What would the density of a liquid that has a mass of 275 grams and a volume of 200 mL?

Answer:

on the top of the hill there is energy gravitational potential.

Explanation:

The energy of a body is the possibility of doing work, in the case of the bicycle on the hill, it has a configuration energy due to being higher than the lower part of the hill.

If we let go of the bicycle it accelerates downwards due to the component of the force of gravity, converting this potential energy into work and kinetic energy.

It should be clarified that the total energy is always the same.

Consequently, on the top of the hill there is energy gravitational potential.

Answer:

Yes, the rider and bicycle have energy at the top of the hill. That’s because they move without pedaling when the brake is released. If the rider and bicycle were at the bottom of the hill, just releasing the brake wouldn’t create motion. The rider would need to pedal.

Explanation:

This is the sample answer on edmentum.

The local convection heat transfer coefficient for uniform flow perpendicular to a heated circular disk can be determined through empirical correlations or experimental measurements.

These methods take into account various factors such as fluid properties, flow velocity, disk diameter, and surface conditions to estimate the heat transfer coefficient.

When a heated circular disk is exposed to a fluid flow that is perpendicular to its surface, the local convection heat transfer coefficient characterizes the rate of heat transfer between the disk and the surrounding fluid. Determining this coefficient requires empirical correlations or experimental measurements. These correlations or experiments consider several factors that influence heat transfer.

Factors such as fluid properties (such as viscosity and thermal conductivity), flow velocity, disk diameter, and surface conditions (such as roughness or presence of a boundary layer) play a role in determining the heat transfer coefficient. By conducting experiments or using empirical correlations derived from experimental data, engineers and researchers can estimate the local convection heat transfer coefficient for a specific flow situation. These estimates are crucial for designing and optimizing heat transfer systems and ensuring efficient cooling or heating processes.

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Answer:

what is the question?

Igneous landscapes are formed through the solidification and cooling of molten rock, known as magma or lava. They exhibit various features such as volcanic cones, lava flows, volcanic craters, and volcanic mountains. The type of igneous rock present depends on factors like composition, cooling rate, and mineral presence. erosion and weathering processes can also shape these landscapes over time.

Igneous landscapes are formed through the solidification and cooling of molten rock, which is known as magma when it is beneath the Earth's surface and lava when it reaches the surface. This process can occur through volcanic activity, where magma erupts onto the surface, or through the solidification of magma beneath the Earth's surface.

One of the key characteristics of igneous landscapes is the presence of igneous rocks. These rocks are formed when magma or lava cools and solidifies. The type of igneous rock that forms depends on factors such as the composition of the magma, the rate of cooling, and the presence of other minerals.

Igneous landscapes can exhibit various features. volcanic cones, such as cinder cones and composite cones, are formed by the accumulation of volcanic materials around a vent. lava flows occur when lava spreads out over the surface, creating flat or gently sloping areas. volcanic craters are depressions at the summit of a volcano, often formed by explosive eruptions. volcanic mountains, such as shield volcanoes and stratovolcanoes, are formed by repeated eruptions over time.

It is important to note that igneous landscapes can also be influenced by erosion and weathering processes over time. These processes can shape the landforms and alter the appearance of igneous landscapes.

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Igneous landscapes are formed by volcanic activity.

Igneous landscapes are characterized by the presence of volcanic landforms, such as volcanoes, lava flows, and volcanic cones. These landscapes are shaped by the cooling and solidification of molten rock (magma) from volcanic eruptions.

The formation of igneous landscapes is directly linked to volcanic activity, where magma rises to the Earth's surface and solidifies, creating various landforms. These landscapes can exhibit diverse features, including volcanic mountains, lava plateaus, and volcanic craters. Understanding the characteristics and processes involved in igneous landscapes helps geologists and scientists study the Earth's history, volcanic hazards, and the impact of volcanic activity on the surrounding environment.

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t^2 distance will it roll in t seconds if a ball rolls down an inclined plane with an acceleration of 2 ft/sec2

S=ut+at^2/2

a= 2ft/sec^2

u=0

s=?

t=t

put the data in equation

s=0+2×t^2/2

s=t^2

Distance is the length between two locations or things, independent of direction. Since distance is a scalar property, it only takes into consideration the total magnitude and ignores the start and finish positions. Since distance is a scalar attribute, it can only have a positive or zero value; it cannot have a negative value.

The most common unit of measurement for distance is the meter (m), while larger distances can also be stated in kilometers (km), while smaller distances can be expressed in centimeters (cm) or millimeters (mm). When calculating distance, the letter D is often used to represent the distance traveled.

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The negatively charged van de Graff generator can make a flow of electrons through the tape and these both will repel each other. When the tape comes in contact with the balloon, the positive charges of balloon gets attracted and they stick together.

Electrons are drawn from the earth by a Van de Graaff generator, transported via a belt, and then stored on the big sphere. These electrons are attracted to one another and try to distance themselves from one another by dispersing throughout the surface of the sphere.

Electrons can spread out widely on the earth, thus they will choose the shortest route possible to return to the ground. The electrons from the tape repel the electron from the tape, make the tape negatively charged.

This negatively charged tape when comes in contact with the balloon, it will polarize the balloon and its positive charges aligns with the tape's charge and gets stuck.

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Answer:

9.8 m/ssr=2322

Explanation:

The minimum work function for a metal to eject photoelectrons with a zero stopping potential would need to be less than the energy of visible light, which ranges from 380 to 750 nm.

Visible light consists of photons with energies ranging from approximately 1.65 to 3.26 electron volts (eV), corresponding to wavelengths between 380 and 750 nm.

When light shines on a metal surface, it can cause the ejection of electrons through the photoelectric effect. The minimum work function refers to the minimum energy required to remove an electron from the metal's surface.

For photoelectrons to be ejected with a zero stopping potential, the energy of the photons must be greater than or equal to the work function of the metal. If the work function is too high, even with the application of light, the energy of the photons may not be sufficient to overcome the metal's binding energy, and no electrons would be ejected.

Therefore, the minimum work function for the metal needs to be less than the energy of visible light photons. This ensures that when light is incident on the metal, it provides enough energy to liberate electrons, resulting in the observed photoelectric effect.

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At a depth of 500 meters in the mine, the estimated vertical stress is 13.5 MPa, and the estimated horizontal stress is 11.57 MPa. Specific details to consider are Chalk Strength, Chalk Permeability, Chalk Heterogeneity.

Before proceeding with the excavation of the cavern beneath the sea, the main geological information that would be important to have includes the properties and characteristics of the chalk formation. Some specific details to consider are:

a) Chalk Strength: It is essential to determine the strength and stability of the chalk formation to ensure that it can support the excavation without collapsing or experiencing excessive deformation. This would involve assessing parameters such as the cohesion, friction angle, and compressive strength of the chalk.

b) Chalk Permeability: Understanding the permeability of the chalk is crucial, especially since the cavern will be beneath the sea. The permeability will impact the water flow within the chalk and may affect stability, seepage, and potential groundwater inflow into the excavation.

c) Chalk Heterogeneity: Chalk formations can exhibit variations in their composition, including the presence of layers or discontinuities such as faults or joints. Understanding the geological structure and heterogeneity of the chalk will help in assessing the potential for rock mass instability, water ingress, or the presence of other geological hazards.

To estimate the vertical and horizontal in-situ stresses at a depth of 500 meters in the mine, we can use the principles of rock mechanics and consider the given parameters.

Vertical Stress:

The vertical stress is the stress component acting vertically downward due to the weight of the overlying rock. It can be calculated using the average unit weight of the rock and the depth.

Vertical Stress = Unit Weight of Rock × Depth

Vertical Stress = 27 kN/m³ × 500 m

Vertical Stress = 13,500 kN/m² or 13.5 MPa

Horizontal Stress:

The horizontal stress can be estimated using the in-situ stress ratio, which is influenced by Poisson's ratio. The relationship between the horizontal and vertical stresses can be expressed as:

Horizontal Stress = Vertical Stress × (2 × Poisson's Ratio) / (1 - Poisson's Ratio)

Horizontal Stress = 13.5 MPa × (2 × 0.3) / (1 - 0.3)

Horizontal Stress = 13.5 MPa × 0.6 / 0.7

Horizontal Stress = 11.57 MPa

Therefore, at a depth of 500 meters in the mine, the estimated vertical stress is 13.5 MPa, and the estimated horizontal stress is 11.57 MPa.

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We have that The acceleration due to gravity on the Moon And

The acceleration due to gravity on the surface of the Earth is approximately

\(1.625 m/s^2\)

\(9.81 m/s^2,\)

From the Question we are asked

The value of G on earth and moon?

Where G refers to The acceleration due to gravity

Generally

The acceleration due to gravity on the Moon is approximately

\(1.625 m/s^2,\)

And

The acceleration due to gravity on the surface of the Moon is approximately

\(9.81 m/s^2,\)

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The magnitude of the angular velocity of the merry-go-round is equal to 2.39 rad/s after a 23 kg child gets onto it.

Angular momentum can be described as the rotational form of linear momentum. It is a physical conserved quantity as the total angular momentum remains constant.

Given, the mass of the child m = 23 Kg

The mass of the merry-go-round M = 125 Kg

The initial speed of the merry-go-round, ω₁ = 0.52 rev/s = 3.27 rad/s

The radius, r = 1.8 m

From the conservation of the angular momentum, we can find the angular velocity:

\(I_1\omega_1= (I_1+mr^2)\omega\)

\((\frac{1}{2} Mr^2)\omega_1= (\frac{1}{2} Mr^2+mr^2)\omega\)

\(\omega =\frac{M.\omega_1}{M+2m}\)

\(\omega = \frac{125\times 3.27}{125 +2\times23}\)

ω = 2.39 rad/s

Therefore, the magnitude of its angular velocity after a 23 kg child gets onto it by grabbing its outer edge is 2.39 rad/s.

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Your question was incomplete, but the most probably complete question was,

A playground merry-go-round with a mass of 125 Kg and a radius of 1.8 m is rotating with a frequency of 0.52 rev/s. what is the magnitude of its angular velocity, in radians per second, after a 23 kg child gets onto it by grabbing its outer edge? the child is initially at rest.

Answer:

Core: the temperature at the very center of the Sun is about 27 million degrees Farenheit (F). The temperature cools down through the radiative and convective layers that make up the Sun's core.

Explanation:

it is about 27 million degrees Fahrenheit

good luck :D

Answer:

reacts to mos metlal

Explanation:

Answer:

A factor of 2*4 = 8

Explanation:

F_g = (G*m1*m2)/r^2  

where m1 and m2 are the two masses, G is Newton's gravitational constant, and r is the distance between the center of mass of the two objects.

So, if you double m1 and quadruple m2:

m1' = 2*m1

m2' = 4*m2

Then F_g' = (G*m1'*m2')/r^2 = (G*2*m1*4*m2)/r^2 = 8*(G*m1*m2)/r^2 = 8*F_g

The speed of rocket alpha as measured from rocket bravo is 0.31c due to head-on collision.

In physics, the change in momentum causes a head-on collision. As was already explained, an object's momentum is a property that results from a change in velocity in reaction to an applied force. Before a collision may occur, the momentum must equal zero and this is called head-on collision.

The target particle's velocity following a head-on impact in which the projectile is significantly more massive than the target will be roughly twice that of the projectile, but the projectile's velocity will remain practically unaltered.

speed of rocket alpha=0.90 c

speed of rocket bravo=0.52c

Now, in order to find the speed of rocket alpha measured from rocket bravo =0.90-0.52c

speed=0.31c

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The speed of the rocket alpha when observed from rocket bravo is calculated to be 1.42c.

Alpha rocket is travelling at a speed of 0.90c, while Bravo rocket is flying at a speed of 0.52c.

The two rockets are heading straight at one another in the same direction to collide.

When the rocket's frame of reference is the Bravo rocket, the rocket's speed can both be perceived from the earth's perspective and

Therefore, the rocket Bravo is moving, and the rocket Alpha will approach it more quickly.

If Rocket Alpha's speed is V₁ and Rocket Bravo's speed is V₂, then Rocket Alpha's speed from Rocket Bravo is V₁₂.

V₁₂ = 0.52 -(-0.90)

V₁₂ = 1.42c

Therefore, the rocket alpha's speed from the rocket bravo is 1.42c.

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The net force on an object is zero that is pulled with forces of 80 newtons to the right and 80 newtons to the left.

Net force is equal to sum of all the force acting on a body.

The formula for net force if n force are acting on it:

                       \(F_{net}=F_{1}+ F_{2}+F_{3}.....F_{n}\)

In this case the two forces are equal but opposite in direction.

Putting the values in the formula

\(F_{net} = 80+(-80)\) (since forces are equal but opposite)

\(F_{net}= 0\)

So the net force acting on the object is zero because the forces are equal and opposite.

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The net force on an object that is pulled with forces of 80 newtons to the right and 80 newtons to the left is: 0 newtons

To solve this problem the formula of net force and the procedure that we have to use is:

Fr = ∑F

Where:

Information about the problem:

Applying the resultant force formula we get:

Fr = ∑F

Fr = F1 + F2

Fr = 80 newtons - 80 newtons

Fr= 0 newtons

We can say that the resultant force is the algebraic sum of all the forces acting on a body.

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The time it takes the object to fall freely at a distance of 120m is  7.75 sec.

Velocity is the directional pace of an item in motion as an indication of its rate of exchange in the role as determined from a selected frame of reference and as measured by way of a selected standard of time.

Calculation:-

mass = 20 kg

height = 200 m

new height = 120

S = ut +1/2at²

120 = 0 + 0.5× 10 t²

t² = 120/5

    =  60

   = 7.75 sec

Average velocity is calculated by means of dividing your displacement (a vector pointing out of your initial role in your final position) through the entire time; the average pace is calculated by way of dividing the overall distance you traveled by means of the total time.

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The frictional force experienced on the coin, when it is at a distance of 14 cm is 0.77N and the coefficient of static friction when the coin slides off will be 0.964.

To find the answer, we need to know more about the friction.

                    \(m=140*10^{-3} kg\\w=1 rev/s=2\pi rad/s\\r_1=14*10^{-2}m\\g=9.81m/s^2\\\)

                    \(f=F_c=ma_c=m*r_1w^2\\f=140*10^{-3}*14*10^{-2}*4*\pi ^2=0.77N\)

                              \(f_s=kN,\\\\Where, \\N=mg\\\\k=\frac{f_s}{mg}\)

                         \(F_c=f_s=mrw^2=140*10^{-3}*24*10^{-2}*4\pi ^2\\f_s=1.325N\)

                   \(k=\frac{1.325}{140*10^{-3}*9.81}=0.964\)

Thus, we can conclude that, the frictional force experienced on the coin, when it is at a distance of 14 cm is 0.77N and the coefficient of static friction when the coin slides off will be 0.964.

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The closest answer choice is E. 5 x 10¹⁹ photons/m².s.

We can use the formula relating intensity and photon energy to calculate the photon flux:

Intensity = Photon Energy x Photon Flux

The energy of a photon with a wavelength of 400 nm can be calculated using the formula:

Photon Energy = hc/λ

where h is Planck's constant (6.626 x 10⁻³⁴ J.s), c is the speed of light (3.00 x 10⁸m/s), and λ is the wavelength in meters. Thus, we have:

Photon Energy = hc/λ = (6.626 x 10⁻³⁴ J.s)(3.00 x 10⁸ m/s)/(400 x 10⁻⁹m) = 4.97 x 10⁻¹⁹ J

Substituting the given values into the first equation and solving for photon flux, we get:

Photon Flux = Intensity / Photon Energy = 2500 W/m² / 4.97 x 10⁻¹⁹ J = 5.02 x 10¹⁸ photons/m².s

Therefore, the closest answer choice is E. 5 x 10¹⁹ photons/m².s.

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Answer:

height = 1.5 x 10⁶ m = 1500 km

Explanation:

We can use the formula of gravitational force from the Newton's Gravitational Law:

\(F = \frac{Gm_{1}m_{2}}{r^2}\)

where,

F = Gravitational Force = 6.6 x 10³ N

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

m₁ = mass of earth = 6 x 10²⁴ kg

m₂ = mass of satellite = (1.02 tons)(1000 kg/1 ton) = 1.02 x 10³ kg

r = distance between center of earth and satellite = ?

Therefore, using these values in the equation, we get:

\(6.6\ x\ 10^3\ N = \frac{(6.67\ x\ 10^{-11} N.m^2/kg^2)(6\ x\ 10^{24} kg)(1.02\ x\ 10^3\ kg)}{r^2}\\\\r^2 = \frac{(6.67\ x\ 10^{-11} N.m^2/kg^2)(6\ x\ 10^{24} kg)(1.02\ x\ 10^3\ kg)}{6.6\ x\ 10^3\ N}\\\\\)

\(r = \sqrt{61.84\ x\ 10^{12}\ m^2 }\)

\(r = 7.86\ x\ 10^6 m\)

The distance between center of earth and the satellite is equal to the sum of height of satellite and radius of earth:

\(r = height + radius\ of\ earth\\7.86\ x\ 10^6 m = height + 6.36\ x\ 10^6 m\\height = 7.86\ x\ 10^6 m - 6.36\ x\ 10^6 m\)

height = 1.5 x 10⁶ m = 1500 km

Answer:

A note of frequency 300 Hz is produced when the length of a wire is 80 cm and the tension is 40 N. What is the frequency...

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Explanation:

A note of frequency 300 Hz is produced when the length of a wire is 80 cm and the tension is 40 N. What is the frequency if the length of the wire is halved and the tension is doubled? NECO 200834 Ans: 848.4 Hz

i don't really get the question

sorryyyy

Answer:mass

Explanation:

a. The amplitude of the ball's motion is 0.350 m. b. The frequency of the ball's motion is 2.55 Hz. c. The mass is 0.781 kg. d. The total mechanical energy of the oscillator is 12.25 J. e. The maximum speed of the ball is 5.60 m/s.

a. The amplitude of the ball's motion is given by the coefficient of the cosine term, which is 0.350 m. Therefore, the answer is (ii) 0.350 m.

b. The angular frequency of the ball's motion is given by the coefficient of time in the argument of the cosine term, which is 16.0 rad/s. The frequency is given by f = ω/2π = 16.0/2π ≈ 2.55 Hz. Therefore, the answer is (ii) 2.55 Hz.

c. The mass of the ball can be found using the formula for the angular frequency of a mass-spring system: ω = √(k/m), where k is the spring constant and m is the mass. Solving for m, we get m = k/ω² = 200/(16.0)² ≈ 0.781 kg. Therefore, the answer is (ii) 0.781 kg.

d. The total mechanical energy of the oscillator is given by the sum of its kinetic and potential energies: E = (1/2)mv² + (1/2)kx², where m is the mass, v is the velocity, k is the spring constant, and x is the displacement. At maximum displacement, the velocity is zero and the energy is entirely potential, so E = (1/2)kA², where A is the amplitude. Substituting the given values, we get E = (1/2)(200)(0.350)² ≈ 12.25 J.

e. The maximum speed of the ball occurs when it passes through the equilibrium position, where the displacement is zero. At this point, the velocity is at a maximum and is given by v = ωA = (16.0)(0.350) ≈ 5.60 m/s. Therefore, the answer is 5.60 m/s.

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Answer:

good morning mam going nme mam morning mam going on in the correct

Answer: 554.9 seconds

Explanation:

345.7/0.623=554.9 seconds

The  tension in the string of a conical pendulum is 18.6 N.

The  tension in the string of a conical pendulum can be determined using the following formula:

T = mg(L / L + lcos(θ))

where:

The  tension in the string of a conical pendulum is calculated as

T = 2.5 x 9.8 x (0.68 / (0.68 + (2.5 x 9.8 x cos(35°)))

T = 18.6 N.

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Additional information, we cannot determine the sending end quantities, voltage regulation, or transmission efficiency.

The states that the line delivers 400 MVA at 0.8 lagging power factor.

The given ABCD constants of a three-phase, \(345-kV\) transmission line are:
\(A = D = 0.98182 + j0.0012447\)
\(B = 4.035 + j58.947\)
\(C = j0.00061137\)

To determine the sending end quantities, voltage regulation, and transmission efficiency, we can follow these steps:
1. Calculate the line impedance (Z):
  \(Z = (A + B)(C) / (B + D)\)
  Substituting the given values:
\(Z = (0.98182 + j0.0012447 + 4.035 + j58.947)(j0.00061137) / (4.035 + j58.947 + 0.98182 + j0.0012447)\)
  Simplifying the expression:
 \(Z = (5.01682 + j58.9482447)(j0.00061137) / (5.01682 + j58.9482447)\)
 \(Z = (0.0030659285 - j0.035828609) Ω\)
2. Calculate the sending end voltage (V_s):
\(V_s = A * V_r + B * I_r\)
  Where V_r is the receiving end voltage and I_r is the receiving end current.
  Since the question does not provide the receiving end current, we cannot calculate the sending end voltage.
3. Calculate the voltage regulation (VR):
  \(VR = (V_s - V_r) / V_r * 100%\)
  Since we don't have the sending end voltage (V_s), we cannot calculate the voltage regulation.
4. Calculate the transmission efficiency (η):
\(η = (P_r / P_s) * 100%\)
Where P_r is the receiving end power and P_s is the sending end power.

Since we don't have the receiving end power, we cannot calculate the transmission efficiency.

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