Torque created by the weight of the beam about the new reference axis is 224 N*m.
To calculate the torque created by the weight of the beam about the new reference axis, we need to first find the perpendicular distance between the weight of the beam and the new reference axis. This distance is equal to the original distance between the weight of the beam and the original reference axis .
Adding 2 m to this gives us a perpendicular distance of 3.2 m.
Therefore, the torque created by the weight of the beam about the new reference axis is:
\(Torque = Force * Perpendicular Distance\\Torque = 70 N * 3.2 m\\Torque = 224 N*m\)
The torque created by the weight of the beam about the new reference axis is 224 N*m.
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Adam is driving his truck at 18 m/s for a distance of 46 m, how much time was Adam driving?
Answer:
2.6 seconds
Explanation:
You have to divide the distance by the velocity to find the time:
46/18 = 2.55 ≈ 2.6 seconds
The answer you are looking for is approximately 2.6 seconds.
Solution/Explanation:
To get the correct answer, you must divide the distance and velocity.
This means that 46÷18=2.5556.
2.5556≈2.6.
So, therefore, the final answer is approximately 2.6 seconds.
I hope that this has helped you. Enjoy your day, and take care.
suppose you place 3.31mL of a substance into a graduated cylinder. The graduated cylinder has a mass of 12.55 g when empty and a mass of 15.5 7 g after adding the substance. what is the density of the substance (in g/ml)
The density of the substance is 0.913 grams per milliliter (g/mL).
Density is a measure of how much mass is contained in a certain volume of a substance. It is defined as the mass of a substance divided by its volume. In this problem, we need to calculate the density of a substance given its volume and the mass of the substance and the container it is placed in.
To calculate the density of the substance, we need to first determine the mass of the substance alone. We can do this by subtracting the mass of the empty graduated cylinder from the mass of the cylinder with the substance in it.
The mass of the substance can be calculated as follows:
Mass of substance = Mass of cylinder with substance - Mass of empty cylinder
Mass of substance = 15.57 g - 12.55 g
Mass of substance = 3.02 g
Now that we know the mass of the substance, we can calculate its density using the formula:
Density = Mass / Volume
We were given the volume of the substance as 3.31 mL, so we can plug this into the formula:
Density = 3.02 g / 3.31 mL
Simplifying this expression gives us the density of the substance:
Density = 0.913 g/mL
Therefore, the density of the substance is 0.913 grams per milliliter (g/mL). This means that for every milliliter of the substance, there is 0.913 grams of mass. Density is a fundamental property of a substance that can help us identify or classify it.
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A kid jumping on a trampoline reaches a height of 0.925 m. What was his speed when he left the trampoline?
Answer:
4.26 m/s
Explanation:
h = 0.925
v = 0
u = ?
v = u^2 - 2gh
0 = u^2 - 2gh
u = sqrt 2gh
= sqrt 2*9.8*0.925
= 4.258
= 4.26
if the observation screen is a distance of 5m from the slits, how far apart are the zero order maximum and the third order maximum?
The distance between the zero order maximum and the third order maximum is 6.6 m.
The distance between the zero order maximum and the third order maximum on an observation screen can be calculated using the formula:d = (m * λ) / a,
where , m is the order of the maximum, λ is the wavelength of light used, and a is the separation between the two slits.
The zero order maximum is the center maximum on the screen, and the third order maximum is the third maximum on either side of the center. To find the distance between them, we need to know the wavelength of light and the separation between the slits.If we assume that the light used has a wavelength of 550 nm (a common value for green light), and the separation between the slits is 0.25 mm, the distance between the zero order and the third order maximum can be calculated as follows:d = (3 * 550 * 10^-9) / (0.25 * 10^-3) = 6.6 m
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A small car and a large heavier bus are traveling at the same speed. Which has more momentum?
Answer:
small car since they weigh less than a bus
Explanation:
Problem 3) A 70 ft long, 0. 5 in diameter hose with a roughness of 0. 0009 ft is fastened to a water faucet where the pressure is P1, Determine P1 if there is no nozzle attached and the average velocity in the hose is 6 ft/s Neglect minor losses and elevation changes. Repeat the problem if there is a 0. 25 in diameter nozzle attached to the end of the hose
If there is no nozzle attached and the average hose velocity is 6 ft/s, determine p. Neglect little elevation changes and losses. = 70f7.
Explain about the Velocity?Velocity, as opposed to speed, refers to the pace and direction of an object's movement as it moves down a path. In other words, whereas velocity is a vector, speed is a scalar quantity.
Simply said, velocity is the speed at which an object is moving in a particular direction. using a car travelling north on a highway as an illustration or a rocket after it has taken off as an illustration of speed. Scalar implies that the absolute magnitude of the velocity vector will always equal the speed of the motion.
186,282 miles per second is another way to express the speed of light. In dry air, the speed of sound is 343.2 meters per second.
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PLS ANSWER FAST
California sea lions communicate underwater at frequencies ranging from 500 to 4,000 hertz. The speed of sound in sea water is approximately 1,500 m/s. What are the approximate wavelengths of sound
with which the California sea lions communicate? (1 point)
O 750,000 to 6,000,000 meters
O2,000 to 5,500 meters
O 0.33 to 2.66 meters
O 0.375 to 3 meters
The California sea lions communicate is option C: 0.375 to 3 meters.
To calculate the approximate wavelengths of sound with which the California sea lions communicate, we can use the formula:
Wavelength = Speed of Sound / Frequency
Given:
Speed of Sound in Sea Water = 1,500 m/s
Frequency Range = 500 Hz to 4,000 Hz
For the lower frequency of 500 Hz:
Wavelength = 1,500 m/s / 500 Hz = 3 meters
For the higher frequency of 4,000 Hz:
Wavelength = 1,500 m/s / 4,000 Hz = 0.375 meters
Therefore, the approximate wavelengths of sound with which the California sea lions communicate are approximately 0.375 to 3 meters.
So, the correct answer is option C: 0.375 to 3 meters.
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what is the process of subduction
Answer:
Subduction is a geological process that takes place at convergent boundaries of tectonic plates where one plate moves under another and is forced to sink due to high gravitational potential energy into the mantle. Regions where this process occurs are known as subduction zones.
How do the resistances of two conducting wires compare if they have the same length, but one is twice the radius of the other?.
The thicker wire has one-fourth the resistance of the thinner wire.
What are resistance and resistivity?The characteristic of a substance that prevents the flow of current is known as resistance. The free electrons begin to move in a specific direction when a voltage is applied across the conductor. These electrons collide with atoms or molecules as they move, creating heat in the process. These atoms or molecules prevent free electrons from moving through a substance. Resistance is represented by the symbol R.
Specific resistance is another name for resistivity. A substance with certain dimensions, such as one meter in length and a cross-sectional area of one square meter, has a resistance that is represented by its resistivity. Resistivity or specific resistance is represented by ρ.
The relation between resistance R and resistivity ρ is given as:
R = ρL/A
where,
R = resistance of the conductor
ρ = resistivity of the material
L = length of the conductor
A = cross-sectional area of the conductor
Calculation:Given,
r₁ = 2r₂
L₁ = L₂
where
r₁ = radius of the first conductor
r₂ = radius of the second conductor
L₁ = length of the first conductor
L₂ = length of the second conductor
To find
R₁/R₂ =? (the ratio of R₁ and R₂)
If the radius is twice the other then the area will become,
A₁ = π r₁²
A₂ = π r₂²
A₁ = π (2r₂)²
= 4π r₂²
Therefore,
A₁ = 4 A₂
Now put the values in formula,
R = ρL/A
R₁/R₂ = ρ L₁ A₂/ ρ L₂ A₁
R₁/R₂ = L A₂/ L (4A₂)
R₁/R₂ = 1/4
R₁ = R₂/4
Hence, the thicker wire with twice the radius of thin wire has one-fourth the resistance of the thinner wire.
I understand the question you are looking for is this:
How do the resistances of two conducting wires compare if they have the same length, but one is twice the radius of the other?
(a) The thicker wire has half the resistance of the thinner wire
(b) The resistance is the same in both wires
(c) The thicker wire has one-fourth the resistance of the thinner wire
(d) The thicker wire has twice the resistance of the thinner wire.
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An object moves along a straight line so that at any time t greater than or equal to 0 it's velocity is given by v(t)= 2cos(3t). What is the distance traveled by the object from t=0 to the first time that it stops?
A. 0
B. Pi/6
C. 2/3
D. Pi/3
E. 4/3
The distance traveled by the object from t=0 to the first time that it stops is 2/3. So, option C. is correct.
To find the distance traveled by the object from t=0 to the first time it stops, we first need to determine when the object stops. The object stops when its velocity v(t) is equal to 0:
v(t) = 2cos(3t) = 0
This occurs when cos(3t) = 0.
The first positive value for t that satisfies this equation is when 3t = π/2, which gives us t = π/6.
Now, we need to find the distance traveled. Since we know the velocity function v(t), we can find the position function s(t) by integrating v(t):
s(t) = ∫v(t)dt = ∫2cos(3t)dt
Integrating the function gives:
s(t) = (2/3)sin(3t) + C
As the initial condition is s(0) = 0, we find C = 0.
So, the position function is:
s(t) = (2/3)sin(3t)
Now, we can find the distance traveled by the object from t=0 to t=π/6:
Distance = s(π/6) - s(0)
= (2/3)sin(3(π/6)) - (2/3)sin(0)
= (2/3)sin(π/2) - 0
= (2/3)(1)
= 2/3
So, the correct answer is C option.
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A characteristic of a substance?
A substance could have physical characteristics and chemical ones too, which are unique to the certain substance.
Color, odor, and how hard the substance, are all examples of physical characteristics of a substance.
Toxicity, flammability, and acidity, are all examples of chemical characteristics of a substance.
a driver brings a car to a full stop in 2.0s its acceleration is -11m/s. how far did the car travel while braking
Answer:
22
Explanation:
Dr. Clairmont will have his psychology students training dogs from the local animal shelter to sit using various types of reinforcements. One group of students will train the dogs
to sit by giving the dog a treat when it correctly performs. The other group of students will train the dogs to sit by firmly and loudly scolding the dog when it does not correctly
perform. After 3 weeks of training, the dogs will be evaluated to see which group has more dogs that will sit on command.
What might an ethics review committee decide about the proposal?
The proposal is approved, as it meets the ethical guidelines related to animal research.
The proposal is approved, because while the animals suffer harm, the human participants suffer no psychological harm.
The proposal is denied, because the animal participants suffer physical harm.
The proposal is denied, because the animal participants cannot leave the study
The proposal is denied, because the human participants are deceived
Answer:
A. The proposal is approved, as it meets the ethical guidelines related to animal research
Explanation:
Use process of elimination:
B. The proposal is approved, because while the animals suffer harm, the human participants suffer no psychological harm.
This can't be true because while the human participants suffer no psychological harm, there is no evidence that shows that animals suffer any harm in the experiment.
C. The proposal is denied, because the animal participants suffer physical harm.
Again, there are no animals that suffer physical harm.
D. The proposal is denied, because the animal participants cannot leave the study
There is no evidence that shows that animal participants cannot leave the study.
E. The proposal is denied, because the human participants are deceived
In what way could the human participants be decieved? This is not true.
By using process of elimination(and of course your psychology lesson) you will find that the answer is A.
...Plus, I also took the test and that's the answer. :)
A cyclist sitting still at the top of a hill displays gravitational potential energy. What makes it possible for the cyclist to have this type of energy?
Explanation:
because its speed (v) is 0
A straight wire carries a 10.0 A current (Fig. E28.9). ABCD is a rectangle with point D in the middle of a 1.10 mm segment of the wire and point C in the wire. Find the magnitude and direction of the magnetic field due to this segment at (a) point A; (b) point B; (c) point C
At point A, there is a 1.26 10-6 T magnetic field entering the page.
What is Biot-law, Savart's Statement 1?According to the Biot-Savart equation, the magnetic field generated by a small current element at any given location is proportional to its length, current, and the sine of the angle formed between the current's direction and the line connecting it to the point.
\(r = √[(1.10 mm)² + (0.40 m)²] = 0.400 m\)
\(dB = (μ₀/4π) * (I * dℓ × ẑ) / r²\)
\(= (μ₀/4π) * (I * dℓ × (-ẋ)) / r²\)
\(B = ∫dB = (μ₀/4π) * (I * ℓ / r²) * sin(θ)\)
\(B = (μ₀/4π) * (I * ℓ / r²) = (4π × 10^-7 T m/A) * (10.0 A * 0.40 m / 0.400 m²) = 4π × 10^-7 T = 1.26 × 10^-6 T\)
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Two go carts, A and B race eachother around a 1.0 km track. Go cart A travels at a constant speed of 20.0 m/s. Go cart B accelerates uniformly from rest at a rate of 0.333 m/s 2. Which go cart wins the rice and by how much time?
We have that Since Cart A spends t=77.5secs and Cart B spends t=50sec
Therefore
The Cart A wins the Race and by 25.5( 77.7-50)secs
From the question we are told
Two go carts, A and B race each other around a 1.0 km track. Go cart A travels at a constant speed of 20.0 m/s. Go cart B accelerates uniformly from rest at a rate of 0.333 m/sFor Cart A
Generally the equation for the Velocity is mathematically given as
\(v=\frac{d}{t}\\\\t=\frac{d}{v}\\\\t=\frac{1000}{20}\\\\t=50sec\)
For Cart B
Generally the Newtons equation for the Motion is mathematically given as
\(S=ut+1/2at^2\\\\Therefore\\\\S=ut+1/2at^2\\\\1000=0+1/2*(0.33)t^2\\\\t=\frac{1000}{1/2*(0.33}}\\\\t=77.5secs\)
Since
Cart A spends t=77.5secs and Cart B spends t=50sec
Therefore
The Cart A wins the Race and by 25.5( 77.7-50)secs
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MOTION The period p of simple harmonic motion, such as the swing of a pendulum, can be modeled by p= 2(pi)√m/k where m is mass and k is a constant. Use the properties of logarithms to find the expanded form of log p.
Answer:
Explanation:
use gauthmat is helpful
Consider the electric field lines shown in the diagram below. From the diagram, it is apparent that object A is ____ and object B is ____.
A 15 kg wagon with frictionless wheels carrying a 5 kg mass is moving at a speed of 3.75 m/s when it reaches another frictionless wagon of mas 15 kg. This wagon is attached to a spring of negligible mass which has a spring constant of 250 N/m. The other end of the spring is fixed to the wall. Upon impact the two wagons stick together and compress the spring. Determine the distance the wagons travel until the spring is fully compressed.
The distance the wagons travel until the spring is fully compressed is 2 × xmax = 3.42 m. To solve this problem, we need to apply the principle of conservation of momentum and conservation of energy.
Initially, the momentum of the system is given by:
p1 = (15 kg + 5 kg) × 3.75 m/s = 75 kg m/s
After the collision, the two wagons stick together and move as one unit, with a combined mass of 30 kg. Let v be the common velocity of the two wagons after the collision. Then, the momentum of the system is given by:
p2 = 30 kg × v
According to the principle of conservation of momentum, p1 = p2. Therefore, we have:
75 kg m/s = 30 kg × v
which gives:
v = 2.5 m/s
Now, let's consider the energy of the system. Initially, the kinetic energy of the system is given by:
K1 = (1/2) × (15 kg + 5 kg) × (3.75 m/s)² = 421.875 J
After the collision, the energy of the system is stored in the compressed spring. The potential energy of a spring is given by:
U = (1/2) × k × x²
where k is the spring constant and x is the displacement of the spring from its equilibrium position. At maximum compression, the displacement is xmax, and the potential energy is:
Umax = (1/2) × 250 N/m × xmax²
According to the principle of conservation of energy, the initial kinetic energy of the system is converted to potential energy of the spring at maximum compression. Therefore, we have:
K1 = Umax
which gives:
xmax = sqrt(2 × K1 / k) = 1.71 m
Therefore, the distance the wagons travel until the spring is fully compressed is 2 × xmax = 3.42 m.
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The coldest clouds in the ISM are molecular clouds, so named because their temperatures are low enough and their densities high enough for atoms to join together into molecules. These clouds are capable of collapsing to form new stars, in a stellar nursery like the one in the left image. The Pleiades (right image) is an example of stars that formed recently within such a nursery.
Molecular clouds range in mass from a few times the mass of our Sun (solar masses) to 10 million solar masses. Individual stars range from 0.08 to about 150 solar masses.
What does all of this imply about how stars form from molecular clouds?
Stars form from molecular clouds through a process known as stellar formation.
These clouds, characterized by low temperatures and high densities, provide the ideal conditions for atoms to combine and form molecules. With a mass range spanning from a few solar masses to millions of solar masses, molecular clouds serve as the birthplaces of new stars. The Pleiades cluster serves as a notable example of stars that have recently formed within such a stellar nursery.
The formation of stars from molecular clouds involves several key steps. Firstly, gravitational forces acting on regions of higher density within the cloud cause them to collapse under their own gravity. As the cloud collapses, it begins to fragment into smaller, denser clumps called protostellar cores. These cores continue to collapse, and their central regions become increasingly dense and hot. At this stage, they are known as protostars.
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During a classroom lab activity, students built each of the circuits shown below and measured the current and resistance in each circuit. Each circuit contains a 1. 5-volt battery and each bulb has a resistance of 50 Ω.
When the switch is closed, in which circuit would resistance be the highest and current be lowest?
When the switch is closed, in the third circuit the resistance would be the highest and the current be the lowest.
From the question, we have
Voltage in the circuit, V = 1.5 volts,
The circuit's resistance, R = 50,
In the third diagram, the bulb is connected in parallel, which means that the voltage in the circuit will remain constant. Additionally, because the current depends on the resistor, the resistance in this circuit will be larger.
Additionally, according to Ohm's law, a high resistance will result in a low current flow.
Since there is only one bulb in the first circuit, resistance will be minimal and current flow will be high.
As a result, the third circuit's resistance would be the highest and its current the lowest when the switch is closed.
Current :
The phrase "electric current" is frequently used to describe how much electricity flows through a circuit and how it flows in an electronic circuit. Amperes are used to measure it (A). As more electricity passes through the circuit, the ampere value increases.
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When the switch is closed, in the third circuit the resistance would be the highest and the current be the lowest.
What is current?
When describing how much electricity flows through a circuit and how it flows in an electronic circuit, the term "electric current" is often employed. It is measured in amperes (A). The ampere number rises as more electricity flows through the circuit.
Given:
The Voltage in the circuit, V = 1.5 volts,
The resistance in the circuit, R = 50 Ω,
As you can see in the third diagram, there is a parallel connection of the bulb, so the voltage in the circuit will remain the same and the current depends on the resistor, so there will be higher resistance in this circuit.
And if the resistance is high the current flow will be low, (By Ohm's law)
In the first circuit, there is only one bulb, so resistance will be low, and the current flow will be high.
Therefore, when the switch is closed, in the third circuit the resistance would be the highest and the current be the lowest.
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8. An electrical resistor immersed in a liquid produces 65.0 W of electrical energy for 120
specific heat capacity of the liquid in this temperature range. Assume that negligible h
O
O
O
2.51 x 10³ J/(kg. C°)
1.67 x 106 J/(kg C°)
2.02 x 104 J/(kg. C°)
The specific heat capacity of the liquid is 2.51 x 10³ J/kg⁰C.
Specific heat capacity of the liquidThe specific heat capacity of the liquid is calculated as follows;
Q = mcΔФ
where;
Q is quantity of heat c is specific heat capacitym is mass of the liquidΔФ is change in temperature = 22.54 - 18.55 = 3.99 ⁰Cc = Q/mΔФ
c = (65 x 120)/(0.78 x 3.99)
c = 2.51 x 10³ J/kg⁰C
The complete question is below:
An electrical resistor immersed in a liquid produces 65.0 W of electrical energy for 120 s. The mass of the liquid is 0.780 kg and its temperature increases from 18.55°C to 22.54°C. a) Find the average specific heat capacity of the liquid in this temperature range.
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Because we live in a universe with an accelerating expansion rate, the actual age of the universe is ________ the Hubble time.
Because we live in a universe with an accelerating expansion rate, the actual age of the universe is greater than the Hubble time.
The Hubble time is a measure of the age of the universe based on the current rate of expansion. According to the current best estimates, the Hubble time is around 13.8 billion years. However, the expansion of the universe is accelerating, which means that the universe is expanding faster and faster over time.
Because of this acceleration, the actual age of the universe is greater than the Hubble time. The exact age of the universe is difficult to determine, as it is influenced by a variety of factors, including the density and composition of the universe, the rate of expansion, and the effects of dark energy. However, current estimates suggest that the age of the universe is somewhere between 13.8 billion and 14.2 billion years.
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what is the value of sin square 60
Explanation:
\( \sin(60) = \frac{ \sqrt{3} }{2} \\ \\ \sin(60 ) {}^{2} = ( \frac{ \sqrt{3} }{2} ) {}^{2} \\ \\ \sin(60 ) {}^{2} = \frac{3}{4} \)
everything in the universe is made up of what A.atoms B.minerals C.nitrogen
Answer: A) Atoms.
Explanation:
Answer:
a atoms
Explanation:
what is the density of a 75 g block of wood measuring 12 cm x 8cm x 9cm
Answer:
density is equal to mass divided by volume (m/v)
volume: 12×8×9=864cm³
75÷864=0.09
Answer: 0.09g/cm³
A student conducts three experiments to determine how certain quantities influence the centripetal force responsible for an object to spin in a horizontal circle. The student uses one end of a string to attach the object while the other end is connected to a force sensor that allows the student to change the tension on the string, as shown in the figure. The student records data from the three experiments in the table above. Which of the following experiments, if any, collected data that do not agree with the expression for the net centripetal force on the object?
A)The experiment in which mass was changed
B)The experiment in which the radius of the circular path was changed
C)The experiment in which the speed of the object was changed
D)All the data are expected.
Option C) The experiment in which the speed of the object was changed
is only statement that doesn't satisfy the given data as shown below:
The above statement can be verified using the calculation:
Formula for centripetal force(F) = \(\frac{mv^2}{r}\)
where m is mass of object , v is speed of object and r is radius of the circular motion.
For option A) when only mass of object is changed and rest all are same.
so F = k*m where k = \(\frac{v^2}{r}\) as both are constant
=> \(\frac{F_1}{F_2}\) = 4.04/8.08 = 0.5
and \(\frac{m_1}{m_2}\) = 0.1/0.2 =0.5
so \(\frac{F_1}{F_2} = \frac{m_1}{m_2}\)
similary \(\frac{F_2}{F_3} = \frac{m_2}{m_3}\) and hence data is correct for option A)
For option B) when only radius of object is changed and rest all are
same.
so F = k/r where k = \(m*v^2\) as both are constant
=> \(\frac{F_1}{F_2}\) = 4.04/8.08 = 0.5
and \(\frac{r_2}{r_1}\) = 0.3/0.6 =0.5
so \(\frac{F_1}{F_2} = \frac{r_2}{r_1}\)
so both are same , similary \(\frac{F_2}{F_3} = \frac{r_3}{r_2}\) and hence data is correct for option B
For option C) when only speed of object is changed and rest all are
same.
so F = k*\(v^2\) where k = \(\frac{m}{r}\) as both are constant
=> \(\frac{F_1}{F_2}\) = 4.04/9.09 = 0.44444
and \(\frac{v_1^2}{v_2^2}\) = 4.08/9.181 =0.44439
so ,\(\frac{F_1}{F_2}\) ≠ \(\frac{v_1^2}{v_2^2}\)
and hence data is not correct for option C
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Complete question:
A student conducts three experiments to determine how certain quantities influence the centripetal force responsible for an object to spin in a horizontal circle. The student uses one end of a string to attach the object while the other end is connected to a force sensor that allows the student to change the tension on the string, as shown in the figure. The student records data from the three experiments in the table above. Which of the following experiments, if any, collected data that do not agree with the expression for the net centripetal force on the object?
A)The experiment in which mass was changed
B)The experiment in which the radius of the circular path was changed
C)The experiment in which the speed of the object was changed
D)All the data are expected.
a coil of 40 henry inductance is connected in series with aresistance of 8ohm and the combination is joined to the terminals of a 2 volt battery. the time constant of the circuit is?
Answer: 5 seconds
Explanation:
Given the following :
Inductance (L) = 40 henry
Resistance = 8 ohms
The circuit given above is a Resistor - Inductor (RL) circuit network. The time constant of an RL circuit is the ratio of the circuit Inductance (L) and Resistance (R). Time constant is measured in seconds.
THAT IS;
Time constant = L / R
THEREFORE ;
Time constant = 40 / 8
Time constant = 5 seconds
If researchers failed to take into account the effect of air resistance on the pitch, how would it impact their measurements of the efficiency of energy transfer from the arm to the baseball
The efficiency of energy transfer from the arm to the baseball would be lower than the actual efficiency, as there was a higher initial velocity at release.
In order to answer this question, we must look at the experimental design and assess how air resistance would affect the scientists' computations. The ball's velocity would be reduced as it moved from the mound to home plate, where the velocity was measured, due to air resistance.
Therefore, the measured velocity ought to be lower than the release velocity. As a result of the baseball's predicted energy being lower due to the lowered velocity, the efficiency of the energy transfer from the arm to the ball will also be lower.
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In the diagram of the earth’s interior, which part causes the diffraction of P waves made by earthquakes?
Answer:
D
Explanation: