Answer:
Niches
Explanation:
Sodium hypochlorite (NaOCL) solution is available with _____ available chlorine.
a.) 2 to 5%
b.) 5 to 20%
c.) 25 to 50%
d.) 50 to 70%
Sodium hypochlorite (NaOCL) solution is available with 5 to 20% available chlorine. The correct answer is option b.
Sodium hypochlorite (NaOCL) solution is a commonly used disinfectant in various industries, including healthcare, food processing, and water treatment. The available chlorine concentration in the solution is an important parameter that determines its efficacy as a disinfectant. The answer to the question is (b) 5 to 20% available chlorine.
Sodium hypochlorite solutions with lower available chlorine concentrations (2 to 5%) are typically used for household cleaning and disinfection, while solutions with higher concentrations (50 to 70%) are used for industrial applications, such as water treatment. Solutions with 5 to 20% available chlorine are commonly used for disinfection in healthcare settings, such as hospitals and clinics.
It is important to note that the concentration of sodium hypochlorite solutions can vary between different brands and products. It is crucial to follow the manufacturer's instructions for dilution and use to ensure proper disinfection and safety. Also, it is important to handle sodium hypochlorite solutions with caution, as they can be corrosive and harmful to skin and eyes.
Therefore, option b is correct.
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I got told if i got a lighter lit it and put it on my self that i should eat a cookie an watch :D should i do it :3
Balance the following: ___C + ___S → ___CS2
Answer:
1C + 2S -----> 1CS2
in order to make the reactants carbon and sulfur be equal to the product Carbon 2 Sulfur, we need to have 2 sulfurs on the left side so that both sides have 1 carbon and 2 sulfurs
(c) Describe and explain how fractional distillation can be used to separate a mixture of neon,
argon, krypton and xenon.
Answer:
in fractional distillation we look at different boiling point of the mixture
Explanation:
argon will be separated from the mixture first because it has the lowest boiling point
The mixture of elements of gases of neon,argon, krypton and xenon can be separated using fractional distillation as the have difference in their boiling points.
What is an element?
An element is defined as a substance which cannot be broken down further into any other substance. Each element is made up of its own type of atom. Due to this reason all elements are different from one another.
Elements can be classified as metals and non-metals. Metals are shiny and conduct electricity and are all solids at room temperature except mercury. Non-metals do not conduct electricity and are mostly gases at room temperature except carbon and sulfur.
The number of protons in the nucleus is the defining property of an element and is related to the atomic number.All atoms with same atomic number are atoms of same element.
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For each of the following pairs of compounds, choose which will elute faster in a TLC experiment (i. E. , which compound will have a larger Rf value). Explain what factors led to your choice. 6 pt a. Naphthalene or 1-Bromonaphthalene Choice Explanation: 1-Bromonaphthalene is more polar than Naphthalene. If polarity is higher, its Rf value will be less which means that molecule will travel less distance (lower Rf value) during a TLC experiment
In a TLC experiment, the compound with the larger Rf value will elute faster. In the case of naphthalene and 1-bromonaphthalene, the 1-bromonaphthalene will elute faster and have a larger Rf value.
This is because 1-bromonaphthalene is more polar than naphthalene. Polar compounds have a stronger attraction to the polar stationary phase (such as the silica gel in TLC plates) and will interact more with it, resulting in a lower Rf value.
Naphthalene, on the other hand, is less polar and will have a weaker interaction with the stationary phase, allowing it to travel further and have a higher Rf value.
The polarity of a compound is determined by the presence of functional groups or atoms that create an uneven distribution of charge or electronegativity. In this case, the bromine atom in 1-bromonaphthalene increases its polarity compared to naphthalene, leading to a stronger interaction with the stationary phase.
In summary, the 1-bromonaphthalene will elute faster in a TLC experiment and have a larger Rf value compared to naphthalene due to its higher polarity resulting from the presence of a bromine atom.
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The thermochemical equation shows the combustion of carbon in oxygen. How many moles of carbon, C must be burnt to produce 196.5 kJ of heat?
Given thermochemical equation; C(s) + O2(g) -> CO2(g) = -393 kJ mol ‐¹
Answer:
0.5 moles OF CARBON WILL BE BURNT SHOULD 196.5 kJ OF HEAT IS LIBERATED IN THE REACTION.
Explanation:
The standard heat of combustion of a substance is the heat evolved when one mole of the substance is burned completely in oxygen under standard conditions.
From the reaction, -393kJ of heat is required to burn 1 mole of Carbon completely in oxygen.
C(s) + O2 (g) -----> CO2(g) -393 kJ mol^-1
Should 196.5 kJ of heat was evolved by the reaction, the number of moles of carbon to be produced will be x moles;
-393 kJmol^-1 of heat was required to burn 1 mole of Carbon
196.5 kJ/mol of heat will burn x moles of carbon.
x = ( 196.5 * 1 / -393)
x = -0.5 moles
0.5 moles of carbon will be burnt when 196.5 kJ of heat is liberated
a laboratory owned by a company other than the physician’s practice is a
A laboratory owned by a company other than the physician's practice is typically referred to as an "independent laboratory" or an "external laboratory." These laboratories are separate entities from the physician's practice and may provide various diagnostic, testing, or research services. They operate independently and may serve multiple healthcare providers or organizations.
Independent laboratories play a crucial role in the healthcare industry by offering specialized testing, advanced technologies, and expertise that may not be available within a physician's practice. They often handle a wide range of laboratory services, including clinical chemistry, microbiology, pathology, genetic testing, and more.
Physicians and healthcare providers may send patient samples or specimens to independent laboratories for analysis and diagnostics. The results obtained from these laboratories can aid in accurate diagnoses, treatment decisions, and monitoring of patient health.
Overall, independent laboratories contribute to the comprehensive healthcare system by providing specialized laboratory services and collaborating with healthcare providers to deliver quality patient care.
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put the names of the planets in increasing oder based on their distance from the sun mars neptune mercury earth. saturn
Answer:
MercuryEarthMarsSaturnNeptuneAnswer:
Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune
For the reaction C + 2H2 → CH4, how many moles of carbon are needed to make 174.6 grams of methane, CH4 ?
Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0
Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:
Element
Molar Mass
Hydrogen
1
Carbon
12
Answer:
To determine the number of moles of carbon needed to make 174.6 grams of methane (CH4), we will first need to calculate the number of moles of CH4 and then use the stoichiometry of the balanced chemical equation to find the moles of carbon (C).
First, let's find the molar mass of CH4:
Molar mass of CH4 = (1 × 4) + 12 = 16 g/molNow, let's find the number of moles of CH4:moles of CH4 = 174.6 g / 16 g/mol = 10.9125 molIn the balanced chemical equation, 1 mole of carbon (C) reacts with 2 moles of hydrogen (H2) to produce 1 mole of methane (CH4). Therefore, the number of moles of carbon needed is equal to the number of moles of CH4:
moles of C = 10.9125 molRounding to the nearest tenth:
moles of C ≈ 10.9 molSo, approximately 10.9 moles of carbon are needed to make 174.6 grams of methane (CH4).
Which reaction of these potential acids and bases does not occur to any appreciable degree due to an unfavorable equilibrium?
The reaction between acetic acid and ammonia to form ammonium acetate does not occur to any appreciable degree due to an unfavorable equilibrium
There are several potential acids and bases that can react with each other, but not all reactions occur to an appreciable degree. In chemistry, the equilibrium constant is used to determine the extent to which a chemical reaction occurs. When the equilibrium constant is very small, it means that the reaction is not favorable, and the reaction will not proceed to any significant degree.
One example of a potential acid-base reaction that does not occur to any appreciable degree due to an unfavorable equilibrium is the reaction between acetic acid (CH3COOH) and ammonia (NH3) to form ammonium acetate (CH3COONH4). This reaction is reversible, and the equilibrium constant (Kc) for the forward reaction is very small, indicating that the reaction does not occur to any significant degree.
The reason for this unfavorable equilibrium is that the ammonium acetate that forms is a weak acid, and it can react with water to form the original reactants, acetic acid and ammonia. Therefore, the equilibrium between the reactants and products is shifted towards the reactants, and the reaction does not occur to any appreciable degree.
In summary, the reaction between acetic acid and ammonia to form ammonium acetate does not occur to any appreciable degree due to an unfavorable equilibrium.
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how do we solve a WEAK/STRONG acid
Answer:
Strong acids completely dissociate into their ions in water, while weak acids only partially dissociate. There are only a few (7) strong acids, so many people choose to memorize them. All the other acids are weak.
Explanation:
Weak acids. Explaining the term "weak acid" A weak acid is one which doesn't ionise fully when it is dissolved in water. Ethanoic acid is a typical weak acid. It reacts with water to produce hydroxonium ions and ethanoate ions, but the back reaction is more successful than the forward one.
A strong acid is an acid which dissociates completely in water. That is, all the acid molecules break up into ions and solvate (attach) to water molecules. Therefore, the concentration of hydronium ions in a strong acid solution is equal to the concentration of the acid.
pls mark brainiest
hope this helps
chemicals like bacterial toxins that poison cells are described as being
Chemicals like bacterial toxins that poison cells are commonly described as being toxic or poisonous. These substances have the ability to disrupt normal cellular functions and processes, leading to harmful effects on the cells and organisms they come into contact with.
Toxins can have various mechanisms of action. Some toxins interfere with essential biochemical pathways, disrupt cellular membranes, or inhibit vital enzymes, while others may directly damage DNA or disrupt cellular signaling. Regardless of their specific mode of action, toxins are designed to have a detrimental impact on cellular function and can cause a wide range of adverse effects, from mild symptoms to severe illness or even death.
The toxicity of a substance is often determined by its concentration, exposure duration, and the specific vulnerability of the target cells or organisms. Toxins produced by bacteria can be classified into exotoxins, which are secreted by bacteria and released into the surrounding environment, or endotoxins, which are part of the bacterial cell wall and are released upon cell death or lysis.
Chemicals like bacterial toxins are referred to as toxic or poisonous due to their ability to disrupt cellular function and cause harm to cells and organisms.
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2 X + 3Y ----> 4 Z
If 2.50 moles of X were reacted with Y, how many moles of Z would be produced?
5.00 moles of Z would be produced when 2.50 moles of X are reacted with Y.
From the balanced chemical equation:
2 X + 3Y → 4 Z
We can see that the molar ratio of X to Z is 2:4 or 1:2.
Therefore, if 2.50 moles of X are reacted, we can calculate the number of moles of Z produced using this ratio:
2.50 moles X × (2 moles Z / 1 mole X) = 5.00 moles Z.
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3. Describe how the energy differences between the higher energy levels of an atom compare to the energy differences between the lower energy levels of the atom? Use the Bohr model shown below to help with this answer.
Answer:
H
Explanation:
In the SIM media, which ingredients could be eliminated if the medium were used strictly for testing for motility and indole production? What if I were testing only for motility and sulfur reduction? Edit View Insert Format Tools Table 12pt Paragraph | BI VA V e T²v | 6 D D V Question 2 2 pts All bacteria have the enzymes inside their cells to use citrate for energy. That being said, you saw that only some bacteria can grow on citrate media. Explain why bacteria that can use citrate for energy and carbon may not be able to grow on this media. Edit View Insert Format Tools Table 12pt Paragraph IB I Y A e per l oor BE D
In the event that the SIM (Sulfide Indole Motility) medium is utilized entirely for testing motility and indole generation, the ingredients that can be killed are those particularly related to the discovery of hydrogen sulfide (H2S) generation. These ingredients incorporate ferrous sulfate or ferrous ammonium sulfate, which are utilized to identify the arrangement of dark precipitates showing the presence of H2S.
What if I were testing only for motility and sulfur reduction?In the event that the testing is exclusively for motility and sulfur reduction, the ingredients that can be killed are those related to the discovery of indole generation. Indole isn't directly included in sulfur reduction, so the following fixing can be removed:
Tryptophan: Tryptophan is the amino corrosive substrate utilized for identifying indole generation. Since the center is on sulfur diminishment, the consideration of tryptophan is pointless.Bacteria have the enzymes vital to utilize citrate as a source of vitality and carbon, but not all microbes can develop on citrate media. The failure of a few microbes to develop on citrate media can be clarified by the taking after reasons:
Citrate Permease: Citrate cannot be transported into bacterial cells without the availability of a particular transporter called citrate permease. A few bacteria need or have constrained expression of this transporter, which anticipates them from taking up citrate from the media, in this manner hindering their development on citrate media.Citrate Utilization Pathway: Although bacteria can transport citrate into their cells, they still require a utilitarian citrate utilization pathway to metabolize it. A few microscopic organisms may need the fundamental proteins or regulatory variables required to prepare and utilize citrate as an vitality and carbon source. As a result, they cannot develop on citrate media.It's vital to note that the capacity to develop on citrate media is regularly evaluated utilizing the Simmons citrate agar test, which contains sodium citrate as the sole source of carbon.
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Perform the following operationand express the answer inscientific notation.8.6500x103 + 6.5500x105[? ]x10!?)
First, we need to make the exponent of 10 the same for both.
So let's transform 6.5500 x 10^5 into some number x 10^3.
For this, we need to move the dot to the right, some places where it gives the number 3. In this case, 2 places.
655.00 x 10^3
now we can sum the numbers
8.6500 x 10^3 + 655.00 x 10^3 = 663.65 x 10^3
now we need to transform this number into scientific notation. For this, must have only one number before the dot(on the left side of the dot). We will move the dot to the left, 2 places:
6.6365 x 10^5
Answer: 6.6365 x 10^5
Calculate the amount of heat (in kJ) that must be absorbed to convert 108 g of ice at 0oC to water at 70oC.
"The amount of heat that must be absorbed to convert 108 g of ice at 0°C to water at 70°C is approximately 68.12 kJ."
To calculate the amount of heat required to convert ice at 0°C to water at 70°C, we need to consider two steps:
Heat required to raise the temperature of ice from 0°C to its melting point (0°C).
Heat required to melt the ice at its melting point (0°C) and raise the temperature of water from 0°C to 70°C.
Let's calculate the heat for each step:
Step 1: Heating ice from 0°C to its melting point (0°C)
The specific heat capacity of ice is 2.09 J/g°C.
Heat = mass × specific heat capacity × change in temperature
Heat = 108 g × 2.09 J/g°C × (0°C - 0°C)
Heat = 0 kJ (No heat is absorbed as there is no change in temperature)
Step 2: Melting ice and heating water from 0°C to 70°C
The enthalpy of fusion (heat of fusion) for ice is 334 J/g, which represents the amount of heat required to melt ice at 0°C.
Heat for melting ice = mass × enthalpy of fusion
Heat for melting ice = 108 g × 334 J/g
Heat for melting ice = 36,072 J
Next, we need to calculate the heat required to raise the temperature of the water from 0°C to 70°C.
The specific heat capacity of water is 4.18 J/g°C.
Heat = mass × specific heat capacity × change in temperature
Heat = 108 g × 4.18 J/g°C × (70°C - 0°C)
Heat = 32,043.6 J = 32.04 kJ
Now, we can sum up the heat required for both steps:
Total heat = Heat for melting ice + Heat for raising water temperature
Total heat = 36,072 J + 32,043.6 J
Total heat = 68,115.6 J = 68.12 kJ
Therefore, the amount of heat that must be absorbed to convert 108 g of ice at 0°C to water at 70°C is approximately 68.12 kJ.
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If a helium balloon is put into a hot oven. What happens to the volume of the balloon?
Answer:
What about hot air balloons? They work by similar principles. If you heat up a gas it expands. In the case of a hot air balloon, when the gas inside the balloon expands the extra gas is pushed out the bottom of the balloon, meaning that there are fewer atoms inside the balloon, meaning that the air in the balloon is lighter than the air outside the balloon.
The amount of lifting power is controlled by how hot the air is. If you heat the air inside the balloon 100 degrees F hotter than the outside air temperature, then the air inside the balloon will be about 25 percent lighter than the air outside the balloon. So a cubic foot of air weighs about 35 grams at 32 degrees F. A cubic foot of hot air at 132 degrees F will weigh 25 percent less, or about 26.5 grams. The difference is 8.5 grams or so. So a hot air balloon has to be much bigger to support the same weight, but it will float because hotter air is lighter than cooler air.
Explanation:
The amount of lifting power
Natural gas (methane) flows at 20 m/s through a pipe with a 1 m diameter. The temperature of the methane is 15°C, and the pressure is 150 kPa gage. Determine the mass flow rate.
Methane is a chemical compound with the molecular formula CH₄. The mass flow rate of methane is approximately 0.0004346 kg/s.
Methane is a hydrocarbon, meaning it consists of hydrogen and carbon atoms. It is a colorless, odorless gas and is lighter than air. Methane is highly flammable and is a potent greenhouse gas, contributing to climate change when released into the atmosphere. It is produced naturally through the decomposition of organic matter and is also a byproduct of various industrial processes, agriculture, and livestock farming.
To calculate the final result, we need specific values for pressure and temperature. In your previous question, you provided the temperature as 15°C and the pressure as 150 kPa. Let's plug in these values and calculate the mass flow rate:
\(n = (150,000 Pa * \pi * (0.5 m)^2) / (8.314 J/(mol.K) * (15 + 273.15 K))\\n = 0.02712 mol\)
Mass flow rate = n × molar mass
Mass flow rate ≈ 0.02712 mol × 16 g/mol
Mass flow rate ≈ 0.4346 g/s
Mass flow rate (in kg/s) = Mass flow rate (in g/s) / 1000
Mass flow rate (in kg/s) ≈ 0.4346 g/s / 1000
Mass flow rate (in kg/s) ≈ 0.0004346 kg/s
Therefore, the mass flow rate of methane is approximately 0.0004346 kg/s.
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If 12.3 mol HCl are produced in this reaction, how many grams of sodium sulfate are produced?
ANSWER
The mass of Na2SO4 is 874g
EXPLANATION
Given that;
The number of moles of HCl is 12.3 mol
Follow the steps below to find the mass of sodium sulfate produced
Step 1; Write a balanced equation for the reaction
\(\text{ 2NaCl + H}_2SO_4\text{ }\rightarrow\text{ 2HCl + Na}_2SO_4\)In the reaction above, 2 moles of NaCl react with 1 mole of H2SO4 to give 2 moles of HCl and 1 mole of Na2SO4
Let the number of moles of Na2SO4 be x
\(\begin{gathered} \text{ 2 moles HCl }\rightarrow\text{ 1 mole Na}_2SO_4 \\ \text{ 12.3 moles HCl }\rightarrow\text{ x moles Na}_2SO_4 \\ \text{ Cross multiply} \\ \text{ 2 moles HCl }\times\text{ x moles Na}_2SO_4\text{ }=\text{ 1 mole Na}_2SO_4\text{ }\times\text{ 12.3 mole HCl} \\ \text{ Isolate x} \\ \text{ }\times\text{ }=\text{ }\frac{1\text{ mole Na}_2SO_4\times12.3mol\cancel{HCl}}{2moles\cancel{HCl}} \\ \text{ } \\ \text{ x = }\frac{1\text{ }\times\text{ 12.3}}{2} \\ \text{ x = 6.15 moles} \end{gathered}\)The number of moles of Na2SO4 is 6.15 moles
Step 3; Find the mass of Na2SO4 using the below formula
\(\text{ mole = }\frac{\text{ mass}}{\text{ molar mass}}\)Recall, that the molar mass of Na2SO4 is 142.04 g/mol
\(\begin{gathered} \text{ mass = mole }\times\text{ molar mass} \\ \text{ mass = 6.15 }\times\text{ 142.04} \\ \text{ mass = 873.546} \\ \text{ mass = 874g Na}_2SO_4 \end{gathered}\)Therefore, the mass of Na2SO4 is 874g
Explain the concept law of diminishing marginal rate of substitution. What is/are the reason/s why the law of diminishing marginal rate of substitution suggest/s that isoquant must be bent toward the origin?
The law of diminishing marginal rate of substitution indicates that the rate at which one input can be substituted for another decreases as the quantity of one input increases, leading to isoquants being bent toward the origin.
In other words, as the quantity of one good increases, the individual is willing to sacrifice fewer units of the other good to obtain an additional unit of the first good. This reflects a diminishing rate of substitution between the two goods.
The reason why the law of diminishing marginal rate of substitution suggests that isoquants must be bent toward the origin is rooted in the concept of diminishing marginal utility. As more units of a particular input (e.g., labor or capital) are added while holding other inputs constant, the additional output gained from each additional unit of the input will decrease. This diminishing marginal productivity leads to a decreasing MRS.
When isoquants (which represent different combinations of inputs that produce the same level of output) are bent toward the origin, it reflects the fact that as more of one input is used, the amount of the other input that needs to be substituted decreases. This bending signifies the diminishing MRS and captures the idea that a larger quantity of one input can be substituted for a smaller quantity of the other input to maintain the same level of output.
Overall, the law of diminishing marginal rate of substitution indicates that the rate at which one input can be substituted for another decreases as the quantity of one input increases, leading to isoquants being bent toward the origin.
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difference between soap and detergent
Soap is potassium or sodium salts of a carboxylic acid attached to a long aliphatic chain. Detergent is the potassium or sodium salts of a long alkyl chain ending with a sulfonate group.
The absolute entropy of He at 298.15 K is 126.04 J/mol K. What is its absolute entropy at 1000.00 K? Assume that the heat capacity is constant.
To solve this problem, we can use the formula: \(ΔS = Cp * ln(T2/T1) + R * ln(V2/V1)\)
Where ΔS is the change in entropy, Cp is the molar heat capacity at constant pressure, T1 and T2 are the initial and final temperatures, V1 and V2 are the initial and final volumes, and R is the gas constant.
Since the problem assumes that the heat capacity is constant, we can simplify the formula to: ΔS = Cp * ln(T2/T1)
To find the change in entropy between 298.15 K and 1000.00 K, we can plug in the values: ΔS = Cp * ln(1000.00 K / 298.15 K)
Since we are dealing with a monatomic gas (He), we can use the molar heat capacity at constant volume (Cv) to approximate Cp. For He, Cv is approximately 3/2 R, where R is the gas constant.
So, Cp = Cv + R = (3/2) R + R = (5/2) R
Substituting this value into the formula, we get: ΔS = (5/2) R * ln(1000.00 K / 298.15 K)
We can simplify this further by using the value of R, which is 8.314 J/mol K:
ΔS = (5/2) * 8.314 J/mol K * ln(1000.00 K / 298.15 K)
Calculating this expression gives:
ΔS = 22.80 J/mol K
Therefore, the absolute entropy of He at 1000.00 K is:
S = S1 + ΔS = 126.04 J/mol K + 22.80 J/mol K = 148.84 J/mol K
So, the absolute entropy of He increases from 126.04 J/mol K at 298.15 K to 148.84 J/mol K at 1000.00 K, due to the increase in temperature and the corresponding increase in molecular disorder (entropy).
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Write a statement to explain which characteristics of an atom determine the VSPER structure of an atom
The VSEPR model explains that each atom in a molecule with a central atom will achieve a geometry of the molecule which minimizes the repulsion between electrons of the molecule in the valence shell of that atom.
VSEPR Model can be used to predict the structure of any molecule with a central metal atom present in it. In the polyatomic molecules which is the molecules made up of three or more atoms and one of the constituent atoms is determined as the central atom to which all other atoms belonging to the molecule are linked together.
VSEPR theory explains five main shapes of simple molecules consisting the central atom. Those five structure basically are linear, trigonal planar, tetrahedral, trigonal bipyramidal, and octahedral geometry. Using the VSEPR theory, we predict that the electron bond pairs and lone pairs on the center atom will help us to predict the shape of a central atom of a molecule. Using this theory the shape of a molecule is determined by the location of the nuclei and its electrons of the molecule.
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where do most of the elements on the periodic table come from?
Stars
All the elements on earth have been cooked from billions of years in stars and the released in the universe through super-nova explosions
Modern vehicles are designed to crush when they crash to absorb kinetic energy.
a. true
b. false
The given statement "Modern vehicles are designed to crush when they crash to absorb kinetic energy" is true. Because, Modern vehicles are designed with safety features that include controlled deformation or "crumple zones" to absorb kinetic energy during a crash. Option A is correct.
These crumple zones are strategically placed in the front and rear of the vehicle and are designed to collapse and deform upon impact.
When a vehicle collides with an object or another vehicle, the kinetic energy of the moving vehicle is converted into various forms of energy, including deformation energy. By allowing certain parts of the vehicle to crush or deform, the kinetic energy is absorbed and dissipated over a longer period of time, reducing the force transmitted to the occupants.
The purpose of designing vehicles to crush during a crash is to enhance occupant safety. By absorbing and dissipating energy through controlled deformation, the impact forces on the occupants are reduced, which can help minimize the risk and severity of injuries.
Hence, A. is the correct option.
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How many molecules are in 385 grams of CO2?
Answer:
8.748111203262969
Explanation:
A chemistry student weighs out 0.104g of sulfurous acid (H2SO3) , a diprotic acid, into a 250.mL volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.0700 M NaOH solution. Calculate the volume of NaOH solution the student will need to add to reach the final equivalence point. Be sure your answer has the correct number of significant digits.
Explanation :
To calculate the volume of 0.0700 M NaOH solution needed to reach the final equivalence point, follow these steps:
1. Determine the moles of H2SO3.
2. Determine the moles of NaOH required.
3. Calculate the volume of NaOH solution needed.
Step 1: Determine the moles of H2SO3
Moles = mass / molar mass
Molar mass of H2SO3 = (2 * 1.01) + (32.07) + (3 * 16.00) = 82.07 g/mol
Moles of H2SO3 = 0.104 g / 82.07 g/mol = 0.00127 mol
Step 2: Determine the moles of NaOH required
Since H2SO3 is a diprotic acid, it can react with two moles of NaOH. Therefore, the moles of NaOH required will be double the moles of H2SO3.
Moles of NaOH = 2 * 0.00127 mol = 0.00254 mol
Step 3: Calculate the volume of NaOH solution needed
Volume = moles / molarity
Volume of 0.0700 M NaOH solution = 0.00254 mol / 0.0700 mol/L = 0.0363 L
Convert the volume to mL:
0.0363 L * 1000 mL/L = 36.3 mL
So, the student will need to add 36.3 mL of 0.0700 M NaOH solution to reach the final equivalence point.
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at , substance a has a vapor pressure of and substance b has a vapor pressure of . which has a higher enthalpy of vaporization?
The correct answer is
Due to the significant H-bonding in HF, a given amount of HF requires more energy to move from the liquid to the vapour state (l). Among the many hydrogen halides, HF has the greatest molar enthalpy of vaporisation.
The amount of energy (enthalpy) that must be added to a liquid material in order to convert a portion of that substance into a gas is referred to as the enthalpy of vaporisation (symbol Hvap), also known as the (latent) heat of vaporisation or heat of evaporation. The pressure at which the transition occurs affects the enthalpy of vaporisation.The enthalpy of vaporisation is frequently stated for the substance's typical boiling point. Despite the fact that tabulated values are often adjusted to 298 K, the error in the observed value is frequently less.
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The standard reduction potentials of the following half-reactions are given in Appendix E in the textbook:
Ag+(aq)+e−→Ag(s)= .799
Cu2+(aq)+2e−→Cu(s)= .337
Ni2+(aq)+2e−→Ni(s)= -.28
Cr3+(aq)+3e−→Cr(s). = -.74
1. Determine which combination of these half-cell reactions leads to the cell reaction with the largest positive cell emf.
1st and 2nd,
1st and 3rd,
1st and 4th,
2nd and 3rd,
3rd and 4th.
It isn't the first or last one because I have gotten it wrong twice.
Answer:
To identify which half-cell reaction combination produces the cell reaction with the highest positive cell emf, we must compute and compare the cell potentials for each combination.
When the first and second half-reactions are combined, we get:
Cu(s) + Ag+(aq) = Ag(s) + Cu2+(aq)
This reaction's cell potential is:
Ecell is equal to E°(Cu2+/Cu). - E°(Ag+/Ag)
(0.337 V) - (0.799 V) = Ecell
Ecell is equal to -0.462 V.
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Combining the first and third half-reactions, we get:
Ag+(aq) + Ni(s) → Ag(s) + Ni2+(aq)
The cell potential for this reaction is:
Ecell = E°(Ni2+/Ni) - E°(Ag+/Ag)
Ecell = (-0.28 V) - (0.799 V)
Ecell = -1.079 V
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Combining the first and fourth half-reactions, we get:
Ag+(aq) + Cr(s) → Ag(s) + Cr3+(aq)
The cell potential for this reaction is:
Ecell = E°(Cr3+/Cr) - E°(Ag+/Ag)
Ecell = (-0.74 V) - (0.799 V)
Ecell = -1.539 V
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Combining the second and third half-reactions, we get:
Cu2+(aq) + Ni(s) → Cu(s) + Ni2+(aq)
The cell potential for this reaction is:
Ecell = E°(Ni2+/Ni) - E°(Cu2+/Cu)
Ecell = (-0.28 V) - (0.337 V)
Ecell = -0.617 V
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Combining the third and fourth half-reactions, we get:
Ni2+(aq) + Cr(s) → Ni(s) + Cr3+(aq)
The cell potential for this reaction is:
Ecell = E°(Cr3+/Cr) - E°(Ni2+/Ni)
Ecell = (-0.74 V) - (-0.28 V)
Ecell = -0.46 V
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As a result, the second and fourth combinations of half-cell reactions result in the cell reaction with the highest positive cell emf: Cu2+(aq) + Ni(s) Cu(s) + Ni2+(aq). This reaction has a cell potential of -0.617 V.
To determine the combination of half-cell reactions that leads to the cell reaction with the largest positive cell emf, we need to look at the reduction potentials of the half-reactions. The half-reaction with the highest reduction potential will be the one that is most likely to occur as reduction is the gain of electrons.
To calculate the overall cell potential, we need to subtract the reduction potential of the anode (where oxidation occurs) from the reduction potential of the cathode (where reduction occurs). The half-reaction with the higher reduction potential will be the cathode, and the other half-reaction will be the anode.
Therefore, we need to look for the combination of half-reactions where the difference between the reduction potentials is the highest.
1st and 2nd: .799 - .337 = .462
1st and 3rd: .799 - (-.28) = 1.079
1st and 4th: .799 - (-.74) = 1.539
2nd and 3rd: .337 - (-.28) = .617
3rd and 4th: (-.28) - (-.74) = .46
The combination with the highest difference in reduction potentials is 1st and 4th, with a difference of 1.539. Therefore, the cell reaction with the largest positive cell emf would be Ag+(aq) + Cr(s) → Ag(s) + Cr3+(aq).
To know more about half-cell reaction : https://brainly.com/question/9579016
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