume
Density = 4.3 x 10^16 kg / 7.52 x 10^18 cm^3 ≈ 0.0057 g/cm^3
Finally we get the density of Ida is approximately 0.0057 g/cm^3.
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What is the unit for intensity? Describe the relationship between intensity and area of the wave.
The unit for intensity is watts per square meter (W/m²) and the intensity of a wave is proportional to the square of the amplitude of the wave and inversely proportional to the square of the distance from the source of the wave.
Intensity is a measure of the power or energy of a wave per unit area, and it is proportional to the square of the amplitude of the wave. This means that the intensity of a wave increases as the amplitude of the wave increases, and it decreases as the distance from the source of the wave increases.
The relationship between intensity and area of the wave can be described by the inverse square law. According to this law, the intensity of a wave is inversely proportional to the square of the distance from the source of the wave. This means that as the distance from the source of the wave increases, the intensity of the wave decreases, and as the area of the wave increases, the intensity decreases.
For example, if you move twice as far away from a source of sound waves, the intensity of the sound waves will decrease by a factor of four. Similarly, if you double the area over which the waves are spread out, the intensity of the waves will be halved.
In summary, the unit for intensity is watts per square meter.
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a stone with weight w is thrown vertically upward into th eair with initial velocityv 0 • if a constant forcef due to air drag acts on the stone throughout the flight
When a stone is thrown vertically upward with an initial velocity and experiences a constant force due to air drag, the force opposes the motion of the stone, reducing its upward velocity. This force opposes the motion of the stone and decreases its velocity.
The force due to air drag can be calculated using the equation F = bv, where b is a constant that depends on the properties of the stone and the air, and v is the velocity of the stone.
As the stone moves upward, the force due to air drag acts in the opposite direction to its motion, reducing its upward velocity. At the highest point of its trajectory, the stone momentarily comes to rest before falling back down due to the force of gravity.
To understand the effect of the force due to air drag, let's consider an example. Suppose the stone is thrown upward with an initial velocity of 20 m/s and experiences a force due to air drag that is proportional to its velocity, with a constant b = 0.5.
As the stone moves upward, its velocity decreases due to the force of air drag. At a certain height, the upward velocity becomes zero, and the stone starts falling back down. The force of gravity acting on the stone increases its downward velocity until it reaches the ground.
The force due to air drag affects the stone's trajectory by reducing its maximum height and changing the time it takes to reach the ground. The magnitude of the force depends on the stone's velocity, so the greater the initial velocity, the stronger the force of air drag.
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which element has 5 valence electrons and 4 shells
Answer:
Arsenic
Explanation:
Arsenic is in group 5 and period 4. Group numbers tell us the number of valence electron and period number tells us the number of shells in an element.
What is one similarity between Platyhelminthes and Nematoda?
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Answer:
They are both unsegmented worms
Also:
They are both multicellular, invertebrates, heterotrophs, bilateral symmetry
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Water flows smoothly through a pipe with various circular cross-sections of diameters 2D, 6D,and D`, respectively.
What is the ratio of the speed in section 3 to the speed in section 1?
In which section is the pressure largest? Choose the best answer.
Therefore, the largest pressure is in section 1. Therefore, the answer is Section 1.
Water flows smoothly through a pipe with various circular cross-sections of diameters 2D, 6D, and D', respectively. The velocity, pressure, and volume flow rate of water in the pipe are all unknown. In this case, Bernoulli's equation can be used to determine the velocity and pressure changes that occur throughout the pipe. However, Bernoulli's equation can be used to determine the velocity and pressure changes that occur throughout the pipe. The following is the formula for Bernoulli's equation:
p1 + (1/2)ρv1² + ρgh1 = p2 + (1/2)ρv2² + ρgh2
Where:
p1 is the pressure at section 1,
ρ is the density of water,
v1 is the velocity at section 1,
g is the acceleration due to gravity,
h1 is the height at section 1,
p2 is the pressure at section 2,
v2 is the velocity at section 2, and
h2 is the height at section 2.
Let's take the velocity ratio first. Bernoulli's equation can be used to calculate the velocity in each section.
p1 + (1/2)ρv1² + ρgh1 = p2 + (1/2)ρv2² + ρgh2
p2 = p1, h1 = h2, and ρ are all constants, and thus can be canceled. Using Bernoulli's equation, we get:
(1/2)ρv1² = (1/2)ρv2² + (1/2)ρv3²
v3/v1 = (v1² - v2²)½ / (v1² - v3²)½ = (D'² - D²)½ / (D'² - 4D²)½
So, the ratio of the speed in section 3 to the speed in section 1 is (D'² - D²)½ / (D'² - 4D²)½.
Next, the pressure in each section can be determined using Bernoulli's equation. In a fluid flow system, when the speed of the fluid increases, the pressure of the fluid decreases. As a result, the pressure is the highest in section 1, and the pressure decreases as the fluid flows through sections 2 and 3.
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