Answer:37
Step-by-step explanation:
HELP!! The side of a square is 3 raised to the 5/2 power inches. Using the area formula A = s squared, determine the area of the square.
Answer:
3^5/2 is 15.5885.
Step-by-step explanation:
This is plug in math! I'd recommend to get a Ti-84 (makes math like this so much easier)
Answer:
243 square inches
Step-by-step explanation:
The area is the square of the side length:
A = s^2
A = (3^(5/2))^2 = 3^(5/2*2) = 3^5 = 243
The area of the square is 243 square inches.
_____
The relevant rule of exponents is ...
(a^b)^c = a^(bc)
the input power to a motor is 300 w. in 20 s it lifts a load of 400 n through a height of 6.0 m. what is the efficiency of the motor?
By dividing the output power (work completed) by the input power ratio, the motor's efficiency may be determined. In this instance, the input power is 300 W, and the output power is 2400 joules (400 N * 6.0 m). As a result, the motor has an efficiency of 2400 J/300 W, or 8.0.
The input power is 300 W.
Time (t) = 20 s
Height is 6.0 metres.
(F) = 400 N Load
Output power (Pout) is calculated as follows: F x h = 400 N x 6.0 m = 2400 J
Efficiency (e) is calculated as Pout / P = 2400 J / 300 W = 8.0.
A motor's efficiency can be determined by dividing its output power by its input power. Assuming that the input power is 300 W and the output power equals the amount of work completed, the load (F) and height can be multiplied to determine the output power (h). The output power in this example is 2400 joules (400 N * 6.0 m) since the load is 400 N and the height is 6.0 m. The motor's efficiency is 2400 J/300 W, or 8.0, as a result. Knowing the input power, output power, and length of time it took the motor to lift the load will help you determine the efficiency. In this illustration, the time is 20 s, and the input power is 300 W.
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The table shown is missing an X. Where should the X be placed?
A)
A
B)
B
C)
C С
D)
D
The X should be placed in the corresponding shape for above each property.
What is the congruent angle?
When two parallel lines are cut by a transversal, the angles that are on the same side of the transversal and in matching corners will be congruent.
The X should be placed in the corresponding shape for each property:
Square: congruent angles, 4 congruent sides, perpendicular diagonals, 2 pairs of opposite sides congruent.
Rectangle: congruent angles, perpendicular diagonals, 2 pairs of opposite sides congruent.
Rhombus: 4 congruent sides, perpendicular diagonals, congruent diagonals, 2 pairs of opposite angles congruent.
Isosceles Trapezoid: congruent angles, congruent diagonals, 2 pairs of opposite sides congruent.
hence, The X should be placed in the corresponding shape for above each property.
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how do I write a function for area A (s)there are 36 tiles with lengths from 2-6 inches
In the diagram, AEF∼ △ DEB. Find the length of side BE
.
Write the proportion to solve for BE :
40 = ____?________
__?____= BE
The length of side BE is = __?__
Please answer asap, will make brainiest
Answer:
SOMEBODY ANSWER THIS
Step-by-step explanation:
PLEASE
A large aircraft is flying on a bearing of 310° (50° west of north) with an airspeed of 700 mph. It is being affected by a 100 mph wind
blowing towards the west, as shown in the diagram below.
The distance, R, as indicated in the diagram, that the plane has travelled after 1 hour is, to the nearest mile,
Answer:
779
Step-by-step explanation:
Aiming to get the value of formula
Given that
50° + 80² = 140°.
:: Cos140² = 100 + 700²³ - R²
kaw of ousines axivox. T
·· R² = 607246
R≈ 780 miles
• The result is T80 miles
Question 4
3 pts
Use substitution to solve the following system of equations. What is the value of y?
3x +2y = 12
15x – y=7
y=-2
y=2
y=-3
y=3
According to the synthetic division below, which of the following statements are true? Check all that apply.
Answer: d, f
explanation:
Please help me on question 32!!!
assume that a grade of a, b, c, d, f, i, or nc is assigned to each of 10 students. in how many different ways can grades be assigned?
There are numerous ways to grade a class of ten students. There are seven possible grades that could be given (A, B, C, D, F, I, or NC), depending on the grading scheme employed.
This indicates that there are mathematically 7 to the power of 10 (710) distinct methods to give the kids grades. There are approximately 8.3 billion ways to grade the ten pupils, or 8,300,000,000 ways in total.
Because there are seven different grades for each student, this number is extremely high. The number of possible options increases exponentially because there are 10 pupils. As a result, there are countless alternatives for how to assess the 10 kids.
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If 1 < a ⩽ x , then the minimum value of \( \rm log_{a}(x) + log_{x}(x) \) is ?
PLEASE HELP!!!!
The minimum value of the expression log_a(x)+log_x(x) is 2 because the minimum value of each term is 1.
What is a logarithm?It is another way to represent the power of numbers, and we say that 'b' is the logarithm of 'c' with base 'a' if and only if 'a' to the power 'b' equals 'c'.
\(\rm a^b = c\\log_ac =b\)
We have:
1 < a ≤ x
We have an expression:
\(\rm log_a(x)+log_x(x)\)
We know,
\(\rm log_aa = 1\)
\(\rm log_a(x)+1\)
If a = x
Then, \(\rm log_a(x)=1\)
We cannot find the function value less than 1 because it goes infinitely in a negative direction.
So the minimum value of the expression:
= 1 + 1
= 2
Thus, the minimum value of the expression log_a(x)+log_x(x) is 2 because the minimum value of each term is 1.
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a signal can be formed by running different colored flags up a pole. how many distinct signals can be made with 6 flasgs if 3 of them are red, 2 of them are blue, and 1 is green?
Answer:
6
Step-by-step explanation:
The number of signals will be the factorial of 3 which is 6
That is
3×2×1=6
This question is similar to asking the combination of clothes you'll put on when you have 3 shirts and 6 pants and 1 hat, the answer is 18.
Find the absolute maximum value of the function f of x equals 2 times x plus 1 for x between negative 2 and 0 inclusive and equals negative x squared plus 1 for x greater than 0
The absolute maximum value for the given function
f(x) = 2x + 1, -2 < x < 0
= -x² + 1 , x > 0 is equal to ( 0,1 ).
Graph is attached.
As given in the question,
Given function is equal to :
f(x) = 2x + 1, -2 < x < 0
= -x² + 1 , x > 0
Graph is attached.
From the attached graph we directly conclude that absolute maximum located at the point ( 0, 1) when both the curves meet at highest point.
From the calculation of the function we get,
f(x) = 2x + 1, -2 < x < 0
Value of f(x) for x = -2, -1, 0
f(-2) = 2(-2) + 1
= -3
f(-1) = 2(-1) + 1
= -1
f(0) = 2(0) +1
= 1
Maximum value is ( 0,1) for f(x)
f(x) = -x² + 1 , x > 0
for x = 0 or any value greater than 0
f(0) = 1
f(1) = 0
f(2) = -3 and so on.
Maximum and common point is ( 0,1)
Therefore, the absolute maximum for the given function is equal to (0, 1).
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Please help‼️ domain and range‼️
The domain and the range of the function are (-∝, ∝) and (0, ∝), respectively
Calculating the domain and range of the graph?From the question, we have the following parameters that can be used in our computation:
The graph
The above graph is an exponential function
The rule of an function is that
The domain is the set of all real values
In this case, the domain is (-∝, ∝)
For the range, we have
Range = (0, ∝)
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My height in inches is equivalent to the third prime number times 12 and plus itself.
Answer:
120
Step-by-step explanation:
(5*12)*2
In a company, 85% of the workers are women. If 675 people work for the company who aren't women, how many workers are there in all?
Answer:
so there are 3825 worker in total
Step-by-step explanation:
675=15%
women=85%
how much workers are 5%=675/3 =225
225=5%
how many workers is 85%= 85/5=17
85%=225x17=3825
Please help find the missing side length using trig!
The missing side length is x = 30
What are basic Trigonometric functions?
The angles of sine, cosine, and tangent are the primary classification of functions of trigonometry. And the three functions which are cotangent, secant, and cosecant can be derived from the primary functions. Basically, the other three functions are often used as compared to the primary trigonometric functions.
In a Right-angled triangle, the tan of an angle is equal to the opposite side/adjacent side
from the given figure,
tan 37° = x/40
0.75 = x/40
x = 30
Therefore, The missing side is 30.
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18 PTS!! What is the 400th term of the sequence below when using the explicit formula
aₙ=a₁+(n-1)•d?
79, 82, 85, 88,...
A. 1273
B. 1279
C. 1276
D. 1282
Answer:
\(\huge\boxed{\sf a_{400}=1276}\)
Step-by-step explanation:
Sequence:79, 82, 85, 88, ....
Explicit formula:\(a_n=a_1+(n-1)d\)
Where,
\(a_n = a_{400\) (the term that is to be found)\(a_1 = 79\) (the first term)\(n = 400\)\(d = 3\) (difference between first and second term)Put the givens in the above formula
\(a_{400}=79 +(400-1)3\\\\a_{400}=79 + 399\times3\\\\a_{400}=79+ 1197\\\\a_{400}=1276\\\\\rule[225]{225}{2}\)
HELP ME PLEASEEEE!!!
PLEASE help me. I am stuck on this question for a long time.
Answer:
b.28% of the patients tested received the medication and experienced a decrease in blood pressure
Answer:
The second one
Step-by-step explanation:
The total of patients is 100% wich is equivalent to 1.
● 0.5 of them received medication and ● 0.54 of them experienced a decrease in blood pressure.
The intersection of both is worth 0.28
So out of 1, 0.28 took medication and experienced a blood pressure decrease
Jacobs pizza parlor sells pizza for $10 each, with a $20 delivery fee. Ashley's pizza parlor has a $12 delivery fee and sells pizza for $12 dollars each. At what point do the pizza parlors cost the same to deliver pizza?
Answer:
The pizza parlors cost the same when delivering 4 pizzas.
Step-by-step explanation:
For each store, the total price is
cost of pizzas + cost of delivery
The cost of delivery is just a fixed number for each store, $20 or $12.
The cost of the pizzas is the price of a pizza multiplied by the number of pizzas.
Let x = number of pizzas
The cost of the pizzas is
Jacob's: 10x
Ashley's: 12x
Jacob's total cost (pizzas + delivery):
10x + 20
Ashley's total cost (pizzas + delivery):
12x + 12
We want the total costs to be the same, so we set our two total cost expressions equal and solve for x.
12x + 12 = 10x + 20
Subtract 10 from both sides.
2x + 12 = 20
Subtract 12 from both sides.
2x = 8
Divide both sides by 2.
x = 4
Answer: The pizza parlors cost the same when delivering 4 pizzas.
8. Given: Q is the midpoint of PT and RS
Prove: APQR = ATOS
1.
2.
3.
4.
5.
9. Given: DE | GH
Statements
Prove: ADFE- AGFH
Statements
1.
2.
3.
4.
5.
P
R
Q
Reasons
D
E
Reasons
S
F
0
H
G
1. We can see here to prove ΔPQR ≅ ΔTQS:
Statements Reasons
1. Q is the midpoint of line PT
and RS Given
2. ∠PQR = ∠TQS Vertically opposite angles are equal
3. ∠RPQ = ∠STQ Alternate angles are equal
4. ∠QRP = ∠QST Alternate angles are equal.
What is a triangle?A triangle is a basic two-dimensional geometric shape that consists of three line segments or sides and three angles. The three line segments are connected to form a closed shape, and the angles are formed where the sides meet.
2. Proving that ΔDFE ≈ ΔGFH, we have:
Statements Reasons
1. Line DE || Line GH Given
2. ∠EFD = ∠GFH Vertically opposite angles are equal
3. ∠EDF = ∠HGF Alternate angles are equal
4. ∠DEF = ∠GHF Alternate angles are equal
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what is the volume of the shoebox shown above in cubic inches? the shoebox is 12in, 4in, and 2in
Volume = lxbxh=12x2x4=96 cubic inches (option C)
Given that sinØ = 0.707, 0.707, what is cosØ when π/2 < Ø < π? (round to the nearest thousandth)
Use the Pythagorean identity cosØ ≈ -0.707 is the value of cosØ.
To solve for cosØ, we can use the Pythagorean identity: sin²Ø + cos²Ø = 1.
First, we need to find sin²Ø:
sin²Ø = (0.707)² = 0.5
Then, we can solve for cos²Ø:
cos²Ø = 1 - sin²Ø = 1 - 0.5 = 0.5
Finally, we take the square root of both sides to find cosØ:
cosØ = ±√0.5
Since Ø is in the second quadrant (π/2 < Ø < π), cosØ must be negative.
Therefore, cosØ ≈ -0.707 (rounded to the nearest thousandth).
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The average weight of a high school freshman is 142 pounds. If a sample of twenty
freshmen is selected, find the probability that the mean of the sample will be greater than
145 pounds. Assume the variable is normally distributed with a standard deviation of 12.3
pounds.
The probability that the mean weight of a sample of twenty freshmen will be greater than 145 pounds is 0.138.
What is the probability?The probability is determined using the central limit theorem and the formula for the standard error of the mean:
SE = σ/√nwhere;
SE is the standard error of the mean,σ is the population standard deviation, andn is the sample size.Data given;
σ = 12.3 pounds; n = 20
SE = 12.3/√20
SE = 2.75 pounds.
The sample mean is then standardized using the z-score formula:
z = (x - μ) / SE
z = (145 - 142) / 2.75
z = 1.09
Using a calculator, the probability of a z-score greater than 1.09 is 0.138.
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find an explicit solution of the initial value problem dy/dt 2y=1, y(0)=5/2
The explicit solution to the initial value problem dy/dt = 2y with y(0) = 5/2 is given by: y = ±⁵/₂e²ᵗ
How did we get this value?To find the explicit solution of the initial value problem dy/dt = 2y with y(0) = 5/2, separate the variables and integrate both sides.
Starting with the differential equation:
dy/dt = 2y
Rewrite it as:
dy/y = 2dt
Now, we integrate both sides with respect to their respective variables:
∫ dy/y = ∫ 2dt
The integral of dy/y can be evaluated as the natural logarithm of the absolute value of y, while the integral of 2 dt is simply 2t:
ln |y| = 2t + C
Here, C is the constant of integration.
To determine the value of the constant C, we can use the initial condition y(0) = ⁵/₂. Substituting t = 0 and y = ⁵/₂ into the equation above:
ln |⁵/₂| = 2(0) + C
ln |⁵/₂| = C
Thus, we have the value of C as ln |⁵/₂|.
Substituting this value back into the equation:
ln |y| = 2t + ln |⁵/₂|
To eliminate the natural logarithm, we can take the exponential of both sides:
|y| = e²ᵗ + ln |⁵/₂|
Since |y| represents the absolute value of y, write it as:
|y| = ⁵/₂e²ᵗ
To simplify further, we can remove the absolute value by considering both positive and negative values of y:
y = ±⁵/₂e²ᵗ
Therefore, the explicit solution to the initial value problem dy/dt = 2y with y(0) = 5/2 is given by: y = ±⁵/₂e²ᵗ
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nitially 100 milligrams of a radioactive substance was present. after 6 hours the mass had decreased by 5%. if the rate of decay is proportional to the amount of the substance present at time t, find the amount remaining after 24 hours. (round your answer to one decimal place.)
If the rate of decay is proportional to the amount of the substance present at time t, then the amount remaining after 24 hours is 57.7 milligrams
Now we need to find the value of k. We know that the mass decreased by 5% after 6 hours, which means that the amount remaining is 95% of the initial amount. We can substitute these values into our formula and solve for k:
0.95 initial amount = initial amount x (1 - k x initial amount)⁶
Simplifying this equation, we get:
1 - \((0.95)^{(1/6)})\) = k x initial amount
Solving for k, we get:
k = (1 - \((0.95)^{(1/6)})\)) / initial amount
Now we can use this value of k to find the amount remaining after 24 hours:
Amount remaining = 100 x (1 - k x 100)²⁴
Plugging in the value of k, we get:
Amount remaining = 100 x (1 - (1 - \((0.95)^{(1/6)})\) * 100)²⁴
Evaluating this expression, we get:
Amount remaining = 57.7 milligrams
Therefore, after 24 hours, there will be approximately 57.7 milligrams of the radioactive substance remaining.
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If g(x) = (x + 7)/(1 - x) find gog^-1(x), g^-1og(x), g^-1og(3) and gog^-1(- 3) .
From the composite functions, gog^-1(-3) = 3.
Determining the composite functionsFinding the inverse of g(x):
Let y = g(x)
Then, we can solve for x in terms of y:
y = (x + 7)/(1 - x)
y(1 - x) = x + 7
y - yx = x + 7
y - 7 = x + yx
y - 7 = x(1 + y)
x = (y - 7)/(1 + y)
So, g^-1(x) = (x - 7)/(1 + x)
Now, we can find the composite functions:
gog^-1(x) = g[(x - 7)/(1 + x)]
= [(x - 7)/(1 + x) + 7]/[1 - (x - 7)/(1 + x)]
= [(x - 7) + 7(1 + x)]/[1 + x - (x - 7)]
= (8x)/8
= x
Therefore, gog^-1(x) = x.
g^-1og(x) = g^-1[(x + 7)/(1 - x)]
= [(x + 7)/(1 - x) - 7]/[1 + (x + 7)/(1 - x)]
= [(x + 7 - 7 + x)]/[1 - x + 7 + x/(1 - x)]
= (2x)/(2 - x)
Therefore, g^-1og(x) = (2x)/(2 - x).
g^-1og(3) = g^-1[(3 + 7)/(1 - 3)]
= g^-1[-5]
= (-5 - 7)/(1 + (-5))
= (-12)/(-4)
= 3
Therefore, g^-1og(3) = 3.
gog^-1(-3) = g[(-3 - 7)/(1 - (-3))]
= g[-1]
= (-1 + 7)/(1 - (-1))
= 6/2
= 3
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find the slope of a line that goes through the points ( -3,4) and (-3,1)
Please help me solve this
0
Step-by-step explanation:
The slope for this linear function would be 0.
It'd be a straight line, and slope tells you the steepness of a line, so it won't have slope.
Equation: x=-3
Image included to see line, and the two points.
Answer:
The slope is –3
Step-by-step explanation:
using the coordinate
(–3,4) and (–3,1)
x1 = –3,x2 = –3,y1 = 4, y2 = 1
using the formula for slope
m = y2 — y1/x2 — x1
m = 1 – 4/–3–(–3)
m = –3/–3+3
m = –3/0
m = –3
i hope this helps please rate the answer as brainliest so you can get some points
PLEASE HELP WILL MARK BRAINLIEST!!
Look at the rectangle and the square:
A rectangle PQRS and square LMNO are drawn side by side. The length SR of the rectangle is labeled as 14 inches, and the width QR is labeled as 7 inches. The side LM of the square is labeled as 7 inches.
Anna says that the length of diagonal SQ is two times the length of diagonal OM.
Is Anna correct? Justify your answer and show all your work. Your work should state the theorem you used to find the lengths of the diagonals.
Answer:
i need help too
Step-by-step explanation: