What do you call the set of numbers that
includes the whole numbers, their opposites and
zero?
Imaginary Numbers
Negatives
Integers
Positives

Answer: d=6m

Step-by-step explanation:

d=6m

r Radius

3

m

d

r

r

r

d

d

C

A

Solution

d=2r=2·3=6m

Answer:

D=6m

r=3

solution just in case you need it d=2 r = 2▪︎3=6m

Answer:I’m pretty sure it’s c

Answer: 39

Step-by-step explanation:

i = 1  iv = 4  ix = 9  xxi = 21

Answer:

16.8

Step-by-step explanation:

just took it on USA test-prep

Answer:

c

Step-by-step explanation:

Answer:

a

Step-by-step explanation:

The required GCF is 8.

The greatest common factor is that greatest number from the factors which divides the number completely.

For example take numbers 12 and 16.

The factors of 12 are 2×2×3.

And the factors of 16 are 2×2×2×2.

We can clearly see that the common factors are 2×2 which gives 4. So, 4 is the greatest common factor which divides both 12 and 16.

Here it is given to find the greatest common factor of 16 and 40.

Factors of 16 = 2×2×2×2

Factors of 40 = 2×2×2×5

We can see clearly the common factors are 2×2×2 which gives 8.

So, 8 is the greatest common factor.

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Answer:

I guess it is 45°

Step-by-step explanation:

Hope it helps!!!!

Answer:

45°

Step-by-step explanation:

the sum of the exterior angles of a polygon is 360°

a regular octagon has 8 equal exterior angles , then

exterior angle = 360° ÷ 8 = 45°

Answer:

3

Step-by-step explanation:

Answer:

Life without you is like a broken pencil…..pointless.

Step-by-step explanation:

Answer:

400

Step-by-step explanation:

Volume=⅓*B*h

B=10×10=100

Bh=100×12=1200

then divide by

1200÷3=4

The volume of a pyramid with a square base is 400 cm³.

A pyramid is a structure where outer surfaces are triangular and converge to a point at the top.

The volume of a pyramid with a square base is given as:

Volume = 1/3 x base area x height

We have,

The volume of a pyramid with a square base is given as:

Volume = 1/3 x base area x height

Now,

Height = 12 cm

Base area = 10² = 100 cm²

Now,

Volume.

= 1/3 x 100 x 12

= 400 cm³

Thus,

The volume of a pyramid with a square base is 400 cm³.

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The center of a dilation is a fixed point in the plane about which all points are expanded or contractedAnswer:

Step-by-step explanation:

We have two right-angled triangles that share a common side, with side lengths 6 and 10. Let's label the sides of the triangles as follows:

Triangle 1:

Side adjacent to the right angle: 6 (let's call it 'a')

Side opposite to the right angle: x (let's call it 'b')

Triangle 2:

Side adjacent to the right angle: x (let's call it 'c')

Side opposite to the right angle: 10 (let's call it 'd')

Using the Pythagorean theorem, we can write the following equations for each triangle:

Triangle 1:\(a^2 + b^2 = 6^2\)

Triangle 2: \(c^2 + d^2 = 10^2\)

Since the triangles share a common side, we know that b = c. Therefore, we can rewrite the equations as:

\(a^2 + b^2 = 6^2\\b^2 + d^2 = 10^2\)

Substituting b = c, we get:

\(a^2 + c^2 = 6^2\\c^2 + d^2 = 10^2\)

Now, let's add these two equations together:

\(a^2 + c^2 + c^2 + d^2 = 6^2 + 10^2\\a^2 + 2c^2 + d^2 = 36 + 100\\a^2 + 2c^2 + d^2 = 136\)

Since a^2 + 2c^2 + d^2 is equal to 136, we can conclude that x (b or c) is between 11 and 12

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Answer:

Im sorry but I am not really sure myself ! I hope you find or found your answer already !

Step-by-step explanation:

Answer:

138

Step-by-step explanation:

5x+2+6x+90=180

11x+92=180

11x=88

x=8

5(8)+2. = 42

180-42= 138

Answer:

C. y = ⁶/5x + ⁷/2

Step-by-step explanation:

First, find the slope of line AB that goes through A(3, 1) and B(-3, 6):

\( slope(m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{6 - 1}{-3 - 3} = \frac{5}{-6} \).

Slope of line AB = -⅚.

The slope of the line that is a perpendicular bisector of line AB will be a negative reciprocal of the slope of line AB.

Thus:

Negative reciprocal of -⅚ = ⁶/5. (Reciprocal of ⅚, also the sign will change from positive to negative).

Next is to find the y-intercept, b, of the line.

To do this, you need to find the midpoint where the two lines intersect:

Therefore,

Midpoint (M) of AB, for A(3, 1) and B(-3, 6) is given as:

\( M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}) \)

Let \( A(3, 1) = (x_1, y_1) \)

\( B(-3, 6) = (x_2, y_2) \)

Thus:

\( M(\frac{3 +(-3)}{2}, \frac{1 + 6}{2}) \)

\( M(\frac{0}{2}, \frac{7}{2}) \)

\( M(0, \frac{7}{2}) \)

Substitute x = 0, y = ⁷/2, and m = ⁶/5 into y = mx + b and find the value of b.

⁷/2 = ⁶/5(0) + b

⁷/2 = b

b = ⁷/2

The slope (m) and the y-intercept, b, of the line we are looking for are ⁶/5 and ⁷/2, respectively.

Therefore, substitute m = ⁶/5 and b = ⁷/2 into y = mx + b.

y = ⁶/5x + ⁷/2

The equation that is the perpendicular bisector of the line AB is y = ⁶/5x + ⁷/2.

Answer:

Addition Property of Equality, or A

Step-by-step explanation:

This is the definition of addition property of equality

Answer:

0

Step-by-step explanation:

Total outcomes = 6

Favourable outcomes = 0(As there is no 7 in a dice)

Probability = Favourable Outcome/Total outcomes

=> 0/6

=> 0

The value of the iterated integral 5∫_(-5)^(5) ∫_0^(π/2) (y + y^2 cos x) dx dy is 5π^2/4 + (π^3/12) sin 5.

To calculate the iterated integral ∬_S (y + y^2 cos x) dA over the given region S, where S is the rectangle defined by -5 ≤ x ≤ 5 and 0 ≤ y ≤ π/2, we will evaluate the integral in two steps: first integrating with respect to x and then integrating with respect to y.

Let's start by integrating with respect to x:

∫_S (y + y^2 cos x) dA = ∫_0^(π/2) ∫_(-5)^5 (y + y^2 cos x) dx dy

To integrate with respect to x, we treat y as a constant and integrate the expression (y + y^2 cos x) with respect to x over the range -5 to 5:

∫_S (y + y^2 cos x) dA = ∫_0^(π/2) [(y * x + y^2 sin x)]|_(-5)^(5) dy

Now we have an expression in terms of y only. We substitute the limits of integration for x, which are -5 and 5, into the expression (y * x + y^2 sin x) and evaluate it:

∫_S (y + y^2 cos x) dA = ∫_0^(π/2) [5y + y^2 sin 5 - (-5y - y^2 sin(-5))] dy

Simplifying further:

∫_S (y + y^2 cos x) dA = ∫_0^(π/2) [10y + 2y^2 sin 5] dy

Now we integrate the expression [10y + 2y^2 sin 5] with respect to y over the range 0 to π/2:

∫_S (y + y^2 cos x) dA = [5y^2 + (2/3)y^3 sin 5] |_0^(π/2)

Evaluating the expression at the limits:

∫_S (y + y^2 cos x) dA = [5(π/2)^2 + (2/3)(π/2)^3 sin 5] - [5(0)^2 + (2/3)(0)^3 sin 5]

Simplifying:

∫_S (y + y^2 cos x) dA = [5(π^2/4) + (2/3)(π^3/8) sin 5] - [0]

Finally, we simplify the expression:

∫_S (y + y^2 cos x) dA = 5π^2/4 + (π^3/12) sin 5

Therefore, the value of the iterated integral 5∫_(-5)^(5) ∫_0^(π/2) (y + y^2 cos x) dx dy is 5π^2/4 + (π^3/12) sin 5.

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Answer:

20

Step-by-step explanation:

I did it on khan academy

Answer:

its 3

Step-by-etep explanation:

Answer:

Step-by-step explanation:

option c is correct

product of two numbers can be written as 4x

R.I.P YOUR PHONE!! I'm "learning" this in my online school- Haven't been paying attention at all to anything - SoRrY cHiLdD!

The ratios 2/3 and 5/6 are not equivalent.

To determine whether the ratios 2/3 and 5/6 are equivalent, we can simplify both ratios and compare them.

Let's simplify the first ratio, 2/3:

There are no common factors between 2 and 3, so the ratio is already in its simplified form.

Now let's simplify the second ratio, 5/6:

Both 5 and 6 have a common factor of 1, so we can't simplify the ratio further.

Comparing the simplified ratios, we have 2/3 and 5/6. To check if they are equivalent, we can cross-multiply and see if the products are equal:

2 * 6 = 12

3 * 5 = 15

Since 12 is not equal to 15, the ratios 2/3 and 5/6 are not equivalent.

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The function which could represent the price of the car after t years, with annual decay rate is given as 47000 × 0.5^(t/6).

Decay rate in financial terms is defined as the rate at the price of the product which is lost as the life of the product reduces or has passed since it was manufactured. In the given problem, the value of car in initial purchase is given as $47000. Since its value depreciates or decreases by half in every six years, so the simple product of the initial cost and the depreciation rate/decay rate will give the present value of car.

If a decay rate is to be represented in percentage then, decay rate is given as:

Decay rate = [1 - 0.5^(t/6)] × 100

Since t=1, therefore Decay rate = [1 - 0.5^(1/6)] × 100 = 6.06 %

This value represents the percentage rate of decay per year, to the nearest hundredth of a percent.

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The constant term that is necessary to complete the perfect square trinomial pictured in the algebra tile is 16.

A perfect square trinomial is an algebraic statement with three terms of the type ax²+bx+c. It is calculated by multiplying a binomial with itself.

For the given trinomial to be a perfect square trinomial, the value of the constant term should be such that the value of the term expression must be similar to (a+b)². Therefore,

\((a+b)^2=a^2+2ab+b^2\)

            \(=x^2+8x+16\)

Now, if we compare the two equations we will understand that the first term of the perfect square trinomial is x, and thus, the last term should 16.

\((x+4)^2=x^2+8x+16\)

Hence, the constant term that is necessary to complete the perfect square trinomial pictured in the algebra tile is 16.

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16 is the constant term is necessary to complete the perfect square trinomial pictured in the algebra tiles will be (x + 4).

A perfect square is a number that may be written as the product of two integers or as the integer's second exponent.

The perfect square obtained from the given equation is  (x + 4).;

On squaring we get;

\((x + 4)^2 = x^2 + 8x + 16.\)

16 is the only constant term in the equation.

Hence 16 is the constant term that is necessary to complete the perfect square.

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The method of periodization that an athlete performs is  traditional periodization method.

Given,

An athlete perform five sets of five repetitions at 90% of 1rm on the first day of the week, five sets of fourteen repetitions at 85% of 1rm on the next training day, and five sets of two repetitions at 62.5%of 1rm on the last training day of the week;

Here,

The example above, where the percentage of one-repetition maximum (1RM) decreases as the training day progresses, is essentially a traditional periodization method.

As a result, during the course of the training cycle, the athletes' completed work gradually grows. As a result, as the load increases over time, there is a corresponding decrease in volume.

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The dimensions of Sharon's mural meet the given requirements

The given parameters are:

The dimensions of Sharon's mural

Height = 6 1/4 feet

Width = 12 7/8 feet

The required dimensions of the mural

Height = At least 6.2 feet

Width = At least 12.8 feet

Start by representing the dimensions of Sharon's mural in decimals

Height = 6.25 feet

Width = 12.875 feet

By comparing the dimensions of Sharon's mural and the required dimensions of the mural, we have:

6.25 feet is at least 6.2 feet

12.875 feet is at least 12.8 feet

Hence, the dimensions of Sharon's mural meet the given requirements

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Answer:

the measure of angle sbt is 95 degrees

Step-by-step explanation:

50+35=85

180-85+95

Answer:

y = 45

Step-by-step explanation:

y = k x^2

500 = k * 10^2

500 = k*100

k = 5

y = 5*x^2

x = 3

y = 5*3^2

y = 45