The work function for platinum is 6.35 eV . Ultraviolet light of wavelength 150 nm is incident on the clean surface of a platinum sample. We wish to predict the stopping voltage we will need for electrons ejected from the surface. (b) How do you know that these photons will eject electrons from platinum?

Answer:

Current- the flow of free charges, such as electrons and ions

Drift velocity- the average speed at which these charges move

Answer:

An electric current is the stream of changed particals, such as electrons & ions, moving through an electrical conductor.

The average velocity attained bycharged partical ,such as electrons,in a material due to electric fields

The energy of a photon with a wavelength of 21 nm is approximately 9.429 x \(10^-^1^6\) Joules.

The energy of a photon can be calculated using Planck's equation:

E = (hc) / λ

Where:

Given that the wavelength (λ) is 21 nm (21 x \(10^-^9\) m) and using the given value of the Planck constant, we can calculate the energy of the photon:

E = (7 x \(10^-^3^4\) x 3.00 x 10^8) / (21 x\(10^-^9\) )

When we calculate this, we get the value: 9.429 x \(10^-^1^6\) Joules.

Therefore, the energy of a photon with a wavelength of 21 nm is approximately 9.429 x \(10^-^1^6\) Joules.

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Answer:

a. 4.29 m b. 2.25 m/s

Explanation:

Here is the complete question

A box slides across a frictionless floor with an initial speed v = 2.9 m/s. It encounters a rough region where the coefficient of friction is µk = 0.1. a) What is the shortest length of rough floor which will stop the box? b) If instead the strip is only 1.71 m long, with what speed does the box leave the strip?

Solution

a) What is the shortest length of rough floor which will stop the box?

Using work-kinetic energy theorem,

ΔK = W where ΔK = kinetic energy change of box and W = work done by friction = -fd where f = frictional force and d = length of rough floor

So, ΔK = -fd  where f = μmg, μ = coefficient of friction = , m = mass of box and g = acceleration due to gravity = 9.8 m/s²

1/2m(v₂² - v₁²) = μmgd

v₁ = 2.9 m/s and v₂ = 0 m/s (since the box stops)

So,

1/2m(v₂² - v₁²) = -μmgd

(v₂² - v₁²)/2 = -μgd

d = -(v₂² - v₁²)/2μg

substituting the values of the variables into the equation, we have

d = -((0 m/s)² - (2.9 m/s)²)/(2 × 0.1 × 9.8 m/s²)

d = -(0 m²/s² - 8.41 m²/s²)/1.96 m/s²

d = -(- 8.41 m²/s²)/1.96 m/s²

d = 8.41 m²/s²/1.96 m/s²

d = 4.29 m

b) If instead the strip is only 1.71 m long, with what speed does the box leave the strip?

Using work-kinetic energy theorem,

ΔK = W where ΔK = kinetic energy change of box and W = work done by friction = -fd where f = frictional force and d' = length of strip = 1.71 m

So, ΔK = -fd  where f = μmg, μ = coefficient of friction = , m = mass of box and g = acceleration due to gravity = 9.8 m/s²

1/2m(v₂² - v₁²) = μmgd'

v₁ = 2.9 m/s and v₂ = unknown

So,

1/2m(v₂² - v₁²) = -μmgd'

(v₂² - v₁²)/2 = -μgd'

v₂² - v₁² = -2μgd'

v₂² = v₁² - 2μgd'

v₂ = √(v₁² - 2μgd')

substituting the values of the variables into the equation, we have

v₂ = √((2.9 m/s)²) - (2 × 0.1 × 9.8 m/s² × 1.71 m)

v₂ = √(8.41 m²/s² - 3.3516 m²/s²)

v₂ = √(5.0584 m²/s²)

v₂ = 2.25 m/s

Answer:

Higher force would be required to stop 5 kg of ball

Explanation:

The force required to stop a moving object depends on its momentum.

The momentum for 8 kg of rolling ball is = 8 kg * 0.2 m/s = 1.6 kgm/s

The momentum for 5 kg of rolling ball is = 8 kg * 1.0 m/s = 5 kgm/s

Hence, momentum of 5 Kg ball is higher than the momentum of 8 Kg of ball

Hence, higher force would be required to stop 5 kg of ball

Answer:

Magnetic forces are non contact forces; they pull or push on objects without touching them. Magnets are only attracted to a few 'magnetic' metals and not all matter. Magnets are attracted to and repel other magnets.

Explanation:

The magnitude of the uniform electric field required to stop the protons in a distance of 2 m is 1.10 x 10^32 N/C.

To solve this problem, we need to use the equation for the work done by an electric field on a charged particle:

W = qEd

First, we need to calculate the velocity of the protons:

\(K = 1/2 mv^2 \\v = sqrt(2K/m)\)

Plugging in the values, we get:

\(v = sqrt(2 * 3.25 * 10^{-15} J / 1.673 * 10^{-27} kg)\\v = 5.94 * 10^6 m/s\)

Time it takes for the proton to stop:

\(t = d/v \\t = 2 m / 5.94 * 10^6 m/s \\t = 3.37 * 10^-7 s\)

Finally, we can use the time and the acceleration due to the electric field to calculate the electric field strength:

\(a = v/t \\a = 5.94 * 10^6 m/s / 3.37 * 10^{-7} s\\a = 1.76 * 10^13 m/s^2\)

\(E = a/q \\E = 1.76 * 10^{13} m/s^2 / 1.602 * 10^{-19} C\\E = 1.10 * 10^{32} N/C\)

Therefore, the magnitude of the uniform electric field required to stop the protons in a distance of 2 m is 1.10 x 10^32 N/C.

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Answer:

the one made from aluminum

Explanation:

The labelled table data hat the experimenter can record observations for the sand and water temperatures at various points is given below.

Here is a labeled data table for recording sand and water temperatures at various points:

Point            Sand Temperature (°C)                 Water Temperature (°C)

1  

2  

3  

4  

5  

The table is 5 columns wide and 3 rows long, with the first column labeled "Point" to indicate the location being observed, and the second and third columns labeled "Sand Temperature (°C)" and "Water Temperature (°C)" respectively to indicate the type of temperature being measured.

The cells under the "Sand Temperature (°C)" and "Water Temperature (°C)" columns are left blank to allow the experimenter to record the corresponding temperature readings for each point.

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Full Question:

Although part of your question is missing, you might be referring to this full question:

Label a data table so that the experimenter can record observations for the sand and water temperatures at various points.

the column table 5 length x 3 width

Answer:

Accept electron flow

Explanation:

The battery gives a change in the potential and the light bulb works like a resistor, so we will need a material that allows the flow of current. Therefore, we need a material that has the ability to accept electron flow.

So, the answer is:

Accept electron flow

340.14 \(\frac{meters}{second}\)= \(\frac{m}{s}\)          ☆                ☆                ⭐︎           ★             ★           ★            ★                ★

                            ☆               ★                     ★                    ☆              ★             ★        ☆          ⭐︎                        ★               ☀︎                   ✏☆                        ☽          ☂︎           ☔︎                

Meters per second is the unit that we get after dividing meters per seconds.

That's the unit we get after dividing distance by time.

I Hope it Helps!

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Answer:

C. 29.21 m³

Explanation:

Given the following data;

To find the final volume, we would use Boyle's law;

Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.

Mathematically, Boyles law is given by;

PV = K

\( P_{1}V_{1} = P_{2}V_{2} \)

Making V2 the subject of formula, we have;

\( V_{2} = \frac {P_{1}V_{1}}{P_{2}} \)

Substituting the values into the formula, we have;

\( V_{2} = \frac {18.9 * 3.4}{2.2} \)

\( V_{2} = \frac {64.26}{2.2} \)

Final volume, V2 = 29.21 m³

The Astronauts on the moon communicate by radio even when close to one another due to the lack of atmosphere and the limitations of sound transmission in the lunar environment.

The Earth, sound travels through the air, which is a medium that allows sound waves to propagate. In contrast, the moon has no atmosphere, meaning there is no air to facilitate sound transmission. As a result, sound waves cannot travel effectively between astronauts, even if they are standing nearby. To overcome this challenge, astronauts use radio communication systems, which transmit information through electromagnetic waves. These waves can travel efficiently in a vacuum, making them suitable for use in the lunar environment. By using radios, astronauts can communicate with each other clearly and effectively, ensuring their safety and ability to complete tasks during their missions.

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EAC( Low-energy lightbulb )=18.47 EAC( Conventional lightbulb )=7.33 Conventional lightbulb is cheaper to operate. Option D

To calculate the Equivalent Annual Costs (EAC), we need to consider the initial cost, maintenance costs, and the present value of future costs, taking into account the discount rate.

The EAC (Equivalent Annual Cost) is calculated by summing up the annual costs of the lightbulb over its lifetime, discounted at the real discount rate of 4%.

For the low-energy lightbulb:

EAC = Cost of bulb + Present value of annual electricity cost

= $3.60 + ($2.00 / (1 + 0.04)^1) + ($2.00 / (1 + 0.04)^2) + ... + ($2.00 / (1 + 0.04)^9)

≈ $18.47

For the conventional lightbulb:

EAC = Cost of bulb + Present value of annual electricity cost

= $0.60 + ($7.00 / (1 + 0.04)^1) + ($7.00 / (1 + 0.04)^2) + ... + ($7.00 / (1 + 0.04)^1)

≈ $7.33

Since the EAC for the low-energy lightbulb is $18.47 per year and the EAC for the conventional lightbulb is $7.33 per year, the conventional lightbulb is cheaper to operate assuming a burnt-out bulb is replaced by an identical bulb.

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Answer: the water level would rise since the pebble displaces minimal water compared to the boat.

Explanation:..........

Answer:

By using moving shaft and coiled wire together, electric generators create electricity. Electric generators essentially convert kinetic energy (the energy of motion) into electric energy.

Explanation:

hope this helped

Hugh Ben Hour and minute hands of the parliament tower clock in London measure 2. 70 m and 4. 50 m in length and weigh 60 kg and 100 kg, respectively.

A similar right-hand rule relates the rotational direction to the torque direction. Your fingers will curl in the rotational direction if you point your thumb in the direction of the torque. Positive torques create counterclockwise rotation whereas negative torques induce clockwise rotation.

The vector quantity of torque has both direction and magnitude. The screw will go inward and then outward if the screwdriver handle is rotated clockwise and then counterclockwise. Conventionally, clockwise and positive torques are counterclockwise.

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A. Electrical energy  B. Elastic energy  are the forms of potential energy.

Potential energy is the energy possess by an object because due to its position relative to other objects, stresses within itself, its electric charge, or other factors.

Types of Potential energy:

Therefore,

Electrical energy , Elastic energy are the forms of potential energy.

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Answer:

Potential energy

Explanation:

Answer:

12.5

Explanation:

The dark-adapted eye can detect 120 photons of light with a wavelength of 500 nm per second.

If the dark-adapted eye can supposedly detect one photon of light of wavelength 500 nm, and 120 such photons enter the eye each second, we can make a few calculations based on this information.

First, let's determine the energy of a single photon using the formula:

\(E = hc/λ\)

Where:

E is the energy of a photon,

h is Planck's constant (approximately \(6.626 x 10^-34\) J·s),

c is the speed of light (approximately\(3.0 x 10^8 m/s\)), and

λ is the wavelength of light.

Substituting the given values:

E = (\(6.626 x 10^-34\) J·s)(\(3.0 x 10^8 m/s\))/(\(500 x 10^-9 m)\)

\(E ≈ 3.9768 x 10^-19 J\)

Now, let's calculate the total energy entering the eye per second:

Total energy = Energy per photon × Number of photons per second

Total energy = (\(3.9768 x 10^-19\) J/photon) × 120 photons/s

Total energy ≈ \(4.7722 x 10^-17 J/s\)

Therefore, approximately \(4.7722 x 10^-17\) Joules of energy enter the eye each second when 120 photons of wavelength 500 nm enter the dark-adapted eye.

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The magnitude of the output gear angular velocity is 50 rad/sec. The actual value of the angular velocity will depend on the specific values of the gear ratio and the input gear's angular velocity.

The magnitude of the output gear angular velocity is determined by the gear ratio between the input and output gears. The gear ratio is the ratio of the number of teeth on the output gear to the number of teeth on the input gear.
To find the magnitude of the output gear angular velocity in units of rad/sec, you can use the formula:
Output gear angular velocity = Input gear angular velocity * (Number of teeth on input gear / Number of teeth on output gear)
Let's say the input gear has 20 teeth and the output gear has 40 teeth. If the input gear is rotating at 100 rad/sec, we

can calculate the output gear angular velocity as follows:
Output gear angular velocity = 100 rad/sec * (20 / 40) = 50 rad/sec
In this case, the magnitude of the output gear angular velocity is 50 rad/sec.
Remember to check the units and the gear ratio to ensure the correctness of your calculation. Also, note that the actual value of the angular velocity will depend on the specific values of the gear ratio and the input gear's angular velocity.

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Answer:

White holes do not exist in space

Explanation:

Any outgoing matter would collide with the matter in orbit, and the system would collapse into a black hole

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A regular polygon's interior angles add up to 3060° of a 19 sided polygons.

Polygons are defined as a flat shape surrounded by sides, or line segments.

It can be defined as a plane figure whose description is given by a closed polygonal chain made up of a finite number of straight line segments.

It can also be defined as any closed curve made up of a number of connected line segments that do not cross one another.

Sum of interior angle = (p - 2) x 180°

Where p = 19

Sum of interior angle = (19 - 2) x 180°

                                   = 17 x 180°

                                   = 3060°

Thus, a regular polygon's interior angles add up to 3060° of a 19 sided polygons.  

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The acceleration of a rocket increases as it travels upward from the ground mainly because of two primary factors: the decrease in mass due to fuel consumption and the reduction in air resistance as it gains altitude.

As a rocket burns its fuel, its mass decreases. According to Newton's second law of motion, acceleration is directly proportional to the net force acting on an object and inversely proportional to its mass. Therefore, as the rocket's mass decreases, its acceleration increases, given that the net force remains constant.

Additionally, as the rocket ascends, the air density decreases, leading to a reduction in air resistance. With less air resistance acting against the rocket's motion, the net force acting on it increases, which in turn boosts its acceleration.

In summary, the increasing acceleration of a rocket as it travels upward is primarily due to the decrease in mass resulting from fuel consumption and the reduction in air resistance encountered at higher altitudes.

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The acceleration of a rocket increases as it travels upward from the ground mainly because of the decreasing gravitational force (F_grav) and the absence of air resistance.

The force acting on a rocket can be broken down into two main components: the gravitational force (F_grav) and the thrust force (F_thrust) generated by the rocket engines.

Initially, when the rocket is on the ground, the gravitational force is the dominant force, and the rocket experiences a net force of F_net = F_thrust - F_grav, resulting in an upward acceleration.

As the rocket ascends, the distance between the rocket and the center of the Earth increases, causing a decrease in the gravitational force. The gravitational force is inversely proportional to the square of the distance between the rocket and the center of the Earth (F_grav ∝ 1/r²), where r represents the distance.

Therefore, as the rocket moves upward, the gravitational force decreases, and the net force increases, leading to an increased acceleration.

Additionally, as the rocket leaves the Earth's atmosphere, the effect of air resistance diminishes. Air resistance opposes the motion of the rocket, causing a drag force that reduces the net force. With decreasing air resistance, the net force and, subsequently, the acceleration of the rocket increase further.

Therefore, the increasing acceleration of a rocket as it travels upward is primarily due to the decreasing gravitational force and the diminishing effect of air resistance.

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Answer:

20 m

Explanation:

The ball travels 4 m up, then 16 m down.  It travels a total distance of 20 m.

If you plot the absorbance measurements of solutions vs. their concentrations, the slope is equal to molar absorptivity, if the path length is 1 cm

A = ε c l

A = Absorbance

ε = Molar absorption coefficient

c = Molar concentration

l = Optical path length

A ∝ ε c

Since A is only proportional to absorptivity and and not wavelength, out of the given options only option 2 is correct.

Therefore, if you plot the absorbance measurements of solutions vs. their concentrations, the slope is equal to molar absorptivity, if the path length is 1 cm

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The belt of constellations through which all the planets move is called the Zodiac. The zodiac belt runs along the plane of the ecliptic.

The Zodiac is the belt of constellations that all the planets pass through. The sun and moon are also always within this belt. The ecliptic occurs when they appear to move ordinarily along on the particular path through the sky. On the path of the ecliptic, those are 13 astronomical constellations:

In the fifth century B.C., astronomers identified the 12 astronomical constellations as zodiac signs without Ophiuchus. Ophiuchus did not fit into the ancient calendar of 12 lunar months. As a result, the astronomers omitted Ophiuchus for practical reasons.

Astronomy studies the constellations of the zodiac. So, the constellations of the zodiac are not astrology, which is concerned with personal characteristics (zodiac signs differ with zodiac constellations). In the past, they assisted in the creation of calendars and served to track the time period and the seasons for ancient people. They are still applied today for scientific observations and maritime navigation. For example, they serve as excellent reference points for amateur astronomers when trying to find planets.

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The correct ordered pair about the equivalent capacitance for each arrangement is; D > A and B > C. Option D is correct.

Let's analyze each arrangement and determine the correct ordered pair for the equivalent capacitance;

Arrangement X;

In this arrangement, the capacitors A and B are connected in parallel, resulting in an equivalent capacitance greater than the capacitance of C. Capacitor D is not connected in parallel with any other capacitor. Therefore, the correct statement for this arrangement is; A > C and B > D

Arrangement #;

In this arrangement, capacitor A is connected in parallel with capacitor B, resulting in an equivalent capacitance greater than the capacitance of D. Capacitor C is not connected in parallel with any other capacitor. Therefore, the correct statement for this arrangement is; A > D and B > C

Arrangement A;

In this arrangement, capacitors B and D are connected in series, resulting in an equivalent capacitance greater than the capacitance of C. Capacitor A is not connected in series or parallel with any other capacitor. Therefore, the correct statement for this arrangement is; A > C and B > D

Arrangement B;

In this arrangement, capacitor D is connected in parallel with capacitor C, resulting in an equivalent capacitance greater than the capacitance of A. Capacitor B is not connected in parallel with any other capacitor. Therefore, the correct statement for this arrangement is; D > A and C > B

Therefore, the correct ordered pair about the equivalent capacitance for each arrangement is; D > A and B > C.

Hence, D. is the correct option.

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--The given question is incomplete, the complete question is

"Four arrangement of capacitors are shown below Each has an equivalent capacitance. Which ordered pair is correct about the equivalent capacitance for these arrangements Assume that all capacitors are identical. ff X # A B D a) C > D and A > B  b) A > C and B > D c) A > Band D > C d)  D > Aand B > C."--