to calculate the energy needed to boil water that initially starts in the liquid state below the boiling point, what quantities are needed?

Answer: 3.44 *10^22 atoms of Au

Explanation: To solve the number of atoms given the amount of moles can be solved by multiplying the number of moles by Avogadro's numbers, a number that represents the number of atoms in one mole of an element.

Avogradros number is: 6.02214076×10^23 so we do

6.02214076×10²³ * 5.71*10^-2 = # atoms

# atoms = 3.438*10^22 atoms

To simplify to 3 sig figs, it would be 3.44*10^22 since we round the hundradth place.

Answer:

1.) First thing to recognize is that it requires you to know the molecular formula for Iron(III) Oxide, which is Fe2O3. If you don't know this formula  in all textbooks there is a page that has it and other compounds listed. I would encourage you to review this page and memorize the other compounds as these compounds will come up in future questions.

2.) Now we will write an unbalanced equation, keeping in mind that molecular oxygen( O2) is used:

Fe + O2 ==> Fe2O3

3.) In balancing problems, I like to always start with Oxygen. Because there are 2 oxygen atoms on the reactant side and  three on the product side and we know that both of these numbers go into 6, we will use this to balance the oxygen. We will put a e in front of the molecular Oxygen and a 2 in front of the iron(III) oxide. This will balance the oxygens.

Fe + 3O2 ==> 2Fe2O3

However, notice now that the iron is still out of balance, This can be easily solved by having a 4 in front of the iron. Now everything is balanced!

4Fe + 3O2 ==> 2Fe2O3

Explanation:

The statement that is true regarding beta particles is D. "Beta-particle formation is accompanied by the conversion of a neutron into a proton."

Beta particles are high-energy electrons or positrons that are emitted during certain types of radioactive decay processes. Beta decay occurs when an unstable nucleus undergoes a transformation in order to reach a more stable state. In beta-minus decay, a neutron in the nucleus is converted into a proton, releasing a beta particle (high-energy electron) and an antineutrino. The conversion of a neutron into a proton increases the atomic number of the nucleus by one.

The statement that beta particles have a mass number of 0 is incorrect. Beta particles do have mass, although they are much less massive compared to protons or neutrons. Similarly, the statement that beta particles have an atomic number of 1 is incorrect. The atomic number refers to the number of protons in an atom, and beta particles are not atoms themselves. Beta particles are high-energy particles emitted from the nucleus during beta decay.

Therefore, the only true statement regarding beta particles is that their formation is accompanied by the conversion of a neutron into a proton, which leads to an increase in the atomic number of the nucleus. Therefore, Option D is correct.

which of the statements regarding beta particles are true?

A. beta particles have a mass number of 0.

B. beta-particle formation is accompanied by the conversion of a proton into a neutron.

C. beta particles have an atomic number of 1.

D. beta-particle formation is accompanied by the conversion of a neutron into a proton.

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Answer:

A

Explanation:

Answer:

see photo

Explanation:

PLATO answer

Answer:

Ummm haven't learneed it yet

Explanation:

Answer:

A conversion factor is a variable that transforms the dimension of one variable into the terms of another variable.

Explanation:

Let be \(x\) and \(y\) two variables with diferent dimensions (units), \(r\) is a conversion if transforms the dimension of one variable into the terms of the other variable. That is:

\(y = r\cdot x\) (1)

Where:

\(x\) - Input, [input unit]

\(y\) - Output, [output unit]

\(r\) - Conversion factor, [output unit] per [input unit]

In the synthesis of camphor, a common impurity that may be present is borneol.

Borneol is a stereoisomer of camphor, and the two compounds can interconvert under certain conditions. Borneol can be formed as an intermediate during the synthesis of camphor, and if not carefully controlled, it can contaminate the final product.

Borneol has a similar chemical structure to camphor, but it has different physical and chemical properties. Therefore, the presence of borneol as an impurity can affect the purity and properties of the synthesized camphor.

Stereoisomers are molecules with the same chemical formula and connectivity but differ in the spatial arrangement of their atoms, resulting in different properties.

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The mass of moles of one mole of potassium permanganate is 170.6 g.

The number of moles of one mole of potassium permanganate is calculated as folows;

The molecular formula of  potassium permanganate is written as;

potassium permanganate = KMnO₄

K = potassium = 39 g/mol

Mn = Manganese = 55 g/mol

O = oxygen = 16

The molecular formula of  potassium permanganate is calculated as follows;

KMnO₄ = 39 + 55 + 4 (16)

KMnO₄ = 158 g/mole

One mole = 158 g/mol x  1 mole/1 = 158 g

1 mole ------- > 158 g

1.08 mole ------- ?

= 1.08 x 158 g

= 170.6 g

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ANSWER

EXPLANATION

Given that;

Follow the steps below to find the grams of H2SO4

Step 1; Find the number of moles of H2SO4 using the below formula

Recall, that Avogadro's number is 6.02 x 10^23

Step 2; Find the mass of H2SO4 using the formula below

Recall, that the molar mass of 98.079 g/mol

Answer:

d. NH4+ and C2H3O2- ions

Explanation:

When ammonium acetate (NH4C2H3O2) is mixed with water, it dissociates into its ions. In this case, it dissociates into NH4+ (ammonium ion) and C2H3O2- (acetate ion). Therefore, the solution will contain NH4+ and C2H3O2- ions dissolved in water.

The solution contains NH4+ and C2H302 ions. Among the given options, the correct answer is option d. It forms a solution containing NH4+ and C2H302 ions that are fully dissolved in the water.

When a chemist mixes ammonium acetate into 500 mL of water, the ammonium acetate (NH4C2H3O2) dissolves and dissociates into its constituent ions. This results in the formation of NH4+ ions (ammonium ions) and C2H3O2- ions (acetate ions) in the solution. Ammonium acetate is a salt that readily dissolves in water, dissociating into NH4+ and C2H302 ions. The aqueous solution will contain NH4+ ions and C2H3O2- ions, which are formed due to the dissociation of ammonium acetate in water. These ions will be dispersed throughout the solution and will not sink to the bottom.

In conclusion, when ammonium acetate is mixed into water, it forms a solution containing NH4+ and C2H302 ions that are fully dissolved in the water.

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Among the given images, the first structure is a valid representation of a hydrocarbon molecule. The given structure is of 3-methylpentane.

Hydrocarbons are a type of organic compounds containing carbon and hydrogen atoms only. Hydrocarbons can be long chain compounds with or without branches.

The carbon -carbon bond and the carbon - hydrogen bond in hydrocarbons are covalent bonds. The valency of carbon is 4. Hence, it only forms 4 bonds at a time.

In the second, third and 4th structures, the valency of carbon is not satisfied and it is correct in the first structure only. Hence, the first structure is a valid representation of a hydrocarbon molecule.

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A soft, silvery-white metal combines with a yellow gas to form a white crystal-like solid. Option D. The change is not a physical change because a new substance was formed.

Physical changes are changes affecting the shape of a chemical substance, but no longer its chemical composition. bodily changes are used to separate mixtures into their element compounds, however, cannot generally be used to split compounds into chemical factors or less difficult compounds.

In a physical change, the fabric worried inside the alternate is structurally the same before and after the exchange. varieties of a few physical modifications are texture, shape, temperature, and trade inside the country of depend. Trade in the texture of a substance is an alternative in the manner it feels.

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Disclaimer:- your question is incomplete, please see below for the complete question.

A. The change is a physical change because the yellow gas changed into a solid.

B. The change is a physical change because a new substance was not formed.

C. The change is not a physical change because the color of the metal changed.

D. The change is not a physical change because a new substance was formed.

Prokaryotic cells typically have diameters ranging from 0.1 to 5.0 micrometers (m) and are substantially smaller than eukaryotic cells, which typically have diameters ranging from 10 to 100 m.

A single-celled creature called a prokaryote lacks a nucleus and other membrane-bound organelles. The term prokaryote is derived from the Greek and v. Prokaryotes were classed into the empire Prokaryota in the two-empire concept developed by Édouard Chatton. A nucleoid area, DNA and RNA as genetic material, ribosomes that create proteins, and cytoplasm that contains a cytoskeleton that organizes cellular components are all present in all prokaryotic cells. Prokaryotic creatures, on the other hand, are a tremendously varied group of organisms that exist in a wide range of forms and sizes.

Here,

Prokaryotic cells typically have diameters ranging from 0.1 to 5.0 micrometers (m), making them substantially smaller than eukaryotic cells, which typically have dimensions ranging from 10 to 100 m.

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Answer:

true

Explanation:

Answer:

false

Explanation:

i took the test and got it right

Answer: P2= 3.41atm

Answer: 3.41

Hope this helps :)

C₂H₆, compound has a C-H bond with the lowest bond dissociation energy, hence option A is correct.

Toluene has the lowest bond dissociation energy because it undergoes hyper conjugation with the C-H protons.

The energy needed to break a bond and create two atomic or molecular fragments, each containing one of the original shared pair of electrons, is known as the bond dissociation energy.

As a result, an extremely stable bond has a high bond dissociation energy, meaning additional energy is required to break the binding.

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0.140 g of chromium metal will produce 0.102 g of chromium(iii) oxide.

To find the mass of chromium(iii) oxide produced when 0.140 g of chromium metal reacts completely with oxygen, we need to use stoichiometry and the balanced chemical equation for the reaction. The balanced equation is:
4 Cr + 3 O2 = 2 Cr2O3

From the equation, we can see that 4 moles of chromium react with 3 moles of oxygen to produce 2 moles of chromium(iii) oxide.

To calculate the mass of chromium(iii) oxide, we need to find the number of moles of chromium metal first. We can do this by dividing the given mass of chromium metal by its molar mass, which is 52 g/mol.

0.140 g Cr × (1 mol Cr / 52 g Cr) = 0.00269 mol Cr

According to the stoichiometry of the balanced equation, 4 moles of chromium react with 2 moles of chromium(iii) oxide. Therefore, the number of moles of chromium(iii) oxide produced is half the number of moles of chromium.

0.00269 mol Cr × (1 mol Cr2O3 / 4 mol Cr) = 0.0006725 mol Cr2O3

Finally, to calculate the mass of chromium(iii) oxide, we multiply the number of moles by its molar mass, which is 152 g/mol.
0.0006725 mol Cr2O3 × (152 g Cr2O3 / 1 mol Cr2O3) = 0.102 g Cr2O3

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Answer:

Charge is conserved due to the groups in which Lithium and Chlorine are located in the periodic table of the elements.

Explanation:

In the reaction \(Li + Cl - > LiCl\), we can examine the groups in which Li and Cl are found in the periodic table of the elements. Lithium appears in Group 1A, or the alkali metals group, indicating that it carries a charge of +1. Chlorine appears in Group 7A, or the halogen group, indicating that it carries a charge of -1. Because LiCl's constituent elements carry the same charges as previously mentioned, LiCl will have an overall charge of 0.

The chemical equation can then be rewritten as \(Li^{+} + Cl^{-} - > LiCl\), which, if looking at the individual charges of Li and Cl in lithium chloride, becomes \(Li^{+} + Cl^{-} - > Li^{+}Cl^{-}\). Adding the charges on the reactant and product sides of this chemical equation gives us zero in both locations, meaning that we have a charge of 0 on the reactant side and a charge of 0 on the product side. This indicates that charge is conserved in this reaction.

Another way to look at this is expressed in the valence electrons of Li and Cl. Li has an electron configuration of \(1s^{2}2s^{1}\), where the n = 2 electron shell has one of eight total electrons needed to fill the valence shell. This means that Li will easily lose one electron in order to have an electron configuration where the n = 1 electron shell is full, \(1s^{2}\), and become the \(Li^{+}\) ion. Similarly, Cl has an electron configuration of \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{5}\) (or \([Ne]3s^{2}3p^{5}\)), meaning that the n = 3 electron shell is one electron away from becoming complete. Cl will easily gain one electron to have the electron configuration \([Ne]3s^{2}3p^{6}\) (or \([Ar]\)) in order to have an electron configuration where the n = 3 electron shell is full, \(3s^{2}3p^{6}\), and become the \(Cl^{-}\) ion. Thus, when Li and Cl bond, Li will lose the electron \([1, 0, 0, +\frac{1}{2}]\) and transfer it to Cl, where it will become the electron \([3, 1, 1, -\frac{1}{2}]\), thus conserving charge, as there is an equal total number of electrons before and after the reaction.

Answer:

A. a wild dog that finds and mates with a domestic dog.

Explanation:

Answer:

22 and 28 and 22

Explanation:

Brainliest please!

Answer:

22

28

22

Explanation:

hopes this helps can i have brainlist pls trying to get a new role :^)

To solve this question we will assume that the moles of gas do not change and that the gas behaves like an ideal gas.

For an ideal gas we have that its behavior will be according to the following equation:

Where,

P is the pressure of the gas, in atm

V is the volume of the gas, in liters

n are the moles of the gas

T is the temperature of the gas, in Kelvin

R is a constant, 0.08206 atm.L/mol.K

We have for this gas two states, an initial state (1) and a final state (2), so for each state we can apply the ideal gas law, we will have:

Initial state:

Final state:

Since nR are constants, we can equate both equations:

For each state the conditions of pressure, volume and temperature will be:

P1=1.00atm

V1=195mL = 0.195L

T1=20°c = 293.15K

P2= 600mmHg=0.79atm

T2=60°C=333.15K

V2=Unknown

We clear V2 and replace the known data:

Answer: The final volume of the gas will be 280mL

The adjacent nucleotides are bound to each other through a phosphodiester bond in a nucleic acid.

Nucleic acid is a biopolymer made up of nucleotide monomers that make up nucleic acid chains. The nucleotide's three components are a five-carbon sugar, a phosphate group, and a nitrogenous base. Nucleic acids are present in all living cells, including viruses and bacteria, and they play a critical role in storing, transmitting, and expressing genetic information. RNA and DNA are two types of nucleic acids.

The phosphate group in one nucleotide forms a phosphodiester bond with the hydroxyl group on the sugar molecule of the next nucleotide in line in nucleic acids. This reaction is carried out by removing a molecule of water, resulting in a strong covalent bond between two nucleotides. These bonds make up the sugar-phosphate backbone of a nucleic acid chain, which is fundamental to its structure.

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The amount of heat released when 75 g of CH4O reacts is -1705.64 kJ.

The equation given is the balanced equation for the combustion of methanol (CH4O) with oxygen to form carbon dioxide (CO2) and water (H20). The value of ΔΗ given (-726 kJ) is the enthalpy change for the reaction, which represents the amount of heat released or absorbed when the reaction occurs.

To calculate the amount of heat released when 75 g of CH4O reacts, we need to use the equation: q = n x ΔΗ where,

We know that the molar mass of CH4O is 32.04 g/mol, so we can convert 75 g to moles using the following formula: n = m/M where,

So, n = 75 / 32.04 = 2.34 moles

Using this value of n in the equation above, we can calculate the heat released as q = 2.34 x -726 = -1705.64 kJ

Therefore, -1705.64 kJ of heat is released when 75 g of CH4O reacts.

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p [OH-] = -log[OH-]= -log ( 1x10^-11M) = 11

we know that

p[OH-] + p[H+] = 14

so p[H+] = 14- p[OH-] = 14- 11 = 3

pH = 3, answer

a. The new electronic configuration of Neon is 1s²2s²2p⁶ + 2p² + 2p² + 2p² or 1s²2s²2p⁹.

b. The element with a completed n = 2 shell is Oxygen (O).

c. The number of unpaired electrons in F is 1.

Given, ms can take +1/2, 0, and -1/2 values whereas other quantum numbers remain the same as in our universe.

As per Pauli's exclusion principle, no two electrons can have the same set of four quantum numbers. Therefore, the number of electrons with the same value of ms must not exceed the total number of orbitals available for that sublevel.

Each sublevel can have a maximum of 2(2l+1) electrons, where l is the azimuthal quantum number, that is, the letter associated with the sublevel.

a. Electronic configuration of Neon (Ne) = 1s²2s²2p⁶

The last electron added was to the 2p orbital. In our world, there are two 2p orbitals, one with ms = +1/2 and the other with ms = -1/2. In this new universe, we have three possible values of ms, implying that there are three 2p orbitals. Since Ne has 10 electrons, all three 2p orbitals are filled with 2 electrons each, and no 2 electrons have the same set of quantum numbers. Therefore, the new electronic configuration of Neon is 1s²2s²2p⁶ + 2p² + 2p² + 2p² or 1s²2s²2p⁹.

b. To determine the element with a completed n = 2 shell, we must locate the element whose electronic configuration has 2 electrons in the 2s orbital and 6 electrons in the 2p orbitals. The atomic number of such an element would be:

Atomic number = number of protons = 2 (from 1s²) + 2 (from 2s²) + 4 (from 2p⁴) = 8. Therefore, the element with a completed n = 2 shell is Oxygen (O).

c. The number of unpaired electrons in Fluorine (F) is 1, and the electronic configuration of F is 1s²2s²2p⁵. The 5 electrons fill up the 1s, 2s, and the first two 2p orbitals. The last electron goes to the third 2p orbital with ms = +1/2. This electron is unpaired and is present in a different orbital than the other 4 electrons in the 2p sublevel. Hence, the number of unpaired electrons in F is 1.

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Answer:

6.31x10^-10

Explanation:

Answer: 6.31 x 10^-10

Explanation:

The ignition occurs when a mixture of fuel & oxygen encounter an external heat source with sufficient heat Piloted ignition.

When a volatile fuel is close to a nearby local energy source (pilot) and reaches its lower limit of flammability in air, piloted ignition may be possible. The flame that originates in the premixed system spreads outward from the pilot. The first law of thermodynamics for systems with fixed mass only describes the energetics of this process.

The science of thermodynamics examines how heat, work, temperature, and energy are related. The general topic of thermodynamics is the transfer of energy from one location or form to another. The fundamental idea is that heat is a type of energy that is equivalent to a specific quantity of mechanical labor.

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When ignited, a uranium compound burns with a green flame, emitting light with a wavelength greater than that of red light, infrared light, radio waves, ultraviolet light, and gamma rays.

The color of a flame is determined by the energy levels of the atoms or molecules present in the burning substance. When uranium compounds burn, they release energy in the form of light. The specific wavelength of the emitted light corresponds to the energy difference between the electronic transitions occurring in the uranium atoms or ions.

In this case, the green flame suggests that the emitted light has a longer wavelength than red light, infrared light, radio waves, ultraviolet light, and gamma rays. Each of these options has a progressively shorter wavelength. Red light has a longer wavelength than green light, and it is visible to the human eye. Infrared light has even longer wavelengths and is not visible to the human eye, but it can be detected as heat. Radio waves have even longer wavelengths and are used for communication purposes. Ultraviolet light has shorter wavelengths than visible light and can cause harm to living organisms. Gamma rays have the shortest wavelengths and are highly energetic, typically associated with nuclear processes.

Therefore, the wavelength of the light emitted by a burning uranium compound falls within the range of visible light, specifically longer than that of red light.

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