The telescope that allowed astronomers to discover most of the planets found with the transit method was called?.

The frequency of the radiation emitted by the green laser pointer is approximately 5.635 x 10^14 s^(-1), which corresponds to option d. 5.635 x 10^14 s^(-1).

To find the frequency of radiation, we can use the equation:

c = λν

where c is the speed of light, λ is the wavelength, and ν is the frequency.

Given that the wavelength of the green laser pointer is 532.0 nm, we can convert it to meters by dividing by 10^9, which gives us 5.32 x 10^-7 m.

Substituting the values into the equation, we have:

3 x 10^8 m/s = (5.32 x 10^-7 m)ν

Simplifying the equation and solving for ν, we get:

ν = (3 x 10^8 m/s) / (5.32 x 10^-7 m)

ν ≈ 5.635 x 10^14 s^(-1)

Therefore, the frequency of the radiation emitted by the green laser pointer is approximately 5.635 x 10^14 s^(-1), which corresponds to option d. 5.635 x 10^14 s^(-1).

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The force that needs to be applied to the second piece of rock to produce an acceleration of 8a is 8F.

The relationship between the force, mass, and acceleration of an object is given in the formula below:

The force on an object is directly proportional to its mass and acceleration.

However, the acceleration of an object when a constant force is applied is inversely proportional to the mass of the object.

Given two rocks that weigh 5 N each.

Force applied on the first rock, F produces an acceleration = a

F = ma

mass = constant

hence, F = a

For the second rock to have an acceleration 8a, the force applied will be:

F / a = Fx / 8a

Fx = 8 F

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An electric circuit consists of a completer closed path (or paths) for electric current. A series circuit is a type of electric circuit in which there is a single current path.

Hence, the correct option is (2)

Answer:

The answer is "1.0748 and 1.0875".

Explanation:

Please find the complete question in the attachment file.

The incidence angle is \(i=45^{\circ}\) for all colors When the angle is r, then use \(\frac{\sin{i}}{\sin{r}}=\frac{n_{o}}{n}\) . Snell's rule Where \(n_{o}\) is an outside material reflectance (same hue index) or n seems to be the crown glass index of the refraction, That index of inclination is \(90^{\circ}\) as the light in color shifted behaver from complete inner diffraction to diffraction.

Whenever the external channel has a thermal conductivity for the red light, that's also

\(n_{o}=\frac{n_{r}\sin{45^{\circ}}}{\sin{90^{\circ}}}=\frac{1.520\times\sin{45^{\circ}}}{\sin{90^{\circ}}}=1.0748\)

When outside the material has a refractive index, this happens with violet light.

\(n_{o}=\frac{n_{r}\sin{45^{\circ}}}{\sin{90^{\circ}}}=\frac{1.538\times\sin{45^{\circ}}}{\sin{90^{\circ}}}=1.0875\)

In point a, The only red light flows out from the leaned face and the residual colors are mirrored mostly on prism for the primary benefits \(n_{o}=1.0748\) (and slightly larger than that).

In point b, The only violet light is shown in the prism with the majority of the colors coming out from the sloping face for a scale similar to \(n_{o}= 1.0875\) (and slightly smaller than this).

Answer:

The enthalpy change of the water during the process is 1.4 kJ/kg

Explanation:

The enthalpy change of the water during the process can be determined from

\(\Delta H = \frac{\Delta P}{\rho} + C_{p} \Delta T\)

Where

\(\Delta H\) is the enthalpy change

\(\Delta P\) is the change in pressure

\(\rho\) is the density

\(C_{p}\) is the specific heat

and \(\Delta T\) is the temperature change

From the question

\(\Delta P\) = 900 kPa - 100 k Pa

\(\Delta P\) = 800 kPa

\(\rho\) = 1 kg/L = 1kg/dm³ = 1000 kg/m³

\(C_{p}\) = 4.18 kJ/kg.°C

\(\Delta T\) = 0.15 °C

∴\(\Delta H = \frac{\Delta P}{\rho} + C_{p} \Delta T\)

\(\Delta H = \frac{800}{1000} +4.18 \times 0.15\)

\(\Delta H = 0.8 + 0.627\\\)

\(\Delta H = 1.4 kJ /kg\)

Hence, the enthalpy change of the water during the process is 1.4 kJ/kg

Answer:

The answer to this question is given below in this explanation section.

Explanation:

If you place a row of several steel balls on a track and let ball strike it and one end of the row,then the last ball at the other end will fly off,corresponding to the income impulse.All the other balls will remain at rest.This experiment is well known from the newton cradle toy,However you world be you surprise if the last ball in the row shot away like a bullet,even through the first ball.only seemed to have a very moderate velocity.This would not seem consistent with the law of the conservation of energy.

The effect is so surprising that one guesses it might be a trick and you would be right: one or more of the similar looking balls are in fact magnetic.

The first strike approaching from the left hand is from a non magnetic steel ball which will be strongly accelerated through the magnetic balls and thrust with a relatively high velocity on the row of resting balls.

If the wheel is rolling without sliding on a horizontal surface, the frictional force between the surface and the wheel is static friction.

The static frictional force opposes the tendency of the wheel to slide. In this case, the forward force acting on the axle provides the torque necessary to accelerate the wheel. As the wheel accelerates, the static frictional force adjusts to match the force needed to prevent sliding.

The magnitude of the static frictional force can be calculated using the equation:

Frictional force = μs * Normal force,

where μs is the coefficient of static friction and Normal force is the perpendicular force exerted by the surface on the wheel.

Since the wheel is not sliding, the static frictional force is equal to the force exerted on the wheel. Therefore, the frictional force of the surface on the wheel is equal to the forward force acting on the axle.

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which of the following is not a barrier to physical activity it is fear of injury I think.

F=ma

Newton's second law states that force is proportional to what is required for an object of constant mass to change its velocity. This is equal to that object's mass multiplied by its acceleration. We use Newtons, kilograms, and meters per second squared as our default units, although any appropriate units for mass (grams, ounces, etc.) or velocity (miles per hour per second, millimeters per second2, etc.) could certainly be used as well - the calculation is the same regardless.

The statements which are correct about calculating LaToya's mechanical advantage are—The input force is 50 N, the output force is 450 N and the mechanical advantage is 10.Therefore, the correct option is A, D and E.

Mechanical advantage is the ratio of output force to input force. In this case, LaToya is using a force of 50 N to pull a cart that weighs 500 N. The output force is the weight of the cart minus the force LaToya exerts on it:

Output force = 500 N- 50 N = 450 N

To see why statement F is incorrect, note that the formula for mechanical advantage is:

Mechanical advantage = output force / input force

Substituting the values we found earlier, we get:

Mechanical advantage = 450 N / 50 N = 9

So the mechanical advantage is actually 9, not 100.

Therefore, the correct option is A, D and E.

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When you double capacitance and inductance, the new resonance frequency becomes f/2.

The resonance frequency of RLC series circuit, is the frequency at which the capacity reactance is equal to inductive reactance.

It can also be defined as the natural frequency of an object where it tends to vibrate at a higher amplitude.

Xc = Xl

which gives the value for resonance frequency:

\(f = \frac{1}{2\pi \sqrt{LC} }\)

where;

f is the resonance frequency

L is the inductance

C is the capacitance

When you double capacitance and inductance, the new resonance frequency becomes;

\(f' = \frac{1}{2\pi \sqrt{2L2C} }\)

\(f' = \frac{1}{2\pi \sqrt{4LC} }\)

\(f' = \frac{1}{\pi \sqrt{LC} }\frac{1}{2}\)

\(f' = \frac{1}{2} f\)

Thus from above,

When you double capacitance and inductance, the new resonance frequency becomes f/2.

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(a)

- The coefficient of log(income) (0.88) suggests that a 1% increase in income is associated with a 0.88% increase in cigarette consumption, holding other variables constant.

- The coefficient of log(price) (-0.75) indicates that a 1% increase in cigarette prices is associated with a 0.75% decrease in cigarette consumption, holding other variables constant.

- The coefficient of educ (-0.50) implies that a one-year increase in education is associated with a 0.50 unit decrease in cigarette consumption, holding other variables constant.

- The coefficient of age (0.77) suggests that a one-year increase in age is associated with a 0.77 unit increase in cigarette consumption, holding other variables constant.

- The coefficient of age squared (-0.008) indicates that the relationship between age and cigarette consumption is not linear, and as age increases further, the rate of increase in cigarette consumption slows down.

- The coefficient of restaurant (2.83) implies that individuals who have access to smoking in restaurants smoke, on average, 2.83 more cigarettes per week compared to those who do not have access.

(b) The R-squared measures the proportion of the total variation in cigarette consumption that is explained by the independent variables. In this case, the R-squared is not provided, so it cannot be calculated or commented upon.

The Adjusted R-squared takes into account the number of variables and the sample size, providing a more reliable measure of model fit. Unfortunately, the Adjusted R-squared is also not provided, so it cannot be calculated or commented upon.

The difference between R-squared and Adjusted R-squared lies in the penalization of the latter for including additional variables that may not significantly contribute to the model.

(c) To perform a 1% individual significance test for each slope coefficient, we need the t-statistics and the corresponding p-values for each coefficient. These values are not provided, so we cannot perform the significance tests or comment on the results.

The null hypothesis (H0) for each significance test would be that the corresponding slope coefficient is equal to zero. The alternative hypothesis (Ha) would be that the slope coefficient is not equal to zero.

(d) The confidence interval for each slope coefficient can be calculated using the provided standard errors and assuming a t-distribution. However, the standard errors are not provided in the given format, so we cannot calculate the confidence intervals.

(e) To perform a 5% test of the overall significance of the regression model, we need the F-statistic and its corresponding p-value. Unfortunately, these values are not provided, so we cannot perform the test or comment on the results.

The null hypothesis (H0) for the overall significance test would be that all slope coefficients are equal to zero, indicating that none of the independent variables have a significant effect on cigarette consumption. The alternative hypothesis (Ha) would be that at least one of the slope coefficients is not equal to zero, indicating that at least one independent variable has a significant effect on cigarette consumption.

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Answer:

A. Neon and argon

General Formulas and Concepts:

Explanation:

Elements that have a full valence shell (the outermost shell), are in Group 18 of the Periodic Table.

Because their outermost shell is full, they are inert, meaning that they do not like to bond or react with other elements.

Therefore, these gases with a stable full valence shell are known as Noble Gases.

A. would be the correct answer.

Answer:argon and krypton

Explanation:

Noble gases

Let's first resolve the two forces into their components as shown in the diagram below: The larger force (617 N) makes an angle of 46° with the horizontal axis.

Therefore, the horizontal component will be given by:

H = 617 cos 46°H = 617 × 0.69H = 425.73 N

The vertical component will be given by:V = 617 sin 46°V = 617 × 0.73V = 450.66 NOn the other hand, the smaller force (411 N) makes an angle of (90° - 46°) = 44° with the horizontal axis. Therefore, the horizontal component will be given by:H = 411 cos 44°H = 411 × 0.72H

= 296.52 N

The vertical component will be given by:V = 411 sin 44°V = 411 × 0.67V = 274.47 N The resultant horizontal component, R will be given by:R = 425.73 + 296.52R = 722.25 N The resultant vertical component, R will be given by:R = 450.66 + 274.47R = 725.13 N The magnitude of the resultant, R will be given by:R² = (722.25)² + (725.13)²R = √(522198.06)R = 722.82 N The angle that R makes with the larger force (617 N) will be given by:θ = tan⁻¹(725.13/722.25)θ = 45.23° Therefore, the magnitude of the resultant is 722.82 N and it makes an angle of 45.23° with the larger force.

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Answer:

The energy of these two photons would be the same as long as their frequencies are the same (same color, assuming that the two bulbs emit at only one wavelength.)

Explanation:

The energy \(E\) of a photon is proportional to its frequency \(f\). The constant of proportionality is Planck's Constant, \(h\). This proportionality is known as the Planck-Einstein Relation.

\(E = h\, f\).

The color of a beam of visible light depends on the frequency of the light. Assume that the two bulbs in this question each emits light of only one frequency (rather than a mix of light of different frequencies and colors.) Let \(f_{1}\) and \(f_{2}\) denote the frequency of the light from each bulb.

If the color of the red light from the two bulbs is the same, those two bulbs must emit light at the same frequency: \(f_{1} = f_{2}\).

Thus, by the Planck-Einstein Relation, the energy of a photon from each bulb would also be the same:

\(h\, f_{1} = h\, f_{2}\).

Note that among these two bulbs, the brighter one appears brighter soley because it emits more photons per unit area in unit time. While the energy of each photon stays the same, the bulb releases more energy by emitting more of these photons.

Answer:

A chemical bond is a force of attraction between atoms or ions. Bonds form when atoms share or transfer valence electrons. Atoms form chemical bonds to achieve a full outer energy level, which is the most stable arrangement of electrons

Explanation:

Answer:

A chemical bond is a force of attraction between atoms or ions. Bonds form when atoms share or transfer valence electrons. Atoms form chemical bonds to achieve a full outer energy level, which is the most stable arrangement of electrons.

The smallest height needed to make a wave is (D)any height.

Wave in term of object is a condition of an object has different value of height in its surface as long as the surface has the crest point and the trough, an object can be determine has a wave. The highest point of the wave is named as the crest and the lowest point is named the trough. The wave height define as the overall vertical difference in height between the trough and the crest, and distance between two successive troughs or crests is the length of the wave or wavelength.

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Answer:

B

can i be brainlyest

Explanation:

Answer: 510 in Newton’s and 115 lbs

Explanation:

Considering the definition of weigh, Lisa weighs 0.5096 N or 0.1146 pounds.

Mass is the amount of matter that a body contains, while weight is the action exerted by the force of gravity on the body. That is, weight is a measure of how much force gravity exerts on the mass of an object.

The mass of an object will always be the same, no matter where it is located. Instead, the weight of the object will vary according to the force of gravity acting on it.

Weight can be calculated as the product of mass and acceleration due to gravity:

W=m×g

In this case, you  know:

Replacing in the definition of weigh:

W=0.052 kg×9.8 m/s²

Solving:

W= 0.5096 N

1 newton equals 0.2248 pound. Then W=0.5096 N= 0.1146 Pounds

Finally, Lisa weighs 0.5096 N or 0.1146 pounds.

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0.8 A of current is flown through the upper branch of the circuit shown below:

as shown in the figure the current through lower loop is \(I_1+I_2\) and the current through the upper loop is \(I_2\).

the kirchoff's loop eqns in lower loop is:

 -4\(I_1\) + 5 -\(I_1\) - 10(\(I_1+I_2\)) = 0

=> 2\(I_1\) +\(I_1\) + 2\(I_2\) = 1

=> 3\(I_1\) + 2\(I_2\) =1    ----- (i)

we have obtanied 1 equation

the kirchoff's loop eqns in upper loop is:

-3\(I_2\) +10 -2\(I_2\) + \(I_1\) - 5 +4\(I_1\) = 0

=> - 5  \(I_2\) +10+ 5 \(I_1\) -5 =0

=> \(I_2\) -  \(I_1\) =1     -------(ii)

solving equation (i) and equation (ii) we get

\(I_1\) = -0.2

here negative sign represents that the current direction is opposite to our assumption.

so     \(I_2\) = 1 + \(I_1\)

=>     \(I_2\) = 0.8A

So the current through the upper branch is 0.8A

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Complete question:

in the circuit shown in the figure , find the magnitude of current in the upper branch.

Answer:

The answer should be True, but it's False on Edge 2021

Explanation:

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Li is hearing overlapping frequencies that have a harmonic structure, and their brain is interpreting it as the sound of an electric guitar.

Based on the given information, it seems like the question is asking about li's perception of sound. Li is hearing various frequencies that have a similar harmonic structure, and they are perceiving it as the sound created by an electric guitar being played.

To answer this question more thoroughly, we can break it down into several steps:

Harmonic Structure: Harmonic structure refers to the arrangement of frequencies that make up a sound. When a sound has a harmonic structure, it means that the frequencies are related to each other in a specific way. For example, the frequencies might be multiples of a fundamental frequency. This creates a pleasing and organized sound.

Overlapping Frequencies: Li is hearing frequencies that overlap in their harmonic structure. This means that multiple frequencies are present, and they share common harmonics. When these frequencies are played together, they create a complex sound with a rich tonal quality.

Perception: Li's brain is grouping these overlapping frequencies together and perceiving them as the sound produced by an electric guitar being played. This suggests that the harmonic structure and tonal qualities of the sound resemble those typically associated with an electric guitar.

Li is hearing overlapping frequencies that have a harmonic structure, and their brain is interpreting it as the sound of an electric guitar. This perception is likely due to the similarity in harmonic structure and tonal qualities between the actual sound and the sound produced by an electric guitar.

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Answer:

Input force of pulley system = 200 N

Explanation:

Given:

Mechanical advantage of pulley system = 5

Output force from pulley system = 1,000 N

Find;

Input force of pulley system

Computation:

Mechanical advantage = Output force / Input force

Mechanical advantage of pulley system = Output force from pulley system / Input force of pulley system

5 = 1,000 / Input force of pulley system

Input force of pulley system = 1,000 / 5

Input force of pulley system = 200 N

Explanation:

F = MA

200 = 100 * A

A = 200/100

A = 2m/sec^2

Answer:

Velocity

Explanation:

I took the test.

The minimum value of M1 to keep a board from falling off the platform is 90 kg.

The mass (M1) placed on the left side edge of the board

the mass of the board = 60 kg

the length of the board = 6 m

If the mass on the right side = 30 kg, and the length of the board L1 = 2m

Then, the length L2 which extend over the edge = 4m

Consider the center of gravity in the board that lies at the length of the board midpoint.

Then, the distance (D) of the gravity center from the platform end = 3 - 2

= 1

The moment when the platform end, the mass (M1) placed on the left side edge of the board can be computed as:

M1= 60kg+120kg/2

M1=180kg/2

M1=90kg

Therefore, The minimum value M1 needed to keep the board from falling off the platform is 90 kg.

Mass is a quantitative measure of inertia, a fundamental property of matter.

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The formula to calculate the utilization of the second activity in a push system can be determined by dividing the total time spent on the second activity by the total time available.

In a push system, activities or tasks are performed sequentially, and the completion of one activity triggers the start of the next activity. The utilization of activity refers to the proportion of time that the activity is being used or occupied.

To calculate the utilization of the second activity in a push system, we need to determine the total time spent on the second activity and divide it by the total time available. The formula can be expressed as:

Utilization of Second Activity = (Time spent on Second Activity / Total Time Available) * 100

The time spent on the second activity refers to the duration or amount of time required to complete that specific activity. The total time available represents the total duration or available time for the entire process or system.

By using this formula, we can determine the utilization of the second activity, which provides insight into how efficiently the activity is being utilized within the overall system.

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A potential drawback to the use of solar energy systems is that it requires a large power grid to be effective.

Potential drawbacks to the use of solar energy systems include:

Requires a large power grid

Uses a large amount of water

Production of components that use toxic materials

Solar energy systems require a large power grid because solar panels produce direct current (DC) electricity. However, the electricity grid operates on alternating current (AC) electricity. Therefore, the direct current must be converted into alternating current before it can be distributed on the power grid. This requires a large power grid. This is because these systems need to dissipate the heat generated by the sun’s energy, which is done through a cooling process that requires water. The production of some solar components, such as solar panels, can require the use of toxic materials, such as lead and cadmium. This can have environmental and health impacts if not handled correctly.

Additionally, the production of solar energy components can use toxic materials, and the process of creating solar energy can require a large amount of water.

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Potential drawbacks to the use of solar energy systems include the need for

I. a large power grid.

II. a large amount of water.

III. toxic metals for production of components

The pressure on the rainy day is 0.9684 atmospheres. It is important to note that atmospheric pressure can vary depending on weather conditions and altitude, so this value may not be the same in all locations or at all times.

To convert a barometric reading from millimeters of mercury (mmHg) to atmospheres (atm), you can use the following conversion factor: 1 atm = 760 mmHg.

Given that the barometer reads 737 mmHg on a rainy day, you can convert this value to atmospheres using the formula:

Atmospheres = (mmHg reading) / (760 mmHg/atm)

By plugging in the value:

Atmospheres = (737 mmHg) / (760 mmHg/atm)

Atmospheres ≈ 0.97 atm

So, on a rainy day when the barometer reads 737 mmHg, the atmospheric pressure is approximately 0.97 atmospheres.

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Answer:

females

Explanation:

The ova(egg) starts meiosis as a foetus but doesn't complete it until puberty. This is when the menstrual cycle will start to occur indicating the gametes( egg) is maturing and if not fertilized will be removed.

Answer:

Explanation: