what type of mixtures can be seperated by using fractional distillation? Give any two examples​

Answer:

Cu1+ can be written as "Cu+" in Roman numeral notation.

CoCl2 can be written as "CoCl2" in Roman numeral notation.

Roman numeral notation is used to indicate the oxidation state of an element in a compound. The oxidation state is the charge an atom would have if all of the bonding electrons were assigned to the more electronegative atom. The + sign shows that Copper has lost an electron and now has a positive charge.

In the case of CoCl2, the Roman numeral notation is not used since cobalt does not have variable oxidation states and therefor it does not have any change in its charge to indicate.

The Lewis structure for ICl2– has 3 lone pairs around the central iodine atom. The formal charge for iodine is 0. The hybridization of the iodine atom is sp3d, and the shape of the ion is trigonal bipyramidal.

To draw the Lewis structure for ICl2–, we first need to determine the number of valence electrons in each atom. Iodine (I) has 7 valence electrons, and each chlorine (Cl) has 7 valence electrons as well. The negative charge of the ion indicates the addition of one extra electron.

Next, we need to determine the central atom. In this case, it is iodine since it is the least electronegative and can form more than one bond.

We can connect each chlorine atom to the central iodine atom with a single bond, giving us a total of two bonds. We then place the remaining valence electrons around the atoms to satisfy the octet rule. In this case, we will have 3 lone pairs around the central iodine atom, and one lone pair on each chlorine atom.

The formal charge for the iodine atom can be calculated using the equation: Formal charge = valence electrons - non-bonding electrons - 1/2 bonding electrons. In this case, the iodine atom has 7 valence electrons, 6 non-bonding electrons (3 lone pairs), and 2 bonding electrons (1 bond), giving it a formal charge of 0.

The hybridization of the iodine atom can be determined by looking at the number of electron domains around the atom. In this case, there are 2 bonding domains and 3 lone pairs, giving a total of 5 electron domains. The hybridization for this is sp3d. The shape of the ion can be described as trigonal bipyramidal.

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Answer:

"500 Joule/sec" is the right answer.

Explanation:

The given values are:

Force,

F = 1000 N

Velocity,

s = 10 m

Time,

t = 20 s

Now,

The power will be:

=  \(\frac{Force\times Velocity}{Time}\)

On putting the values, we get

=  \(\frac{1000\times 10}{20}\)

=  \(\frac{10000}{20}\)

=  \(500 \ Joule/sec\)

The symbol for a silver-108 nucleus using the isotope notation with 'a' as superscript, 'z' as subscript, and 'x' as the element symbol is ^108Ag_47.

The symbol for a silver-108 nucleus in the isotope notation with 'a' as superscript, 'z' as subscript, and 'x' as the element symbol would be written as ^108Ag.

In this notation, the superscript represents the mass number (a), which is the sum of protons and neutrons in the nucleus. For a silver-108 nucleus, the mass number would be 108.

The subscript 'z' represents the atomic number, which indicates the number of protons in the nucleus. However, the atomic number for silver (Ag) is missing from the question. Silver has an atomic number of 47, so if we assume the silver-108 nucleus, the complete isotope notation would be ^108Ag_47.

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Answer:

no I'm about to say we will be didn't 1,600 we will 500

Answer:

purifying copper to produce copper wiring for homes

Explanation:

Answer:

b.purifying copper to produce copper wiring for homes

Explanation:

Answer:

Ne

Explanation:

Comparing Ne and Na, Neon atoms will have the greatest ionization energy.

The ionization energy is the energy required to remove the most loosely held electrons within an atom.

After the calculating we have Test statistic: -3.874.

Critical values: -2.086 and 2.086.

To test if the population mean pH of rainwater is equal to 5.4, we can perform a one-sample t-test.

We have the data:

Population mean (μ) = 5.4

Sample mean (x) = 4.7

Sample standard deviation (s) = 0.8

Sample size (n) = 21

Significance level (α) = 0.05

To calculate the test statistic, we can use the formula:

t = (sample mean - population mean) / (sample standard deviation / sqrt(sample size))

Plugging in the values:

t = (4.7 - 5.4) / (0.8 / √(21))

Calculating:

t ≈ (-0.7) / (0.8 / 4.582)

t ≈ -3.874

The test statistic is approximately -3.874.

To find the critical values, we need to refer to the t-distribution table or use statistical software. At a significance level of α = 0.05 with (n-1) degrees of freedom (n = sample size), the critical values for a two-tailed test are approximately -2.086 and 2.086.

Therefore, the correct answer is:

Test statistic: -3.874.

Critical values: -2.086 and 2.086.

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According to the graph presented, we can see that NaNO3 has a higher solubility at 30°C, as we can see more than 100 grams of NaNO3 can be dissolved in 100 grams of water, whereas all other solutes will have a way lower value. Letter D

If HauCl4 H2O was added to the 8% solution and then compared to the 5% sample, the AuNPs in the 8% sample would likely be more concentrated than in the 5% sample.

To provide some context, HauCl4 H2O is a solution of gold chloride that is commonly used in the synthesis of gold nanoparticles (AuNPs).

AuNPs are tiny particles of gold that exhibit unique physical and chemical properties, making them useful in a wide range of applications, including medicine, electronics, and catalysis.

When HauCl4 H2O is added to a solution containing gold ions, the ions are reduced to AuNPs, which then aggregate and form a colloidal suspension.

The concentration of AuNPs in the suspension depends on a number of factors, including the concentration of gold ions in the initial solution, the amount of reducing agent used, and the reaction conditions.

In the case of the 8% solution, it is likely that the concentration of gold ions is higher than in the 5% sample, which means that more AuNPs could be formed when HauCl4 H2O is added.

Additionally, if the reaction conditions are optimized to promote AuNP formation, the final concentration of AuNPs in the 8% sample could be significantly higher than in the 5% sample.

It is worth noting, however, that the exact concentration of AuNPs in the final suspension will depend on a number of factors beyond just the initial gold ion concentration, including the size and shape of the particles, the stability of the suspension, and the presence of any other ions or molecules that could affect the reaction.

In summary, it is difficult to predict exactly how much more concentrated the AuNPs in the 8% sample would be compared to the 5% sample without more information about the specific reaction conditions and experimental setup.

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Answer: Kansas City Chiefs

Explanation: what ever you think.

Answer:

Conservation of Charge is the principle that the total electric charge in an isolated system never changes. The net quantity of electric charge, the amount of positive charge minus the amount of negative charge in the universe, is always conserved.

Answer:

Upwelling

Explanation:

Prolyl hydroxylase cannot effectively utilize copper as a substitute for iron in its redox active center. The specific chemical properties of iron make it crucial for the enzyme's function.

Prolyl hydroxylase is an enzyme that plays a critical role in the post-translational modification of proteins. It contains an iron (Fe) redox active center, which is essential for its catalytic activity. Iron is a transition metal with specific chemical properties that allow it to participate in redox reactions, making it an ideal cofactor for this enzyme.

Copper (Cu), although also a transition metal, has different chemical properties that make it less suitable for this specific role. The redox potentials of copper and iron are different, meaning that copper would not provide the same catalytic efficiency as iron in prolyl hydroxylase's active site. Additionally, the coordination geometry and ligand preferences of copper differ from those of iron, which may lead to altered enzyme structure and function.

In summary, although copper is a transition metal like iron, its distinct chemical properties make it an unsuitable substitute for iron in the redox active center of prolyl hydroxylase.

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Answer:

select all of them except they are the biggest

The predators have good hearing, keen eyesight, and also have special adaptations that help them to be successful hunters. The correct options are A, B, and D.

A predator is an organism that consumes all or part of the body of its prey, which is another living or recently killed organism.

"Living or recently killed" distinguishes predators from decomposers, such as fungi and bacteria, which break down the remains of dead organisms.

Predation is classified into four types: carnivory, herbivory, parasitism, and mutualism. Each type of predation can be classified based on whether or not the prey is killed.

Prey animals are prey animals that are killed and eaten by other animals. For instance, Rabbits and crickets are both prey for larger animals.

The predators have excellent hearing and vision, as well as special adaptations that allow them to be successful hunters.

Thus, the correct options are A, B, and D.

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Answer:

ExplaAt high temperatures MgCO3 decomposes to magnesium oxide and carbon dioxide. This process is important in the production of magnesium oxide. This process is called calcining: MgCO3 → MgO + CO2 (ΔH = +118 kJ/mol)

nation:

The molarity of a solution made by dissolving 45.6 g glucose, C₆H₁₂O₆, in enough water to make 350.0 ml of solution is 0.722 M.

given that :

volume = 350 mL = 0.350 L

mass of glucose = 45.6 g

molar mass of glucose = 180.15 g/mol

the number of moles of glucose = mass / molar mass

                                                      = 45.6 / 180.15

                                                      = 0.253 mol

the molarity expression is given as follows :

Molarity = moles / volumes in L

              = 0.253 / 0.350

              = 0.722 M                  

Thus, the molarity of the solution to make 350.0 mL of solution is 0.722 M.          

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Answer:

Fatty acids are the building blocks of the fat in our bodies and in the food we eat. During digestion, the body breaks down fats into fatty acids, which can then be absorbed into the blood. Fatty acid molecules are usually joined together in groups of three, forming a molecule called a triglyceride.

Answer: 63.55

Explanation:

The attached chart shows the calculation.  The orange line points to the % abundance of Cu-65, which is the difference of 100% less the % Abundance of Cu-65 (since there are only 2 isotopes).

The weighted average contribution of each istope is calculated (blue arrow) and then summed to find the atomic mass of copper.

7. the pH of 0.81 M Mg(OH)₂ solution is 9.19.

8. the pH of 0.27 M pyridine solution is 9.11.

Mg(OH)₂ is a base which dissociates to produce two OH⁻ ions.

Mg(OH)₂ → Mg²⁺ + 2 OH⁻

Let the concentration of OH⁻ ions produced be x.

Therefore, the concentration of Mg²⁺ is 0.81-x

Mg(OH)₂ → Mg²⁺ + 2 OH⁻

Initial concentration (M)    0         0

Change (M)                 -x         +2x

Equilibrium Concentration  0.81-x      x     x

Using Kb for Mg(OH)₂,Kb = Kw/Ka

Kw = 1.0 × 10⁻¹⁴ at 25 °C.

For Mg(OH)₂,Kb = [Mg²⁺][OH⁻]²/Kw= (x)²/0.81 - x

Kb = 4.5 × 10⁻¹² = x²/0.81 - x

On solving the equation,x = 7.7 × 10⁻⁶M

Therefore, the concentration of OH⁻ ions = 2 × 7.7 × 10⁻⁶ = 1.54 × 10⁻⁵ M

To calculate the pH of the solution, use the formula:

pOH = - log [OH⁻]= - log 1.54 × 10⁻⁵pOH = 4.81pH = 14 - 4.81 = 9.19

Thus, the pH of 0.81 M Mg(OH)₂ solution is 9.19.

Let the concentration of OH⁻ ions produced be x.

Therefore, the concentration of C₅H₅NH⁺ is 0.27 - x.

C₅H₅N + H₂O ⇌ C₅H₅NH⁺ + OH⁻

Initial concentration (M)   0.27      0

Change (M)                -x       +x

Equilibrium Concentration  0.27-x     x

Using Kb for C₅H₅N,Kb = Kw/Ka

Kw = 1.0 × 10⁻¹⁴ at 25 °C.

For C₅H₅N,

Kb = [C₅H₅NH⁺][OH⁻]/[C₅H₅N]= (x) (x)/(0.27-x)Kb = 1.7 × 10⁻⁹

= x²/(0.27-x)

On solving the equation,

x = 1.3 × 10⁻⁵ M

Therefore, the concentration of OH⁻ ions = 1.3 × 10⁻⁵ M

To calculate the pH of the solution, use the formula:

pOH = - log [OH⁻]= - log 1.3 × 10⁻⁵pOH

= 4.89pH = 14 - 4.89 = 9.11

Thus, the pH of 0.27 M pyridine solution is 9.11.

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Answer:

For starters, convert the mass of potassium bromide to moles by using the molar mass of the compound.

15.6

g

⋅

1 mole KBr

119.002

g

=

0.1311 moles KBr

Now, in order to find the molarity of the solution, you need to figure out how many moles of solute are present for every

1 L

of solution.

You already know that

1.25 L

of solution contain

0.1311

moles of potassium bromide, the solute, so all you have to do now is to use this known composition as a conversion factor to go from

1 L

of solution to number of moles of solute.

1

L solution

⋅

0.1311 moles

1.25

L solution

=

0.10488 moles KBr

Since this represents the number of moles of solute present in

1 L

of solution, you can say that the molarity of the solution is equal to

molarity = 0.105 mol L

−

1

−−−−−−−−−−−−−−−−−−−−−−

Answer:C

Explanation: I learnet it too but more time ago hope its good

Answer:

Explanation:

Hi there!

We have,

1 mole of Al = 6.23*\(10^{23}\) atoms

Also given no. of atoms = 3.90 x \(10^{22}\) atoms

Now,

6.23*\(10^{23}\) atoms= 1 mole

1 atom = \(\frac{1 }{6.23*10^{23}}\) moles

or, 3.90 x \(10^{22}\) atoms =  \(\frac{1 }{6.23*10^{23}}\) *3.90 x \(10^{22}\) moles

Therefore, 3.90 x \(10^{22}\) atoms has 0.0626 mols of Al.

Hope it helps!

Answer:

THREE

Explanation:

Answer: True

Explanation:

Solubility is a physical property. The reason is because it can be determined by simple observation and does not change the chemical composition of the material. If the material is soluble, the solubility is the maximum amount of material that dissolves in a solvent at a given temperature.

A physical property is a characteristic of matter that is not associated with a change in its chemical composition. Familiar examples of physical properties include density, color, hardness, melting and boiling points, and electrical conductivity.

Answer: True

Explanation: These are both examples of physical properties

Answer:

WEAR YOUR SAFETY GOGGLES!!!!

Explanation:

acids can cause SERIOUS burns to your skin and eyes

The molar mass of the gas, given that 3.25 g of the gas occupied 2.56 L is 30.66g/mol

To obtain the molar mass of the gas, we shall first obtain the number of mole of the gas. This can be obtained as follow:

PV = nRT

0.95 × 2.56 = n × 0.0821 × 280

Divide both sides by (0.0821 × 280)

n = (0.95 × 2.56) / (0.0821 × 280)

n = 0.106 mole

Haven obtain the mole of the gas, we shall determine the molar mass of the gas as follow:

Molar mass = mass / mole

Molar mass of gas = 3.25 / 0.106

Molar mass of gas = 30.66g/mol

Thus, the molar mass of the gas is 30.66g/mol

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Answer: Scientific reasoning

Explanation:

A scientific reasoning can be defined as the justification which connects the evidence with that of the claim and it rules out all those claims that are not supported by any evidence. It explains the fact that how evidence can support a claim and scientifically acceptable conclusion can be drawn. An argument is always based on one or more claims which can either be true or evidentially proved.

Glycogen synthase forms an B)α-1,4-glycosidic bond upon release of UDP.

Glycogen synthase is an enzyme that catalyzes the formation of glycogen, a branched polysaccharide that serves as a storage form of glucose in animals. The enzyme adds glucose residues to the growing glycogen chain by forming α-1,4-glycosidic bonds between adjacent glucose molecules.

When the chain reaches a certain length, branching occurs through the formation of α-1,6-glycosidic bonds, catalyzed by the enzyme branching enzyme.

The release of UDP from glycogen synthase occurs after the addition of each glucose residue, and it is required for the enzyme to continue adding glucose residues to the growing glycogen chain. Therefore, glycogen synthase forms B) α-1,4-glycosidic bonds upon release of UDP.

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