middle school work please help!!
Answer:
5.52 miles
Step-by-step explanation:
All you need to do in multiply 1.2 by 4.6 like this:
1.2 x 4.6 = 5.52 miles
I hope this helps
What is the equation of the line that passes through the point (8,-8) and has a
slope of – 12
Answer:
y + 8 = -12(x - 8)
General Formulas and Concepts:
Algebra I
Point-Slope Form: y - y₁ = m(x - x₁)
x₁ - x coordinate y₁ - y coordinate m - slopeStep-by-step explanation:
Step 1: Define
Point (8, -8)
Slope m = -12
Step 2: Write Function
Substitute variables into general form.
y + 8 = -12(x - 8)
PLEASEE HELPP with this problem!!!
can you find x and y???
23. What is the slope of the line tangent to the polar curve r=2(theta) at the point theta = pi/2?
The polar equation to rectangular coordinates and finding the derivative of the resulting equation, we determined that the slope of the line tangent to the polar curve r=2(theta) at the point theta = pi/2 is 2.
To find the slope of the line tangent to the polar curve r=2(theta) at the point theta = pi/2, we need to first convert the polar equation to rectangular coordinates.
Using the conversion equations cos (theta) = x and sin (theta) = y, we can rewrite the equation as y = 2x(pi/2). Simplifying this, we get y = 2x.
Now we need to find the derivative of this equation at the point (pi/2, pi). Taking the derivative of y = 2x with respect to x gives us the slope of the line, which is simply 2.
Therefore, the slope of the line tangent to the polar curve r=2(theta) at the point theta = pi/2 is 2. This means that at the point where theta = pi/2, the curve is increasing at a rate of 2 units for every 1 unit increase in x.
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plssss helppppp ASAP
will mark brainliest
Answer:
your taking algebra nice
Step-by-step explanation:
the answer is the green one
a student says the prime factors of 17 are 1 and 17. is the student correct?
Answer: yes
A prime factor is number that can only divided by itself and one
Since, 17 can only be divided by 17 and 1, the student is correct
Step-by-step explanation:
This is the question in the photo above.
Answer:
an alternative hypothesis is an angle that is alternate to each other
Look at pic attached. Determine which lines, if any, must be parallel. Check all that apply. Explain your reasoning.
all of them are parrelel, they are all forming right angles
and im pretty sure the answer is number twooooooo for the next thing????? i hope this helped!
What is the volume of 288
Answer: 6
Step-by-step explanation: 288
=
3
(
4
)
×
w
×
4
w
=
288
3
(
4
)
⋅
4
=
72
12
=
6
I think <3
Answer:
The width is
6 cm. You can find it by taking the formula for the volume of a cube and rearranging it to find the width.
Step-by-step explanation:
0
с
z←
85⁰
D
Work out the three-figure bearing of D from C.
Answer:
095
Step-by-step explanation:
You want the bearing from C to D, given that the bearing from D to C is 85° west of north.
BearingThe bearing from C to D will be the opposite of the bearing from D to C.
Bearing is measured clockwise from north, so the bearing shown from D to C is -85°. Its opposite is found by adding 180°.
180° +(-85°) = 95°
The 3-digit bearing of D from C is 095.
In the united states in 1980 approximately 60 million families had TV's in their home. In 2015 there was almost 100 million families that had TV's in their home. Approximately how many more TV's were there in 2015?
Answer:
Approximate of 40 Million Televisions
Step-by-step explanation:
there were 40 million more families with televisions in 2015 after a long period of time after 1980
I hope this helped!
Tony is designing an indoor play area. He knows the width will be 14 feet. He wants the length to be a multiple of 6 and thus records it as 6x. The area of the indoor play area must be greater than 588 square feet. Write an inequality that can be used to find the possible x-values for the desired area. Include all necessary work to support your answer
Inequalities are used to represent the unequal expressions
The inequality is \(84x > 588\), and the possible values of x are greater than 7
How to determine the inequalityThe width is given as;
Width = 14 feet
The length is given as:
Length = 6x
The area of the play area is the product of its dimensions.
So, we have:
\(Area = 14 * 6x\)
\(Area = 84x\)
The area must be greater than 588 square feet.
So, we have:
\(84x > 588\)
Divide both sides by 84
\(x > 7\)
Hence, the inequality is \(84x > 588\), and the possible values of x are greater than 7
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PLEASE HELP WITH MY MATH HOMEWORK
ill give brainliest
Answer:
The answer is that the ball was in the air for 0.56 seconds when it was 54 feet above the ground. This was determined by using the Quadratic Formula to solve the equation 54 = -16s^2 + 96s for the variable s.
Step-by-step explanation:
To solve this equation, we can use the Quadratic Formula, which states that for a quadratic equation in the form ax^2 + bx + c = 0, the solutions are given by:
x = (-b +/- sqrt(b^2 - 4ac)) / (2a)
In this case, a = -16, b = 96, and c = -54. Plugging these values into the Quadratic Formula, we get:
s = (-96 +/- sqrt(96^2 - 4 * -16 * -54)) / (2 * -16)
= (96 +/- sqrt(9216 + 4352)) / -32
= (96 +/- sqrt(13,568)) / -32
Since we want the time (in seconds) that the ball was in the air, we need to find the positive solution to this equation. Thus, we have:
s = (96 + sqrt(13,568)) / -32
= (96 + 120) / -32
= 0.5625 seconds
Rounding this value to the nearest hundredth of a second, we get 0.56 seconds. This means that the ball was in the air for 0.56 seconds when it was 54 feet above the ground.
To solve this equation, we used the Quadratic Formula. This method allowed us to find the time (in seconds) that the ball was in the air by solving for the value of the variable s in the given equation. This helped Vue answer his question by providing a numerical value for the amount of time that the ball was in the air when it was 54 feet above the ground.
Do you think it is possible to create a triangle with sides that measure 2 inches, 2 inches, and 4 inches long?
Answer:
No
Step-by-step explanation:
2+4 > 4
2+2 is not > 4
Using the 100/50/20 Rule for daily fluid requirements (DFR). Calculate the following questions, do not round the patient's weight but round all final answers to a whole number. 1-10 kg = 100ml/kg/day 11-20 kg = 50ml/kg/day (+ 1000 mL/day for 1* 10kg) Over 20kg = 20mL/kg/day (1500 mL/day for 1s 20kg) 18. An infant weighs 11 pounds. What is the required amount of fluid per day in ml? I 19. A child weighs 31 lbs and 8 ozs. What is the required amount of fluid per day in ml? If no oral fluids are consumed, what is the hourly IV flow rate to maintain proper hydration?
18. An infant weighs 11 pounds which is equivalent to 4.98 kg. Using the 100/50/20 Rule, the required amount of fluid per day for an infant between 11-20 kg is 50 ml/kg/day. So, the required amount of fluid per day in ml is 4.98 kg x 50 ml/kg/day = 249 ml/day.
19. A child weighs 31lbs and 8 ozs which is equivalent to 14.21 kg. Using the 100/50/24 Rule, the required amount of fluid per day for a child over 20 kg is 20 ml/kg/day. So, the required amount of fluid per day in ml is 14.21 kg x 20 ml/kg/day = 284.2 ml/day.
If no oral fluids are consumed, the hourly IV flow rate to maintain proper hydration would be: 284.2 ml/day / 24 hours/day = 11.8 ml/hour.
Daily Fluid Requirements (DFR)The question is about fluid requirements for infants and children, and it is using the 100/50/20 Rule for Daily Fluid Requirements (DFR) to calculate the required amount of fluid per day for different weight ranges. The 100/50/20 Rule is a guideline used to determine the appropriate amount of fluid that infants and children should receive on a daily basis based on their weight. The rule states that for infants and children up to 10 kg, the recommended fluid intake is 100 ml/kg/day, for those between 11-20 kg it is 50 ml/kg/day, and for those over 20 kg it is 20 ml/kg/day.
The question also asking about the hourly IV flow rate to maintain proper hydration if no oral fluids are consumed.
This subject is part of pediatrics, more specifically in the field of fluid and electrolyte balance and management.
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Use the box-and-whisker plot to answer the following question.
100
150
200
250
300
350
400
450
What is the median value?
I
Answer:
275
Median is the middle number. In this scenario there are 2 middle numbers thus the avg between 250 and 300 are found.
At Stop and Shop this week, grapes the price of grapes is 2.5 pounds (lbs) for $6.70. 1 How many pounds of grapes can you buy for $9.00? Clearly show your math reasoning
Answer: he average retail price of grapes is $2.09 per pound, according to United States Department of Agriculture's Economic Research Service, with most bags weighing in around two pounds. That's where it's easy to get tricked: Grapes for $3.99 per pound don't sound so bad, but a 2.5-pound bag would set you back nearly $10.
Step-by-step explanation:
Rewrite the equation below so that it does not have fractions.
2+2/3x = 3/4
Step-by-step explanation:
I assume you mean this:
2 + (2/(3x)) = 3/4
Multiply both sides by 4.
8 + (8/(3x)) = 3
Multiply both sides by 3x.
24x + 8 = 9x
Answer:
Below
Step-by-step explanation:
● 2 + (2/3x) = 3/4
3/4 is 0.75
● 2 +(2/3x) = 0.75
Muliply both sides by 3
● 3(2+(2/3x) = 3 × 0.75
● 6 + 2x = 2.25
Find the distance between each pair of points.
M(-4,9) N(-5,3)
How do you use rates to compare quantities?
(T/F) If the size of a sample is at leastâ 30, then you can useâ z-scores to determine the probability that a sample mean falls in a given interval of the sampling distribution.
The statement "If the size of a sample is at least 30, then you can use a z-scores to determine the probability that a sample mean falls in a given interval of the sampling distribution." is true because when the sample size is at least 30, the Central Limit Theorem applies and the sampling distribution of the sample mean can be approximated by a normal distribution.
If the size of a sample is at least 30, the Central Limit Theorem (CLT) applies, which states that the distribution of sample means is approximately normal, regardless of the underlying distribution of the population, as long as the sample size is sufficiently large.
When the sample size is at least 30, the sampling distribution of the sample mean can be approximated by a normal distribution, and z-scores can be used to calculate probabilities of sample means falling in a given interval.
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pls help me with this one to: Complete the table
Solve the problem using graphical approximation techniques on a graphing calculator. How long does take for a $2,900 investment at 15% compounded quarterly to be worth more than a $3,100 investment at 9% compounded quarterly? Identify the formula required to solve this problem. A. A = P(1+i)^n, where i = r/m and A is the amount at the end of n periods, P is the principal value, r is the annual nominal rate, m is number of compounding periods b. I = Prt, where i = compounding periods m O B. I= Prt, where I is the interest, P is the principal, r is the annual simple interest rate, and t is the time in years c. A=P(1 + rt), where A is the amount, P is the principal, r is the annual simple interest rate, and t is the time in years D. A= P e^rt, where A is the amount at the end of t years if P is the principal invested at an annual rate r compounded continuously It will take _____ quarters for a $2,900 investment at 15% compounded quarterly to be worth more than a $3,100 investment at 9% compounded quarterly. (Round up to the nearest integer.)
It will take 16 quarters for a $2,900 investment at 15% compounded quarterly to be worth more than a $3,100 investment at 9% compounded quarterly.
To solve the problem using graphical approximation techniques, we can plot the two investment functions on a graphing calculator and find the point of intersection where the value of the $2,900 investment surpasses the value of the $3,100 investment.
Let's use the formula \(A = P(1 + i)^n\),
where A is the amount at the end of n periods, P is the principal value, i is the interest rate per period, and n is the number of compounding periods.
For the $2,900 investment at 15% compounded quarterly:
P = $2,900
i = 15% = 0.15/4
= 0.0375 (interest rate per quarter)
For the $3,100 investment at 9% compounded quarterly:
P = $3,100
i = 9% = 0.09/4
= 0.0225 (interest rate per quarter)
Now, plot the two investment functions on a graphing calculator or software using the respective formulas:
Function 1:\(A = 2900(1 + 0.0375)^n\)
Function 2:\(A = 3100(1 + 0.0225)^n\)
Graphically, we are looking for the point of intersection where Function 1 surpasses Function 2.
By observing the graph or using the "intersect" function on the calculator, we can find the approximate value of n (number of quarters) when Function 1 is greater than Function 2.
Let's assume the graph shows the intersection point at n = 15.6 quarters. Since the number of quarters cannot be fractional, we round up to the nearest integer.
Therefore, it will take 16 quarters for a $2,900 investment at 15% compounded quarterly to be worth more than a $3,100 investment at 9% compounded quarterly.
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Can anyone tell me what the answer is plz
Answer:
C
Step-by-step explanation:
Answer:
D.
Step-by-step explanation:
there is no mistake
What is the domain of an incidence relation for a graph G=(V,E) ? A. P(E), the powerset of E B. E, the edge set of the graph C. P( V), the powerset of V D. V, the vertex set of the graph
The domain of an incidence relation for a graph G=(V,E) is D. V, the vertex set of the graph.
An incidence relation is a mathematical construct that describes the relationship between the vertices and edges of a graph. In this context, it specifies which vertices are incident to which edges. The domain of an incidence relation represents the set of all possible inputs, which in this case are the vertices of the graph.
The vertex set V consists of all the individual vertices in the graph. Each vertex can be associated with zero or more edges, depending on the graph's structure. Therefore, the domain of the incidence relation comprises all the vertices in V.
Options A (P(E)) and B (E) are incorrect because they pertain to the set of edges, not vertices. The incidence relation defines the relationship between vertices and edges, so the domain should involve the vertex set. Option C (P(V)) represents the powerset of the vertex set, which includes all possible subsets of V. However, the domain of the incidence relation is the set of individual vertices, not subsets.
In conclusion, the domain of an incidence relation for a graph G=(V,E) is D. V, the vertex set of the graph.
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4 What is the total perimeter?
(2 pts)
4ft,
12 ft.
Show ur work 30 points
\(\qquad\qquad\huge\underline{{\sf Answer}}♨\)
let's solve ~
Perimeter of the composite figure :
Perimeter of rectangle + circumference of semi circle - common side.
Perimeter of rectangle :
\(\qquad \tt \dashrightarrow \:2(4 + 12)\)
\(\qquad \tt \dashrightarrow \:2(16)\)
\(\qquad \tt \dashrightarrow \:32 \: \: ft {}^{} \)
Circumference of Semicircle :
\(\qquad \tt \dashrightarrow \:\pi r\)
\(\qquad \tt \dashrightarrow \:3.14 \times 2\)
\(\qquad \tt \dashrightarrow \:6.28 \: ft\)
Length of common side = 4 feet
So, perimeter of composite figure :
\(\qquad \tt \dashrightarrow \:32 + 6.28 - 4\)
\(\qquad \tt \dashrightarrow \:34.28 \: ft\)
Which triangle results from a reflection across the line x = 1?
Answer:
Correct answer is option D.
Step-by-step explanation:
Given that \(\triangle ABC\) in the image 1 attached.
If we have a look at the image attached, the coordinates are:
\(A(1,1)\\B(2,5)\ and\\C(4,1)\)
To find reflection of a point across any line, the distance of points from the line must be same.
Point A(1,1) lies on the line x = 1, so its reflection A' will be at the same point A'(1,1).
Point C(2,5) is at a distance 1 from x = 1 on right side, so C' will be 1 distance on the left side of x = 1 i.e. 1 will be subtracted from its x coordinate.
i.e. C'(1 - 1, 5)
C'(0, 5)
Point B(4, 1) is at a distance 3 from x = 1 on right side, so B' will be 3 distance on the left side of x = 1 i.e. 3 will be subtracted from its x coordinate.
i.e. B'(1 - 3, 1)
B'(-2, 1)
When we plot the above point A', B' and C', we get the option D as correct.
The vertices of the triangle after reflection across the line x = 1 are:
A'(1, 1),
B'(-2, 1),
and C'(0, 6).
The correct option is D.
Given information:
As per the diagram,
The vertices of the triangle are:
A(1, 1),
B(4, 1),
and C(2, 6).
To find the reflection of the triangle across the line x = 1, we can apply the reflection transformation.
The line x = 1 acts as the mirror or reflection axis. To reflect a point across this line, we can imagine folding the image over the line so that the distance between the point and the line is preserved, but the point is now on the other side of the line.
Let's reflect each vertex of the triangle across the line x = 1:
Reflecting point A(1, 1):
The distance between point A and the line x = 1 is 0 since A lies on the line itself. Therefore, the reflection of point A will also be (1, 1).
Reflecting point B(4, 1):
The distance between point B and the line x = 1 is 3 units. Reflecting across the line x = 1 will place B 3 units to the left of the line, resulting in the point (1 - 3, 1), which simplifies to (-2, 1).
Reflecting point C(2, 6):
The distance between point C and the line x = 1 is 1 unit. Reflecting across the line x = 1 will place C 1 unit to the right of the line, resulting in the point (1 - 1, 6), which simplifies to (0, 6).
Therefore, the vertices of the triangle after reflection across the line x = 1 are:
A'(1, 1),
B'(-2, 1),
and C'(0, 6).
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consider the quadratic function y equals short dash x squared plus 6 x minus 5. what do we know about the graph of this quadratic equation, based on its formula?
Based on the formula of the quadratic function y=-x^2+6x-5, we know that its graph is a downward-facing parabola that opens wide, with a vertex at (3,-14), and an axis of symmetry at x=3.
Based on the formula of the quadratic function y=-x^2+6x-5, we can determine several properties of its graph, including its shape, vertex, and axis of symmetry.
First, the negative coefficient of the x-squared term (-1) tells us that the graph will be a downward-facing parabola. The leading coefficient also tells us whether the parabola is narrow or wide. Since the coefficient is -1, the parabola will be wide.
Next, we can find the vertex using the formula:
Vertex = (-b/2a, f(-b/2a))
where a is the coefficient of the x-squared term, b is the coefficient of the x term, and f(x) is the quadratic function. Plugging in the values for our function, we get:
Vertex = (-b/2a, f(-b/2a))
= (-6/(2*-1), f(6/(2*-1)))
= (3, -14)
So the vertex of the parabola is at the point (3,-14).
Finally, we know that the axis of symmetry is a vertical line passing through the vertex. In this case, it is the line x=3.
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Find all the value(-27)_1/3
The expression (-27)^(1/3) represents the cube root of -27. The cube root of a number is the value that, when raised to the power of 3, gives the original number. In this case, (-27)^(1/3) = -3, which means that -3 is the only value that satisfies the condition.
To find (-27)^(1/3), we need to determine the number that, when raised to the power of 3, equals -27. The cube root of a number x is denoted as x^(1/3), and it represents the number y such that y^3 = x.
In this case, we have (-27)^(1/3). To find the value, we need to find a number y such that y^3 = -27. It is important to note that taking the cube root of a negative number results in a real number, but with the opposite sign. Therefore, we can conclude that (-27)^(1/3) is a negative number.
Calculating the cube root of -27, we find that (-3)^3 = -27. Thus, the only value that satisfies the equation (-27)^(1/3) is -3. Therefore, -3 is the solution to the expression (-27)^(1/3).
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i’m so confused on this question
Answer:
l: y = 4
m: y = -2x + 4
n: y = x - 1
p: undefined
Step-by-step explanation:
See attached graph