What're three main orbital overlapping?​

Answer:

B) Because modern corals live in warm, shallow seas, we can infer the same

environment existed during the Devonian period, where the Kimberleys are

today

Explanation:

Based on the law of Uniformitarianism we can infer the environment that existed during the formation of the Devonian limestone and the Barrier Reef today.

Answer: B

Explanation: USA test prep, K12

Answer:

The most common forms of N fertilizer include anhydrous ammonia, urea, and urea-ammonium nitrate (UAN) solutions.

Explanation:

The energy to launch the model spacecraft come from the spacecraft that is moving against the magnetic field.

The energy to launch the model spacecraft come from the spacecraft that is moving against the magnetic field. the called potential energy in the magnetic field is moving is used to move the magnet against the magnetic field. magnetic force can be converted into the potential energy in to the kinetic energy. An electric current is created by electromagnetic. it will create the model of magnetic system.

Thus, The energy to launch the model spacecraft come from the spacecraft that is moving against the magnetic field.

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Answer:

The formula of ammonis is given as NH3

Explanation:

The given IUPAC name of ammonia is nitrogen trihydride.

From the name of IUPAC name of the ammonia it is evident that there is only one atom of nitrogen is present in one molecule of ammonia.

Word 'trihydride ' means a that there are three hydrogen atoms present as hydride in one ammonia molecule.

So, the formula of ammonia will be guven as: NH3

Answer:

it's NH3.....

Explanation:

so......

The pressure change of a system can be determined from the change in volume using Boyle's law. The new pressure of the system if the volume is increased by a factor of 2.3 is 224.8 kPa.

According Boyle's law the volume of a system is inversely proportional to the pressure of the system thus PV = constant . Thus as pressure increases volume will decrease.

If p1 and v1 be the initial pressure and initial volume respectively and p2,v2 be the final quantities, then the we have the relation,

p1v1 = p2v2.

Here the initial pressure is 517.1 kPa and volume increases by a factor of 2.3 therefore, v2 = 2.3 V1. Now, the final pressure p2 is calculated as follows:

517.1 kPa × v1 =  p2 × 2.3 v1

 P2 = (517.1 kPa × v1 l)/2.3 v1 l

      = 517.1 kPa / 2.3

      = 224.8 kPa

Therefore, the new pressure of the system if the volume is increased by a factor of 2.3 is 224.8 kPa.

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Answer:

the ability to do work.

Explanation:

The pair of elements which forms an ionic bond are Ba and O.

Ionic bond is also called as a electrovalent bond, it is type of linkage formed from the electrostatic attraction between oppositely charged ions in a chemical compound. Generally, an ionic bond is formed when the valence or the outermost electrons of one atom are transferred permanently to the another atom.

Here, in this type of case where barium is metal and oxygen is non-metal. Generally, ionic bonds are formed between metallic elements and nonmetallic elements. Hence, the bond formed between metal and non-metal will be ionic in nature. Therefore, BaO has an ionic bond and it is a ionic compound.

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To find the concentration of sulfide ion when hydroxide ion begins to precipitate, we need to determine the point at which the reaction between sodium sulfide and iron(III) nitrate produces a precipitate.

This reaction can be represented by the following balanced equation: Na2S(aq) + Fe(NO3)3(aq) → FeS(s) + 2NaNO3(aq) First, let's write the balanced equation for the reaction between potassium hydroxide and iron(III) nitrate:

3KOH(aq) + Fe(NO3)3(aq) → Fe(OH)3(s) + 3KNO3(aq)

From the balanced equation, we can see that for every 3 moles of potassium hydroxide (KOH), we get 1 mole of Fe(OH)3(s) precipitate.

Therefore, when hydroxide ion begins to precipitate, the concentration of sulfide ion will be equal to the concentration of potassium hydroxide. Given that the concentration of sodium sulfide is 1.27×10^(-2) M and the concentration of potassium hydroxide is 1.35×10^(-2) M, the concentration of sulfide ion [S^2-] at the point of precipitation is also 1.35×10^(-2) M. Therefore, the concentration of sulfide ion when hydroxide ion begins to precipitate is 1.35×10^(-2) M.

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Answer:

the answer should be: 12.00 Mol KCIO³ × 3 Mol 0² divided by 2 mol KCIO³ = 18.00 mol 0²

False , The most abundant cation in intracellular fluid is potassium (K+), not sodium (Na+). Potassium ions are found in higher concentrations inside cells, contributing to the positive charge within the intracellular environment.

Sodium ions, on the other hand, are more abundant in extracellular fluid. The concentration gradient of sodium and potassium across the cell membrane plays a crucial role in various cellular processes, including the generation of action potentials and the maintenance of cell volume and osmotic balance.

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Answer:0

Explanation: zero because it is the most stable form of oxygen in its standard state

The moles of hydrogen produced in the reaction has been 0.105 mol. Hence, option D is correct.

The balanced chemical equation for the decomposition of Ammonia has been:

\(\rm 2\;NH_3\;\rightarrow\;N_2\;+\;3\;H_2\)

From the balanced chemical equation, decomposition of 2 moles of ammonia produces, 3 moles of hydrogen and 1 mole, nitrogen.

The moles of hydrogen produced along with 0.0351 mol nitrogen has been:

\(\rm 1\;mol\;N_2=3\;mol\;H_2\\ 0.0351\;mol\;N_2=0.0351\;\times\;3\;mol\;H_2\\ 0.0351\;mol\;N_2=0.105\;mol\;H_2\)

Thus, the moles of hydrogen produced in the reaction has been 0.105 mol. Hence, option D is correct.

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Answer:

mid-ocean ridge.

Explanation:

Option B) n=4 to n=2 and C) n=2 to n=1  would emit a photon of light with the greatest energy.

The energy of a photon emitted during a hydrogen atom transition is determined by the difference in energy between the initial and final energy levels. This can be calculated using the equation:

ΔE = -13.6 eV * (1/n_f^2 - 1/n_i^2)

Where ΔE is the energy difference in electron volts (eV), and n_f and n_i are the final and initial energy levels, respectively.

Considering the given options, we can calculate the energy differences:

A) ΔE = -13.6 eV * (1/3^2 - 1/5^2) = -13.6 eV * (1/9 - 1/25) = 1.51 eV

B) ΔE = -13.6 eV * (1/2^2 - 1/4^2) = -13.6 eV * (1/4 - 1/16) = 10.2 eV

C) ΔE = -13.6 eV * (1/1^2 - 1/2^2) = -13.6 eV * (1 - 1/4) = 10.2 eV

D) ΔE = -13.6 eV * (1/4^2 - 1/5^2) = -13.6 eV * (1/16 - 1/25) = 0.858 eV

E) ΔE = -13.6 eV * (1/3^2 - 1/6^2) = -13.6 eV * (1/9 - 1/36) = 2.27 eV

Comparing the energy differences, we can see that option C) n=2 to n=1 and option B) n=4 to n=2 have the greatest energy differences. Therefore, these two transitions would emit photons of light with the greatest energy.
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A longitudinal wave is one in which the particles of a medium are moved in an orientation parallel to the path of energy transmission.

A longitudinal wave may be formed in a slinky by stretching it horizontally and vibrating the end coil back and forth in a motion that is horizontal.

There is a centre line where what the medium would lie if there was no wave, which is commonly referred to as the undisturbed state. The movement of the medium above this disturbed location is referred to as a crest, whereas the displacement below this undisturbed position is referred to as a trough.

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Answer:

HCl + KOH ⇒ KCl + H₂O

Explanation:

Which of the following is an acid-base neutralization reaction?

Sn + 2HBr ⇒ SnBr₂ + H₂. NO. This is a single displacement reaction.

HCl + KOH ⇒ KCl + H₂O. YES. An acid reacts with a base to form salt and water.

2AlCl₃ + 3Ca(OH)₂ ⇒ 2Al(OH)₃ + 3CaCl₂. NO. This is a double dispacement reaction.

2C₂H₆ +7O₂ ⇒ 4CO₂ + 6H₂O. NO. This is a combustion reaction.

The moles of Fe³⁺ present at equilibrium is 3.8 × 10⁻³ moles and the correct option is option 2.

Chemical equilibrium is the state of a system in which the rate of the forward reaction is equal to the rate of the reverse reaction.

Chemical equilibrium is a dynamic process. The forward and reverse reactions continue to occur even after equilibrium has been reached. However, because the rates of the reactions are the same, there is no change in the relative concentrations of reactants and products for a reaction that is at equilibrium.

Given,

The reaction of [Fe(SCN)]²⁺ :

                                   Fe³⁺ + SCN⁻ ⇆ [Fe(SCN)]²⁺

The initial number of moles of Fe³⁺ = 4 × 10⁻³

Number of moles of [Fe(SCN)]²⁺ at equilibrium = 2 × 10⁻⁴

    Number of moles of Fe³⁺ at equilibrium =

   (initial number of moles of Fe³⁺ - moles of [Fe(SCN)]²⁺ at equilibrium)

                         = ( 4 × 10⁻³ - 2 × 10⁻⁴)

                          = 3.8 × 10⁻³ moles

Therefore, the number of moles of Fe³⁺  of at equilibrium is 3.8 × 10⁻³ moles.

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Answer:

option first is the right answer

Answer:

By writing an experiment report

Explanation:

Muhammad Ali is a professional boxer and American activist. He is known as "The Greatest" and is regarded as one of the greatest sports stars of all time.

Ali famously said, "I am the greatest!" after defeating the much favoured Sonny Liston in six rounds on February 25, 1964, to win the heavyweight title.

He became a Muslim in 1961. He won the heavyweight world championship by defeating Sonny Liston on February 25, 1964, when he was only 22 years old. He considered to his old name as a "slave name" and changed it to Muhammad Ali that year.

The first heavyweight championship battle, for the WBC/Ring/Lineal title, was on November 22, 1965, and the second, for the North American Boxing Federation (NABF) heavyweight title, happened on September 20, 1972.

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Concentration refers to the amount of solute present in a given volume of solvent. The concentration of a gas, on the other hand, can be measured in terms of the number of molecules in a particular volume of air. The concentration of CO2 in air is therefore 0.002%.

In order to calculate the concentration of CO2 in air, you would need to know the total number of molecules present and the number of CO2 molecules present. If there are 0.002 molecules of CO2 per 100 molecules of air, the concentration of CO2 in air can be expressed as 0.002%. This means that for every 100 molecules of air, there are two molecules of CO2 present. Concentration refers to the amount of solute present in a given volume of solvent. The concentration of a gas, on the other hand, can be measured in terms of the number of molecules in a particular volume of air. In order to calculate the concentration of CO2 in air, you would need to know the total number of molecules present and the number of CO2 molecules present. To calculate the concentration, you would use the following formula:
Concentration = (Number of CO2 molecules / Total number of molecules) x 100%
In this case, the number of CO2 molecules is 0.002 and the total number of molecules is 100. Therefore, the concentration of CO2 can be calculated as:
Concentration = (0.002 / 100) x 100% = 0.002%
This means that for every 100 molecules of air, there are two molecules of CO2 present. The concentration of CO2 in air is therefore 0.002%.

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Answer:

See the answer below

Explanation:

When magnesium is heated in air, the element combines with oxygen to form a compound known as magnesium oxide according to the following equation:

    \(2Mg(s) + O_2 (g)--> 2MgO (s)\)

Hence, the product formed - a combination of magnesium and the oxygen component of air - is heavier than the original magnesium ribbon.

On the other hand, potassium manganate (7) is heated in air and decompose to form potassium manganate (6), manganate oxide, and oxygen gas according to the following equation:

    \(2KMnO_4 --> K_2MnO_4 + MnO_2 + O_2\)

Hence, the final product formed is lighter than the original product because oxygen gas has been evolved.

Answer:

During the heating of magnesium in air, it gains mass with the addition of oxygen present in air to form the oxide. However, during the heating of potassium manganate (vii), it decomposes or breaks down to simpler products and oxygen gas is given off.

Explanation:

During the heating of magnesium in air, it gains mass with the addition of oxygen present in air to form the oxide.

The equation for the reaction is given below:

2Mg(s) + O2(g) ---> 2Mg0

The molar mass of the magnesium metal is 24.0 g while the mass of the magnesium oxide is 40.0 g. The total mass of the metal before heating is 24 × 2. + 32 = 48.0 g. The total mass after heating = 48 + 32 = 80.0 g. Therefore, there is an increase in mass.

However, during the heating of potassium manganate (vii), it decomposes or breaks down to simpler products and oxygen gas is given off. The equation for the reaction is given below;

2KMnO4(s) ----> K2MnO4(s) + MnO2(s) + O2(g)

With the evolution of oxygen gas, there's a loss in mass of potassium manganate (vii). Molar mass of KMnO4 is 158.0 g while the mass of K2MnO4 is 197.0 g and that of MnO2 is 87.0 g. The total mass on the right hand side is 2 × 158 = 316.0 g. The total mass on the left-hand side with the exception of the gas evolved is 284.0 g. Therefore, there is a loss in mass.

Answer:  Count only the electrons in the highest shell s and p orbitals when determining valence.

Explanation:  I'm glad you asked this question.  It is often not well explained.   The term valence electrons is assigned to only the electrons in an element's highest energy level.  These reside only in the s and p orbitals, and not the d or f, as I'll explain later.  The s orbital can hold 2 electrons and the p can hold 6.  Potassium, K, has an s orbital in its highest energy shell, 4.  It contains only 1 electron, so it has a valency of 1.  

Calcium, Ca, has 2 in its highest energy level: 4s^2, so it has a valency of 2.   Moving to the right, the element scandium, Sc, add another electron, but it goes into the 3d orbital.  3d is in the 3rd energy shell, so it is not counted as a valence electron.  Only after we move further right, to gallium, Ga, do we start adding electrons to the 4th energy level again - the 4p orbitals can accept up to 6 electrons.  Ga has 3 valence electrons - 2 in the 4s and 1 in the 4p.  Oxygen has 2 in the 2s and 4 in the 4p orbitals, for a total of 6.  It is close to having a comple outer shell (2 in the 2s and 6 in the 2p).  Just 2 more electrons would fill both the 2s and 2p orbitals for a total of 8 valence electrons, a stable configuration (the same configuration as thje stable gas Neon).

In combustion analysis, the amounts of carbon dioxide (CO2) and water (H2O) produced from the combustion of a hydrocarbon can be used to determine the empirical formula of the hydrocarbon.

From the given information, we have produced 33.01 g of CO2 and 5.42 g of H2O.

To determine the empirical formula, we need to find the moles of carbon and hydrogen in the products. We can then use these moles to calculate the mole ratio of carbon to hydrogen and simplify it to the smallest whole number ratio.

First, let's find the moles of CO2 and H2O produced:

Moles of CO2 = mass / molar mass = 33.01 g / 44.01 g/mol (molar mass of CO2) = 0.750 mol

Moles of H2O = mass / molar mass = 5.42 g / 18.02 g/mol (molar mass of H2O) = 0.301 mol

Next, we need to determine the mole ratio of carbon to hydrogen. From the balanced combustion equation of a hydrocarbon, we know that one mole of carbon dioxide is produced for each mole of carbon in the hydrocarbon, and one mole of water is produced for each mole of hydrogen in the hydrocarbon.

Mole ratio of carbon to hydrogen = Moles of CO2 / Moles of H2O = 0.750 mol / 0.301 mol ≈ 2.49

Since we need to simplify the ratio to the smallest whole number ratio, we can round it to the nearest whole number. Thus, the empirical formula of the hydrocarbon is approximately C2H5.

It's important to note that this simplified empirical formula assumes the simplest ratio of carbon to hydrogen atoms in the hydrocarbon. However, without additional information, we cannot determine the exact molecular formula of the hydrocarbon. Additional analysis, such as the determination of the molar mass of the hydrocarbon, would be needed to determine its molecular formula.

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Answer:

See explanation

Explanation:

The question is incomplete because the images of the models are absent. However, i will try to give you a general description of what the correct answer should be.

Beryllium is a member of group 2 in the periodic table. Beryllium has an atomic number of 4. This implies that it has four protons in its nucleus and four electrons in its shells. In a neutral atom, the number of electrons on the shells is equal to the number of protons in the nucleus.

The electronic configuration of Beryllium is 1s2 2s2. This implies that it should have two shells each containing only two electrons each.

Since we are using white foam balls for protons and black foam balls for neutrons, the clear plastic will contain four white foam balls and five  black foam balls since the mass number of beryllium is 9 and number of neutrons = mass number - number of protons.

Four blue foam balls hanging from strings will represent the electrons around the nucleus.

Any model that corresponds to the description above is the correct answer.

Answer:

my answer isnt any better than hers

Explanation:

Answer:

The Ideal gas law

Explanation:

From the given question, we have:

V \(\alpha\) \(\frac{nT}{P}\)

where each variable has its usual meaning.

Thus,

V = \(\frac{nRT}{P}\)

where R is the ideal gas constant

cross multiply to have;

PV = nRT

This implies that the volume of the gas is directly proportional to the number of moles of the gas.

Therefore, the law can be used to determine the relationship between the volume and number of moles is the ideal gas law.

The temperature of the nitrogen in units of kelvin is 288 kelvin

The sample of pure nitrogen has a temperature of 15 degree Celsius.

Let's convert the temperature from degree Celsius to kelvin.

K = C + 273

where

Therefore,

K = 15 + 273

K = 15 + 273

K = 288 kelvin

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Answer:

When sodium hydroxide (NaOH) dissolves in water, it separates into positively - charged sodium ions (cations) and negatively - charged hydroxide ions (anions).

Hope this helped.

Radiocarbon dating, also known as carbon-14 dating, is a method used to determine the age of organic materials. It is based on the radioactive decay of the isotope carbon-14 (14C).

Living organisms constantly absorb carbon, including a small amount of carbon-14, from the atmosphere. When an organism dies, it no longer takes in carbon-14, and the existing carbon-14 begins to decay at a known rate. By measuring the ratio of carbon-14 to stable carbon isotopes (carbon-12 and carbon-13) in a sample, scientists can estimate the time that has elapsed since the organism's death. Radiocarbon dating is effective for dating materials up to about 50,000 years old.

Therefore, both radiocarbon dating and radiopotassium dating rely on the principles of radioactive decay. The decay rates of the isotopes used in these methods are well-established and constant, allowing for accurate age determinations.

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