Using values from Appendix C of your textbook, calculate the value of Keq at 298 K for each of the following reactions:(a) H2(g) + I2(g) 2 HI(g)
Keq =
.
(b) 2 HBr(g) H2(g) + Br2(g)
Keq =
.
(c) 3 Fe(s) + 4 CO2(g) Fe3O4(s) + 4 CO(g)
Keq =

Answer:

The Force of Gravity  force between each planet and the Sun keeps the planets in orbit around the Sun.

Explanation:

Answer:

Para ser mas exactos una reaccion quimica es donde los reactivos se transforman en productos.

Explanation:

Durante las reacciones quimicas, ocurren ciertas transformaciones que hace que se tome o se libere energia del medio, generando que los reactivos de la reaccion, es decir los compuestos iniciales, en un determinado espacio y tiempo bajo ciertas condiciones de presion y temperatura exactas se transformen en productos.

Para la quimica, la misma cantidad de materia que se encuentra en los reactivos se mantendra en los productos, es por eso que cada reaccion quimica debe respetar las reglas de la estequiometria y estar balanceadas a la perfeccion.

Liquid is the state of matter that has particles that are close together but can slide past one another.

In Chemistry, there are three definite states of matter including liquid, solid and gases and the fourth state is called plasma.

Out of the three states of matter, solids are rigid substances having definite shape, size and volume. In solids, intermolecular forces are greater and hold the atoms together tightly.

While in liquids, the intermolecular forces are comparatively weak due to molecules are loosely attached. It has a definite volume and acquires the shape of the container.

In gases, intermolecular forces are least and the molecule move randomly. Gases have no definite and volume.

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The size of the Kf indicate regarding the stability of the transition metal complexes is the large values of the Kf indicate that transition metal complexes are often very stable.

The larger the value of the Kf of the complex ion, the more stable will be the transition metal complexes. Due to the how large formation constants are often is not uncommon to listed as the logarithms in the form of the log Kf.

The Kf values that are the very large in the magnitude for the complex ion formation that indicate that the reaction is heavily favors the products. The complex ions that are the poorly formed and this value will be the very small.

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The reaction with S_N₂mechanism is likely to be faster than the reaction with S_N₂ mechanism. This is because the carbocation intermediate formed in S_N₁ mechanism is more stable.

The pair of reactions given below is:

CH₃Cl + NaOH→CH₃OH + NaCl

CH₃I + NaOH→CH₃OH + NaI

The type of substitution mechanism:

The first reaction involves S_N₁ mechanism (unimolecular nucleophilic substitution). The second reaction involves S_N₂ mechanism (bimolecular nucleophilic substitution).

Prediction of the reaction that will occur at a faster rate:

The reaction with S_N₁ mechanism is likely to be faster. The rate of this reaction mainly depends on the stability of the carbocation intermediate formed after the initial step. In this case,CH₃Cl reacts to form a tertiary carbocation which is more stable than the primary carbocation formed in CH₃I.

Drawing the correct organic product:

CH₃Cl + NaOH→CH₃OH + NaCl

CH₃I + NaOH→CH_3OH + NaI

CH₃C reacts with NaOHin an S_N₁ mechanism to produceCH₃OH and NaCl.


CH₃ reacts withNaOH in an S_N₂mechanism to produce CH₃OH and NaCI.


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Answer:

Explanation:

The volume of distilled water that should be added to 25 cm3 of 0.125 moldm-3 HCl in order to dilute it 10 times can be calculated using the following equation:

Volume of added water = (25 cm3 x 10) / (0.125 moldm-3)

= 200 cm3

Therefore, the volume of distilled water that should be added to 25 cm3 of 0.125 moldm-3 HCl in order to dilute it 10 times is 200 cm3.

This body part in squid allows them to propel themselves rapidly by sucking in through the mantle and out through the siphon.

The siphon is a large tube at the bottom of the giant squid's body and allows it to move. The giant squid draws air into a siphon and pushes the air out to propel itself forward.

Squids have a tubular bodies and small rod-like internal structures called pens, which help support the squid's body. The mantles help protect the cavity of the squid, as well as help it move, as they suck water in and then push it out.

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Answer: Fluorine.

Explanation:

Explanation:

taking a special juice independent variable

the number of stuck of paper dependent variable

the control group is group B

experimental group is Group A

for more information study on thougtco

Answer:

0.021

Explanation:

Step 1: Write the balanced equation

2 HF(g) ⇄ H₂(g) + F₂(g)

Step 2: Calculate the value of the concentration equilibrium constant

The concentration equilibrium constant (K) is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients.

K for this reaction is:

K = [H₂] × [F₂] / [HF]²

K = (8.4 × 10⁻³) × (8.4 × 10⁻³) / (5.82 × 10⁻²)² = 0.021

The pH of the solution after adding 15 mL of 0.1 M sodium hydroxide is 4.16.

The titration of acetic acid (CH3COOH) with sodium hydroxide (NaOH) can be represented by the balanced chemical equation:

CH3COOH + NaOH → CH3COONa + H2O

In this reaction, one mole of acetic acid reacts with one mole of sodium hydroxide to produce one mole of sodium acetate (CH3COONa) and one mole of water.

Before any base is added, the solution consists of 10 mL of 0.15 M acetic acid. At this point, the concentration of acetic acid can be calculated using the formula:

M1V1 = M2V2

where M1 is the initial concentration of the acid, V1 is the initial volume of the acid, M2 is the final concentration of the acid after adding the base, and V2 is the final volume of the solution after adding the base. Substituting the given values:

(0.15 M) × (10 mL) = M2 × (25 mL)

M2 = 0.06 M

When 15 mL of 0.1 M sodium hydroxide is added to the solution, it reacts with the acetic acid according to the balanced chemical equation. The amount of sodium hydroxide added is not enough to completely neutralize all of the acetic acid, so a buffer solution is formed consisting of sodium acetate and acetic acid. The moles of acetic acid remaining after the addition of the base can be calculated using the formula:

moles of acetic acid = initial moles - moles of NaOH added

The initial moles of acetic acid can be calculated from the initial concentration and volume:

moles of CH3COOH = (0.15 M) × (10 mL) = 0.0015 moles

The moles of NaOH added can be calculated from the concentration and volume:

moles of NaOH = (0.1 M) × (15 mL / 1000 mL/mL) = 0.0015 moles

Therefore, the moles of acetic acid remaining are:

moles of CH3COOH = 0.0015 moles - 0.0015 moles = 0 moles

The concentration of the acetate ion (CH3COO-) can be calculated using the formula:

M = moles / volume

The volume of the solution after adding the base is 25 mL. The moles of acetate ion can be calculated from the moles of sodium hydroxide that reacted with the acetic acid:

moles of CH3COO- = moles of NaOH added = 0.0015 moles

The concentration of the acetate ion is then:

M = 0.0015 moles / (25 mL / 1000 mL/mL) = 0.06 M

We can use the Henderson-Hasselbalch equation to calculate the pH of the buffer solution:

pH = pKa + log([A^-]/[HA])

where pKa is the acid dissociation constant of acetic acid (4.76), [A^-] is the concentration of the acetate ion, and [HA] is the concentration of the acetic acid.

Substituting the given values:

pH = 4.76 + log(0.06 M / 0.15 M) = 4.76 - 0.6 = 4.16

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Answer:

Option C:

CO2 can displace oxygen around the flame because it has a higher density than air.

Explanation:

CO2 is heavier - or in this case, we can say denser than air.  In addition to that, CO2 does not support burning. t is a major component in fire extinguishers that are designed to stop minor domestic fire incidents.

Since CO2 is denser than air, it sinks to the bottom of the room, and surrounds the flame with an atmoshphere inert to combustion, pushing the oxygen upwards in the process, away from the reach of the flames.

This causes the fire to starve to death from lack of oxygen

There are 2 moles in a 24.022 g sample of Carbon (C).

HOW TO CALCULATE NUMBER OF MOLES:

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Mass of AlCl₃ : 93.39 g

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

\(\large {\boxed {\bold {M ~ = ~ \dfrac {n} {V}}}\)

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

So to find the number of moles can be expressed as

n = V x M

the volume of the solution = 330 cm³=0.33 dm³

the concentration of the solution = 283 g/dm³

mass of AlCl₃ :

\(\tt mass=V\times M\\\\mass=0.33\times 283=93.39~g\)

Answer:The mass of oxygen gas sample collected over water is 0.544 g.

The given parameters;

temperature of the oxygen gas, t = 25 °C

total pressure of the gas, P = 644 torr

volume of the gas, V = 500 mL

vapor pressure = 23.8 torr

molar mass of oxygen gas = 32 g/mol

The number of moles of the gas collected is calculated by using ideal gas equation as follows;

PV = nRT

where;

R is the ideal gas constant = 62.36 L.torr/mol.K

P is the pressure of the gas = 644 torr - 23.8 torr = 620.2 torr

T is the temperature of the gas = 25 + 273 = 298 K

V is the volume of the gas = 500 mL = 0.5 L

The number of moles of the  gas is calculated as follows;

The mass of oxygen gas collected is calculated as follows;

m = 0.017 (32 g/mol)

m = 0.544 g

Thus, the mass of oxygen gas sample collected over water is 0.544 g.

Explanation:

The partial pressure of oxygen is; 760.0 torr - 23.8  torr = 736.2 torr.

We know that in a mixture of gases, the pressure that is exerted by each gas is called the partial pressure of the mixture.

In this case, we have the total pressure of the mixture as 760.0 torr and the vapor pressure of water as 23.8 mm Hg or 23.8  torr) at that temperature. Hence, the partial pressure of oxygen is; 760.0 torr - 23.8  torr = 736.2 torr.

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Phenolphtalein is chosen because it changes color in a pH range between 8.3 - 10. It will appear pink in basic solutions and clear in acidic solutions.

A titration is a method where the concentration of an unknown solution is ascertained by comparing it to a solution of known concentration. The analyte (the unknown solution) is typically added in a known amount to the titrant (the known solution) from a buret until the reaction is finished.

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Answer:

8.3mL

Explanation:

According to the question, the initial volume of a measured amount of water is 12.5mL. Karen then adds a rubber stopper that weighs 2.3grams. This increases the volume of the water.

The increase in the volume of the water is attributed to the rubber stopper. Hence, to calculate the volume of the rubber stopper, we subtract the initial volume of the water from the final volume. i.e.

Volume of added rubber stopper = final volume of water - initial volume of water

= 20.8 - 12.5

= 8.3mL

Hence, the volume of the rubber stopper is 8.3mL

The concentration of Ag+ ions in silver phosphate must be less than the concentration of Ag+ ions in silver oxalate.Therefore, we can conclude that silver oxalate has a greater concentration of Ag+ ions than silver phosphate.

Molar solubility is the maximum amount of a solute that can dissolve in a solvent to form a saturated solutions at a specific temperature and pressure.

To compare concentration of Ag+ ions in silver oxalate and silver phosphate,we calculate the molar solubility of each compound.

For silver oxalate, the solubility product constant (Ksp) is given as 5.40x10⁻¹².

The balanced equation for the dissociation of silver oxalate is:

Ag₂C₂O₄s) ⇌ 2 Ag+(aq) + C₂O₄₂-(aq)

The Ksp expression for silver oxalate is:

Ksp = [Ag+]² [C₂O₄₂₋]

Since the stoichiometric coefficient of Ag+ is 2, we can assume that the molar solubility of silver oxalate is equal to x mol/L. Then, the molar concentration of Ag+ ions is also x mol/L.

Using the Ksp expression for silver oxalate, we can solve for x:

Ksp = [Ag+]² [C₂O₄₂-]

5.40x10⁻¹² = (x)² (2x)

5.40x10⁻¹² = 2x³

x = (5.40x10⁻¹²/₂)¹/₃

x = 4.38x10⁻⁴ mol/L

Therefore, the molar solubility of silver oxalate is 4.38x10⁻⁴ mol/L, and the concentration of Ag+ ions is also 4.38x10⁻⁴ mol/L.

For silver phosphate, the Ksp is given as 8.89x10⁻¹⁷

The balanced equation for the dissociation of silver phosphate is:

Ag₃PO₄(s) ⇌ 3 Ag+(aq) + PO₄₃-(aq)

The Ksp expression for silver phosphate is:

Ksp = [Ag+]³ [PO₄₃-]

Using the Ksp expression for silver phosphate, we can solve for x:

Ksp = [Ag+]³[PO₄₃-]

8.89x10⁻¹⁷ = (3x)³[PO₄₃-]

8.89x10⁻¹⁷ = 27x³ [PO⁴³-]

[PO⁴³-] = 8.89x10⁻¹⁷/27x³

Since we don't know the value of x yet, we can't directly solve for [PO₄₃-]. However, we know that the molar solubility of silver phosphate must be less than the molar solubility of silver oxalate, since the Ksp value for silver phosphate is smaller.

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Answer:

The molecular formula of the hydrocarbon compound is C₈H₁₈

Explanation:

The type of chemical substance in the question = Hydrocarbon

The mass of the hydrocarbon = 5.7 g

The mass of carbon in the given hydrocarbon (sample) = 4.8 g

The relative molecular mas of the hydrocarbon = 114 g

Therefore, the mass of hydrogen in the sample, H = 5.7 g - 4.8 g = 0.9 g

The ratio of the mass of carbon in the sample = 4.8/5.7

The ratio of the mass of hydrogen in the sample = 0.9/5.7

By the law of constant composition, we have;

The mass of carbon in a mole of the hydrocarbon = (4.8/5.7) × 114 g = 96 g

The molar mass of carbon, C = 12 g/mol

The number of moles of carbon in a mole of the hydrocarbon, 'n₁', is given as follows;

n₁ = 96 g/12 g = 8 moles

The mass of hydrogen in a mole of the hydrocarbon = (0.9/5.7) × 114 g = 18 g

The molar mass of hydrogen, H ≈ 1 g/mol

The number of moles of hydrogen in a mole of the hydrocarbon, 'n₂', is given as follows;

n₂ = 48 g/1 g = 18 moles

Therefore, in each each molecule of the compound, we have have 8 atoms of carbon, 'C', and 18 atoms of hydrogen, 'H'

Therefore, we get;

The molecular formula of the hydrocarbon compound is C₈H₁₈ which is the chemical formula for the hydrocarbon also known as octane

Answer:

- start by recycling the question

- explain the topic using key words related to that topic

- include a few examples/data if it's using a graph/photo

Answer:

65.56 M

Explanation:

Using the formula as follows:

C1V1 = C2V2

Where;

C1 = initial concentration (M)

C2 = final concentration (M)

V1 = initial volume (L)

V2 = final volume (L)

According to the information in this question,

C1 = 1,049 M

C2 = ?

V1 = 120 mL

V2 = 1,920 mL

Using C1V1 = C2V2

1049 × 120 = C2 × 1920

125880 = 1920C2

C2 = 125880 ÷ 1920

C2 = 65.56 M

Answer:

B. Wall applies equal reaction force on hand

Explanation:

This is newton's third law. You push something, that something pushes you back with same force. The direction is opposite, so if I push a wall, the wall pushes me back with same force just in opposite direction (so wall towards me). This is why option A is incorrect b/c it says force in same direction as wall. C and D talk about unequal force which is incorrect.

Answer:Wall applies equal reaction force on hand

Explanation:

Answer:

Lower, Higher

Explanation:

The 134.6 milliliters of 0.644 M NaOH are required to precipitate all of the Fe2+ ions in the FeBr2 solution.

To calculate the number of milliliters of 0.644 M NaOH required to precipitate all of the Fe2+ ions in 156 mL of 0.556 M FeBr2 solution, we can use the stoichiometry of the reaction between Fe2+ ions and NaOH.

The balanced equation for the reaction is:

FeBr2 + 2NaOH → Fe(OH)2 + 2NaBr

From the equation, we can see that 1 mole of FeBr2 reacts with 2 moles of NaOH to form 1 mole of Fe(OH)2.

To find the amount of NaOH required, we need to determine the moles of Fe2+ ions in the 156 mL of 0.556 M FeBr2 solution.

Moles of Fe2+ ions = volume (L) x concentration (M)
                   = 0.156 L x 0.556 M
                   = 0.086736 moles

Since 1 mole of FeBr2 produces 1 mole of Fe2+ ions, we need 0.086736 moles of NaOH to react with all of the Fe2+ ions.

Now, we can use the concentration of NaOH to calculate the volume needed.

Volume (L) = moles / concentration (M)
          = 0.086736 moles / 0.644 M
          = 0.1346 L

To convert the volume to milliliters, we multiply by 1000.

Volume (mL) = 0.1346 L x 1000
            = 134.6 mL

Therefore, 134.6 milliliters of 0.644 M NaOH are required to precipitate all of the Fe2+ ions in the FeBr2 solution.

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Answer:

The atmosphere traps heat energy from the Sun and energy radiated from Earth's surface helping to maintain Earth's climate

Explanation:

Earth's atmosphere keeps much of the Sun's energy from escaping into space. This process, called the greenhouse effect, keeps the planet warm enough for life to exist. The atmosphere allows about half of the Sun's heat energy (50%) to reach Earth's surface.

The type of solvent used with a marker can greatly affect the reaction and outcome of the marker. When selecting a solvent, it is important to consider the polar or non-polar nature of both the solvent and the marker in order to achieve the desired result.

Solvents are liquids that are used to dissolve substances and are an important aspect of chemical reactions and processes. When it comes to markers, the type of solvent used can greatly affect the reaction and outcome of the marker.

In general, solvents can be classified as polar or non-polar. Polar solvents, such as water, have a positive and negative end, while non-polar solvents, such as oil, have a more uniform distribution of electrons. The solubility of a substance is determined by its polar or non-polar nature and the polar or non-polar nature of the solvent.

Markers contain various types of dyes or pigments that can be either polar or non-polar. When a polar solvent, such as water, is used with a polar marker, the marker will dissolve easily, leading to a more intense and uniform color. On the other hand, when a non-polar solvent, such as alcohol, is used with a polar marker, the marker may not dissolve as well and the color may be lighter or less intense.

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