The force on the current-carrying loop is 0 N, and the torque experienced by the loop is 0.009 Nm.
To find the force and torque on the square-shaped 6A current-carrying loop, we first need to understand that the force on a current loop in a magnetic field is given by F = qvB, where q is the charge, v is the velocity, and B is the magnetic field strength. In this case, the force will be 0 N, because the magnetic field is parallel to the loop and the angle between them is 0°.
To calculate the torque τ, we use the formula τ = μBsinθ, where μ is the magnetic moment, B is the magnetic field strength, and θ is the angle between them. The magnetic moment μ is calculated as μ = IA, where I is the current and A is the area of the loop. Plugging in the values, we have μ = 6A × 0.0025m^2 = 0.015 Am^2. Since the magnetic field is tilted at 37°, we have θ = 37°.
Now, τ = (0.015 Am^2)(2 × 10^-2 T)sin(37°) ≈ 0.009 Nm. Thus, the torque experienced by the loop is 0.009 Nm.
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What phase of the moon would this be?
1st quarter, waxing half moon
3rd quarter, waning half moon
waxing gibbous
waning gibbous
Answer:
First Quarter
Explanation:
A copper sphere with density 8900 kg/m3, radius 5. 00 cm, and emissivity e = 1. 00 sits on an insulated stand. The initial temperature of the sphere is 300 K. The surroundings are very cold, so the rate of absorption of heat by the sphere can be neglected.
a. How long does it take the sphere to cool by 1. 00 K due to its radiation of heat energy? Neglect the change in heat current as the temperature decreases.
b. To assess the accuracy of the approximation used in part A, what is the fractional change in the heat current H when the temperature changes from 300 K to 299 K?
a.The time it will take the sphere to cool by 1. 00 K due to its radiation of heat energy is 3225s.
b. The fractional change in the heat current H when the temperature changes from 300 K to 299 K is 3.18 %.
(a) The rate of cooling of a copper sphere is given by Newton's law of cooling, i.e.,
H = kA(Ts - T0),
where k is the heat-transfer coefficient, A is the surface area of the sphere, Ts is the temperature of the surroundings, and T0 is the temperature of the sphere.
Since the surroundings are very cold, Ts can be taken to be zero.The heat transfer coefficient k depends on the emissivity e of the sphere and is given by:
k = σeA,
where σ is the Stefan-Boltzmann constant.
The surface area A of the sphere is:
A = 4πr²,
where r is the radius of the sphere.
The heat transfer coefficient k is therefore k = 4πr²σe.
Substituting the values of the parameters for the copper sphere in the above equations, we get
k = 4π(0.05 m)²(5.67 × 10^-8 W/m²K⁴)(1) = 0.0562 W/m²K⁴
H = kA(Ts - T0) = 0.0562(4π(0.05 m)²)(300 K - 0) = 1.41 W.
The rate of cooling of the sphere is therefore 1.41 W.
The heat capacity C of the sphere is given by
C = mCp,
where m is the mass of the sphere and Cp is the specific heat capacity of copper.
The mass of the sphere is m = (4/3)πr³ρ= (4/3)π(0.05 m)³(8900 kg/m³) = 0.0118 kg
The specific heat capacity of copper is Cp = 385 J/kgK.
The heat capacity of the sphere is therefore
C = 0.0118 kg × 385 J/kgK = 4.54 J/K.
The time Δt taken for the sphere to cool by ΔT = 1.00 K is given by
Δt = ΔQ/H = CΔT/H = (4.54 J/K)/(1.41 W) ≈ 3225s.
(b) The fractional change in the heat current H when the temperature changes from 300 K to 299 K is given by
ΔH/H = (dH/dT)ΔT/H,
where ΔT is the change in temperature and dH/dT is the rate of change of the heat current H with temperature.
To find dH/dT, we differentiate the equation
H = kA(Ts - T0) with respect to T and get dH/dT = -kA = -4πr²σe.
Substituting the values of the parameters for the copper sphere, we get
dH/dT = -4π(0.05 m)²(5.67 × 10^-8 W/m²K⁴)(1) = -0.0449 W/K/m².
The fractional change in the heat current is therefore:
ΔH/H = (dH/dT)ΔT/H = (-0.0449 W/K/m²)(-1 K)/(1.41 W) = 0.0318 or 3.18%.
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Electromagnetic waves differ from other types of waves because they are (2 points)
Group of answer choices
a. a continuous transfer of energy.
b. able to travel through a vacuum.
c. a visible form of energy.
d. able to move particles in a medium.
Answer:
b. able to travel through a vacuum.
Explanation:
The most distinguishing factor of an electromagnetic waves is that they are able to travel through a vacuum.
These waves do not require materials in a medium for propagation.
Electromagnetic waves are formed by the propagation of the electric and magnetic fields. They vibrate at an angle of 90° . They are unlike like mechanical waves that requires that requires materials in medium for their propagation.A satellite weighing 5,400 kg is launched into orbit 30,000 km above sea level. The mass of Earth is 6.0 × 1024 kg and its radius is 6,400 km. The gravitational constant is 6.673 × 10–11 N•m2/kg2. What is the gravitational force of Earth on the satellite in scientific notation with two decimals.
A satellite weighing 5,400 kg is launched into orbit 30,000 km above sea level. The mass of Earth is 6.0 × 1024 kg and its radius is 6,400 km. The gravitational constant is 6.673 × 10–11 N•m2/kg2 . What is the gravitational force of Earth on the satellite in scientific notation with two decimals.
–1.6 × 103 N
–1.63 × 103 N
–2.4 × 103 N
–5.27 × 104 N
The gravitational force of Earth on the satellite, given that the satellite is launched into orbit 30000 km above sea level is 1.63×10³ N
How do I determine the gravitational force?The gravitaional force between two objects can be obtained by using the following formula:
F = GM₁M₂ / r²
Where
F is the gravitaional force G is the gravitational constant M₁ and M₂ are the masses of the objects r is the distance apartThe following data were obtained from he question:
Mass of satellite (M₁) = 5400 = 5.4×10³ KgHeight (h) = 30000 km = 30000 × 1000 = 30000000 mMass of Earth (M₂) = 6.0×10²⁴ KgRadius of Earth (R) = 6400 km = 6400 × 1000 = 6400000 mDistance apart (r) = R + h = 6400000 + 30000000 = 36400000 mGravitational constant (G) = 6.673×10¯¹¹ Nm²/Kg²Gravitational force (F) =?The gravitaional force can be obtained as shown below:
F = GM₁M₂ / r²
F = (6.673×10¯¹¹ × 5.4×10³ × 6.0×10²⁴) / (36400000)²
F = 1.63×10³ N
Thus, the gravitational force is 1.63×10³ N
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A box is placed on a 30o frictionless incline. What is the acceleration of the box as it slides down the incline
Answer:
2.78m/s²
Explanation:
Complete question:
A box is placed on a 30° frictionless incline. What is the acceleration of the box as it slides down the incline when the co-efficient of friction is 0.25?
According to Newton's second law of motion:
\(\sum F_x = ma_x\\F_m - F_f = ma_x\\mgsin\theta - \mu mg cos\theta = ma_x\\gsin\theta - \mu g cos\theta = a_x\\\)
Where:
\(\mu\) is the coefficient of friction
g is the acceleration due to gravity
Fm is the moving force acting on the body
Ff is the frictional force
m is the mass of the box
a is the acceleration'
Given
\(\theta = 30^0\\\mu = 0.25\\g = 9.8m/s^2\)
Required
acceleration of the box
Substitute the given parameters into the resulting expression above:
Recall that:
\(gsin\theta - \mu g cos\theta = a_x\\\)
9.8sin30 - 0.25(9.8)cos30 = ax
9.8(0.5) - 0.25(9.8)(0.866) = ax
4.9 - 2.1217 = ax
ax = 2.78m/s²
Hence the acceleration of the box as it slides down the incline is 2.78m/s²
Which of these is a good way to begin your personal helath plan for physical fitness A. An assessment B. An action plan C. A plan for measuring progress toward your goal D. An ambitious goal.
Answer: A. An Assessment
I hope this helps, and Happy Holidays! :)
ANSWER
A. An assessment
Fill in the blanks. In the PET technique, detectors record the emission of _____ from active substrates to form a tomographic image of the cross-sectional distribution of tissue concentration.
A. Positrons
B. Alpha particles
C. Beta particles
D. Gamma rays
In the PET (Positron Emission Tomography) technique, detectors record the emission of Positrons from active substrates to form a tomographic image of the cross-sectional distribution of tissue concentration.
Detectors are employed in the PET (Positron Emission Tomography) method to capture the positron emission from active substrates. The subatomic particle known as a proton has the opposite charge to that of an electron but the same mass. They are released into the body by certain radioactive isotopes called positron-emitting radionuclides.
An immediate collision between an emitting positron and an electron is known as annihilation. The positron and electron collide during annihilation, which causes the conversion of their masses into gamma-ray energy. High-energy photons make up these gamma rays. The gamma rays released during annihilation events are intended to be detected and measured by the detectors in a PET scanner.
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You are running late to school and need to go 1,500 m in 10 minutes. What speed will you travel?.
The required average speed to reach the school will be 2.5 meters per second.
According to the question,
School is still 1500m away and it starts in 10 minutes. We need to determine at what average speed you need to travel to reach the school on time.
What is speed?
Speed is defined as when an object is subjected to move, the distance covered by the object in a certain time interval is the speed of that particular object.
Here it is given,
Distance = 1500m
Time = 10 minutes or 10×60(seconds) = 600 seconds
Speed = distance/time
Speed = 1500/600
Speed = 2.5 meters per second
Thus, the average speed needed to reach the school at a distance of 1500m in 10 minutes will be 2.5 meters per second.
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Claire lost weight thanks to the support and encouragement of her friends. They helped her stick to a healthy diet and pushed her to engage in physical exercise every day. Identify the FaceTime that helped her lose weight
Answer:
hello the options to your question is missing below are the options
culture
heredity
physical environment
social environment
answer : social environment
Explanation:
Claire ability to lose weight due to the encouragement and support of her friends shows that she was ability to achieve her goal due to her social circle ( friends ). therefore the face time that helped her lose weight is her social environment and not culture nor any other option as mentioned above.
social environments help/play a vital role in individual's life a lot as long as every human being is a social being
As a source of sound moves away from a person what increases? What decreases? And what stays the same
Moving away from the source causes the observer to measure a lower frequency and higher wavelength.
The frequency of the detected sound from a stationary source will change as a result of the observer's movement. Moving away from the source causes the observer to measure a lower frequency and higher wavelength.
The Doppler effect is a shift in sound wave frequency that happens when the source of the sound waves is moving in relation to a listener who is stationary.
The wave propagates the sound energy throughout the medium, typically in all directions and with decreasing intensity as it gets further away from the source.
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The two properties that are
parts of refraction are ...
Answer:
-Relative refractive index– It is the ratio of speed of light in one medium to the speed of light in another medium
-Absolute refractive index– It is the ratio of light in vacuum to the speed of light in another medium.
Explanation:
hii please help i’ll give brainliest if you give a correct answer please please hurry it’s timed
Answer:
A
Explanation:
You can rule out c and d since they make no sense but i would say a makes more since than b since your sitting on the chair your putting force on it
please help with how to set up
the questions thanks!
9. A race car is awaiting the start of a race. Once the light turns green, the car accelerates at a to the top speed v in time t. (a) What force is supplied by the engine? (b) How far does the car tra
(a)The mass of the race car is ma.(b) The initial velocity (v₀) is assumed to be zero since the car is at rest before accelerating.
(a) To calculate the force supplied by the engine, we can use Newton's second law of motion, which states that the force (F) acting on an object is equal to its mass (m) multiplied by its acceleration (a):
F = m × a
The mass of the race car is ma.
(b) To determine how far the car travels, we can use the equation of motion that relates displacement (d), initial velocity (v₀), acceleration (a), and time (t):
d = v₀ × t + (1÷2) × a× t²
The initial velocity (v₀) is assumed to be zero since the car is at rest before accelerating.
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--The question is incomplete, the complete question is given:
" A race car is awaiting the start of a race. Once the light turns green, the car accelerates at a to the top speed v in time t. (a) What force is supplied by the engine? (b) How far does the car travel before it reaches top speed?"--
A point load of 1.29 nC is fixed in glycerin (Er=43). The intensities of its electrostatic field at two points are equal to 168.75 N / C and 300 N / C, respectively. determine the Mechanical Work performed by the field forces when moving the load of 2 microcolomb from the first point to the second.
Answer= -4.5 microJ
I need solving
Answer:
1 4.5 divede by 1.29 I think that is the literal answer
A student is standing 8 m from a roaring truck engine that is measured at 20 dB. The student moves 4 m closer to the engine. What is the measured sound intensity at the new distance? (dB)
Can you also explain why? I need to know how to do it and I don't know how to
Sound intensity is inversely proportional to the square of the distance traveled by the sound.
Sound, a mechanical disturbance from a state of equilibrium that propagates through an elastic material medium. The sound travels in all the mediums i.e. solid, liquid, and gas.
According to the question, the sound frequency which he is hearing is 20dB when he is standing 8m away from the engine.
Sound intensity is inversely proportional to the square of the distance traveled by the sound. Thus;
r1^2 divide by r2^2 = L2divideL1
where r= distance (m)
L= sound intensity (decibel dB)
8squared divide by 4 squared = L2 divide 20 dB
L2 = 4 × 20
L2= 80 dB
This means that the sound is increased from 20 dB to 80 db.
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Why is there an attraction between the two ions in this chemical bond?
Answer:
One atom will give electrons to another atom to fill its shell, this is an ionic bond. The atom giving away electrons becomes positive and the one recieving electrons becomes negative.
Explanation:
Answer: One atom will give electrons to another atom to fill its shell, this is an ionic bond. The atom giving away electrons becomes positive, and the one receiving electron becomes negative.
Explanation:
I did the Gizmo.
A boy scout troop hikes 10.0 km East and then hikes an
additional 7km North. What the total displacement of
the boy scout troop?
Answer:
wouldn't it be 17km?
Explanation:
Since its 10km and 7km it would make 17km in total. sorry if this didnt help i suck at this stuff :/
Newton's heating-cooling law states that the rate of change in the temperature, H, is proportional to the difference between the object and the surrounding temperature. Let H(t) be the temperature of the object being cooled and S be the surrounding temperature. A warm object at 100 degrees is placed in a refrigerator at 35 degrees Fahrenheit and after 30 minutes the object is 75 degrees. Write and solve the differential equation which describes the temperature of the object over time, where time is measured in hours. OH(t)=35-65e-0.97t OH(t)=35+65e-t(0.97) OH(t)=75-35e-0.97t OH(t)=35+75e0.971
The differential equation which describes the temperature of the object over time is;
dH/dt = -k (H-S), where k = 0.97. The solution to this differential equation is given by H(t) = S + 65e^(-0.97t).
Newton’s law of heating and cooling is an application of the first law of thermodynamics. The law suggests that the rate of change of temperature of an object is proportional to the difference between its temperature and the temperature of the surroundings.
A warm object is placed in a refrigerator where the surrounding temperature is cooler, and the temperature of the object decreases. This phenomenon can be explained using differential equations. Given that H(t) is the temperature of the object being cooled and S is the surrounding temperature, the differential equation which describes the temperature of the object over time is given by;dH/dt = -k (H-S)
where k is the constant of proportionality.To solve this differential equation, we can use separation of variables, such that;
dH/dt = -k (H-S)dH/(H-S) = -k dt
Integrating both sides, we get;ln|H-S| = -kt + Cwhere C is the constant of integration.Rearranging, we have;
|H-S| = e^(-kt+C)
At time, t = 0, H = 100 and after 30 minutes the object is 75 degrees; t = 0.5 hours, H = 75. We can use these values to solve for C and k as follows;
|100-35| = e^(C) => 65 = e^(C) …(1)
and|75-35| = e^(-0.5k+C) => 40 = e^(C) e^(-0.5k) => e^(-0.5k) = 40/65 => e^(-0.5k) = 8/13 => -0.5k = ln(8/13) => k = -2ln(8/13) => k = 0.97 …(2)
Substituting equation (1) into (2), we get;H-S = 65e^(-0.97t) => H(t) = S + 65e^(-0.97t)
Therefore, the differential equation which describes the temperature of the object over time is;dH/dt = -k (H-S), where k = 0.97.
The solution to this differential equation is given by H(t) = S + 65e^(-0.97t).
The differential equation which describes the temperature of the object over time is;
dH/dt = -k (H-S), where k = 0.97. The solution to this differential equation is given by H(t) = S + 65e^(-0.97t).
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code talker: the first and only memoir by one of the original navajo code talkers of wwii
"Code Talker: The First and Only Memoir by One of the Original Navajo Code Talkers of WWII" is a book written by Chester Nez in collaboration with Judith Schiess Avila. It is an autobiography of the author and his experiences in World War II as a Navajo code talker.
The Navajo Code Talkers were an elite group of Navajo Marines who used their language to develop a code that could not be deciphered by the enemy. The Japanese had broken all American codes, so the Marines wanted to create an unbreakable code. The Navajo language, which had no written form, was the perfect solution. Navajo Code Talkers developed an intricate code that used their language's complex syntax, tonal qualities, and dialects. It proved to be the only code that the Japanese couldn't break.
The Navajo Code Talkers took part in every major Marine operation in the Pacific, from Guadalcanal to Okinawa. Chester Nez, the book's author, was one of the original Navajo Code Talkers. He was born in New Mexico in 1921 and was educated in a boarding school where he was forbidden from speaking his native Navajo language. Chester Nez was a U.S. Marine who was recruited in 1942 and became a part of the Navajo Code Talkers program. He was a member of the 382nd Platoon and served in the Pacific, where he worked as a radio operator.
Code Talker is about the Navajo Code Talkers, the Marine unit that used the Navajo language to develop an unbreakable code that played a crucial role in the U.S. victory over Japan in World War II. The book offers a first-hand account of what it was like to be a Navajo Code Talker during the war, as well as the impact that the code talkers had on the outcome of the war. Chester Nez provides an in-depth look at Navajo culture and history while telling his own personal story of growing up on the Navajo reservation and joining the Marine Corps.
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icy comets that were originally orbiting in the inner part of the solar system could have met which of several fates?
The correct option is D. Icy comets that were originally orbiting in the inner part of the solar system could have met All of the above of several fates.
The solar system is a collection of celestial bodies that orbit around a central star, the Sun. It includes the Sun, eight planets, dwarf planets, moons, asteroids, comets, and various other small objects.
The eight planets in our solar system, in order from the sun, are Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune. Each planet has unique characteristics, such as size, atmosphere, and number of moons. The dwarf planets in our solar system include Ceres, Pluto, Haumea, and Makemake.
The solar system is thought to have formed about 4.6 billion years ago from a cloud of gas and dust that collapsed under its own gravity. Over time, the particles in this cloud began to stick together and form into larger objects, eventually forming the celestial bodies that make up the solar system today.
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Complete Question: -
Icy comets that were originally orbiting in the inner part of the solar system could have met which of several fates?
A. Collision with a planet or a plantesimal
B. The loss of their icy constituents due to volatilization
C. Being swept to the outer part of the solar system by a strong solar wind.
D. All of the above
balance of chemical equations
Answer:
an equation is balanced when the same number of each element is represented on the reactant and product sides. equations must be balanced to accurately reflect the law of conservation of matter.
coherent light with single wavelength falls on two slits separated by 0.710 mm. in the resulting interference pattern on the screen 2.00 m away, adjacent bright fringes are separated by 1.80 mm. what is the wavelength (in nanometers) of the light that falls on the slits? use formula for the small angles of diffraction
The coherence qualities of various light sources are explored, as well as how they affect the image quality of a holographic display.
Temporal coherence is connected to the intrinsic spectrum bandwidth of the light source, but spatial coherence is determined by light source size and propagation distance. These two coherence properties, as well as the quality of the holographic reconstructed images, are measured for various light sources of diode-pumped solid-state (DPSS) laser, laser diode (LD), light emitting diode (LED), super luminescent light emitting diode (sLED), and micro light emitting diode (mLED) in various settings. Although image sharpness and speckle are both related to coherence parameters, our findings and subsequent research reveal that spatial coherence is directly connected to image sharpness.
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A car is traveling with a constant speed of 30. 0 m/s when the driver suddenly applies the brakes, causing the car to slow down with a constant acceleration. The car comes to a stop after 8 seconds. What was the acceleration of the car as it slowed down?.
The acceleration of the car as it slowed down is -3.75 m/s². We can use the following formula to find the acceleration of the car: final velocity (v) = 0 m/s
initial velocity (u) = 30 m/s
time (t) = 8s
acceleration (a) = ?
We can use the formula: v = u + at
Rearranging the formula: a = (v - u) / t
Substituting the values of v, u, and t into the formula: a = (0 m/s - 30 m/s) / 8 s
a = -3.75 m/s²
The negative sign indicates that the car was decelerating or slowing down.
Therefore, the acceleration of the car as it slowed down was -3.75 m/s².
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a cylinder has volume 50 cm and radius 4 cm find its volume. pls do it with the full process
Explanation:
Please, check the question properly
Table C: Average Speeds for Lower Racetrack
Answer:
Centripetal Acceleration = v^2/r
= (circumference/time)^2/r
= (2*pi*r/t)²)/r
= ((2³.14*50/14.3)²)/50
= 9.64 m/s²
brainlist?
Explanation:
b) A stone is projected horizontally with velocity 10 m/s from height 100 m in a vacuum and moves along a path as shown. X is the point on this path after 2 seconds. Calculate the magnitude and direction of velocity at this point.
At the point X after 2 seconds, the stone has a magnitude of velocity equal to 10 m/s, and its direction is purely horizontal.
When a stone is projected horizontally in a vacuum, it only experiences horizontal motion due to the absence of air resistance. The vertical motion is governed by the force of gravity alone. In this scenario, the stone will undergo uniform horizontal motion with a constant horizontal velocity.
Given that the stone is projected horizontally with a velocity of 10 m/s, its horizontal velocity remains constant throughout the motion. After 2 seconds, the stone will have traveled a horizontal distance equal to the product of its horizontal velocity and the time, which is 10 m/s * 2 s = 20 m. Therefore, the stone will be located 20 meters horizontally from the point of projection. Since the stone is moving horizontally, its vertical velocity remains zero throughout the motion. The magnitude of the velocity at this point is equal to the horizontal velocity, which is 10 m/s. However, since the stone is moving horizontally, there is no vertical component of velocity.
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the talk test can be used to assess which of the following? select one: a. immediate energy system b. lactate threshold c. aerobic power
The talk test can be used to assess : b. lactate threshold. Talk test is an easy way to measure the relative intensity.
What is talk test?The talk test is one way to measure the relative intensity. If you're doing moderate-intensity activity, then you can talk but not sing during the activity. And if you're doing vigorous-intensity activity, then you will not be able to say more than a few words without pausing for a breath.
Researchers at the University of New Hampshire discovered that the results of the talk test in student volunteers were more closely associated with lactate threshold than with ventilatory threshold.
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State four (4) Forms (abstracts) that the liberated prisoner confronts and the copy of each of those Forms (tangible, finite, concrete, identifiable by sensory perception).
The four abstract forms and their tangible copies that apply to the liberated prisoner in the myth of Plato's cave are:
1. Astonishment.
Copy: Elevation of the eyebrows and opening of the mouth.2. Anger.
Copy: Screaming.3. Happiness.
Copy: Laugh.4. Alienation:
Copy: Crying.The feelings of the liberated prisoner in the myth of Plato's cave.
Once the prisoner is released by figures that do not correspond to shadows but to tangible beings that can lift him or even pull or drag him, the first form he must experience is astonishment, identifiable by his copy, which would be the raising of the eyebrows and / or or the opening of its mouth reflecting that shape.
Next, the myth of the cave tells us that the man was forced to leave the cave, for which the experienced form must have been anger, reflected in his copy that would be possible shouts towards the people who take him out of the cave and they make you walk on rough terrain.
Later, once the liberated man accustoms his eyes and can see more defined forms such as trees, people or even the sun, his form is joy, whose copy is laughter, out of laughter if that is the case, being now aware of a whole new that I did not know.
Once the freed prisoner returns to the cave, having a different concept about the reflected shadows to which his companions are accustomed, the abstract form is alienation, followed by his copy that is crying, since he will surely be excluded by his acquaintances. , which I would be trying to help.
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Using your own words, define what is a Tensile Stress and give an example. [10 pts]
Tensile stress refers to the force per unit area experienced by a material when it is stretched or pulled apart. It is a measure of the internal resistance of a material to external forces that attempt to elongate or deform it.
Tensile stress is a mechanical phenomenon that occurs when a force is applied to a material in such a way that it stretches or pulls the material apart. It is defined as the force per unit area acting on a cross-sectional area of the material. Tensile stress is denoted by the symbol σ (sigma) and is measured in units of pressure, such as pascals (Pa) or newtons per square meter (N/m²).
To understand tensile stress, consider the example of a metal wire being pulled apart. As an external force is applied to the wire, it experiences tension, causing the atoms within the wire to move away from each other. This leads to an increase in the length of the wire and the development of tensile stress along its cross-section.
The magnitude of the tensile stress depends on the applied force and the original cross-sectional area of the wire. If the applied force exceeds the material's strength, the wire may ultimately break or fracture.
Tensile stress plays a crucial role in engineering and materials science, as it helps determine the structural integrity and load-bearing capacity of various components. Understanding the behavior of materials under tensile stress is essential for designing structures, such as bridges, buildings, and aircraft, to ensure they can withstand external forces without failure.
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How much longer will a 300 m steel bridge be on a 30C day than a –10C night?
Answer:
Explanation: A bar of an unknown metal has a length of 0.975 m at 45°C and a length of 0.972 m at. 23°C.