Using the given reaction profile, what must compound K be? A) An intermediate B) A reactant Potential Energy C) A product KA+B KAB D) A catalyst AB+K E) A transition state Reaction Progress +

Answer:

135.80 g of Ag

Explanation:

\(40gCu *\frac{1mol Cu}{63.546g Cu} *\frac{2mol Ag}{1molCu} *\frac{107.868g Ag}{1mol Ag}\)

~ 135.80 g of Ag

Answer: C. Silicon

A solid-state rectifier is primarily made of silicon, which is a semiconductor material. Silicon is used in the manufacturing of rectifiers because it has unique electrical properties that make it ideal for this purpose. When impurities, such as boron or phosphorus, are added to silicon, it becomes a better conductor of electricity in certain areas, creating a p-n junction. This p-n junction is the basis of the diode, which is the fundamental building block of the rectifier. Therefore, silicon is the primary material used in the construction of solid-state rectifiers.

The most commonly used substance in the production of solid-state rectifiers is (D) Silicon.

A solid-state rectifier is an electronic device that is primarily used to convert AC (alternating current) to DC (direct current) by using semiconductor materials.

Silicon is a widely used semiconductor material that has excellent electrical properties. It is highly conductive and has a stable electrical response. It is readily available and affordable. The process of manufacturing solid-state rectifiers involves doping silicon with impurities to create a PN junction. The PN junction is a critical component of a solid-state rectifier, as it allows the device to act as a one-way valve that only permits the flow of current in one direction.

Iron and aluminum are not commonly used in the production of solid-state rectifiers because they do not have the electrical properties required to function as semiconductor materials. Arsenic is a semiconductor material that is sometimes used in the production of solid-state rectifiers, but it is not as widely used as silicon due to its high toxicity.

In conclusion, solid-state rectifiers are primarily made of silicon, which is an affordable, widely available, and highly conductive semiconductor material that is used to create the PN junction required for the device to function as a one-way valve.

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Ribosomes link together amino acids to synthesize proteins.

Amino acids are the building blocks of proteins, and ribosomes play a crucial role in protein synthesis by facilitating the formation of peptide bonds between amino acids. Macronutrients such as carbohydrates (monosaccharides), fats (both saturated and unsaturated fatty acids), and proteins themselves are involved in various biological processes, but specifically, ribosomes use amino acids to create proteins.

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Answer:

1 mol of O2

Explanation:

n = m/ M

n = 32/ ( 2× 15.999)

n= 1 mol of O2

The correct answers about the matter are:

Horizontal:

4. Substance

8. States of Matter

9. Compound

11. Chemical Reaction

12. Conversion Factor

15. Mass

18. Heterogeneous

20. Mixture

Vertical:

1. Density

2. Matter

22. Product

5. Reactivity

6. Homogeneous

7. Quantity

10. Unit

13. Weight

14. Pure Substance

16. Atom

17. Volume

19. Element

21. Physical Property

22. Molecule

23. Reactant

Matter is the substance that makes up all physical objects, including living things and non-living things.

Matter can exist in several states, including solid, liquid, and gas, and can undergo physical and chemical changes. It is made up of tiny particles, such as atoms and molecules, which interact with each other through various physical and chemical processes.

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Answer:

The independent variable effects the dependent variable.

Explanation:

The independent variable Is what you change whereas the dependent variable would change because of that.

for example, the indipendent variable could be how much you water a plant in ml each day, and the dependent variable would be how tall each plant grown]s with that water doseage per day.

Answer: Copper is a key component of state-of-the-art energy, aerospace, transportation, and telecommunications systems throughout the world.

Explanation:

Copper mining and processing provide jobs and economic benefits to communities throughout Arizona.

Copper is one of the four C's in Arizona because it is one of the state's primary industries. The other three C's are cotton, cattle, and citrus. Arizona is a major copper-producing state, with mines and processing facilities located throughout the state. In fact, Arizona produces more copper than any other state in the United States, and it is one of the largest copper-producing regions in the world. Copper mining and processing provide jobs and economic benefits to communities throughout Arizona.

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The number of mole of ethanol present in the sample is 0.005 mole

The mole of a substance is related to it's mass and molar mass according to the following equation

Mole = mass / molar mass

With the above formula, we can obtain the mole of ethanol

Mole = mass / molar mass

Mole of ethanol = 0.2301 / 46

Mole of ethanol = 0.005 mole

Complete question

A sample of ethanol (C2H6O) has a mass of 0.2301 g. Complete combustion of this sample causes the temperature of a bomb calorimeter to increase by 1.33°C. The calorimeter has a mass of 2.000 kg and a specific heat of 2.45 J/g•°C. How many moles of ethanol are present in the sample?

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Concentrated solution that it would take to prepare 2.65 l of 0.515 m Hcl upon dilution with water is 131 ml.

A solution  that has a relatively large amount of dissolved solute is known a concentrated solution .

As we know,

And , moles of hydrochloric acid =  M₁ * V₁= M₂ * V₂

Now, V₁ =   V₂ * M₂/M₁

Given,

M₂ = 0.515 M

V₂ =2.65 L

As the hydrochloric acid can be concentrated up to 38% p/V ,

Therefore, maximum M₁ =38% p/V = 38 gr/ 0.1 L / 36.5 gr/mol = 10.41 M

Now, min V₁ =   V₂ * M₂/ max M₁

=  2.65 L* 0.515 M/ 10.41 M

= 0.131 L

= 131 ml

So, the quantity required can go from 131 ml up to 2900 ml ( if M₁ = M₂)

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Answer:

I THINK expose all six plants to green light

Explanation:

The net ionic equation for the behavior of ethylamine (C₂H₅NH₂) as a Bronsted-Lowry base in water is:

C₂H₅NH₂ + H₂O → C₂H₅NH₃⁺ + OH⁻

The net ionic equation for the behavior of benzoic acid (C₆H₅COOH) as a Bronsted-Lowry acid in water is:

C₆H₅COOH + H₂O → C₆H₅COO⁻ + H₃O⁺

In water, ethylamine (C₂H₅NH₂) can act as a Bronsted-Lowry base by accepting a proton (H⁺) from water. The reaction can be represented by the net ionic equation: C₂H₅NH₂ + H₂O → C₂H₅NH₃⁺ + OH⁻. In this equation, ethylamine (C₂H₅NH₂) accepts a proton from water (H₂O) to form the ethylammonium ion (C₂H₅NH₃⁺) and hydroxide ion (OH⁻). This shows the base behavior of ethylamine as it accepts a proton.

On the other hand, benzoic acid (C₆H₅COOH) can act as a Bronsted-Lowry acid in water by donating a proton (H⁺) to water. The reaction can be represented by the net ionic equation: C₆H₅COOH + H₂O → C₆H₅COO⁻ + H₃O⁺.

In this equation, benzoic acid (C₆H₅COOH) donates a proton to water (H₂O) to form the benzoate ion (C₆H₅COO⁻) and hydronium ion (H₃O⁺). This demonstrates the acid behavior of benzoic acid as it donates a proton.

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Answer:

D atoms of the same element which have different numbers of neutrons

Explanation:

Isotopy is the existence of two or more atoms of the same element having the same atomic number but difference mass number due to differences in the number of neutrons in their various nuclei.

The concentration of ammonium ion in the given reaction is  0.734M. There are many types of molar (quantity) concentration, including normal  concentration as well as osmotic concentration.

Concentration in chemistry is calculated by dividing a constituent's abundance by the mixture's total volume. Weight concentration, molar concentration, integer concentration, or volume concentration are four different categories of mathematical description. Any type of chemical combination can be referred to by the term "concentration," however the solvents and solutes in solutions are most usually mentioned.

NH\(_4\)Cl(s) → \(NH_4^+\) (aq) + \(Cl^-\)(aq)

ΔGrxn, for the reaction is = –9.27 kJ/mole

ΔG°rxn = -7.74 kJ/mole

T = 250C = 298K

ΔGrxn = ΔG°rxn + RT(lnQ)

Q= e^ ((ΔGrxn - ΔG°rxn)/RT)

Q = e^(–9.27 kJ/mole – ( -7.74 kJ/mole)/8 .314 J/K·mole x 298K

Q = 0.53929

Q = [ \(NH_4^+\)][ \(Cl^-\)]

Q = x²

√Q = x

x = √0.53929

[NH4+] = 0.734M

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Answer:

A, Condensation

Explanation:

I got it correct :)

As per the given problem, 400 kg of a solution containing 35 wt % acetic acid in water is contacted with 400 kg of pure isopropyl ether. We need to calculate the amounts and compositions of the extract and raffinate layers, and the percentage of acetic acid removed.

Using the lever-arm rule, we can determine the amounts of the extract and raffinate layers. Since the two solvents are being mixed in equal quantities, the total weight of the system is 800 kg. The lever arm for the isopropyl ether is 1, and for the acetic acid/water solution is (0.35/0.65) = 0.538. Therefore, the weight of the extract can be calculated as (1/1.538) × 400 kg = 259.97 kg, and the weight of the raffinate can be calculated as (0.538/1.538) × 400 kg = 140.03 kg.

To determine the compositions of the extract and raffinate layers, we use the lever-arm rule and the equilibrium data from Appendix A.3. For the extract layer, the lever-arm for isopropyl ether is 1, and for acetic acid, it is (0.90/0.10) = 9. Therefore, the weight percent of acetic acid in the extract layer is (1/10) × 35% = 3.5%. Similarly, for the raffinate layer, the lever arm for isopropyl ether is 0, and for acetic acid, it is (0.04/0.96) = 0.042. Therefore, the weight percent of acetic acid in the raffinate layer is (0.042/1.042) × 35% = 1.48%.

To determine the percentage of acetic acid removed, we need to calculate the amount of acetic acid that remains in the raffinate layer. The weight of acetic acid in the original solution is 0.35 × 400 kg = 140 kg. The weight of acetic acid in the raffinate layer is 0.0148 × 140.03 kg = 2.07 kg. Therefore, the amount of acetic acid removed is 140 kg - 2.07 kg = 137.93 kg. The percentage of acetic acid removed is (137.93 kg/140 kg) × 100% = 98.52%.

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Answer:

here is my answerrrrrrr

Answer:

no

Explanation:

Answer:

protons and neutrons

Explanation:

The nucleus of the atom contains protons and neutrons. The electrons of the atom orbit the nucleus.

Sample of helium gas initially at 37.0 c, 785 torr and 2 l was heated to 58.0c while the volume expanded to 3.24 l .The final pressure of the helium gas is 8.66 atm.

Helium is a chemical element with the symbol He and atomic number 2. It is the second lightest and second most abundant element in the universe. Helium is a colourless, odourless, tasteless, non-toxic, inert monatomic gas. It is the most common element in the universe, making up about 24% of its mass.

The ideal gas law can be used to solve this problem. The ideal gas law states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles of the gas, R is the ideal gas constant, and T is the temperature.We can rearrange the equation to P = (nRT)/V.

We know the values of n, R, V, and T. n is 1 mol of helium, R is 0.0821 atm∙L/mol∙K, V is 3.24 L, and T is 58.0 °C, which is equal to 331.15 K.

Plugging these values into the equation, we get:

P = \((1 mol*0.0821 atm∙L/mol∙K*331.15 K)/3.24 L = 8.66 atm\)

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The molecular formula is \(\rm C_2O_8\). The empirical formula is \(\rm C_2H_1_2O_6\) which is the simplest from.

Molecular formula is defined as  a chemical formula that gives the total number of atoms of each element in each molecule of a substance.

It can also be defined as a formula derived from molecules that indicates the total number of individual atoms in the molecule of a compound.

Empirical formula is defined as a chemical formula that depicts the simplest elemental ratio of a compound rather than the total number of atoms in the molecule.

Molecular formula = n - empirical formula

Thus, the molecular formula is \(\rm C_2O_8\). The empirical formula is \(\rm C_2H_1_2O_6\) which is the simplest from.

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Here are some general steps you can follow to write a lab report:

Understand the purpose of the lab report: Before you begin writing, make sure you understand the purpose of the lab report. What are the objectives of the experiment? What are the research questions being investigated? What hypothesis is being tested?

Gather your data: Make sure you have all the data you need to write your report. This includes raw data, observations, and any notes you took during the experiment. Organize your data in a clear and logical manner so that you can easily refer to it when writing your report.

Write an outline: Create an outline for your report that includes the main sections you need to cover. These typically include an introduction, methods, results, discussion, and conclusion.

Write the introduction: The introduction should provide an overview of the experiment and explain its significance. You should also provide some background information to help the reader understand the context of the experiment.

Write the methods: In the methods section, describe the experimental design, materials used, and procedures followed. Be sure to include enough detail so that someone else could repeat the experiment.

Write the results: In the results section, present your data in a clear and organized manner. Use tables, graphs, and figures to help illustrate your findings. Make sure to include any statistical analyses you performed.

Write the discussion: In the discussion section, interpret your results and explain what they mean. Discuss any patterns or trends you observed and explain how they relate to the research question. Compare your results to previous research in the field, and discuss any limitations or potential sources of error.

Write the conclusion: The conclusion should summarize the main findings of the experiment and explain their significance. You should also discuss any future directions for research in the field.

Proofread and revise: Once you have completed your first draft, proofread your report carefully to check for errors and inconsistencies. Revise your report as necessary to make sure it is clear, concise, and well-organized.

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i think it is D

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The enthalpy of the reaction is 14 J/mol.

The enthalpy of a reaction (ΔH) is the amount of energy transferred between a system and its surroundings during a chemical reaction at constant pressure, measured in joules per mole (J/mol). This value is important because it can tell us whether a reaction is exothermic or endothermic, as well as give us information about the strength of chemical bonds within the reactants and products.To calculate the enthalpy of a reaction, we need to know the amount of energy released or absorbed (Q) and the number of moles of the compound involved in the reaction (n). We can use the equation:
ΔH = Q/n
Given that 6 moles of a compound produce 84 J of energy, we can calculate the enthalpy of the reaction as follows:
ΔH = Q/n
ΔH = 84 J / 6 mol
ΔH = 14 J/mol
This means that for every mole of the compound involved in the reaction, 14 J of energy is transferred between the system and the surroundings. Since the value is positive, we can conclude that the reaction is endothermic, meaning that it requires an input of energy to occur.It is worth noting that the enthalpy of a reaction can depend on a number of factors, such as temperature, pressure, and the specific conditions under which the reaction occurs. As such, it is important to take these factors into account when calculating or predicting enthalpy values.

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Answer: °32= 0 °C.

Explanation:

Answer:

Explanation:

Please add the temperature readings from all three trials for both thermometers. Will do the calculation with readings.

The vapor pressure of the solution is 311.5 torr.

To find the vapor pressure of the solution, use the Raoult's Law.

Raoult's law is a thermodynamic law that relates the vapor pressure of an ideal solution to the mole fraction of the solvent and the vapor pressure of the pure solvent. It states that the vapor pressure of an ideal solution is equal to the mole fraction of the solvent multiplied by the vapor pressure of the pure solvent.

Mathematically, Raoult's law can be expressed as:

P_A = X_A * P^o_A

where P_A is the vapor pressure of the solvent in the solution, X_A is the mole fraction of the solvent, P^o_A is the vapor pressure of the pure solvent.

Mole fraction acetone = 5.81g/mol / (5.81g/mol + 11.9g/mol) = 0.329

Mole fraction chloroform = 11.9g/mol / (5.81g/mol + 11.9g/mol) = 0.671

Vapor Pressure of the solution = (0.329) * (345 torr) + (0.671) * (293 torr) = 311.5 torr.

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