True or false
hey is for horses

The simplified value of the expression\(\sqrt{ ((2^3 * 64^(1/2) + 1176 + (3^2)^3 + (11 * 3)^1) - 153) }\) is 43.

Given expression: \(\sqrt{(2^3 * 64^(1/2) + 1176 + (3^2)^3 + (11 * 3)^1) - 153)}\)

Step 1: Evaluate the exponentiations.

\(2^3 = 8\) and \(3^2 = 9.\)

The expression becomes: \(\sqrt{((8 * 64^(1/2) + 1176 + 9^3 + (11 * 3)^1) - 153)\\}\)

Step 2: Simplify the square root.

\(64^{(1/2)\) is the square root of 64, which is 8.

The expression becomes: \(\sqrt{((8 * 8 + 1176 + 9^3 + (11 * 3)^1) - 153)}\)

Step 3: Evaluate the multiplications and additions.

8 * 8 = 64, \(9^3\) = 729, and 11 * 3 = 33.

The expression becomes: \(\sqrt{(64 + 1176 + 729 + 33 - 153)\\}\)

Step 4: Perform addition and subtraction.

64 + 1176 + 729 + 33 - 153 = 1849

Step 5: Take the square root of the result.

\(\sqrt{1849\\}\) = 43

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Therefore, Carel's height is approximately 167.54 cm.

The question is asking to calculate the standardised value or z-score corresponding to Maseru's height, the proportion of residents who are taller than Maseru, the number of standard deviations below or above the mean Carel's height is, and Carel's height if it is known that Carel, another college student, is shorter than 34% of the residents in the college.

Here,Mean μ = 171 cmStandard deviation σ = 8.5 cmMaseru's height x = 165.4 cm

(a) To calculate the standardised value or z-score corresponding to Maseru's height, we will use the formula of standardised value or z-score, which is given by;`z = (x - μ) / σ`Substitute the known values and calculate;

z = (165.4 - 171) / 8.5 = -0.635Ans: -0.635

(b) We have to find the proportion of residents who are taller than Maseru. To calculate this, we will use the standard normal distribution table or calculator. From the table, we get the value of 0.2611. Therefore, the proportion of residents who are taller than Maseru is 1 - 0.2611 = 0.7389 or 73.89%.Ans: 73.89%

(c) It is given that Carel, another college student, is shorter than 34% of the residents in the college. This means the area to the left of Carel's height on the distribution curve is 0.34. To find how many standard deviations below or above the mean Carel's height is, we will use the standard normal distribution table or calculator to find the z-score corresponding to 0.34. From the table, we get the value of -0.44.

Therefore, the number of standard deviations below the mean Carel's height is -0.44.Ans: -0.44

(d) To compute Carel's height, we will use the formula of standardised value or z-score which is given by;`z = (x - μ) / σ`Rearranging the formula, we get;x = μ + zσSubstitute the known values and calculate;x

= 171 + (-0.44) × 8.5 = 167.54

Ans: 167.54 cm

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We can find the variance of a uniform distribution, using the following formula: Variance = (b - a)² / 12. Here: a is the lower limit of the uniform distribution, b is the upper limit of the uniform distribution.

The formula for the variance of a uniform distribution is based on the fact that the variance of a continuous uniform distribution is equal to the square of the range (i.e., the difference between the upper and lower limits) divided by 12.

For example, let's say we have a uniform distribution between 0 and 10. To find the variance, we would use the formula:

Variance = (10 - 0)² / 12

Variance = 100 / 12

Variance = 8.33

Therefore, the variance of a uniform distribution between 0 and 10 is 8.33.

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Answer:

A product of a number and 12 is increased by 23

Answer:

3,5000 and 21% for account earns simple interest

Answer: D, x < 8

Step-by-step explanation: Subtract 18 from both sides.

Simplify the expression

Subtract the numbers

Subtract the numbers

Divide both sides by the same factor, and flip the relation because the factor is negative

Cancel terms that are in both the numerator and denominator

Divide the numbers

−6x+18−18>−30−18=

=x<8

There are 608400 plates are possible.

If the first is A, we have 26 possibilities:

AA, AB, AC,AD,AE ...................................... AW, AX, AY, AZ.

If the first is B, we have 26 possibilities:

BA, BB, BC, BD, BE .........................................BW, BX,BY,BZ

And so on for every letter of the alphabet.

There are 26 choices for the first letter and 26 choices for the second letter. The number of different combinations of 2 letters is:

26×26=676

The same applies for the three digits.

There are 9 choices for the first as first digit cannot be 0

10 for the second,

10 for the third

9×10×10=900

So for a license plate which has 2 letters and 3 digits, there are:

676 × 900 = 608400 possibilities

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Answer:

0

Step-by-step explanation:

2nd avenue is a horizontal line, parallel to the x-axis.

The slope of a horizontal line is zero.

Answer: slope = 0

Step-by-step explanation:

To find the Highest Common Factor (H.C.F.) of 567 and 255 using Euclid's division lemma, we can follow these steps:

Step 1: Apply Euclid's division lemma:

Divide the larger number, 567, by the smaller number, 255, and find the remainder.

567 ÷ 255 = 2 remainder 57

Step 2: Apply Euclid's division lemma again:

Now, divide the previous divisor, 255, by the remainder, 57, and find the new remainder.

255 ÷ 57 = 4 remainder 27

Step 3: Repeat the process:

Next, divide the previous divisor, 57, by the remainder, 27, and find the new remainder.

57 ÷ 27 = 2 remainder 3

Step 4: Continue until we obtain a remainder of 0:

Now, divide the previous divisor, 27, by the remainder, 3, and find the new remainder.

27 ÷ 3 = 9 remainder 0

Since we have obtained a remainder of 0, the process ends here.

Step 5: The H.C.F. is the last non-zero remainder:

The H.C.F. of 567 and 255 is the last non-zero remainder obtained in the previous step, which is 3.

Therefore, the H.C.F. of 567 and 255 is 3.

Answer:

1.38d

Step-by-step explanation:

Answer: y = 1/5x+5

Step-by-step explanation: Slope intercept form is y = mx+b, where m is the slope, and b is the y intercept. Substitute accordingly.

A. To find the gradient of the function at the point (2, -1), we need to find the partial derivatives of f with respect to x and y, and evaluate them at the given point.

∂f/∂x = y^2

∂f/∂y = 2xy

At (2, -1),

∂f/∂x = (-1)^2 = 1

∂f/∂y = 2(2)(-1) = -4

Therefore, the gradient of f at (2, -1) is (1, -4).

B. To sketch the gradient together with the level curve that passes through the point, we first need to find the equation of the level curve.

The level curve passing through (2, -1) is given by

f(x, y) = xy^2 = (-1)^2 = 1

Substituting y^2 = 1 into the equation of f, we get

f(x, y) = xy^2 = x

So the level curve passing through (2, -1) is the line y = -1.

Now, we can sketch the gradient vector (1, -4) at the point (2, -1) and draw the line y = -1 through the point.

C. To parameterize the level curve from part b, we can set y = t and x = t for any real number t. Then, the parameterization of the level curve is

x = t

y = -1

So the level curve can be expressed as the set of points (t, -1) for any real number t.

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Answer: D) -20.99

Step-by-step explanation:

-4.97-2.36+-5.19-8.47 = -20.99

When drawing cabinets obliquely, we start with the front face of an object and draw the depths or sides at 45 degrees.

The object is depicted as having a cabinet oblique with half height and full depth. In a cabinet oblique drawing, the object's height is depicted at half scale while its depth is represented at full scale.

In doing so, a foreshortening effect is produced, giving the object a deeper than tall appearance. The drawing is normally displayed at a 45-degree angle, with the breadth of the object drawn to full scale.

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True/False question cannot be answered with a "main answer". However, the archaeologists do believe that the cities of Sodom and Gomorrah were near the Dead Sea.

The location of Sodom and Gomorrah is a subject of debate among archaeologists and scholars. Some believe that they were located near the Dead Sea, while others propose different locations. However, the prevailing theory is that they were situated near the Dead Sea, which is a salt lake bordered by Jordan to the east and Israel and Palestine to the west.

The true/false question you have posed cannot be answered with a long answer as it is a binary question. However, if you want to know more about the archaeology and history of Sodom and Gomorrah, there is a wealth of information available online and in scholarly articles and books. The story of Sodom and Gomorrah is a biblical tale that recounts the destruction of two cities by God due to their wickedness. The story appears in both the Book of Genesis in the Hebrew Bible and in the Quran. Archaeological evidence suggests that there were settlements in the area of the Dead Sea around the time the story of Sodom and Gomorrah is said to have occurred, but there is no conclusive proof that these were the cities referred to in the Bible. Some scholars argue that the story is a myth, while others believe that there is a historical basis for it. Regardless of the veracity of the tale, the story of Sodom and Gomorrah has captured the imagination of people for centuries and continues to be a subject of scholarly inquiry.

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The fair swap rate should be not lower than 5.5%.The quoted swap rate of 5.5% on a 3-year fixed-for-floating swap is not fair. To determine the fair swap rate,

we need to calculate the present value of the fixed and floating rate cash flows and equate them. By using the given spot rates, the fair swap rate is found to be lower than 5.5%.

In a fixed-for-floating interest rate swap, one party pays a fixed interest rate while the other pays a floating rate based on market conditions. To determine the fair swap rate, we need to compare the present values of the fixed and floating rate cash flows.

Let's assume that the notional amount is $1.

For the fixed leg, we have three cash flows at rates of 5.5% for each year. Using the spot rates, we can discount these cash flows to their present values:

PV_fixed = (0.055 / (1 + 0.04)) + (0.055 / (1 + 0.05)^2) + (0.055 / (1 + 0.06)^3).

For the floating leg, we have a single cash flow at the 3-year spot rate of 6%. We discount this cash flow to its present value:

PV_floating = (0.06 / (1 + 0.06)^3).

To find the fair swap rate, we equate the present values:

PV_fixed = PV_floating.

Simplifying the equation and solving for the fair swap rate, we find:

(0.055 / (1 + 0.04)) + (0.055 / (1 + 0.05)^2) + (0.055 / (1 + 0.06)^3) = (0.06 / (1 + fair_swap_rate)^3).

By solving this equation, we can determine the fair swap rate. If the calculated rate is lower than 5.5%, then the quoted swap rate of 5.5% is not fair.

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Reason:

Plug in w = 16 and compute.

D = 4w + 30

D = 4(16) + 30

D = 64 + 30

D = 94

This says at week 16, Jose will have $94 in his piggy bank.

Answer:

-20.5, -8, 4.5, and 17

Step-by-step explanation:

You just replace x with the given information, then solve it

Answer:

-20.5

-8

4.5

17

Step-by-step explanation:

plug in the X value

Analysis of the data set is given below .

Answer of the question "how hot is the sidewalk during the school day?'

Temperature Limits for Animals and People

Research is limited regarding temperature impact on animals, but what I found was alarming.

Experimental tests on live animals for thermal burns had been done by several researchers in the

1940’s. The data showed several key temperatures and are noted below. I have added about 10°F

which the pads on dogs feet offer:

•  120°F: the initial pain threshold for direct skin contact without permanent damage.

•  140°F: burns, permanent damage, and scarring appear after one minute contact .

•  150°F: rapid burns and blistering.

Humans have similar temperature limits but they can vary substantially with age, skin condition and contact method, compared to most animals.

•  120°: burns after five to 10 seconds in hot water for small children and the elderly.

•  140°: burns after one minute of contact or hot

water immersion for average adult.

•  160°: rapid burns and blistering after contact

with firm surface or water immersion, with possible nerve damage.

Just like a human’s callused hands, a larger dog’s pads may be able to tolerate these high temperatures for several minutes, but you will

eventually cause permanent damage or blistering with continuous exposure.

Temperature Measurements

The temperatures we measured often occur in Southern California, Arizona, New Mexico, Texas, Louisiana, Alabama, Georgia, Florida and

often up the East Coast on summer days. In the heat of the summer it is also common for middle latitude states like Tennessee, Missouri, Oklahoma, and others to see such temperatures. These states

easily touch one half of the population during the summer.

To measure this data, we held an infrared thermometer about one foot above the ground. It’s highly recommend all pet sitters purchase such a device to ensure the safety of their animals.

Temperature Data

The pavement temperature data I measured on the 95° day in South Florida was simply stunning. During the peak overhead sun periods,

black pavement temperatures hit 140°F in mid afternoon between 2:00 p.m. and 4:00 p.m.

They exceeded 120° on blacktop between 11:00 a.m. and 6:00 p.m., which is still above the pain thresholds for most dogs. I also tested a red brick sidewalk area but it was only about five degrees cooler than the blacktop. Most animals walk on the sidewalk, and I assumed the white concrete surface would be much cooler since light colors reflect heat more.

Other Temperature Problems Everyone has experienced that gush of hot air when opening their car door on a hot summer day and sitting down on a hot leather seat. After measuring these temperatures on the pavement, I felt it was also a good idea to measure the seat

temperatures with light gray leather seats. I was stunned when I saw the 152° reading on the seat surface. This would certainly burn any animal’s paws and emphasizes the need to carry towels or

blankets to cover the seats before allowing your pet to get in the car or let your bare skin touch it.

In addition, the vehicle had an air temperature over 130° sitting in the daytime sun, so this is further proof that leaving animals in closed cars is dangerous. It’s also against the law in a number of states. Even temperatures in cars with windows cracked open can rise 20° to 30° above the outside air temperature. A 70° day can feel like 90 to 100° inside a locked car. Remarkably black leather seats inside a car can easily achieve this and the black dashboards in many cars can exceed

170°.

One more surprising measurement was the thermal heating of an actual dogs’ coat. On these 95° days I was measuring temperatures of

more than 125° on the top of the black fur of the Belgium Shepherd. Although a dog’s fur keeps them warm in the winter, it also acts as an insulator in the summer. The problem with this concept is

that the insulator breaks down over time. The hot temperature on the surface of their coat warms their fur, eventually reaching their skin. These high sun exposures can easily create heat stroke for a dog that has been in the sun.

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The mirror and image has a distance of 90 cm

The image is inverted with a height of 12 cm.

Given,

Concave mirror with a radius of curvature 60 cm

The height of the object = 6 cm

The distance between the object and the mirror = 45 cm

We have to find the location and height of the image;

Here,

For any mirror, the radius of curvature is twice the focal length:

r = 2f

Where

r is the radius of curvature

f is the focal length

Then,

f = r/2 = 60/2 = 30 cm

Focal length = 30 cm

Now,

The distance of the image from the mirror;

The mirror equation is:

1/s' = 1/f - 1/s

Where

s' is the distance of the image from the mirror

f is the focal length

s is the distance of the object from the mirror

Here,

1/s' = 1/30 - 1/45

1/s' = 3/90 - 2/90

1/s' = 1/90

s' = 90 cm

The distance of the image from the mirror is 90 cm

Next,

Height of the image.

For that we have to find the magnification first;-

Magnification, M = - s'/s = - 90/45 = -2

Now,

Magnification in terms of height of the image;

M = y'/y

y' is the height of the image

y is the height of the object

So,

-2 = y'/6

y' = -2 x 6 = -12 cm

That is,

The image is of 12 cm height and which is inverted.

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Answer:

100.

Step-by-step explanation:

Let the number of robberies be x ( in 2013).

Then x - 0.10x = 90

0.90x = 90

x = 90 / 0.90

= 100.

Answer:

Yes it does. Because it's a linear graph, what Mena's it's a linear relationship, and linear relationships are proportional

Answer:

-5

Step-by-step explanation:

Given the functions

f(x) = 2x - 20

g(x) = x - 1

f(x)/g(x) = 2x - 20/x-1

f/g(x) = 2x - 20/x-1

Substituting x = -5 int the result

f/g(5) = 2(5) - 20/5-1

f/g(5) = 10 - 20/4

f/g(5) = -10/4

f/g(5) = -5

Hence the result is -5

The interest she earn in 7years is £287

Compound interest is the interest you earn on interest. This can be illustrated by using basic math: if you have $100 and it earns 5% interest each year, you'll have $105 at the end of the first year. At the end of the second year, you'll have $110.25.

The total amount to earn after a specified time if compound interest is :

A = P( 1+r/100)^t

where P is the principal, r is the rate and t is the time

A= 700( 1+ 5/100)⁷

A = 700( 1+0.05)⁷

A = 700(1.05)⁷

A= 700× 1.41

A = £ 987

interest =Amount - Principal

I = 987-700

I = £287

Therefore the interest she will earn in 7years is £287

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There are 1.5625 grams of the radioactive substance that would remain after 60 seconds.

The exponent of a number represents the total time required to multiply that number. 8 8 8 may be stated as 83 since 8 is multiplied by itself three times. In this case, 3 is the 'exponent' or 'power' that indicates how many times 8 is multiplied by itself, and 8 is the 'base' that represents the integer being multiplied.

The exponent is given as:

y = a (1 - r)ˣ

As per the question, we have

a = 100, and r = 0.50 and x = 6

Substitute the known values in the above formula, and we get

y = 100 × (1-0.50)⁶

y = 100 × (0.50)⁶

y = 100 × 0.015625

Apply the multiplication operation, a

y = 1.5625

So, after 60 seconds, 1.5625 grams of the radioactive substance would remain.

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Answer:

(A.

Explanation:

In A, line AD straight into BC, thus creating two 90 degree angles. This means that they are perpendicular.

(: Hope this helps

9514 1404 393

Answer:

  company B

Step-by-step explanation:

The growth rate is 1 less than the growth factor. The growth factor is the base of the exponential term.

Company A

  growth factor: 0.70

  growth rate: 0.70 -1 = -0.30 = -30%

__

Company B

  growth factor: 1.90

  growth rate: 1.90 -1 = 0.90 = 90%

__

Company B has a higher growth rate than Company A. (Company A has decreasing sales, not increasing.)

Company B has a higher growth rate than Company A.