What is the reason for a stone sink in the water but a plastic floats?


Select one:
A.
The density of plastic is greater than stone
B.
Mass of the stone is greater than mass of plastics.
C.
The density of plastic is greater than water.
D.
The density of stone is greater than water.​

Answer: The head temperature rises as the vapors of lower-boiling compound fill the distillation head. The temperature drops because the lower-boiling compound finishes distilling before vapors of the higher-boiling compound can fill the distillation head, which then cause the head temperature to rise.

If the electric potential is zero everywhere along the x-axis in a certain region of space, it means that there is no change in electric potential as you move along the x-axis. This implies that the x component of the electric field is also zero.

Now, let's consider the scenario where the electric potential is +2 V everywhere along the x-axis. In this case, there is a constant increase in electric potential as you move along the x-axis. Since the electric field is related to the rate of change of electric potential, a constant increase in potential along the x-axis indicates that the x component of the electric field is non-zero.

To determine the exact value or direction of the x component of the electric field, we need more information. The electric field could have a positive or negative x component, depending on the direction of the increase in electric potential along the x-axis. We would need to know whether the electric potential is increasing or decreasing as you move in the positive x direction to conclude more definitively about the x component of the electric field.

In summary, when the electric potential is zero everywhere along the x-axis, the x component of the electric field is zero as well. However, when the electric potential is +2 V everywhere along the x-axis, we need more information to determine the exact value or direction of the x component of the electric field.

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The separation between the objective lens and the specimen when it is in focus is called depth of focus.

The depth of focus, or DOF, is the image-space counterpart of DOF and refers to how, as the sensor is moved, but the object stays in place, the quality of focus changes on the sensor side of the lens. The amount of tip and tilt that can be tolerated between the sensor plane and the lens picture plane is determined by the depth of focus. Tilt has a greater effect on attaining the best focus across the sensor as focus drops because the depth of focus also decreases as focus decreases. Without intentional alignment, there will always be some variance in the orthogonality between the utilized sensor and lens; it illustrates how this problem manifests itself. Problems with depth of focus alone are typically thought to be rare.

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The time taken for the stone to reach the ground when it is thrown above the ground is 0.57 s.

Given that,

Velocity of the stone = 6.38 m/s

Height above the ground = 1.63 m

The time t at which the stone's vertical position y(t) becomes zero is the amount of time it takes for it to fall to the earth.

It is given by the formula, y(t) = 1.63 - 1/2* 9.81* t² = 0

1.63 - 4.9 t² = 0

4.9 t² = 1.63

t² = 1.63/4.9 = 0.33

t = 0.57 s

Thus, the time taken by the stone to reach the ground is 0.57 s.

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Answer:

Rs 16.5 lakh is a charge of an electric car at a public charging station

If an air parcel cools adiabatically at the surface with a temperature of 17 °C, the temperature drops by about 10 °C for every 1000 meters of altitude. 500mb is typically about 5500 meters from the surface, so with dry adiabatic cooling the package temperature will be about 17°C - (10°C * 5.5) = -33°C.

On the other hand, if the air parcel is moist and adiabatically cooled, the temperature change will be slower because latent heat is released when the water vapor condenses. The adiabatic temperature drop rate when wet is typically about 6°C per 1000 meters.

However, it is generally cooler than the dry adiabatic decay rate, so for wet adiabatic cooling, the -15°C, -25°C, 0, and -35°C options are possible temperatures for a 500MB package. There is a possibility. . 

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If your body resistance is 100,000 ohms, then the current which would flow would be: 120v/100,000Ω=0.0012 amperes, which equals 1.2mA.

Answer:

The speed of sound is greater in hot air than it is in cold air. This is because the molecules of air are moving faster and the vibrations of the sound wave can therefore be transmitted faster. This means that when sound travels from hot air to cold air or from cold air to hot air it will refract.

Explanation:

Hope this will be help!

Answer:

vega the first one

pb

p

Explanation:

Answer:

B) Make the ramp longer

Explanation:

A machine is a device that makes work more easier and faster. A machine also saves time.

A ramp is a simple machine that is used to lift heavy object with a force that is lesser than the actually force needed. A ramp is in the shape of an inclined plane, which makes pushing an object easier than the required force needed.

The formula for a ramp is given by:

Force needed to push * length of the ramp = weight of object * height of ramp.

Force needed to push = (weight of object * height of ramp) / length of ramp

We can see that the force needed is inversely proportional to the ramp length. Hence for a ramp with longer length you need lesser force to raise the object.

Cocaine is considered a stimulant drug because it tends to increase overall levels of neural activity. This drug stimulates the central nervous system, leading to increased energy, alertness, and elevated mood. It is a potent and addictive drug that is derived from the leaves of the coca plant.

Cocaine works by blocking the reuptake of dopamine, norepinephrine, and serotonin, which are neurotransmitters that are responsible for regulating mood and behavior. When these neurotransmitters are released, they produce feelings of pleasure and reward. Cocaine use can lead to tolerance, dependence, and addiction, as well as a range of negative health effects such as heart attack, stroke, and respiratory failure.

In conclusion, Cocaine is considered a stimulant drug because it tends to increase overall levels of neural activity.

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Answer:

The speed of the wave is 15ms .

Explanation:

Answer:

B. 24.2 m/s

Explanation:

Given;

mass of the roller coaster, m = 450 kg

height of the roller coaster, h = 30 m

The maximum potential energy of the roller coaster  due to its height is given by;

\(P.E_{max} = mgh\\\\PE_{max} = 450 *9.8*30\\\\PE_{max} = 132,300 \ J\)

\(P.E_{max} = K.E_{max} \ (law \ of \ conservation\ of \ energy)\)

\(K.E_{max} = \frac{1}{2}mv_{max}^2\\\\ v_{max}^2 = \frac{2K.E_{max}}{m}\\\\ v_{max}^2 = \frac{2*132300}{450}\\\\ v_{max}^2 =588\\\\v_{max} = \sqrt{588}\\\\ v_{max} = 24.2 \ m/s\)

Therefore, the maximum speed of the roller coaster is 24.2 m/s.

Answer:

1. 24.2 m/s

2. 20.4 m

3. 22.5 m/s

4. 109,375 J

5. It is easy to calculate new scenarios.

Explanation:

5/5 on the Maximum Energy Quick Check

Answer:

(a) By small angle approximation, we have;

F = -2×T×Δy/l

(b) \(The \ frequency \ of \ oscillation, \ f = \dfrac{1}{2\cdot \pi }\cdot\sqrt{\dfrac{2 \cdot T}{l \cdot M} }\)

Explanation:

(a) The diagram shows the mass, M, being restored by two equal tension, T acting on the elastic strings l, such the restoring force, F acts along the path of motion of the mass, with distance Δy

Therefore, the component of the tension T that form part of the restoring force is given as follows;

Let the angle between the line representing the extension of the elastic strings T and the initial position of the string = ∅

Then we have;

String force, \(F_{string}\) = T×sin∅ + T×cos∅ + T×sin∅ - T×cos∅  = 2×T×sin∅

Whereby the angle is small, we have;

sin∅ ≈ tan∅ = Δy/l

Which gives;

\(F_{string}\) = 2×T×sin∅ = 2×T×Δy/l (for small angles)

Restoring force F = \(-F_{string}\) = -2×T×Δy/l

F = -2×T×Δy/l

(b) Given that the the tensions do not change appreciably as the mass, M, oscillates from Δy we have;

By Hooke's law, F = -k×x

Whereby Δy corresponds to the maximum displacement of the mass, M from the rest position, which gives;

Which gives;

F = M×a = -k×Δy

a =  -k×Δy/M

d²(Δy)/dt² =  -k×Δy/M

When we put angular frequency as follows;

ω² = k/M

We get;

d²(Δy)/dt² =  -ω²×Δy

Which gives;

Δy(t) = A×cos(ωt + Ф)

The angular frequency is thus, ω = √(k/M)

Period of oscillation = 2·π/ω = 2·π/√(k/M)

The frequency of oscillation, f = 1/T = √(k/M)/(2·π)

Where:

k = 2·T/l, we have;

f = √(k/M)/(2·π) = √(2·T/l)/m)/(2·π)

The frequency of oscillation is given as follows;

\(f = \dfrac{1}{2\cdot \pi }\cdot\sqrt{\dfrac{2 \cdot T}{l \cdot M} }\)

The X component of the tiger's velocity is 53.59 km/h.

The vertical (Y) component of the tiger's velocity is 12.37 km/h.

The components of the tiger's velocity include X and Y components; the magnitudes of the X and Y components is calculated using the following formula.

The X component of the tiger's velocity is calculated as;

Vx = V cosθ

where;

Vx = 55 km/h  x  cos (13)

Vx = 53.59 km/h

The vertical (Y) component of the tiger's velocity is calculated as;

Vy = V sinθ

Vy = 55 km/h  x sin (13)

Vy = 12.37 km/h

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Answer:

d = 100.56 m

Explanation:

It is given that,

Force acting on the dog is 22.4 N

Angle at which the force is applied is 115 º

Work done is - 42.3 J

We need to find the distance covered by the dog. The work done by an object is given by :

\(W=Fd\cos\theta\)

d = distance covered by the dog

\(d=\dfrac{W}{\cos\theta}\\\\d=\dfrac{-42.5}{\cos(115)}\\\\d=100.56\ m\)

So, the dog moves a distance of 100.56 m.

Answer:

4.47 M.

Explanation:

I do Acellus and just got it correct!

The initial velocity at which the rock must be thrown to attain the given final velocity is 442.72 m/s.

The initial velocity with which the rock must be thrown to attain the final velocity of 3 m/s is calculated by using the following kinematic equation.

Mathematically, the equation of the motion of the rock is given as;

v² = u² - 2gh

where;

Assuming the following parameters;

Substitute the given parameter and solve for the initial velocity of the rock as shown below.

u² = v² + 2gh

u² = (3²) + (2 x 9.8 x 10,000)

u² = 196,009

u = √196,009

u = 442.72 m/s

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If the volume of a gas decreases, the pressure will increase. This is because the gas molecules will have less space to move around, so they will collide with the walls of the container more often. The more often the gas molecules collide with the walls of the container, the higher the pressure will be.

This is known as Boyle's law, which states that for a fixed mass of an ideal gas kept at a fixed temperature, pressure and volume are inversely proportional. This means that if the volume of a gas is decreased, the pressure will increase proportionally.

For example, if the volume of a gas is decreased by half, the pressure will double. If the volume of a gas is decreased by a quarter, the pressure will quadruple.

Boyle's law is one of the gas laws, which are a set of equations that describe the behavior of gases. The other gas laws are Charles' law, Gay-Lussac's law, and Avogadro's law.

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Object 1 was travelling faster than Object 2, as it had a larger slope on the velocity versus time graph.

Object 1 and Object 2 have different slopes on the velocity versus time (x vs t) graph, indicating that the two objects had different velocities. The slope of Object 1 is 1.2754 m/s and the slope of Object 2 is 0.7249 m/s.

The fact that the plots are linear tells us that the velocity of both objects is constant.

The average velocity for each object can be determined by the slope of the line, which is the change in position (x) divided by the change in time. Therefore, the larger the slope, the greater the velocity.

From this, we can determine that Object 1 was travelling faster because it had a larger slope, indicating a larger change in position (x) over time, compared to Object 2.

The Position versus Time squared (x vs t2) graph for Object 3 shows that the acceleration is constant because the graph is linear. The slope of this line is 0.0628 m/s2, which is the average acceleration of the object.

The acceleration is determined by the change in velocity over time, which can be calculated from the change in the slope. From this, we can see that the acceleration of Object 3 is constant.

Overall, the three graphs indicate that the velocity and acceleration of these objects is constant.

The velocity of each object can be determined by the slope of the velocity versus time graph, and the acceleration can be determined by the slope of the position versus time squared graph.

Object 1 was travelling faster than Object 2, as it had a larger slope on the velocity versus time graph.

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Based on the given information, the most appropriate classification for the state of the volcano would be "Active-Dormant."

The volcano's history of generating multiple lava flows over the past 10,000 years indicates that it has been active in the relatively recent past. The presence of lava flows that have spread over large areas suggests ongoing volcanic activity, although not necessarily in the immediate present.

Additionally, the mention of very little tephra (volcanic ash and fragments) indicates that the volcano is not currently experiencing explosive eruptions. Instead, it has been primarily characterized by effusive eruptions that produce lava flows.

The fact that people in the nearby town remember the last eruption, which caused some forest fires, further supports the classification of the volcano as active-dormant. While the volcano may not be actively erupting at the moment, the memory of the recent eruption and the potential for future volcanic activity suggests that it is still in a state of activity, albeit in a relatively dormant phase.

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The complete table are:

Variable Changed : outcome

In regards to the question, It's important to note that these predictions are based on basic physics principles and assumptions, and actual results may vary depending on the specific materials and measurements used in Darnell's bell design.

Additionally, other variables such as the shape and thickness of the bell may also affect the loudness of the ring, so Darnell may want to consider these factors as well when making changes to his design.

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The magnetic field is \(\vec B = \frac{\mu_0 jR^2}{2r}\hat \theta\).

The area in which the force of magnetism works around a magnetic substance or a moving electric charge is known as the magnetic field. a diagram that shows the magnetic field and how a magnetic force is distributed within and outside of a magnetic substance.

a) the magnetic field, B outside the wire

Using ampere law:

\(\int Bdl = \mu_0 I_{net}\)

so:

\(B(2\pi r) = \mu_0 (jA) = \mu_0 j(\pi R^2)\)

\(B = \frac{\mu_0 jR^2}{2r}\\\)

the direction is in\(\hat \theta\)

\(\vec B = \frac{\mu_0 jR^2}{2r}\hat \theta\)

b) the magnetic field, B inside the wire

Using ampere law:

\(\int Bdl = \mu_0 I_{net}\)

so:

\(B(2\pi r) = \mu_0 (jA) = \mu_0 j(\pi r^2)\)

\(B = \frac{\mu_0 jr}{2}\)

the direction is in\(\hat \theta\)

\(\vec B = \frac{\mu_0 jr}{2}\hat \theta\)

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It is 1.93 metres away from the post.

for vertical motion

\(S= u t + \frac{1}{2} g t^{2}\)

S = 0 +  \(\frac{1}{2} g t^{2}\)

1.7 = \(\frac{1}{2} 9.8 t^{2}\)

t = 0.589 sec

using law of  conservation of momentum, on the horizontal motion

\(m_{bullet} \ v_{bullet i} = m_{bullet} \ v_{bullet f} + m_{tin} \ v_{tin}\)

\(0.0020 = 0.0020 \ 3 \ 720 + 0.11 \ v_{tin}\)

\(v_{tin}\) = 3.273 m/s

S = \(v_{tin} \ t\)

   = 3.273 m/s * 0.589 s

   = 1.93 m

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Answer:

Elasticity

Elasticity is the ability of rubber, for example to return to it's natural shape after being bent and forced in different directions.

Answer:

Elasticity

Explanation:

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The diagram of the eye correctly focuses a distant object onto the retina when the eye is air-filled. The image formed will be behind the retina if the eye is filled with water.

The diagram of the eye is shown below: It correctly focuses a distant object onto the retina when the eye is air-filled. If the eye is actually filled with water, the image formed will be behind the retina. This is because the refractive index of water is higher than that of air, and this causes the image to be formed further back. The diagram below shows this change when the eye is filled with water.

The diagram of the eye correctly focuses a distant object onto the retina when the eye is air-filled. The image formed will be behind the retina if the eye is filled with water.

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This question deals with the physics of resonance and sound. The possible frequency of the pano key is 258hz.

The beat of a frequency is the difference (an absolute value) in the frequencies produced by the two waves.

Beat per second equals |f1 - f2| Where

ft = Frequency of the Tunning fork and

fp= Frequency of the Piano Key

Hence

3 =  261 - fp

Solving for fp,

fp = 261-3

= 258hz

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Answer:d

Explanation:

I took the quiz and I got that question right :)

The activity of 1.0 g of 226Ra is approximately 2.19 x \(10^4\) Bq.

Activity = decay constant x number of atoms

The decay constant of 226Ra is:

decay constant = ln(2) / half-life = ln(2) / (1600 years x 365.25 days/year x 24 hours/day x 3600 seconds/hour) ≈ 4.95 x \(10^{-12} s^{-1\)

The number of atoms in 1.0 g of 226Ra is:

number of atoms = mass / molar mass = 1.0 g / 226 g/mol = 4.42 x \(10^{-3\)mol

Multiplying the decay constant and the number of atoms, we get:

Activity = decay constant x number of atoms = (4.95 x \(10^{-12} s^{-1\)) x (4.42 x \(10^{-3\) mol) ≈ 2.19 x \(10^4\) Bq

The decay constant is a measure of the probability of a radioactive atom decaying per unit of time. It is a fundamental concept used to describe the behavior of radioactive decay and is denoted by the symbol λ (lambda). The decay constant is related to the half-life of a radioactive material, which is the time required for half of the material to decay.

The decay constant is determined by the type of radioactive decay, as each type of decay has a unique probability of occurring. For example, the decay constant for alpha decay is typically much higher than that of beta decay. The decay constant can be calculated using the activity of the radioactive material, which is the rate at which it emits radiation. The decay constant is a critical parameter in the prediction of the behavior of radioactive materials and their potential impact on the environment.

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Answer:

In the wild, clownfish rarely leave their anemone home. In fact, part of its purpose is to defend the anemone from other fish. However, clownfish bred in aquariums (without an anemone home) may still have this instinct, but it’s much calmer than wild harvested species.

Explanation:

Answer:

78.02 V

Explanation:

Given that,

Primary voltage in a transformer is 120 V

No of windings in the primary coil is 100

No of windings in the secondary coil is 65

We need to find the outgoing voltage of the transformer. For a transformer, the ratio of primary voltage to the secondary voltage is equal to the ratio of turns in Primary coil to the turns in secondary coil are equal. So,

\(\dfrac{V_p}{V_s}=\dfrac{N_p}{N_s}\\\\\dfrac{120}{V_s}=\dfrac{100}{65}\\\\V_s=\dfrac{120\times 65}{100}\\\\V_s=78\ V\)

So, out of the given options, the correct one is option (d) i.e. 78.02 V