the standard enthalpy of fusion of 1.0 mole of a compound is 10 kj at its melting point of 200 k. what is the entropy change for the melting 2.0 mole of this compound at its melting point?

Answers

Answer 1

1. The standard enthalpy of fusion of 2.0 moles of the compound is 20 kJ.

2. The entropy change for the melting of 2.0 moles of the compound at its melting point is 2 times the entropy change for the melting of 1.0 mole.

1. The standard enthalpy of fusion is a measure of the heat energy required to convert one mole of a substance from solid to liquid at its melting point.

Given that the standard enthalpy of fusion of 1.0 mole of the compound is 10 kJ, we can conclude that the standard enthalpy of fusion of 2.0 moles of the compound would be double that value, which is 20 kJ.

2. The entropy change (ΔS) for the melting of a substance is related to the standard enthalpy of fusion (ΔH) by the equation ΔS = ΔH/T, where T is the temperature in Kelvin. In this case, the temperature is given as the melting point, which is 200 K.

Since the entropy change is directly proportional to the number of moles, we can conclude that the entropy change for the melting of 2.0 moles of the compound at its melting point would be twice the entropy change for the melting of 1.0 mole.

Therefore, the entropy change for the melting of 2.0 moles of the compound would be 2 times ΔS.

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Related Questions

Nutrients that are made by living things, are required only in small amounts, and that assist many chemical reactions are.

Answers

Vitamins are an important nutrient that the body needs to grow, develop, and carry out its functions normally. These nutrients are classified as macronutrients or micronutrients, which means the body needs them in small amounts. Generally, vitamins come from organic foods and fruits.

Vitamins

Not all vitamins can be produced by the body, so humans still need vitamins as additional nutrition. Vitamins and minerals are nutrients that fall into the category of micronutrients. The body requires levels of vitamins and minerals in small amounts.

Some types of vitamins that are known are:

Vitamins A, C, D, E, K,

B vitamins, including thiamin (B1), riboflavin (B2), niacin (B3), pantothenic acid (B5), pyridoxal (B6), cobalamin (B12) , biotin, and folic acid/folate.

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What’s the elements found in these formulas?

NaC2HO4

H2F5BLi

2He2PSO4

3He2O4PH

Answers

Answer:

The only one I know is NaC2HO4.

There is Sodium, Carbon, Hydrogen and Oxygen.

1 atom in sodium, 2 atoms in carbon, 1 atom in hydrogen and 4 atoms in oxygen completeting the total of 8 atoms in this element.

The elements are the simplest chemical forms and they cannot be broken down through chemical reactions. There are many elements in the given formulas.

What are elements?

The elements are defined as those substances whose atoms all have the same number of protons. The elements are considered as the building blocks of matter. Each element has an atomic number and a symbol.

Each atom is regarded as an element. The elements create bonds to form molecules. The isotopes are the elements with the same atomic number but different mass numbers.

NaC₂HO₄  - 'N' , 'C', 'H','O'

H₂F₅BLi - 'H','F','B','Li'

He₂PSO₄ - 'He', 'P','S','O'

He₂O₄PH - 'He', 'O','P','H'

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Match the following aqueous solutions with the appropriate letter from the column on the right. Assume complete
dissociation of electrolytes.
1. 0.10 m Culz
2. 0.13 m Cr(CH COO)2
3. 0.17 m CuSO4
A. Lowest freezing point
B. Second lowest freezing point
C. Third lowest freezing point
4. 0.37 m Glucose (nonelectrolyte)
D. Highest freezing point

Answers

The freezing point depression of a solution is proportional to the molality (m) of the solution, where molality is defined as the number of moles of solute per kilogram of solvent.

The more solute dissolved in a solution, the lower its freezing point will be. Based on this information, we can match the aqueous solutions with their appropriate letter from the column on the right:

0.10 m CuCl2 → C. Third lowest freezing point

0.13 m Cr(CH3COO)2 → B. Second lowest freezing point

0.17 m CuSO4 → A. Lowest freezing point

0.37 m Glucose (nonelectrolyte) → D. Highest freezing point

Explanation:

CuCl2 and CuSO4 are both strong electrolytes that dissociate completely in solution to form two ions per formula unit.

Therefore, they will have a greater effect on the freezing point depression compared to Cr(CH3COO)2, which only dissociates partially in solution.

Glucose is a nonelectrolyte and does not dissociate in solution, so it will have no effect on the freezing point depression. Therefore, it will have the highest freezing point among the given solutions.

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When a person runs, how is
the energy transformed?
A. The chemical energy in their food is
transformed into sound and thermal energy.
B. The mechanical energy in their food is
transformed into electromagnetic and
thermal energy.
C. The chemical energy in their food is
transformed into mechanical and thermal
energy.

Answers

The energy can neither be created nor be destroyed. But it can be converted from one form to another. When a person runs, The chemical energy in their food is transformed into mechanical and thermal energy. The correct option is C.

What is mechanical energy?

The mechanical energy of an object is the sum of the potential and kinetic energies which is used to do a particular work. It represents the energy of an object due to its motion or position or both.

The body takes chemical energy in the form of food. when a person runs this chemical energy is utilized by our body and converted into kinetic energy (Mechanical). The body get heated by running which then releases thermal energy.

Thus the correct option is C.

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The half-life of sodium-24 is 15 hours. How much sodium-24 will remain after 3.75 days, if the initial sample
was 20.0 grams

Answers

After 3.75 days, 6.25 grams of sodium-24 will remain.

What property of a metal does the image represent

Answers

Answer:

malleable

Explanation:

The image represent in malleable property of metal.

Final answer:

The image possibly represents the photoelectric effect of a metal, which is when it emits electrons after being exposed to electromagnetic radiation. Metals are also characterized by physical properties such as conductivity, malleability, metallic luster, and metallic bonding.

Explanation:

Based on your question, the image possibly represents the photoelectric effect, a key property of metals. This phenomenon occurs when a metal surface exposed to electromagnetic waves of a certain frequency absorbs radiation and emits electrons. These emitted electrons are called photoelectrons. Metals can also exhibit free electron model behavior, where electrons freely roam within the metal structure.

Metals possess unique physical properties like conductivity, malleability, and metallic luster. Malleability refers to the metal's ability to deform without breaking, while conductivity refers to the metal's ability to transfer heat or electricity. A metallic luster gives metals their characteristic shiny appearance.

Finally, metals are also known for their metallic bonding—a unique force that holds together the atoms within a metallic solid. Metallic bonding gives rise to many useful and varied bulk properties of metals.

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Cell types a classification

Answers

Answer:

It is possible to divide cells into two classifications: eukaryotic cells, which have a nucleus, and prokaryotic cells, which do not possess a nucleus but do contain a nucleoid area. In contrast to prokaryotes, which are one-celled creatures, eukaryotes may be either single-celled or multicellular in nature.

Explanation:

Hope it helps:)

the mass of an object in a given space is known as its

Answers

The mass of an object in a given space is known as its relativistic mass.

The system's mass as it will be determined by a scale just might be the relativistic mass, however, in some instances (such as the box above), this fact only holds true since this system must typically be at rest in order to be measured .

For instance, if an electron in such a cyclotron is traveling in circles at a relativistic velocity, its relativistic mass rather than its rest mass increases the mass of the cyclotron and electron system.

Therefore, The mass of an object in a given space is known as its relativistic mass.

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Amateur rheologist noticed a strong low pressure system (yellow circle in this image) moving into the state of California what is most likely the forecast for California please answer this question carefully and quickly because this is a test and I would love to get it right so please help me out I will give Brain things lol

Amateur rheologist noticed a strong low pressure system (yellow circle in this image) moving into the

Answers

Amateur rheologist noticed a strong low pressure system moving into the state of California therefore the most likely forecast for California is that it is windy with rainy conditions and is therefore denoted as option C.

Who is a Rheologist?

This is referred to as a professional who is involved in the study of the deformation and flow of materials such as solids and liquids.

An area with low pressure is characterized by rainfall and we can also observe the blue color in the area which depicts a cloudy weather which is therefore the reason why windy with rainy condition was chosen.

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Find the unit rate for 306 mines in 10 hours
0.03 miles/hour
30.6 miles/hour
306 miles/hour
3,060 miles/hour

Answers

30.6 miles/hour. You just divide 306 by 10. hope this helps!

Which orbital is portrayed on the right?

Which orbital is portrayed on the right?

Answers

A maximum of two electrons will be placed in 1s first. With a maximum of two electrons, 2s will then be filled. With a maximum of 6 electrons, 2p will then be filled.

What's the appearance of the p orbital?A maximum of two electrons will be placed in 1s first. With a maximum of two electrons, 2s will then be filled. With a maximum of 6 electrons, 2p will then be filled.A maximum of two electrons will be placed in 1s first. With a maximum of two electrons, 2s will then be filled. With a maximum of 6 electrons, 2p will then be filled.Each shell can only carry a certain amount of electrons: the first shell can hold two electrons, the second shell can hold eight electrons (2 + 6) and so on, the third shell can hold 18 electrons (2 + 6 + 10).        

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38. calculate k for the following reaction at 25°c: 3i2(s) 2fe(s) à 2fe3 (aq) 6i-(aq).

Answers

it is not possible to provide an exact numerical value for the equilibrium constant (K) of the reaction 3I2(s) + 2Fe(s) -> 2FeI3(aq) + 6I-(aq) at 25°C.

How can equilibrium constant be determined ?

I apologize for the confusion earlier. Let's assume the correct balanced equation for the reaction you mentioned is:

  3I2(s) + 2Fe(s) -> 2FeI3(aq) + 6I-(aq)

To calculate the equilibrium constant (K) at 25°C, we need to know the concentrations of the species at equilibrium. Without the specific concentrations, we won't be able to provide an exact numerical value for K. However, I can guide you through the process of calculating K using the given information.

Let's assume the initial concentration of I2 is [I2]₀ and the initial concentration of Fe is [Fe]₀. At equilibrium, let's assume the concentration of FeI3 is [FeI3] and the concentration of I- is [I-].

The balanced equation indicates that the stoichiometric ratio between I2 and FeI3 is 3:2. Therefore, at equilibrium, the concentration of I2 will be [I2]₀ - (3 * x), where x is the change in concentration of I2.

Similarly, the stoichiometric ratio between Fe and FeI3 is 2:2 (or 1:1), meaning the concentration of Fe at equilibrium will be [Fe]₀ - (1 * x).

Since 6 moles of I- are produced for every 1 mole of FeI3 consumed, the concentration of I- at equilibrium will be 6x.

The equilibrium constant expression (K) for the given reaction is:

K = ([FeI3] * [I-]^6) / ([I2]^3 * [Fe])

To obtain the numerical value of K, we would need the specific concentrations at equilibrium.

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The amount of pollution produced by cars was measured for cars using gasoline containing difference amounts of lead. What is the control group?

Answers

Answer:

The constant/"control" would be the type of car

Explanation:

This is because the car is what you are experimenting on. The independent variable would be the different amounts of lead and the dependent would be the pollution produced because it is affected by the independent variable.

IV: different amounts of lead

DV: pollution produced

Constant- type of car

The minimum amount of energy that particles must have in order to react is known as the... what?

Answers

Activation energy

Hope this helps

Neglect overpotential and determine the minimum potential required to electrolyze molten CrClz How grams of Cr would be deposited and how many liters of Clz gas would be produced at 194 cC and 1.68 atm by passing current of 17.0 for 11.0 hrs? 221.49 79.604

Answers

To determine the minimum potential required to electrolyze molten CrCl2, we need to consider the electrochemical cell potential. Given the current and time, we can calculate the amount of Cr deposited and the volume of Cl2 gas produced using Faraday's laws and stoichiometry.

To determine the minimum potential required to electrolyze molten CrCl2, we need to consider the reduction half-reaction that occurs at the cathode during electrolysis. In this case, the reduction of Cr3+ to Cr occurs:

Cr3+ + 3e- → Cr

The standard reduction potential for this reaction can be found in electrochemical tables. By applying Faraday's laws, we can relate the amount of charge (Q) passed through the cell to the moles of electrons transferred. The potential required can be calculated using the equation:

E = (Q * E°) / (n * F)

where E is the cell potential, Q is the charge passed, E° is the standard reduction potential, n is the number of moles of electrons transferred, and F is Faraday's constant.

Given the current of 17.0 A and the time of 11.0 hours, we can calculate the total charge passed using Q = I * t. Substituting the values into the equation and solving for E will give the minimum potential required to electrolyze molten CrCl2.

To determine the amount of Cr deposited and the volume of Cl2 gas produced, we need to use the stoichiometry of the balanced equation for the reaction. From the balanced equation:

1 mole of Cr3+ + 3 moles of e- → 1 mole of Cr

2 moles of Cl- → 1 mole of Cl2

Using the calculated charge passed and Faraday's constant, we can calculate the moles of electrons transferred. From the stoichiometry, we can then determine the moles of Cr deposited and the moles of Cl2 produced. Finally, we can convert the moles of Cr to grams and the moles of Cl2 to liters at the given temperature and pressure.

By following these steps and performing the necessary calculations, we can determine the minimum potential required to electrolyze molten CrCl2, the amount of Cr deposited in grams, and the volume of Cl2 gas produced in liters.

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A tank contains a mixture of 3.00 mol N₂, 2.00 mol O₂, and 1.00 mol CO₂ at 25 °C and a total pressure
of 10.0 atm. Calculate the partial pressure of each gas in the mixture.

Answers

The partial pressure of N₂ is 3.75 atm, the partial pressure of O₂ is 2.50 atm, and the partial pressure of CO₂ is 1.25 atm in the given mixture at 25 °C and a total pressure of 10.0 atm.

To calculate the partial pressure of each gas in the mixture, we can use the concept of Dalton's law of partial pressures. According to this law, the total pressure exerted by a mixture of gases is equal to the sum of the partial pressures of each individual gas.

First, we need to find the mole fraction of each gas in the mixture. The mole fraction of a gas is the ratio of the number of moles of that gas to the total number of moles in the mixture. We can calculate the mole fraction using the following formula:

Mole fraction (X) = Moles of gas / Total moles of all gases

For N₂:

Mole fraction of N₂ (X_N₂) = 3.00 mol / (3.00 mol + 2.00 mol + 1.00 mol) = 0.375

For O₂:

Mole fraction of O₂ (X_O₂) = 2.00 mol / (3.00 mol + 2.00 mol + 1.00 mol) = 0.250

For CO₂:

Mole fraction of CO₂ (X_CO₂) = 1.00 mol / (3.00 mol + 2.00 mol + 1.00 mol) = 0.125

Next, we can use the mole fractions to calculate the partial pressures of each gas. The partial pressure of a gas is equal to the mole fraction of that gas multiplied by the total pressure of the mixture.

Partial pressure of N₂ (P_N₂) = X_N₂ * Total pressure = 0.375 * 10.0 atm = 3.75 atm

Partial pressure of O₂ (P_O₂) = X_O₂ * Total pressure = 0.250 * 10.0 atm = 2.50 atm

Partial pressure of CO₂ (P_CO₂) = X_CO₂ * Total pressure = 0.125 * 10.0 atm = 1.25 atm

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What foods of the aztec found their way into mayan cooking?.

Answers

Avocados and tomatoes were mainly eaten by the Aztecs and Maya.

How did Mayans cook their food?

"Mayans cooking method includes digging a shallow pit, lining it with stones or clay balls.

Avocados and tomatoes were mainly eaten by the Aztecs and Maya, with different types of fruit. Corn was made into a kind of porridge, called atole in Mesoamerica and capita in Inca territory.

Avocados and tomatoes were mainly eaten by the Aztecs and Maya.

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Q23) quickly please
23) The cooling a food with the formation of the first ice crystals called a. Super cooling b. Initial freezing point c. Critical point d. Eutectic temperature

Answers

The process of cooling a food until the first ice crystals form is referred to as supercooling. Supercooling occurs when a substance is cooled below its freezing point without undergoing solidification.

This phenomenon is commonly observed in liquids that are pure and free from impurities. Supercooling allows the formation of ice crystals to be delayed until a nucleation site is present or an external disturbance occurs.

Supercooling refers to the state where a substance remains in a liquid phase below its freezing point. When a food is rapidly cooled, it can reach a temperature below the freezing point without solidifying. This occurs because the process of nucleation, which initiates the formation of ice crystals, is hindered. In the absence of nucleation sites or external disturbances, the food remains in a supercooled state.

However, as soon as a nucleation site is introduced or an external disturbance occurs, the supercooled food rapidly crystallizes and forms ice. This process is commonly observed when touching an already supercooled liquid, causing it to freeze instantly. Supercooling can be utilized in various applications, such as in the production of supercooled drinks or in cryopreservation techniques.

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a scientist begins this experiment with 3 m a(g) and 3 m b(g). after running the experiment, she notices the concentration of a(g) is 0.75 m. what are the concentrations of the other two components?

Answers

The concentration of b(g) is 2.25 m, and the concentration of a(g) is 0.75 m.

Since the total amount of the two components, a(g) and b(g), remains constant throughout the experiment, the total concentration after the experiment can be expressed as:

3 m (a(g)) + 3 m (b(g)) = 0.75 m (a(g)) + b(g)

Rearranging this equation and solving for b(g), we find that:

b(g) = 3 m (a(g)) + 3 m (b(g)) - 0.75 m (a(g))

b(g) = 3 m - 0.75 m

b(g) = 2.25 m

What are the two components of concentration?

Concentration is determined mathematically by taking the mass, moles, or volume of solute and dividing it by the mass, moles, or volume of solution (or, less commonly, the solvent).

What are the components of the concentration of a solution?

Many solutions contain one component, called the solvent, in which other components, called solutes, are dissolved. An aqueous solution is one for which the solvent is water. The concentration of a solution is a measure of the relative amount of solute in a given amount of solution.

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A 1.7 M solution of the base B has a pH of 12.80. What is the Kb of the base? The equation described by the Kb value is B(aq)+H2O(l)⇌BH+(aq)+OH−(aq) Select the correct answer below:
1.5×10−3
2.4×10−3
0.065
0.0631

Answers

The Kb value of the base B is 2.4 x \(10^{-3}\). To determine the Kb value, we can use the relationship between pH and pOH. The correct option is 2.4 x \(10^{-3}\)

Since pH + pOH = 14, we can calculate the pOH of the solution by subtracting the pH from 14. In this case, the pOH is 14 - 12.80 = 1.20.

Next, we can convert the pOH to OH- concentration using the formula pOH = -log[OH-]. Thus, [OH-] = \(10^{(-pOH) }\) = \(10^{-1.20}\) = 0.0631 M.

Since the concentration of the base B is 1.7 M, we can assume that the concentration of BH+ is also 1.7 M, as they have a 1:1 stoichiometric relationship. Therefore, [BH+] = 1.7 M.

Now, using the equation for Kb: Kb = [BH+][OH-]/[B], we can substitute the known values to find the Kb value:

Kb = (1.7 M)(0.0631 M)/(1.7 M) = 0.0631.

Thus, the Kb value of the base B is 0.0631.

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if the influent nh4 concentration is 21.8 mg-n/l, estimate the amount of alkalinity (in mg/l as caco3) that must be added to buffer against complete nitrification, assuming a residual alkalinity of 80 mg/l as caco3 is required to keep the ph at approximately neutral. assume the influent alkalinity is 150 mg/l as caco3.

Answers

In order to buffer against complete nitrification, you need to add the amount of alkalinity (in mg/l as caco3) that is equal to the difference between the influent alkalinity of 150 mg/l as caco3 and the residual alkalinity of 80 mg/l as caco3. So, the amount of alkalinity that must be added to buffer against complete nitrification is 70 mg/l as caco3.


To calculate this, you need to first determine the difference between the influent alkalinity and the required residual alkalinity. The influent alkalinity (in mg/l as caco3) is 150, and the required residual alkalinity (in mg/l as caco3) is 80. So, the difference between these two values is 70 mg/l as caco3. This is the amount of alkalinity that must be added to buffer against complete nitrification.


Therefore, if the influent NH4 concentration is 21.8 mg-N/l, you need to add 70 mg/l as caco3 of alkalinity to buffer against complete nitrification, assuming a residual alkalinity of 80 mg/l as caco3 is required to keep the pH at approximately neutral, and the influent alkalinity is 150 mg/l as caco3.

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Propane (c3h8) is a component of natural gas and is used in domestic cooking and heating. c3h8 5o2 --> 3co2 4h2o how many grams of carbon dioxide can be produced by burning 3.65 moles of propane? assume that oxygen is the excess reagent in this reaction.

Answers

Below is the balanced chemical equation. 1.07 103 kilograms of carbon dioxide will be created. Every balanced chemical equation adheres to the principle of mass conservation.

What does "balanced chemical equation" mean?

A chemical equation is said to be balanced if the quantity of each type of atom in the reaction is the same on both the reactant and product sides. In a balanced chemical equation, the mass and the change are both equal.

Every balanced chemical equation follows the law of conservation mass , according to the information provided.

The total number of individual atoms on the reactant side and the total number of individual atoms on the product side must match,

according to this law.

The balancing chemical for the indicated reaction equation follows:

C₃H₈+5O₂→3CO₂=4H₂O

All the substances are present in gaseous state.

By Stoichiometry of the reaction:

1 mole of propane gas produces 3 moles of carbon dioxide gas.

So, 3.65 moles of propane gas will produce =  of carbon dioxide gas.

Now, calculating the mass of carbon dioxide using equation:

3/1×3.65

=10.95

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide = 24.33 mol

Putting values in above equation, we get:

10.95=Mass of carbon dioxide÷44g/mol

         =4.50×10³g

Hence, the amount of  produced in the given reaction and expressed in scientific notation is 4.50×10³

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Make sure T is in Kelvin! If it is in °C then use K = C +273

Example 1: If a 2.0 L sample of air is collected at 298K, but its temperature falls to -25°C, what is the final

volume of the sample?

Answers

The final volume of the sample is (2.0 L ˣ 248 K) / 298 K L.

What is the final volume of a 2.0 L sample of air collected at 298K when its temperature falls to -25°C?

To calculate the final volume of the sample of air, we need to convert the temperature from Celsius to Kelvin and then apply Charles's law, which states that the volume of a gas is directly proportional to its temperature at constant pressure.

Given:

Initial volume (V1) = 2.0 L

Initial temperature (T1) = 298 K

Final temperature (T2) = -25°C

To convert the final temperature from Celsius to Kelvin:

T2 (in Kelvin) = -25°C + 273 = 248 K

According to Charles's law:

V1 / T1 = V2 / T2

Solving for V2 (final volume):

V2 = (V1 ˣ T2) / T1

Substituting the given values:

V2 = (2.0 L ˣ 248 K) / 298 K

Now we can calculate the final volume, V2, using this formula.

Performing the calculation will give you the final volume of the sample in liters.

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A magnet was placed near a pile that contained both iron and sulfur. The magnet was moved gradually

closer to the pile. As it neared the pile, the magnet started attracting small pieces of iron from the pile

Answers

A magnet was placed near a pile that contained both iron and sulfur. The magnet was moved gradually closer to the pile. As it neared the pile, the magnet started attracting small pieces of iron from the pile since G. It is a heterogeneous mixture of iron and sulfur.

A heterogeneous mixture is one that does not possess a consistent structure. We must remember that a combination is any combination of materials which do not chemically react and are physically separable. Having said that, it is obvious that I can separate the iron from the sulphur using simple magnetic (physical) means. As a result, it is a heterogeneous iron and sulphur mixture. A heterogeneous mixture is one in which the composition varies all through the solution. A single-phase is defined as a pure compound or a homogeneous mixture. A heterogeneous mixture has two or more different stages.

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The complete question is :

A magnet was placed near a pile that contained both iron and sulfur. The magnet was moved gradually closer to the pile. As it neared the pile, the magnet started attracting small pieces of iron from the pile. Which of these statements best describes the contents of the pile?

F. It is a homogeneous mixture of iron and sulfur. G. It is a heterogeneous mixture of iron and sulfur. H. It is a compound that contains both iron and sulfur. I. It is a compound that can be separated by magnetism.

A student ran the following reaction in the laboratory at 527 k:

cocl2(g) co(g) + cl2(g)

when she introduced 1.60 moles of cocl2(g) into a 1.00 liter container, she found the equilibrium concentration of cocl2(g) to be 1.57 m.

calculate the equilibrium constant, kc, she obtained for this reaction.

kc =

Answers

The equilibrium constant kc, she obtained for this reaction is 5.7×10⁻⁴.

What is equilibrium constant?

The amount of reactant to product in a chemical reaction can be compared to determine the equilibrium constant, which is used to predict chemical behavior. The rate constants are fixed at some temperature.

The rate constant for the forward reaction divided by the rate constant for the reverse reaction is the equilibrium constant.

Balanced reaction,

COCl₂(g)  ↔ CO(g) + Cl₂(g)

The equilibrium COCl₂ = 1.57M (volume is 1L hence concentration is M)

1.6 - x = 1.57

so, x = 1.57 - 1.6

x = -0.03M

Thus, Kc = x²/1.6 - x

Kc = 0.0009/1.57

Kc = 5.7×10⁻⁴

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What 2 main factors drive the water cycle? view attachment

What 2 main factors drive the water cycle? view attachment

Answers

Answer:

sun and ocean. I had this last week

How is pesudoscience different than science

Answers

The big difference between science and pseudo-science is a difference in attitude. While a pseudo-science is set up to look for evidence that supports its claims, a science is set up to challenge its claims and look for evidence that might prove it false

what could you do to increase the electrical force between two charged particles by a factor of 16

Answers

Increasing one charged particle by 16 will lead to increasing the electrical force between two charged particles by a factor of 16.

What is Electrical force?

This is referred the attractive or repulsive interaction between any two charged bodies present.

F= kq1q2/r²

F1/F2= kq1q2/r² / 16kq1q2/r²

F1/F2 = 1/16

F2 = 16F1

This is therefore how to increase the electrical force between two charged particles by a factor of 16.

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what is the condensed electron configuration of a ground state atom of manganese (Z =25).

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The condensed electronic configuration  of a ground state atom of manganese is \([Ar] 3d^5 4s^2\).

Electronic configuration is defined as the distribution of electrons which are present in an atom or molecule in atomic or molecular orbitals.It describes how each electron moves independently in an orbital.

Knowledge of electronic configuration is necessary for understanding the structure of periodic table.It helps in understanding the chemical properties of elements.Manganese has  five electrons in d-orbital and two in s-orbital .

Thus, the  condensed electronic configuration  of a ground state atom of manganese is \([Ar] 3d^5 4s^2\).

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naming compoundingLi2O • 9 H2O

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Let's see that the first compound represents an oxide which is a combination resulting from the union of a metallic or nonmetallic element with oxygen. To name an oxide, you have to write "___ oxide", where the line is the name of the element. In this case, lithium is the element that is bonded with oxygen, so its name is lithium oxide.

The second compound that you can recognize as water, is an oxide too. So its name is also hydrogen oxide.

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