What are the degrees of freedom for a one sample t-test study with 48 people in the sample group?

I think the area is 398.48m²

Answer:

6

Step-by-step explanation:

The triangles ΔAEB and ΔCDB are congruent as per SSS criteria. The correct option is (B).

Two triangles are said to be congruent when all of their corresponding sides and angles are equal. For this relation between two triangles, there are many criteria such as SSS, SAS, ASA and RHS.

The relation between the two triangles ΔAEB and ΔCDB as per the given information can be shown as follows,

In ΔAEB and ΔCDB,

AE = CB

AB = CD

EB = BD

Since all the three corresponding sides of the triangles are equal, the triangles  ΔAEB ≅ ΔCDB by SSS criteria.

Hence, the two triangles are congruent by SSS criteria.

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Answer: (-4,-7)

Step-by-step explanation:

Answer:

94hhfgkifc llo gfc bbn jdcjkydcjkufv

Answer:

The first one

Step-by-step explanation:

You can see the pattern

Answer:

31, 65, 146

Step-by-step explanation:

math

Answer:

26.9 cm

Step-by-step explanation:

5cm x 4

5x 5 x 4.5

Answer: k = 32

Step-by-step explanation:

k/8 - 1 = 3         We add 1 on both sides

+1          +1

k/8 = 4          Now we have to multiply by both sides to isolate the k

x8     x8

k = 32

Area of a polygon can be derived from sum of area of its sub-parts. The area of the considered polygon is given by: Option C: 316 cm²

Some polygon are of standard shapes like rectangle, triangle, parallelogram etc, but some are not standard and can be of any shape. For finding their area, we divide that non-standard polygon in parts such that it gets divided in standard polygons.

Then, we get:

Area of non-standard polygon = sum of all standard polygons forming that initial polygon.

For the given case, dividing the polygon in the shapes whose area we know(which is called here as standard polygons), as shown in the figure attached below, we get:

Area of polygon = Sum of area of those composing parts.

Area of polygon =  Area of upper triangle ABC + Area of bottom rectangle BDEF

Height of ABC triangle = height of polygon - height of rectangle

Height of ABC = 18 - 14 = 4 cm

Base of ABC = length of BC = length of BD - length of CD = 21-10 = 11 cm

Thus, area of ABC = \(\dfrac{1}{2} \times base \times height = \dfrac{1}{2} \times 4 \times 11 = 22 \: \rm cm^2\)

Area of rectangle BDEF = length times width = \(14 \times 21 = 294\: \rm cm^2\)

Thus, area of polygon = Area of ABC + Area of BDEF = 22 + 294  cm²

Area of polygon = 316 cm² (option C)

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Answer: 338 cm^2

Hope this helps! :)

Please mark me brainliest.

To solve this problem, we can use algebraic equations. Let's say that the number of weeks it takes for Ted and Carly to have the same account balance is "w".

Ted's account balance after "w" weeks can be represented by:

300 + 4w

Carly's account balance after "w" weeks can be represented by:

16w

We want to find out when their account balances will be equal, so we can set these two equations equal to each other:

300 + 4w = 16w

Simplifying this equation, we get:

300 = 12w

Dividing both sides by 12, we get:

25 = w

Therefore, it will take 25 weeks for Ted and Carly to have the same account balance.

The simplified expression is 7x- 2.

A mathematical operation such as subtraction, addition, multiplication, or division is used to combine terms into an expression. In a mathematical expression, the following terms are used:

Given:

−4x−2y+6 from 3x−2y+4.

So, subtraction will be as follows

3x - 2y + 4-( -4x  -2y + 6 )

or, 3x - 2y + 4  + 4x + 2y -6

or, 7x - 2

Hence, the simplified expression is 7x- 2.

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Answer:

There are four terms.

Step-by-step explanation:

The terms are basically just 2x, 5, 2y, -3

I hope this helps you :D

c h e e s e c h e e s e s m i l e f o r t h e c a m e r a c h e e s e c h e e s e s t o p s m i l i n g c h e e s e c h e e s e s m a s h t h e c a m e r a c h e e s e c h e e s e k i l l t h e p h o t o g r a p h e r c h e e s e c h e e s e s m i l e a t t h e d e a d b o d y c h e e s e c h e e s e t h i s i s t h e c h e e s e s o n g c h e e s e c h e e s e .

You may quickly determine the fundamental trigonometric numbers of the most typical angles by utilizing a trigonometry table or the SOHCAHTOA approach.

Make a new table for trigonometry. Create a table with six rows and six columns. Put the trigonometric ratios in the first column (sine, cosine, tangent, cosecant, secant, and cotangent). Write the usual trigonometric angles (0°, 30°, 45°, 60°, and 90°) in the first column. Leave all of the other table entries blank.

the three basic trig ratios that are used to solve for missing sides and angles in a right triangle. It is defined as follows: SOH: Opposite / Hypotenuse = Sin().

Fill the sine, cosine, and tan values in the appropriate columns.

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The Economic Order Quantity (EOQ) is calculated to be 547.72 units. The number of orders placed per year is 5.84, and the reorder point (ROP) is 32.01.

The total holding cost of lawnmowers is R1369.30, and the total ordering cost of lawnmowers is R876.00. These calculations provide valuable insights for efficient inventory management.

The Economic Order Quantity (EOQ) can be calculated by using the formula: EOQ = √2DS / H,

where D = Total Demand = 3200 units,

S = Ordering cost per order = R150,

and H = Annual holding cost per unit = R5.

Therefore, EOQ = √ (2 x 3200 x 150) / 5 = 547.72 units.

4.2 Number of orders placed per year: No of orders per year = D / Q,

where D = Total Demand = 3200 units and Q = EOQ = 547.72 units.

Therefore, No of orders per year = D / Q = 3200 / 547.72 = 5.84 orders.

4.4 Total holding cost of lawnmowers:

Total holding cost of lawnmowers = (Average inventory level) x (Annual holding cost per unit),

where (Average inventory level) = EOQ / 2 = 547.72 / 2 = 273.86 units and Annual holding cost per unit = R5.

Thus, the Total holding cost of lawnmowers = 273.86 x R5 = R1369.30.

4.1 Reorder Point (ROP): ROP can be calculated by using the formula:

ROP = dL, where d = Daily demand = D / Number of working days

= 3200 / 300 = 10.67 and L = Lead time = 3 days.

Hence, ROP = dL = 10.67 x 3 = 32.01.

4.5 Total ordering cost of lawnmowers:

Total ordering cost of lawnmowers = (Number of orders placed per year) x (Ordering cost per order),

where (Number of orders placed per year) = 5.84 orders and Ordering cost per order = R150.

Therefore, the Total ordering cost of lawnmowers = 5.84 x R150 = R876.00.

The Economic Order Quantity (EOQ) is calculated to be 547.72 units.

The number of orders placed per year is 5.84, and the reorder point (ROP) is 32.01.

The total holding cost of lawnmowers is R1369.30, and the total ordering cost of lawnmowers is R876.00.

These calculations provide valuable insights for efficient inventory management.

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Answer: 40 gallons per second

Step-by-step explanation:

every second, a set number of gallons is emptied from the pool. to find this amount, you essentially have to subtract the one number From one on top of it. Example: 300 - 260 = 40

You can either stop there or continue until you are confident you have the right answer

300 - 260 = 40

260 - 220 = 40

220 - 180 = 40

180 - 140 = 40

The quantifiers are not correctly used in the expressions vx ³ (x = y²) and vxy 3z (x+y=z).

In the expression vx ³ (x = y²), the universal quantifier should bind the variable 'x' instead of the inequality 'x³'. The correct expression would be ∀x (x = y²), which states that for all real numbers 'x', 'x' is equal to the square of 'y'.

In the expression vxy 3z (x+y=z), both quantifiers are used correctly. The universal quantifier 'vxy' states that for all real numbers 'x' and 'y', there exists a real number 'z' such that 'x+y=z'. This expression represents a valid mathematical statement.

However, the expression 3x (x² < 0) does not correctly use the existential quantifier. The inequality 'x² < 0' implies that the square of 'x' is a negative number, which is not possible for any real number 'x'. The correct expression would be ∀x (x² < 0), indicating that for all real numbers 'x', the square of 'x' is less than zero.

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Larger sample sizes provide more accurate estimates of the population mean, even if the population is not normally distributed.

For a population that is not normally distributed, the distribution of the sample means will approach a normal distribution as the size of the sample increases.

This is known as the Central Limit Theorem, which states that as the sample size increases, the distribution of sample means becomes more normal regardless of the shape of the population distribution.

Therefore, larger sample sizes provide more accurate estimates of the population mean, even if the population is not normally distributed.

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The equation for the hyperbola with foci (0,±5) and asymptotes y=± 3/4 x is:

y^2 / 25 - x^2 / a^2 = 1

where a is the distance from the center to a vertex and is related to the slope of the asymptotes by a = 5 / (3/4) = 20/3.

Thus, the equation for the hyperbola is:

y^2 / 25 - x^2 / (400/9) = 1

or

9y^2 - 400x^2 = 900

The center of the hyperbola is at the origin, since the foci have y-coordinates of ±5 and the asymptotes have y-intercepts of 0.

To graph the hyperbola, we can plot the foci at (0,±5) and draw the asymptotes y=± 3/4 x. Then, we can sketch the branches of the hyperbola by drawing a rectangle with sides of length 2a and centered at the origin. The vertices of the hyperbola will lie on the corners of this rectangle. Finally, we can sketch the hyperbola by drawing the two branches that pass through the vertices and are tangent to the asymptotes.

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If a body is moving in the horizontal axis with a velocity Vx= 6m/s and in the vertical axis Vy=8m/s, the magnitude of the velocity of the body V is 10

The given parameters are;

The velocity of the body relative to the horizontal axis, vₓ = 6 m/s

The velocity of the body relative to the vertical axis,  = 8 m/s

Required;

The measure of the magnitude of the velocity of the moving body, v

The velocity of the body can be represented vectorially as follows;

v = 6·i + 8·j

|V| = \(\sqrt{Vx^{2} + Vy^{2} }\)

|V| = \(\sqrt{6^{2} + 8^{2} }\)

= \(\sqrt{64 + 36}\)

= √100

|V| = 10

Therefore if a body is moving in the horizontal axis with a velocity Vx= 6m/s and in the vertical axis Vy=8m/s, the magnitude of the velocity of the body V is 10

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Answer:

666,000

Step-by-step explanation:

18000

×37= 666,000

The total square footage of the two-story home is 7,200 square feet.

To calculate the total square footage of the home, we need to multiply the exterior wall measurements of each floor and add them together.

Assuming both floors have the same dimensions, the square footage of one floor would be:

40 feet x 90 feet = 3,600 square feet

Since the house has two floors, we need to double this number:

3,600 square feet x 2 = 7,200 square feet

Therefore, the total square footage of the two-story home is 7,200 square feet.

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As given by the question,

There are given that the equation:

Now,

First, suppose any number, for which the given equation has satisfied.

So, the number is, x = 2 and y = 6

Then,

Put both values into the given equation

Then,

Put the same value of x and y into the given option and check whether it is satisfied:

So,

From option 3:

Hence, the correct option is 3.

Let's say the new crew of painters can paint the small apartment in x hours, and the experienced crew can paint the small apartment in y hours. Let the time taken by the new crew of painters to paint the small apartment be N hours, and the time taken by the experienced crew be E hours.

We are supposed to find the time it takes for both crews to paint the apartment together.

Step 1: Find the work rate of each crew.
The new crew's work rate is 1/N (apartments painted per hour).
The experienced crew's work rate is 1/E (apartments painted per hour).

Step 2: Calculate the combined work rate of both crews.
Combined work rate = New crew's work rate + Experienced crew's work rate
Combined work rate = (1/N) + (1/E)

Step 3: Find the time it takes for both crews to paint the apartment together.
Let T be the time it takes for both crews to paint the apartment together. Their combined work rate can be expressed as the reciprocal of T.

1/T = (1/N) + (1/E)

Step 4: Solve for T.
T = 1 / [(1/N) + (1/E)]

So, it takes T hours to paint the apartment when the two crews work together. Once you know the specific values of N and E, you can plug them into the equation and solve for T to find the solution.

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Answer:

A) Values in the solution set satisfy both inequalities.

B) It is the intersection of two solution sets.

Step-by-step explanation:

We denote intersection as AND.

\(A \cap B \implies \text{A and B}\)

Take those sets. The intersection is what A and B share.

Now

It's a right angle triangle

Perpendicular be radius and P

Apply Pythagorean theorem

\(\\ \rm\rightarrowtail P^2=36^2-24^2\)

\(\\ \rm\rightarrowtail P^2=720\)

\(\\ \rm\rightarrowtail P=\sqrt{720}\)

\(\\ \rm\rightarrowtail P=\sqrt{2(2)(2)(2)(3)(3)(5)}\)

\(\\ \rm\rightarrowtail P=4(3)\sqrt{5}\)

\(\\ \rm\rightarrowtail P=12\sqrt{5}\)

Answer:

Quartile Q1: 18

Quartile Q2: 28

Quartile Q3: 32

there you go

The MAD of the given data set is 3.3.

The average absolute distance between each data value and the mean of a data set is measured as the mean absolute deviation (MAD). MAD is a metric or statistic that, like standard deviation, evaluates the spread or variance in your data. We assess the absolute distance between each data point and the mean in order to compute MAD. After that, averaging such distances. The MAD equation is as follows:

\(\frac {1}{n} \sum \limits_{i=1}^n |x_i-m(X)|\)

m(X) = average value of the data set

n = number of data values

x_i = data values in the set

Given a data set of  yearly rainfall for a 9-year period in inches:

29, 24, 19, 21, 23, 27, 26, 29, 18

The Mean of the given data is 24. The following table will calculate the Absolute deviation.

Data Value Deviation from mean Absolute Value of Deviation

29                            29-25 = 4           |4| = 4

  24                    24-25 = -1    |-1| = 1

  19                            19-24 = -5           |-5| = 5

   21                    21-24= -3     |-3| = 3

   23                         23-24= -1           |-1| = 1

   27                    27-24 = 3    |3| = 3

   26                     26-24 = 2          |2| = 2

   29                   29-25 = 4           |4| = 4

   18                     18-24 = -6           |-6| = 6

Total of Absolute Deviations: 24

For MAD = 24/9 = 3.222

Therefore,  the MAD for this set of data in inches is 3.222≅ 3.3 inches.

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Therefore, it would take approximately 10.246 hours for the satellite to fly 82000 miles.

We can use the concept of unit rate to solve this problem.

Given that the satellite flies 73680 miles in 9.21 hours, we can calculate the unit rate of the satellite's speed:

Unit Rate = Distance / Time

= 73680 miles / 9.21 hours

≈ 8004.55 miles/hour

Now, to find out how long it would take for the satellite to fly 82000 miles, we can use the unit rate:

Time = Distance / Unit Rate

= 82000 miles / 8004.55 miles/hour

Calculating this value:

Time ≈ 10.246 hours

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The volume of water that will be needed to finish filling the water tank is 300ft²

A pyramid is a three-dimensional shape. A pyramid has a polygonal base and flat triangular faces, which join at a common point called the apex.

The volume of a pyramid is expressed as ;

V = 1/3 base area × height

base area = l×w

= 10× 15 = 150ft²

height = 12 ft

V = 150 × 12/3

V = 600ft³

The whole volume of the tank is 1800ft³

but it is half filled

= 600/2 = 300 ft³

therefore the volume of water to fill the tank is

= 600-300

= 300ft³

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