Upon being diagnosed with Cirrhosis of the liver, doctors urge patients to limit the amount of salt intake in their diet to help decrease the rate of scarring. During salt intake the blood becomes increasingly (hypertonic, hypotonic) to the interstitial fluid. Due to this osmotic imbalance, the liver cells become (hypertonic, hypotonic) to the interstitial fluid. This causes the liver cells to appear (shriveled, swollen).

\(12 \times 2 + 2 \times 2 + 16 \times 2\)

\( = 24 + 2 + 32 \)

\( = 58 \: gram \: per \: mole\)

\(58 = 100\% \\ 24 = x\%\)

\(x = \frac{24 \times 100}{58} = 41.38\%\)

Answer:

Aniline is heated with acetic anhydride to form acetanilide. Treatment with bromine/acetic acid gives p-bromoacetanilide. Acid/alkaline hydrolysis gives p-bromoaniline.

Explanation:

Answer:

goes deep into the ground and pollutes the groundwater.

Answer:

X = ¹₀n

Explanation:

The mass number is the total amount of neutrons and protons in the element. The atomic number is the total protons in the element. The mass number is the superscript and the atomic number is the subscript. The mass and atomic numbers must be balanced on both sides of the equation. The element can be identified by the atomic number.

In the event that we have an atomic number of zero, there is no element this represents, so the letter "n" should be used.

²³₁₁Na + ¹₁H  →  ²³₁₂Mg + X

Mass Number:

Reactants = Products

23 + 1 = 23 + ?

24 = 23 + ?

1 = ?

Atomic Number:

Reactants = Products

11 + 1 = 12 + ?

12 = 12 + ?

0 = ?

The complete equation is:

²³₁₁Na + ¹₁H  →  ²³₁₂Mg + ¹₀n

Answer:

Composition: All hydrocarbons are made up of only two types of atoms: carbon and hydrogen. They are like building blocks that contain carbon and hydrogen stuck together.

Organic Nature: Hydrocarbons are special because they are part of a group of compounds that come from living things or things that were once alive. They have carbon and hydrogen in them, which is what makes them different from other types of compounds.

Explanation:

Answer:

0.110625 g of Ni

Explanation:

The first step in solving this problem is to put down the accurate chemical reaction equation.

Ni(s) + 2HCl(aq) ---> NiCl2(aq) + H2(g)

Secondly, we obtain the amount of HCl that reacted from the information provided.

Volume of HCl (V)= 25 ml

Concentration of HCl (C)= 0.15 mol/L

Then, to find the number of moles of HCl (n);

n= CV

Substitution values

n= 25/1000 × 0.15

n= 3.75 ×10^-3 moles

Mass of 3.75 ×10^-3 moles of HCl = number of moles × molar mass

Molar mass of HCl= 36.5 gmol-1

Therefore;

Mass of HCl = 3.75 ×10^-3 moles × 36.5 gmol-1

Mass of HCl= 0.136875 g of HCl

Thirdly we determine the mass of Ni reacted;

If 1 mole of Ni reacted with 2 moles of HCl according to the reaction equation

Then x moles of Ni reacts with 3.75 ×10^-3 moles of HCl

x= 1 × 3.75 ×10^-3 moles/ 2

x= 1.875 × 10^-3 moles of Ni

Mass of Ni= 1.875 × 10^-3 moles of Ni × 59 gmol-1

Mass of Ni= 0.110625 g of Ni

Answer:

Genes are segments of deoxyribonucleic acid (DNA) that contain the code for a specific protein that functions in one or more types of cells in the body.

Chromosomes are structures within cells that contain a person's genes. A trait is any gene-determined characteristics and is often determined by more than one gene.

for study island:

A single trait can be controlled by multiple genes.

A single gene can influence multiple traits.

If one knows the mass of A, they may calculate the mass of any other reactant and product in a chemical reaction.

Find out how many moles each reactant has. To identify which reactant is limiting, compare the mole ratios of the reactants with the ratio in the balanced chemical equation. Determine how many moles of the limiting reactant can be converted into the product.

Calculate the maximum number of moles of product that can be produced from the limiting reactant using mole ratios. Add the product's molar mass to the number of moles.

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The balanced molecular equation for the reaction between sodium hydroxide (NaOH) and aluminum chloride (\(AlCl_3\)) in aqueous solution can be written as follows: 2NaOH(aq) + 3\(AlCl_3\)(aq) → 3NaCl(aq) + \(Al(OH)_3\)(s)

In this reaction, sodium hydroxide (NaOH) reacts with aluminum chloride (\(AlCl_3\)) to form sodium chloride (NaCl) and aluminum hydroxide (\(Al(OH)_3\)). The coefficients in the balanced equation indicate the stoichiometric ratio between the reactants and products.

The physical states of the substances are indicated by the symbols (aq) for aqueous solutions and (s) for the solid precipitate.

The reaction is a double-displacement reaction, also known as a precipitation reaction. Double-displacement reactions involve the exchange of ions between two compounds, resulting in the formation of a precipitate.

In this case, sodium hydroxide and aluminum chloride react to form sodium chloride and aluminum hydroxide, with aluminum hydroxide being the white solid precipitate.

It's worth noting that the actual reaction might involve hydrated forms of the compounds, such as NaOH·x\(H_2O\) and \(AlCl_3\)·y\(H_2O\). However, for simplicity, these hydrated forms are not included in the balanced equation.

Overall, the balanced equation represents the chemical reaction between sodium hydroxide and aluminum chloride, showing the reactants, products, and their stoichiometric ratios.

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The concentration of the solution is 0.3 mol/L.

We know that concentration is the amount of substances that is present. We know that the concentration can be measured by the use of several units and one of the units that we can be able to use is the  mol/L.

We have that the concentration in w/w is 5.0% and this means that the mass of water in the solution is 5g. From the density of the solution;

volume = mass/density

= 5g/  1.000 g/mL

= 5 mL or 0.005 L

Number of moles of sugar = 5g/342.30 g/mol

= 0.015 moles

Concentration = Number of moles/volume

=  0.015 moles/0.005 L

= 0.3 mol/L

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The oxidation number of Ag in Ag2O is +1.

In Ag2O, there are two silver atoms (Ag) and one oxygen atom (O). Oxygen is known to have an oxidation number of -2 in most compounds. Since the compound is neutral, the sum of the oxidation numbers of all the atoms must equal zero.

Therefore, the oxidation numbers of the two silver atoms must add up to +2 to balance out the -2 oxidation number of the oxygen atom. Since there are two silver atoms, each silver atom must have an oxidation number of +1 to yield a total oxidation number of +2 for the compound.

In Ag2O, the silver atoms lose one electron each to form Ag+ ions. This results in an oxidation number of +1 for each silver atom. The oxygen atom gains two electrons from the silver atoms to achieve a stable octet configuration, resulting in an oxidation number of -2 for the oxygen atom. The compound Ag2O is formed through the transfer of electrons, with each silver atom exhibiting an oxidation number of +1.

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In a reaction between two different types of materials, metals often lose electrons to finish out their octet whereas non-metals receive electrons to do the same.

A crucial component of a whole. a simple material that cannot be divided into smaller components or transformed into another substance is referred to as in chemistry. Atoms, which are made up of protons, neutrons, and electrons, are the building blocks of an element. One element has a fixed number of protons in each of its atoms.

A material is considered to be an element if all of its atoms contain the same number of protons, or, to put it another way, if all of the atoms. The most basic chemical forms are those of the elements.

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Organic transformation sequential equation using catalysts will be as follows:

2CH3-CH2-O => (alc. KOH) => CH2=CH2 + KCl + H2O => (Br2/CCl4) => CH2Br-CH2Br + Zn

CH2Br-CH2Br + Zn => (HBr /Pd) => CH2=CH2+ZnBr2

As can be visualized from above organic transformation equation, conversion of dry ether in presence of alkaline potassium hydroxide results in formation of unstable ethene. This dry unsaturated compound of ethene is stabilized by reaction that happens in presence of bromine or calcium tetrachloride as the catalyst which results in formation of ethylene bromide which in presence of highly efficient palladium as catalyst results in formation of stable ethene as byproduct. Thereby with formation of stable compound of ethylene, it releases zinc bromide as byproduct resulting completion of reaction equation. This stable product ethene is a double bonded carbon structure that is chemically extremely flammable and has planar structure.

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Answer:

The answer is 4.31 × 10²³ C atoms

Explanation:

The number of C atoms can be found by using the formula

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 0.716 × 6.02 × 10²³

We have the final answer as

Hope this helps you

The electrolytic reaction between Zn and Ag results in the oxidation of Zn and reduction silver metal. The oxidation of Zn make the Zn ions pass into the solution and its mass decreases.

An electrochemical cell converts chemical energy to electrical energy. It involves redox reaction of two metallic electrodes. The electrode with higher negative electrode potential undergo oxidation and one with lower negative or having positive potential undergoes reduction.

The electrode which undergo oxidation is consumed in the process and metal gets ionized. Ions move into the electrolyte. Whereas, the ions of the second electrode gets reduced into metallic state and deposits on the electrode.

In this case, Zn is oxidizing and  it is consumed to reduce the silver metal on the cathode. Therefore, the mass of Zn metal decreases in the strip.

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Answer:

1.) 0.619 M

2.) 6.34 L

3.) 12.7 moles

Explanation:

Part 1: To find the molarity, you first need to convert grams to moles using the molar mass.

Molar Mass (NaCl): 22.990 g/mol + 35.453 g/mol

Molar Mass (NaCl): 58.443 g/mol

143 grams NaCl               1 mole
-------------------------  x  ------------------------  =  2.45 moles NaCl
                                    58.443 grams

Molarity = moles / volume (L)

Molarity = 2.45 moles / 3.95 L

Molarity = 0.619

Part 2: To find the volume, you need to use the given moles and the previously calculated molarity.

Molarity = moles / volume (L)

0.619 M = 3.93 moles / volume

(0.619 M) x volume = 3.93 moles

volume = 6.34

Part 3: To find the moles, you need to use the given volume and the previously calculated molarity.

Molarity = moles / volume (L)

0.619 M = moles / 20.55 L

12.7 = moles

Answer:

Prudent execution of experiments requires not only sound judgment and an accurate assessment of the risks involved in the laboratory, but also the selection of appropriate work practices to reduce risk and protect the health and safety of trained laboratory personnel as well as the public and the environment. Chapter 4 provides specific guidelines for evaluating the hazards and assessing the risks associated with laboratory chemicals, equipment, and operations. Chapter 5 demonstrates how to control those risks when managing the inventory of chemicals in the laboratory. The use of the protocols outlined in Chapter 4 in carefully planned experiments is the subject of this chapter.

Explanation:

Answer:

\(\boxed {\boxed {\sf Mass \ of \ products \ = \ mass \ of \ reactants}}\)

Explanation:

The Law of Conservation of Mass states that mass cannot be created or destroyed.

In a chemical reaction, there are products and reactants. The reactants react and produce the products.

Since mass can't be created or destroyed, the mass of the products must be equal to the mass of the reactants if mass was conserved in a chemical reactions.

Answer:

The answer is When CO2 increases, pH decreases and acidity increases.

Explanation:

Excess carbon dioxide (CO2) in the atmosphere gets absorbed at the ocean surface of the ocean. This excess CO2 results in more hydrogen ions, which increases the acidity of the ocean.

Answer:

Using your answer from Part A, calculate the volume of a mole of Na atoms (in cm3/mol ). Assume that the entire volume is occupied by Na atoms leaving no gaps or holes between adjacent atoms. (Answer A is V= 2.70*10^7)

Answer

A. -1305 kJ

Explanation

Given:

Equation: C2H4(g) + 302(g) ---- > 2C02(g) + 2H20(l).

Formation ΔH values:

​​for C2H4(g) = 52.30 kJ/mol,

for 02(g) = 0 kJ/mol,

for CO2(g) = -393.5 kJ/mol, and

for H20(1) = -285.8kJ/mol.

What to find:

The ΔHrxn from the ΔH of formation for the given reaction.

Step-by-step solution:

ΔHrxn = (Sum of ΔH formation for the product) - (Sum of ΔH formation for the reactants).

ΔHrxn = (ΔH for 2CO2(g) + ΔH for 2H2O(l)) + (ΔH for C2H4(g) + ΔH for 3O2(g))

ΔHrxn = [(2 x -393.5) + (2 x -285.8)] + [52.30 + (3 x 0)]

ΔHrxn =(-787.0 - 571.6) + (52.30 + 0)

ΔHrxn = -1358.6 + 52.30

ΔHrxn = -1306.3 kJ

so the closest answer is A. -1305 kJ

Some types of solids that are insoluble in water are:

Many solids are insoluble in water, meaning they do not dissolve in water to a significant extent. Here are some examples of common solids that are generally insoluble in water:

Metals: Most metals, such as gold, silver, platinum, and copper, are insoluble in water.

Non-Metallic Elements: Many non-metallic elements, such as carbon (in the form of graphite or diamond), sulfur, phosphorus, and iodine, are insoluble in water.

Metal Oxides: Some metal oxides, particularly those of less reactive metals, are insoluble in water. Examples include aluminum oxide (Al2O3), iron(III) oxide (Fe2O3), and lead(II) oxide (PbO).

Metal Carbonates: Most metal carbonates are insoluble in water. Examples include calcium carbonate (CaCO3), lead(II) carbonate (PbCO3), and copper(II) carbonate (CuCO3).

Metal Sulfides: Many metal sulfides are insoluble in water. Examples include lead(II) sulfide (PbS), silver sulfide (Ag2S), and mercury(II) sulfide (HgS).

Insoluble Salts: Certain salts have limited solubility in water. Examples include silver chloride (AgCl), lead(II) iodide (PbI2), and calcium sulfate (CaSO4).

It's important to note that while these solids are generally insoluble in water, they may exhibit some solubility to a small extent. The solubility of a solid in water can vary depending on factors such as temperature, pressure, and the presence of other solutes.

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XeF⁴ has a mοlar mass οf abοut 207.2886 g/mοl.

One mοle οf a material weighs οne mοlar mass. It is cοmputed by cοmbining the atοmic masses οf all the atοms in a mοlecule and is οften repοrted in grams per mοle (g/mοl). The mass οf an atοm in a chemical element is knοwn as its atοmic mass.

The atοmic masses οf the cοmpοnents, which are: can be added tο determine the mοlar mass οf XeF⁴ (xenοn tetrafluοride).

Atοmic mass οf xenοn (Xe) is 131.293 g/mοl.

Atοmic mass οf fluοrine (F) is 18.9984 g/mοl.

As a result, the fοrmula fοr calculating the mοlar mass οf XeF⁴ is:

Mοlar mass οf XeF⁴ = (1 x mοlar mass οf Xe) + (4 x mοlar mass οf F) = (1x 131.293 g/mοl) + (4 x 18.9984 g/mοl) = 207.2886 g/mοl (apprοx)

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Answer:

C

Explanation:

This is a chemical reaction because the materials that were mixed have different solubilities than the materials that were made.

Answer:

C

Explanation:

When a chemical reaction occurs, new materials form. Different materials each have unique physical properties, such as solubility.

When olive oil and sodium hydroxide were mixed together, soap and glycerol were made. The table shows that olive oil and sodium hydroxide have solubilities that are different than soap and glycerol. This means that olive oil and sodium hydroxide are different materials than soap and glycerol. Therefore, this is a chemical reaction because the materials that were mixed have different solubilities than the materials that were made.

Answer:  \([Ni(NH_3)_3Br]Cl\) and \([Ni(NH_3)_3Cl]Br\) are ionization isomers.

\([Pt(Cl)_2(SCN)_4]^{4-}\) and \([Pt(Cl)_2(NCS)_4]^{4-}\) are linkage isomers.

Explanation:

Ionization isomerism occur when a ligand that is bound to the metal center exchanges places with an anion or neutral molecule that was originally outside the coordination complex

Thus \([Ni(NH_3)_3Br]Cl\) and \([Ni(NH_3)_3Cl]Br\) are ionization isomers.

Linkage isomerism is the existence of coordination compounds that have the same composition differing with the connectivity of the metal to a ligand.

Thus \([Pt(Cl)_2(SCN)_4]^{4-}\) and \([Pt(Cl)_2(NCS)_4]^{4-}\) are linkage isomers.

Some real-world examples of convection are as follows:

Convection may be defined as the methodology through which heat is significantly transferred by the normal movement of a heated fluid such as air or water within the component.

The process of convection remarkably involves the transfer of heat through a fluid (liquid or gas) that is provoked by molecular motion.

Therefore, some real-world examples of convection are well-described above.

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The correct mass-volume relationship at STP is A. 32.00 g of \(O_{2}\) react with an excess of \(H_{2}\) to produce (2 ´ 22.4) L of \(H_{2}O\)

To determine the correct mass-volume relationship at STP (Standard Temperature and Pressure), we need to consider the stoichiometry of the balanced chemical equation, the molar masses of the substances involved, and the molar volume of gases at STP.

The balanced equation indicates that 2 moles of \(H_{2}\) react with 1 mole of \(O_{2}\) to produce 2 moles of \(H_{2}O\). At STP, 1 mole of any gas occupies 22.4 liters.

In option A, it states that 32.00 g of \(O_{2}\) react with an excess of \(H_{2}\) to produce (2 × 22.4) L of \(H_{2}O\). The molar mass of \(O_{2}\) is 32.00 g/mol, which corresponds to 1 mole of \(O_{2}\). According to the balanced equation, 1 mole of \(O_{2}\) reacts to form 2 moles of \(H_{2}O\). Therefore, the given mass of \(O_{2}\) (32.00 g) corresponds to 1 mole of \(O_{2}\), which will produce 2 moles of \(H_{2}O\).

Since 1 mole of any gas occupies 22.4 L at STP, 2 moles of \(H_{2}O\) would occupy (2 × 22.4) L, which is equal to 44.8 L. Hence, the correct answer is A, where 32.00 g of \(O_{2}\) react with an excess of \(H_{2}\) to produce (2 × 22.4) L of \(H_{2}O\). This choice represents the correct mass-volume relationship at STP based on the given equation and stoichiometry. Therefore, Option A is correct.

The question was incomplete. find the full content below:

Consider the equation. 2\(H_{2}\)(g) + \(O_{2}\)(g) >>>> 2\(H_{2}O\)(g)

Which represents the correct mass-volume relationship at STP?

A. 32.00 g of \(O_{2}\) react with an excess of \(H_{2}\) to produce (2 ´ 22.4) L of \(H_{2}O\)B. 2.00 g of \(H_{2}\) react with an excess of \(O_{2}\) to produce (2 ´ 22.4) L of \(H_{2}O\).

C. 32.00 g of \(O_{2}\) react with an excess of \(H_{2}\) to produce 22.4 L of \(H_{2}O\)

D. (2 ´ 2.00) g of \(H_{2}\) react with an excess of \(O_{2}\) to produce 22.4 L of \(H_{2}O\).

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Answer:

b.exothermic and entropy is decreasing

Answer:

Na3N

Explanation:

cuzdoodlikeimsosure

Answer:

Bo

Explanation:

Bo is not a element