Answers
Answer:D
The momentum of an object is defined as the product of its mass and velocity. So, to calculate the momentum of an object with a mass of 750 kg and a velocity of 15 m/s, we can use the following formula:
Momentum = mass x velocity
Momentum = 750 kg x 15 m/s
Momentum = 11,250 kg m/s
Therefore, the momentum of the object is 11,250 kg m/s.
Related Questions
If a person pulls on a cart to the right with a force of 10 N, and a second person pulls to the left with a force of 3 N, what is the net force on the cart? (Please show work with units and the direction the answer goes in)
Answers
The net force on the cart is 7 N to the right. The unit of force is Newtons (N).
What factors influence a cart?Unlike the frictional force , which operates in the opposite direction to the cart's velocity, gravitational force on the cart always points in the same direction, regardless of the cart's motion.
What kind of force pushes or pulls?A pull is a force that causes an object to move closer to you. On the other side, it is a push if it travels away. An object may experience a push or pull as a result of interacting with another object, which is a common definition of force. Hence, any force is essentially a push or a pull.
Net force = 10 N to the right - 3 N to the left
Simplifying, we get:
Net force = 10 N - 3 N
Net force = 7 N to the right
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a 56.5 kg skateboarder starts out with a speed of 1.75 m s he does 80.0 j of work on himself by pushing with his feet against the ground in addition friction does 265 j of work on him in both cases the forces doing the work are non conservative the final speed of the skateboarder is 6.00 m s. (a) Calculate the change (ΔPE = PEf-PE0) in the gravitational potential energy. (b) How much has the vertical height of the skater changed?
(c) Is the skater above or below the starting point?
Answers
a)The gravitational potential energy has changed by 1536.92 joules.
b) The skateboarder's vertical height fluctuated by 2.919 meters.
How to apply the law of conservation of energy and the law of work?Energy to a skateboarder (a) - 1620.8J
The skateboarder's initial kinetic energy is given by K i = 1/2 * mu 2 = 1/2 * (56.5kg) * (2.44m/s) 2 = 165.5J, whereas his final kinetic energy is given by K f = 1/2 * m * v 2 = 1/2 * (56.5kg) * (7.24m/s) 2 = 1457.2J, where v is his final speed.
The kinetic energy shift is therefore Delta*K = K f - K i = 1457.2J - 166.5.J = 1290.6J.
The change in the skateboarder's mechanical energy (kinetic plus potential) is equal to the work done on
it: W = 80.0J is the effort the skateboarder did on himself, therefore Delta*K + Delta*E p = W + W f
The amount of work done by friction is W f = 265J.
The shift in gravitational potential energy is represented by the formula Delta*E p =E pf -E pi.
Delta*K = 80.0J - 265J - 1457.2J = - 1620.8J, where Delta*E p = W + W f - Delta*K.
(b) 2.97 m
The skateboarder's shift in potential energy may be expressed mathematically as Delta*E p = mg*Delta*h.
where g = 9.8m / (s 2) is the acceleration of gravity and m = 56.5 kg is the mass.
The skateboarder's change in vertical height is measured by delta*h.
Delta*h is calculated as (Delta*E p)/(mg) = (- 1620.8J)/((56.5kg)(9.8m / (s 2))) = - 2.99m.
Where the skateboarder has descended as indicated by the negative symbol. Because we are only concerned with the absolute value, the solution is h = 2.99m.
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Part-II Work out Step by step clearly (6%) 5. A 5kg mass starts from rest at xo = -1 and moves under the action of a variable force F(x) = √1-x² to point xf = 1. Calculate the total work done by the force? (1%)
Answers
If a 5kg mass starts from rest at xo = -1 and moves under the action of a variable force F(x) = √1-x² to point xf = 1. Then the total work done by the force is equal to π/2 + 1.
To calculate the total work done by the force in this scenario, we can use the formula for work:
Work = ∫F(x) dx
where F(x) is the force as a function of position and dx represents an infinitesimal displacement.
In this case, the force is given by F(x) = √(1 - x²), and we need to find the total work done as the object moves from xo = -1 to xf = 1.
Let's break down the calculation step by step:
Write the integral for work:
Work = ∫F(x) dx
Substitute the given force:
Work = ∫√(1 - x²) dx
Integrate with respect to x:
To integrate the square root of (1 - x²), we use the trigonometric substitution. Let's substitute x = sin(θ) and dx = cos(θ) dθ.
Work = ∫√(1 - sin²(θ)) cos(θ) dθ
Simplify the integrand:
Using the trigonometric identity sin²(θ) + cos²(θ) = 1, we can rewrite the integrand as cos²(θ).
Work = ∫cos²(θ) dθ
Apply the power-reducing formula:
The power-reducing formula states that cos²(θ) = (1 + cos(2θ)) / 2. We can use this formula to simplify the integrand further.
Work = ∫(1 + cos(2θ))/2 dθ
Integrate the terms separately:
Work = (1/2) ∫dθ + (1/2) ∫cos(2θ) dθ
The first integral, ∫dθ, is simply θ, and the second integral, ∫cos(2θ) dθ, can be calculated as sin(2θ)/2.
Work = (1/2) θ + (1/2) (sin(2θ)/2) + C
Evaluate the integral limits:
To find the total work done, we need to evaluate the integral at the upper and lower limits of integration.
At xf = 1, the angle θ is π/2, and at xo = -1, the angle θ is -π/2.
Work = (1/2) (π/2) + (1/2) (sin(2(π/2))/2) - [(1/2) (-π/2) + (1/2) (sin(2(-π/2))/2)]
Simplifying further:
Work = π/4 + (1/2) - (-π/4 + (1/2))
Work = π/4 + 1/2 + π/4 + 1/2
Work = π/2 + 1
Therefore, the total work done by the force is equal to π/2 + 1.
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1)What is the pressure at point D in kPa ?
2)Temperature at point D
3)What is the net work done on the gas as it is taken through four cycles?
4)What is the internal energy of the gas when it is at point A?
5)What is the total change in internal energy of this gas during four complete cycles?
Answers
The answer is 1) The pressure at point D is 80 kPa. 2) The temperature at point D is 800 K. 3) The net work done on the gas over four cycles is zero. 4) The internal energy of the gas at point A is 100 J. 5) The total change in internal energy during four complete cycles is zero.
The total change in internal energy of this gas during four complete cycles is zero. The given diagram represents the Carnot cycle involving four stages. The four stages of the Carnot cycle are reversible and follow an ideal gas that is placed in a cylinder with a movable piston.Let's solve each question asked one by one.1) From the graph, it can be observed that the pressure at point D is 0.08 M Pa, which is equal to 80 kPa. Hence, the pressure at point D in kPa is 80 kPa.2) Temperature at point D The isotherm at point D is about 800 K. Hence, the temperature at point D is 800 K.3) The net work done on the gas as it is taken through four cycles is zero because the Carnot cycle is a cycle that has four stages. In each cycle, the net work done is the area enclosed by the cycle. Therefore, for a complete cycle, the net work done is zero because the area enclosed is a loop.4) The internal energy of the gas when it is at point A is 100 J because the internal energy of the gas is directly proportional to the temperature and volume. Here, at point A, the temperature is 500 K, and the volume is 2 m³, so the internal energy of the gas when it is at point A is 100 J.5) The Carnot cycle is a reversible cycle that is used to determine the efficiency of heat engines. It is a closed cycle that does not involve any net energy exchange with the surroundings. Therefore, the total change in internal energy of this gas during four complete cycles is zero since the initial and final states are the same. Hence, the total change in internal energy of this gas during four complete cycles is zero.For more questions on the Carnot cycle, click on:
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What are 2 factors that affect gravity? *
Answers
If you lie on the ground at night with no cover, you get cold rather quickly. Much of this is due to energy loss by radiation. At night in a dry climate, the temperature of the sky can drop to −40∘C. If you are lying on the ground with thin clothing that provides little insulation, the surface temperature of your skin and clothes will be about 30∘C. Estimate the net rate at which you body loses energy by radiation to the night sky under these conditions. Hint: What area should we use?
Answers
Answer:
301.48 J/s
Explanation:
We are given;
Temperature of the sky dropping to −40∘C: T_o = -40°C = -40 + 273 = 233 K
Temperature of your skin and clothes: T = 30°C = 30 + 273 = 303 K
Body surface area of human body is around 2 m². But here only half of the body is facing the sky, Thus Area is: A = 2/2 = 1 m²
To solve this, we will use the equation for thermal heat transfer known as the Stefan bolt Mann equation.
ΔQ/Δt = εσA(T⁴ - (T_o)⁴)
Where;
ΔQ/Δt is the rate at which you body loses energy by radiation
ε is the emissivity of the human body with a value of 0.97
σ is Stefan boltzmann constant with a value of 5.67 X 10^(-8) W/m².K⁴
Thus;
ΔQ/Δt = 0.97 × 5.67 X 10^(-8) × 1(303⁴ - 233⁴)
ΔQ/Δt = 301.48 J/s
In the video, the students create two charged tapes, a "pointy" tape and a "square" tape. The pointy tape is first placed on top of the square tape, and the two are pulled apart. After pulling them apart, the students observed the behavior of the tapes when they were brought near each other, but not touching each other.
Answers
The two pointy tapes repel. This shows they have the same type of charge.
Attraction of two chargesThe attraction of two charges occurs when the two charges have opposite charges.
Repulsion of two chargesThe repulsion of two charges occurs when the two charges have similar charges.
Thus, since the two pointy tapes will have the same charge, we can conclude that they will repel each other when brought near each other.
The complete question is below:
How did the pointy tapes behave when brought near each other, and what does this demonstrate about their charges?
Two pointy tapes repel. This shows they have opposite types of charge.
Two pointy tapes attract. This shows they have opposite types of charge.
Two pointy tapes repel. This shows they have the same type of charge.
Two pointy tapes attract. This shows they have the same type of charge.
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Which process describes the warm ocean that transfers heat to the air above it?
O conduction
O convection
O reflection
O radiation
Answers
Answer:
convection is the answer
The process that describes the warm ocean that transfers heat to the air above it is known as Convection. Thus, the correct option for this question is B.
What are some characteristics of heat?Some characteristics of heat are as follows:
It has no mass, shape, color, odor, volume, and weight.It is one of the invisible forms of energy.It stimulates the presence of warmth.It gets remarkably transferred from one body to another.This form of energy has the capacity to flow in each and every direction.The process of convection transfers heat with the help of the migration of a fluid (liquid or gas) between areas of different temperatures. It is an approach that signifies the transfer of heat between two bodies by involving currents of moving gas or fluid.
Therefore, convection is the process that describes the warm ocean that transfers heat to the air above it. Thus, the correct option for this question is B.
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5.33 A constant force F= (4.70-379, 2.09) N. acts on an object of mass 180 kg, causing a displacement of that object by F= (4.25, 3.69-245) m What is the total work done by this force
Answers
The total work done by this force is 28.9-1457.86 N m.
What is total work?Total work is the sum of all the energy expended in completing a job or task. It is the amount of effort and energy expended to accomplish a goal or complete a task. Total work can be calculated by adding up all of the individual components of the job or task, such as time, effort, and materials.
The total work done by this force can be calculated using the formula W = F * Δx, where F is the force vector, and Δx is the displacement vector. In this case, the total work done is:
W = (4.70-379, 2.09) * (4.25, 3.69-245) = (19.9-944.81, 8.00-513.05) N m
Therefore, the total work done is 28.9-1457.86 N m.
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5.
Find the equation of the circle tangential to the line 3x-4y+1=0 and with
centre at (4,7).
20
Answers
Answer: (x - 4)² + (y - 7)² = 9
Explanation:
The equation of a circle is: (x - h)² + (y - k)² = r² where
(h, k) is the centerr is the radiusGiven: (h, k) = (4, 7)
Find the intersection of the given equation and the perpendicular passing through (4, 7).
3x - 4y = -1
-4y = -3x - 1
\(y=\dfrac{3}{4}x-1\)
\(m=\dfrac{3}{4}\) --> \(m_{\perp}=-\dfrac{4}{3}\)
\(y-y_1=m_{\perp}(x-x_1)\\\\y-7=-\dfrac{4}{3}(x-4)\\\\\\y=-\dfrac{4}{3}x+\dfrac{16}{3}+7\\\\\\y=-\dfrac{4}{3}x+\dfrac{37}{3}\)
Use substitution to find the point of intersection:
\(x=\dfrac{29}{5}=5.8,\qquad y=\dfrac{23}{5}=4.6\)
Use the distance formula to find the distance from (4, 7) to (5.8, 4.6) = radius
\(r=\sqrt{(5.8-4)^2+(4.6-7)^2}\\\\r=\sqrt{3.24+5.76}\\\\r=\sqrt9\\\\r=3\)
Input h = 4, k = 7, and r = 3 into the circle equation:
(x - 4)² + (y - 7)² = 3²
(x - 4)² + (y - 7)² = 9
How many phase conductors are installed between the switch and the light fixture shown in the figure? A. Four
B. Three
C. Two
D. Five
Answers
Answer:
TWO
Explanation:
HELP PLEASE I WILL MARK BRAINLIEST
Answers
Answer:
Acceleration.
Explanation:
Seems like u don't have time for a explanation. :
Answer:
A. Displacement
What does the speedometer in a moving car measure?
Answers
PLEASE ANSWER FASG I WILL MARK BRAINELIST PLEASEEEEE
The number of protons in the nucleus of an atom determines the species of the atom, i.e., the element to which the atom belongs. An atom has the same number of protons and neutrons. But the electron number cannot be used instead because (5 points)
a. electrons are not within the nucleus
b. electrons are negatively charged
c. electrons can be removed from or added to an atom
d. electrons are lighter than protons
Answers
The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)
Why the electron number cannot be used instead?The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.
This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.
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To make a shadow that appears as a clear Shadow and not a blurry shadow, the light source must be ________
Answers
To make a shadow that appears as a clear shadow and not a blurry shadow, the light source must be small and the object creating the shadow should be placed closer to the light source.
What is light source ?
A light source is any object or device that emits light.
When a light source is small and the object creating the shadow is close to the light source, the light rays that are blocked by the object are blocked more sharply, creating a clear and well-defined shadow.
In contrast, if the light source is large or the object creating the shadow is far from the light source, the light rays that are blocked by the object are blocked less sharply, creating a blurry and less-defined shadow.
This is because the edges of the object create a region of partial shadow where some light is partially blocked and some light is not blocked at all, resulting in a fuzzy and less-clear shadow.
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a body is under going non uniform circular motion work done by tangential force on body is
Answers
Answer:
The tangential force will act as a torque on the body, increasing its angular velocity and thus also increasing its kinetic energy. By the work-kinetic-energy theorem, work has been done on the body. Yes, in non-uniform circular motion the work done on the object is non-zero, for the reason you stated.
Explanation:
A clarinetist, setting out for a performance, grabs his 3.010 kg clarinet case (including the clarinet) from the top of the piano and carries it through the air with an upward force of 28.05 N. Find the case's vertical acceleration. Indicate an upward acceleration as positive and a downward one as negative. Answer needs to be in m/s2.
Answers
Answer:
-0.481 m/s^2
Explanation:
The force equation of this problem is given as:
F - W = ma
where F = upward force holding the clarinet bag
W = downward force (weight of the clarinet)
The mass of the clarinet bag is 3.010 kg, therefore, its weight is:
W = mg
W = 3.010 * 9.8 = 29.498
F = 28.05 N
Therefore:
28.05 - 29.498 = 3.010 * a
-1.448 = 3.010a
=> a = -1.448 / 3.010
a = -0.481 m/s^2
The acceleration of the bag is downward.
What is the term used when a ball is hit and the batter reaches the following bases safely (without being called out)?
please help me
a) first base
b)second base
c)third base
d) homerun
Answers
A 8.5 kg brick is dropped onto a 6.5 kg toy truck, which is moving across a level floor at 0.50 m/s. With what velocity do the truck and brick continue to move, after the brick has landed on the truck?
Answers
Answer:0.2167 m/s
Explanation:
Given
mass of brick M=8.5 kg
mass of toy truck m=6.5 kg
the velocity of truck u=0.5 m/s
Suppose v is the velocity after brick is landed on the truck
There is no external force acting so momentum is conserved
mu=(M+m)v
\(v=\dfrac{6.5}{15}\times 0.5\\v=0.2167\ m/s\)
what is the most effortless walking speed for a person with 90cm long legs if the length of each step is 90cm
Answers
Answer:
75 cm/second.
Explanation:
Formula:
Walking speed = stride length / time per step
Walking speed = 90cm/time per step
= 90cm/1.2 seconds (a common estimate time per step)
= 75cm/second.
1) Calculate the time required for a 6,000.-newton
net force to stop a 1,200.-kilogram
traveling at 10. meters per second. Show all
work, including the equation and substitution
with units.
PLEASE HELP!!
I need equation, substitution with units and final answer +explanation. TYSM
Answers
According to the given statement The time required is 2 seconds.
What is Force ?An unseen factor is an agent that has the power to alter the resting or moving condition of a body. It has a direction or a magnitude. The stress applied is the location at which force is applied, and the direction where the force applied is known also as direction of the force.
The vector composition of mass (m), acceleration, and the amount of force is used to express force (a). Mathematically, the equation or equation for force may be written as follows:
Force = mass x acceleration.
We know the force and the mass, so we can write:
6,000 N
= (1,200 kg) x (acceleration).
i.e. Acceleration = 6000N/1200kg = 5 m/s² .
That's the acceleration. The speed changes by 5 m/s each second
that the force acts on it. If the force pushes from behind, then it goes
5 m/s per second faster. It moves 5 m/s slower each second if the force is pushing from the front.
We wish to slow it down from its current speed of 10 m/s to 0 m/s. Therefore, the force must push from the front, and the task will be finished in (10/5) = 2 seconds.
So, time required is 2 seconds.
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A flute is 0.8m long. What is the first harmonic frequency for this flute?
214hz
183hz
265hz
308hz
Answers
Answer:
I believe it is 214hz
Explanation:
I apologize if I am wrong!
A car is travelling in a straight line and has its velocity uniformly reduced from 20 m * s ^ - 1 to 12m * s ^ - 1 in a distance of 80 m. The car the travels at the lower velocity for 1 minute, and then decelerates uniformly to rest in a further 12 sec. show the whole journey on a velocity-time graph and calculate
(i) the initial deceleration and the time taken to travel 80 m.
(ii) the final deceleration
(iii) the total displacement for the whole journey
Answers
i) The initial deceleration of the car is -1.6 m/s² and the time taken is 5 seconds
ii) The final deceleration is -1 m/s²
iii) The total dispalcement = 1016 m
What is the initial deceleration of the car?The initial deceleration of the car is given by the formula below:
v² = u² + 2as
where;
v is the initial velocityu is the final velocitya is acceleration/decelerations is the displacementSolving for a;
12² = 20² + 2 * a * 80
a = -1.6 m/s²
Time taken, t = v - u / a
t = 12 - 20 / (-1.6)
t = 5 seconds
Final deceleration:
a = v - u / t
a = 0 - 12 / 12
a = -1 m/s²
iii) Displacement at constant velocity = 12 * 1 * 60
Displacement at constant velocity = 720 m
Final displacement, s = ut + 0.5at²
s = 12 * 12 + 0.5 * 1 * 12²
s = 216 m
Total dispalcement = 80 + 720 + 216
Total dispalcement = 1016 m
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A student flexes her neck to 40 degrees from vertical while studying for her final exam. She pivots her head around the upper vertebra, approximated as point P (in the middle of the picture). Her head has a mass of 4.5 kg, and its center of mass is 11 cm away from point P. Her neck muscles are 1.5 cm from point P, measured perpendicular and pulling straight down. How much force do the neck muscles have to exert to keep the head still
Answers
Answer:
\(T=208N\)
Explanation:
From the question we are told that:
Neck flex angle \(\angle_n=40 \textdegree\)
Head mass \(M_h=4.5kg\)
Center of mass \(M_c= 11cm\)
Distance of neck from P \(d_p=1.5cm\)
Let
\(T_g=Gravitational\ force\ torque\\T_{nm}=Tension\ on\ neck\ muscle\ torque\)
Generally the net Torque T_n is mathematically given by
\(T_n=0\)
Therefore
\(T_g-T_{nm}=0\)
Generally the equation for Torque T is mathematically given by
\(T=\frac{M_h*g*l_g}{d_p}\)
where
\(l_g=M_c*sin\angle_n\)
\(l_g=11*10^{-2}*sin40\)
\(l_g=0.07m\)
Therefore
\(T=\frac{4.5*9.8*0.07}{1.5*10^{-2}}\)
\(T=208N\)
Part A
Compute the x and y components of vector A.
Express your answers in meters to three siginificant figures. Enter your answers separated by
A comma
Answers
The component of vector A in the x direction will be -11.01 meters. and in the y direction will be 9.18 meters.
What is meant by vectors?A quantity or phenomenon with independent qualities for both magnitude and direction is called a vector. The term can also refer to a quantity's mathematical or geometrical representation. Velocity, momentum, force, electromagnetic fields, and weight are examples of vectors in nature.
What are examples of vectors?Vector quantities can also include things like movement, acceleration, force, momentum, weight, the speed of light, a gravitational field, current, and more.
component of vector A in x direction = A cos theta
= 12 cos(53)
= -11.01 meters
component of vector A in y direction = A sin theta
= 12 sin (53)
= 9.18 meters
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A 6kg block of ice on a table is acted on by two forces F1 and F2 as shown in the diagram. If the magnitude of F1
- 13N and F2 = 111, find (A) Draw a FBD (B) the acceleration of the ice and (C) The normal force exerted on it by
the table.
Answers
Answer:15n and 16n
Explanation:
a 6kg block of ice on a table is acted by 2 forces
Hello!
If light on the wavelength spectrum has an energy of 1.8 eV and microwaves have an energy of 1.2 x 10^-4 , does that mean ligth is 15.000 more dangerous than the radiation of a microwave ?
Answers
It is true that the light is 15.000 more dangerous than the radiation of a microwave.
What is the wavelength?The wavelength shows the extent or how far the wave travels. Now we know that the energy of the wave can be use to find out how much dangerous the wave is.
Now;
1.6 * 10^-19 J = 1eV
x J = 1.8 eV
x = 1.8 eV * 1.6 * 10^-19 J /1eV
x = 2.88 * 10^-19 J
Now if the energy of the microwaves is 1.2 x 10^-4 J, then it follows that;
2.88 * 10^-19 J/ 1.2 x 10^-4 J,
= 2.4 * 10^15
Hence, it is true that the light is 15.000 more dangerous than the radiation of a microwave.
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A proton with an initial speed of 600,000 m/s is brought to rest by an electric field.1. What was the potential difference that stopped the proton?
2. What was the initial kinetic energy of the proton, in electron volts?
Answers
Answer:
(1) the potential difference that stopped the proton is 1878.75 V
(2) the initial kinetic energy of the proton is 1878.75 eV
Explanation:
Given;
initial speed of the proton, v = 600,000 m/s
mass of proton, m = 1.67 x 10⁻²⁷ kg
(1) The work done in bringing the proton to rest is given as;
\(W = eV\)
Apply work energy theorem;
\(K.E =W\\\\ \frac{1}{2} mv^2 = eV\\\\V = \frac{mv^2}{2e}\)
where;
V is the potential difference
\(V = \frac{1.67\times 10^{-27} \times\ 600,000^2}{2 \ \times \ 1.6 \times 10^{-19}} \\\\V = 1878.75 \ V\)
(2) the initial kinetic energy of the proton, in electron volts;
\(K.E = \frac{1}{2} mv^2\\\\K.E = \frac{1}{2} \times \ 1.67\times 10^{-27} \times 600,000^2 = 3.006 \times 10^{-16} \ J\\\\K.E = \frac{3.006 \times 10^{-16} \ J \ \ eV}{1.6 \times 10^{-19} \ J} = 1878.75 \ eV\)
Write a hypothesis about how the mass of the cylinder affects the temperature of the water. Use the "if . . . then . . . because . . .” format and be sure to answer the lesson question: "How is potential energy converted to thermal energy in a system?”
Answers
Hypothesis, If the mass of the cylinder increases, then the temperature of the water will also increase because an increase in mass leads to greater potential energy, which is converted to thermal energy in the system.
According to the principle of conservation of energy, energy cannot be created or destroyed but can be transformed from one form to another. In this case, potential energy from the mass of the cylinder can be converted into thermal energy in the system. When the cylinder is lifted and submerged in the water, it possesses gravitational potential energy due to its elevated position.
As the cylinder is released and descends into the water, this potential energy is converted into kinetic energy, causing the water molecules to move and collide with higher energy. These collisions generate heat and increase the overall temperature of the water. By increasing the mass of the cylinder, more potential energy is stored.
As a result, there is a greater amount of energy available to be converted into thermal energy when the cylinder is released into the water. Thus, the temperature of the water is expected to increase as the mass of the cylinder increases.
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Lewis is towing a 1140kg car. His truck pulls with a force of 2880 N, and increases the car's velocity from 0 to 6.4m/s. How long did Lewis apply the force for to achieve this change in velocity?
2.5s
16.2s
8.1 s
9.9 s
Answers
Answer:
2.5 s
Explanation:
F = ma
F = m(v - u/t)
2880 = 1140(6.4/t)
t = 7296/2880
t = 2.53
t ≅ 2.5 s