Answer:
Anything that isn't in the sky like a book or a chicken
Explanation:
11 What was the main difference between the House of Burgesses
and the Mayflower Compact?
Following Greek customs of direct democracy and majority rule when passing legislation, the Mayflower Compact of 1620 served as the Massachusetts colony's constitution. The House of Burgesses had an impact on the founding fathers' decision to create a representative form of government where members gathered to discuss topics, adopt laws, and pass taxes.
What did the Mayflower Compact and the House of Burgesses have in common?To help organise and rule the populace, they all passed laws.
What are the Mayflower Compact's two main significances?Because the Mayflower Compact was the first document to establish self-government in the New World, it was significant. Up until Plymouth Colony joined Massachusetts Bay Colony in 1691, it was still in operation.
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Show your work: zero credit for this question. pieces and the lengths are 49.19 cm and 49.93 cm. What is the total Taguchi quality cost of these two pieces of metal? a) The Taguchi parameter T is $/cm^2
(round your response to two decimal places). b) The Taguchi Quality Cost of the second metal rod is $ (round your response to two decimal places). c) The Taguchi Quality Cost of the first metal rod is $ (round your response to two decimal places). d) What is the total Taguchi Quality Cost of that sample of two units? \$ (round your response to two decimal places).
To calculate the Taguchi quality cost, we need to multiply the length of each piece by the Taguchi parameter T, and then sum up the costs.
Given:
Length of the first metal rod = 49.19 cm
Length of the second metal rod = 49.93 cm
a) Taguchi parameter T:
Since we don't have the specific value of T, we cannot calculate it.
b) Taguchi Quality Cost of the second metal rod:
Taguchi Quality Cost = Length of the second metal rod * Taguchi parameter T
c) Taguchi Quality Cost of the first metal rod:
Taguchi Quality Cost = Length of the first metal rod * Taguchi parameter T
d) Total Taguchi Quality Cost of the two units:
Total Taguchi Quality Cost = Taguchi Quality Cost of the first metal rod + Taguchi Quality Cost of the second metal rod
Since we don't have the Taguchi parameter T, we cannot calculate the specific values for parts (b), (c), and (d).
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which is the best example of an unbalanced force?
A)A book resting on a shelf
b)A train accelerating from the station.
c) A chair sitting motionless
d) a car driving at a constant speed.
plz answer correctly!!!!!
Earthquakes at fault lines in Earth's crust create seismic waves, which are longitudinal (P-waves) or transverse (S-waves). The P-waves have a speed of about 5 km/s. Estimate the average bulk modulus of Earth's crust given that the density of rock is about 2,900 kg/m3
The bulk modulus is a measure of the resistance of a material to compression and is an important parameter for understanding the behavior of seismic waves in the Earth's crust during earthquakes.
The speed of longitudinal waves (P-waves) in a solid is given by:
v = √(K/ρ)
where v is the velocity of the wave, K is the bulk modulus, and ρ is the density of the medium.
Rearranging the above equation, we get:
K = ρ * v^2
Substituting the given values, we get:
K = 2,900 kg/m^3 * (5,000 m/s)^2
K ≈ 7.25 x 10^10 N/m^2
Therefore, the average bulk modulus of Earth's crust is approximately 7.25 x 10^10 N/m^2. This value is consistent with the bulk moduli of various types of rocks that make up the Earth's crust, which typically range from 5 x 10^9 N/m^2 to 100 x 10^9 N/m^2.
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Consider an object launched upward against the force of
gravity. What is the velocity of the object at the moment it
reaches its the maximum height?
Answer:
Zero
Explanation:
When it reaches max height, it stops and begins to fall back down....at this point the velocity = 0
The mass of the earth is 6x10^24 kg and that of the moon is 7.4x10^22 kg. If the radius of the moon is 1740 km, then find the value of g if the earth is compressed into the size of moon.
Answer:
In the surface of the moon, gravitational acceleration is 1.63 m/s*2.
Explanation:
An object of mass M will accelerate gravitationally at a distance R if it is at the following distance:
g = G*M/R^2
Where the gravitational constant is G.
G = 6.67*10^(-11) m^3/(kg*s^2)
At the surface of a moon, the distance between its surface and its center will be equal to its radius, since a moon's mass is concentrated at its center, thus:
R = 1740 km
It's important to remember that we need meters in order to work:
1 km = 1000 m
so:
1740 km = (1740)*1000 m = 1740000 m
R = 1740000 m
Basically, the mass consists of:
M = 7.4x10^22 kg
Incorporating all that into the gravitational acceleration equation, we get:
g = (6.67*10^(-11) m^3 / (kg*s^2))*(7.4x10^22 kg) / ( 1740000 m)^2
g = 1.63 m / s^2
In the surface of the moon, gravitational acceleration is 1.63 m / s*2.
If an astronaut has a mass of 16 Kg on Earth, what would be his mass on the moon and on the space station
Answer:
The astronaut's mass is 16 kg.
Explanation:
Mass can be defined as a measure of the amount of matter an object or a body comprises of. The standard unit of measurement of the mass of an object or a body is kilograms.
Irrespective of the location of an object or a body at a given moment in time, the mass (amount of matter that they're made up of) is constant. This ultimately implies that, whether you're in the moon, space, earth or any other place, your mass remains the same (constant).
Therefore, if an astronaut has a mass of 16 Kg on Earth, his mass on the moon and on the space station would remain the same, as his original mass of 16 Kg because mass is indestructible.
A ball in a simple pendulum is tied to a string and pulled up to the side 15 cm above its lowest position and then starts with an initial speed of 0.5 m/s. What will be its speed when it reaches the bottom? (2.5 point)
Answer:
1.786m/sExplanation:
We are given the following the following
Initial speed u = 0.5m/s
initial distance S1 = 15cm = 0.15m
Final distance = 0m
Required
Final speed v
Using the equation of motion;
v² = u²+2gS
v² = 0.5²+2(9.8)(0.15)
v² = 0.25+2.94
v² = 3.19
v = √3.19
v = 1.786m/s
Hence its speed when it reaches the bottom is 1.786m/s
Books in a library were counted one by one. There were a total of 57000 books in the library. How many significant digits are there in the result? Will the result change if the books are measured in the paacket of 10?
The total number of significant digits in the given number is five. If the books are measured in packets of 10, the number of significant digits reduces to two.
The given data is: Total number of books in the library = 57,000. We are to determine how many significant digits are there in the result? For this, let us define what are significant digits: Digits that are used to communicate meaning or accuracy of measurements are known as significant digits. In other words, the digits that carry meaning contributing to its measurement uncertainty are called significant digits. It is used to determine the accuracy of the results. In this question, the total number of books in the library is given as 57,000. As there are five non-zero digits in the given number, there are five significant digits in the result. Will the result change if the books are measured in the packet of 10? If the number of books is measured in the packet of 10, then there will be a change in the number of significant digits. When we express 57,000 in the packet of 10, we get: 57,000 = 5.7 × 10^4. Now, there are only two significant digits in the result (5 and 7), and hence the result changes.
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A charge gains 2.77 J of energy when it moves between the terminals of a battery with a potential difference of 9.00 V What is the amount of the charge? (Unit = C)
Answer: 0.308
Explanation:
acellus
A 5kg box rests on a table. a 3 kg box rests on top of the 5 kg box. what is the normal force from the table?
a. 19.6 n
b. 29.4 n
c. 49 n
d. 78.4 n
==> The total mass resting on the table is (5 kg + 3 kg) = 8 kg.
==> The total weight of that mass is (8 kg) x (9.8 m/s) = 78.4 newtons
==> The boxes are stacked. So the table doesn't know if the weight on it is coming from one box, 2 boxes, 3 boxes, or 100 boxes in a stack. The table only knows that there is a downward force of 78.4 newtons on it.
==> The table stands in a Physics classroom, and it soaks up everything it hears there. It knows that every action produces an equal and opposite reaction, and that forces always occur in pairs.
Ever since the day it was only a pile of lumber out behind the hardware store in the rain, the table has known that in order to maintain the good reputation of tables all over the world, it must resist the weight of anything placed upon it with an identical upward force. This is the normal thing for all good tables to do, up to the ultimate structural limit of their materials and construction, and it is known as the "normal force".
So the table in your question provides a normal force of 78.4 newtons. (d)
I am having a bit of difficulty with this lab question:
_________________________________________
The passage of an occluded front may be accompanied by widespread precipitation and little temperature change at ground level. This is because occluded fronts are a combination of (1). [one / two / three] cold/cool air mass(es), which shifts a (2). [cold / warm / hot] air mass (3). [aloft / sideways / downwards].
_________________________________________
Currently, I have my answers as follows:
1. two cool/cold air masses
2. warm
3. downwards
Could someone help me out and let me know if I am correct? Thanks!
This is due to the fact that occluded fronts combine two cold air masses, which causes one of the cold air masses to go downward.
When a warm air mass is sandwiched between two cold air masses, an occluded front occurs. In an occlusion, the warm front passes over the cold front, which dives beneath it.
In a front is obscured, the warm front is fully supplanted by the cold front, in which the warm air masses have completely disappeared. Furthermore, there are frequent shifts in the various weather producing circumstances because of the cold front's relatively low temperature.
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The rigid beam is supported by the three suspender bars. bars ab and ef are made of aluminum and bar cd is made of steel. if each bar has a cross-sectional area of 450 mm2, determine the maximum value of p if the allowable stress is (σallow)st = 200 mpa for the steel and ( σallow)al = 150 mpa for the aluminum. est = 200 gpa and eal = 70 gpa.
Answer:
Pmax = 67.5 KN
Explanation:
We need to calculate the maximum allowable value of P for both aluminum and steel bars.
FOR STEEL BARS:
Since,
(σallow)st = (Pmax)st/A
where,
(σallow)st = maximum allowable stress of steel bar = 200 MPa = 2 x 10⁸ Pa
A = Cross-sectional area of steel bar = 450 mm² = 0.45 x 10⁻³ m²
(Pmax)st = Maximum allowable force for steel bar = ?
Therefore,
2 x 10⁸ Pa = (Pmax)st/0.45 x 10⁻³ m²
(Pmax)st = (2 x 10⁸ Pa)(0.45 x 10⁻³ m²)
(Pmax)st = 9 x 10⁴ N = 90 KN
FOR Aluminum BARS:
Since,
(σallow)al = (Pmax)al/A
where,
(σallow)al = maximum allowable stress of Al bar = 150 MPa = 1.5 x 10⁸ Pa
A = Cross-sectional area of Aluminum bar = 450 mm² = 0.45 x 10⁻³ m²
(Pmax)al = Maximum allowable force for Aluminum bar = ?
Therefore,
1.5 x 10⁸ Pa = (Pmax)al/0.45 x 10⁻³ m²
(Pmax)al = (1.5 x 10⁸ Pa)(0.45 x 10⁻³ m²)
(Pmax)al = 6.75 x 10⁴ N = 67.5 KN
Since,
(Pmax)al < (Pmax)st
Therefore,
The maximum allowable force will be:
Pmax = (Pmax)al
Pmax = 67.5 KN
At 10°C, the gas in a cylinder has a volume of 0.250 L. The gas is allowed to expand to 0.285 L.
What must the final temperature be for the pressure to remain constant? (Hint °C + 273 = K.)
282 K
284 K
323 K
248 K
A type of electromagnetic radiation that has a higher frequency than visible light is Question 15 options: ultraviolet infrared radiowaves microwaves two of the above
Ultraviolet rays are Electromagnetic waves that have higher frequencies than visible light, so they carry more energy.
What are Ultraviolet rays?Johann Wilhelm Ritter, a German physicist, first noticed that paper soaked in silver chloride browned more quickly when exposed to Ultraviolet rays than when it was exposed to violet light itself in 1801.For the most part, humans cannot see ultraviolet rays. The cornea filters out shorter wavelengths, while the lens of the human eye primarily inhibits radiation in the 300–400 nm range. Additionally, UV color receptor adaptations are not present in humans. The retina's photoreceptors are sensitive to near-UV, though, and those without lenses (a condition known as aphakia) see near-UV as whitish-blue or whitish-violet.The body produces vitamin D, which is necessary for life when exposed to UV light, more especially UVB. UV rays are necessary for humans to maintain proper vitamin levels.To learn more about Electromagnetic waves refer to:
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An outfielder throws a baseball to the second baseman at a speed of 19.6 m/s and and angle of 60 degrees above the horizontal. If the ball is caught at the same height from which it was thrown, calculate the amount of time the ball was in the air
Please help if possible!! Much love <3
Newton's 2nd law of motion says:
Net force = (mass) · (acceleration) .
Newton didn't make up this law for his health.
Let's use it to answer this question about the car moving down the road.
Net force on the car = (car's mass) · (car's acceleration).
But the net force on the car is zero. So we can write:
0 = (car's mass) · (car's acceleration).
Look at the right side of this equation.
Newton's law tells us that the product of the car's mass and the car's acceleration is zero.
That tells us that at least one of three things must be true.
Either 1). the car's mass is zero, or 2). the car's acceleration is zero, or 3). Newton was crazy.
We're pretty sure that 1). and 3). are false. The car's acceleration is zero.
What does this mean ? It means that the car's speed and direction are not changing.
That's exactly what Choice-B says.
why does time = 2h/g?
h = height
g = gravitational acceleration
Answer:
Explanation:
I assume you meant to type t = √2h/g and you're referring to an object in free fall: If so, here's my answer:
x = x₀ + v₀t + 1/2at²
for an object in free fall x - x₀ = h (height the object falls)
v₀ = 0 (if the object starts at rest)
a = g
Therefore,
h = 1/2gt²
t² = 2h/g
t = √2h/g
how much does the angle of refraction change from 380nm to 700nm when the incident angle is 80?
Answer:
35 degrees
Explanation:
The incident angle, an 80-degree angle, and as the angle of incidence increases, the amount of refraction also increases. So, we can expect a significant change in the angle of refraction from blue to red light at an 80-degree angle of incidence.
What is refraction?Refraction refers to the bending of light when it passes from different mediums.The amount of refraction that occurs at an interface between two materials depends on the wavelength of light, the angle of incidence, and the properties of the materials. The relationship between these factors is described by Snell's law:
n1 sinθ1 = n2 sinθ2
where n1 and n2 are the refractive indices of the two materials, θ1 is the angle of incidence, and θ2 is the angle of refraction.
For a given angle of incidence, the amount of refraction that occurs is greater for shorter wavelengths (i.e., blue light) than for longer wavelengths (i.e., red light). This effect is known as dispersion, and it is why we see rainbows when sunlight is refracted through water droplets.
In the absence of any information about the properties of the materials involved, we can assume that the amount of refraction will increase as the wavelength decreases.
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how is earth a sphere?
Which feature of the diagram is an example of chart junk? A graph with the title computer ownership 1998 to 2002. The horizontal x axis has the title year and the years 1998, 2000 and 2002. The vertical y axis has the title households in millions, a range of 0 to 70 and increments at 10. Each increment has a horizontal gridline. The legend at the bottom shows a gray block with the text presence of computer and a black square represents internet access. On the graph, the values for the black square are connected by a line. A table is beneath the graph. Both the table and the graph shows the value for internet access and presence of a computer as follows. Year, presence of computer, internet access. 1998, 42M, 26M. 2000, 51M, 42M. 2002, 62 M 55 M. the presence of a title the table showing the numerical values of the data plotted having two sets of data in the same graph the labels along the axes of the graph
The chartjunk allows you to find unnecessary elements in the chart,
lines on the horizontal gridvalues in numerous at each pointUnderstanding the exercise is easier with a graph. See attached
The graphical representation of a set of values saves a lot of time in the data analyst, it is called chartjunk to all the unnecessary elements in a graph that do not help to understand the information represented or that are a distraction for the observer.
In the case presented we have a scatter plot with the x-axis the year of the computer and on the y-axis the number of units in millions, the graph shows two data sets the number of computers and the number of them with access to the internet depending on the year.
The lines in the horizontal grids are excessive represents chartjunk, since it does not help to understand the relationship between the data presented
Computer symbols are shown in the legend and the data to be plotted, this is important information, but in the graph at each point the values are shown in a distracting element since it is in the table and is unnecessary, therefore it's a chartjunk
A missing piece of data in the graph is a connecting line between the total number of computers.
The chartjunk allows you to find unnecessary elements in the chart,
lines on the horizontal gridvalues in numerous at each point
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Susan makes the following entry in her notebook: “On Friday we were given a blue liquid in a shallow container. We placed it on the windowsill over the weekend. On Monday morning, there was no liquid left, but the dish had some solid blue stuff in it.”
a. Was the blue liquid in the dish a heterogenous mixture, a solution, or a pure substance? Explain your choice.
b. Write a few sentences about what you think happened in the dish.
Answer:
Explanation:
a. From the information provided in the question, the blue liquid is a solution. This is because a solution is a type of homogeneous mixture (that has an evenly distributed solute in a solvent) which is the reason the liquid was said to be blue (and not immiscible blue solid in a liquid) but after been exposed to heat became just a blue solid. Typically, a solution has a solute and a solvent (combined), the solute here is the blue solid while the solvent is the liquid that made the combination a liquid.
b. Since the dish containing the liquid was placed on a windowsill, it can be assumed that the dish was subjected to heat from the sun which caused the liquid (in the solution) to evaporate after exposure to the heat from the sun (over the weekend) leaving the blue solid solute (of the solution) to remain in the dish. This can be referred to as evaporation to dryness in separation techniques (if the goal was to intentionally separate the solid solute from the liquid solvent).
Four identical springs each have the same spring constant k. If these four springs are attached end to end forming a spring four times the length of one of the original springs, what will be the spring constant of the combination?.
The arrangement of the springs is in series if they are connected end to end. The forces for a sequence of springs are additive.
F1 = k1(x1) for spring 1.
F2 = k2(x2) in spring 2.
F3 = k3(x3) in spring 1.
Total Force is k1(x1)+k2(x2)+k3(x3).
Total Force is equal to (k1+k2+k3)(x,total).
The overall force acting on it is calculated by multiplying the whole length of elongation by the sum of the spring constants.
What use do springs serve?A spring is an elastic object that can store mechanical energy and release it in response to the removal of an opposing force. Springs may be the solution if you need to exert force in order to move something or keep it still without the use of an engine or other powered device.
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i really need help please just answer at least one
Answer:
9) a = 25 [m/s^2], t = 4 [s]
10) a = 0.0875 [m/s^2], t = 34.3 [s]
11) t = 32 [s]
Explanation:
To solve this problem we must use kinematics equations. In this way we have:
9)
a)
\(v_{f}^{2} = v_{i}^{2}-(2*a*x)\\\)
where:
Vf = final velocity = 0
Vi = initial velocity = 100 [m/s]
a = acceleration [m/s^2]
x = distance = 200 [m]
Note: the final speed is zero, as the car stops completely when it stops. The negative sign of the equation means that the car loses speed or slows down as it stops.
0 = (100)^2 - (2*a*200)
a = 25 [m/s^2]
b)
Now using the following equation:
\(v_{f} =v_{i} - (a*t)\)
0 = 100 - (25*t)
t = 4 [s]
10)
a)
To solve this problem we must use kinematics equations. In this way we have:
\(v_{f} ^{2} = v_{i} ^{2} + 2*a*(x-x_{o})\)
Note: The positive sign of the equation means that the car increases his speed.
5^2 = 2^2 + 2*a*(125 - 5)
25 - 4 = 2*a* (120)
a = 0.0875 [m/s^2]
b)
Now using the following equation:
\(v_{f}= v_{i}+a*t\\\)
5 = 2 + 0.0875*t
3 = 0.0875*t
t = 34.3 [s]
11)
To solve this problem we must use kinematics equations. In this way we have:
\(v_{f} ^{2} = v_{i} ^{2} + 2*a*(x-x_{o})\)
10^2 = 2^2 + 2*a*(200 - 10)
100 - 4 = 2*a* (190)
a = 0.25 [m/s^2]
Now using the following equation:
\(v_{f}= v_{i}+a*t\\\)
10 = 2 + 0.25*t
8 = 0.25*t
t = 32 [s]
A 100 MVA, 24kV,110% three-phase synchronous generator carries the rated load at a power factor of 0.75 (lagging). Calculate the necessary excitation voltage and input complex power.
The necessary excitation voltage is \(1.314 kV\)and the input complex power is\(75,000 kW + 66,792 kVAR\) (lagging).
Convert the apparent power from MVA to kVA. Since 1 MVA = 1000 kVA, the rated apparent power is 100 MVA × 1000 kVA/MVA = 100,000 kVA.
Calculate the rated complex power using the formula P = S × power factor, where P is the active power and S is the apparent power. In this case, P = 100,000 kVA × 0.75 (lagging)
= 75,000 kW.
Calculate the rated reactive power using the formula \(Q = S × sin(θ),\) where Q is the reactive power and θ is the angle of the power factor. In this case, \(Q = 100,000 kVA × sin(acos(0.75))\)
\(= 66,792 kVAR\).
Calculate the necessary excitation voltage using the formula\(Vex = sqrt(P^2 + Q^2) / (S × power factor)\), where Vex is the excitation voltage. In this case,
\(Vex = sqrt((75,000 kW)^2 + (66,792 kVAR)^2) / (100,000 kVA × 0.75)\)
= 1.314 kV.
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A drag racer accelerates uniformly over a course 400m long. Determine the car's acceleration if it reaches a top speed of 120 m/s. Assume that the car starts from rest.
According to thrid equation of kinematicsthird equation of kinematics
\(\\ \rm\hookrightarrow v^2-u^2=2as\)
Isolate the equation for a
\(\\ \rm\hookrightarrow a=\dfrac{v^2-u^2}{2s}\)
\(\\ \rm\hookrightarrow a=\dfrac{120^2-0^2}{2(400)}\)
\(\\ \rm\hookrightarrow a=120^2/800\)
\(\\ \rm\hookrightarrow a=16m/s^2\)
Derive the wave equation describing the vibrations of a drum, more precisely, an elastic membrane.
The wave equation that describes the vibrations of a drum, specifically an elastic membrane, is given by the equation:
frac{partial^2y}{partial t^2} = c^2 left( frac{ partial^2y}{partial x^2} + frac{ partial^2y}{partial y^2}right) where y represents the displacement of the membrane, t represents time, and c represents the wave speed.For the derivation, we start by considering the forces acting on a small section of the membrane. These forces include the tension force in the membrane and the pressure difference above and below the membrane due to sound waves.
To simplify the derivation, we make some assumptions about the membrane:
It is thinIt is stretched tightly across a circular frameThe displacement is small compared to the radius of the frameWith these assumptions, we can describe the motion of the membrane as follows We assume that the displacement varies only in the and directions, and not in the direction.This means that the displacement can be written as y(x,y,t).We apply Newton's second law to a small section of the membrane. The tension force in the membrane is proportional to the displacement and is given by T\frac partial^2y partial x^2. The pressure difference above and below the membrane is proportional to the displacement and is given by rho h frac partial^2y partial t^2 , where rho is the density of air and h is the distance between the membrane and the nearest air boundary (either above or below).Since the forces acting on the membrane are in equilibrium, we can set the sum of these forces equal to zero:
T frac partial^2y partial x^2 = -rho h frac partial^2y partial t^2 Solving for frac partial^2y partial t^2 and substituting in the wave speed c = sqrt frac Trho h, we get the wave equation:frac partial^2ypartial t^2 = c^2 left frac partial^2y partial x^2 + frac{partial^2y}{partial y^2}right).About VibrationsVibrations is motion that occurs back and forth around equilibrium. The condition for the occurrence of vibration is that an object experiences a state of rest if it does not receive a force of motion. In addition, the farthest distance that occurs back and forth due to vibration is always the same when measured from the center point. Examples of vibrations in everyday life are numerous, such as vibrations when we move guitar strings, vibrations due to earthquakes and so on.
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once ejected, how long does it take the electrons with maximum kinetic energy to travel 2.34 cm to a detection device, in seconds? you may assume these electrons travel in a collisionless manner.
It takes approximately 3.95 x 10⁻¹⁰ seconds for the electrons with maximum kinetic energy to travel 2.34 cm to a detection device.
To determine the time it takes for the electrons with maximum kinetic energy to travel 2.34 cm to a detection device, we need to use the equation:
time = distance / velocity
The velocity of the electrons can be calculated using the equation for kinetic energy:
KE = 0.5mv²
where KE is the kinetic energy, m is the mass of the electron, and v is the velocity.
Since we are assuming that the electrons are traveling in a collisionless manner, we can assume that they are traveling at a constant velocity.
Therefore, we can use the maximum kinetic energy of the electrons to calculate their velocity.
The maximum kinetic energy of the electrons is given by:
KE = eV
where e is the charge of an electron and V is the voltage applied to the electron gun.
Assuming a voltage of 10 kV, the maximum kinetic energy of the electrons is:
KE = (1.6 x 10⁻¹⁹ C) x (10,000 V) = 1.6 x 10⁻¹⁵ J
Using this value for KE and the mass of an electron (9.11 x 10⁻³¹ kg), we can calculate the velocity of the electrons:
1.6 x 10⁻¹⁵ J = 0.5 x (9.11 x 10⁻³¹ kg) x v²
v = 5.93 x 10⁷ m/s
Now we can calculate the time it takes for the electrons to travel 2.34 cm:
time = 0.0234 m / 5.93 x 10⁷ m/s = 3.95 x 10⁻¹⁰ s
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What happens when waves slow down and change direction?
Answer:
Refraction
Explanation:
Refraction is the change in direction of a wave as it slows down. ... Tsunamis also refract around land masses
two disks of identical mass but different radii (r and 2 r) are spinning on frictionless bearings at the same angular speed ω0 but in opposite directions. the two disks are brought slowly together. the resulting frictional force
When two disks of identical mass but different radii are brought slowly together while spinning on frictionless bearings at the same angular speed but in opposite directions, the resulting frictional force increases due to the increase in angular velocity caused by the change in moment of inertia of the system.
Angular momentum is given by the equation L = Iω, where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity. The moment of inertia of a rotating object depends on its mass and how that mass is distributed around its axis of rotation.
In this scenario, the disks have the same mass but different radii. The moment of inertia of a disk is given by the equation I = (1/2)mr^2, where m is the mass and r is the radius. Since the disks have the same mass, their moments of inertia will be proportional to their radii squared.
Since the disks are rotating in opposite directions, the change in angular momentum due to their interaction will be the sum of their individual angular momenta. The change in angular momentum is given by ΔL = Lfinal - Linitial.
As the disks are brought closer, their moments of inertia decrease. Therefore, in order to conserve angular momentum, the angular velocity ω will increase. This increase in angular velocity results in an increase in frictional force between the disks.
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