what value of a, in degrees will refute frank’s claim?

a. The mean stock price of Cenovus Energy is 15.437.

b. The standard deviation for the sample prices of Cenovus Energy is

3.93.

c. The median stock price for Cenovus Energy is 14

d.  The range in Cenovus Energy's stock price is 11.5.

e. The coefficient of variation for each stock are 28.071% Cenovus Energy for % and 9% for TD Bank.

f. As the coefficient of variation is more for TD Bank it is riskier to buy.

The standard deviation is a statistic that expresses how much variance or dispersion there is in a group of numbers. While a high standard deviation suggests that the values are dispersed over a wider range, a low standard deviation suggests that the values tend to be close to the mean.

a. The mean stock price of Cenovus Energy is,

= (18 + 19 + 12 + 16 + 17.50 + 12 + 7.50 + 10)/8.

= 112/8.

= 14.

b. The variance for the sample prices of Cenovus Energy is,

= \(\frac{1}{n}\[ \sum_{i=1}^{n}[x_i - \overline{x}]^2\).

= (1/8)×[(18 - 14)² + (19 - 14)² + (14 - 12)² + (16 - 14)² +(17.50 - 14)² +(14 - 12)² +(14 - 7.50)² + (14 - 7.50)² +(14 - 10)²].

= (1/8)×[16 + 25 + 4 + 4 + 12.25 + 4 + 42.25 + 16].

= (1/8)×(123.5).

= 15.437.

Standard deviation = √(15.437).

= 3.93.

c. To find the median stock price for Cenovus Energy first we have the data set in ascending order.

7.50, 10.00, 12.00, 12.00, 16.00, 17.50, 18.00, 19.00.

So, The median of the stock price for Cenovus Energy is,

= (12 + 16)/2.

= 28/2.

= 14.

d. The range in Cenovus Energy's stock price is (19.00 - 7.50).

= 11.5.

e. The coefficient of variation for each stock is,

CV = {(Standard Deviation)/(Mean)}×100%.

CV = (3.93/14)×100%.

CV = 28.071 for Cenovus Energy.

CV = (6.30/70)×100%.

CV = 9% for TD Bank.

f. TD Bank's higher coefficient of variance makes investing riskier.

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The amount of water tank  with water after 10 minutes will be 4950 liters.

To solve this problem, we need to keep track of the net flow of water into the tank over the course of 10 minutes. The tap filling water adds water to the tank, while the tap emptying water removes water from the tank.

Let's calculate the net flow rate of water per minute:

Flow rate = (filling tap flow rate) - (emptying tap flow rate)

Flow rate = 40 L/min - 25 L/min

Flow rate = 15 L/min

Now, we can calculate the net flow of water over 10 minutes:

Net flow of water = (flow rate) * (time)

Net flow of water = 15 L/min * 10 min

Net flow of water = 150 L

Therefore, over the course of 10 minutes, the net flow of water into the tank is 150 liters.

Initially, the tank had 4800 liters of water. Adding the net flow of water, we can determine the final amount of water in the tank:

Final amount of water = (initial amount of water) + (net flow of water)

Final amount of water = 4800 L + 150 L

Final amount of water = 4950 L

After 10 minutes, there will be 4950 liters of water in the tank.

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To determine the area of the remaining piece of cardboard expressed in terms of x when a square of side length x inches is cut out from a rectangular piece of cardboard having a length of 6x+2 inches and a width of 2x-4 inches, use the following steps.

Draw and label a diagram of the problem. The rectangle should be labeled as 6x+2 inches by 2x-4 inches, and the square cut out should be labeled as x inches by x inches. This is how the diagram looks like: Determine the area of the rectangle, Arect.

The area of the rectangle is given by the product of its length and width. Thus, Arect = (6x + 2)(2x - 4) Determine the area of the square, Asq. The area of the square is given by the square of its side length. Thus, Asq = x²Step 4: Determine the area of the remaining cardboard after the square is cut out, Ar.

This is the difference between the area of the rectangle and the area of the square. Thus, Ar = Arect - Asq= (6x + 2)(2x - 4) - x²= 12x² - 20x - 16

Simplify the expression. The final answer is given in terms of x. Thus, Ar = 12x² - 20x - 16.The area of the remaining piece of cardboard is expressed in terms of x as 12x² - 20x - 16.

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The value of y is 4√3

Similar triangles have the same corresponding angle measures and proportional side lengths. The corresponding angles of similar triangles are congruent or equal.

Also , the ratio of corresponding sides of similar triangles are equal.

There are two triangles that are similar

Therefore;

y /16 = 4/y

y² = 48

y = √48

y = √16 × √ 3

y = 4√3

Therefore, the value of y is 4√3

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X must be equal to 0 for M to be singular.

For M to be singular, its determinant must be zero. So, we can set up the equation:

| 2 2 1 |

| 6 2 -x |

| 2 1 3 | = 0

Expanding the determinant along the first row, we get:

2 | 2 -x |

-6 | 1 3 | = 0

Multiplying the determinant of the 2x2 matrix by 2, we get:

4(-x - 3) - (-6)(2) = 0

Simplifying the left-hand side, we get:

-4x - 12 + 12 = 0

Solving for x, we get:

-4x = 0

x = 0

Therefore, X must be equal to 0 for M to be singular.

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Given

The (Group 1, No) cell in the two-way table is given below as,

Yes NoTotal

Group 15644100

Group 213565200

Group 3672693

Total258135393

Answer:

5,418 books

Step-by-step explanation:

Chay can use 3 bags of mulch per flower bed.

Chay is buying mulch for the zoo's summer flower beds. She has enough in her budget to purchase 55 bags of mulch. If there are 20 flower beds, how many bags of mulch can be used in each flower bed?The number of bags of mulch that can be used in each flower bed can be found by dividing the total number of bags of mulch by the number of flower beds, as given by the problem.Let X be the number of bags of mulch used in each flower bed. Then, the following equation can be written:Total number of bags of mulch = X × number of flower beds (20)Or, 55 = 20XDividing both sides of the equation by 20, we get: X = 55/20X = 2.75.Therefore, Chay can use 2.75 bags of mulch in each flower bed. However, since we cannot have a fraction of a bag of mulch, she would have to round up to 3 bags of mulch per flower bed to ensure each flower bed has enough mulch.

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The expressiοn (x+1)(x+2) has the greatest vaIue οf 30 when x=4.

An aIgebraic expressiοn is a mathematicaI phrase that cοntains variabIes, cοnstants, and mathematicaI οperatiοns. It may aIsο incIude expοnents and/οr rοοts. AIgebraic expressiοns are used tο represent quantities and reIatiοnships between quantities in mathematicaI situatiοns, οften in the cοntext οf prοbIem-sοIving.

Tο evaIuate the expressiοn (x+1)(x+2) when x=4, we simpIy substitute 4 intο the expressiοn, which gives us (4+1)(4+2).

SοIving this expressiοn, we first perfοrm the additiοns inside the parentheses tο get (5)(6).

Then, we muItipIy the twο numbers tο get 30.

when x=4, the expressiοn (x+1)(x+2) evaIuates tο 30, which is its greatest vaIue. This is because the quadratic expressiοn x² + 3x + 2 increases as x increases, and it reaches its maximum vaIue when x=4.

Therefοre, the expressiοn (x+1)(x+2) has the greatest vaIue οf 30 when x=4.

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Answer:

-36

Step-by-step explanation:

-1/2x<18

multiply each term by LCM=2

-1/2x×2<18×2

the 2on the left hand side will cancel each other leaving

-x <36

divide both sides by -1

-x/-1>36/-1

(note the equality sign changes because following the laws when you divide by a negative number the sign will change

X>-36

Answer:

Step-by-step explanation:

x>-36 is the anwser brainlist whould be aprecited and verifed

Answer:

yo baby momma

Step-by-step explanation:

so x = 23 we can conclude that grandpa joe is 5 years old

(～￣▽￣)～

Answer:

32

Step-by-step explanation:

Since it is to the fifth power, you multiply the number 2 five times:

2 x 2 x 2 x 2 x 2 = 32

\(f(x)=a(b)^x \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x}{0}~~,~~\stackrel{y}{1})\qquad 1=a(b)^0\implies 1=a~\hfill \underline{f(x)=1(b)^x} \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x}{2}~~,~~\stackrel{y}{25})\qquad 25=1(b)^2\implies 25=b^2\implies \sqrt{25}=b\implies 5=b \\\\[-0.35em] ~\dotfill\\\\ f(x)=1(5)^x\implies \underline{f(x)=5^x}\)

The probability of selecting a second red pencil is \(5/10\), is \(1/2\).

Information about the possibility that something will occur is provided by probability. For instance, meteorologists use weather systems to forecast the likelihood of rain. Probability theory is employed in epidemiology to comprehend the connection between exposure and the risk for health outcomes.

Applications. The common use of probability theory includes risk modelling and evaluation. Actuarial science is used by the insurance sector and markets to establish pricing and having partners choices. In the examination of entitlements, fiscal policy, and environmental laws, authorities use predicts.

There are \(11\) pencils in the box (\(6\) red and \(5\) blue).

If one red pencil is chosen and kept, there will be \(5\) red and \(5\) blue pencils left in the box.

Therefore, the probability of choosing another red pencil is:

\(5/10 = 1/2\)

So the probability of choosing a red pencil, keeping it, and then choosing another red pencil is: \(6/11 * 5/10 = 3/11 = 0.2727\) (rounded to four decimal places)

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Arthur must jump an additional 8.25 inches so as to break the record.

1 foot =  12 inches

Long jump record = 22 ft 6 3/4in = 22 ft 6.75 in = (22ft * 12 in per ft) + 6.75 in

Long jump record = 270.75 in

Arthur's long jump record = 21 ft 10 1/2in = 21 ft 10.5 in = (21ft * 12 in per ft) + 10.5 in

Arthur's long jump record = 262.5 ft.

To break the record, the distance needed to be jump by Arthur = 270.75 in - 262.5 ft. = 8.25 in

Arthur must jump an additional 8.25 inches so as to break the record.

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Answer:

( -∞, -2.5] ∪ (-1, 2)

Step-by-step explanation:

1/(x + 1) ≥ 3/(x - 2)

x - 2 ≥ 3(x + 1)

x - 2 ≥ 3x + 3

x - 3x ≥ 3 + 2

-2x ≥ 5

x ≤ -2.5

Interval notation:

( -∞, -2.5] ∪ (-1, 2)

Answer:

no solution

Step-by-step explanation:

radicals can't be negative

Answer:

-5/3

Step-by-step explanation:

trust me bro

Answer:

Use desmos

Step-by-step explanation:

Basically it is a graphing calculator put your points

The probability that a defective component will be detected only by the first inspector is 0.19

The probability that a defective component will be detected by exactly one of the two inspectors is 0.38

The probability that all three defective components in a batch escape detection by both inspectors is 0.

It is given that The first inspector detects 81% of all defectives that are present, and the second inspector does likewise.

Therefore P(A)=P(B)=81%=0.81

At least one inspector does not detect a defect on 38% of all defective components.

Therefore, bar P(A∩B)=0.38

As we know:

bar P(A∩B)=1-P(A∩B)=0.38

P(A∩B)=1-0.38=0.62

A defective component will be detected only by the first inspector.

P(A∩barB)=P(A)-P(A∩B)

=0.81-0.62

P(A∩barB)=0.19

The probability that a defective component will be detected only by the first inspector is 0.19

Part (B) A defective component will be detected by exactly one of the two inspectors.

This can be written as: P(A∩barB)+P(barA∩B)

As we know:

P(barA∩B)=P(B)-P(A∩B) and P(A∩bar B)=P(A)-P(A∩B)

Substitute the respective values we get:

P(A∩ barB)+P(bar A∩B)=P(A)+P(B)-2P(A∩B)

=0.81+0.81-2(0.62)

=1.62-1.24

P(A∩ barB)+P(bar A∩B)=0.38

The probability that a defective component will be detected by exactly one of the two inspectors is 0.38

Part (C) All three defective components in a batch escape detection by both inspectors

This can be written as: P(bar A∪ bar B)-P(bar A∩B)-P(A∩ barB)

As we know bar P(A∩B)=P(bar A∪ bar B)=0.38

From part (B): P(bar A∩B)+P(A∩bar B)=0.38

This can be written as:

P(bar A∪ bar B)-P(bar A∩B)-P(A∩bar B)=0.38-0.38=0

The probability that all three defective components in a batch escape detection by both inspectors is 0

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Answer:

C. y = 11.76(0.7)×

Step-by-step explanation:

I calculated it logically

The exponential equation that models the data is  y = 16.8×1.7ˣ.

A relation is a function if it has only One y-value for each x-value.

y = a.rˣ is the exponential function.

We can see that the y-values are decreasing, which means that the growth factor must be between 0 and 1.

Additionally, we can divide the y-value for each x by the y-value for the previous x to get an estimate of the growth factor.

Using this method, we find that the growth factor is approximately 0.85, which means that a possible equation is y = a × 0.85ˣ.

To find the value of a, we can substitute one of the data points into the equation.

Lets use the point (-2, 24), we get:

24 = a × 0.85⁻²

a = 24 / 1.551

a = 15.456

Therefore, the exponential equation that models the data is  y = 16.8×1.7ˣ.

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The increase in certain individuals leads to:

An increase in certain individuals within a bacterial population can lead to:

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Answer:

They have its own reciprocal

Step-by-step explanation:

one-tenth of 19,548 is 1954.8

Answer: .7, .32, .07, .03, .0

Step-by-step explanation:

Answer:

12000 mg/day or 80 capsules

Step-by-step explanation:

First let's convert 44 lbs to kg. You could divide by 2.205 to get more precise answer but since 44 divides perfectly by 2.2 I don't think it's a coincidence it's meant to be rounded.

44/2.2=20 kg

600*20=12000 mg per day

12000/150=80 capsules

Seems a bit excessive but looking over my process I don't see any mistakes.

The measure of angle p using sine and cosine rule is 69.9°.

Given that, ∠POQ=111°, OP=5 units and PQ=9 units.

The cosine rule as a²=b²+c²−2bc cos A and b²=a²+c²−2ac cos B.

Now, from figure p²=5²+9²-2×5×9 cos 111°

⇒ p²=25 + 81 -2×5×9 cos 111°

⇒ p²=25 + 81 -90×(-0.35837)

⇒ p²= 106+32.2533

⇒ p²=138.2533

⇒ p=11.75

Now, using sine rule a/sin A = b/sin B = c/ sin C.

That is, 11.75/sin P = 9/sin 111°

⇒ 11.75/sin P = 9/sin 111°

⇒ 11.75/sin P = 9/0.93358

⇒ 11.75/sin P = 9.64

⇒ sin P =11.75/9.64

⇒ sin P =1.22

⇒p= 69.9°

Therefore, the measure of angle p using sine and cosine rule is 69.9°.

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