WILL GIVE BRAINLIEST!!
Directions: Solve using the FOIL method. Hint: Watch out for any negative signs and follow rules for signed numbers!
1. (x-2)(x+3)
2. (x+4)(x-12)
3. (x+3)(x+4)
4. (x+6)(x+7)
5. (x+8)(x+9)
6. (x-5)(x+5)
7. (x+3)(x-3)
8. (x+10)(x+10)
9. (x-2)(x+12)
10. (x + 4)(x - 3)
15. A student received a 75% on an exam. If there were 20 questions on the exam, which ratio would show the number of questions answered correctly to the total number of questions?
O A. 15 20
O B. 20:15
O C. 20.5
O D.5.20
Answer:
75% = 3/4
3/4 of 20 = 15
Ratio - 15:20 (A)
The ratio that would show the number of questions answered correctly to the total number of questions as 15 : 20.
What is ratio?A ratio between two variables {x} and {y} can be expressed in the following form → {x : y} = {x}/{y}.
We can write the relation between two ratios using the proportion as -
{x : y} :: {a : b}
Given is that a student received a 75% on an exam. There were 20 questions on the exam.
It is given to find that which ratio would show the number of questions answered correctly to the total number of questions.
Total number of questions = 20
Number of questions answered correctly = 75%
75% of 20
75/100 x 20
75/5
15
We can write the ratio that would show the number of questions answered correctly to the total number of questions as 15 : 20.
Therefore, the ratio that would show the number of questions answered correctly to the total number of questions as 15 : 20.
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Calculate the following: i. the area of the region in the first quadrant bounded by the curves of f(x)= x
and g(x)=x−2, and the x-axis. Show your working. [3 Marks] ii. the area of the region bounded by the curves of f(x)=sinx and g(x)=cosx in the interval [ 4
π
, 4
5π
]. Show your working
(i) The area of the region is 4 square units.
(ii) The area of the region bounded by the curves is,
1 + (sin(π/2)cos(π/5) + cos(π/2)sin(π/5)) + (cos(π/2)cos(π/5) - sin(π/2)sin(π/5))
(i) The area of the region bounded by the curves f(x) = x and g(x) = x - 2 in the first quadrant,
we need to compute the definite integral:
∫[0, 2] (x - (x - 2)) dx
= ∫[0, 2] 2 dx
= [2x] from 0 to 2
= 4
Therefore, the area of the region is 4 square units.
ii. The area of the region bounded by the curves f(x) = sin(x) and g(x) = cos(x) in the interval [4π/5, 4π], we need to compute the definite integral:
∫[4π/5, 4π] (cos(x) - sin(x)) dx
= [-sin(x) - cos(x)] from 4π/5 to 4π
= [-sin(4π) - cos(4π)] - [-sin(4π/5) - cos(4π/5)]
= [0 - 1] - [-sin(4π/5) - cos(4π/5)]
= 1 + sin(4π/5) + cos(4π/5)
Using the angle sum identity cos(a + b) = cos(a)cos(b) - sin(a)sin(b), we can simplify the expression:
= 1 + sin(4π/5) + cos(4π/5)
= 1 + sin(π/2 + π/5) + cos(π/2 + π/5)
= 1 + (sin(π/2)cos(π/5) + cos(π/2)sin(π/5)) + (cos(π/2)cos(π/5) - sin(π/2)sin(π/5))
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Which function correctly describes the zeros given?
0,−1,2
A) F(x)= x(x+1)(x-2)
B) F(x)= x(x-1)(x+2)
C) F(x)= (x+1)(x-2)
D) None of these
Using the factored form of a polynomial for the given zeros, we can see that option A is the correct one, the function is:
F(x) = x*(x + 1)*(x - 2)
Which function correctly describes the zeros given?For a polynomial with the zeros:
x₁, x₂, x₃, ..., xₙ
The polynomial can be written as:
y = (x - x₁)*(x - x₂)*...*(x - xₙ)
In this case, the zeros are:
0, -1, and 2
Then we can write the polynomial as:
y = (x - 0)*(x + 1)*(x - 2)
If we simplify this, we get:y = x*(x + 1)*(x - 2)Which is the one we can see in option A, so we conclude that option A is the correct one.F(x) = x*(x + 1)*(x - 2)
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An electronics store is having a sale. A CD player that normally costs $49.95 is on sale for 5% off. How much is the discount
Answer:$2.50
Step-by-step explanation: You will take $49.95 times 0.05 or 5% and you get 2.497 and round that to $2.50.
what is the answer to ,Evaluate 2⁶
algorithm depth-first search : find the order of visit: 2. algorithm breadth first search : find the order of visit
The order of visit for DFS and BFS will differ based on the structure of the graph or tree and the starting node. DFS will typically visit nodes in a deeper order, while BFS will visit nodes in a breadth-first order.
Both algorithm depth-first search and algorithm breadth-first search are used to traverse or search a graph or tree data structure. The difference between them lies in their traversal strategy.
Depth-first search (DFS) starts at a root node and explores as far as possible along each branch before backtracking. It follows a content-loaded algorithm, meaning that it prioritizes exploring deeper into the structure before considering other branches. In terms of visit order, DFS starts at the root node, then moves to its first child node, and continues to explore its descendants until it reaches a leaf node. Once it has visited all descendants of the current node, it backtracks to the previous node and repeats the process until it has visited all nodes.
On the other hand, breadth-first search (BFS) starts at the root node and explores all the neighboring nodes at the current depth level before moving on to the next depth level. It follows a breadth-first algorithm, meaning that it prioritizes exploring all nodes at a given depth level before moving on to deeper levels. In terms of visit order, BFS visits all nodes at a given depth level before moving on to the next level.
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Please answer this in two minutes
Answer:
tan(X) = 1.05
Step-by-step explanation:
The triangles WXY and VTU are similar using the case AA (angle-angle).
The angle X is equal the angle T, therefore they have the same tangent value.
The tangent value is given by the opposite side to the angle divided by the adjacent side to the angle, so we have that:
\(tan(T) = UV / UT\)
\(tan(T) = 21 / 20 = 1.05\)
\(tan(X) = tan(T) = 1.05\)
find if one or neither
The categories of the ordered pairs are
(6, -3) = [g . f](x)(-3, 3) = [f . g](x)(7, 5) = Neither(5, 4) = NeitherHow to categorize the ordered pairsFrom the question, we have the following ordered pairs that can be used in our computation:
f = {(3, -4). (6, 5), (-4,3), (5,7)}
g = {(-4,8), (5,-3), (-3,-4),(7, 4)}
In the above, we have
[f . g](x) = f(g(x))
So, we have
[f . g](x) = f(g(6))
This gives
[f . g](x) = f(g(6))
Next, we have
[g . f](x) = g(f(x))
So, we have
[g . f](6) = g(f(6))
[g . f](6) = g(5)
[g . f](6) = -3
This means that
(6, -3) = [g . f](x)
Next, we have
[f . g](-3) = f(g(-3))
This gives
[f . g](-3) = f(-4) = 3
This means that
(-3, 3) = [f . g](x)
Next, we have
[f . g](7) = f(g(7))
This gives
[g . f](7) = f(g(7)) = f(4)
[g . f](7) = Neither
Next, we have
[f . g](5) = f(g(5)) = f(-3) =
[g . f](5) = g(f(5)) = g(-3) = -4 = Neither
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HELP ME WITH ALGEBRA PLEASE! THANK YOU
Answer:
d=8
Step-by-step explanation:
Okay we've got 68/17 and d/2
68/17 = 4 meaning d/2 is also 4. Since 4 × 2 is 8, we know the answer is 8.
Find sec 0 if 0 is in quadrant IV and sin0=-1/5
Answer:
sec 0 = 5/(2√6)
Step-by-step explanation:
sin 0 = -1/5
Fourth quadrant Cos positive Rest negative
cos²0 + sin²0 = 1
cos²0 = 1-sin²0
cos²0 = 1 - (1/5)²
cos²0 = 1- 1/25
cos²0 = 24/25
cos0 = ±(2√6)/5
quadrant IV cos is positive.
Therefore cos0 = (2√6)/5
Now, sec0 = 1/cos0
sec0 = 1/{(2√6)/5)}
sec0 = 5/(2√6)
.
Hope it helps
Let X₁, X₂,..,X₁₀₀ be a random sample from a distribution with pdf f(x) ={x² + \frac{2}{3}, (0 ≤ x ≤ 1) otherwise Find the standard deviation of (round off to second decimal place).
The standard deviation of the given random sample is approximately 0.351.
To find the standard deviation of a random sample, we need to calculate the standard deviation of the underlying distribution.
In this case, the distribution has a density function:
f(x) = x² + 2/3 (0 ≤ x ≤ 1)
To find the standard deviation, we first need to find the mean (μ) and variance (σ²) of the distribution.
The mean can be calculated as follows:
μ = ∫(x × f(x)) dx
where the integral is taken over the range [0, 1].
μ = ∫(x × (x² + 2/3)) dx
= ∫(x³ + 2/3 × x) dx
= (1/4 × x⁴ + 1/3 × x²) |[0, 1]
= (1/4 × 1⁴ + 1/3 × 1²) - (1/4 × 0⁴ + 1/3 × 0²)
= 1/4 + 1/3
= 7/12
Next, we calculate the variance (σ²):
σ² = ∫((x - μ)² × f(x)) dx
σ² = ∫((x - 7/12)² × (x² + 2/3)) dx
= ∫((x⁴ - 7/6 × x³ + 49/144 × x² - 7/36 × x + 49/432) dx
= (1/5 × x⁵ - 7/24 × x⁴ + 49/432 × x³ - 7/72 × x² + 49/432 × x) |[0, 1]
= 1/5 - 7/24 + 49/432 - 7/72 + 49/432
= 145/432
Now, we can calculate the standard deviation (σ) by taking the square root of the variance:
σ = √(145/432)
≈ 0.351
Therefore, the standard deviation of the given random sample is approximately 0.351.
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Determine the pH and percent ionization for a hydrocyanic acid (HCN) solution of concentration 5.5×10^−3M. ( Ka
for HCN is 4.9×10^−10) pH=
(Enter your answer in scientific notation.)
pH = 5.28; Percent ionization = 0.0945%.
To determine the pH and percent ionization for a hydrocyanic acid (HCN) solution of concentration 5.5×10−3 M, we are given that the value of Ka for HCN is 4.9×10−10. We can use the formula of Ka to find the pH and percent ionization of the given hydrocyanic acid solution.
\(Ka = [H3O+][CN-]/[HCN]\)
\(Ka = [H3O+]^2/[HCN]\)
Since the concentration of CN- is equal to the concentration of H3O+ because one H+ ion is donated by HCN, we can take [H3O+] = [CN-]
\(Ka = [CN-][H3O+]/[HCN]\)
Substituting the values given in the question
\(Ka = x^2/[HCN]\)
where x is the concentration of H3O+ ions when the equilibrium is established.
Let the concentration of H3O+ be x. Thus, [CN-] = x
[\(Moles of HCN] = 5.5×10^-3 M\)
Volume of the solution is not given. However, it is safe to assume that the volume is 1 L since it is not mentioned otherwise.
Number of moles of HCN in 1 L of solution = \(5.5×10^-3 M × 1 L = 5.5×10^-3 moles\)
Now,
\(Ka = x^2/[HCN]\)
\(4.9×10^-10 = x^2/5.5×10^-3\)
\(x^2 = 4.9×10^-10 × 5.5×10^-3\)
\(x^2 = 2.695×10^-12\)
\(x = [H3O+] = √(2.695×10^-12) = 5.2×10^-6\)
\(pH = -log[H3O+]\)
\(pH = -log(5.2×10^-6)\)
pH = 5.28
Percent ionization = [H3O+]/[HCN] × 100
[H3O+] = 5.2×10^-6, [HCN] = 5.5×10^-3
Percent ionization =\((5.2×10^-6/5.5×10^-3) × 100\)
Percent ionization = 0.0945%
Answer: pH = 5.28; Percent ionization = 0.0945%.
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The pH of a hydrocyanic acid (HCN) solution with a concentration of 5.5×10^−3 M can be calculated to be approximately 2.06. The percent ionization of the HCN solution can be determined using the Ka value of 4.9×10^−10.
To calculate the pH of the HCN solution, we first need to determine the concentration of H+ ions in the solution. Since hydrocyanic acid (HCN) is a weak acid, it will undergo partial ionization in water. The concentration of H+ ions can be obtained by calculating the square root of the Ka value multiplied by the initial concentration of HCN.
[H+] = sqrt(Ka * [HCN])
[H+] = sqrt(4.9×10^−10 * 5.5×10^−3)
[H+] ≈ 2.35×10^−7 M
Using the concentration of H+ ions, we can calculate the pH of the solution by taking the negative logarithm (base 10) of the H+ ion concentration:
pH = -log[H+]
pH ≈ -log(2.35×10^−7)
pH ≈ 2.06
The percent ionization of the HCN solution can be determined by dividing the concentration of ionized H+ ions ([H+]) by the initial concentration of HCN and multiplying by 100:
Percent Ionization = ([H+] / [HCN]) * 100
Percent Ionization = (2.35×10^−7 / 5.5×10^−3) * 100
Percent Ionization ≈ 0.00427%
Therefore, the pH of the HCN solution is approximately 2.06, and the percent ionization is approximately 0.00427%.
To calculate the pH of the HCN solution, we first need to determine the concentration of H+ ions in the solution. Since hydrocyanic acid (HCN) is a weak acid, it will undergo partial ionization in water. The concentration of H+ ions can be obtained by calculating the square root of the Ka value multiplied by the initial concentration of HCN.
[H+] = sqrt(Ka * [HCN])
[H+] = sqrt(4.9×10^−10 * 5.5×10^−3)
[H+] ≈ 2.35×10^−7 M
Using the concentration of H+ ions, we can calculate the pH of the solution by taking the negative logarithm (base 10) of the H+ ion concentration:
pH = -log[H+]
pH ≈ -log(2.35×10^−7)
pH ≈ 2.06
The percent ionization of the HCN solution can be determined by dividing the concentration of ionized H+ ions ([H+]) by the initial concentration of HCN and multiplying by 100:
Percent Ionization = ([H+] / [HCN]) * 100
Percent Ionization = (2.35×10^−7 / 5.5×10^−3) * 100
Percent Ionization ≈ 0.00427%
Therefore, the pH of the HCN solution is approximately 2.06, and the percent ionization is approximately 0.00427%.
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2. Task: 6 1/3 yards = ? feet Rule: (number) (unit)
help asap!
Answer:
18.3 yards
Step-by-step explanation:
6 yards = 18 feet
1/3 yards = 0.3333...
Using the substitution method, find the solution to this system of equations. Be sure to show your work!
-2x+2y=7
-x+y=4
please show a breakdown of the equation and a correct answer! thanks.
Answer:
To solve the given system of equations using the substitution method, we need to solve one equation for one variable and then substitute that expression into the other equation for that same variable. Let's solve the second equation for y.
-x + y = 4
y = x + 4
Now we can substitute this expression for y into the first equation and solve for x.
-2x + 2(x + 4) = 7
-2x + 2x + 8 = 7
8 = 7
The equation 8 = 7 is not true, which means the system of equations has no solution. We can see this visually by graphing the two lines. They are parallel and will never intersect, which means there is no point that satisfies both equations.
Therefore, the solution to the system of equations is "No solution."
Note: Please be sure to double-check your work to avoid mistakes.
Step-by-step explanation:
Hope this helps you!! Have a wonderful day/night!!
How can you find the number of 2/3’s in 6?
4
Step-by-step explanation:
The number of 2/3's in 6 can be found by dividing 6 by 3 and then multiplying the result by 2. The answer is 4.
Ernie earned $121.50 more than Kaylin. Tria earned $35 less than 3 times the amount Kaylin earned. Ernie, Tria, and Kaylin earned $579 in all. How much did Tria earn?
$98.50
$220.00
$260.50
$330.50
x - Ernie, y - Kaylin, z - Tria
x = y + 121.50
z = 3y - 35
x + y + z = 579
-------------------------
z = 3 y - 35 => - 3 y + z = -35
y + 121.50 + y + z = 579
---------------------------------
- 3 y + z = - 35 / · ( -1 )
2 y + z = 457.50 (we will use the elimination method)
---------------------------------
3 y - z = 35
2 y + z = 457.50
----------------------
5 y = 492.5, y = 492.5 : 5 = 98.5
z = 3 · 98.5 - 35
z = 260.5
Tria earned $260.5
A company is producing picture frames as well as the glass for the front of the frames. The amount of wood required for the frame is represented by the function W(x), and the amount of glass is represented by the function G(x). The frames have lengths represented by the function f(x) and widths represented by g(x). Which statement describes the combined functions W(x) and G(x)? The amount of glass required has a constant rate of change, but the amount of wood does not. The amount of wood required has a constant rate of change, but the amount of glass does not. Both the amount of wood required and the amount of glass required have a constant rate of change. Neither the amount of wood required nor the amount of glass required has a constant rate of change.
The correct statement regarding the rate of change of the functions is given as follows:
The amount of wood required has a constant rate of change, but the amount of glass does not.
How to obtain the rate of change of the functions?The rate of change of a function is obtained as the change in the output of the function divided by the change in the input of the function.
For the wood function, we have that when x is increased by one, the output of the function W(x) is increased by 10, hence the rate of change is constant.
For the glass function, we have that:
When x increases by one from 2 to 3, the output G(x) increases by 21.When x increases by one from 3 to 4, the output G(x) increases by 33.Hence the rate of change is not constant, and then the second statement is the correct statement.
Missing InformationThe table is given by the image shown at the end of the answer.
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Which expressions are equivalent to 7x7x7x7x7x7?
Choose 2 answers:
A: 7^8/7^2
B: 7^6x 7^1
C: (7^2)^3
D: 7^12/7^2
Answer:
B & D
Step-by-step explanation:
You can use PEMDAS (exponets go first)
7x7x7x7x7x7=7^6 times 7=7^1
42
7^12=7x7x7x7x7x7x7=13841287201 divided by 7x7=49
13841287201/49=282475249
What is the difference between 6^ and ^ 6 ?
Mr. Hollins determines that he gives away $800 each month. If he gives away 16% of his budget, how much is his overall budget?
Answer:
$5000
Step-by-step explanation:
800/16=50
50*100=5000
Write the slope-intercept form of an equation of the line that passes through the given point and is perpendicular to the graph of the equation.
(−6,4), 3y=2x−3
Write an informal proof to show triangles ABC and DEF are similar. Please don’t answer if you don’t know!!
Answer:
ΔABC ~ ΔDEF
Step-by-step explanation:
If the given triangles ΔABC and ΔDEF are similar,
Their corresponding sides will be proportional.
\(\frac{\text{AB}}{\text{DE}}=\frac{\text{BC}}{\text{EF}}=\frac{\text{AC}}{\text{DF}}\)
By substituting the measures of the given sides,
\(\frac{4}{2}=\frac{6}{3}=\frac{2}{1}\)
2 = 2 = 2
Since, corresponding sides of both the triangles are proportional, both the triangles will be similar.
ΔABC ~ ΔDEF
PLEASE HELP!
NO LINKS!
I only need help on letter d!!
15. Darius has a cylindrical can that is completely full of sparkling water. He also has an empty cone-shaped paper cup. The height and radius of the can and cup are shown. Darius pours sparkling water from the can into the paper cup until it is completely full. Approximately, how many centimeters high is the sparkling water left in the can?
9.2 b. 9.9 c.8.4 d. 8.6
The height of water left in the cylindrical can is 9.9 cm.
How to find the height of the water left in the can?Darius pours sparkling water from the can into the paper cup until it is completely full.
Therefore, the height of the water in the can can be calculated as follows:
volume of water in the cylindrical can = πr²h
volume of water in the cylindrical can = 4.6² × 13.5π
volume of water in the cylindrical can = 285.66π cm³
volume of the water the cone shaped paper can take = 1 / 3 πr²h
volume of the water the cone shaped paper can take = 1 / 3 × 5.1² × 8.7 × π
volume of the water the cone shaped paper can take = 75.429π
Therefore,
amount of water remaining in the cylindrical can = 285.66π - 75.429π = 210.231π
Therefore, let's find the height of the water as follows:
210.231π = πr²h
r²h = 210.231
h = 210.231 / 21.16
h = 9.93530245747
h = 9.9 cm
Therefore,
height of the water in the can = 9.9 cm
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Find the solution of the given initial value problem. where 8(1) +2y-g(r), y(0)-8,y (0) - 2 #≤1<2n - 16 0, 0≤1<1>2m ©
y(t) = u,h(t – a) – U2zh(t – 2n)
where h(t) = - ( (e cost + e ¹sint) (e cost 2
y(t) = unh(tr)- u₂h(t - 2n) + 8e cost + 10e sint 1
where h(t) = - -(e-¹cost cost + e-'sint)
y(t) U2h(t - π)-u,h(t - 2n) + 8e 'cost + 10e 'sint 1 1
where h(t) = www (e-¹cost 'cost + e-'sint) 2
y(t) = uh(t) - u2h(t) + 8e 'cost + 10e sint 1
where h(t) = (e-'cost + e-'sint) -(e-¹cost 2
y(t) = uh(t)- u₂h(t - 2n) + 8e 'cost + 10e sint
where h(t) = -(e-'cost + e-¹sint)
Therefore, The solution of the given initial value problem is;y(t) = 5.9334h(t) - 2.0666h(t - 2π) + 8e'cost + 10e'sint.
The given initial value problem is;
8(1) +2y-g(r), y(0)-8,
y (0) - 2 #≤1<2n - 16 0,
0≤1<1>2m y(t) = unh(tr)- u₂h(t - 2n) + 8e cost + 10e sint 1
where
h(t) = - -(e-¹cost cost + e-'sint)
The given initial value problem is solved as follows:The equation in the given initial value problem is;
y(t) = unh(tr)- u₂h(t - 2n) + 8e cost + 10e sint
where
h(t) = - -(e-¹cost cost + e-'sint)
The corresponding characteristic equation is obtained as;
r = u1(u - h(π)) - u2(u - h(2π))
Therefore;
r = u1(1 - e-ir) - u2(1 - e-2ir)
r = u1 - u1e-ir - u2 + u2e-2iru1 - u2
= r(1 - e-ir) + u2(1 - e-2ir)
Since; y(0) = 8, we can solve for u1 and u2 using the given equation.The values of u1 and u2 are obtained as;
u1 = 5.9334 and u2 = 2.0666
The solution to the initial value problem is thus;
y(t) = 5.9334h(t) - 2.0666h(t - 2π) + 8e'cost + 10e'sint
Therefore, The solution of the given initial value problem is;y(t) = 5.9334h(t) - 2.0666h(t - 2π) + 8e'cost + 10e'sint.
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you can change the contents of a stringbuilder object, but you cannot change the contents of a string object. question 2 options: True or False
The required Answer that will help in the selection of the correct option from the given statement is True.
A string builder is considered a class in JAVA API where it provides the mutual sequence of characteristics. It is used for the requirement of dynamic string manipulation. Using it to form new characters in an existing string.
In comparison with string, the following points help in differentiating the ability, function, and purpose of their creation,
The string is immutable that cannot be changed after its creation.Any modification that takes place eventually creates a new set of strings, hence leaving the original or parent string unchanged. Unlike string builder, string can't be modified after it is been created.To learn more about string builder,
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What is9.52 rounded to the nearest tenth
Answer:
9.5
Step-by-step explanation:
Note the place values:
9 ones place value
.
5 tenths place value
2 hundredths place value.
You are solving for the nearest tenths. To solve, look at the place value directly next (the hundredths place value). If the value of the number is 5 or greater, round up. If it is 4 or less round down.
In this case, it is 2, so you will round down.
9.52 rounded to the nearest tenths is 9.5
~
Answer:
9.5
Step-by-step explanation:
I used Rounding Numbers calculator on calculator soup.
what is the domain of the function shown in the graph below?
The domain of the function shown in the graph above include the following: D. {x|x ≥ -4}.
What is a domain?In Mathematics, a domain can be defined as the set of all real numbers for which a particular function is defined.
In Mathematics, the horizontal extent of any graph of a function represents all domain values and they are read and written from smaller to larger numerical values, and from the left of a graph to the right.
By using set builder notation, the domain of this function shown in the graph above can be written as follows;
Domain = {-4, ∞}
Domain = {x|x ≥ -4}
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what is equivalent to the expression7(3+4i)