What is the value of x in the given triangle, in inches?

9514 1404 393

Answer:

  A)  3 1/4

Step-by-step explanation:

Your calculator can help with this.

__

  3/4 + ((1/3)/(1/6)) -(-1/2)

  = 3/4 + ((2/6)/(1/6)) + 2/4

  = 5/4 + 2/1

  = 3 1/4

Q) 3/4 + {(1/3) ÷ (1/6)} - ( - 1/2) = ?

→ 3/4 + {(1/3) ÷ (1/6)} - ( - 1/2)

→ 3/4 + {(1/3) × (6/1)} - ( - 1/2)

→ 3/4 + 6/3 - ( - 1/2)

→ {(3/4) + (6/3)} + 1/2

→ 11/4 + 1/2

→ (11 + 2)/4 = 13/4

→ 3 1/4

Hence, option (A) is the answer.

Step-by-step explanation:

6 worker do the painting of house = 48 hours

1 worker will take = 48/6 = 8 hours

4 worker will take. = 4× 8 = 32 hours

to paint the house

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hope this will be helpful to you ☺️.

Answer:

96 hours

Step-by-step explanation:

48 / 6 = 8

8 hours per worker.

4 x 8 = 24 x 2 = 48

So 96 hours

Hope that helps!

Answer:

\(3\)

Step-by-step explanation:

\(\mathrm{Let\ the\ age\ of\ Sophia\ be\ }x\mathrm{\ and\ age\ of\ Mohal\ be\ }x+2.\\\mathrm{Given,}\\\mathrm{Product\ of\ their\ ages = 15}\\\mathrm{or,\ }x(x+2)=15\\\mathrm{or,\ }x^2+2x=15\\\mathrm{or,\ }x^2+2x-15=0\\\mathrm{or,\ }x^2+5x-3x-15=0\\\mathrm{or,\ }x(x+5)-3(x+5)=0\\\mathrm{or,\ }(x+5)(x-3)=0\\\mathrm{i.e.}\ x=-5\ \mathrm{or}\ 3.\)

\(x=-5\ \mathrm{is\ disgarded\ because\ age\ cannot\ be\ negative.}\\\mathrm{So\ the\ age\ of\ Shopia,\ }x=3\)

Answer:

4250 m

Step-by-step explanation:

1 day = 850

5 days = 850×5

= 4250

The algebraic rule for translating the figure 3 units left and 2 units up is (x-3, y+2).  Option B.

To translate a figure 3 units to the left and 2 units up, we need to adjust the coordinates of the figure accordingly. The algebraic rule that represents this translation can be determined by examining the changes in the x and y coordinates.

When we move a figure to the left, we subtract a certain value from the x coordinates. In this case, we want to move the figure 3 units to the left, so we subtract 3 from the x coordinates.

Similarly, when we move a figure up, we add a certain value to the y coordinates. In this case, we want to move the figure 2 units up, so we add 2 to the y coordinates.

Taking these changes into account, we can conclude that the algebraic rule for translating the figure 3 units left and 2 units up is (x-3, y+2). The x coordinates are shifted by subtracting 3, and the y coordinates are shifted by adding 2. SO Option B is correct.

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The approximate difference in the circumferences of the two circles is: C. 61 cm.

Mathematically, the circumference of a circle can be calculated by using this mathematical expression:

C = 2πr or C = πD

Where:

Substituting the given parameters into the circumference of a circle formula, the circumference of the small circle is;

Circumference of circle, C = πD

Circumference of circle, C = 3.14 × 4.5

Circumference of circle, C = 14.13 cm.

For the larger circle, we have:

Circumference of circle, C = 3.14 × 24

Circumference of circle, C = 75.36 cm.

Difference = 75.36 cm - 14.13 cm.

Difference = 61.23 ≈ 61 cm.

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A possible vector function that represents the curve of intersection of the two surfaces is r(t) = (5 cos(t), 5 sin(t), 5 cos(t) sin(t))

The cylinder x^2 + y^2 = 25 represents the set of points in 3D space where the distance from the origin to the point (x, y, z) is equal to 5. The surface z = xy represents the set of points in 3D space where the height of the point (x, y, z) is equal to its x-y coordinate.

The curve of intersection of the two surfaces is given by the set of points in 3D space that are simultaneously on the cylinder and on the surface z = xy. This means that for any point on the curve of intersection, the distance from the origin to the point must be equal to 5, and the height of the point must be equal to its x-y coordinate.

We can find a vector function that represents the curve of intersection by parameterising the points on the curve in terms of a scalar parameter t. For example, a possible parameterization of the curve of intersection is:

r(t) = (5 cos(t), 5 sin(t), 5 cos(t) sin(t))

where t is a scalar parameter that ranges over all values between 0 and 2π. The values of x, y, and z are given by 5 cos(t), 5 sin(t), and 5 cos(t) sin(t), respectively, and represent a point on the curve of intersection for each value of t.

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The answer is:

g(x + 1) = 6x + 1

g(4x) = 24x -5

Work/explanation:

To evaluate, I plug in x + 1 into the function:

\(\sf{g(x)=6x-5}\)

\(\sf{g(x+1)=6(x+1)-5}\)

Simplify

\(\sf{g(x+1)=6x+6-5}\)

\(\sf{g(x+1)=6x+1}\)

------------------

Do the same thing with g(4x)

\(\sf{g(4x)=6(4x)-5}\)

\(\sf{g(4x)=24x-5}\)

Hence, these are the answers.

The function f(x) = \(-2(x+4)^2\) + 1 has a greater maximum.

1. The given function is f(x) = \(-2(x+4)^2\) + 1.

2. To find the maximum of the function, we need to determine the vertex of the parabola.

3. The vertex form of a quadratic function is given by f(x) = \(a(x-h)^2\) + k, where (h, k) represents the vertex.

4. Comparing the given function to the vertex form, we see that a = -2, h = -4, and k = 1.

5. The x-coordinate of the vertex is given by h = -4.

6. To find the y-coordinate of the vertex, substitute the x-coordinate into the function: f(-4) = \(-2(-4+4)^2\) + 1 = \(-2(0)^2\) + 1 = 1.

7. Therefore, the vertex of the function is (-4, 1), which represents the maximum point.

8. Comparing this maximum point to the information provided about the other function g(x) on the coordinate plane, we can conclude that the maximum of f(x) = \(-2(x+4)^2\) + 1 is greater than the maximum of g(x).

9. The given information about g(x) is not sufficient to determine its maximum value or specific equation, so a direct comparison is not possible.

10. Hence, the function f(x) =\(-2(x+4)^2\) + 1 has a greater maximum.

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Answer:

Step-by-step explanation:

Volume = Bh

Turn the shape so the trapezoid is on the bottom/base

h=18   for overall shape

B = area of base, trapezoid

B = 1/2 (b₁ + b₂) h  

b₁ = 11

b₂ = 25

h = 24   for trapezoid

B = 1/2 (11 + 25)(24)

B = 432

V = Bh

V = (432)(18)

V= 7776 in³

The value of secant XY is 37.5 units.

The Secant-Secant Theorem states that "if two secant segments which share an endpoint outside of the circle, the product of one secant segment and its external segment is equal to the product of the other secant segment and its external segment".

Using the theorem above, we can say:

VZ * VW = VX * VY

30 * 45 = 22.5 * VY

22.5VY = 1350

VY = 1350/22.5

VY = 60 units

Since VY = VX + XY. We have:

60 = 22.5 + XY

XY = 60 - 22.5

XY = 37.5 units

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Answer:

Area of pupil = 0.007855 square inch.

Step-by-step explanation:

Given the following data;

Diameter = 0.1 inch

To find the area of the pupil (circle);

Area of circle = π(D/2)²

Area of pupil = 3.142*(0.1/2)²

Area of pupil = 3.142*(0.05)²

Area of pupil = 3.142*0.0025

Area of pupil = 0.007855 square inch.

Answer:

16

Step-by-step explanation:

Given the point:

(0, 6)

Let's find the quadrant and the axis where the point is located.

We have:

(x, y) ==> (0, 6)

The x-coordinate of the point is 0, while the y-coordinate of the point is 6.

Here, the point (0, 6) lies on the y-axis.

Also, since the x-coordinate is 0, we can say the point lies in between quadrant I and quadrant II.

From the graph above we can see the point (0, 6) is between quadrant I and II, and the point lies on the y-axis.

ANSWER:

• The point is in beween Quadrant I and II

• The point lies on the y-axis.

Answer: (x+6)(x-3)

Step-by-step explanation:

y=x^2+3x-18

(x+6)(x-3 )

Answer:

11x+15

Step-by-step explanation:

Step-by-step explanation:

sorry po talaga kung wala po

akong masagot dyan :(

Therefore, the solutions to the equation 0 = |3x + 3| + 3 are x = -2 and x = 0.

To solve the equation 0 = |3x + 3| + 3, we need to eliminate the absolute value. Remember that the absolute value of a number is always non-negative.

First, let's isolate the absolute value term on one side of the equation:

|3x + 3| = -3

Since the absolute value cannot be negative, there are no solutions to the equation as it stands. However, if we modify the equation to make the right side positive, we can find a solution.

To eliminate the absolute value, we can rewrite the equation as two separate equations, considering both the positive and negative cases:

   3x + 3 = -3

   -(3x + 3) = -3

Solving equation 1:

3x + 3 = -3

3x = -6

x = -2

Solving equation 2:

-(3x + 3) = -3

-3x - 3 = -3

-3x = 0

x = 0

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Let's start by finding the amount that Alex earns per hour before overtime. We know that he works 40 hours, so if we let his hourly pay be x, then his total pay before overtime can be expressed as 40x.

Since Alex gets 50% more than his usual pay for overtime, his overtime pay per hour would be 1.5x, or his usual pay plus 50% of his usual pay. This means that for the 6 hours of overtime he worked, he would earn a total of 6 * 1.5x = 9x.

Now we can write an expression for Alex's total pay, including overtime:

Total pay = 40x + 9x

Simplifying this expression, we get:

Total pay = 49x

So Alex's total pay, including overtime, is 49 times his hourly pay.

Answer:

9.

h(x)=-x-1

let y =-x-1

interchanging role of x & y

x=-y-1

y=-x-1

h-¹(x)=-x-1

again

f(x)=(2-3x)/2

let

y=(2-3x)/2

interchanging role of x & y

x=(2-3y)/2

2x-2=-3y

y=(2-2x)/3

f-¹(x)=(2-2x)/3

Given function are not inverse of each other.

10.

f(x)=-x+3

let y=-x+3

interchanging role of x & y

x=-y+3

y=3-x

f-¹(x)=-x+3

equal to g(x)=-x+3

Given function are inverse of each other.

Answer:

Step-by-step explanation:

Call h(x) = y (It's easier to see).

y = -x - 1

The first step is always to interchange x and y

y = -x - 1

-x = y - 1

Solve for y

-x + 1 = y

If I understand the question, these two (f(x) and h(x)) are not inverses.

10 is a bit tricky. An inverse can invert into itself: This is called an involution. But if they are differently labeled, I'm not sure. I don't think that this is exactly what is men by an involution. Something like y = x would be. But you have 2 different inverses. I'm not sure that this qualifies.

y = x + 3      

g = x + 3

x = y + 3

x - 3 = y

Answer and Explanation:

First, we can find the factored areas of the circle (the non-shaded area) and the rectangle (which includes the shaded and non-shaded areas).

We can use the rule:

if \(x^2 + cx + d = (x + a)(x + b)\), then \(c = a + b\) and \(d = a \cdot b\).

__

\(A_\circ = \dfrac{x+1}{x^2 + 6x + 8}\)

\(\boxed{A_\circ = \dfrac{x+1}{(x + 2)(x + 4)}}\)

__

\(A_\square = \dfrac{x+1}{x^2 - 6x -16}\)

\(\boxed{A_\square = \dfrac{x+1}{(x+2)(x-8)}}\)

Since we want to subtract the area of the circle from the area of the rectangle, we need them to have a common denominator.

We can achieve this by multiplying the area of the circle by \(\dfrac{(x-8)}{(x-8)}\) and the area of the rectangle by \(\dfrac{(x+4)}{(x+4)}\) because then both fractions will have the denominator \((x+2)(x+4)(x-8)\).

\(A_\circ = \dfrac{(x+1)(x-8)}{(x + 2)(x + 4)(x-8)}\)

\(A_\square = \dfrac{(x+1)(x+4)}{(x+2)(x-8)(x+4)}\)

Now that they have a common denominator, we can subtract them to get the area of the shaded region.

\(A_\text{shaded} = A_\square - A_\circ\)

\(A_\text{shaded} = \left(\dfrac{(x+1)(x+4)}{(x + 2)(x + 4)(x-8)}\right) - \left(\dfrac{(x+1)(x-8)}{(x+2)(x+4)(x-8)}\right)\)

Now, we can foil out the numerators of each fraction and combining like terms.

\(A_\text{shaded} = \left(\dfrac{x^2 + 5x + 4}{(x + 2)(x + 4)(x-8)}\right) - \left(\dfrac{x^2 - 7x - 8}{(x+2)(x+4)(x-8)}\right)\)

↓ rewriting as one fraction ... \(\dfrac{x}{y} - \dfrac{z}{y} = \dfrac{x-z}{y}\)

\(A_\text{shaded} = \dfrac{ (x^2 + 5x + 4) - (x^2 - 7x - 8)}{(x + 2)(x + 4)(x-8)}\)

↓ distributing the negative

\(A_\text{shaded} = \dfrac{x^2 + 5x + 4 - x^2 + 7x + 8}{(x + 2)(x + 4)(x-8)}\)

↓ grouping like terms

\(A_\text{shaded} = \dfrac{(x^2 - x^2) + (5x + 7x) + (4 + 8)}{(x + 2)(x + 4)(x-8)}\)

↓ combining like terms

\(\boxed{A_\text{shaded} = \dfrac{12x + 12}{(x + 2)(x + 4)(x-8)}}\)

Answer: it will be 11

Step-by-step explanation:

Answer:

I simplified and got 11

Answer:

36720 different desserts

Step-by-step explanation:

(1020x3)x12=36720

Yes, Matrix B is invertible.

And, The eigenvalues of B−1 are;

⇒ (5 ± 7.68) / 14 - 1

An Invertible Matrix is a square matrix defined as invertible if the product of the matrix and its inverse is the identity matrix.

Given that;

B be a 2 ×2 matrix such that;

⇒ 7B² −5B + 3I = 0

Now,

Since, B be a 2 ×2 matrix.

And, The expression is,

⇒ 7B² −5B + 3I = 0

⇒ B² −5/7B + 3I/7 = 0

Multiply by B⁻¹, we get;

⇒ B - 5/7 + 3B⁻¹ = 0

Solve for B⁻¹;

⇒ 3B⁻¹ = - B + 5/7

⇒ B⁻¹ = - B/3 + 5/21

Thus, The matrix B is invertible.

And, The eigen value of B are;

⇒ 7B² −5B + 3I = 0

⇒ 7B² −5B + 3I = 0

⇒ B = - (-5) ± √(-5)² - 4×7×3 / 2×7

⇒ B = 5 ± √25 - 84/14

⇒ B = 5 ± √- 59 / 14

⇒ B = 5 ± 7.68 i / 14

⇒ B - 1 = (5 ± 7.68) / 14 - 1

Thus, Matrix B is invertible.

The eigenvalues of B−1 are = (5 ± 7.68) / 14 - 1

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Answer:

A) 5 times the sum of 3 and 4, then subtract 4

Answer: 1.) 2n 2.) z+6 3.) 20 years old

Step-by-step explanation:

Answer:

answer one: 2n

answer two: z + 6

answer three: 20 years old

Step-by-step explanation:

edge 2020