Answer
Low Fan Speed - 9.0 cm/s2
Medium Fan Speed - 12.0 cm/s2
High Fan Speed - 16.0 cm/s2
Explanation:
Just took that test
The answer is:
Low Fan Speed - 9.0 cm/s2Medium Fan Speed - 12.0 cm/s2High Fan Speed - 16.0 cm/s2How are electromagnetic waves used in a bar-code scanner?
O A. An image is produced when a silicon chip releases electrons by the photoelectric effect. OB. Red light shines on a bar code, and light is reflected according to the black-and-white pattern.
C. Visible light is reflected off an object and then captured by a charge-coupled device.
O D. X-rays shine on objects, and the rays either pass through or are absorbed by the objects.
The electromagnetic waves used in a bar-code scanner by an image is produced when a silicon chip releases electrons by the photoelectric effect and Visible light is reflected off an object and then captured by a charge-coupled device.
What is electromagnetic wave?The electromagnetic wave is the white light or Sunlight coming directly from the Sun. This light ray is the form of wave. This light when falls on any object segregates into the range of all types of EM radiation.
Radiation is packet of energy that travels and spreads out. It has radio waves, infrared waves and visible light waves, ultraviolet rays and microwaves.
Bar code scanner uses the photoelectric effect and visible light reflection phenomenon.
Thus, the correct options are A and C.
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nih cla causes weight loss of about 1.1 pounds (0.52 kg) compared with a placebo. this number increased to 2.3 pounds (1.05 kg) in people over age 44 (47 trusted source).
However, this weight loss seems to be greater in people over the age of 44, with an average of 2.3 pounds (1.05 kg) of weight loss. These findings suggest that nih cla may be more effective for weight loss in older individuals.
The statement you provided mentions that nih cla causes weight loss of about 1.1 pounds (0.52 kg) compared with a placebo. However, this number increases to 2.3 pounds (1.05 kg) in people over the age of 44.
To break it down step-by-step:
1. The first part of the statement says that nih cla causes weight loss of about 1.1 pounds (0.52 kg) compared with a placebo. This means that when people take nih cla instead of a placebo, on average, they lose 1.1 pounds (0.52 kg) more in weight.
2. The second part of the statement mentions that this number increases to 2.3 pounds (1.05 kg) in people over the age of 44. This suggests that older individuals (over age 44) may experience a greater weight loss of 2.3 pounds (1.05 kg) when taking nih cla compared to the placebo.
In summary, nih cla has been found to cause weight loss compared to a placebo, with an average of 1.1 pounds (0.52 kg) overall. However, this weight loss seems to be greater in people over the age of 44, with an average of 2.3 pounds (1.05 kg) of weight loss. These findings suggest that nih cla may be more effective for weight loss in older individuals.
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A thin lens is comprised of two spherical surfaces with radii of curvatures of 34.5 cm for the front side and -26.9 cm for the back side. The material of which the lens is composed has an index of refraction of 1.66. What is the magnification of the image formed by an object placed 42.6 cm from the lens?
The magnification of the image formed by the lens is -0.982.
To determine the magnification of the image formed by the lens, we can use the lens formula:
1/f = (n - 1) * (1/r1 - 1/r2)
Where f is the focal length of the lens, n is the refractive index of the lens material, r1 is the radius of curvature of the front surface, and r2 is the radius of curvature of the back surface.
Given that the radii of curvature are 34.5 cm and -26.9 cm, and the refractive index is 1.66, we can substitute these values into the lens formula to calculate the focal length.
Using the lens formula, we find that the focal length of the lens is approximately 13.54 cm.
The magnification of the image formed by the lens can be determined using the magnification formula:
m = -v/u
Where m is the magnification, v is the image distance, and u is the object distance.
Given that the object is placed 42.6 cm from the lens, we can substitute this value and the focal length into the magnification formula to calculate the magnification.
Substituting the values, we find that the magnification of the image formed by the lens is approximately -0.982.
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For Each Of The Following Scenarios Described Where A Molecule Or Ion Is Moving From One Side Of A Membrane To The Other, Select The Method By Which The Molecule Or Ion Is Moving. Each Answer Can Be Used More Than Once, Or Not At All. A. Simple Diffusion B. Facilitated Diffusion By A Channel Protein C. Facilitated Diffusion By A Carrier/Transport Protein
For Each Of The Following Scenarios Described Where A Molecule Or Ion Is Moving From One Side Of A Membrane To The Other, Option A is correct answer.
Scenario A: Oxygen moving across a plasma membrane Answer: A. Simple Diffusion Scenario B: Glucose moving across a plasma membrane Answer: C. Facilitated Diffusion By A Carrier/Transport Protein Scenario C: Sodium moving across a plasma membrane Answer: B. Facilitated Diffusion By A Channel Protein Scenario D: Water moving across a plasma membrane Answer: A. Simple Diffusion : Simple diffusion allows the nonpolar and small molecules to pass through the plasma membrane without any assistance of proteins. In facilitated diffusion, larger polar molecules or ions move across the membrane through the help of transport proteins. Transport proteins are of two types, channel and carrier proteins. Channel proteins provide an open path for the molecules to move whereas carrier proteins hold the molecules to move across the membrane and change their shape.
Option A is correct answer.
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Increasing your workload a little bit is called?
A progression
B regularity
C overload
D specificity
Answer: A
Explanation:
The frequency, or number of waves that pass a given point per second, of
sound is measured in:
A. hertz
B. meters
C. cycles
D. frequencies
Answer:
Hertz is the answer for this question
A source emits sound at a fixed constant frequency f. If the source moves away from you, and at the same time you run away from the source, the frequency you hear is the same as f.
higher than f.
lower than f.
unrelated to f.
If a source emits sound at a fixed constant frequency f, and it moves away from the observer at the same time as the observer moves away from the source, the frequency the observer hears is lower than f. Hence option lower than f. is correct.
This is due to the Doppler effect. What is the Doppler effect? The Doppler effect is a phenomenon that occurs when a source of waves, such as sound or light, is moving relative to an observer. The Doppler effect causes the observed frequency of the waves to differ from the emitted frequency when the source and observer are moving relative to each other. This change in frequency is due to the compression or stretching of the waves that occurs as the source moves closer or farther away from the observer.
If a source of sound is moving away from an observer, the sound waves become stretched and the frequency of the sound decreases, resulting in a lower pitch. If the source of sound is moving towards the observer, the sound waves become compressed, causing the frequency of the sound to increase, resulting in a higher pitch. This is the reason why an ambulance siren sounds higher-pitched as it approaches the listener and then drops to a lower pitch as it moves away.
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A boy with a ma of 30kg ride a merry go round with a radiu of 1. 5m and a velocity of. 48m/. What i the centripetal force on the boy
Answer:
46,080N
Explanation:
Fc=mv^2/r
Fc=30kg*(48m/s)^2/1.5m
Fc=69,120kg*m^2/s^2/1.5m
Fc=46,080kg*m/s or 46,080N
what is potentiometer
Answer:
potentiometer is a device used to measure potential difference across the circuit
a -0.06 C charge is placed in a uniform electric field with a strength of 200 N/C. what is the magnitude and direction of the force on the charge
The magnitude and direction of the force on the charge is -12 N opposite the electric field
To calculate the force on a charge in an electric field, we make use of the formula below.
Formula
F = E×Q .......................... Equation 1
Where:
F = Force on the chargeE = Electric FieldQ = chargeFrom the question,
Given:
E = 200 N/CQ = -0.06 CSubstitute these values into equation 1
F = 200(-0.06)F = -12 NNote: The negative sign indicates that the force is in the direction negative of the electric field.
Hence, The magnitude and direction of the force on the charge is -12 N opposite the electric field
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Answer: A edge 202694020
Explanation:
A barrel ride at an amusement park
starts from rest and speeds up to
0.520 rev/sec in 7.26 s. What is
the angular acceleration during
that time?
The angular acceleration of the barrel ride at the amusement park during the 7.26 seconds is approximately 0.450 radians/sec².
To determine the angular acceleration of the barrel ride, we need to use the following formula:
angular acceleration (α) = (ω_final - ω_initial) / t
where ω_final is the final angular velocity, ω_initial is the initial angular velocity, and t is the time taken.
In this case, the barrel ride starts from rest, so ω_initial is 0 rev/sec. The final angular velocity, ω_final, is given as 0.520 rev/sec. The time taken, t, is 7.26 seconds.
Before we plug the values into the formula, let's convert the final angular velocity from rev/sec to radians/sec. To do this, we use the conversion factor:
1 rev = 2π radians
So, ω_final = 0.520 rev/sec × 2π radians/rev ≈ 3.265 radians/sec
Now, let's calculate the angular acceleration:
α = (ω_final - ω_initial) / t
α = (3.265 radians/sec - 0 radians/sec) / 7.26 sec
α ≈ 0.450 radians/sec²
Therefore, the angular acceleration of the barrel ride during the 7.26 seconds is approximately 0.450 radians/sec².
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7
Radon-222 is radioactive. It can be represented as 222 Rn.
86
For a neutral atom of radon-222, state
1. the number of protons,
2. the number of neutrons,
3. the number of electrons.
For a neutral atom of radon-222, the number of protons is 86, the number of neutrons is 136, and the number of electrons is 86.
What is a neutral atom?A neutral atom can be described as one in which the amount of the positive charge is equal to the of amount the negative charge. Therefore, the net charge on the atom will be equal to zero. Therefore, such type of atom is said to be a neutral atom.
For a neutral atom, we usually say that the number of electrons in an atom is equal to the number of protons. All chemical elements which are arranged in the modern periodic table are in their neutral state.
Given, the atomic number of Radon-22 is 86.
Atomic number = the number of electrons = Number of protons
The number of electrons for the neutral atom of Rn = 86
The number of protons in Rn-222 = 86
The number of neutrons = 222 - 86 = 136
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Calculate the size of the magnetic field (in µT) at 10.76 m below a high voltage power line. The line carries 450 MW at a voltage of 300,000 V. You should round your answer to the nearest integer.
The magnetic field at 10.76 m below the high voltage power line is approximately 41,835,820 µT when the line carries 450 MW at a voltage of 300,000 V. Rounded to the nearest integer, the magnetic field is 41,836 µT.
To calculate the magnetic field at a distance below a high voltage power line, we use the formula \(B=\frac{u0IH}{2\pi r}\)
Current, I = 450 MW = 450 × 10^6 W
Height, H = 0 m (since the power line is at ground level)
Distance below the power line, r = 10.76 m
Using the formula for the magnetic field, we substitute the given values:
\( B = \frac{{(4\pi \times 10^{-7} \, \text{{T}} \cdot \text{{m/A}}) \cdot (450 \times 10^6 \, \text{{W}}) \cdot (0 \, \text{{m}})}}{{2\pi \cdot 10.76 \, \text{{m}}}} \)
Simplifying the expression:
\( B = \frac{{450 \times 10^6 \, \text{{W}}}}{{10.76 \, \text{{m}}}} \)
Calculating the value:
\( B \approx 41,835,820 \, \text{{T}} \)
Rounding the magnetic field to the nearest integer:
\( B \approx 41,836 \, \mu\text{{T}} \)
Therefore, the magnetic field at 10.76 m below the high voltage power line is approximately 41,836 µT (rounded to the nearest integer).
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Please help I have 10 minutes to submit.
Answer:
(17) B. I think
Explanation:
why is a cement base usually unnecessary beneath a composite resin restoration?
A cement base is usually unnecessary beneath a composite resin restoration because composite resin materials have adhesive properties that allow them to bond directly to the tooth structure.
1. Composite resin is a tooth-colored dental material commonly used for restorations such as fillings, inlays, and onlays.
2. Composite resin materials are composed of a mixture of resin and filler particles, which give them their strength and aesthetic properties.
3. One of the key advantages of composite resin is its ability to bond directly to the tooth structure, creating a strong and durable restoration.
4. The bonding process involves applying an adhesive bonding agent to the tooth surface, which is then cured to create a micromechanical bond between the composite resin and the tooth.
5. This bonding mechanism allows the composite resin to adhere securely to the tooth, creating a tight seal and preventing leakage or microleakage between the restoration and the tooth structure.
6. Additionally, composite resin materials have improved physical properties and wear resistance compared to earlier dental materials, making them suitable for use without a cement base.
7. In contrast, traditional dental materials such as amalgam or glass ionomer cement often require a cement base for retention purposes due to their different properties and mechanisms of retention.
8. The absence of a cement base beneath a composite resin restoration also allows for a more conservative tooth preparation, preserving more of the natural tooth structure.
9. However, it is important to note that in certain cases where the tooth structure is severely compromised or additional support is needed, a cement base or other techniques may be employed in combination with composite resin restorations.
10. Overall, the adhesive properties of composite resin materials eliminate the need for a cement base in most cases, providing a reliable and aesthetic restoration while preserving tooth structure.
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What is the relation between acceleration due to gravity and radius of the earth?
Answer:
As the earth is an oblate spheroid, its radius near the equator is more than its radius near poles. Since for a source mass, the acceleration due to gravity is inversely proportional to the square of the radius of the earth, it varies with latitude due to the shape of the earth.
Formula: g = GM/r2
Dimensional Formula: M0L1T-2
Values of g in SI: 9.806 ms-2
Explanation:
Please Mark me brainliest
Answer:
♡
Explanation:
As the earth is an oblate spheroid, its radius near the equator is more than its radius near poles. Since for a source mass, the acceleration due to gravity is inversely proportional to the square of the radius of the earth, it varies with latitude due to the shape of the earth.
two forces of magnitude 12 n and 24 n act at the same point. which force cannot be the resultant of these forces?
The force that cannot be the resultant of these forces is 10N since it is less than both given forces
Given the forces with a magnitude of 12N and 24N, the resultant of these forces must not be less than any of the two forces.
From the given options, the only force that is less than both 12N and 24 N is 10N. Hence the force that cannot be the resultant of these forces is 10N since it is less than both given forcesLearn more on resultant force here: https://brainly.com/question/14626208
The current in an RL circuit builds up to one-third of its steady state value in 5.20 s. Find the inductive time constant.
To find the Inductive time constant (L/R) in an RL circuit, we can use the formula: t = L/R
where:
t is the time it takes for the current to reach one-third (1/3) of its steady-state value, and
R is the resistance in the circuit.
In this case, we are given that the current builds up to one-third of its steady-state value in 5.20 s. Let's denote this time as t. So, we have t = 5.20 s.
To find the inductive time constant, we need to determine the resistance (R). Unfortunately, the resistance is not given in the question. Therefore, without the value of resistance (R), we cannot calculate the inductive time constant (L/R).
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a car starts from rest and increases its velocity at constant rate until it reaches a speed of 20 m/s in 5 seconds what is the acceleration of the car
Answer:
4m/s²
Explanation:
initial velocity(u)=0m/s
final velocity (v)=20m/s
time taken(t)=5 sec
Acceleration of car(a)=(v-u)/t
=(20-0)/5
= 20/5
=4m/s²
A vibrating tuning fork of frequency 730 Hz is held above a tube filled with water. Assume that the speed of sound is 340 m/s. As the water level is lowered, consecutive maxima in intensity are observed at intervals of about A) 107.4 cm B) 46.6 cm C) 11.6 cm D214.7 cm EU 23.3 cm
The interval between consecutive maxima in intensity is approximately 46.58 cm i.e., the correct answer is B) 46.6 cm.
To determine the interval between consecutive maxima in intensity, we can use the formula:
λ = v/f
where λ is the wavelength, v is the speed of sound, and f is the frequency.
Given that the frequency of the tuning fork is 730 Hz and the speed of sound is 340 m/s, we can calculate the wavelength:
λ = 340 m/s / 730 Hz ≈ 0.4658 m
Now, we need to convert the wavelength to centimeters to match the options provided.
There are 100 centimeters in a meter, so:
0.4658 m × 100 cm/m ≈ 46.58 cm
Therefore, the interval between consecutive maxima in intensity is approximately 46.58 cm.
Among the options provided, the closest one to 46.58 cm is option B) 46.6 cm.
So, the correct answer is B) 46.6 cm.
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Venus has the smallest orbital eccentricity of any of the planets. What is the eccentricity of Venus?(1 point)
Responses
1.0300
0.8040
0.0068
0.0000
The eccentricity of Venus is = 0.0068. That is option C.
What is orbital eccentricity?The orbital eccentricity is defined as the measurement that is used to show how an orbit deviates from the shape of a circle.
The Venus is one of the planets of the universe that is the second closest to the sun.
The Venus is one of the planets that has a small orbital eccentricity being 0.006772 which is approximately 0.0068. This means that it is closest to being circular in shape.
The planets with the largest orbital eccentricity is the planet Mercury with orbital eccentricity of 0.2056.
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a large piece of debris that only partially burns up in the atmosphere, leaving a fragment to hit the surface, is called a
A large piece of debris that only partially burns up in the atmosphere, leaving a fragment to hit the surface is called: a meteorite
When an asteroid or comet fragment encounters the Earth's atmosphere, it is called a meteor. A meteor is a visual phenomenon that occurs when a meteoroid enters the Earth's atmosphere at high speeds and burns up due to friction with the atmosphere.
As it enters the atmosphere, the meteor heats up and begins to glow, producing a streak of light across the sky. Most meteors burn up completely in the atmosphere, but occasionally, a large piece of debris may only partially burn up, leaving a fragment to hit the surface. This is what is referred to as a meteorite.
Meteorites are valuable to scientists because they provide important information about the origins and evolution of our solar system. They can also give insights into the conditions that existed on early Earth and provide clues to the formation of planets.
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since the original discovery of magnetic reversals, scientists have shown that these reversals have occurred over the past 10 million years at an average rate of 4 to 5 reversals per million years. the last such reversal occurred about how many years ago?
The last magnetic reversal occurred around 780,000 years ago.
Geomagnetic reversal is a change in the planet's magnetic field, which means the position of magnetic north and sound are interchanged. It's caused by the rotation of the planet that caused buoyant fluid to rise in curved trajectories. The reversals occur at random. Scientists have known that there have been 183 reversals over the last 83 million years, with the latest occurring around 780,000 years ago (called the Brunhes-Matuyama reversal).
The image below is a supercomputer model of the Earth's magnetic field created by NASA. The left one is a normal magnetic field, and the right one is the magnetic field during the upheaval of a reversal.
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hey guys this is physical science can i get help
answer:
1=c
2= d
3=e
4=a
5=b
a spring with a force of 2.9 n / m has a relaxed 0.85 m distance, when a 0.5 kg mass is attached it stretches to 1.65 m. what is the elastic potential energy?
The calculated answer is 1.96kg * m \s2\s /2. The energy that is stored when a force is used to deform an elastic object is known as elastic potential energy.
Until the force is released and the object springs back to its original shape, doing labor in the process, the energy is retained. The object may be compressed, stretched, or twisted during the deformation. Since you are aware of the spring constant k, which is 144 N/m, and the spring stretch from equilibrium position x, which is 16.5 cm, or 0.165, you can use the equation
PE = 2 1 kx 2
= 2 1144(.165) 2
to determine the potential energy of the spring.
This, if you prefer SI terms, is kg * m 2 /s2, or 1.96 Joules.
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A string under a tension of 170 N has a frequency of 300 Hz.What will its frequency become if the tension is increased to 340 N?
The speed of the wave on a string is given by Taylor's formula:
\(v=\sqrt[]{\frac{F}{\mu}}\)where
F = tension force
μ = linear density = mass per unit length
But also we can say the speed of any wave is given by:
\(v=\lambda\times f\)where:
λ = wave length
f = frequency
Plug the second equation in the first one. We get:
\(\lambda\times f=\sqrt[]{\frac{F}{\mu}}\)Now solve for f:
\(f=\frac{1}{\lambda}\times\sqrt[]{\frac{F}{\mu}}\)Lets say wave length is the same on the second case. Since it's the same string μ will also be the same.
See that 340 N = 2 x 170, so we can write:
\(\begin{gathered} f_{new}=\sqrt[]{2}\times\frac{1}{\lambda}\sqrt[]{\frac{F}{\mu}} \\ f_{new}=\sqrt[]{2}\times f_{old} \\ f_{new}=\sqrt[]{2}\times300 \\ f_{new}\approx424Hz \end{gathered}\)(a) what is the characteristic time constant of a 23.2 mh inductor that has a resistance of 4.21 ω? ms (b) if it is connected to a 12.0 v battery, what is the current after 12.5 ms? a
The current through the circuit after 12.5 ms is 2.5864 A.
The characteristic time constant of a 23.2 mh inductor that has a resistance of 4.21 ω is 5.82115 ms.
If it is connected to a 12.0 v battery, the current after 12.5 ms will be 2.5864 A.
Below are the steps to get to the answer:(a) Calculate the characteristic time constant of the circuit using the formula:τ = L/RWhere τ is the time constant, L is the inductance of the inductor, and R is the resistance of the circuit.tau=23.2mH/4.21Ω=5.82115ms
Hence, the characteristic time constant of the circuit is 5.82115 ms.
(b) To calculate the current through the circuit, we need to use the formula:i = (V/R) [1 - e(-t/τ)]Where i is the current, V is the voltage of the battery, R is the resistance of the circuit, t is the time, and τ is the characteristic time constant of the circuit.i = (12/4.21) [1 - e(-12.5/5.82115)]i = 2.5864
Hence, the current through the circuit after 12.5 ms is 2.5864 A.
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Object A has a stronger gravitational pull than Object B.
Which factors best explain the different gravitational pulls of the two objects?
A. weight and distance
B.mass and distance
C. mass and acceleration
D. distance and acceleration
Answer:
D
Explanation:
i do not know how to explain my answer
What is needed in a market for a good to be considered elastic?
If the amount demand of a product changes more than proportionally as its price rises or falls, then it is said to be elastic.
How is a market made elastic?The more replacements there are for an item, more elastic the good is, according to definition of an elastic good, which is where change in price results in a large movement in demand. Price elasticity of demand is determined by dividing percentage change in quantity required by the percentage change in price.
Products like cars, appliances, and luxury items that are rarely purchased are examples of elastic commodities. In the event that the cost of these products is momentarily high, consumers may decide to put off buying.
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Localized surface plasmon resonance shows the restricted conduction of electrons in the metal nanoparticles due to strong coupling with incident light.
a. True
b. False
The statement that "Localized surface plasmon resonance shows the restricted conduction of electrons in the metal nanoparticles due to strong coupling with incident light" is true.
Localized surface plasmon resonance (LSPR) refers to the collective oscillations of conduction electrons within a nanoparticle in response to incident light. This phenomenon is highly dependent on the size, shape, and composition of the nanoparticle, and can be observed in a variety of metallic materials.
When the LSPR is excited, it results in a strong interaction between the nanoparticle and the incident light, leading to restricted conduction of electrons within the particle.
This is due to the strong coupling between the incident light and the LSPR, which results in a highly localized and intense electromagnetic field around the nanoparticle.
Overall, the LSPR is an important phenomenon in the field of nanotechnology and has numerous applications in sensing, imaging, and energy conversion.
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