What reagent/catalyst would bring about the following conversion? Answer with formula(s), in the appropriate box. OH OH NOZ & In progress reagent catalyst leave blank if none Submit Answer Retry Entire Group 8 more group attempts remaining What reagents/catalysts could bring about the following conversions? Answer with formulas, in the appropriate boxes. OH OH OH NO: NO2 step 1 step 2 reagent reagent catalyst leave blank if none catalyst leave blank if none Submit Answer Retry Entire Group 8 more group attempts remaining What reagent/catalyst would bring about the following conversion? Answer with formula(s), in the appropriate box. сн. CHE CI ed reagent catalyst leave blank if none Submit Answer Retry Entire Group 8 more group attempts remaining [Review Topics) (References) When the following compound is treated with HNO3, H804, the two major products are the singly-substituted ortho and para isomers. Draw the structural formula of the ortho substituted product. CH H2804 + HNO3 In progress You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. In cases where there is more than one answer, just draw one. The NO2 (nitro) group should be drawn in the following way (R1 represents the rest of the molecule): 0 RIN С P opy to 54 CE REVIEW When the following compound is treated with H2SO4, there is only one single-substitution product possible. Draw a structural formula for this product. + H2SO4 . You do not have to consider stereochemistry, . In cases where there is more than one answer, just draw one. • The SO3H (sulfonic acid) group should be drawn in the following way (R1 represents the rest of the molecule): оо M ited RIPOH С be [Review Topics] [References) When the following compound is treated with Cl2, FeCl3, the two major products are the singly-substituted ortho and para isomers. Draw the structural formula of the para substituted product. осн. + Cl2 FeCl3 • You do not have to consider stereochemistry, • In cases where there is more than one answer, just draw one.

There are 0.0267255 moles of KBr present in 153 ml of a 0.175 m solution.

To find the moles of KBr present in 153 ml of a 0.175 m solution, we can use the formula for molarity:

Molarity (M) = moles of solute ÷ liters of solution

We are given the following information:

Volume of solution (V) = 153 ml = 0.153 L

Concentration of solution (M) = 0.175 m

Let's solve for the moles of KBr:

0.175 m = moles of KBr ÷ 0.153 L

moles of KBr = 0.175 m × 0.153 L

moles of KBr = 0.0267255 mol

Therefore, there are 0.0267255 moles of KBr present in 153 ml of a 0.175 m solution.

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Hi! I'd be happy to help you understand how adding anhydrous sodium sulfate to the dichloromethane solution removes water.

When you add anhydrous sodium sulfate (Na2SO4) to a dichloromethane (CH2Cl2) solution containing water, the anhydrous sodium sulfate acts as a drying agent. This means it can absorb the water present in the solution. Here's a step-by-step explanation:

1. Anhydrous sodium sulfate is added to the dichloromethane solution containing water.
2. The anhydrous sodium sulfate has a strong affinity for water, meaning it attracts and bonds with the water molecules present in the solution.
3. As the sodium sulfate absorbs the water, it forms hydrated sodium sulfate, which is not soluble in dichloromethane.
4. The hydrated sodium sulfate can then be easily separated from the dichloromethane solution, leaving you with a dry dichloromethane solution free of water.

By using anhydrous sodium sulfate as a drying agent, you effectively remove water from the dichloromethane solution.

When you upload anhydrous sodium sulfate (\(Na_2SO_4\)) to a dichloromethane (\(CH_2Cl_2\)) answer containing water, the anhydrous sodium sulfate acts as a drying agent.

This way it is able to soak up the water present withinside the solution. 1. Anhydrous sodium sulfate is introduced to the dichloromethane answer containing water. 2. The anhydrous sodium sulfate has a robust affinity for water, that means it draws and bonds with the water molecules present withinside the answer. 3. As the sodium sulfate absorbs the water, it bureaucracy hydrated sodium sulfate, which isn't soluble in dichloromethane. 4. The hydrated sodium sulfate can then be without difficulty separated from the dichloromethane solution leaving you with a dry dichloromethane answer freed from water. By the use of anhydrous sodium sulfate as a drying agent, you efficiently eliminate water from the dichloromethane solution.

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The % yield is approximately 62.1%.  The percent yield is an important measure of the efficiency of a chemical reaction and indicates the success of the reaction in converting reactants into products.

To calculate the percent yield, we need to compare the actual yield (0.00157 mol) with the theoretical yield and then calculate the percentage.

First, let's calculate the theoretical yield of aspirin. The molar ratio between salicylic acid and aspirin is 1:1, so the number of moles of aspirin produced should be the same as the number of moles of salicylic acid used, which is 0.00253 mol.

Next, we'll calculate the theoretical mass of aspirin:

Mass = moles × molecular weight

Mass of aspirin = 0.00253 mol × 180.16 g/mol

Mass of aspirin = 0.455 g

Now we can calculate the percent yield:

% yield = (actual yield / theoretical yield) × 100

% yield = (0.00157 mol / 0.00253 mol) × 100

% yield = 0.6195 × 100

% yield = 61.95%

Rounding to one decimal place, the percent yield is approximately 62.1%.

The percent yield of the reaction is approximately 62.1%. This means that 62.1% of the maximum possible amount of aspirin was obtained from the given amount of salicylic acid. The percent yield is an important measure of the efficiency of a chemical reaction and indicates the success of the reaction in converting reactants into products.

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The element with 14 protons, 14 neutrons, and 14 electrons is silicon (Si).

An element is a type of pure substance that cannot be broken down into a simpler substance. An element is characterized by the number of protons in the nucleus of its atoms, which is referred to as the atomic number. All atoms of an element have the same number of protons, which determines its identity. In the question, the element with 14 protons, 14 neutrons, and 14 electrons is silicon (Si).

The atomic number of silicon is 14, indicating that it has 14 protons in its nucleus. Its mass number, which is the total number of protons and neutrons in the nucleus, is 28 since it has 14 neutrons. The number of electrons in a neutral atom is equal to the number of protons, which is 14.

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Answer:

True

Explanation:

The greater the mass of the object, the greater its weight force will be.

Answer:The two correct sentences about the energy of the filled gas cylinder are:

It has gravitational potential energy because of its height.

Its atoms and molecules have thermal energy.

Explanation:

The gas cylinder being held still does not imply that it has no energy. Energy can exist in different forms.

The gravitational potential energy is present because the gas cylinder is at a certain height from the ground, and it possesses the potential to fall and convert that potential energy into kinetic energy.

The atoms and molecules of the gas inside the cylinder possess thermal energy, which is related to their random motion and temperature.

The statement about motion energy and conversion to potential energy is not applicable to the gas cylinder being held still.

Answer:

The cation is written first in the name; the anion is written second in the name. Rule 2. When the formula unit contains two or more of the same polyatomic ion, that ion is written in parentheses with the subscript written outside the parentheses.

When writing the formula of a compound that contains polyatomic ion, the metal is written first followed by the central atom in the ion and then other atoms that surround the central atom.

A poly atomic ion refers to an ion that comprises of more than one atom. Such ions are common in chemistry. Examples of polyatomic ions include; PO4^3-, BH4^- etc.

When writing the formula of a compound that contains a polyatomic ion, the metal is written first then the central atom in the ion follows before other atoms that surround the central atom in the ion.

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Answer:

The first one.

Explanation:

Answer:

Gap 1, S-Phase, Gap 2, Prophase, Metaphase, Anaphase, Telophase, Cytokinesis

Hope this helps.

Explanation:

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pa brainliest na din po thanks

Answer:

So, sodium oxide + water = sodium hydroxide + hydrogen is written Na2O+H2O-->NaOH+H.

To balance the equation it should read NaO+H2O-->2NaOH

Explanation:

Na2O+H2O-->2NaOH+0H2.......the 0H2 is dropped because there is no value

The correct balance of equation will be

Na2O + H2O - - > 2NaOH

A chemical equation where the number of atoms on both the reactant side and the product side of the reaction are equal is called a balanced chemical equation.

In a balanced chemical equation, not only the number of atoms but the charge and the mass is the same on both sides of the equation.

A chemical equation needs to be balanced to validate the law of conservation of mass. The law of conservation of mass states that the 'mass can neither be created nor destroyed in a chemical reaction'.

If the chemical equation is not balanced, it will go against the fundamental law of law of conservation of mass.

Thus, the chemical equations need to be balanced.

Therefore to balanced the given chemical equation, we equate the number of atoms on both the reactant and the product side of the reaction.

It will be written as

Na2O + H2O - - > 2NaOH

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Answer:

42 liters of oxygen (liquid) weighs 47900 grams.

Explanation:

Based on the given information, the structure for the compound C10H13NO2 can be drawn as follows:

     H        H
      |        |
H - C - C - C - C - C - C - C - C - C - N - C - O - O - H
    |     |    |    |     |    |
    H     H    H    H     H    H

This structure represents a molecule with a carbon chain of 10 carbons, attached to a nitrogen atom and a carboxyl group (COOH).

The IR spectrum indicates the presence of N-H (3285 cm-1), C=O (1659 cm-1), and C-N (1246 cm-1) bonds.

The 1H NMR spectrum shows several peaks, including a triplet at 1.4 ppm (3H, J = 7 Hz), a large singlet at 2.01 ppm (3H), a quartet at 4.0 ppm (2H, J = 7 Hz), two doublets at 6.8 and 7.38 ppm (2H each, J = 9 Hz), and a weak singlet at 7.6 ppm (1H).

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The alkyl halide can be prepared by electrophilic addition of HCl to two different alkenes.

Electrophilic addition reactions involve the addition of an electrophile (electron-deficient species) to a double bond. In this case, HCl (hydrochloric acid) acts as the electrophile and adds to two different alkenes, resulting in the formation of two distinct alkyl halides.

The first alkene, let's call it alkene A, has the molecular formula CnH2n and a double bond between two carbon atoms. When HCl is added to alkene A, the chlorine atom (Cl) from HCl becomes attached to one of the carbon atoms originally involved in the double bond, while the hydrogen atom (H) becomes attached to the other carbon atom.

This leads to the formation of an alkyl halide where one of the carbon atoms is bonded to the halogen (chlorine) and the other carbon atom is bonded to the hydrogen atom.

The second alkene, alkene B, also has the molecular formula CnH2n and a double bond between two carbon atoms. Similarly, when HCl is added to alkene B, the chlorine atom (Cl) from HCl attaches to one of the carbon atoms involved in the double bond, and the hydrogen atom (H) attaches to the other carbon atom.

As a result, another alkyl halide is formed where one carbon atom is bonded to the halogen (chlorine) and the other carbon atom is bonded to the hydrogen atom.

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Option B: voluntary muscles are the muscles which have complete control and are responsible for all kinds of movements.

Animals' muscles are the types of tissue that cause movement or motion. Voluntary refers to action taken of one's own free will or will. All of the muscles that are linked to the skeleton are voluntary muscles, hence these muscles are also referred to as skeletal muscles or striated muscles because of the way their muscle fibres give them a striated, or stripy, appearance. This, therefore, tells us that option B is he right choice.

The only muscles that can be actively manipulated are those in the skeleton. Since the muscles are connected to the bones, pulling on them moves the bones. Skeletal muscles are used for every conscious movement a person makes.

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Answer:

electrons

Explanation:

The group number tells you the number of electrons in the element's outer shell (or valence shell).

Extra info: Elements with the same number of electrons on their outer shell are grouped together in the periodic table because they have similar properties.

Hope this helps!

Answer:

true

Explanation:

water is polar, and oil and water do not mix. nonpolar solvents do not like or mix with water, so they do not dissolve in water. so it's true.

Answer:

Option C

Explanation:

The theory is useful as in the usual constitution of the theory the professor stated

Answer:

Potassium-40 (40K) is a radioactive isotope of potassium which has a long half-life of 1.251×109 years. It makes up 0.012% (120 ppm) of the total amount of potassium found in nature.

...

Potassium-40.

General

Natural abundance 0.0117(1)%

Half-life 1.251(3)×109 y

Parent isotopes Primordial

Decay products 40Ca (β−) 40Ar (EC, γ; β+)

Answer:

Within the visible spectrum, red light has the longest wavelength.

Hope that helps! :)

Explanation:

According to the information, the proper order for the solutions from highest to lowest concentration can be inferred: 0.5 L (3 atoms), 1 L (5 atoms), 0.5 L (2 atoms), 1 L (3 atoms), 0.8 L (2 atoms).

To classify solutions according to their concentration, we must bear in mind that concentration refers to the number of atoms of an element in a given quantity. According to the above, it can be inferred that depending on the amount of liquid in each container and the amount of atoms (units) of another element we can establish the concentration.

According to the above, the correct classification from higher concentration to lower concentration would be:

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The approximate pH of an acetate buffer with equimolar concentrations of acetic acid and sodium acetate is 5.

Let's understand this in detail:

What is a buffer solution?

A buffer solution is an aqueous solution that has the ability to maintain a constant pH level. The buffer's most significant property is the ability to resist changes in pH when small quantities of acids or bases are added.

The buffer solution comprises a weak acid and its conjugate base and a weak base and its conjugate acid.

The Henderson-Hasselbalch equation is used to calculate the pH of a buffer:

Henderson-Hasselbalch equation

pH = pKa + log [A-]/[HA]Where pKa is the acid dissociation constant,

[A-] is the concentration of the conjugate base, and [HA] is the weak acid concentration.

The pKa value for acetic acid is 4.76. Since the concentrations of acetic acid and sodium acetate are equimolar, their concentrations are identical. Therefore, the concentration of the conjugate base is the same as the concentration of the weak acid.

Using the Henderson-Hasselbalch equation,

pH = 4.76 + log [A-]/[HA]pH = 4.76 + log 1pH = 4.76 + 0pH = 4.76

Therefore, the approximate pH of an acetate buffer with equimolar concentrations of acetic acid and sodium acetate is 5.

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Explanation:

Answer:

5 g/mL

Explanation:

So, if the mass is 10 g and the volume is 2 mL, the density equals...

10 g ÷ 2 mL = 5 g/mL

The order of the reaction with respect to nitrate ion is 2.3. The activation energy for this reaction is Ea = 148 kJ/mol.

1. The basic form of rate law for the given reaction is as follows:

\(Rate = k [NO3-][I-]^3[H+]^22\).

Given: doubling the concentration of nitrate ion causes the rate of reaction to quadruple.The order of reaction with respect to nitrate ion can be calculated using the formula;

\(k2/k1 = (2^n)\)

where,n is the order of reaction with respect to nitrate ion k1 and k2 are rate constants of reaction at the respective concentrations of nitrate ion.Substituting the values given in the question;

\(4 = (2^n)\)

The value of n can be obtained by solving the equation.

n = 2

Therefore, the order of the reaction with respect to nitrate ion is 2.3.

We can use the Arrhenius equation to calculate the activation energy of the reaction.

\(k = Ae^{(-Ea/RT)}ln\)

\(k = ln A - (Ea/RT)\)

Taking the natural logarithm of both sides of the Arrhenius equation will give the equation of the line in the form y = mx + b,

where y = ln k, x = 1/T, m = -Ea/R, and b = ln A.

The slope of the straight line is -Ea/R.

Therefore,-6114 = (-Ea/R)

Solving for Ea,

Ea = 148 kJ/mol

The activation energy for this reaction is Ea = 148 kJ/mol.

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A current of 0.80 A applied for 2.5 hours and assuming 100% current efficiency, the mass of cadmium metal deposited is \(1.2 \times 10^3\) g.

Faraday's law of electrolysis relates the amount of substance deposited during electrolysis to the quantity of electric charge passed through the electrolyte. The equation for calculating the mass of the substance deposited is:

Mass = (Current × Time × Molar mass) / (Number of electrons × Faraday's constant)

In this case, the current is 0.80 A and the time is 2.5 hours, which is equivalent to 2.5 × 60 × 60 = 9,000 seconds. The molar mass of cadmium (Cd) is 112.41 g/mol. Since the current efficiency is assumed to be 100%, the number of electrons involved in the reduction of\(Cd^{2+}\) to Cd metal is 2. The Faraday's constant is 96,485 C/mol.

Plugging in the values into the formula, we get:

Mass = (0.80 A × 9,000 s × 112.41 g/mol) / (2 × 96,485 C/mol) ≈ \(1.2 \times 10^3\) g

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If the radiation is able to pass through the cardboard box holding the sample, but doesn't pass through the row of steel file cabinets along her wall then the element is emitting gamma radiation.

Gamma rays are the type of high-energy electromagnetic radiation that is released from the nucleus when undergoing radioactive decay. Gamma rays have the highest energy of all types of radiation and can penetrate matter deeper than alpha and beta rays. Gamma rays are used in a variety of medical, industrial, and scientific applications such as; Cancer treatment, sterilization, scientific research, food safety. Gamma rays are also a form of ionizing radiation, meaning they can damage living tissue.

In this case, the element most likely emits gamma rays. Gamma rays are the most penetrating type of radiation, easily penetrating cardboard but not steel. Alpha and beta rays have low penetrability and cannot pass through cardboard.

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Answer:

The feedback mostly on the scenario mentioned is defined downwards.

Explanation:

There seem to be forces that regulate the whole mechanism as well as preserve equilibrium in every natural cycle. It is possible to divide these variables into two simple types:

The improvement throughout the natural state is attempted by negative factors as well as the positive reinforcement attempts to mitigate this improvement and approach the problem to something like the primary comfortable position.

Let's take a basic example including its process for suggestions. Users start whimpering if you get too cold. Your body continues to pump additional blood attributable to the whole shivering and indeed the temperature therefore raises. Throughout this circumstance, the temperature drop is a mechanism that serves to initiate the shivering, as well as the shivering attempts to recover the steady body’s temperature. Therefore the shivering case seems to be positive feedback that seeks to restore the primary balance.

Much the same for the landmass uplifting allows the emergence of more life above it. So, social advancement seems to be a system of negative criticism that disturbs the equilibrium. After that, the main elevation of the landform needs to regain the excess volume of degradation. So, this is indeed a tool for constructive feedback.

Answer:

Z negative

Explanation:

The negative charge shows that this is an electron. Electrons are present outside the nucleus of the atom and having negative charge. Usually represented by e-

Answer:

Only Z?

Explanation:

Given the number of moles of carbon in the compound is 0.074 and the number of moles of oxygen is 0.148 moles. Convert these numbers to whole number ratios we get the empirical formula of the compound as CO₂.

The empirical formula of a compound is derived from the number of moles of the constituent elements of the compound. The mole ratio of the elements give  the subscripts in the formula.

Given,

number of moles of carbon in the compound = 0.074 moles

number of moles of oxygen = 0.148 moles

mole ratio of C to O is 0.074 : 0.148.

Divide both numbers by 0.074 to get whole numbers. we will obtain 1:2.

Hence, carbon and oxygen are in the ratio of  1:2 and the formula of the compound is CO₂.

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