what is the flight attitude one system which transmits information to the instruments has malfunctioned

According to the question, 50 kN reactions at the supports A and B for equilibrium of the beama.

When we move a body a tiny distance, the state creates forces that usually oppose the movement and bring the body back to its equilibrium, we say that the body is in stable equilibrium. Think of a stone at the base of a bowl as an illustration.

Since the laden beam is stationary, we should equalize each other out by moving upward and downward.

Thus,

= R+R

=40+60=100 kN - (1)

Now that the beam's force has been evenly distributed across the two supports, the reaction force exerted by the two supports will also be equally, or R=R.

2R=100 kN

R=50 kN

As a result, the reaction at supports A and B will each be 50 kN.

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The resulting acceleration of the box of oranges would be upward, with the same magnitude as before. The change in direction of the pulling force would only affect the direction of the acceleration.

When the worker pushes the box of oranges, the downward force of gravity and the normal force cancel each other out, resulting in zero net vertical force. The horizontal force of the worker's push causes the box to accelerate horizontally.

When the worker pulls the box from the other side, the vertical component of the pulling force opposes the force of gravity. As a result, the net vertical force becomes the difference between the upward vertical component of the pulling force and the downward force of gravity. However, the magnitude of the vertical component of the pulling force remains the same as the magnitude of the pushing force. Therefore, the resulting upward acceleration of the box of oranges will have the same magnitude as before.

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The magnitude of the net force on the truck is 2070.5 N.

Frictional force is the force that opposes motion or attempted motion between two surfaces in contact. It arises as a result of the interlocking of irregularities on the surfaces in contact, and it acts in the direction opposite to the direction of motion or attempted motion.

Frictional force can be classified into two types: static friction and kinetic friction. Static friction is the force that prevents an object from moving when a force is applied to it, while kinetic friction is the force that opposes the motion of an object that is already in motion.

The normal force is equal to the weight of the truck, which can be calculated as:

weight = mass x gravity

where gravity is approximately 9.81 m/s^2.

So the weight of the truck is:

weight = 900 kg x 9.81 m/s^2 = 8829 N

Therefore, the normal force is:

normal force = weight = 8829 N

And the frictional force is:

frictional force = 0.5 x 8829 N = 4414.5 N

Next, we can find the net force on the truck by subtracting the force of friction from the force exerted by the car:

net force = 2345 N - 4414.5 N = -2070.5 N

Note that the negative sign indicates that the net force is in the opposite direction to the force exerted by the car, which makes sense since the truck is slowing down.

Finally, we can use Newton's second law to find the acceleration of the truck:

net force = mass x acceleration

-2070.5 N = 900 kg x acceleration

acceleration = -2.3 m/s^2

Again, the negative sign indicates that the truck is slowing down.

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Answer:

63.0 x (6.02 x 10^23) = 3.79 x 10^25 atoms of gold

Explanation:

There are 6.02 x 10^23 representative particles in a mole of any substance. Multiply it by the number of moles, and you will get the number of representative particles (atoms, molecules, formula units)

Answer:

1) The specific heat is the heat required to be added to a unit mass of the substance to cause a unit rise in its temperature

2) The temperature change is 20.92°C

Explanation:

The given parameters are;

The mass of the substance, m = 2.50 g

The heat released by the sample, ΔQ = 12 calories = 50.208 J

The specific heat capacity of the substance, c = 0.96 J/(g·°C)

Therefore, we have;

Heat released, ΔQ = Mass, m × Specific heat capacity, c × Temperature change, ΔT

Substituting in the known values gives

50.208 J = 2.50 g × 0.96 J/(g·°C) × ΔT

ΔT = 50.208 J/(2.5 g× 0.96 J/(g·°C)) = 20.92°C

The temperature change = 20.92°C

Answer:

A

Explanation:

The electrostatic force and strong nuclear force are opposite forces. The electrostatic force causes the repulsion beteween the positively charged protons in the nucleus but the strong force keeps the nucleus glued together but overcoming the electrostatic force. They would both increase upon the addition of a proton or radioactivity will result.

The electric field will never equal zero between two oppositely charged particles because the electric field from each charge points is in opposite direction in between the charges.

An electric field in physics is a region of space around a charged particle, or between two voltages, which exerts a force on charged objects in its vicinity.

For opposite charges, the point of zero electric fields will lie outside the system along the line joining the two charges.

Therefore, the electric field will never equal zero between two oppositely charged particles because the electric field from each charge points is in opposite direction in between the charges.

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Standing waves are equal-amplitude, equal-frequency waves that are moving in the opposite direction.

In the case of longitudinal waves, standing waves are feasible; an example of this is sound waves. Standing waves form nodes and antinodes along with longitudinal waves in air columns. In a tube that is open on both ends, a second harmonic longitudinal standing wave forms.

The two types of stationary waves (1) transverse waves, which are created by superimposing two identical transverse waves moving in the opposing direction. (2) Longitudinal waves produced by the superposition of two longitudinal waves that are identical but are moving in the opposite direction. The terms sound wave, seismic P-wave, and ultrasonic wave all refer to longitudinal waves. Electromagnetic waves and ocean waves are two examples of transverse waves.

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The radius of curvature of the mirror is 40 cm.

In this case, the mirror produces an inverted image, which means it is a concave mirror. We are given the object distance (u), image distance (v), and magnification (M). The magnification is -2, as the image is twice as tall and inverted. The mirror formula for concave mirrors is:
1/f = 1/u + 1/v
We can find the focal length (f) using the magnification formula:
M = -v/u
By solving for v, we get:
v = -2u
Now, we can substitute this value back into the mirror formula:
1/f = 1/u - 1/(2u)
Since the image is 60 cm from the mirror:
1/f = 1/60 - 1/(2 * 60)
1/f = 1/60 - 1/120
1/f = 2/120 - 1/120
1/f = 1/120
Thus, the focal length (f) is 60 cm / 2 = 30 cm
The radius of curvature (R) is twice the focal length:
R = 2 * f = 2 * 30 = 40 cm

Summary: The radius of curvature of the mirror is 40 cm.

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Answer:

1 Watt

Explanation:

P=W/t

P=10/10

P=1 Watt

Kieran had a greater average speed than Jevon. Let us go into more detail in the explanation below. To compare the average speeds of Kieran and Jevon, we need to find out the speed of each person.

We can use the formula speed = distance/time. Kieran ran 8 laps in 18 minutes, which means he ran 8/18 = 0.44 laps per minute. To find out Kieran's speed, we need to multiply this by the length of one lap. If we assume that the length of one lap is 400 meters, then Kieran's speed is:0.44 laps per minute × 400 meters per lap = 176 meters per minute Jevon ran 6 laps of the track, but we don't know how long it took him.

Therefore, we can't calculate his speed directly. However, we can still compare his speed to Kieran's by using ratios. If we assume that Jevon ran the same length of track as Kieran, then we can write the following equation: Kieran's speed/Jevon's speed = Jevon's time/Kieran's time.

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The given paraboloid coordinate system (u, v, ϕ) with x = u.v cosϕ,

y = u.v sinϕ , z = 1/2 (u2 - v2) is orthogonal. The gradient is ∇f = (∂f/∂u) e_u + (∂f/∂v) e_v + (∂f/∂ϕ) e_ϕ ; divergent is ∇²f = ∇ · (∇f) ; curl is (∇ x) and laplacian is  (∇²).

We can prove that the paraboloid coordinate system (u, v, ϕ) is orthogonal, by computing the dot products of the basis vectors. The basis vectors in this coordinate system are given by:

e_u = (∂x/∂u, ∂y/∂u, ∂z/∂u) = (v cosϕ, v sinϕ, u)

e_v = (∂x/∂v, ∂y/∂v, ∂z/∂v) = (u cosϕ, u sinϕ, -v)

e_ϕ = (∂x/∂ϕ, ∂y/∂ϕ, ∂z/∂ϕ) = (-u.v sinϕ, u.v cosϕ, 0)

By Taking the dot products, we find that e_u · e_v = 0, e_v · e_ϕ = 0, and e_ϕ · e_u = 0. This proves that the basis vectors are mutually perpendicular, and therefore, the coordinate system is orthogonal.

Next, we can calculate the gradient (∇) in this coordinate system. The gradient of a scalar function f(u, v, ϕ) is given by:

∇f = (∂f/∂u) e_u + (∂f/∂v) e_v + (∂f/∂ϕ) e_ϕ

The divergence (∇ ·) and curl (∇ x) can be computed using the standard formulas in terms of the basis vectors. Finally, the Laplacian (∇²) can be obtained by taking the divergence of the gradient:

∇²f = ∇ · (∇f)

Thus, By evaluating these operations in the given coordinate system using the appropriate partial derivatives, we can determine the gradient, divergent, curl, and Laplacian for any scalar function in the (u, v, ϕ) coordinates.

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Yes, work is performed as we apply more twist (torque) to change the radius of rotation of the bob. The net acceleration is still directed towards the axis of rotation.

The torque that we add to the system is always perpendicular to the radius of rotation. The torque vector is always tangent to this radius vector, so when we increase the amount of torque applied by twisting harder, we cause a larger angle between torque and radius vectors. This means that there is more work done on the system (since more force was applied), and thus net acceleration towards the axis of rotation must increase.

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Maglev trains utilize the principles of magnetism by having the north pole of the train's magnets face the corresponding poles on the guideway.

Maglev trains, short for magnetic levitation trains, use magnets on the train and guideway to levitate the train off the track, providing a frictionless and efficient transportation method. The alignment of the magnets is crucial for this system to work properly. The north pole of the magnets on the train must face the corresponding poles on the guideway.

This setup employs two main types of magnets: electromagnets and permanent magnets. Electromagnets are used to provide the levitation effect, while permanent magnets are used for stabilization and guidance. By arranging the magnets on the train and guideway in a specific way, they create a magnetic field that causes the train to lift and hover above the track.

When the north pole of the magnets on the train faces the same pole on the guideway, it creates a repulsive force between the magnets. This repulsion lifts the train off the track, reducing friction and allowing it to move more smoothly and at higher speeds than conventional trains. Additionally, the arrangement of the magnets on the sides of the train and guideway provides lateral stability and guidance, ensuring the train remains on its intended path.

In summary, maglev trains utilize the principles of magnetism by having the north pole of the train's magnets face the corresponding poles on the guideway. This arrangement creates a repulsive force that levitates the train, reducing friction and enabling faster, more efficient transportation.

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Answer:

Explanation:

First, he can add the rock salt to the water and mix it well. Then he can remove the sand by decantation, after the sand has sedimented. He can seperate the water from the salt by evaporation. He should evaporate the water completely and capture the steam. the steam will cool into water. After evaporating completely, the salt will remain in the container

Answer:

Is the force on the  object  a push or pull force?

leaning against a wall    

push

kicking a football

push

carrying a suitcase

pull

pressing the button for an elevator  

push

opening a sliding door    

pull

Explanation:

Answer:

push

push

pull

push

pull

Explanation:

The correct answer is at the same temperature

An object with a temperature of 273.2 K is equivalent to 0°C. This is because 0°C is the same as the freezing point of water, and at this temperature, water freezes and becomes a solid.

On the other hand, 273.2 K is the same as the melting point of water, where water changes from a solid to a liquid.

Therefore, an object with a temperature of 273.2 K is at the same temperature as an object with a temperature of 0°C.

This is an example of the Celsius and Kelvin temperature scales being directly related and can be converted from one to the other using the formula: K = °C + 273.15.

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From the calculation, the acceleration of the body is 26m/s^2.

When an object is thrown up or down, the motion of the body is influenced by the gravitational pull on the body.

Now;

Given that;

v = 39 m/s

t = 1.5 s

u = 0 m/s

a = ?

v = u + at

v = at

a = v/t

a = 39 m/s/1.5 s

a = 26m/s^2

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Answer:

Approximately \(2.69\; {\rm A}\).

Explanation:

Ensure that all values are measured in standard units. Charge should be measured in coulombs, while time should be measured in seconds:

\(\begin{aligned}t &= 3.0\; {\rm hr} \times \frac{3600\; {\rm s}}{1\; {\rm hr}} = 10800\; {\rm s}\end{aligned}\).

Electric current \(I\) is the rate of flow of electric charge.

In order to find the electric current, divide electric charge \(q\) by the time \(t\) required to transfer these charge. If charge \(q\!\) is measured in coulombs and time \(t\!\) is measured in seconds, the unit of current \(I\)would be amperes:

\(\begin{aligned}I & = \frac{q}{t} \\ &= \frac{29000\; {\rm C}}{10800\; {\rm s}} \approx 2.69\; {\rm A}\end{aligned}\).

The estimated time en route from Addison to Dallas Executive would be approximately 20.1 minutes.

To estimate the time en route from Addison (area 2) to Dallas Executive (area 3), we need to calculate the groundspeed first. The groundspeed is the true airspeed corrected for wind effect.

- Wind direction: 300° (from the northwest)

- Wind speed: 15 knots

- True airspeed: 120 knots

- Magnetic variation: 7° east

To calculate the groundspeed, we need to find the headwind (wind component opposing the aircraft's direction) and crosswind (wind component perpendicular to the aircraft's direction).

Using trigonometry, we can determine the headwind and crosswind components:

Headwind component = Wind speed × cos(wind angle - runway heading)

Crosswind component = Wind speed × sin(wind angle - runway heading)

Assuming the aircraft is flying a direct course from Addison to Dallas Executive, we'll use the magnetic variation to convert the true course to the magnetic course.

Magnetic course = True course + magnetic variation

Let's calculate the headwind and crosswind components:

Headwind component = 15 × cos(300° - magnetic course)

Crosswind component = 15 × sin(300° - magnetic course)

To calculate the groundspeed, we'll use the Pythagorean theorem:

Groundspeed = √(True airspeed² - Headwind component²)

Finally, we can estimate the time en route by dividing the distance between Addison and Dallas Executive by the groundspeed:

Time en route = Distance / Groundspeed

Assuming the runway heading from Addison to Dallas Executive is 100° and the distance between the two locations is 40 nautical miles, we can estimate the time en route.

First, let's calculate the magnetic course:

Magnetic course = True course + magnetic variation

Magnetic course = 100° + 7° = 107°

Next, we can calculate the headwind and crosswind components:

Headwind component = 15 × cos(300° - 107°) ≈ 5.91 knots

Crosswind component = 15 × sin(300° - 107°) ≈ -13.92 knots

Since the crosswind component is perpendicular to the aircraft's direction, it won't affect the groundspeed significantly. We'll focus on the headwind component.

Now, let's calculate the groundspeed:

Groundspeed = √(True airspeed² - Headwind component²)

Groundspeed = √(120² - 5.91²) ≈ 119.36 knots

Finally, we can estimate the time en route:

Time en route = Distance / Groundspeed

Time en route = 40 / 119.36 ≈ 0.335 hours

Converting the time to minutes:

Time en route ≈ 0.335 hours × 60 minutes/hour ≈ 20.1 minutes

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Answer:

thanks me later

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Option C is an example of energy conservation. Recycling aluminum soda cans is an example of energy conservation because it is a way of reusing a product that has already been produced rather than creating a new one.

Energy conservation means saving energy and using it wisely so that it can be used again and again. By using less energy, we can reduce the amount of pollution we create, save money, and extend the life of our natural resources. Recycling and conservation are the best ways to do this. Energy conservation involves making changes in your daily routine, using appliances that are energy-efficient, and being mindful of the amount of energy you use.Therefore, the answer to the question is option C. Recycling aluminium soda cans is an example of energy conservation because it is a way of reusing a product that has already been produced rather than creating a new one. This results in a reduction of the amount of energy needed to produce new cans.The production of new cans involves the extraction and processing of raw materials such as bauxite, which requires a lot of energy. By recycling aluminum cans, the energy that would have been used to extract and process the raw materials can be saved. This, in turn, leads to a reduction in greenhouse gas emissions, which are a major contributor to climate change.

Option C is an example of energy conservation. Recycling aluminum soda cans is an example of energy conservation because it is a way of reusing a product that has already been produced rather than creating a new one. This results in a reduction of the amount of energy needed to produce new cans. By recycling aluminum cans, the energy that would have been used to extract and process the raw materials can be saved. This, in turn, leads to a reduction in greenhouse gas emissions, which are a major contributor to climate change.

In conclusion, we can say that energy conservation is important for the sustainability of our planet. It is important to be mindful of the amount of energy we use and to make changes in our daily routine to reduce our energy consumption. Recycling is an example of energy conservation, which can help to reduce the amount of energy needed to produce new products.

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Distance can be defined as the amount of ground covered (traveled) by a physical object over a specific period of time and speed, regardless of its direction, starting point or ending point.

Mathematically, the distance traveled by a physical object can be calculated by using this formula:

Distance = speed × time

Dimitri's total distance is the sum of the distance he covered by moving from point A to B and then from B to C. Thus, his total distance is given by:

Total distance = AB + BC

Total distance = 18.1 + 13.3

Total distance = 31.4 feet.

The magnitude of Dimitri's displacement would be calculated by finding the difference in the position of the two point-to-point distances as follows:

Displacement = AB - BC

Displacement = 18.1 - 13.3

Displacement = 4.8 feet.

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The expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by E = Y * e * ln(L) * A

The work done to stretch the wire can be calculated by integrating the force applied over the displacement. In this case, the force applied is the tension (T) in the wire, and the displacement is the change in length (ΔL) from the original length (L) to the stretched length (L + ΔL).

The tension in the wire is given by Hooke's law, which states that the tension is proportional to the extension of the wire:

T = Y * (ΔL / L)

where Y is the Young's modulus of the material of the wire.

Now, let's calculate the work done to stretch the wire:

dW = T * dL

Integrating this expression from L to L + ΔL:

W = ∫ T * dL = ∫ Y * (ΔL / L) * dL

W = Y * ΔL * ∫ (dL / L)

W = Y * ΔL * ln(L) + C

Here, C is the constant of integration. Since the energy stored in the wire is zero when it is unstretched (ΔL = 0), we can set C = 0.

Finally, the expression for the energy stored in the wire (E) is:

E = W = Y * ΔL * ln(L)

or, if we substitute the cross-sectional area (A) and strain (e) of the wire, where e = ΔL / L:

E = Y * e * ln(L) * A

Thus, the expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by:

E = Y * e * ln(L) * A

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The diameter of each disk is 16.8 mm.

The diameter of the disk can be found using the following equation:

d = sqrt((4t/επ)),

where t is the spacing between the disks, ε is the permittivity of free space, and d is the diameter of the disk.

According to the problem statement, the distance between the two circular disks is 0.5 mm.The electric field strength in a parallel-plate capacitor is given by the following formula:

E = σ / ε

Where E is the electric field strength, σ is the surface charge density, and ε is the permittivity of free space.The surface charge density can be determined by dividing the number of electrons transferred by the area of the disk.

σ = Q / A

where Q is the number of electrons transferred and A is the area of the disk.Substituting this into the formula for the electric field strength and solving for σ gives us:

σ = Eε = (4.0 x 10⁵ N/C)(8.85 x 10⁻¹² F/m) = 3.54 x 10⁻⁶ C/m²

The area of the disk can be found using the formula for the capacitance of a parallel-plate capacitor.

C = εA / t

Where C is the capacitance, ε is the permittivity of free space, A is the area of the disk, and t is the spacing between the disks.Substituting the known values and solving for A gives us:

A = Ct / ε = (3.54 x 10⁻⁶ C/m²)(π(d/2)²) / (0.5 x 10⁻³m)(8.85 x 10⁻¹² F/m) = 1.25 x 10⁻⁶ m²

The number of electrons transferred can be determined using the following formula.

N = Q / e

Where N is the number of electrons transferred, Q is the charge in Coulombs, and e is the charge of an electron.

e = 1.6 x 10⁻¹⁹ C is the charge of an electron.

Substituting the known values and solving for N gives us:

N = Q / e = 3.0 x 10⁻⁹ (1.6 x 10⁻¹⁹) = 4.8 x 10^-10 C

The diameter of the disk can be found using the formula:

d = sqrt((4t/επ))

Substituting the known values and solving for d gives us:

d = sqrt((4(0.5 x 10⁻³ m) / (8.85 x 10⁻¹² F/m)(π)(4.8 x 10^-10 C / (π(8.85 x 10⁻¹² F/m)))))d = sqrt(0.000282) = 0.0168 m

The diameter of each disk is 16.8 mm.

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Answer:

.004 Hz

Explanation:

Frequeny is cycles per second. An oscillation is 1 cycle

F=cycles/sec

4/100

=0.004Hz (Hz- Hertz=1 cycle/sec)

Because the mass is constant, if the velocity is increased, the kinetic energy must also increase.

We know that the mechanical energy is conserved, that is:

Which means that when the car is riding down the potential energy is being converted to kinetic energy; conversely, when the car is riding up the kinetic energy is being converted to potential energy.

Now, the first hill has to be the tallest so that at that point the car has the greater potential energy and for conservation of energy we make sure that the car can climb up all the remaining hills on the roller coaster without getting stopped and without having the need of making more work on the roller coaster.

Answer:

So the roller coaster can gain momentum.

Explanation:

Answer:

D :)

Explanation:

When an impact causes the car to suddenly change its motion, (D) the people in the car will continue to move in the same direction and at the same speed as before the impact.

Newton's first law of motion states that Unless influenced by an imbalanced force, a body at rest stays at rest, and a body in motion keeps moving in a straight path at a constant pace. This law is commonly known as law of inertia and the resistance of a body to maintain its state of rest is called inertia of rest, same as, the resistance of a body to maintain its state of motion is called inertia of motion.

When a car is moving with certain speed, the car along with the people inside the car is in inertia of motion. In an event of accident, the car comes in rest in no time but the man in the car is still in inertia of motion. So, his body moves forward in the car which may cause injuries. To prevent such injuries, the people inside a car are advised to use safety belts.

So, correct answer  is option (D).

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