This type of soil is found in warm, humid climates. question 5 options: pedocal laterite pedalfer humus

Answers

Answer 1

Answer:

Laterite would be your answer.

Explanation:

I hope this helps!

Answer 2

Laterite is the type of soil is found in warm, humid climates.

What is laterite soil?

Laterite is rich in iron and aluminum soil and rock type that is thought to have originated in hot, humid tropical climates. Nearly all laterites are of rusty-red hue, because of significant iron oxide concentration.

They form as a result of intense and extended erosion of the underneath rock material, which occurs most often when there are high temperatures and significant rainfall, with alternate wet and dry intervals.

Tropical weather is a long-term chemical weathering process that results in a wide range of soil thickness. Laterite is the type of soil is found in warm, humid climates.

Hence laterite is the correct option.

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Related Questions

Suppose that it takes a simple pendulum 1.2 seconds to swing from its leftmost point to its rightmost point. what is the period of the pendulum

Answers

The time period of the simple pendulum is 2.4 seconds.

Given the data in the question;

Time taken to swing from leftmost point to rightmost point; \(t = 1.2s\)Period of the pendulum; \(T = \ ?\)

What is Period?

Period is the time needed for a complete cycle of vibration to pass a given point.

Period of a pendulum is the of time needed for it to complete one full back-and-forth motion. It is the time required to for the pendulum to swing from leftmost point to rightmost point and back to leftmost point.

Now, if it took the pendulum \(1.2s\) to swing from leftmost point to rightmost point, it will also take the pendulum \(1.2s\) to swing back to its original position( leftmost point )

Hence,

\(T\) = time taken to swing from leftmost to rightmost + time taken to swing from rightmost point to leftmost point.

\(T = 1.2s + 1.2s\\\\T = 2.4s\)

Therefore, the time period of the simple pendulum is 2.4 seconds.

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We return to a circuit that you partly examined in the pre-lab for electricity IV. You were in a position to make predictions about the brightness of the identical bulbs in; Circuit 1 0 B A oc But you weren't asked to predict the effect of closing the switch on bulb A (although you built and observed the actual brightness of bulb A earlier in this lab). Multimeters Paul Mac Alevey Fall 2021 At the end of the pre-lab, we noticed that the flow through bulb A involved two competing factors: the flow from the battery increased when the switch was closed. The model of electricity is given later in this introduction 1. Explain why the flow from the battery increases when the switch is closed. Give the label of the concept(s) that you use from the model of electricity. [3] However, when the switch is closed, only half of the increased) flow goes through bulb A and the other half goes through bulb C. 2. Explain how we know that the flow splits in half. Give the label of the concept(s) that you use from the model of electricity. 121 The following table will help you to include the idea of pressure difference in the analysis. There will be a flow from the battery when the switch is open and, for the sake of discussion, we'll call that flow 1 glow. Assume that the obstacle presented by any of the identical bulbs is L no matter what flow goes through it. (This assumption is equivalent to;'assume that the bulbs are ideal'. ) Table 6: Obstacle presented Flow from to Battery (in terms Battery of L) Pressure Difference Flow caused by the Battery through bulb 4 Switch open 1 glow Switch closed 3. Fill out the rest of table six in your pre-lab. 171 4. Explain the change in brightness of bulb A when the switch closes. [1] Notice that this explanation is not possible without the knowing about pressure difference (as measured by 'product')

Answers

We return to a circuit that you partly examined in the pre-lab for electricity IV. When the switch is closed, the flow from the battery increases.

The half of the increased flow from the battery goes through bulb A and the other half goes through bulb C.

The brightness of both bulbs A and C increase when the switch is closed.

1. When the switch is closed, the flow from the battery increases because the switch provides an additional pathway for the current to flow through. This pathway has a lower resistance compared to the original pathway that included bulb A, so more current can flow through the circuit overall. This is known as Kirchhoff's junction rule, which states that the total current entering a junction must equal the total current leaving the junction.

2. We know that the flow splits in half because the bulbs are identical, so they have the same resistance. According to Ohm's law, the current through each bulb is proportional to the voltage across it, and since the voltage across the bulbs is the same, the current through each bulb must be equal. Therefore, half of the increased flow from the battery goes through bulb A and the other half goes through bulb C.

3. Table 6

Obstacle presented (L)

L

L

Flow from battery (in terms of L)

1

2

Pressure Difference (product)

L

2L

Flow caused by the battery through bulb A (in terms of L)

0

L/2

Flow caused by the battery through bulb C (in terms of L)

0

L/2

4. When the switch closes, the pressure difference (product) increases from L to 2L, which causes the flow from the battery to increase from 1L to 2L. Half of this increased flow, or L, goes through bulb A, which causes its brightness to increase. The other half of the increased flow also goes through bulb C, which also causes its brightness to increase. Therefore, the brightness of both bulbs A and C increase when the switch is closed.

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If m=120kg and a=15m/s2, what is the force

Answers

Answer:

F= 1800N

Explanation:

the equation for force is F= ma

so plug in the numbers: F= (120)(15)

solve this to get F= 1800N

tip: don't forget to add the units when writing your answer :)

The gravitational force between two students sitting beside each other on Earth is

Answers

Answer:

Fgrav. = GM1×M2/R2

Explanation:

Gravitational force is mostly related

to planetary bodies by Newton's law of gravitation which states that the gravitional force is proportional to the product of the mass of the object and inversely proportional to the square of the distance between them.

Hence in this case the Gravitational force,

Fgrav. = GM1×M2/R2

M1 and M2 are the mass of the two students and R is their distance apart

G is a constant known as gravitational constant.6.67408 × 10-11 m3/kgs2

Four weights, of masses m₁ = 6.50 kg, m₂ = 3.80 kg,
m3 = 10.70 kg, and m₁ = 4.20 kg, are hanging from
a ceiling as shown in the figure. They are connected
with ropes. What is the tension in the rope connecting
masses m, and m₂?
9
W

Answers

The tension in the rope connecting masses is 47N.

In a rope with two masses, how do you determine tension?

Mass 1 is only being pulled to one side by the pull caused by the tension in the rope. Because of the rope and lack of friction, the acceleration is the same, and the tension T is therefore given by T=m₁F/(m₁+m₂).

Any two physical objects in contact have the ability to exert forces on one another. Based on the kinds of objects in touch, we give these contact forces various names. When a rope, string, chain, or cable is one of the things applying the force, the force is referred to as tension.

Given,

m₁ = 6.50 kg, m₂ = 3.80 kg,

m₃ = 10.70 kg, and m₄ = 4.20 kg

The tension in the rope(T) = 2g(m₁)(m₂)/(m₂+m₁)

The tension in the rope(T) =2×9.8×6.50×3.80/3.8+6.5

The tension in the rope(T) = 484.12/10.3

The tension in the rope(T) = 47N.

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A tap supplies water at 26°c while another supplies at 82°c. If a man wishes to bath with water at 40°c, what is the ratio of the mass of hot water to that of cold water

Answers

Where a tap supplies water at 26°c while another supply at 82°c. If a man wishes to bath with water at 40°c, then the ratio of the mass of hot water to that of cold water is: 1/3.

What is the rationale for the above response?

The ratio of the mass of hot water to that of Cold water is determined as follows:

M₁C (82  40) = M₂C (40-26)

Where M₁C is the Mass of Tap 1; and

M₂C is the Mass of Tap 2.

Thus,

M₁C (82  40) = M₂C (40-26)

M₁/M₂ = 14/42

= 1/3

Thus, it is right to state that the ratio of the mass of hot water to that of cold water is: 1/3.

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Use the light speed (3.00 x 108 m/s) and a given frequency or wavelength value for a light wave to calculate the wavelength or the frequency of the wave.

Determine the wavelength of the infrared carrier wave transmitted by a television remote control at 36 500 Hz. Round your answer to two places after the decimal

Answers

The wavelength of the infrared carrier wave transmitted by a television remote control at 36 500 Hz is 8.21 x 10³ m

The speed of the light = 3 x 10⁸ m/s

The frequency of the remote control = 36,500 Hz

The wavelength of the infrared carrier can be found using the formula,

                          λ = c/ν

where λ is the wavelength of the infrared carrier

          c is the speed of the light

          ν is the frequency of the infrared carrier

Substituting the known values in the above equation,

                  λ = 3 x 10⁸ / 36,500

                     = 0.0000821 x 10⁸

                     = 8.21 x 10³ m

Thus, the wavelength of the infrared carrier is  8.21 x 10³ m

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An object is moving back and forth on the x-axis according to the equation x(t) = 3sin(20πt), t> 0, where x(t) is measured in cm and t in seconds. Give decimal answers below. (a) How many complete back-and-forth motions (from the origin to the right, back to the origin, to the left and finally back to the origin) does the object make in one second? (b) What is t the first time that the object is at its farthest right? (c) At the time found in part (b), what is the object's velocity? (d) At the time found in part (b), what is the object's acceleration?

Answers

Answer:

a.) 10Hz

b.) 0.1 s

c.) 187.4 m/s

d.) -412.6 m/s^2

Explanation:

Given that an object is moving back and forth on the x-axis according to the equation x(t) = 3sin(20πt), t> 0, where x(t) is measured in cm and t in seconds. Give decimal answers below.

(a) How many complete back-and-forth motions (from the origin to the right, back to the origin, to the left and finally back to the origin) does the object make in one second?

from the equation given,  the angular speed w = 20π

but w = 2πf

where f = frequency.

substitute w for 20π

20π = 2πf

f = 20π/2π

f = 10 Hz

(b) What is t the first time that the object is at its farthest right?

since F = 1/T

T = 1 / f

T = 1/10

T = 0.1 s

Therefore, the t of  first time that the object is at its farthest right is 0.1 s

(c) At the time found in part (b), what is the object's velocity?

The velocity can be found by differentiating the equation;

x(t) = 3sin(20πt)

dx/dt = 60πcos(20πt)

where dx/dt  = velocity V

V = 60πcos(20π * 0.1)

V = 187.4 m/s

(d) At the time found in part (b), what is the object's acceleration?

to get the acceleration, differentiate equation  V = 60πcos(20πt)

dv/dt = -1200πSin(20πt)

dv/dt = acceleration a

a = -1200πSin(20πt)

substitute t into the equation

a = -1200πSin(20π * 0.1)

a = - 412.6 m/s^2

The type of motion the object undergoes that consist of a back-and-forth

movement that is repetitive is a simple harmonic motion.

The correct responses are;

(a) Number of complete back-and-forth motions per second is 10(b) The first time is after 0.025 seconds(c) Velocity is 0(d) Acceleration is approximately -11843.53 m/s²

Reasons:

The equation that represents the motion of the object is x(t) = 3·sin(20·π·t)

Where;

t ≥ 0

x(t) is in cm, and t is in seconds.

(a) The general sine function is y = A·sin(B·(t - C) + D

\(\mathrm{The \ period \ P} = \dfrac{2 \cdot \pi}{B}\)

By comparison, we have;

B = 20·π

Therefore;

\(P = \dfrac{2 \cdot \pi}{20 \cdot \pi} = \dfrac{1}{10} = 0.1\)

The period, which is the time to complete one cycle = 0.1 seconds

The number of cycle completed per second, is the frequency, f

\(f = \dfrac{1}{P} = \dfrac{1}{0.1} = 10\)

f = 10 Hz = 10 cycles

The number of cycle completed per second is f = 10 cycles

(b) When the object is at the farthest right, we have;

sin(20·π·t) = Maximum = 1

\(\mathbf{sin\left(\dfrac{\pi}{2}\right)} = 1\)

Therefore,

\(20 \cdot \pi \cdot t = \dfrac{\pi}{2}\)

\(t = \dfrac{\pi}{20 \cdot \pi \cdot 2} = \dfrac{1}{40} = 0.025\)

The first time it is at the farthest right is t = 0.025 seconds after start

(c) \(\mathrm{Velocity, \ v, \ is \ given \ by \ v = \dfrac{dx(t)}{dt}}\)

Therefore;

\(v = \dfrac{dx(t)}{dt} = \dfrac{dx(t)}{dt} \left(3 \cdot sin \left(20 \cdot \pi \cdot t \right) = 60\cdot \pi \cdot cos \left(20 \cdot \pi \cdot t \right)\)

At t = 0.25 seconds, we have;

\(v = \dfrac{dx(t)}{dt} = 60\cdot \pi \cdot cos \left(20 \times \pi \times 0.025 \right) = 0\)

The velocity of the object at the t = 0.025 seconds is v(t) = 0

(d) Acceleration, a, is given by \(a = \dfrac{dv(t)}{dt}\)

Therefore;

\(a = \dfrac{dv(t)}{dt} = \dfrac{d}{dt} \left( 60\cdot \pi \cdot cos \left(20 \times \pi \times t\right) \right) =-1200 \cdot \pi ^2 \cdot sin(20 \cdot t \cdot \pi)\)

a = -1200·π²·sin(20·t·π)

∴ a = -1200×π²×sin(20×0.025×π)

sin(20×0.025×π) = 1

∴ a = -1200×π²×1 ≈ -11843.53

At the time found in part b the acceleration of the object, a ≈ -11843.53 m/s²

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how would a planet move if the sun suddenly disappeared ?

Answers

Explanation:

The sun gravity keeps the solar system i.e planets in its place and orbits if there is no sun the planets would flying off and  It would be complete and utter chaos in our solar system

HELP PLZZZZZ NOW!!!
Discuss how earthquakes are affected by the uneven distribution of Earth’s natural resources like minerals, energy, and groundwater resources, and how human activities affect Earth’s processes. Discuss past events and future risks associated with such activities in the country you selected.
Propose at least 1 resolution that the Ministry of Environment can take to limit the negative effects of such activities and as a result protect the country against harmful earthquakes.

Answers

Answer:Climatic processes affect the dynamics of Earth's ice sheets and glaciers, and along ... by abrupt events and by continuous reshaping of Earth's surface from surface ... Forecasting natural disasters, including the timing and size of earthquakes, the . Last, human activity has a profound impact on water resources, landscape

Explanation:

step by step

If it takes 600 N to move a box 5 meters, how much work is done on the box?
O
A. 600 J
OB. 5,000 J
O C. 3,000 J
O D. 120 J​

Answers

Answer:

3000 J

Option C is the correct option.

Explanation:

Given,

Force = 600 N

Distance = 5 meters

Work = ?

Now,

Work = Force \( \times \) distance

\( = 600 \times 5\)

Calculate the product

\( = 3000 \: \) Joule

Hope this helps...

Good luck on your assignment..

C it is 600 x 5 = 3000 J hope this helped!

3 after a completely inelastic collision, two objects of the same mass and same initial speed move away together at half their initial speed. find the angle between the initial velocities of the objects.

Answers

The angle between the initial velocities is 60 degrees. an inelastic collision, kinetic energy is not conserved, but momentum is. Let's assume that the two objects are moving in the x-y plane. Let their initial velocities be v1 and v2, with an angle θ between them. After the collision, the two objects move together with a speed of v/2, where v = v1 + v2 is the initial speed.

Using the law of conservation of momentum, we can write:

m*v1 + m*v2 = 2*m*(v/2)

where m is the mass of each object. Simplifying this expression, we get:

v1 + v2 = v

Substituting v/2 for v in the above expression, we get:

v1 + v2 = 2*(v/2) = v/2

We can then solve for v1 and v2 in terms of v and θ:

v1 = v*cos(θ/2)

v2 = v*sin(θ/2)

Substituting these expressions into the equation v1 + v2 = v/2, we get:

v*cos(θ/2) + v*sin(θ/2) = v/2

Dividing both sides by v/2 and simplifying, we get:

tan(θ/2) = 1/3

Solving for θ, we get:

θ = 2*arctan(1/3) = 60 degrees

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The eye of the Atlantic giant squid has a diameter of 3.50 × 10^2 mm. If the eye
is viewed in a concave mirror with a radius of curvature equal to the diameter
of the eye and the eye is 0.800 × 10^3 mm from the mirror, how far is the image
from the mirror? What is the size of the image? Is the image real or virtual?​

Answers

Answer:

   q = 224 mm,   h ’= - 98 mm, real imagen

Explanation:

For this exercise let's use the constructor equation

        \(\frac{1}{f} = \frac{1}{p} + \frac{1}{q}\)

       

where f is the focal length, p and q are the distance to the object and the image respectively.

In a mirror the focal length is

        f = R / 2

indicate us radius of curvature is equal to the diameter of the eye

       R = 3,50  10² mm

       f = 3.50 10² /2 = 1.75 10² mm

they also say that the distance to the object is p = 0.800 10³ mm

        1 / q = 1 / f - 1 / p

        1 / q = 1 / 175 - 1 /800

        1 / q = 0.004464

         q = 224 mm

to calculate the size let's use the magnification ratio

          m = \(\frac{h'}{h} = - \frac{q}{p}\)

          h '= \(- \frac{q}{p} \ h\)

          h ’= - 224 350 / 800

          h ’= - 98 mm

in concave mirrors the image is real.

What is the efficiency of a light bulb if it produces 30j of light energy, with an input of 120j of electrical energy?

Answers

The efficiency of this light bulb is 25% .

How do you calculate the efficiency of a light bulb?Utilizing the following formula, efficiency may be represented as a ratio: output input. The total quantity of beneficial work accomplished, excluding waste and spoilage, is known as output or work output. Efficiency may also be expressed as a percentage by dividing the ratio by 100.To represent the result as a percentage, divide the output by the input and then multiply by 100. Although both work and energy are measured in terms of the Joule, the calculator above has a space for a different unit. Make sure the energy and labour units are equivalent.Efficiency is essentially a measurement of the amount of labour or energy that may be saved throughout a process. In other words, it's similar to comparing the energy intake and output in any particular system.

Given data :

output = 30j

Input = 120j

Efficiency  = output / input x 100

  = 30 / 120 x 100

  = 25%

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Modifying games is one way to level the playing field for individuals of varying abilities provide four examples of how you could modify the game of baseball

Answers

It has been demonstrated that modified sports, in which the equipment and rules are altered to improve skill performance, foster skill learning and may even boost participation.

The sport is replicated in a modified game, although some of the regulations are altered. Limited touches or time with the ball, a smaller field or court, different-sized balls or goals, or the obligation to defend repeatedly are some examples of modified rules. Like any other sport you may have played, such as basketball or football, modified sports feature regulations that have been modified to take into account the talents and abilities of older or less mobile participants. Depending on the skills of the participants who want to participate, modified sports can be altered.

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A slinky was measured to carry a longitudinal wave 10 tiles (on the floor) per second. One tile is 30 cm. What is the speed of this wave? In your answer , use millimeters and scientific notation

Answers

(10 tiles/sec) · (30 cm/tile)  =  300 cm/sec

That's  3000 mm/sec

That's  3 x 10³  mm/sec

Substitute for F from Part B in the expression for work from Part C. Then substitute for a from the relation in Part A. This will yield an expression for the network W done on the particle by the external forces during the particle's motion in terms of mass and the initial and final velocities. Give an expression for the work W in terms of those quantities.

Answers

To find the expression for the work W done on the particle by the external forces during the particle's motion in terms of mass and the initial and final velocities,

1. Substitute for F from Part B: Recall that from Part B, we have F = ma,

where F is the force, m is the mass, and a is the acceleration.

2. Substitute for a from the relation in Part A: From Part A, we have the relation a = ( v*f - vi) / t,

where vf is the final velocity, vi is the initial velocity, and t is the time.

3. Now, substitute the expression for a from step 2 into the equation for F from step 1: F = m * (v f - v i) / t

4. Next, find the expression for work, W: Recall that W = F * d,

where W is the work done, F is the force, and d is the distance.

5. Substitute the expression for F from step 3 into the equation for W from step 4: W = (m * (v*f - vi) / t) * d

6. Finally, to express W in terms of mass, initial and final velocities, we can use the relation d = (vi + v*f) / 2 * t. Substituting this relation for d in the equation from step 5, we get:

W = (m * (vf - vi) / t) * ((vi + vf) / 2 * t)

7. Simplify the expression by canceling out the t terms: W = (1/2) * m * (vf^2 - vi^2)

So, the expression for the work W done on the particle by the external forces during the particle's motion in terms of mass and the initial and final velocities is:  W = (1/2) * m * (vf^2 - vi^2)

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Select the correct answer

What happens to a sound wave when it interie with another sound wave hdking the same frequency but traveling in the opposite direction?

A. Astanding wave is generated
B. Beats are produced
C. Atraveling wave is generated
D. Resonance occurs
E. The frequency of the resultant wave decreases

Answers

A. A standing wave is generated

Answer:

A. Astanding wave is generated

Explanation:

Standing waves arise from the interference of traveling and reflected waves, which have the same wavelength at the point of reflection, but mutually opposite directions of propagation.

can both liquid water and steam exist at 100°C​

Answers

Explanation:

Yes , Both liquid water and steam exist at 100°C

Hope it will help you

what are the two purposes of heat fixation?

Answers

Heat fixing kills or eliminates the contaminating organisms that are present in the sample and allows better penetration of certain stains into the cell.

Those are the two purposes, hope this helps have an excellent day!

Sean is moving heavy furniture by sliding it across the floor. He puts a blanket underneath the furniture. Why dis this help him?

Answers

I think that it would help him so it can slide and help him move his furniture faster

For the PE formula, why is the height required for calculations? Why do we need to know the height in order to determine PE? *

Answers

Answer:

Answer in Explanation

Explanation:

Whenever we talk about the gravitational potential energy, it means the energy stored in a body due to its position in the gravitational field. Now, we know that in the gravitational field the work is only done when the body moves vertically. If the body moves horizontally on the same surface in the Earth's Gravitational Field, then the work done on the body is considered to be zero. Hence, the work done or the energy stored in the object while in the gravitational field is only possible if it moves vertically. This vertical distance is referred to as height. This is the main reason why we require height in the P.E formula and calculations.

The derivation of this formula is as follows:

Work = Force * Displacement

For gravitational potential energy:

Work = P.E

Force = Weight = mg

Displacement = Vertical Displacement = Height = h

Therefore,

P.E = mgh

Eric has a mass of 19.0 kg on the earth. What is Eric's weight on earth? What is Eric's weight on Mars? where the acceleration of gravity is approximately 0.381 of that of Earth's? ________.

Answers

Answer:

Weight on Earth = We = 186.2 N

Weight on Mars = Wm = 70.94 N

Explanation:

The weight of an object is defined as the force applied on the object by the gravitational field. The magnitude of weight is given by the following formula:

W = mg

were,

W= Weight of Eric

m = mass of Eric

g = acceleration due to gravity

ON EARTH:

W = We = Eric's Weight on Earth = ?

m = Eric's Mass on Earth = 19 kg

ge = acceleration due to gravity on Earth = 9.8 m/s²

Therefore,

We = (19 kg)(9.8 m/s²)

We = 186.2 N

ON MARS:

W = Wm = Eric's Weight on Mars = ?

m = Eric's Mass on Mars = 19 kg

gm = acceleration due to gravity on Mars = 0.381(ge) = (0.381)9.8 m/s² = 3.733 m/s²

Therefore,

Wm = (19 kg)(3.733 m/s²)

Wm = 70.94 N

Discribe the phrase "like dissolves like" in terms of polarity.

Answers

The phrase "like dissolves like" can be described as the compounds which have similar nature dissolve in each other that is polar dissolves polar and non-polar dissolves non-polar molecules.

What is Polarity?

Polarity is the separation of electric charge which is leading to a molecule or the chemical groups which are having an electric dipole moment, with a negatively charged end and a positively charged end as well. Polar molecules are the molecules which must contain one or more polar bonds which occur due to a difference in the electronegativities between the bonded atoms of the molecule.

A simple way to predict the compounds which will dissolve in other compounds is the phrase of the compound such as "like dissolves like". This means that the polar compounds dissolve in polar compounds, and the nonpolar compounds dissolve in nonpolar compounds, however, the polar and nonpolar molecules do not dissolve in each other.

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what is the total work wfric done on the block by the force of friction as the black moves a distance l up the incline

Answers

The total work done by the force of friction on the block as it moves a distance L up the incline is given by the formula:

Wfric = −f × L

The work done by the force of friction on the block as it moves a distance L up the incline is equal to the product of the force of friction and the distance moved. Work is the measure of the amount of energy transferred by a force when an object is moved a certain distance. If a force acts on an object and the object moves, work is done by the force. Therefore, work can be defined as the product of force and displacement.

Mathematically, it can be expressed as follows:

W = F × S

where W is work, F is force, and S is displacement. The SI unit of work is joules (J). When a block moves on an inclined plane, friction is one of the forces acting on the block. As the block moves up the plane, the force of friction acts opposite to the direction of motion of the block. Hence, the work done by the force of friction is negative. This means that the force of friction acts to decrease the energy of the block.

The work done by the force of friction on the block as it moves a distance L up the incline is given by the formula:

Wfric = −f × L

where Wfric is the work done by the force of friction, f is the force of friction, and L is the distance moved by the block up the incline. Therefore, the total work done by the force of friction on the block as it moves a distance L up the incline is given by the formula:

Wfric = −f × L

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What provides the original mechanical energy for the simple generator in the figure?

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According to the given figure(See Picture),  some external source, such as a turbine, windmill, or water wheel, supplies the initial mechanical energy for a simple generator.

A type of energy known as mechanical energy is related to an object's location and motion. It is the total of an object's kinetic energy and potential energy. The energy that an object has as a result of its motion is known as kinetic energy, whereas the energy it has as a result of its location or other state is known as potential energy. Several natural and industrial systems, including engines, turbines, and machines, depend heavily on mechanical energy. A fundamental tenet of physics, the conservation of mechanical energy is frequently applied to understand and forecast the behaviour of physical systems. Ultimately, the study and comprehension of the physical world around us depend heavily on the concept of mechanical energy.

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What provides the original mechanical energy for the simple generator in the figure(See Picture)?

What provides the original mechanical energy for the simple generator in the figure?

How does the ratio of tin to copper affect the properties of the alloy bronze?

Answers

Answer:

Stronger and harder than either of the pure metals

Explanation:

a brass rod is encased in aluminum. what happens to the speed of a sound wave when it moves from the aluminum into the brass?

A. it stays the same.

B. it decreases.

C. it falls to zero.

D. it increases

Answers

A brass rod is encased in aluminium. The speed of a sound wave decreases when it moves from the aluminium into the brass. Thus, the correct option is B.

What factors affect speed of sound?

The speed of sound is the speed with which sound travels in a medium. It depends on the density and the elasticity of the medium through which the sound waves travel. In general, sound wave travels faster in the liquid mediums than in gas medium and these are quicker in solids than in liquid mediums. The greater the elasticity and the lower the density of the waves, the faster the sound waves travel in a medium.

The speed of sound in aluminium is 5100m/s and in brass it is 6,923. So, if the sound wave is moving from aluminum to the brass medium, we can clearly observe that the speed of sound is decreasing. So, we can say here that it decreases.

Therefore, the correct option is B.

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Salmon often jump waterfalls to reach their
breeding grounds.
Starting downstream, 2.61 m away from a
waterfall 0.277 m in height, at what minimum
speed must a salmon jumping at an angle of
39.3° leave the water to continue upstream?
The acceleration due to gravity is 9.81 m/s.
Answer in units of m/s.

Answers

With the projectile launch we can find that the response for the initial velocity of the salmon is  3.68 m/s

Projectile launching is an application of kinematics for movement in two dimensions.  In this case they indicate the jump distance x = 2.61 m and the jump height y = 0.277 m and the angle of 39.3º and ask the initial velocity.

Let's use trigonometry for the initial velocity.

              cos 39.3 = \(\frac{v_x}{v}\)

              sin 39.3 = \(\frac{v_y}{v}\)

              vₓ = v cos 39.3

              = v sin 39.3

 

Suppose that when you reach the height of the waterfall you are in the highest part of the jump, therefore the vertical velocity is zero.

                \(v_y^2 = v_{oy}^2 -2 g y\)

                 0 = - 2 g y

                 \(v_{oy}\) = \(\sqrt{2gy}\)

           

Let's calculate

                 \(v_{oy} = \sqrt{2 \ 9.8 \ 0.277}\)

                  = 2.33 m / s

The relationship of the initial velocity and the angle.

                    = v sin 39.3

                   v = \(\frac{ v_{oy}}{son 39.3}\)

                   v = 2.33 / sin 39.3

                   v = 3.68 m / s

               

In conclusion using projectile launch we can find the initial velocity of the salmon is 3.68 m / s.

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A. B. C. D.
-___________

A. B. C. D.-___________

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where is the data for this question? what is the purpose ?
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