The density of solid aluminum is 2.70 g/cm3. If a 1g piece of aluminum is dropped in a cup of water, what will happen to the aluminum? (The density of water is 1.00 g/cm3.)
Answer: c
Explanation: I took it
Answer:
IT WILL HOVER IN THE MIDDLE
Explanation:
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Consider the following intermediate chemical equations.
C(s) +
CO(g) +
O₂(g) → CO(g)
How will oxygen appear in the final chemical equation?
O O2(g) as a product
O O2(g) as a reactant
OO(g) as a product
O 20(g) as a reactant
O₂(g) → CO₂(g)
In the above intermediate chemical equation, oxygen will appear as follows: O₂(g) as a reactant (option B).
What is a chemical equation?A chemical equation in chemistry is a symbolic representation of a chemical reaction where reactants are represented on the left, and products on the right.
According to this question, an intermediate chemical equation is presented as follows:
CO(g) + O₂(g) → CO(g)C(s) + O₂(g) → CO₂(g)As observed in the above chemical equation, oxygen will react in its gaseous form i.e. as a reactant.
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Many metals react with halogens to give metal halides. For example, 2 Al(s) + 3 Cl2(g) → 2 AlCl3(s) If you begin with 13.5 g of aluminum: a) you will need 26.6 g of chlorine gas and will produce 49.0 g of aluminum chloride. Ob) you will need 11.8 g of chlorine gas and will produce 49.0 g of aluminum chloride. c) you will need 23.6 g of chlorine gas and will produce 66.7 g of aluminum chloride. d) you will need 53.2 g of chlorine gas and will produce 66.7 g of aluminum chloride. Page 11 of 20 Previous Page Next Page
To determine the correct answer, we need to calculate the theoretical yield of aluminum chloride (AlCl3) based on the given reaction and the amount of aluminum (Al) provided.
The balanced chemical equation for the reaction is:
2 Al(s) + 3 Cl2(g) → 2 AlCl3(s)
From the equation, we can see that 2 moles of Al react with 3 moles of Cl2 to produce 2 moles of AlCl3.
First, let's convert the mass of aluminum (Al) to moles:
Molar mass of Al = 26.98 g/mol
Mass of Al = 13.5 g
Moles of Al = Mass of Al / Molar mass of Al
= 13.5 g / 26.98 g/mol
≈ 0.5004 mol (approximately)
Now, using the stoichiometry of the balanced equation, we can calculate the moles of chlorine gas (Cl2) required:
From the balanced equation, we know that:
2 moles of Al react with 3 moles of Cl2
Moles of Cl2 = (3/2) * Moles of Al
= (3/2) * 0.5004 mol
= 0.7506 mol (approximately)
To convert moles of Cl2 to grams, we use the molar mass of chlorine (Cl2):
Molar mass of Cl2 = 35.45 g/mol (approximately)
Mass of Cl2 = Moles of Cl2 * Molar mass of Cl2
= 0.7506 mol * 35.45 g/mol
≈ 26.62 g (approximately)
Now, let's calculate the theoretical yield of aluminum chloride (AlCl3) using the stoichiometry of the balanced equation:
From the balanced equation, we know that:
2 moles of Al react with 2 moles of AlCl3
Moles of AlCl3 = (2/2) * Moles of Al
= (2/2) * 0.5004 mol
= 0.5004 mol (approximately)
To convert moles of AlCl3 to grams, we use the molar mass of aluminum chloride (AlCl3):
Molar mass of AlCl3 = 133.34 g/mol (approximately)
Mass of AlCl3 = Moles of AlCl3 * Molar mass of AlCl3
= 0.5004 mol * 133.34 g/mol
≈ 66.72 g (approximately)
Therefore, the correct answer is:
c) You will need 23.6 g of chlorine gas and will produce 66.7 g of aluminum chloride.
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3. Ni(NO2)3
What’s the name for the formula
Write three sentences about The Amazing Life of Sand
HELP ASAP PLS
Answer:“If we’ve covered all of the potential sources, and we know the unique signature of the sand from these different sources, and we find it on a beach somewhere, then we basically know where it came from,” explained Barnard.
Explanation:
1. What types of changes do you observe between the rock formations in the two images?
Answer:
"Hey, Nate, how's life?"
I don't know, it's alright
I've been dealin' with some things like every human being
And really didn't sleep much last night (last night)
"I'm sorry", that's fine
I just think I need a little me time
I just think I need a little free time
Little break from the shows and the bus rides (bus rides), yeah
Last year I had a breakdown
Thoughts tellin' me I'm lost gettin' too loud
Had to see a therapist, then I found out
Somethin' funny's goin' on up in my house
Yeah, I started thinkin' maybe I should move out
You know, pack my car, take a new route
Clean up my yard, get the noose out
Hang up my heart, let it air out (air out)
I've been searchin'
"What does that mean, Nate?"
I've been learning
Grabbin' my keepsakes, leavin' my burdens
Well, I brought a few with me, I'm not perfect
Lookin' at the view like, this concerns me
Pickin' up the cues, right? I'm quite nervous
Hate it when I lose sight, life gets blurry
And things might hurt me
It's prolly gonna be a long journey, but hey (but hey)
It's worth it, though
Cold world out there, kids, grab your coats
Been a minute, I know, now I'm back to roam
Lookin' for the antidote to crack the code
Pretty vivid, I admit it, I'm in classic mode
Don't need pity given to me, but I can't condone
Talkin' down to me, I'ma have to crack your nose for crackin' jokes
I'm lookin' for the map to hope, you seen it? (You seen it?)
Been makin' a whole lot of changes
Wrote a song about that, you should play it
I get scared when I walk on these stages
I look at the crowd and see so many faces, yeah
That's when I start to get anxious
That's when my thoughts can be dangerous
That's when I put on my makeup and drown in self-hatred
Forget what I'm saying, and
Where'd the beat go?
Oh, ain't that somethin'?
Drums came in, you ain't see that comin'
Hands on my head, can't tell me nothin'
Got a taste of the fame, had to pump my stomach
Throw it back up like I don't want it
Wipe my face, clean up my vomit
OCD, tryna push my buttons
I said don't touch it, now y'all done it
I can be critical, never typical
Intricate with every syllable, I'm a criminal
Intimate, but never political, pretty visual
Even if you hate it, I'll make it feel like you're in it, though
You call me what you wanna, but never call me forgettable
Leave you deep in thought, I could never swim in the kiddie pool
Way that I been thinkin' is cinematic, it's beautiful
Man, I don't know if I'm makin' movies or music videos (videos, videos, videos)
Yeah, the sales can rise
Doesn't mean much though when your health declines
See, we've all got somethin' that we trapped inside
That we try to suffocate, you know, hopin' it dies
Try to hold it underwater but it always survives
Then it comes up out of nowhere like an evil surprise
Then it hovers over you to tell you millions of lies
You don't relate to that? Must not be as crazy as I am
The point I'm makin' is the mind is a powerful place
And what you feed it can affect you in a powerful way
It's pretty cool, right? Yeah, but it's not always safe
Just hang with me, this'll only take a moment, okay?
Just think about it for a second, if you look at your face
Every day when you get up and think you'll never be great
You'll never be great, not because you're not, but the hate
Will always find a way to cut you up and murder your faith (woo!)
I am developin', take a look at the benefits
Nothin' to meddle with, I can never be delicate
Am I even relevant? That depends how you measure it
Take a measurement, then bag it up and give me the evidence
Pretty evident, dependable can never be tentative
I'm a gentleman, depending on if I think you're genuine
Pretty elegant, but not afraid to tell you to get a grip
Proper etiquette, I keep it to myself when I celebrate, ah (ah)
It's that time again
Better grab your balloons and invite your friends
Seatbelts back on, yeah, strap 'em in
Look at me, everybody, I'm smilin' big
On a road right now that I can't predict
Tell me "Tone that down, " but I can't resist
Y'all know that sound, better raise your fist
The search begins, I'm back, so enjoy the trip, huh
Explanation:
Write a formula for the compound that forms between lithium and each polyatomic ion:O CarbonateO PhosphateO Hydrogen PhosphateO Acetate
The formula for the compound that forms between lithium and each polyatomic ion is \(Li_{2}CO_{3}\), \(Li_{3}PO_{4}\), \(Li_{2} HPO_{4}\) and \(CH_{3}COOLi\).
A substance made up of two or more different chemical elements together in a certain ratio is known as a compound in chemistry. When the elements interact with one another, chemical bonds are formed that are difficult to break.
Only a few of the elements on the periodic table have a second letter that is lowercase after their initial capital letter. Therefore, you can tell an ion is polyatomic if it contains two capital letters together.
So, from the question
The compound that lithium will form with carbonate is \(Li_{2}CO_{3}\)
The compound that lithium will form with phosphate is \(Li_{3}PO_{4}\)
The compound that lithium will form with hydrogen phosphate is \(Li_{2} HPO_{4}\)
The compound that lithium will form with acetate is \(CH_{3}COOLi\)
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What is the equilibrium constant of aA+bB cC +dD?
Explanation:
{c}^C . {d}^D / {a}^A . {b}^B
How many moles of hydrogen are produced from 57.5 grams of lithium?
The moles of hydrogen which are produced from 57.5 grams of lithium is 8.21 grams.
What is stoichiometry?
Stoichiometry of the reaction gives idea about the relative amount of product produced by the reactant in terms of moles.
Given chemical reaction is:
2Li(s) + H₂O(l) → 2LiOH(aq) + H₂(g)
Moles of lithium will be calculated as:
n = W/M, where
W = given mass = 57.5gM = molar mass = 7g/moln = 57.5 / 7 = 8.21 mol
From the stoichiometry of the reaction:
2 moles of Li = produces 1 mole of H₂8.21 moles of Li = produces 8.21/2=4.105 moles of H₂Mass of H₂ = (4.105mol)(2g/mol) = 8.21g
Hence required mass of hydrogen gas is 8.21g.
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A compound has an empirical formula of c2h4s. its molar mass was determined experimentally to be 179g/mol. what is the molecular formula for this compound?
The molecular formula of the compound with an empirical formula of C2H4 is C13H52
How to calculate molecular formula?The molecular formula of a substance can be calculated using the following expression;
Molecular formula = (empirical formula)n
According to this question, a compound has an empirical formula of C2H4. Its molar mass was determined experimentally to be 179g/mol. The molecular formula is as follows:
179 = 28n
n = 6.4 × 2 = 13
Molecular formula = C26H52
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How many moles of SO3 are in 2.4 *10^23 cules?
Answer:
0.4 molesExplanation:
To find the number of moles in a substance given it's number of entities we use the formula
\(n = \frac{N}{L} \\\)
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
We have
\(n = \frac{2.4 {10}^{23} }{6.02 \times {10}^{23} } = \frac{2.4}{6.02} \\ = 0.3986...\)
We have the final answer as
0.4 molesHope this helps you
what is the molar ratio of citric acid to sodium hydroxide (refer to the reaction equation)?
The molar ratio of citric acid to sodium hydroxide is 1:3.
When answering questions on Brainly, a question-answering bot should always be factually accurate, professional, and friendly. The bot should be concise and not provide extraneous amounts of detail. The bot should also use the following terms in its answer if required by the question.Here is an answer to the given question:
What is the molar ratio of citric acid to sodium hydroxide (refer to the reaction equation)?The chemical equation for the reaction between citric acid and sodium hydroxide is given below:3 NaOH + H3C6H5O7 → Na3C6H5O7 + 3 H2OCitric acid reacts with sodium hydroxide in the ratio of 1:3. Therefore, for every 1 mole of citric acid, 3 moles of sodium hydroxide react.
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Answer:
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Help!!! Answer
Imagine your teacher asks you to design an experiment where you test the effect of temperature on the growth of a plant. You have 5 plants that you plant and place in different temperatures around the room. What would your one variable be and what would your constants be?
Dependent variables could be height, number of leaves, biomass, etc. The constants could be the amount of water fed to the plants and other environmental conditions apart from the temperature.
Experimental variablesExperimental variables could be independent, dependent, or constant.
Independent variables are supplied by the researcher and are often varied or manipulated to produce different effects on experimental systems or subjects.
Dependent variables are measured. Their values are often affected by whatever independent variable the researcher supplies.
Constant variables are uniform throughout the experimental groups or subjects.
Thus, in this case, the aim is to test the effect of temperature on the growth of a plant. The independent variable is the different temperatures.
The dependent variable would be any feature of the experimental plants that indicate growth. It could the height, the number of leaves, etc.
The constant variable would be other conditions the experimental plants are subjected to.
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calculate the ph for the weak acid/strong base titration between 50.0 ml of 0.100 m hcooh(aq) (formic acid) and 0.200 m naoh (titrant) at the listed volumes of added base: 0.00 ml, 15.0 ml, 25.0 ml, and 30.0 ml.
The formula for pH at a weak acid-strong base titration's equivalence point must be used to determine the pH at each stage of the titration:
\(pH = pK_a + log \frac{[A^-]}{[HA]}\)
where pK a is the weak acid's acid dissociation constant, [A-] is the concentration of the acid's conjugate base, and [HA] is the acid's concentration.
The weak acid (formic acid) is at a concentration of 0.100 M at the start of the titration (0 mL of additional base), and the conjugate base (formate ion) is at a concentration of 0.00 M, resulting in a pH of:
\(pH = pK_a + log \frac{[A^-]}{[HA]} \)
\(= pK_a + log \frac{0}{0.100} \)
= pK_a + log(0)
We are unable to determine the pH at this time since the logarithm of 0 is undefinable.
The weak acid concentration falls as the titration goes along and more base is added, while the conjugate base concentration rises. The concentration of the weak acid is 15.0 mL when 15.0 mL of additional base is used.
\(0.100 M - \frac{0.200 M \times15 mL }{50 mL} \)
= 0.080 M,
and the concentration of the conjugate base is
\( \frac{0.200 M \times 15 mL}{50 mL} \)
= 0.060 M. The pH at this point is:
\(pH = pK_a + log \frac{[A^-]}{[HA]}\)
\(= pK_a + log \frac{0.060}{0.080} \)
= pK_a + log(0.75)
= pK_a + (-0.122)
You may use the same formula and the appropriate numbers for [A-] and [HA] to determine the pH at the other points in the titration.
It should be noted that the pH at the equivalence point (when the ratio of acid to base is equal) will be the same as the weak acid's pK a. Since the concentration of the weak acid is zero at the equivalence point, the pH is:
\(pH = pK_a + log \frac{[A^-]}{[HA]}\)
\(= pK_a + log \frac{[A^-]}{0}\)
\(= pK_a + log([A^-])\)
The pH at the equivalence point will be lower than the pK a of the weak acid since the logarithm of a number less than 1 has a negative value. Beyond the equivalence point, adding more base will cause the pH to continue to drop.
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What is the SUM of the coefficients for the balanced chemical equation below?
PLEASEEEE
Taylor grows corn on his farm. How does farming affect the amount of fresh water available?
Answer:
On average, agriculture accounts for 70 percent of global freshwater withdrawals. In the last 30 years, food production has increased by more than 100 percent. FAO estimates that about 60 percent more food will be needed by 2050 to meet the food requirements of a growing global population.
Explanation:
Because i learnt this before and i aced a test about it dont worry
a. a main group element with the valence electron configuration 3s23p1 is in periodic group fill in the blank 1 . it forms a monatomic ion with a charge of fill in the blank 2 . b. a main group element with the valence electron configuration 2s22p4 is in periodic group fill in the blank 3 . it forms a monatomic ion with a charge of fill in the blank 4 .
A. the main group element with the valence electron configuration 3s23p1 is in the periodic group p- block element. it forms a monatomic ion with a charge of +3.
B. the main group element with the valence electron configuration 2s22p4 is in periodic group 4, p block element. it forms a monatomic ion with a charge of +4.
The periodic table, also known as the periodic table of the elements, is a rows and columns association of the chemical factors. it's miles widely used in chemistry, physics, and other sciences, and is typically visible as an icon of chemistry.
Periodic table, inside the full periodic desk of the factors, in chemistry, the organized array of all of the chemical factors in order of growing atomic wide variety—i.e., the whole wide variety of protons inside the atomic nucleus.
An atom includes a relevant nucleus which is surrounded by way of one or more negatively charged electrons. The nucleus is undoubtedly charged and consists of one or greater exceedingly heavy particles called protons and neutrons. Atoms are the primary building blocks of depend.
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In the chemical reaction, calcium carbonate (CaCO3) was heated to form two new
substances: calcium oxide (Cao) and carbon dioxide (CO2).
CaCO3 + CaO + CO2
A student heated 24.8 g of CaCO3. After the reaction, they measured 13.9 g of Cao.
What was the mass of the CO2 gas that escaped during the reaction?
38.79
O 1.78 g
0 24.8 g
10.99
Answer: 10.99
Explanation: because you take the Cao 13.9 and take CO2 which is 10.99 and it makes 24.8 . Which is CaCO3.
Decomposition reactions are the breakdown of chemical species into simpler parts. Decomposition reactions typically require energy input.
The mass of the CO2 gas that escaped = 10.99 g.
What is a decomposition reaction ?Decomposition reactions are the breakdown of chemical species into simpler parts. Decomposition reactions typically require energy input.When one reactant breaks down into two or more products, this is referred to as a decomposition reaction. This is represented by the following general equation: AB A + B. The breakdown of hydrogen peroxide to water and oxygen is an example of a decomposition reaction, as is the breakdown of water to hydrogen and oxygen.When one reactant breaks down into two or more products, this is referred to as a decomposition reaction. It is denoted by the general equation: AB A + B. In this equation, AB represents the reactant that initiates the reaction, and A and B are the reaction products.Molecular mass of CaO = 56.07 g
CO\(_2\) = 44.01 g
the mass of the CO2 gas that escaped = 13.9 x 44.01/ 56.07
= 10.99 g.
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increase food supplies in an ecosystem decrease competition because the competing organsims would
can you put water based polyurethane over oil based stain
Answer:
Yes, you can apply water-based polyurethane over oil-based stain.
Explanation:
is OK to use a water-based polyurethane over an oil-based finish in good condition. You should remove grease, dirt and wax by scrubbing the surface with a wood prep/cleaner/de-glosser, or mineral spirits and synthetic steel wool. ... Apply the new water-based finish per label directions
water is to ____as liquid is to soild
water is to gas as liquid is to solid
How much heat is required to change the temperature of 93 grams of water from 28 c to 68c
I'm sure when you meant heat you meant energy
we can use the formula
energy = specific heat capacity × mass × difference in temperature
the specific heat capacity of water is 4200J
specific heat capacity by the way is the amount of energy needed to raise the temperature of a substance by one degree
so plugging in our values
energy = 4200 × 0.093 × 40 = 16129 joules
why you may ask is the mass 0.093 and not 93
Well because we must convert grams into kilograms by dividing by 1000 since 1000 grams is one kilogram
HOPE THIS HELPSS
11. A 150 gram sample of radon-222 goes through alpha decay. The half-life of
radon-222 is 3.82 days. How much radon will be left after 3.82 days?
Answer:
The correct answer is - 75 grams.
Explanation:
Half-life is the amount of time that is used by the given amount of substance or element to make it half of the initial amount of a particular radioactive substance.
Equation for alpha decay for radon
\(^222_{86}Rn\Rightarrow^{218}_{84}Po \)
we need to calculate the left amount of radon after given time
using formula half life
\(N(t)=N_{0}e^{-\lambda t}\)
\(\lambda =\dfrac{0.693}{3.82}\)
\(\lambda=0.1814\)
\(N(3.82)=150\times e^{-0.1814\times3.82}\)
\(N(3.82)=75.0\ g\)
Thus, the left amount of radon is - 75 grams.
which of the following groups, when attached to a benzene ring, are both electron donating by resonance and electron withdrawing by induction? (select all that apply.) multiple select question. -no2 -ch2och3 -nh2 -oh -f
The options given, let's analyze each group to determine if they are both electron donating by resonance and electron withdrawing by induction when attached to a benzene ring, This group is electron-withdrawing by both resonance and induction, so it doesn't meet the criteria.
This group is electron-donating by resonance (due to the presence of lone pair electrons on the oxygen atom) and electron-withdrawing by induction due to the electronegativity of the oxygen atom. Therefore, it meets the criteria.
This group is electron-donating by both resonance lone pair electrons on the nitrogen atom) and induction (due to the partial positive charge on the nitrogen atom). Thus, it doesn't meet the criteria. This group is electron-donating by resonance lone pair electrons on the oxygen atom and electron-withdrawing by induction (due to the electronegativity of the oxygen atom. Therefore, it meets the criteria. This group is electron-withdrawing by both resonance and induction due to the high electronegativity of the fluorine atom, so it doesn't meet the criteria.
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Is aluminum a cation or anion
Answer:
Aluminum, a member of the IIIA family, loses three electrons to form a 3+ cation. ... And all of them form an anion with a single negative charge. The VIA elements gain two electrons to form anions with a 2- charge. The VA elements gain three electrons to form anions with a 3- charge.
What is to dissolve?
Answer:
(with reference to a solid) become or cause to become incorporated into a liquid so as to form a solution.
A 184.6-mg sample of KCrO, is dissolved in enough water to make 500.0 mL of solution.
The molarity of the K2CrO4 solution would be 0.001254 M.
Molarity CalculationThe molarity of a solution is defined as the number of moles of solute per liter of solution. To calculate the molarity of the K2CrO4 solution, we need to first determine the number of moles of K2CrO4 present in the 184.6 mg sample.
Calculate the number of moles of K2CrO4:
The molar mass of K2CrO4 is 294.19 g/mol.
mass of K2CrO4 = 184.6 mg = 0.1846 g
number of moles = mass/molar mass
number of moles = 0.1846 g / 294.19 g/mol = 0.000627 mol
Calculate the volume of the solution in liters:
We are given that the solution is made up to a final volume of 500.0 mL. To convert milliliters to liters, we divide by 1000.
volume = 500.0 mL ÷ 1000 mL/L = 0.500 L
Calculate the molarity:
Molarity = number of moles / volume of solution
Molarity = 0.000627 mol / 0.500 L = 0.001254 M
Therefore, the molarity of the K2CrO4 solution is 0.001254 M.
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Calculate the molarity. A 184.6-mg sample of K2CrO4, is dissolved in enough water to make 500.0 mL of solution.
When NH4SCN is added to a solution of Fe3+ ions, the solution changes from yellow to orange. What is the best explanation for this color change?
Answer:
The iron present in the solution is reduced because of the presence of SCN⁻ ions in solution
Explanation:
The clue in this problem is the color of the solution:
A solution of Fe³⁻ is yellow but when the Fe³⁺ is reduced by an oxidant to Fe²⁺ the solution change to orange color.
The SCN⁻ ion is a reducing agent than, in presence of a substance that can be reducted as Fe³⁺ ion will promote the reaction. That means the best explanation is:
The iron present in the solution is reduced because of the presence of SCN⁻ ions in solutionCalculate the percent composition of carbon in C6H12O6 :A. 50%B. 40%C. 35,3%D. 22,1%
The percent composition of the carbon in the C₆H₁₂O₆ is 40 %.
The chemical compound is C₆H₁₂O₆.
The molar mass of the compound C₆H₁₂O₆ = 180 g/mol
The mass of the carbon = 12 g
The percent composition is as follows :
Percent composition of the carbon = ( mass of the carbon / total mass of the compound ) × 100 %
Percent composition of the carbon = ( 72 / 180 ) × 100 %
Percent composition of the carbon = 40 %
Thus the percentage composition if the carbon is 40 percent in the chemical compound C₆H₁₂O₆ that is glucose.
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