What is the product of d−9 and 2d2+11d−4 ?

Answer:

Angle EHG

Step-by-step explanation:

If you want explanation tell me in comments

Answer:

the correct answer is angle EHB

Answer:

It states that when the elevation (Y) goes from 900 to 800 feet, the time (X) transitions from 90 to 120 mintes

The z-score with probability 0.225 to the right is 0.15 and the z-score with probability 0.900 to the left is -1.28. This can be calculated using the Z-score table for a standard normal distribution.

(a) Probability 0.225 to the right is equal to z-score 0.15.

This can be calculated using the Z-score table for a standard normal distribution.

The probability to the right of z-score is equal to the cumulative probability of the z-score.

The cumulative probability of 0.15 is 0.225, which is the probability to the right.

(b) Probability 0.900 to the left is equal to z-score -1.28.

This can be calculated using the Z-score table for a standard normal distribution.

The probability to the left of z-score is equal to the cumulative probability of the z-score.

The cumulative probability of -1.28 is 0.900, which is the probability to the left.

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Answer:

y=x+2

Step-by-step explanation:

In this picture ( step by step )

Answer:

B 71 & 71

Step-by-step explanation:

OP is an angle bisector

Answer:

B

Step-by-step explanation:

Since angles MOP and NOP are both labeled as 2x+1, they must both be equivalent. The only answer choice which shows them to be equivalent is B.

Verification:

(2x+1)+(2x+1)=142

4x=140

x=35

(substitution)

2(35)+1 = 71

The length of the edge of the cube with the given total surface area is 7.1 inches.

The region that includes the base(s) and the curved portion is referred to as the total surface area. It is the overall area that the object's surface occupies. The total area of a form with a curved base and surface is equal to the sum of the two areas.

Let us suppose the length of an edge of the cube = l.

The total surface are of the cube is given as:

TSA = 6l²

Substituting TSA = 302.46 we have:

302.46 = 6l²

l² = 50.41

l = 7.1 in.

Hence, the length of the edge of the cube with the given total surface area is 7.1 inches.

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Answer:

1, 4, and 7

Step-by-step explanation:

1, 7, 4

Opposite angles are congruent

The elements of Z3[x]/(x^2 - x) are of the form ax + b that is multiplication table, where a and b are elements of Z3.

The multiplication table is:

  | 0   1   x   1+x   2   2+x

-------------------------------

0 | 0   0   0    0   0   0

1 | 0   1   x   1+x  2  2+x

x | 0   x  2x  2+x   x  1+2x

1+x| 0  1+x 2+x   2  2+x  x

2 | 0   2   x   2+x  1  1+x

2+x| 0  2+x 1+2x  x  1+x 2

Note that in this table, we use the fact that x^2 - x = 0, which implies that x^2 = x.

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Answer:

2 $

Step-by-step explanation:

let the original price be x

price after 10% discount = 3.60$

\(x - \frac{10}{100} \times x = 3.60 \)

\( \frac{100x - 10x}{100} = 3.60 \\ \frac{90x}{100} = 3.60 \\ 9x = 36 \\ x = 4\)

The original price of 2 pens is 4$

original price of one pen = 4/ 2

= 2 $

The range would be the most appropriate measure of spread in this case because it takes into account the extreme values of $300 and $1,300 and provides a clear measure of the difference between them.

To measure the amount of money college students spend on rent per month, the most appropriate measure of spread would be the range. The range is the simplest measure of spread and is calculated by subtracting the lowest value from the highest value in a data set. In this case, the range would be $1,300 - $300 = $1,000.

The median would not be the best choice in this scenario because it only represents the middle value in a data set. It does not take into account extreme values like the $1,300 rent expense.

Standard deviation would not be the most appropriate measure of spread in this case because it calculates the average deviation of each data point from the mean. However, it may not accurately represent the spread when extreme values like the $1,300 rent expense are present.

The interquartile range (IQR) would not be the best choice either because it measures the spread of the middle 50% of the data set. It does not consider extreme values and would not accurately represent the range of rent expenses in this scenario.

In summary, the range would be the most appropriate measure of spread in this case because it takes into account the extreme values of $300 and $1,300 and provides a clear measure of the difference between them.

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Answer: In a right triangle, the length of the hypotenuse is the square root of the sum of the squares of the other two legs. So, using the Pythagorean theorem, the other leg would be the square root of (21^2 - 15^2) = (441 - 225) = 216 = 14.69 inches.

Step-by-step explanation:

To find the gradient vector ∇f(4, 7), we need to compute the partial derivatives of f(x, y) = xy with respect to x and y.

Given:

f(x, y) = xy

Partial derivative with respect to x (keeping y constant):

∂f/∂x = y

Partial derivative with respect to y (keeping x constant):

∂f/∂y = x

So, the gradient vector ∇f(4, 7) is (∂f/∂x, ∂f/∂y) evaluated at (4, 7):

∇f(4, 7) = (7, 4)

The equation of the tangent line to the level curve f(x, y) = 28 at the point (4, 7) can be written as:

z - f(4, 7) = ∇f(4, 7) · (x - 4, y - 7)

Substituting the values:

z - 28 = (7, 4) · (x - 4, y - 7)

Expanding the dot product:

z - 28 = 7(x - 4) + 4(y - 7)

z - 28 = 7x - 28 + 4y - 28

z = 7x + 4y - 56

Therefore, the equation of the tangent line to the level curve f(x, y) = 28 at the point (4, 7) is z = 7x + 4y - 56.

To sketch the level curve, the tangent line, and the gradient vector, you can plot the points on a graph with x and y coordinates and represent the tangent line as a straight line passing through the point (4, 7) with a slope of 7/4. The gradient vector (7, 4) can be represented as an arrow starting from the point (4, 7) in the direction of the vector.

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No, it is not true that ∫_0^1 l(θ | x0) dθ = 1. The integral of the likelihood function l(θ | x0) over the parameter space [0, 1] does not necessarily equal 1.

The likelihood function l(θ | x0) measures the probability of observing the data x0 given the parameter value θ. It is a function of the parameter θ, and not a probability distribution over θ.

Therefore, the integral of the likelihood function over the parameter space does not have to equal 1, unlike the integral of a probability density function over its support.

In fact, the integral of the likelihood function over the parameter space is often referred to as the marginal likelihood or the evidence, and is used in Bayesian inference to compute the posterior distribution of the parameter θ given the data x0. The marginal likelihood is given by: ∫_0^1 l(θ | x0) p(θ) dθ

where p(θ) is the prior distribution of the parameter θ. The marginal likelihood is used to normalize the posterior distribution so that it integrates to 1:
p(θ | x0) = l(θ | x0) p(θ) / ∫_0^1 l(θ | x0) p(θ) dθ

In conclusion, the integral of the likelihood function over the parameter space does not necessarily equal 1, and is used in Bayesian inference to compute the posterior distribution of the parameter θ given the data x0.

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Answer:

multiply 2 times 7 then 9 times 2 then 9 times 7. add them up and you will get your answer

Step-by-step explanation:

The expression states that for every linear polynomial p with real coefficients and a nonzero coefficient of x, there is exactly one real root r.

For all linear polynomials with real coefficients and a nonzero coefficient of x, there exists exactly one real root. This can be expressed using the universal quantifier "for all" and the existential quantifier "there exists", connected by the logical connective "and". Additionally, the statement "exactly one real root" can be expressed using the quantifier "there exists" and the logical connective "and".

Using quantifiers and logical connectives, we can express the given fact as follows:

∀p ∃!r ((isLinearPolynomial(p) ∧ hasRealCoefficients(p) ∧ coefficientOfX(p) ≠ 0) → hasRealRoot(p, r))

Explanation:

- ∀p: For every polynomial p
- ∃!r: There exists exactly one real root r
- isLinearPolynomial(p): p is a linear polynomial (degree 1)
- hasRealCoefficients(p): p has real coefficients
- coefficientOfX(p) ≠ 0: The coefficient of x in p is nonzero
- hasRealRoot(p, r): p has a real root r

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Answer:

\(\frac{2}{9}\)

Step-by-step explanation:

The probability of an event is calculated by dividing the number of successful outcomes by the number of total outcomes. In an algebraic expression, that would be \(\frac{successful}{total}\).

In this case, there are a total of \(20+15+10=45\) ways to choose any ball, since there are \(45\) balls in the box. However, only \(10\) are yellow, so there are \(10\) ways to successfully choose a yellow ball. Therefore, the probability of choosing a yellow ball is \(\frac{10}{45}=\frac{2}{9}\). Hope this helps!

Step-by-step explanation:

(-2^-4)×(2×4^3)÷16

16×(2×64)÷16

16×128÷16

2048÷16

128

Answer:

15, 80

Step-by-step explanation:

Angle of triangle=180 degrees

180-85=95

3x+16x=95

19x=95

x=95/19

x=5

3x=15

16x=80

Answer: 3

Step-by-step explanation:

3x2 = 6

6+8=14

Cluster analysis is a valuable tool in data analysis that helps identify hidden patterns and group similar objects or data points.

It is useful in various fields, such as market research, image analysis, customer segmentation, and anomaly detection. By clustering data, we can gain insights, make predictions, and improve decision-making. Hierarchical clustering is a specific approach to cluster analysis. It organizes data points into a hierarchy of clusters, where each cluster can contain subclusters. This method allows for a hierarchical structure that captures different levels of similarity or dissimilarity between data points.

For example, in customer segmentation, hierarchical clustering can group customers based on similar attributes like demographics, purchase history, and behavior. In image analysis, it can be used to segment images into meaningful regions or objects based on their visual characteristics. Hierarchical clustering offers a flexible and interpretable way to analyze complex datasets and discover underlying structures.

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Answer:

The price of rice per gram is 4.50 / 750 = 0.006 dollars per gram.

Step-by-step explanation:

David wants to make 10 servings, where each serving has 75 grams of rice. So, he needs a total of 10 * 75 = 750 grams of rice. the price of rice per gram is 4.50 / 750 = 0.006 dollars per gram.

Answer:

The answer would be 25.

4x4=16

16+9=25

Step-by-step explanation:

I believe this is correct, if not feel free to let me know and I will fix it. I'm sorry in advance if it is incorrect.

Answer:

25

Step-by-step explanation:

rewrite the equation

(4x4)+9

do the equation

16+9=25

Taylor polynomials of degree 2 and 3 centered at x = 0 for the function f(x) = 16tan(x) are:

P2(x) = 16x + 8x^2

P3(x) = 16x + 8x^2

To find the Taylor polynomials centered at x = 0 for the function f(x) = 16tan(x), we can use the Taylor series expansion for the tangent function and truncate it to the desired degree.

The Taylor series expansion for tangent function is:

tan(x) = x + (1/3)x^3 + (2/15)x^5 + (17/315)x^7 + ...

Using this expansion, we can find the Taylor polynomials of degree 2 and 3 centered at x = 0:

Degree 2 Taylor polynomial:

P2(x) = f(0) + f'(0)(x - 0) + (1/2!)f''(0)(x - 0)^2

= 16tan(0) + 16sec^2(0)(x - 0) + (1/2!)16sec^2(0)(x - 0)^2

= 0 + 16x + 8x^2

Degree 3 Taylor polynomial:

P3(x) = P2(x) + (1/3!)f'''(0)(x - 0)^3

= 0 + 16x + 8x^2 + (1/3!)(48sec^2(0)tan(0))(x - 0)^3

= 16x + 8x^2

Therefore, the Taylor polynomials of degree 2 and 3 centered at x = 0 for the function f(x) = 16tan(x) are:

P2(x) = 16x + 8x^2

P3(x) = 16x + 8x^2

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Percy earns a greater hourly wage of $7.50 at the coffee cart.

Percy earns a greater hourly wage of $7.50 at the coffee cart compared to the wage at the library, which is $7.00. This difference in wages is the reason why Percy earns more per hour at the coffee cart.

When it is stated that the wage at the coffee cart is higher, it means that employees working at the coffee cart are paid a higher rate per hour compared to those working at the library. In this case, the coffee cart pays $7.50 per hour, while the library pays $7.00 per hour.

As a result, when Percy works at the coffee cart, they are compensated at a higher rate for each hour worked, which results in a higher wage. By earning $0.50 more per hour, Percy's total earnings for the same amount of time worked would be greater at the coffee cart than at the library.

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Answer:

The correct answare should be slope of 3.

Step-by-step explanation:

Well if the red line has the slope of 3 and the green and the red are parrallel than the slope of green should also be 3.

\(\measuredangle A\cong \measuredangle E\implies 112=16x\implies \cfrac{112}{16}=x\implies \boxed{7=x} \\\\[-0.35em] ~\dotfill\\\\ \overline{MS}\cong \overline{NR}\implies 41=3x+5y\implies 41=3(7)+5y\implies 41=21+5y \\\\\\ 20=5y\implies \cfrac{20}{5}=y\implies \boxed{4=y}\)

Answer:

(a x b ) : (b x b ) : (b x c)

5x3 : 6x3 : 6 x 8

Step-by-step explanation:

15:18:48

The interval where the derivative function f'(x) has a relative maximum is -2.478 and 1.732 (B) only.

To find the relative maximum of a function, we need to find the critical points of the derivative function. Critical points are where the derivative function is equal to zero or undefined. In this case, the derivative function is f'(x) = sin(x^2 − 3).

To find the critical points, we need to set the derivative function equal to zero and solve for x:
sin(x² − 3) = 0

x² − 3 = nπ, where n is an integer

x² = nπ + 3

x = ±√(nπ + 3)

We need to find the values of x that are in the interval −3 < x < 3. By plugging in different values of n, we can find the critical points in this interval:

n = 0: x = ±√3 ≈ ±1.732

n = 1: x = ±√(π + 3) ≈ ±2.478

n = 2: x = ±√(2π + 3) ≈ ±2.915 (not in the interval)

So the critical points in the interval are -2.478, -1.732, 1.732, and 2.478.

To determine which of these are relative maximums, we need to look at the sign of the derivative function on either side of the critical points. If the derivative function changes from positive to negative at a critical point, then that point is a relative maximum.

At x = -2.478, the derivative function changes from positive to negative, so this is a relative maximum.

At x = -1.732, the derivative function changes from negative to positive, so this is not a relative maximum.

At x = 1.732, the derivative function changes from positive to negative, so this is a relative maximum.

At x = 2.478, the derivative function changes from negative to positive, so this is not a relative maximum.

Therefore, the values of x in the interval −3 < x < 3 where f has a relative maximum are -2.478 and 1.732.

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