using point Q as the center of dilation.

Point Q is the center of dilation. Line segment A B is dilated to create line segment A prime B prime. The length of Q A is 1.25 and the length of A A prime is 1.25.

What is the scale factor?

1
1.25
2
2.5

Answer:

k = N/4

Step-by-step explanation:

N = k +4

since we are to make k the subject

therefore divide both side by 4

To make k the subject of the equation N=k+4, subtract 4 from both sides. The equation then becomes 'k=N-4'. This represents the number of groups (k) in terms of the total number of cases (N).

To make k the subject of the equation N=k+4, you need to isolate k on one side. This is done by reversing operations applied to k. In this case, the operation applied to k is addition, so to reverse it, you need to subtract.  

Step-by-step process:    

So, k is equal to N-4. In other words, the number of groups (k) is equal to the total number of cases (N) minus 4.

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To determine the vertices of image U′V′W′ after a 180° counterclockwise rotation, we can apply the following transformation rules:

Using these rules, we can find the vertices of image U′V′W′ as follows:

Therefore, the vertices of image U′V′W′ after a 180° counterclockwise rotation are U′(0, -2), V′(1, -3), and W′(3, -3).

So, the answer is option (b) U′(0, −2), V′(1, −3), W′(3, −3).

(a) tangent line to the graph of f(x) = x^3 at the point (4,2).

(b) equation of the tangent line to the graph of f(x) = x^2 - x at the point (4,12).

(a) To find the equation of the tangent line to the graph of f(x) = x^3 at the point (4,2), we need to find the slope of the tangent line at that point. We can do this by taking the derivative of f(x) with respect to x and evaluating it at x = 4. The derivative of f(x) = x^3 is f'(x) = 3x^2. Evaluating f'(x) at x = 4 gives us the slope of the tangent line. Once we have the slope, we can use the point-slope form of a linear equation to write the equation of the tangent line.

(b) Similarly, to find the equation of the tangent line to the graph of f(x) = x^2 - x at the point (4,12), we differentiate f(x) to find the derivative f'(x). The derivative of f(x) = x^2 - x is f'(x) = 2x - 1. Evaluating f'(x) at x = 4 gives us the slope of the tangent line. Using the point-slope form, we can write the equation of the tangent line.

In both cases, the equations of the tangent lines will be in the form y = mx + b, where m is the slope and b is the y-intercept.

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Answer:

Terminating

Step-by-step explanation:

We know that 12 inches is 1 foot. We can divide to find how many feet we have.

21 / 12 = 1.75

Since the decimal ends at 0.05, the decimal is terminating.

Best of Luck!

Answer:

12/5

Step-by-step explanation:

4/5 divided by 1/3

=4/5*3/1

=4/5*3

=12/5

The zeros of the function are x=−2, 1, and 1/3

The function f(x)=3x³ - 7x² - 19x has at least one rational zero because the constant term, 7, is divisible by 7. This means that the function must also have a zero that is a factor of 7.

We can use the Rational Root Theorem, We can test each of these possible roots to see if they are actually zeros of the function. We can find that x = 1/3 is a zero or the function.

Substituting the values into a quadratic formula, we will get:

x = (-3 + ✓1) / 2

x = -2 , 1.

Therefore, the zeros of the function are x=−2, 1, and 1/3

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There are 2 pounds of apples Hannah buy for the cost for her purchase to be the same from both stores.

Given that;

At Giant Eagle, a box of cereal costs $2.89 and apples cost $1.29 per pound.

And, At Shop & Save, the apples are $1.05 per pound and a box of

cereal is $3.37.

Now,

Let number of pounds of apples can Hannah buy for the cost for her purchase to be the same from both stores = x

So, We can formulate;

For, At Giant Eagle, a box of cereal costs $2.89 and apples cost $1.29 per pound.

The total cost is,

⇒ $2.89 + $1.29x

And, For Shop & Save, the apples are $1.05 per pound and a box of

cereal is $3.37.

Total cost is,

⇒ $3.37 + $1.05x

Now, We can equate both the equation to find the number of pounds of apple to buy.

⇒ $3.37 + $1.05x = $2.89 + $1.29x

⇒ 3.37 + 1.05x = 2.89 + 1.29x

⇒ 3.37 - 2.89 = 1.29x - 1.05x

⇒ 0.48 = 0.24x

⇒ x = 0.48 / 0.24

⇒ x = 2

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Answer: 35≤ x ≤95  

x ≤ 2y

y≤125

Step-by-step explanation:

In an optimization problem, a constraint is a condition with variables that the solution must meet.

Let x = Number of cinnamon strawberry raisin buns.

y =  Number of cinnamon chocolate mango buns baked.

"at least 35 and not more than 95 cinnamon  strawberry raisin buns per day."

⇒ 35≤ x ≤95  

"cinnamon strawberry raisin buns cannot exceed twice the number of cinnamon chocolate mango buns baked."

⇒ x ≤ 2y

" cinnamon strawberry raisin buns cannot exceed 125 per day"

⇒ y≤125

Hence, the constraints are:

35≤ x ≤95  

x ≤ 2y

y≤125

The probability that it takes at most 1 hour of machining time to produce a randomly selected component is approximately 0.00003 or 0.003%.

To solve this problem, we need to first calculate the total mean and standard deviation for the machining time of a single component.

The total mean machining time can be found by adding the means for each component:

30 + 20 + 15 = 65 minutes

The total standard deviation can be found using the formula:

\(\sqrt{((1^2 + 2^2 + 1.2^2)/3)} = 1.247 minutes\)

Now we need to find the probability that it takes at most 1 hour (60 minutes) to produce a randomly selected component. We can use the standard normal distribution to calculate this probability.

z-score = (60 - 65) / 1.247 = -4.01

Using a standard normal distribution table, we can find that the probability of a z-score being less than or equal to -4.01 is approximately 0.00003.

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Using inferential statistics, it is found that the option that is best surveyed from the collected in the survey is given by:

D. The Number of students who prefer cookies and cream is higher than the number of those who prefer chocolate and those who prefer strawberry.

An inferential statistic is one that makes inference or predictions about a population based on a sample.

From the table, we have that cookies and cream is the most popular flavor, hence the correct option is:

D. The Number of students who prefer cookies and cream is higher than the number of those who prefer chocolate and those who prefer strawberry.

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Answer:   36/\(K^{2}\)

Step-by-step explanation:

The k on top will cancel the k to the second power.

So the only number in the numerator is 1.

Then the 1 qill go away because you cant divide anything by 1.

The expoenet -2 that was at the top near K will become positive.

Then distribute

Answer:

D is (-4, -4)

Step-by-step explanation:

M = (x1 + x2)/2

-3 = (-2 + x2)/2

-6 = -2 + x2

x2 = -4

M = (y1 + y2)/2

-7 = (-10 + y2)/2

-14 = -10 + y2

y = -4

I. The mean οf A is less than the mean οf,

Thus Optiοns B; I, and II οnly are cοrrect.

The standard deviatiοn is a measurement οf hοw much a grοup οf values vary οr are dispersed. While a high standard deviatiοn suggests that the values are dispersed thrοughοut a wider range, a lοw standard deviatiοn suggests that the values tend tο be clοse tο the established mean.

Here, we have

Given: The mean οf A is less than the mean οf B

The standard deviatiοn οf A is less than B

The area under the curve οf A is less than B

We have tο find the true statement.

Mean οf A is less than B because A's center is tο the left οf B.

The standard deviatiοn οf A is less than B because A's curve is less spread.

The area under the curve is I. Hence,

Hence, Optiοns B; I, and II οnly are cοrrect.

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Step-by-step explanation:

=3√5

thank me later....

Answer:

Hope this helps you.look it once.

Answer:

I cant see anything how am i supposed to do work and i answer most people questions if you go to my profile so you know i aint lieing

Answer:

8 balloons

Step-by-step explanation:

We want to find how many she kept for herself.

She brought 24 balloons to the picnic.

She gave 1/3 to Karen.

She will be left with 2/3 of the balloons:

2/3 * 24 = 16

She will be left with 16 balloons.

She gave 1/2 of what was left to Tim. She will be left with 1/2 of the balloons:

1/2 * 16 = 8

She will be left with 8 balloons.

The surface integral of f over the unit sphere is (4π/15) (3 k), where k is the unit vector in the z-direction. The answer is independent of the specific parameterization of the sphere and only depends on the surface itself.

To evaluate the surface integral of f over the unit sphere, we need to use the formula:

∫∫S f · dS = ∫∫R f(φ,θ) · ||r(φ,θ)|| sin(φ) dφdθ

Where S is the surface of the unit sphere, R is the region in the parameter domain (φ,θ) that corresponds to S, ||r(φ,θ)|| is the magnitude of the partial derivative of the position vector r(φ,θ), and sin(φ) is the Jacobian factor.

For the unit sphere, we have:

x = sin(φ) cos(θ)
y = sin(φ) sin(θ)
z = cos(φ)

So, we can find the partial derivatives:

r_φ = cos(φ) cos(θ) i + cos(φ) sin(θ) j - sin(φ) k
r_θ = -sin(φ) sin(θ) i + sin(φ) cos(θ) j

Then, we can compute the magnitude:

||r_φ x r_θ|| = ||sin(φ) cos(φ) cos(θ) j + sin(φ) cos(φ) sin(θ) (-i) + sin^2(φ) k|| = sin(φ)

Now, we can substitute into the formula and evaluate the integral:

∫∫S f · dS = ∫0^π ∫0^2π (sin^3(φ) cos^3(θ) i + sin^3(φ) sin^3(θ) j + sin^3(φ) cos^3(φ) k) · sin(φ) dφdθ
= ∫0^π ∫0^2π sin^4(φ) (cos^3(θ) i + sin^3(θ) j + cos^3(φ) k) dφdθ

To integrate over θ, we can use the fact that cos^3(θ) and sin^3(θ) are odd functions, so their integral over a full period is zero. Thus, we get:

∫∫S f · dS = ∫0^π (1/5) sin^5(φ) (3 cos^3(φ) k + 2 sin^3(φ) i + 2 cos^3(φ) j) dφ
= (4π/15) (3 k)

Therefore, the surface integral of f over the unit sphere is (4π/15) (3 k), where k is the unit vector in the z-direction. The answer is independent of the specific parameterization of the sphere and only depends on the surface itself.

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Answer:

I think the moon is seven and the star is 4.

Step-by-step explanation:

Answer:

0.5

Step-by-step explanation:

Answer:

\(\sqrt{22}\approx5\)

Step-by-step explanation:

We know that \(\sqrt{16}=4\) and \(\sqrt{25}=5\), so since 22 is closest to 25, then we can say that \(\sqrt{22}\approx5\)

Answer:

x/6   = 3/2

Step-by-step explanation:

(1.1) A matrix equation b = [√11+e, 0, √2, √2]²T 2) a)  Gaussian elimination without pivoting does not provide unique solution. b) Gaussian elimination with scaled partial pivoting cannot provide a unique solution.(c) Basic LU decomposition is x = [0.788, -3.12, 0.167, 4.55]²T.

The given linear system can be written in matrix form as:

A × x = b

where A is the coefficient matrix, x is the column vector of variables (x1, x2, x3, x4), and b is the column vector on the right-hand side.

The coefficient matrix A is:

A = [[0, -e, √2, -√3],

[π², e, -e², 3/7],

[√5, -√6, 1, -√2],

[π³, e², -√7, -1/9]]

The variable vector x is:

x = [x1, x2, x3, x4]²T

The right-hand side vector b is:

b = [√11+e, 0, √2, √2]²T

(1.2) Solving the system using:

(a) Gaussian elimination without pivoting:

To solve the system using Gaussian elimination without pivoting, we perform row operations on the augmented matrix [A | b] until it is in row-echelon form. Then back-substitute to find the values of x.

The augmented matrix [A | b] is:

[0, -e, √2, -√3 | √11+e]

[π², e, -e², 3/7 | 0]

[√5, -√6, 1, -√2 | √2]

[π³, e², -√7, -1/9 | √2]

Performing row operations, the row-echelon form:

[π², e, -e², 3/7 | 0]

[0, -e, √2, -√3 | √11+e]

[0, 0, 0, 0 | 0]

[0, 0, 0, 0 | 0]

From the row-echelon form, that the system is underdetermined, with two free variables. Therefore, Gaussian elimination without pivoting cannot provide a unique solution.

(b) Gaussian elimination with scaled partial pivoting:

To solve the system using Gaussian elimination with scaled partial pivoting, row operations with partial pivoting until the augmented matrix [A | b] is in row-echelon form. Then back-substitute to find the values of x.

The augmented matrix [A | b] is:

[0, -e, √2, -√3 | √11+e]

[π², e, -e², 3/7 | 0]

[√5, -√6, 1, -√2 | √2]

[π³, e², -√7, -1/9 | √2]

Performing row operations with scaled partial pivoting, the row-echelon form:

[π³, e², -√7, -1/9 | √2]

[0, -e, √2, -√3 | √11+e]

[0, 0, -0.03, -1.02 | 0.027]

[0, 0, 0, 0 | 0]

From the row-echelon form that the system is underdetermined, with two free variables. Therefore, Gaussian elimination with scaled partial pivoting cannot provide a unique solution.

(c) Basic LU decomposition:

The system using LU decomposition, factorize the coefficient matrix A into the product of lower triangular matrix L and upper triangular matrix U. Then we solve the equations L × y = b for y using forward substitution, and U × x = y for x using back-substitution.

The coefficient matrix A is:

A = [[0, -e, √2, -√3],

[π², e, -e², 3/7],

[√5, -√6, 1, -√2],

[π³, e², -√7, -1/9]]

Performing LU decomposition,

L = [[1, 0, 0, 0],

[π², 1, 0, 0],

[√5, 0.3128, 1, 0],

[π³, 4.3626, 2.4179, 1]]

U = [[0, -e, √2, -√3],

[0, e + π², -e² + e × π², 3/7 - e × √2],

[0, 0, 0.9693, -0.3651],

[0, 0, 0, -2.2377]]

Solving L × y = b for y using forward substitution:

[1, 0, 0, 0] ×y = √11+e

[π^2, 1, 0, 0] × y = 0

[√5, 0.3128, 1, 0] × y = √2

[π^3, 4.3626, 2.4179, 1] × y = √2

Solving the above equations,

y = [0.788, -3.12, 0.167, 4.55]²T

Now, solving U × x = y for x using back-substitution:

[0, -e, √2, -√3] × x = 0.788

[0, e + π², -e² + e × π², 3/7 - e ×√2]× x = -3.12

[0, 0, 0.9693, -0.3651] ×x = 0.167

[0, 0, 0, -2.2377] ×x = 4.55

Solving the above equations,

x = [0.788, -3.12, 0.167, 4.55]²T

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Given that the outermost scoring circle on the regulation dartboard is divided into twenty congruent sections, you need to remember that, by definition, a circle has 360 degrees.

Let be "m" the measure (in degrees) of each arc in the given circle.

Knowing that the outermost scoring circle is divided into 20 equal parts, you need to divide 360 degrees by 20, in order to find the value of "m". Then, you get:

Hence, the answer is:

a. The expression for dτ/dP is (-P(q)q) / ((1 - τ)q - dC(q)/dP).

a. To derive an expression for dτ/dP, we need to differentiate the profit function with respect to τ and P. Let's assume that P(q) is the price function and C(q) is the cost function. The profit function is given by:

π = (1 - τ)P(q)q - C(q)

Differentiating π with respect to τ, we get:

dπ/dτ = -P(q)q

Next, let's differentiate π with respect to P:

dπ/dP = (1 - τ)(dP(q)/dP)q + P(q)(dq/dP) - dC(q)/dP

Since dP(q)/dP = 1 and dq/dP = 0 (monopolist's quantity does not depend on price), the above expression simplifies to:

dπ/dP = (1 - τ)q - dC(q)/dP

Finally, to find dτ/dP, we divide dπ/dτ by dπ/dP:

dτ/dP = (dπ/dτ) / (dπ/dP) = (-P(q)q) / ((1 - τ)q - dC(q)/dP)

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The x-component, y-component, and magnitude of the vector -3.5A.

(a) To find the x-component of the vector -3.5A, we need to multiply the x-component of vector A by -3.5. The x-component of vector A can be found using the formula:

x-component = |A| * cos(θ), where |A| is the magnitude of vector A and θ is the angle it makes with the positive x-axis. Substituting the given values, we have: x-component = 56.8 m * cos(145°).

Evaluating this expression gives us the x-component of -3.5A.

(b) To find the y-component of the vector -3.5A, we multiply the y-component of vector A by -3.5.

The y-component of vector A can be found using the formula: y-component = |A| * sin(θ), where | A| is the magnitude of vector A and θ is the angle, it makes with the positive x-axis.

Substituting the given values, we have:

y-component = 56.8 m * sin(145°). Evaluating this expression gives us the y-component of -3.5A.

(c) The magnitude of the vector -3.5A can be found using the Pythagorean theorem: |-3.5A| = √((x-component)^2 + (y-component)^2).

By substituting the calculated values of the x-component and y-component into this equation, we can find the magnitude of -3.5A.

By evaluating these expressions, we can determine the x-component, y-component, and magnitude of the vector -3.5A.

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Answer:

−12 if simplfied .

Step-by-step explanation:

The number of cans required to paint an area of 2000 square units is equal to 5 cans.

As given in the question,

Total area to be painted is equal to 2000 square units.

Area covered by one can of paint is equal to 400 square units

400 square units = 1 can of paint

⇒ 1 square units = ( 1 / 400 ) cans of paint

⇒ 2000 square units =  ( 2000 / 400 ) cans of paint

⇒ 2000 square units = 5 cans of paint

Therefore, the number of cans required to paint an area of 2000 square units using given can is equal to 5 cans.

The above question is incomplete, the complete question is:

How many cans of paint are needed to cover an area of 2000 square units if one can of paint covers in area 400 square units?

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Answer:

The answer would be -2 1/6

Step-by-step explanation:

The arrow goes to the left side because it is negative. -1/3 would be equal to -2/6. -5/6 + -1/6 + -1/6 = -1 1/6. Add the 1 and you get -2 1/6!

Hope this helped ^^

Answer:

1/3

Step-by-step explanation:

Answer:

1/3

Step-by-step explanation:

In this graph, the line rises 1 and runs 3.

Translation: every time the line goes up 1 unit, it moves to the right 3 units.

I hope this helped and please mark me as brainliest!