Denote by t the time we ned to paint a fence, by l the length of the fence and by n the number of painters. Then, we have the next equation
\(t=k\frac{l}{n}\)It takes 5 hours and 30 minutes, that is
\(5(60)+30=330\text{ minutes}\)to paint a l=150 feet fence with n=3 painters, then
\(\begin{gathered} 330=k\frac{150}{3} \\ k=\frac{3\times330}{150} \\ k=\frac{33}{5} \end{gathered}\)
So, if we have a l=510 feet fence and n=7 painters, then we will need
\(\begin{gathered} t=\frac{33}{5}\cdot\frac{510}{7} \\ t=480.85\text{ minutes} \end{gathered}\)That is, approximately 8 hours.
Roberto made a line plot to show the weight in pounds of the bags of granola in his store he concluded that the total weight of the granola was 2/1/2+2/3/4+3=8/1/4 pounds
The correct total weight of the bags of granola is 8 1/4 pounds.
One thing that can be done to improve Roberto's reasoning is to ensure the accuracy of the calculations.
In his conclusion, Roberto added the weights of the bags of granola (2 1/2, 2 3/4, and 3) and claimed that the total weight was 8 1/4 pounds. However, the sum of these weights does not equal 8 1/4 pounds.
To address this, Roberto should recheck his calculations. Adding mixed numbers involves adding the whole numbers separately and then adding the fractions separately. In this case, 2 1/2 + 2 3/4 + 3 can be calculated as follows:
2 + 2 + 3 = 7 (sum of whole numbers)
1/2 + 3/4 = 2/4 + 3/4 = 5/4 = 1 1/4 (sum of fractions)
Thus, the correct sum is 7 + 1 1/4 = 8 1/4 pounds.
By double-checking the calculations and providing the accurate sum, Roberto's reasoning would be more precise, reliable, and free from errors.
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The probable question may be:
Roberto made a line plot to show the weight in pounds of the bags of granola in his store he concluded that the total weight of the granola was 2 1/2+2 3/4+3=8 1/4 pounds.
what is one thing that you could do to Roberto's Reasoning
In a survey of college students, 840 said that they had cheated on an exam and 1,765 said that they had not. If one college student is selected at random, find the probability that the student has cheated on an exam.
The probability that the student has cheated on an exam is 33%.
What is probability?Probability is defined as the ratio of the number of favorable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.
Probability = Number of favorable outcomes / Number of sample
Given that in a survey of college students, 840 said that they had cheated on an exam and 1,765 said that they had not.
The probability will be calculated as,
Probability = Number of favorable outcomes / Number of sample
Probability = 840 / 2605
Probability = 0.33 or 33%
Therefore, the probability that the student has cheated on an exam is 33%.
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Which statement is true about the y-intercept of a quadratic function
Answer:
A quadratic function can only have one y-intercept. The y-intercept is also called a zero of the function. The y-intercept is located at the point where the value of y is 0.
Step-by-step explanation:
Nick plays 8 games of chess.
He wins 6 games.
What fraction of the games did he win?
Give your answer in its simplest form.
Answer:
3/4
Step-by-step explanation:
6/8 in its simplest form would be 3/4 because
\(6 \div 2 = 3\)
and
\(8 \div 2 = 4\)
so 3/4
Ashley had $14.80. She spent $2.60 on lunch, then
brother gave her the $6 he owed her. What does she
now?
$11.40
$6.20
$18.20
$23.40
Answer: $18.20
Step-by-step explanation:
14.80-2.60 is 12.20.
her brother gives her 6 dollars
12.20+6 is 18.20, which that is the answer.
Answer:
18.20
Step-by-step explanation:
I got this because she got 6 making her total 20.80 then I subtracted what she spent for lunch
Find the vector projection w of u = i – 6j onto v = 2i + 7j.
Given:
\(u=i-6j\text{ }onto\text{ }v=2i+7j.\)To find:
The vector projection u onto v.
Explanation:
The vector projection u onto v formula is,
\(\frac{\vec{u}\cdot\vec{v}}{|\vec{v}|^2}\cdot\vec{v}\)Substituting the given values we get,
\(\begin{gathered} \frac{(i-6j)\cdot(2i+7j)}{|2i+7j|}(2i+7j)=\frac{(2-42)}{(\sqrt{2^2+7^2})^2}(2\imaginaryI+7j) \\ =\frac{(2-42)}{(\sqrt{4+49})^2}(2\mathrm{i}+7j) \\ =\frac{-40}{(\sqrt{53})^2}(2\mathrm{i}+7j) \\ =\frac{-40}{53}(2\mathrm{i}+7j) \end{gathered}\)Final answer:
The vector projection u onto v is,
\(\frac{-40}{53}(2\imaginaryI+7j)\)A triangle is 11 in tall and 22 in wide. If it is enlarged to a height of 198 in, then how wide will it be?
Answer: 12 inches
Step-by-step explanation:
If the dilation is uniform, both height and width will be multiplied by 4.
So the new height = (1 in) × 4 = 4 in
and the new width = (3 in) × 4 = 12 in
Hope it helps!
Which of the following is the inverse of f(x) = 3-x/5
Answer:
The correct answer is, F-1(x) = 5(x-3)/3
Step-by-step explanation:
The inverse of given function f(x) = 3-x/5 would be equal to 3(x - 5)/5
What is the inverse of a function?Suppose that the given function is \(f:X\rightarrow Y\)Then if function 'f' is one-to-one and onto function (a needed condition for inverses to exist), then, the inverse of the considered function is ;
\(f^{-1}: Y \rightarrow X\)
We have been given a function of x as ; 3-x/5.
To find the inverse we will just switch x and function of x with each other.
That means we have;
x = 5/3 f(x) + 5
5/3 f(x) = x - 5
f(x) = 3(x - 5)/5
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Total length of a pole is 21.3 m. If 0.2m of the length of the pole is inside the ground. Find how much of its length is outside the ground
Answer:
21.1 mStep by step explanation
Total length of pole = 21.3 m
Length of pole inside the ground = 0.2 m
Let length of pole outside the ground be X,
So, according to the Question,
\(x + 0.2 = 21.3\)
Move constant to R.H.S and change its sign
\(x = 21.3 - 0.2\)
Calculate the difference
\(x = 21.1 \: m\)
Hope this helps...
Good luck on your assignment...
a 8. The plans of a house are drawn to a scale of 1:50. (a) Find the actual length, in metres, represented by 14 cm on the plan. (b) What length, in centimetres, on the plan represents an actual length of 11 metres? [N/85/P1]
Answer:
a) 7 m
b) 22 cm
Step-by-step explanation:
Given plans at a scale of 1 : 50, you want (a) the actual length corresponding to a plan length of 14 cm, and (b) the plan length corresponding to an actual length of 11 m.
ProportionThe actual lengths are wanted in meters, so we can rewrite the scale to translate between plan cm and actual m.
plan : actual = 1 cm : 50 cm
= 1 cm : 0.5 m
= 2 cm : 1 m
a) 14 cmMultiplying the scale by 7, we have ...
2 cm : 1 m = 14 cm : 7 m
The actual length is 7 meters.
b) 11 mMultiplying the scale by 11, we have ...
2 cm : 1 m = 22 cm : 11 m
The plan length is 22 cm.
13. Solve to find the vertex if :
3x2 – 19x - 5
Answer:
A) y = 3(x -3)^2 -46
B) (3, -46)
C) look at the y-coordinate of the vertex
Step-by-step explanation:
A) Factor the leading coefficient from the variable terms.
y = 3(x^2 -6x) -19
Inside parentheses, add the square of half the x-coefficient. Outside, subtract the same value.
y = 3(x^2 -6x +9) -19 -3(9)
y = 3(x -3)^2 -46
__
B) Compared to the vertex form, ...
y = a(x -h)^2 +k
we find a=3, (h, k) = (3, -46).
The vertex is (3, -46).
__
C) The vertex is an extreme value (as is any vertex). The sign of the leading coefficient tells you whether the parabola opens upward (+) or downward (-). This parabola opens upward, so the vertex is a minimum.
If the leading coefficient is positive, the y-coordinate of the vertex is a minimum. If the leading coefficient is negative, the y-coordinate of the vertex is a maximum.
Step-by-step explanation:
Aaliyah has a loyalty card good for a discount at her local hardware store. The item she wants to buy is priced at $39, before discount and tax. After the discount, and before tax, the price is $33.54. Find the percent discount.
Answer:
16.13
Step-by-step explanation:
The length of a rectangular yard is 5 less than twice the width. The perimeter of the yard is 80 meters. Find
the dimensions of the yard
Lynne read 2.5 chapters of her book on Tuesday, 4.25 chapters on Wednesday, and 5 chapters on Thursday. How many chapters did she read in total during those three days? I think you have to add them
Answer:
11.75
Step-by-step explanation:
2.5 + 4.25 + 5
Answer:
11.75 chapters in total
Step-by-step explanation:
Given:
2.5, 4.25, 5
The question ask for total
2.5 + 4.25 + 5 = 11.75
5. Resenhoeft, Villa, and Wiseman (2008) conducted a
study showing that a woman shown in a photograph
was judged as less attractive when the photograph
showed a visible tattoo compared to the same pho-
tograph with the tattoo removed. Suppose a similar
experiment is conducted as a repeated-measures
study. A sample of n = 12 males looks at a set of
30 photographs of women and rates the attractiveness
of each woman using a 5-point scale (5= most posi-
tive). One photograph appears twice in the set, once
with a tattoo and once with the tattoo removed. For
each participant, the researcher records the difference
between the two ratings of the same photograph. On
average, the photograph without the tattoo is rated
M, 1.2 points higher than the photograph with the
tattoo, with SS 33 for the difference scores. Does
the presence of a visible tattoo have a significant
effect on the attractiveness ratings? Use a two-tailed
test with a= 05.
To test the hypothesis is that the presence of a visible tattoo has a significant effect on the attractiveness ratings at 5% level of significance.
Consider Null and alternative hypothesis
Null hypothesis, H₀ : μd = 0
Alternative hypothesis, H₀ : μd ≠ 0
Calculate the sample standard deviation as follows:
s = √SS /(n-1)
= √33 / (12-1) =√3
= 1.73
Calculate the degree of freedom as follows:
df = n - 1
= 12 - 1
= 11
The critical value of t for 11 degree of freedom and 5% level of significance is 2.201.
The t critical value at 5% significance level is, Compare the calculated value with the critical value.
Here, the calculated value exceeds the critical value then reject the Null hypothesis.
Hence, conclude that there is sufficient evidence to indicate that the presence of a visible tattoo have a significant effect on the attractiveness ratings.
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express 33 1/2% as fraction
A container with an open top is to have 10 m3 capacity and be
made of thin sheet metal. Calculate the dimensions of the box if it
is to use the minimum possible amount of metal.
The dimensions of the box if it is to use the minimum possible amount of metal are,
⇒ 2.714 m, 2.714 m, 1.358 m
What is an expression?Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.
Given that;
A container with an open top is to have 10 m³ capacity.
Now,
Let the dimensions are x, y and z.
Since, Volume of box = 10 m³
Hence, We get;
⇒ xyz = 10
⇒ z = 10/xy
Since, A container is open in top.
Hence, The surface area = 2xz + 2yz + xy
Substitute z = 10/xy;
⇒ S.A = 2x (10/xy) + 2y (10/xy) + xy
= 20/y + 20/x + xy
For minimum metal;
⇒ d (S.A)/ dx = 0
⇒ - 20/x² + y = 0
⇒ y = 20/x² ..(i)
And, d (S.A) / dy = 0
⇒ - 20/y² + x = 0
⇒ x = 20/y² ..(ii)
Divide equation (i) and ((ii);
⇒ x = y
Hence, We get;
⇒ xyz = 10
⇒ x³ = 10
⇒ x = 2.714
And, y = 2.714
So, The value of z is,
⇒ z = 10/xy
⇒ z = 10 / 2.714×2.714
⇒ z = 1.358 m
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1x²- 16x = 20 is mg questions
The solutions to the equation 1x² - 16x = 20 are x = 8 + 2√21 and x = 8 - 2√21.
To solve the quadratic equation 1x² - 16x = 20, we need to rearrange it into the standard form ax² + bx + c = 0. Let's simplify the equation step by step:
1x² - 16x = 20
First, move all terms to one side of the equation:
1x² - 16x - 20 = 0
Now we have a quadratic equation in the standard form. To solve it, we can use factoring, completing the square, or the quadratic formula. In this case, factoring may not be straightforward, so let's use the quadratic formula:
x = (-b ± √(b² - 4ac)) / (2a)
For our equation, a = 1, b = -16, and c = -20. Substituting these values into the quadratic formula:
x = (-(-16) ± √((-16)² - 4(1)(-20))) / (2(1))
Simplifying further:
x = (16 ± √(256 + 80)) / 2
x = (16 ± √336) / 2
x = (16 ± √(16 * 21)) / 2
x = (16 ± 4√21) / 2
Simplifying:
x = 8 ± 2√21
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In 2017 the population of Rexburg, Idaho was 28,337 people. The population was expected to grow at a rate of about 1.55% per year. Based on these numbers, what would we predict the population of Rexburg will be in the year 2022?
(Round to the nearest whole number.)
Number
people
Answer: 30,620 people
Step-by-step explanation:
We will use the given formula for exponential growth.
➜ 1.55% / 100 = 0.0155
➜ 2022 - 2017 = 5 years
\(A=Pe^{rt}\)
\(A=(28,337\;people)e^{(0.0155)(5\;years)}\)
\(A=(28,337\;people)e^{0.0775}\)
\(A=(28,337\;people)e^{0.0775}\)
\(A=30,620.4587 \approx 30,620\;people\)
fill in the blank. a simple linear regression equation relates r and w as follows: the explanatory variable is___, and the dependent variable is___. the slope parameter is___, and the intercept parameter is___. when w is zero, r equals___. for each one unit increase in w, the change in r is___units.
w, r, the coefficient of w, the constant term in the equation, the intercept parameter, equal to the slope parameter in units are ans of fill in the blank respectively.
A simple linear regression equation is used to model the relationship between two variables, where one variable is the independent or explanatory variable and the other is the dependent or response variable. The equation has the form:
y = β0 + β1x,
where y is the dependent variable, x is the explanatory variable, β0 is the intercept parameter, and β1 is the slope parameter. The intercept parameter represents the value of y when x is zero, and the slope parameter represents the change in y for each one-unit change in x. In this problem, the explanatory variable is w, and the dependent variable is r. The slope and intercept parameters need to be estimated from the data to obtain the regression equation. The equation can be used to make predictions about the response variable given a certain value of the explanatory variable.
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Consider the following system of two linear equations:
4y + 3x = 0
4y - x = 16
What is the point of intersection?
Answer: The two lines intersect at (-4,3)
Step-by-step explanation:
So our first step would be to turn both of these into standard slope-intercept form.
1.)
4y + 3x = 0
4y = -3x
y = -3/4x
2.)
4y - x = 16
4y = x + 16
y = 1/4x + 4
Now that we have our 2 equations, y = -3/4x and y = 1/4x + 4 we can graph them to get an intersection at (-4,3)
The July bank statement sent by the bank to ABC company shows a balance of cash on deposit at July 31 of Br.4,964.47 Assume that on July 31, assume the on July 31, ABCs ledger shows a bank balance of Br. 4 173. 83. 1. A deposit of Br 410. 90 made after banking hours and doesnt appear in the bank statement2. A check drawn for Br. 79 had been erroneously charged by the bank Br.973. For checks issued in July have not yet been paid by the bank (outstanding checks). : Theses checks are;- Check No date amount 801 June 15 ---Br.100,00 888 July 24 ----Br. 10.25 890 July 27--- Br. 294.50 891 July 30 ---Br. 205.004. A check written for birr 210 had been incorrectly charged by the bank as birr 120 5. Proceeds from collection of a interest bearing note receivable from David. ABC Company had left this note with the banks collection department. The face amount of the note was birr 500 6. Br. 24.75 interest earned on average account balance during July7. A check for Br. 10 returned with the statement had been recorded in the check register as Br. 100. The check was for the payment of an obligation to Davis Equipment Company for the purchase of office supplies on account 8. Br. 5,00 fee charged by bank for handling collection of note receivable 9. Br. 50.25 check from customer John deposited by ABC company charged bank as Non sufficient fund (NSF) 10. Br. 12.70 service charged by bank for the month of July. 11. Check number 875 was issued July 20 in the amount of Br 85 but was erroneously recorded in the cash payment Journal as Br 58 for payment of telephone expense prepare bank reconcilation and journal entry
The bank reconciliation shows an adjusted bank balance of Br.5,301.42 and an adjusted ledger balance of Br.4,173.83.
To prepare the bank reconciliation and journal entry for ABC Company based on the given information, we need to compare the transactions recorded in ABC's ledger with the transactions shown in the bank statement. Here's the bank reconciliation:
1. Bank Statement Balance:
Cash on deposit at July 31: Br.4,964.47
2. Adjusted Bank Balance:
Bank Statement Balance: Br.4,964.47
3. Deposit not on the statement: + Br.410.90
(Adjusted Bank Balance: Br.5,375.37)
Erroneously charged check: + Br.79
(Adjusted Bank Balance: Br.5,454.37)
Outstanding checks:
Check 801: - Br.100.00
Check 888: - Br.10.25
Check 890: - Br.294.50
Check 891: - Br.205.00
(Adjusted Bank Balance: Br.4,844.62)
4. Incorrectly charged check: + Br.90
(Adjusted Bank Balance: Br.4,934.62)
5. Collection of interest-bearing note: + Br.500
(Adjusted Bank Balance: Br.5,434.62)
6. Interest earned: + Br.24.75
(Adjusted Bank Balance: Br.5,459.37)
7. Incorrectly recorded check: - Br.90
(Adjusted Bank Balance: Br.5,369.37)
8. Collection fee: - Br.5.00
(Adjusted Bank Balance: Br.5,364.37)
9. NSF check: - Br.50.25
(Adjusted Bank Balance: Br.5,314.12)
10. Service charge: - Br.12.70
(Adjusted Bank Balance: Br.5,301.42)
Adjusted Ledger Balance:
Bank Balance in ABC's Ledger: Br.4,173.83
Reconciled Bank Balance: Br.5,301.42
Reconciled Ledger Balance: Br.4,173.83
Journal Entry:
To record the bank reconciliation, we make the following journal entry:
Debit: Cash (Ledger Balance adjustment) - Br.5,301.42
Credit: Cash (Bank Statement Balance adjustment) - Br.4,964.47
Credit: Miscellaneous Income/Expense - Br.336.95 (the difference between the two balances)
This journal entry ensures that the ledger balance matches the reconciled bank balance by adjusting for the discrepancies identified during the reconciliation process.
The journal entry reflects the necessary adjustments to reconcile the two balances, with a debit to Cash (Ledger Balance adjustment), a credit to Cash (Bank Statement Balance adjustment), and a credit to Miscellaneous Income/Expense to account for the difference.
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Complete this sequence of numbers such that the difference between any two adjacent numbers is the same : 3/k, _, _, 9/2k.
The completed sequence is: 3/k, 3/k, 3/k, 9/2k.To complete the sequence of numbers with a constant difference between adjacent numbers, we can calculate the common difference by subtracting the first term from the second term.
Let's denote the missing terms as A and B.
The given sequence is: 3/k, A, B, 9/2k.
The common difference can be found by subtracting 3/k from A or B. Therefore:
A - 3/k = B - A = 9/2k - B.
To simplify, we can equate the two expressions for the common difference:
A - 3/k = 9/2k - B.
Next, we can solve for A and B using this equation.
Adding 3/k to both sides gives:
A = 3/k + 9/2k - B.
Now, we can substitute the value of A into the equation:
3/k + 9/2k - B - 3/k = 9/2k - B.
Simplifying further, we have:
9/2k - 3/k = 9/2k - B.
Cancelling out the common terms, we find:
-3/k = -B.
Multiplying both sides by -1, we get:
3/k = B.
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A blueprint used a scale of 1.5 cm = 2 m to
represent a grain silo. If the height of the silo in
the drawing was 33 cm, how tall is the actual grain
silo?
Answer: The Silo is 44 meters tall
Step-by-step explanation:
To find the height of the silo, first you have to divide the drawing height (33cm) by 1.5 to get the unit rate. Then multiply the 22 by 2 to get 44 meters (The height of the silo)
17
11
S
3
18
If the median is 17, which number could s be?
7
18
Answer:
s=18
Step-by-step explanation:
the median is 17(middle number)
It goes from smaller to bigger
2 numbers onthe left of 17 and 2 numbers on the right of 17
3 11 17 18 18
Answer:
it would be 18
Step-by-step explanation:
18 being the answer makes 17 the middle it has to be more than 17 and it is 18
how to solve this separable differential equation?
The solution to the differential equation \(2^{\sqrt{x}}\frac{dy}{dx} = cosce(ln(y))\) is,
\(\frac{y sin(ln(y))}{2} - \frac{y cos(ln(y))}{2} = C - \frac{2 ln(2) \sqrt{x} + 2}{ln^2(2)2^{\sqrt{x}}}\).
What is a differential equation?Any equation with at least one ordinary or partial derivative of an unknown function is referred to as a differential equation.
The given differential equation is \(2^{\sqrt{x}}\frac{dy}{dx} = cosce(ln(y))\).
Now, multiplying both sides by dx we,
\(2^{\sqrt{x}}dy = cosce(ln(y))dx\).
Dividing both sides by \(2^{\sqrt{x}}\) we have,
\(sin(ln(y))dy = \frac{dx}{2^{\sqrt{x}}}\).
\(\[ \int sin(ln(y))dy = \int \frac{dx}{2^{\sqrt{x}}}\).
\(\frac{y sin(ln(y))}{2} - \frac{y cos(ln(y))}{2} = C - \frac{2 ln(2) \sqrt{x} + 2}{ln^2(2)2^{\sqrt{x}}}\).
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Statistics negative numbers and subtraction in a modular arithmetic system
Solution
(a)
\(\begin{gathered} let\text{ the unknown be x} \\ -7=x(mod\text{ 6\rparen} \\ multiples\text{ of 6 are 6, 12, 18,...} \\ Thus,\text{ } \\ -7(mod\text{ 6\rparen}=-7+12(mod\text{ 6\rparen} \\ =5\text{ mod 6} \\ The\text{ answer = 5} \end{gathered}\)(b)
\(\begin{gathered} 24-25=x(mod\text{ 9\rparen} \\ =-1(mod9)_ \\ Multiples\text{ of 9 are 9, 18, 27, 36,etc} \\ Thus,\text{ } \\ -1(mod\text{ 9\rparen= -1 + 9 \lparen mod 9\rparen} \\ =9=8\text{ \lparen mod 9\rparen} \\ The\text{ answer is 8} \end{gathered}\)A dairy farmer wants to mix a 70% protein supplement and a standard 20% protein ratio to make 1900 pounds of a high grade 55% protein ration how many pounds of each should he use
The dairy farmer should use 1330 pounds of the 70% protein supplement and 570 pounds of the 20% protein ratio to make a 1900-pound high-grade 55% protein ration.
To determine the amounts of the 70% protein supplement and the 20% protein ratio needed to make a 1900-pound high-grade 55% protein ration, we can set up a system of equations.
Let's assume x represents the pounds of the 70% protein supplement and y represents the pounds of the 20% protein ratio.
The total weight equation is given by:
x + y = 1900
The protein content equation is given by:
(0.70x + 0.20y) / 1900 = 0.55
Simplifying the second equation, we get:
0.70x + 0.20y = 0.55 × 1900
0.70x + 0.20y = 1045
Now, we can solve this system of equations to find the values of x and y.
Rearrange the first equation to solve for x:
x = 1900 - y
Substitute this expression for x in the second equation:
0.70(1900 - y) + 0.20y = 1045
1330 - 0.70y + 0.20y = 1045
1330 - 0.50y = 1045
-0.50y = 1045 - 1330
-0.50y = -285
y = -285 / -0.50
y = 570
Now substitute this value of y back into the first equation to find x:
x + 570 = 1900
x = 1900 - 570
x = 1330
Therefore, the dairy farmer should use 1330 pounds of the 70% protein supplement and 570 pounds of the 20% protein ratio to make a 1900-pound high-grade 55% protein ratio.
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15% of the 50 donut holes in the box were chocolate. How many chocolate donut holes were in the box?
Answer:
7.5
Step-by-step explanation:
Answer:
7.5 chocolate holes
Step-by-step explanation:
6. Tell whether the sequence is arithmetic. If it is, what is the common difference?
-19, -11, -3, 5,...
Oyes; 5
Oyes; 6
Oyes; 8
O no
The sequence -19, -11, -3, 5,... is arithmetic with a common difference of 8.
An arithmetic sequence is a sequence of numbers in which each term is obtained by adding a constant value, called the common difference (d), to the preceding term. To determine if the given sequence is arithmetic, we can find the differences between consecutive terms.
The difference between the second and first terms is 11 - (-19) = 30, and the difference between the third and second terms is -3 - (-11) = 8. The difference between the fourth and third terms is 5 - (-3) = 8. Since the differences between consecutive terms are the same, the sequence is arithmetic.
The common difference can be found by subtracting any term from the term that follows it. For example, the common difference can be obtained by subtracting the second term (-11) from the third term (-3), or by subtracting the third term (-3) from the fourth term (5).
In both cases, we get a common difference of 8. Therefore, the common difference of the given sequence is 8.
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