What occurs when a magnesium atom becomes a
magnesium ion?
A. Electrons are gained and the oxidation number
increases.
B. Electrons are gained and the oxidation number
decreases.
C.
Electrons are lost and the oxidation number
increases.
D.
Electrons are lost and the oxidation number
decreases.

The expression relating the concentration of a gas in \(\mu g/m^-^3 (X)\) with the concentration expressed in ppm (Y) is \(Y = (X/MW) * 10^6 / V\)

To derive an expression relating the concentration of a gas in \(\mu g/m^3 (X)\) with the concentration expressed in ppm (Y), we can use the ideal gas law. The ideal gas law states that \(PV = nRT\), where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature. Rearranging the equation, we have \(n = PV/RT\)

To convert the concentration from \(\mu g/m^-^3 (X)\) to moles (n), we divide X by the molecular weight (MW) of the gas. Thus, \(n = X/MW\)

Combining the two equations, we have \(X/MW = PV/RT\)

Since the concentration expressed in ppm (Y) is the same as the number of moles per million parts of air, we can write \(Y = n * 10^6 / V\)

Substituting \(n = X/MW\), we get \(Y = (X/MW) * 10^6 / V\)

Therefore, the expression relating the concentration of a gas in \(\mu g/m^3 (X)\) with the concentration expressed in ppm (Y) is:

\(Y = (X/MW) * 10^6 / V\)

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Complete question is:

Using the ideal Gas Law, derive an expression relating the concentration of a gas \(\mu_g^-^3 (X)\) with the concentration expressed in ppm (Y). (10 pts) Hint:- Ideal gas law \(PV= nRt -R = 0.0821 atm mol^-^1\)  −MW=X= molecular weight

Answer:

it would be B

Explanation:

so, p(OH)+ p(H) = 14, with some simple re-arrangement you get p(OH)=14-p(H).

The pH and pOH is related as pOH = 14 - pH

So, option B is correct one.

Evaluation,

Since, pOH + pH = 14,

By re-arrangement we get,

pOH = 14 - pH

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Answer:

d

Explanation:

moles Cu produced : 0.002

Concentration of copper sulfate (CuSO₄) : 0.319 g/dm³

MW CuSO₄ :

\(\tt =63.5+32+4\times 16=159.5~g/mol\)

mol CuSO₄ /dm³ :

\(\tt \dfrac{0.319}{159.5}=0.002\)

CuSO₄⇒Cu²⁺ + SO₄²⁻

mol Cu : mol CuSO₄ = 1 : 1 , so mol Cu²⁺=0.002

The muscles break down glycogen into glucose which undergoes glycolysis . the end product of glycolysis in active muscles is lactate, which is transported in the blood. the liver uses energy from fally acid oxidation drive glucose. the glucose produced in the liver is transported to muscle in the bloodstream.

muscles breaks into glycogen and glucose. the lactate is always the end product in glycolysis. by the fally acid oxidation liver uses energy. the cori cycle is the metabolic pathway which involves the active muscles and the  liver. so, the fatty acid will react and it forms the carbon dioxide and the water.

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In the Lewis structure of methanol (CH3OH), the OH group is placed on the outside because it is an important functional group that influences the chemical properties and reactivity of the molecule.

The Lewis structure is a representation of a molecule that shows the arrangement of atoms and valence electrons. In methanol, carbon (C) is the central atom bonded to three hydrogen (H) atoms and one oxygen (O) atom. The oxygen atom forms a single bond with carbon and also has two lone pairs of electrons.

The placement of the OH group (hydroxyl group) on the outside of the Lewis structure is significant because it determines the chemical behavior of methanol. The OH group consists of an oxygen atom bonded to a hydrogen atom and represents the presence of an alcohol functional group.

In organic chemistry, functional groups are specific arrangements of atoms within a molecule that give rise to characteristic chemical reactions and properties. The presence and position of functional groups can greatly influence the behavior and reactivity of a compound. In the case of methanol, the hydroxyl group provides the molecule with its characteristic properties.

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Answer:

0.010

Explanation:

Significant Figures Rules:

1. Anything that isn't a zero is a sig fig

2. If a decimal point comes after the ones digit, everything before the decimal is counted as sig fig (i.e 2000. would be 4 sig figs).

3. If we are dealing with small decimals, the zero before and after the decimal (i.e 0.002) is a placeholder and is not counted as sig figs.

4. Any zeros between 2 significant digits is considered in sig figs (i.e 2002 would be 4 sig figs)

5. Any zeros after a significant digit in a decimal (i.e 0.020) is considered a sig fig

0.0102 would be 3 sig figs. Rounding to the thousandths place of 0.010 would be 2 sig figs.

Answer:

P2 = 900 mmHg.

Explanation:

Given the following data;

Initial pressure = 450 mmHg

Initial temperature = 100°C

Final temperature = 200°C

To find the final pressure, we would use Gay Lussac's law;

Gay Lussac states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Gay Lussac's law is given by;

\( PT = K\)

\( \frac{P1}{T1} = \frac{P2}{T2}\)

Making P2 as the subject formula, we have;

\( P_{2}= \frac{P1}{T1} * T_{2}\)

\( P_{2}= \frac{450}{100} * 200 \)

\( P_{2}= 4.5 * 200 \)

Final pressure, P2 = 900 mmHg.

If a proposed mechanism is inconsistent with the experimentally determined rate law, it does not necessarily mean that the rate law is inaccurate. Instead, it suggests that the proposed mechanism is not supported by the experimental evidence and may require further investigation.

The proposed mechanism for a chemical reaction describes the sequence of steps by which the reactants are converted to products. The rate law for a chemical reaction, on the other hand, describes the relationship between the rate of reaction and the concentrations of the reactants.

If a proposed mechanism is inconsistent with the experimentally determined rate law, it does not necessarily mean that the rate law is inaccurate. It simply means that the proposed mechanism is not supported by the experimental evidence. There could be a number of reasons for this inconsistency, including errors in the proposed mechanism, experimental errors in measuring the rate of reaction, or other factors that affect the rate of reaction.

In fact, inconsistencies between the proposed mechanism and the experimentally determined rate law can provide valuable information about the reaction. By analyzing these inconsistencies and comparing them to other data, researchers can refine their understanding of the reaction mechanism and identify areas for further study.

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Answer: 20 g

Explanation: heat received Q = m c dT

Q= 50J , dT= 25 C anc c= 0.10 J / g C

And m = Q / c dT

The mass of the iron sample that received the heat is determined as 20 g.

The mass of the iron sample is calculated as follows;

Q = mcΔT

where;

m = Q/cΔT

m = (50) / (0.1 x 25)

m = 20 g

Thus, the mass of the iron sample that received the heat is determined as 20 g.

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If a building has become accidentally contaminated with radioactivity and initially contained 4.7 kg of strontium-90 and the safe level is less than 10.2 counts/min, then the building will be unsafe for 7.2 x 10^12 seconds.

Radioactivity is the spontaneous emission of radiation from the nucleus of an unstable atom that is accompanied by a decrease in mass and a decrease in charge. There are three types of radioactive emissions : alpha particles, beta particles, and gamma rays.

Steps to solve the given problem :

We can use the following formula to calculate the radioactivity of an element :

Radioactivity = λN

where, λ = decay constant ; N = the number of atoms in the sample

Now we can use the following formula to find the decay constant :

λ = ln2 / t1/2 where, t1/2 = half-life of the substance

To calculate the half-life of strontium-90, we can use the following formula : t1/2 = 0.693 / λ

We know that the atomic mass of strontium is 89.9077 u. Thus, the number of moles of strontium-90 in 4.7 kg of the sample is :

Number of moles = Mass / Molar mass= 4.7 / 89.9077= 0.052252 mol

Now, we can use Avogadro's number to find the number of atoms in the sample :

Number of atoms = Number of moles x Avogadro's number = 0.052252 x 6.022 x 10^23 = 3.1458 x 10^22 atoms

We can use the following formula to find the radioactivity :

Radioactivity = λN= λ (3.1458 x 10^22)

We know that the safe level of radioactivity is less than 10.2 counts/min. Thus, we can set up the following equation and solve for the decay constant :

10.2 = λ (3.1458 x 10^22)λ = 3.24 x 10^-23

We can use this decay constant to find the half-life : t1/2 = 0.693 / λ = 2.14 x 10^13 s

Now we can use the half-life to find the time it takes for the sample to decay to the safe level :

ln (N0 / N) = λtN / N0 = e^(-λt)t = [ln (N0 / N)] / λ

where, N0 = initial number of atoms ; N = final number of atoms

N0 / N = 10.2 / 3.1458 x 10^22= 3.235 x 10^-21

t = [ln (1 / 3.235 x 10^-21)] / (3.24 x 10^-23) = 7.2 x 10^12 s

Therefore, the building will be unsafe for 7.2 x 10^12 seconds.

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Once chewed and swallowed, the food will be digested and absorbed nutrients, while the rest of the food will be excreted through the body's feces. This digestion process can take about 24-72 hours.

The process of digestion of food in humans can be divided into two types, namely mechanical digestion and chemical (enzymatic) digestion. Mechanical digestion is the process of changing food from a large or coarse form to a smaller or finer form. The process takes place in the mouth with the help of teeth and tongue. The mechanical digestion process also occurs in the stomach with the help of peristaltic motion of the stomach wall, so that food is like being stirred. While the chemical digestion process is the process of converting food substances from complex forms into simpler forms with the help of digestive enzymes.

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The aqueous solution that has the lower freezing point is 0.60 m glucose.

Freezing point depression is the reduction in the temperature at which a liquid freezes caused by dissolved particles. The freezing point depression (ΔTf) of a solution is proportional to the molality (m) of the solute, which is the number of moles of solute per kilogram of solvent.

Freezing point depression is a colligative property, which means it depends only on the number of solute particles in the solution, not on their nature. The van't Hoff factor (i) is used to account for the dissociation of solutes in the solution. The van't Hoff factor of glucose is 1, whereas the van't Hoff factor of CaCl2 is 3.

To calculate the freezing point depression, we use the formula:

ΔTf = i * Kf * m

To calculate the freezing point depression, we use the formula:

ΔTf = i * Kf * m

The freezing point depression constant of water is 1.86 °C/m.

Thus, for the given molality of the solutions, the freezing point depression is

:ΔTfcacl2 = 3 * 1.86 °C/m * 0.60 m = 3.348 °CΔTfglucose = 1 * 1.86 °C/m * 0.60 m = 1.116 °C

Therefore, 0.60 m glucose has a lower freezing point depression than 0.60 m CaCl2.

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When electric current flows in a straight wire, then it generates magnetic field around the wire. Direction of the magnetic field changes, but the strength of the magnetic field stays the same.

If the current changes direction, then the direction of the magnetic field will also change. This is because the direction of magnetic field is determined by the direction of current flow, and when current flow is reversed, then the direction of the magnetic field will also be reversed.

The strength of the magnetic field will remain the same, assuming that  current remains constant. This is because the strength of magnetic field is determined by the magnitude of the current and not its direction.

So, the direction of the magnetic field changes, but the strength of the magnetic field stays the same.

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Answer:

The burning of a candle is both a physical and a chemical change.

Explanation:

Plz mark brainliest thanks

Answer:

\(\boxed{\rm Al_{\,(s)}+Fe_2O_{\,(s)} \rightarrow Al_2O_{3\,(s)} + Fe_{\,(s)}}\)

Explanation:

Aluminium metal + iron(I) oxide powder → aluminium oxide solid + iron metal

This is an example of a displacement reaction, with chemical equation:

\(\boxed{\rm Al_{\,(s)}+Fe_2O_{\,(s)} \rightarrow Al_2O_{3\,(s)} + Fe_{\,(s)}}\)

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Answer:

28.163

Explanation:

Givens

V1 = 258 mL

T1 = 0C = 273 K

P1 = 1 atm

V2 = ?

T2 = 298oK

P2 = 10 atm

Formula

V1*P1/T1 = V2 * P2 / T2

Solution

258 mL * 1 / 273 = x * 10/298      Multiply by 298

258 * 1 * 298/273 = 10 * V2

281.63 = 10 * V2                         Divide by 10

28.163 =   V2

Answer:

A. 7

(assuming the water is neutral)

When the child sits on the partially filled balloon, the pressure of the balloon increases. The pressure change is a doubling of the initial pressure, indicating a factor of 2 increase.

When the child sits on a partially filled balloon, the volume of the balloon decreases by half. According to Boyle's Law, which states that the pressure of a gas is inversely proportional to its volume at constant temperature, the pressure inside the balloon increases.

Let's consider the initial volume of the balloon as V and the initial pressure as P. When the volume decreases by half, it becomes V/2. Since the amount of gas remains constant, the pressure increases to maintain equilibrium. The new pressure can be denoted as P'.

According to Boyle's Law, P₁V₁ = P₂V₂, where P₁ and V₁ are the initial pressure and volume, and P₂ and V₂ are the final pressure and volume. Plugging in the values, we have P * V = P' * (V/2).

Simplifying the equation, we get P' = 2P. This means the pressure of the balloon increases by a factor of 2, or it doubles. So, the pressure change can be expressed as an increase of two times the original pressure.

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Answer:

The term "Battery"

Explanation:

The question requires us to calculate the amount of solution that could be prepared from 1.85 g of silver nitrate (AgNO3), considering a 5.0% solution.

Considering that 5.0% solution corresponds to a solution where there are 5g of AgNO3 in 100 g of solution (% m/m), we can write:

5.0 g of AgNO3 ---------- 100 g of solution

1.85 g of AgNO3 --------- x

Solving for x, we have that 37g of a 5.0% solution could be prepared from 1.85g of AgNO3.

Answer:

Protons:

- positive

- aka cation

- in the nucleus along with the neutrons

Electrons:

- negative

- aka anion

- situated in the orbital shells/configuration levels (there are many names)

Answer:

1,3,5,6,7

Explanation:

the state of the object changes to from something new

Answer:

Subconscious - psychic activity just below the level of awareness

Election - the act of electing someone

Explanation:

I hope this helped enough, good luck in chemistry!

The alcohol is used in the thermometers instead of the water because The freezing point of the alcohol is less than -100°C.

Thermometer is the instrument that is used to measure the temperature of the substance which will be present in the liquid state. The freezing point of the alcohol is less than the  - 100 °C, and  we can measure the very low temperature by using an alcohol thermometer.

The expansion of the alcohol is more than as compare to that of the mercury for the same rise or the fall of the temperature, therefore, the  alcohol used in the thermometer can measure the temperature very more accurately.

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The smallest possible value of the principal quantum number (n) for an electron with a magnetic quantum number (ml) of 2 is 3. The principal quantum number (n) determines the energy level or shell that an electron occupies in an atom.

Principal quantum number (n) represents the overall size and energy of the electron's orbital. The allowed values of n are positive integers starting from 1.

The magnetic quantum number (ml) describes the orientation of the orbital in a specific energy level. It ranges from -l to +l, where l is the azimuthal quantum number.

In this case, ml = 2, indicating that the electron is in an orbital with an orientation of the +2 value. To determine the minimum value of n, we can use the relationship between n and l: n ≥ l. Since l can have values ranging from -l to +l, including 2, the minimum value of n would be 3.

Therefore, the smallest possible value of the principal quantum number (n) for an electron with a magnetic quantum number (ml) of 2 is 3.

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Swelling of the nasal sinuses during upper respiratory infections is a common occurrence. It leads to symptoms like nasal congestion, facial pressure, headaches, and post-nasal drip.

The nasal sinuses are hollow cavities located within the facial bones surrounding your nose. They are lined with a mucous membrane that produces mucus, a sticky fluid that helps to moisten and clean the nasal passages. The sinuses also play a role in filtering the air we breathe and adding resonance to our voices.

During an upper respiratory infection, viruses or bacteria can invade the nasal passages and cause inflammation. In response to this invasion, the immune system releases various chemicals, such as histamines, to fight off the infection. Histamines are responsible for causing blood vessels in the nasal passages and sinuses to dilate, leading to increased blood flow and swelling.

The swelling of the nasal sinuses can result in several uncomfortable symptoms. One of the most common symptoms is nasal congestion or a blocked nose. The swollen sinuses can obstruct the flow of air through the nasal passages, making it difficult to breathe freely. This congestion can also lead to a stuffy or ""stuffy"" feeling in the nose.

In addition to congestion, swelling in the sinuses can cause facial pressure and pain. The increased pressure within the sinuses can result in headaches, particularly in the forehead and around the eyes. Some individuals may experience tenderness when touching the affected areas of their face.

Swollen sinuses can also disrupt the normal drainage of mucus. Normally, mucus produced in the sinuses drains into the nasal passages and is either swallowed or blown out through the nose. However, during an upper respiratory infection, the swollen sinuses can block the natural drainage pathways. This can lead to the accumulation of mucus, resulting in post-nasal drip, where excess mucus drips down the back of the throat. Post-nasal drip can cause a sore throat, coughing, and a feeling of needing to clear the throat frequently.

Managing the swelling of the nasal sinuses during an upper respiratory infection involves both symptom relief and treating the underlying infection. Over-the-counter nasal decongestant sprays or oral decongestants can help alleviate nasal congestion by reducing swelling in the sinuses. However, these medications should be used sparingly and as directed, as excessive or prolonged use can lead to a rebound effect and worsen congestion.

Nasal saline irrigation, commonly done using a neti pot or nasal spray, can help flush out mucus and reduce nasal congestion. Warm compresses applied to the face can also provide relief by promoting sinus drainage and reducing inflammation.

It's important to stay hydrated and get plenty of rest during an upper respiratory infection to support the immune system's ability to fight off the infection. If symptoms persist or worsen, it's advisable to consult a healthcare professional who can provide a proper diagnosis and recommend appropriate treatment options, such as antibiotics if a bacterial infection is present.

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Answer:

Thermal energy

Explanation:

Sorry it took me forever

Answer:

Thermal energy

Explanation: