What property is 2(x+4)=2(4+x)

Answer:

this is the answer 0625.

Step-by-step explanation:

hope this helped

Theorem 9.11 states that the p-series ∑_(n=1)^∞ 1/n converges if p > 1 and diverges if p ≤ 1.
In the given series, we can see that each term is of the form n^3, which can be written as (n^p)^3 where p=1/3.

Since p=1/3 is less than or equal to 1, we can conclude that the series diverges by applying Theorem 9.11.

Therefore, the given series diverges.
Using Theorem 9.11, we can determine the convergence or divergence of the given p-series. This theorem states that a p-series ∑_(n=1)^∞ 1/n^p converges if p > 1 and diverges if p ≤ 1.

If you meant to write the series as 1/8 + 2/27 + 3/64 + 4/125 + ... (with terms of the form n/n^3), then it is a p-series with p = 3 > 1. In this case, according to Theorem 9.11, the series converges.

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True....

it's a polynomial.

To test the hypothesis that the mean weight of two sheets is equal (μ1 - μ2) against the alternative that it is not, and assuming equal variances, we can use a two-sample t-test. The t-statistic can be calculated using the following formula:

t = (x1 - x2) / (s_p * sqrt(1/n1 + 1/n2))

where:

x1 and x2 are the sample means of the two sheets,

s_p is the pooled standard deviation,

n1 and n2 are the sample sizes.

The pooled standard deviation (s_p) can be calculated using the following formula:

s_p = sqrt(((n1 - 1) * s1^2 + (n2 - 1) * s2^2) / (n1 + n2 - 2))

where:

s1 and s2 are the sample standard deviations.

To calculate the t-statistic, we need the sample means, sample standard deviations, and sample sizes.

Once you provide the specific values for these variables, I can assist you in calculating the t-statistic to 3 decimal places.

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To test the hypothesis that the mean weight of the two sheets is equal (μ1 - μ2) against the alternative that it is not, we can use a paired t-test assuming equal variances. The paired t-test is used when we have paired data or measurements on the same subjects or objects.

The t-statistic for a paired t-test is calculated as follows:

t = (X1 - X2) / (s / √n)

where X1 and X2 are the sample means of the two samples, s is the pooled standard deviation, and n is the number of pairs.

Please provide the sample means, standard deviation, and sample size for each sheet so that we can calculate the t-statistic to 3 decimal places.

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Answer:

5 is the y-intercept

Step-by-step explanation:

Answer:

They are different because they have different signs

Step-by-step explanation:

In 4,9 both values are positive whereas in 4,-9 the 9 is negative and the 4 is positive.

The value of dw/dt at t = 3 is  -0.282.

Given, the functions are:

w = 4x² + 3y, x = cos(t), and y = sin(t).

Let's find the expressions for w with respect to t using the chain rule.Using the chain rule, we have:

dw/dt = ∂w/∂x × ∂x/∂t + ∂w/∂y × ∂y/∂t...[1]      Here, ∂w/∂x = 8x, and ∂w/∂y = 3.

Substituting these values in [1], we get:

dw/dt = 8x × (-sin(t)) + 3 × cos(t)

dw/dt = -8cos(t)sin(t) + 3cos(t)dw/dt = cos(t)(3 - 8sin(t))...[2]

Now, let's find the expression for w in terms of t and differentiate directly with respect to t.Using w = 4x² + 3y, we get:

w = 4cos²(t) + 3sin(t)dw/dt = 8cos(t)(-sin(t)) + 3cos(t)dw/dt = -8cos(t)sin(t) + 3cos(t)dw/dt = cos(t)(3 - 8sin(t))

dw/dt = cos(t)(3 - 8sin(3)) = -0.282

Since, we have to evaluate at t = 3

Therefore, w = 4cos²(3) + 3sin(3) = 0.416

dw/dt = cos(3)(3 - 8sin(3)) = -0.282

Hence, the expression of dw/dt as a function of t using the chain rule is cos(t)(3 - 8sin(t)).

The expression of dw/dt as a function of t by expressing w in terms of t and differentiating directly with respect to t is -0.282.

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There are 56 bit strings of length 10 over the alphabet {a,b} that have exactly four a's.

To count the bit strings that start with bb, we have two fixed positions and 8 remaining positions to fill. Thus, there are 28 bit strings that start with bb and have exactly four a's.

To count the bit strings that end with bb, we can consider them as starting with the string a, followed by the bit strings that start with bb and have exactly three a's. Thus, there are also 28 bit strings that end with bb and have exactly four a's.

Therefore, the total number of bit strings of length 10 over the alphabet {a,b} that have exactly four a’s and start with bb or end with bb is 28 + 28 = 56.

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The length of the garden is 99 m.

The formula for the area of a rectangle is:

Area = Length x Width

We are given that the area of the rectangle is 8811 \(m^{2}\) and the width is 89 m. Substituting these values into the formula, we get:

8811 \(m^{2}\) = Length x 89 m

To solve for the length, we can divide both sides of the equation by 89 m:

Length = 8811 \(m^{2}\) / 89 m

Simplifying, we get:

Length = 99 m

Therefore, the length of the garden is 99 m.

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Answer:

below

Step-by-step explanation:

Rewrite the expression using the negative exponent rule  

b ^− n =1/ b^ n  . 1 x^ 7

Answer:

False

Step-by-step explanation:

It is multiplied by 2 so the next answer would be -8 not -6 hope this helps!:)

Answer:

D?

Step-by-step explanation:

Yes, Both the students are correct because both students calculate the area of a rectangular garden.

A rectangle is a two dimension figure with 4 sides, 4 corners and 4 right angles. The opposite sides of the rectangle are equal and parallel to each other.

Given that;

Roberto says they can use the expression;

⇒ 2(3)+2(3)

And, Jay says they can use the expression;

⇒ (4.9) 3

Now,

Since, The garden club plants a rectangular garden that.

And, It has been divided into six sections.

Here, The members want to find the area of the sections they planted with herbs.

Roberto says they can use the expression;

⇒ 2(3)+2(3)

Clearly, Robert find the area of garden as;

⇒ 2(3)+2(3) = 12 ft²

And, Jay find the area of garden as;

⇒ (4.9) 3 = 14.7 ft²

Thus, Both the students are correct because both students calculate the area of a rectangular garden.

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Answer:

x=1/2

Step-by-step explanation:

3(2x+9) = 30

Multiply out the 3

6x + 27 = 30

Subtract 27 on both sides

6x = 3

Divide by 6 on both sides

x = 1/2

Answer:

x=1/2

Step-by-step explanation

Answer:

The equation of the line through the given points is y = (1/2)x + 1.

Step-by-step explanation:

To find the equation of a line passing through two given points, we can calculate the slope (m) using the formula:

m = (y2 - y1) / (x2 - x1)

Given the points (7, 2) and (-1, 0), we have:

m = (0 - 2) / (-1 - 7) = -2 / -8 = 1/4

Next, we can use the point-slope form of a linear equation, y - y1 = m(x - x1), where (x1, y1) represents one of the given points. Let's choose the point (7, 2):

y - 2 = (1/4)(x - 7)

Expanding and rearranging the equation, we get:

y - 2 = (1/4)x - (7/4)

y = (1/4)x - (7/4) + 2

y = (1/4)x - (7/4) + (8/4)

y = (1/4)x + 1

Therefore, the equation of the line passing through the points (7, 2) and (-1, 0) is y = (1/4)x + 1.

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First you will get 4dz

The probability that the person has a tattoo is 230 out of 995.

We randomly select a person who responded to this survey. The calculation that gives the probability that the person has a tattoo is 230 out of 995.

Probability is a measure of the likelihood of a particular event occurring, typically expressed as a fraction or percentage.

The probability of an event occurring is calculated by dividing the number of favorable outcomes by the number of possible outcomes.

Therefore, the calculation that gives the probability that the person has a tattoo is 230 out of 995.

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the CDF is: F(y) = (area of triangle formed by AB and the point) / (area of triangle ABC)  = y / 2    for 0 ≤ y ≤ 2 and  the PDF is: f(y) = 1 / 2    for 0 ≤ y ≤ 2

To find the CDF and PDF of Y, the distance from a point chosen uniformly within the triangle to the line segment AB, we can proceed without relying on a diagram.

Let's consider the line segment AB first, which has a length of 2 units. The distance from the point within the triangle to AB can range from 0 to the length of AB.

1. CDF (Cumulative Distribution Function):

The CDF of Y, denoted as F(y), is the probability that Y is less than or equal to a given value y.

For 0 ≤ y ≤ 2:

Since the point can be anywhere within the triangle, the probability of Y being less than or equal to y is equal to the ratio of the area of the triangle formed by the line segment AB and the point within the triangle to the total area of the triangle ABC.

The area of triangle ABC is (1/2) * base * height = (1/2) * 2 * 2 = 2.

For 0 ≤ y ≤ 2, the area of the triangle formed by AB and the point within the triangle is (1/2) * y * 2 = y.

Therefore, the CDF is:

F(y) = (area of triangle formed by AB and the point) / (area of triangle ABC)

    = y / 2    for 0 ≤ y ≤ 2

2. PDF (Probability Density Function):

The PDF of Y, denoted as f(y), is the derivative of the CDF with respect to y.

For 0 ≤ y ≤ 2:

Since the CDF is a linear function within this range, the derivative is constant.

f(y) = d(F(y)) / dy

    = d(y / 2) / dy

    = 1 / 2    for 0 ≤ y ≤ 2

Therefore, the PDF is:

f(y) = 1 / 2    for 0 ≤ y ≤ 2

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The total cost for 10 hours of work would be 25 + 50(10) = 525.

Cost is the monitorial associated with the purchase of production of food or service if can include the prices of material of which is over it and other expenses that are related to the production of the code of service cost is a major fraction of when deciding whether to purchase a product something as it is and indicator of the value of the product of sound service.
The marginal cost of producing 5 items can be calculated using the equation C(x)=1300+4x/10. The marginal cost is the cost associated with producing one additional item. To calculate the marginal cost, we can plug in x=5 into the equation.

The equation in slope-intercept form for cost, c, after h hours of service is c = 25 + 50h.

The total cost for 8 hours of work would be 25 + 50(8) = 425.

The total cost for 10 hours of work would be 25 + 50(10) = 525.

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Answer:

x is all real numbers

Step-by-step explanation:

This means that the graph is continuous from negative infinity to positive infinity.

Answer:

-16,4 are the two numbers

The exact value of sin(u+w) is 8sin(n)cos(n)cos^3(w) - 6sin(n)cos(n)cos(w) + 3sin(n)cos(n)sin(w) - 4sin^3(n)sin(w) + 3cos^2(n)sin(w) - 4sin^3(n)sin^3(w) - cos^2(n)sin^3(w) + sin^3(n)sin(w).

(i) sin(u+w):

To find the exact value of sin(u+w), we can use the trigonometric identity: sin(u+w) = sin(u)cos(w) + cos(u)sin(w). Given that n and w are the angles introduced on page 4, we need to express u and w in terms of n and w.

Since u = 2n and w = 3w, we substitute these values into the identity: sin(2n+3w) = sin(2n)cos(3w) + cos(2n)sin(3w).

We know that sin(2n) = 2sin(n)cos(n) and cos(2n) = cos^2(n) - sin^2(n), and sin(3w) = 3sin(w) - 4sin^3(w) and cos(3w) = 4cos^3(w) - 3cos(w).

Substituting these values into the identity, we have: sin(2n+3w) = 2sin(n)cos(n)(4cos^3(w) - 3cos(w)) + (cos^2(n) - sin^2(n))(3sin(w) - 4sin^3(w)).

Simplifying further, we can expand and simplify the expression: sin(2n+3w) = 8sin(n)cos(n)cos^3(w) - 6sin(n)cos(n)cos(w) + 3sin(n)cos(n)sin(w) - 4sin^3(n)sin(w) + 3cos^2(n)sin(w) - 4sin^3(n)sin^3(w) - cos^2(n)sin^3(w) + sin^3(n)sin(w).

This is the exact value of sin(u+w), obtained by substituting the given values and simplifying the expression.

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A) The probability that all 3 selected were rated excellent is 0.0037 or 0.37%.

B) The probability of selecting one from each category is 0.0526 or 5.26%.

(A) The probability that all 3 selected were rated excellent can be found using the hypergeometric distribution. There are 4 excellent-rated employees in the department and a total of 20 employees, so the probability of selecting an excellent-rated employee on the first draw is 4/20. Since no replacement is allowed, there will be 3 excellent-rated employees left in a total of 19 employees for the second draw, giving a probability of 3/19. Similarly, for the third draw, there will be 2 excellent-rated employees left in a total of 18 employees, giving a probability of 2/18. Therefore, the probability that all 3 selected were rated excellent is (4/20) x (3/19) x (2/18) = 0.0037 or 0.37%.

(B) The probability that one from each category was selected can be found by considering the combinations of employees that could be selected. There are (4 choose 1) ways to select an excellent-rated employee, (15 choose 1) ways to select a good-rated employee, and (1 choose 1) way to select a marginal-rated employee. Therefore, there are (4 choose 1) x (15 choose 1) x (1 choose 1) = 60 ways to select one employee from each category. The total number of ways to select 3 employees from 20 is (20 choose 3) = 1140. Therefore, the probability of selecting one from each category is 60/1140 = 0.0526 or 5.26%.

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This gives us a dendrogram with three levels, where the first level has two clusters {{7,10},{20,28}} and {35}, the second level has two clusters {{7,10,20,28},35}, and the third level has only one cluster {{7,10,20,28,35}}.

What is a sequence?

A sequence is an enumerated collection of objects in which repetitions are allowed. Like a set, it contains members (also called elements, or terms).

To perform hierarchical clustering using single linkage, we start by treating each point as its own cluster, and then iteratively merge the two closest clusters until only one cluster remains. We use the single linkage method, which defines the distance between two clusters as the minimum distance between any two points in the clusters.

First, we calculate the pairwise distances between each point:

  7    10   20   28   35

7   -    3    13   21   28

10  3    -    10   18   25

20  13   10   -    8    15

28  21   18   8    -    7

35  28   25   15   7    -

Next, we find the two closest points/clusters and merge them:

  7,10  20   28   35

7,10  -    10   18   25

20    10   -    8    15

28    18   8    -    7

35    25   15   7    -

The closest points/clusters are 7 and 10, so we merge them to form a new cluster {7,10}.

  7,10  20,28  35

7,10  -    18     25

20,28 18   -      7

35    25   7      -

The closest points/clusters are now {20,28} and 35, so we merge them to form a new cluster {{20,28},35}.

 7,10  {20,28,35}

7,10  -    7

{20,28,35} 7    -

The closest points/clusters are now {7,10} and {{20,28},35}, so we merge them to form a new cluster {{{7,10},{20,28}},35}.

Hence, This gives us a dendrogram with three levels, where the first level has two clusters {{7,10},{20,28}} and {35}, the second level has two clusters {{7,10,20,28},35}, and the third level has only one cluster {{7,10,20,28,35}}.

The dendrogram can be visualized as in the attached image.

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