if something measures 1" on the drawing, it is 8'-0" long in reality. If something measures 1" on the drawing, it is 1/8" long in reality is incorrect.
When a drawing is shown at 1/8" = 1'-0" scale, it means that if something measures 1/8" on the drawing, it is 1'-0" or 10 feet long in reality.
The correct statement about the scale 1/8" = 1'-0" is: If something measures 1/8" on the drawing, it is 1'-0" or 10 feet long in reality.
The scale 1/8" = 1'-0" is a common engineering scale used in architectural drawings. It means that every 1/8" on the drawing represents 1'-0" or 12 inches in reality. So, if something measures 1/8" on the drawing, it is 1'-0" or 10 feet long in reality. On the drawing, the entire drawing is equal to or less than 1/8 " square. If something measures 1" on the drawing, it is 8'-0" long in reality.This is because 1 inch on the drawing represents 8 feet in reality. So, if something measures 1" on the drawing, it is 8'-0" or 96 inches long in reality. Therefore, if something measures 1" on the drawing, it is 8'-0" long in reality. If something measures 1" on the drawing, it is 1/8" long in reality is incorrect.
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1. manganese dioxide is used in dey cell . ( Give reason)
2. Fuses are used in a circuit. ( Give reason )
Answer:
1.In dry cells, manganese dioxide acts as a ‘depolariser'.
In the depolarization process, the depolariser is used to remove hydrogen and doesn't allow the voltage to get reduced due to polarisation of the cell . Manganese oxide was used as a depolariser in Leclanché cell .
In zinc-carbon dry cell, the manganese dioxide takes in electrons as it is converted to Manganese III oxide (Mn2O3)
2.The fuse breaks the circuit if a fault in an appliance causes too much current flow. This protects the wiring and the appliance if something goes wrong. The fuse contains a piece of wire that melts easily. If the current going through the fuse is too great, the wire heats up until it melts and breaks the circuit.
Do you think that it is possible to conduct a similar type of experiment using animals?
Answer: Animals are used in many different kinds of experiments. These are just a few examples and alternatives to using animals in experiments.
Explanation:
why has si system been developed? give reasons
Answer:
It allows people in different places and different countries to use the same units, avoid mistakes and understand each other more easily. The common base 10 of all units makes it easier and has more accurate calculations that are made without cumbersome conversion factors.
Answer:
Explanation:
As we know that the SI units are extended versions of the MSK system. SI system helps us to calculate the appropriate measurement of any quantity. SI system is convenient(easy) to use and it is also followed all over the world which can help in international trade as well. So, SI system been developed.
Does a calculation lose any information when converted from centimeters to meters? Explain
Answer:
No
Explanation:
There are many units that are used to measure length of an object. For example centimeters, meters, millimeters etc.
There is a relationship between any of two units to measure lengths. If we want to convert some length from cm to m, it can be done as follows :
1 cm = 0.01 m
or
1 m = 100 cm
When we use this conversion, the calculation remains the same. Only the way to represent it will be different.
Hence, there is no lose of information when converted from centimeters to meters.
What’s the resistance of the circuit
Which types of changes must follow the law of conservation of mass?
Both physical and chemical changes
Neither physical nor chemical changes
Only physical changes
Only chemical changes
Answer:
Both physical and chemical changes
Answer:
Both physical and chemical changes follow the law since when the system is closed to all transfers of matter and energy, the mass of the system must remain constant over time, irrespective of the state.
Explanation:
pls mark brainliest
if you had something the size of a sugar cube that was made of white dwarf matter, it would weigh about as much as
If you had a sugar cube that was made of white dwarf matter, it would weigh about as much as an elephant.
White dwarfs are the smallest type of stars in the universe, and they have a density of around 100 million times greater than that of water. This means that if you took a sugar cube that was made entirely out of white dwarf matter and put it on your kitchen counter, it would weigh about as much as an elephant!
But don't worry—you're not going to find any white dwarfs at your local grocery store or restaurant. White dwarfs are formed when red giants collapse in on themselves after burning through their fuel. And if you did happen to find one, you'd need a really big countertop.
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5. When an aluminum rod is placed in the middle of an inductor, the resonance frequency of the LRC circuit should
When an aluminum rod is placed in the middle of an inductor, the resonance frequency of the LRC circuit should: decrease
The inductance of an inductor depends on its physical dimensions and the material it is made of. Placing an aluminum rod in the middle of an inductor changes its effective inductance due to the presence of the conductive material. Since the effective inductance is reduced, the resonance frequency of the LRC circuit is decreased. This is because the resonance frequency depends on the values of the inductance, capacitance, and resistance in the circuit, and a decrease in inductance results in a decrease in the resonance frequency. This effect can be utilized in various applications, such as in proximity sensors and metal detectors.
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Who ever gets it right I will give 20 points and Brainly
Answer:
the reflection of the candle in the concave mirror formed upside down real image that is diminished
1. A record with a radius of 0.3m spins in a clockwise circle with a centripetal
acceleration of 4.7 m/s2. How long does it take the record to make one revolution?
(Hint: Find tangential velocity first!)
Solve for the linear/tangential speed:
a = v²/r
where a = centripetal acceleration, v = speed, and r = radius.
4.7 m/s² = v²/(0.3 m)
v² = (0.3 m) (4.7 m/s²)
v ≈ 3.96 m/s
For every time the record completes one revolution, a fixed point on the edge of the record travels a distance equal to its circumference, which is 2π (0.3 m) ≈ 1.88 m. So if 1 rev ≈ 1.88 m, then the angular speed of the record is
(3.96 m/s) (1/1.88 rev/m) ≈ 7.46 rev/s
Take the reciprocal of this to get the period:
1 / (7.46 rev/s) ≈ 0.134 s/rev
So it takes the record about 0.134 seconds to complete one revolution.
What is the input distance for a claw hammer if the output distance is 2.0 cm and the mechanical advantage is 5.5?
Answer:
0.36cm
Explanation:
Given parameters:
Output distance = 2.0cm
M.A = 5.5
Unknown:
Input distance = ?
Solution:
The mechanical advantage is the value of the force multiplier.
M.A = Output distance / Input distance
Input distance = Output distance / mechanical advantage
Input distance = \(\frac{2.0cm}{5.5}\) = 0.36cm
How much useful energy is given out by an appliance supplied by 500 J and wastes
250 J?
it is believed that when electrons spin on their axes as they orbit the nucleus of the atom, the spinning motion causes each electron to become .
Spin is an intrinsic property of electron. This is useful to find comprehensive details about the electron in atom, such as, energy perturbation, angular momentum etc.
What is spin quantum number?
The term "spin quantum number" refers to the fourth quantum number that is presented to characterize the orientation of the electron spin (rotation) in space. It can move either clockwise or counterclockwise.
Quantum numbers provide comprehensive details about the electron in atom including its energy, position, size, shape, orientation, and spin direction. The spin quantum number describes the spin's orientation.An atom's electron spins about its own axis in addition to moving around the nucleus. This number provides details regarding the electron's direction of spin in each given orbital.Like rest mass and charge, the spin angular momentum is an intrinsic feature.An electron's magnitude spin quantum number cannot be altered.The spin can be in the orientation 2s+1=2.Learn more about spin here:
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How quickly would a 65kg object accelerate if the person applied a 500N force?
Answer:
\(a = 7.69\: {m(s)}^{ - 2} \)
Explanation:
\(f = ma \\ a = \frac{f}{m} = \frac{500}{65} = \frac{100}{13} \\ a = 7.6923076923 \: {m(s)}^{ - 2} \)
If you throw a 0.3kg ball straight up with an initial speed of 39m/s, how fast will it be moving when it’s 21m above the release point?
The question relies on conservation of energy
2 Energy equations:
Kinetic Energy = 1/2mv^2
Gravitational potential energy = mgh
Initial energy = final energy
1/2m(v0)^2 = mgh + 1/2m(vf)^2
Divide mass out to save time
1/2(v0)^2 = gh + 1/2(vf)^2
PLug in what we know:
v0 = 39 m/s
h = 21 meters
1/2(39)^2 = 9.8(21) + 1/2(vf)^2
1/2(39)^2 - 9.8(21) = 1/2(vf)^2
554.7 = 1/2(vf)^2
1109.4 = (vf)^2
vf = 33.3076 m/s
-. A game show contestant won a prize by pushing a bowling ball 20 meters using her nose. The amount of workdone was 1470 Joules. How much force did the game show contestant exert on the ball?
If dan ran the 100m dash in 10.23s. What was his average speed during the race? (Round to the nearest tenth of a second)
Answer:
.1 seconds per meter
Explanation:
I am going to assume they are asking for the average time per 1 meter.
Because it took 10.23 seconds to run 100 meters, we are going to divide 10.23 by 100. This number will be the time per 1 meter.
To divide by 100, we will move the decimal point over by two. That will give us .1023 seconds.
The question asks to round to the nearest tenth, so we round it to .1 seconds.
*Just some trivia: Danie van Blerk does in fact have a time of 10.23 seconds. He has the 1073rd best 100 meter dash time. First place, Usain Bolt, has a time of 9.58 seconds.
What is the student's kinetic energy at the bottom of the hill if he is moving
at 18 m/s?
Variables:
Show Work
Answer:
KE = 10530 J or 10.53 KJ
Explanation:
The formula for kinetic energy is KE = 1/2 mv^2
Let's apply the formula:
KE = 1/2 mv^2
KE = 1/2 (65kg) (18m/s)^2
KE = 10530 J or 10.53 KJ
the electric field in an electromagnetic wave is in the y-direction and described by Ey = E0cos(kx - ωt), where E0 = 165 N/C.
a. if the elegtromagnetic wave is traveling in the x-direction in vacuum, what is the direction of the magnetic field?
b. express the smplitudo of the magnetic field B0, in terms of E0 and the speed of light c.
c. find the intensity of the electromagnetic wave, I, in terms of E0, c, and the permeability of free space µ0.
d. solve for the numerical value of I in watts per square meter.
The numerical value of the intensity (I) in watts per square meter is given by:
I = (1/2) * (E0^2 / (µ0 * c))
a. The direction of the magnetic field can be determined using the right-hand rule. According to the right-hand rule, if the electric field is in the y-direction (Ey), then the magnetic field (B) will be in the z-direction. This means the magnetic field is perpendicular to both the electric field and the direction of propagation (x-direction).
b. The relationship between the electric field (E) and the magnetic field (B) in an electromagnetic wave is given by the equation: B = E/c, where c is the speed of light in vacuum.
From the given information, we have E0 = 165 N/C as the amplitude of the electric field. Therefore, the amplitude of the magnetic field (B0) can be expressed as:
B0 = E0 / c
c. The intensity of an electromagnetic wave (I) is related to the amplitude of the electric field (E0), the speed of light (c), and the permeability of free space (µ0) by the equation:
I = (1/2) * ε0 * c * E0^2
However, in the given question, it mentions the permeability of free space (µ0) instead of the electric constant (ε0). The electric constant is related to the permeability of free space by the equation: ε0 = 1 / (µ0 * c^2).
Substituting the value of ε0, the intensity (I) can be expressed as:
I = (1/2) * (1 / (µ0 * c^2)) * c * E0^2
I = (1/2) * (E0^2 / (µ0 * c))
d. To solve for the numerical value of the intensity (I) in watts per square meter, we need the value of the permeability of free space (µ0). The permeability of free space is approximately 4π × 10^-7 T·m/A.
Substituting the value of µ0 into the equation, we can calculate the numerical value of I.
To obtain the numerical value, substitute the known values:
µ0 ≈ 4π × 10^-7 T·m/A
c ≈ 3.0 × 10^8 m/s
E0 = 165 N/C
Substituting these values into the equation, we have:
I = (1/2) * (165^2 / (4π × 10^-7 * (3.0 × 10^8)^2))
Simplifying the equation and evaluating it will give the numerical value of I in watts per square meter.
Please note that due to the complex calculations involved, it is recommended to use a calculator or a software program to obtain the precise numerical value of I.
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An electrical resistor immersed in a liquid produces 65. 0 W of electrical energy for 120
seconds, which heats the 0. 780 kg mass of liquid, causing it to rise in temperature from
18. 55°C to 22. 54°С. Find the average specific heat capacity of the liquid in this temperature
range. Assume that negligible heat is transferred to the container that holds the liquid and that
no heat is lost to the surroundings
The average specific heat capacity of the liquid in this temperature is 2506 J/kg/C
The specific heat capacity, or massic heat capacity, of a substance is calculated using thermodynamics as the heat capacity of a sample of the substance divided by the mass of the sample.A substance's specific heat capacity may be substantially higher when heated in an open vessel that permits expansion than when heated in a closed vessel that prevents expansion, especially when the substance is a gas (specific heat capacity at constant pressure) (specific heat capacity at constant volume).
the amount of heat input to the liquid is 65W x 120s = 65(J/s) x 120s = 7800J
then we have that
Q = \(m\times c \times \delta t\) so that
c = (\(\frac{Q}{m\times\delta t}\)) = \(\frac{7800J}{0.78kg * 3.99C}\) = 2506 J/kg/C
if some of the energy heated the container or surroundings, then less energy actually went into heating the liquid; if less energy caused the 3.99C temp increase, the specific heat must be less, so the value we just calculated is an overestimate.
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You whirl a 2-kg body attached to a 1-meter cord around your head in a nearly horizontal circle with a speed of 4 m/s. the tension in the cord is:________
The tension in the cord is equal to centripetal force which is 32 newton.
We need to know about centripetal force to solve this problem. When an object moves in a circular motion, the object is experiencing centripetal force. The magnitude of centripetal force is
Fc = m . v²/R
where Fc is the centripetal force, m is mass, v is velocity and R is the radius.
From the question, we know that
m = 2 kg
v = 4 m/s
R = 1 m
The tension in the cord is equal to centripetal force
T = Fc
T = m . v²/R
T = 2 . 4² / 1
T = 32 N
Hence, the tension in the cord is 32 newton.
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Frank has a eraser it has a mass of 4g and a volume of 2cm what is it’s density?
Answer:
2 g / cm^3
Explanation:
Density = mass / volume
= 4 g / 2 cm^3 = 2 g / cm^3
The table contains the planets in our solar system in order of their average distance from the Sun and their corresponding diameters. The first step in creating a model of the solar system is to scale these large diameters into smaller, more manageable numbers. Eventually, we’ll represent these numbers using circles drawn on paper. MercuryVenusEarthMarsJupiterSaturnUranusNeptune Diameter (km)487912,10412,7566792142,984120,53651,11849,528 Scaled Diameter (cm) 3.51.9 The ratio between Earth’s actual diameter and its scaled diameter can be used to find the scaled diameter of the other planets. Earth’s diameter of 12,756 kilometers is scaled to 3.5 centimeters as shown in the table. Now let’s find the scaled diameter of Mars as an example. Using the calculations shown, Mars’s diameter of 6,792 would be scaled to 1.9 centimeters. d × 12,756 = 6,792 × 3.5 d = 1.9 cm Use this same process to complete the table with the scaled diameters of the other planets. Round each answer to the tenths place. If you need additional math help, visit the Proportions section of the Math Review.
The scaled diameters of the missing planets are listed below:
Mercury 1.4 cm
Venus 3.3 cm
Mars 1.9 cm
Jupiter 39.2 cm
Saturn 33.1 cm
Uranus 14.0 cm
Neptune 13.6 cm
How to determine the scaled diameters of a planet
In this question we must use conversion factor to calculate the scaled diameters by means of the following direct relationship:
d = k · D (1)
Where:
D - Real diameter, in kilometers.d - Scaled diameter, in centimeters.k - Conversion factor, in centimeters per kilometer.The conversion factor is found by using the real and scaled diameter of the Earth:
k = 3.5 cm/12,756 km
k = 7/25512 cm/km
Then, we determine the scaled diameters of the rest of planets:
Mercury 1.4 cm
Venus 3.3 cm
Mars 1.9 cm
Jupiter 39.2 cm
Saturn 33.1 cm
Uranus 14.0 cm
Neptune 13.6 cm
Remark
The statement reports a table with numerous mistakes, the correct table is shown below:
Planet Diameter (km) Scaled Diameter (cm)
Mercury 4,879
Venus 12,104
Earth 12,756 3.5
Mars 6,792
Jupiter 142,984
Saturn 120,536
Uranus 51,118
Neptune 49,528
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What 2 factors impact gravitational pull?
mass and distance
matter and energy
size and shape
speed and direction
Answer:
When dealing with the force of gravity between two objects, there are only two things that are important – mass, and distance. The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them
A pendulum swings back and forth. If the mass of the pendulum is 3kg and it starts from a height of 1m.How much kinetic energy does it have at 0.5m?
From the principle of energy conservation, the kinetic energy of the pendulum at 0.5 m is 14.7 J.
What is a pendulum?A pendulum swings back and forth and can be used to show the change of potential energy to kinetic energy and vice versa.
Given that the kinetic energy is converted to the potential energy; the potential energy at 0.5 m is 3 * 9.8 * 0.5 = 14.7 J.
Following the principle of energy conservation, the kinetic energy of the pendulum at 0.5 m is 14.7 J.
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what will happen if one of the magenet is put assembly backwards
If one of the magnets is put into assembly backward, it will reverse the magnetic polarity of the assembly.
What is magnetic polarity?
The direction in which the magnetic field lines travel is referred to as magnetic polarity. When a magnet is divided in half, each piece retains its magnetic polarity, with north on one side and south on the other. The magnetic pole refers to the location on the magnet's surface where the magnetic field is at its strongest.
Different poles of a magnet:
Magnetic north and south poles are found on opposite ends of a magnet. When two magnets are brought near each other, opposite poles attract, and like poles repel. When two opposite poles are brought together, the magnetic fields are drawn together, increasing the magnetic field strength. When two like poles are brought together, the magnetic fields are pushed away from each other, decreasing the magnetic field strength.
What happens when one of the magnets is put assembly backward?
If one of the magnets in an assembly is reversed, it will reverse the magnetic polarity of the entire assembly, causing the magnetic fields of the magnets to repel rather than attract each other. If you try to connect the two ends of the assembly, the magnets will push each other away rather than attract each other. The strength of the magnetic field will also be diminished, causing the assembly to have less magnetism.
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Imagine another solar system, with a star of the same mass as the Sun. Suppose a planet with a mass twice that of Earth (2MEarth) orbits at a distance of 1 AU from the star. What is the orbital period of this planet? Hint: Think about how the mass of the Sun compares with the mass of the Earth. a. 3 months b. 6 months
c. 1 year d. 2 years
e. It would not be able to orbit at this distance.
The correct answer is option D.2 years
What is Kepler's third law of planetary motion?According to Kepler's Third Law of Planetary Motion, T² is proportional to r³, where T is the period of revolution of the planet and r is the distance between the planet and the star.
In order to solve for T,
AU = 1
Astronomical Unit = the average distance between the Earth and the Sun = 149.6 million kilometres
Therefore, the planet is orbiting at a distance of 149.6 million kilometres from the star.
Substituting the values of r and solving for
T².T² ∝ r³T² ∝ (149.6)³T²
= (149.6)³T²
= 3.522 x 10¹²T
= √3.522 x 10^¹²T
= 1.87 x 10⁶ seconds
T = 31,100 minutes
T = 518 hours
T = 21.6 days
T = 2 years
Therefore, the orbital period of the planet with twice the mass of Earth orbiting at a distance of 1 AU from a star with the same mass as the Sun is 2 years.
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if the glider oscillates back and forth on the air-track, at what point in the motion is the acceleration zero? where is the velocity maximum? show with a drawing.
If the glider oscillates back and forth on the air-track, at what point in the motion is the acceleration zero when the glider reaches the extreme points of its motion, i.e., at the endpoints of the oscillation.
In the motion of a glider oscillating back and forth on an air-track, the acceleration is zero when the glider reaches the extreme points of its motion, i.e., at the endpoints of the oscillation. These points are called the turning points or the points of maximum displacement.
On the other hand, the velocity is maximum at the center of the motion, which is the midpoint between the two turning points. At this point, the glider changes its direction of motion and its velocity reaches its maximum value.
Here's a simplified diagram illustrating the motion of the glider:
| |
| |
| |
| |
| |
---+-------+---
Turning Turning
Point Point
At the turning points, the acceleration is zero (the glider momentarily stops before changing its direction), while at the midpoint between the turning points, the velocity is maximum (the glider is moving at its highest speed).
Note that this diagram represents a one-dimensional motion, where the glider moves back and forth along a straight line. In reality, the glider's motion may involve more complex trajectories, but the concept of acceleration being zero at the turning points and maximum velocity at the midpoint still holds true.
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Which scenario describes a systematic error?
A. A person bumps the table as a volume is measured.
B.A measurement is recorded before a balance comes to rest.
C.A thermometer reads 0.1 degree higher than it should.
D.An incubator unexpectedly loses power for ten minutes during the night.
Answer: C
A Systematic error occurs when there is a problem with the instrument , so the answer should be c .
Explanation:
Answer:
A Systematic Error Occurs When There Is A Problem With The Instrument, so The Answer Is C
Explanation:
2. Montesquieu's view of the separation of powers was later expressed in the United States Government through which document? A. The Declaration of Independence b. The United States Constitution c. The Two Treatises of Government d. The Social Contract
Answer: b. The United States Constitution
Explanation:
Montesquieu argued that the best form of government, was one where the legislative arm, executive arm, and judicial powers were separate. and in doing so helped kept each other in check to prevent any branch from becoming too powerful. Montesquieu’s separation of powers was not accurate when compared the government of England, But this was later adopted by Americans as the foundation of the U.S. Constitution.