After considering the data given in the question we come to the conclusion that molecules present in gases are in a constant state of random motion and they exercise a straight line course until they collide with another body.
The collisions exercised by gas particles are completely elastic, because when two molecules collide, the experienced total kinetic energy is conserved.
The temperature of the gas is considered proportional to the average kinetic energy of its molecules. So, when energy is transferred into or out of a substance, it converts the kinetic energy of the molecules and their speed.
This convention in speed can affect and also provide serious alternation to the freedom of movement of the molecules.
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in a charming 19th century hotel, an old style elevator is connected to a counterweight by a cable that passes over a rotating disk 2.50 m in diameter. the elevator is raised and lowered by turning the disk, and the cable does not slip on the rim of the disk but turns with it. at how many rpm must the disk turn to raise the elevator at 35.0 cm/s? to start the elevator moving, it must be accelerated at 18g. what must be the angular acceleration of the disk, in r a d / s 2 ? through what angle (in radians ) has the disk turned when it has raised the elevator 2.55 m between floors?
a) To raise the elevator at 35.0 cm/s, the disk must turn at approximately 0.044 rpm.
b) To accelerate the elevator at 18g, the angular acceleration of the disk must be approximately 141.4 rad/s^2.
c) The angle through which the disk has turned when it has raised the elevator 2.55 m between floors is approximately 2.04 radians.
To find the rpm of the disk required to raise the elevator at a speed of 35.0 cm/s, we can start by finding the speed at which the cable is moving over the disk. The circumference of the disk is
C = πd = π(2.50 m) = 7.85 m
The distance traveled by the cable in one revolution of the disk is equal to the circumference of the disk. Therefore, the speed of the cable is
v = C × rpm
To find the rpm required to raise the elevator at 35.0 cm/s, we can solve for rpm
35.0 cm/s = 0.35 m/s
0.35 m/s = 7.85 m × rpm
rpm = 0.35 m/s ÷ 7.85 m = 0.044 rpm
Therefore, the disk must turn at approximately 0.044 rpm to raise the elevator at a speed of 35.0 cm/s.
To accelerate the elevator at 18g, we need to find the force required:
F = ma = (18g)(m)
where m is the mass of the elevator. We can rearrange this equation to solve for m
m = F ÷ (18g)
To find the angular acceleration of the disk required to accelerate the elevator, we can use the equation
α = a ÷ r
where α is the angular acceleration, a is the linear acceleration, and r is the radius of the disk. The radius of the disk is half the diameter, or 1.25 m.
α = (18g) ÷ (1.25 m)
α ≈ 141.4 rad/s^2
Therefore, the angular acceleration of the disk must be approximately 141.4 rad/s^2 to accelerate the elevator at 18g.
To find the angle through which the disk has turned when it has raised the elevator 2.55 m between floors, we can use the equation
θ = s ÷ r
where θ is the angle in radians, s is the distance traveled by the cable, and r is the radius of the disk.
The distance traveled by the cable is equal to the difference in height between the floors, or 2.55 m.
θ = 2.55 m ÷ 1.25 m
θ ≈ 2.04 radians
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a fixed earth required the distant stars to orbit the earth once a day.ptolemy’s estimate that the fixed stars were 20,000 earth radii apartrequired this fixed shell to orbit the earth how fast?
The fixed shell representing the distant stars would need to orbit the Earth at a speed that allows it to cover a distance equal to the circumference of its orbit in 24 hours.
If Ptolemy's estimate assumes that the fixed stars are 20,000 Earth radii apart, it implies that the fixed shell, representing the distant stars, would need to complete one full orbit around the Earth in a single day.
The fixed shell would need to orbit the Earth at a speed that allows it to cover a distance equal to the circumference of its orbit in 24 hours. The speed required for this orbit depends on the radius of the Earth's orbit.
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PLEASE HELP!!
A swimmer starting from rest has a final velocity of 2.0 m/s after 20 seconds. What is her average acceleration?
O A. 18 m/s2
OB. 22 m/s2
OC. 0.10 m/s2
O D. 40 m/s2
Answer:
\(a=0.1\ m/s^2\)
Explanation:
Given that,
Initial velocity, u = 0
Final velocity, v = 2 m/s
Time, t = 20 s
We need to find the acceleration of the swimmer. The acceleration of an object is equal to the change in velocity per unit time. It can be given by :
\(a=\dfrac{v-u}{t}\\\\a=\dfrac{2\ m/s}{20\ s}\\\\a=0.1\ m/s^2\)
So, her average acceleration of the swimmer is \(0.1\ m/s^2\).
a person throws a baseball from height of 7 feet with an initial vertical velocity of 50 feet per second. Use the vertical motion model, h = -16t squared + vt + s, where v is the initial velocity in feet per second and s is the height in feet, to calculate the amount of time the baseball is in the air before it hits the ground. Round your answer to the nearest tenth if necessary.
Time in air:_____ seconds
Answer:33s
Explanation:
Answer: 3.3 seconds
Explanation:
I just did it
when is the mass of an object if it exerts a force of 160 N and an acceleration of 8.15m/s^2
Answer:
f=ma.......m=f/a......m=20kg
How many atoms of aluminum are on each side of the following equation: 4Al + 3O2 --> 2Al2 O3
Answer:
4 atoms of aluminum are on the left side on the equation and 2 atoms of aluminum are on the right side on the equation.
Explanation:
Answer:
both sides have 4 atoms
Explanation:
the first side 4Al has 4 atoms and the second one 2Al2 has 4 atoms because 2 was multiplied by the 2 near l.
Two electrodes (0.68 mm apart) in your car's spark plug are subject to a 3.5 kV potential difference. What magnitude electric field does this produce in the region between the two electrodes
The magnitude of the electric field produced in the region between the two electrodes is \(5.15 \times 10^6 \ V/m\).
Electric field strengthThe electric field strength produced in the region between the two electrodes is calculated as follows;
\(E = \frac{v}{d}\)
where;
v is the potential difference = 3.5 kV = 3,500 Vd is the separation distance = 0.68 mmThe electric field strength is calculated as follows;
\(E = \frac{3500}{0.68 \times 10^{-3}} \\\\E = 5.15 \times 10^6 \ V/m\)
Thus, the magnitude of the electric field produced in the region between the two electrodes is \(5.15 \times 10^6 \ V/m\).
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If you just take the points I will find you and you will not like what I do
Advanced Space Weather Activity
This lesson highlighted different types of space weather. If you were responsible for reporting space weather like Earth's weather is reported, how would you do it? What would you include?
Create any type of weather report to warn people about space weather activity. You can present it like a weather app, radio announcement, television news report, or newspaper weather section. You only need to pick one type of report to submit to your instructor.
Activity Checklist:
Include at least three different types of space weather events.
Include details and warnings for viewers or listeners about space weather outcomes.
Include images to help identify space weather or its effects on Earth.
Pick a weather app, radio announcement, television news report, or newspaper weather section as the format for your report.
Answer:
Explanation:
here this is a whole slideshow i made
Answer:
Explanation:
Fun homework assignment!
I will provide the info that should allow you to write the space weather report.
Three different types of space weather events:
- Solar flare: strong radiation from the Sun. People should stay inside their spacecrafts.
- Meteorite shower: space rocks zipping by at extreme high speed. Again people should stay inside.
- Man-made space debris: big and small space junk left by human space activities. Slower than meteorite but still need to keep an eye on them.
Effect on Earth:
- Solar flare will affect radio communication and satellite transmission.
- Meteorite shower usually burns up in atmosphere but some may hit ground.
- Space debris also burn up in air but some may land like the recent Chinese rocket.
How much current does a100-W lamp draw when connected to 120 V?
The 0.83 Amperes of current will be produced when 100 W lamp is connected to 120 voltage source.
Current is defined as the flow of charge per unit time. It is related with power and voltage. The formula to be used for current calculation is -
P = VI, where P is power, V is voltage and I refers to current.
Keep the values in formula to find the value of current.
I = 100/120
Performing division on Right Hand Side of the equation to calculate current
I = 0.83 Amperes
Thus, the generated current will be 0.83 Amperes.
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Light of wavelength 632 nm is incident upon a sapphire (n = 1.77) prism at an angle of incidence (with respect to the normal) of 70 degrees. If the angle of the prism is 60 degrees, the angle of refraction at the second face,\Theta, is:
A. 26 degrees
B. 37 degrees
C. 56 degrees
D. 63 degrees
E. 70 degrees
The angle of refraction (Theta) at the second face of the sapphire prism is approximately 63 degrees .(D)
To find the angle of refraction at the second face, follow these steps:
1. Use Snell's Law to find the angle of refraction (r1) at the first face: (D)
n1 * sin(i) = n2 * sin(r1)
2. Calculate the angle inside the prism (α):
α = 180 - angle of the prism - r1
3. Use the total internal reflection condition for the second face to find the critical angle (θc):
sin(θc) = n2 / n1
4. Use the angle of incidence (i) at the second face:
i2 = α + θc
5. Use Snell's Law again to find the angle of refraction (Theta) at the second face:
n2 * sin(i2) = n1 * sin(Theta)
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What is the main reason that the gravitational attraction between Earth and the Moon changes each day?
(1) Earth's axis is tilted at 23.5°.
(2) Earth's rotational speed varies with the seasons.
(3) The Moon has an elliptical orbit.
(4) The Moon has a spherical shape
The Moon has an elliptical orbit is the main reason that the gravitational attraction between Earth and the Moon changes each day.
The Effect of Earth's Gravity and Moon's GravityEarth's gravity pulls the moon to the center of the earth, while the moon's gravitational force maintains the moon's position, resulting in a centrifugal force that makes the moon rotate on its axis and surround the earth so that it is not attracted to the earth's center of gravity or stays in its orbit.
The influence of the gravitational force of the earth and the moon is the tides of the sea. The moon's gravitational force pulls seawater toward the moon, affecting wave height and sea level. Because the moon revolves around the earth, there will be times when one side of the earth is closer to the moon. The part that is close to the moon will experience high tide, while the other part that is not close to the moon will experience low tide. The tides are also related to the phases of the moon. Usually, sea water will experience high tides during the full moon.
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An electron moving at 4.10 ✕ 103 m/s in a 1.45 T magnetic field experiences a magnetic force of 1.40 ✕ 10−16 N. What angle does the velocity of the electron make with the magnetic field? There are two answers between 0° and 180°. ° (smaller value) ° (larger value)
ANSWER
\(8.46\degree;\text{ }171.54\operatorname{\degree}\)EXPLANATION
Parameters given:
Speed of electron, v = 4.10 * 10^3 m/s
Magnetic field, B = 1.45 T
Magnetic force, F = 1.40 * 10^(-16) N
To find the angle that the velocity of the electron makes with the magnetic field, apply the formula for magnetic force:
\(F=qvB\sin\theta\)where θ = angle
q = electric charge = 1.6 * 10^(-19) C
Make θ the subject of the formula:
\(\begin{gathered} \sin\theta=\frac{F}{qvB} \\ \\ \theta=\sin^{-1}(\frac{F}{qvB}) \end{gathered}\)Therefore, the angle that the velocity makes is:
\(\begin{gathered} \theta=\sin^{-1}(\frac{1.4*10^{-16}}{1.6*10^{-19}*4.1*10^3*1.45}) \\ \\ \theta=\sin^{-1}(0.1472) \\ \\ \theta=8.46\degree \end{gathered}\)To find the second angle, subtract the angle from 180 degrees:
\(\begin{gathered} 180-8.46 \\ \\ 171.54\degree \end{gathered}\)The angles are:
\(8.46\operatorname{\degree};\text{ }171.54\operatorname{\degree}\)the maximum value of a short circuit current from line-to-neutral grounded
The maximum value of a short circuit current from line-to-neutral grounded will depend on various factors such as the voltage level of the electrical system.
The impedance of the circuit, the available fault current, and the protective devices that are in place to limit the current.In a typical residential or commercial electrical system in the United States, the maximum short circuit current from line-to-neutral grounded is typically around 10,000 to 20,000 amps for a 120/240 volt system. However, in larger industrial or utility systems with higher voltage levels, the short circuit current can be much higher and can exceed several hundred thousand amps.It is important to note that short circuit currents can cause significant damage to electrical equipment and can pose a serious safety hazard to people who come into contact with the electrical system.
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A particle has a rest mass of 6.74×10−27 kg and a momentum of 2.00×10−18 kg⋅m/s .
Part A What is the total energy (kinetic plus rest energy) of the particle?
Part B What is the kinetic energy of the particle?
Part C What is the ratio of the kinetic energy to the rest energy of the particle?
A. The total energy of the particle is 9.04×10⁻¹⁰ J
B. The kinetic energy of the particle is 2.97×10⁻¹⁰ J
C. The ratio of the kinetic energy to the rest energy of the particle is 0.49
How do i determine the total energy?First, we shall obtain the rest energy. Details below:
Mass (m) = 6.74×10⁻²⁷ kgSpeed of light (c) = 3×10⁸ m/s Rest energy (E) =?E = mc²
= 6.74×10⁻²⁷ × (3×10⁸)²
= 6.07×10⁻¹⁰ J
Thus, rest energy is 6.07×10⁻¹⁰ J
Next, we shall obtain the kinetic energy. Details below:
Momentum = 2.00×10⁻¹⁸ Kg.m/sMass (m) = 6.74×10⁻²⁷ KgVelocity (v) = momentum / mass = 2.00×10⁻¹⁸ / 6.74×10⁻²⁷ = 2.97×10⁸ m/sKinetic energy (KE) =?KE = ½mv²
= ½ × 6.74×10⁻²⁷ × (2.97×10⁸)²
= 2.97×10⁻¹⁰ J
Thus, the kinetic energy is 2.97×10⁻¹⁰ J
Finally, we shall obtain the total energy. Details below:
Rest energy (E) = 6.07×10⁻¹⁰ JKinetic energy (KE) = 2.97×10⁻¹⁰ JTotal energy =?Total energy = rest energy + kinetic energy
= 6.07×10⁻¹⁰ + 2.97×10⁻¹⁰
= 9.04×10⁻¹⁰ J
How do i determine the ratio?The ratio of kinetic energy to rest energy can be obtained as follow:
Kinetic energy (KE) = 2.97×10⁻¹⁰ JRest energy (E) = 6.07×10⁻¹⁰ JRatio =?Ratio = KE / E
= 2.97×10⁻¹⁰ / 6.07×10⁻¹⁰
= 0.49
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The phase Ø of light of wavelength λ travelling through a shifter with refraction index n is given by Øs = 2πntλ-1, where t is the shifter thickness. The phase of the same light wave travelling through air for a distance equal to t is Øa= 2ntλ-1. Derive an expression for the thickness of the shifter as a function of λ and n in order to obtain a phase shift of 180°.
The thickness of the shifter is given as t = λ / 2n.
The given equation of the phase of light of wavelength λ traveling through a shifter with a refractive index n is given by: Øs = 2πntλ-1, where t is the thickness of the shifter.
The phase of the same light wave traveling through air for a distance equal to t is Øa= 2ntλ-1.
We are supposed to derive an expression for the thickness of the shifter as a function of λ and n to get a phase shift of 180°.
Given, The phase of light of wavelength λ traveling through a shifter with a refractive index n is given by: Øs = 2πntλ-1
The phase of the same light wave traveling through air for a distance equal to t is Øa = 2ntλ-1
To obtain a phase shift of 180°, we have: Øs - Øa = πi where i is an integer.
Substituting the value of Øs and Øa in the above expression, we have:
2πntλ-1 - 2ntλ-1 = πi2πntλ-1 - 2ntλ-1
= π(2nλt) / λ2πntλ-1
= 2nλt / λπt
= λ / 2n
Hence, the thickness of the shifter is given as t = λ / 2n.
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"true wisdom is knowing what you don't know"
Reader's Response/explanation
(Y'all I need help)
Answer:
“The only true wisdom is in knowing you know nothing.” ― Socrates. Socrates had it right. Remain humble and appreciate the fact that you don't know everything. ... Thankfully, one's search for knowledge has no end as there is always something new to learn, giving one's life meaning and purpose.
Explanation:
Answer:
knowing wisdom cool
Explanation:
lol
virtual images can be projected to a screen if you turn the screen slightly true or false
False
Virtual image cannot be caught on a screen
There are two groups of earthworms on the sidewalk. One group is on a shady, moist area on the sidewalk, and they are moving. The other group is on a very sunny, dry area of the sidewalk, and none of the worms in this group are still living.
What question could be asked to investigate the reason for these observations?
A. What kind of living environment do earthworms need?
B. How do earthworms get on the sidewalk?
C. Why do earthworms crawl?
D. What kinds of birds eat earthworms?
A.
Smooth-skinned earthworms have a body made up of numerous tiny segments. The lines designating the segments are visible on the body. Each segment possesses tiny, stiff hairs that aid in the worm's movement; occasionally, the hairs are difficult to perceive. They lack a skeleton yet have a large number of muscles.
B.
Because they lack lungs, earthworms breathe through their skin. For dissolved oxygen to enter their bloodstream, their skin must be damp. The mucus-coated skin of earthworms makes them dependent on a wet, moist environment to survive.
C.
The earthworm's characteristic crawling movement is caused by the action of muscles in the body wall. These lengthen and shorten the body in wavelike motions. Four pairs of tiny hard bristles on each segment help the worm grip the ground and hold onto the side of the burrow.
D.
Blackbirds, robins, and song thrushes are ground feeders, and for them, a worm is the only food that compares to it in taste. Large eyes and powerful bills let all of them to see in the early morning light, when earthworms are most active close to the surface. Their strong bills also allow them to pull struggling earthworms from the soil.
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A 50 kg ball traveling at 20 m/s would haveA50 kg ball traveling at 5 m/s would haveA 50 kg person falling at 10 m/s would havekinetic energy✓ kinetic energykinetic energythe same2 times more2 times less4 times more4 times lessDoneIntro5 of 9
We have the next formula to calculate the kinetic energy
\(KE=\frac{1}{2}mv^2\)where m is the mass and v is the velocity
For the kinetic energy of ball 50 kg traveling at 10 m/s
\(KE=\frac{1}{2}(50)(10)^2=2500\text{ joules}\)For the kinetic energy of ball 50 kg traveling at 20 m/s
\(KE=\frac{1}{2}(50)(20)^2=10000\text{ joules}\)A 50 kg ball traveling at 20 m/s would have 4 times kinetic energy.
For kinetic energy of the ball 50 kg at 5m/s
\(KE=\frac{1}{2}\mleft(50\mright)\mleft(5\mright)^2=625\text{ joules}\)A 50 kg ball traveling at 5 m/s would have 4 times less kinetic energy
For the person 50kg falling 10 m/s
\(KE=\frac{1}{2}\mleft(50\mright)\mleft(10\mright)^2=2500joules\)A 50 kg person falling at 10 m/s would have the same kineticenergy}.
The solution is
A 50 kg ball traveling at 20 m/s would have 4 times more kinetic energy.
A 50 kg ball traveling at 5 m/s would have 4 times less kinetic energy.
A 50 kg person falling at 10 m/s would have the same kinetic energy.
A lamp is marked 24V, 100W. Describe an experiment to check that the electrical power supplied to the lamp is 100W when the p.d. across it is 24V.
In your account you should
* include a circuit diagram,
* state the readings that are taken,
* show how the result is calculated from the readings.
The electrical power supplied to the lamp is 100W when the p.d. across it is 24V and the current is 4.2 A.
What is electrical power?Electrical power is the rate at which electrical work is done.
The unit of electrical power is Watts.
Power = Current × VoltageThe experiment will require a 24V Battery, a Lamp marked 24V, 100 W, a key, wires, a rheostat, a voltmeter and an ammeter.
The circuit is completed and the rheostat is adjusted to provide until the voltmeter reads 24V.
The ammeter reading is taken as well.
When the voltmeter reading is 24V, it can be seen that' the ammeter reading for current is approximately 4.2 A.
Calculating, the power of the lamp:
Power = 24 × 4.2 = 100 W
Therefore, the electrical power supplied to the lamp is 100W when the p.d. across it is 24V and the current is 4.2 A.
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A soccer ball is kicked off a 150 m tall building and lands 30 m away. How long was the ball in the air?
a. The ball was in the air for 5.53 seconds.
b. The initial velocity of the ball is 54.194 m/s
c. The final velocity of the ball in the y direction is -54.194 m/s
d. The x component of the initial velocity is 50.926 m/s, and the y component is 18.534 m/s.
To solve these questions, we can use the equations of motion for projectile motion. Let's assume the acceleration due to gravity is -9.8 m/\(s^2\) (taking downward as the negative direction).
a. To find the time the ball was in the air, we can use the equation:
Δy = v_iy * t + (1/2) * a_y * \(t^2\)
Where Δy is the vertical displacement, v_iy is the initial vertical velocity, a_y is the vertical acceleration, and t is the time.
Since the ball was dropped from rest, its initial vertical velocity is 0 m/s, and the vertical displacement is -150 m (negative because it is going downward).
-150 = 0 * t + (1/2) * (-9.8) * \(t^2\)
Simplifying the equation and solving for t, we get:
4.9 * \(t^2\) = 150
\(t^2\) = 150 / 4.9
t ≈ 5.53 seconds
Therefore, the ball was in the air for approximately 5.53 seconds.
b. To find the initial velocity of the ball, we can use the equation:
v_fy = v_iy + a_y * t
Where v_fy is the final vertical velocity.
Since the ball lands 30 m away, its final vertical displacement is 0 m, and the time is 5.53 seconds.
0 = v_iy + (-9.8) * 5.53
Solving for v_iy, we get:
v_iy = 9.8 * 5.53
v_iy ≈ 54.194 m/s
Therefore, the initial velocity of the ball is approximately 54.194 m/s.
c. The final velocity of the ball in the y direction is the same as the initial velocity because the only force acting on it is gravity, which causes a constant acceleration. Therefore, the final velocity in the y direction is approximately -54.194 m/s (negative due to the downward direction).
d. When the ball is kicked off the building at an angle of 20 degrees below the horizontal, we need to find the x and y components of the initial velocity.
The magnitude of the initial velocity (from part b) is 54.194 m/s.
The x component of the initial velocity can be found using:
v_ix = v_i * cos(θ)
Where θ is the angle of 20 degrees below the horizontal.
v_ix = 54.194 * cos(20)
v_ix ≈ 50.926 m/s
The y component of the initial velocity can be found using:
v_iy = v_i * sin(θ)
v_iy = 54.194 * sin(20)
v_iy ≈ 18.534 m/s
Therefore, the x component of the initial velocity is approximately 50.926 m/s, and the y component is approximately 18.534 m/s.
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The question was Incomplete, Find the full content below:
A soccer ball is kicked off a 150 m tall building and lands 30 m away.
a. How long was the ball in the air?
b. What was the initial velocity of the ball?
C. What is the final velocity of the ball in the y direction?
d. Assume the ball has the same speed as you solved for in part b except it is kicked off the building at an angle of 20 degrees below the horizontal. What is the x component of the initial velocity? What is the y component of the initial velocity?
which concept was demonstrated by rutherford's gold foil experiment? mastering chem
Answer: the atom is mostly empty space with a tiny, dense, positively-charged nucleus
Explanation: Rutherford's gold foil experiments involved firing positively charged alpha particles at a piece of gold/metal foil. The alpha particles that were fired at the gold foil were positively charged. Most of the time, the alpha particles would pass through the foil without any change in their trajectories, which is what was expected if JJ Thomson's plum pudding model of the atom was correct. However, occasionally the alpha particles would be deflected to some degree, and sometimes an alpha particle would bounce back directly toward the experimenter. Rutherford likened this to firing a 15-inch artillery shell at a sheet of tissue paper and the shell came back to hit you.
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Rutherford's gold foil experiment demonstrated the concept of the nucleus of the atom.What is Rutherford's gold foil experiment?
Rutherford's gold foil experiment is an experiment that was conducted by Ernest Rutherford in 1911 to determine the structure of the atom. Rutherford bombarded alpha particles at thin gold foil and noted their trajectory and path.The experiment was conducted to answer the prevailing model of the atom's structure, which was the Thomson atomic model.
According to the Thomson atomic model, the atom's positive charge is evenly distributed throughout the atom, like raisins in a pudding. Rutherford's experiment refuted this hypothesis and provided a new model that supported his findings.
The findings of the gold foil experiment:
Rutherford's experiment led him to conclude that the positive charge of the atom is concentrated in the nucleus, a central part of the atom. In this model, electrons orbit the nucleus, like planets orbiting the sun.
Rutherford's gold foil experiment demonstrated that the atom is made up of mostly empty space, with a small, dense, and positively charged nucleus at the center. This discovery paved the way for further research into atomic structure and the discovery of subatomic particles like protons and neutrons.
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how can you grow taller in a small amount of time?
Answer:
.
Explanation:
Answer:
do sports eg skipping rope, playing basketball, badminton etc. in other words, activities that involve jumping
Explain why 5N + 4N does not always mean a resultant force of 9N
Answer:
It depends on where the arrow is showing / direction of the resultant force.
Add for vectors in same direction, ie., 5N + 4N=9N
(arrow pointing in same direction)
Minus for different directions, ie., 5N - 4N=1N
(arrow pointing in opposite direction)
Hope this helps!
Further examples:
6N 46N
--------> ----->
(6+4=10N)
5N 4N
<------------ ------>
(5-4=1N)
or
8N 6N
--------------> <--------
(8-6=2N)
8 A student has a resistor with an unknown resistance.
What two measurements must the student make to be able to calculate the resistance?
this is your answer
- BRAINLIEST answerer ❤️
Which statement does NOT explain the concept of the Doppler Effect? A. As an observer moves away from a stationary sound, the sound waves are stretched making the pitch lower. B. As an observer approaches a stationary sound, the sound waves are compressed, making the pitch higher. C. As a sound source approaches a stationary object, the sound waves are compressed, making the pitch higher. D. As a sound source moves away from a stationary object, the sound waves are compressed, increasing the pitch.
Answer:
D
Explanation:
When the sound is moving away from the stationary object the pitch decreases according to the Doppler Effect.
During which type of process applied to an ideal gas is there no change in internal energy of the gas?
a) isobaric
b) isochoric
c) isothermal
d) adiabatic
e) Internal energy changes during any of these processes.
The correct answer to the question is c) isothermal.
During an isothermal process applied to an ideal gas, there is no change in the internal energy of the gas. In an isothermal process, the temperature of the gas remains constant throughout the process. This means that the average kinetic energy of the gas molecules remains the same.
Since internal energy is directly related to the average kinetic energy of the gas molecules, when the temperature is constant, the internal energy also remains constant. This is because the increase in energy due to compression is balanced by the decrease in energy due to expansion, resulting in no net change in internal energy.
To illustrate this, let's consider an example of a gas confined in a cylinder with a movable piston. During an isothermal compression of the gas, work is done on the gas to decrease its volume. However, since the temperature remains constant, the gas molecules do not gain any additional kinetic energy. The work done on the gas is equal to the heat extracted from the gas, resulting in no change in the internal energy.
In contrast, during an isobaric process, the pressure of the gas remains constant while the volume may change. In an isochoric process, the volume remains constant while the pressure may change. In an adiabatic process, no heat is exchanged between the gas and its surroundings. In all these processes, there may be a change in the internal energy of the gas.
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Can anyone answer my questions that I've asked?
Answer:
76 N north-east
Explanation:
V = √(44²+62²) = 76 N
In one of Gregor Mendel's first experiments, he crossed a purple-flowered pea plant (PP) with a white-flowered pea plant (pp).
According to the question the result of Mendel's experiment was that all of the offspring had purple flowers (Pp).
What is offspring?Offspring is a term used to refer to the progeny or descendants of any organism. It is usually used to refer to the biological children of a couple, but can also be used to refer to the descendants of any lineage. The term can also be used to refer to the progeny of plants, animals, and other organisms. Offspring is the result of the reproductive process, when two individuals combine their genetic material through sexual reproduction to produce a new organism. It is the continuation of the species, and the new individual contains genetic material from both of its parents. Offspring can also be produced through asexual reproduction, in which only one organism is involved in the process.
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Which of the following are part of climactic plot structure?
a. Plot begins late in the story
b. Occurs in a restricted locale
c. Covers a short period of time
d. A limited number of characters
Both of the below elements, covering a short period of time and having a limited number of characters, are typically associated with climactic plot structure. The correct options are:
c. Covers a short period of time
d. A limited number of characters
This structure focuses on a specific event or conflict that unfolds rapidly and intensifies towards a climax, usually involving a small set of characters. The plot begins closer to the climax, omitting extensive exposition or background information, and often takes place in a restricted locale to maintain a sense of urgency and intensity.
Climactic plot structure refers to a narrative structure that focuses on a condensed timeframe and a limited number of characters. This type of plot structure often unfolds rapidly, with events building up to a climactic moment or turning point. By covering a short period of time and involving a small cast of characters, the climactic plot structure creates a sense of intensity and immediacy in the story, allowing for focused and impactful storytelling. This structure is commonly used in works such as short stories, plays, and films where brevity and concentrated impact are desired.
Therefore, options c and d are correct.
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