The reaction A →B+C was carried out in a constant-volume batch reactor where the following concentration measurements were recorded as a function of time. t (min) 0 5 9 15 22 30 40 60 CA (mol/dm3) 2 1.6 1.35 1.1 0.87 0.70 0.53 0.35 (a) Use nonlinear least squares (i.e., regression) and one other method to determine the reaction order, a, and the specific reaction rate, k.

Answer:

modern vehicles are made to crunch up a little bit so they that absorbe some of the impact instead of you

Explanation:

It is not safe to operate the motor with a 10-hp shaft load.

Explanation :
Solution-
First, determine the rated speed and current of the motor:
Rated speed = 850 r/min
Rated current = 500 V / (0.1414 ohms + 0.0412 ohms + 0.0189 ohms) = 30.22 A
Next, determine the speed and current for a 10-hp shaft load:
Speed = 1700 r/min
Current = 10 hp / (75 hp * 0.902) = 0.1343 A
Finally, determine whether it is safe to operate the motor with the 10-hp shaft load using the magnetization curve. we can see that the current at 1700 r/min is 0.1264 A, which is less than the current for the 10-hp shaft load (0.1343 A).

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Answer:

Hydrostatic force = 41168 N

Explanation:

Complete question

A triangular plate with a base 5 ft and altitude 3 ft is submerged vertically in water  so that the top is 4 ft below the surface. If the base is in the surface of water, find the force against onr side of the plate. Express the hydrostatic force against one side of the plate as an integral and evaluate it. (Recall that the weight density of water is 62.5 lb/ft3.)

Let "x" be the side length submerged in water.

Then

w(x)/base = (4+3-x)/altitude

w(x)/5 = (4+3-x)/3

w(x) = 5* (7-x)/3

Hydrostatic force = 62.5 integration of  x * 4 * (10-x)/3 with limits from 4 to 7

HF = integration of 40x - 4x^2/3

HF = 20x^2 - 4x^3/9 with limit 4 to 7

HF = (20*7^2 - 4*7^(3/9))- (20*4^2 - 4*4^(3/9))

HF = 658.69 N *62.5 = 41168 N

Answer:

int()

Explanation:

float() is using decimals, so that can't be it, like float(input( "how much does this cost?"))

print() is used to print something, not a user asking, like print("hello")

string() means like a whole, like string( I am good)

By elimination, int() is correct.

Hope this helps!

Answer:

required flow rate is 75.44 gal/min  

Explanation:

Given the data in the question;

Power developed = 250 psi = 1.724 × 10⁶ Pa

hydraulic power W = 11 hp = 11 × 746 = 8206 Watt

now, Applying the formula for pump power

W = pgQμ

where p is density of fluid, Q is flow rate, μ is heat and W is power developed;

W = pgQμ

W = pgμ × Q  

W = P × Q -------- let this be equ 1

so we substitute in our values;

8.2027 kW = 1.724 × 10⁶ Pa × Q

Q = 8206 / 1.724 × 10⁶

Q = 4.75986 × 10⁻³ m³/sec

We know that, 1 cubic meter per seconds = 15850.3 US liquid gallon per minute, so

Q = 4.75986 × 10⁻³  × 15850.3 gallon/min

Q = 75.44 gal/min    

Therefore, required flow rate is 75.44 gal/min    

Answer:

B: Team has the ball near center line

Explanation:

i guessed so...

If the siding is fastened to the studs through the sheathing, the International Residential Code prescribes 3/8-inch plywood for sheathing walls with a typical stud spacing of 16 inches.

The minimum plywood thickness required by the IRC is 1/2 inch if the nails only go through the sheathing and not through the studs.

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Answer: Increase in minimills

Explanation:

The formula for calculating gear speed is: (rpm of the driving gear * number of teeth on the driving gear) / number of teeth on the driven gear.

To calculate the speed of the spur gear, we can use the gear ratio formula, which is gear ratio = number of teeth on driven gear (spur gear) / number of teeth on driving gear (pinion gear).

In this case, the gear ratio is 42/14 = 3.

Next, we can use the formula for gear speed, which is gear speed = pinion gear speed / gear ratio.

Since the pinion gear is turning at 420 rpm, the gear speed of the spur gear is:

gear speed = 420 rpm / 3 = 140 rpm.

Therefore, the speed of the spur gear with 42 teeth driven by a pinion gear with 14 teeth turning at 420 rpm is 140 rpm.

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Answer:

the range of length scales is ( 0.0602 -  0.1094 )

Explanation:  

  Given the data in the question;

\(P_{absolute\) = 1300 kPa

V\(_{prototype\) = 406 km/h

speed of model nit more than 29%

we know that Reynolds number Re = pVl/μ = constant

p\(_m\)V\(_m\)l\(_m\)/μ\(_m\) = pVl/μ  

such that;

l\(_m\)/l = ( p/p\(_m\) )( V/V\(_m\) )( μ\(_m\)/μ )  ----- let this be equation 1

Now, for an idea gas; P = pRT { with constant temperature }

p / p = constant; p/p\(_m\) = p/p\(_m\)  

assuming μ\(_m\) = μ\(_m\)  

Therefore, the relation becomes;

l\(_m\)/l = ( p/p\(_m\) )( V/V\(_m\) )

from the given data;

l\(_m\)/l = ( 101/1300 )( V/V\(_m\) )

where our V\(_m\) = ( 1 ± 29% )V

so

l\(_m\)/l = ( 101/1300 )( V / ( 1 ± 29% )V )

l\(_m\)/l = ( 101/1300 )( 1 / ( 1 ± 0.29  ) )

Now, The minimum limit will be;

l\(_m\)/l = ( 101/1300 )( 1 / ( 1 + 0.29  ) )

= ( 101/1300 ) × ( 1 / 1.29 )

= 0.0602

The maximum limit will be;

l\(_m\)/l = ( 101/1300 )( 1 / ( 1 - 0.29  ) )

= ( 101/1300 ) × ( 1 / 0.71 )

= 0.1094

Therefore, the range of length scales is ( 0.0602 -  0.1094 )

When the string of a helium balloon slips from your hand and rises into the air, the balloon rises until it reaches an altitude where its weight equals that of the same volume of air.

When a helium balloon is released, it rises until it reaches an altitude where its weight equals that of the same volume of air. This is due to the principle of buoyancy.

Helium gas is lighter than air, which causes the balloon to initially ascend. As the balloon rises, the surrounding air pressure decreases, and so does the density of the air. Eventually, the balloon reaches an altitude where the density of the surrounding air matches the density of the helium-filled balloon.

At this point, the upward buoyant force acting on the balloon becomes equal to the downward gravitational force (weight) acting on the balloon. This balance of forces causes the balloon to stop rising further and instead float at a relatively stable altitude.

Option c) accurately describes this behavior, where the balloon rises until it reaches an altitude where its weight equals that of the same volume of air.

The question should be:

The string of a helium balloon slips from your hand and rises into the air. when this happens

a) the balloon rises indefinitely because helium is lighter than air

b) the balloon rises until it reaches an altitude where the air and helium densities are equal.

c) the balloon rises until it reaches an altitude where its weight equals that of the same volume of air

d) the balloon rises continually but slows down to the effect of viscosity

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A person looking off to the right side of the frame is an example of an index vector type. Option C is answer.

In film and photography, vectors refer to the direction of a person or object's movement or gaze. The index vector type indicates where a person or object is looking or moving towards in the frame. In this case, the person looking off to the right side of the frame is an example of an index vector type because their gaze is pointing towards a specific direction in the frame. The other two vector types are motion and graphic, which refer to the movement and shape of objects in the frame, respectively.

Option C is answer.

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Answer:

C

Explanation: Freedmens Bureau provided resources for southerners and newly freed slaves

The work done on the gas during the isothermal compression is approximately 6472.096 Joules.

To determine the work done on the gas during an isothermal compression, we can use the formula:

Work = -nRT ln(V2/V1)

Where:

- Work is the work done on the gas

- n is the number of moles of the gas

- R is the ideal gas constant (8.314 J/(mol·K))

- T is the temperature (in Kelvin)

- V1 is the initial volume of the gas

- V2 is the final volume of the gas

In this case, we have:

- n = 2 moles

- R = 8.314 J/(mol·K)

- T = 300 K

- P1 = 1 bar

- P2 = 5 bar

Since the process is isothermal, we can use the ideal gas law to find the initial and final volumes:

V1 = (nRT1) / P1

V2 = (nRT2) / P2

Substituting the given values:

V1 = (2 * 8.314 * 300) / 1 = 4988.4 cm³

V2 = (2 * 8.314 * 300) / 5 = 997.68 cm³

Now we can calculate the work done on the gas:

Work = -nRT ln(V2/V1)

    = -2 * 8.314 * 300 * ln(997.68/4988.4)

Using a calculator or software to evaluate the natural logarithm, we find:

Work ≈ -2 * 8.314 * 300 * (-1.09861)

      ≈ 6472.096 J

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With a Sync recipe, these visual recipes cannot be used to limit the project's datasets to the years 2008-2012.

The "sync" recipe permits you to synchronize one dataset to another. Global or partition-specific synchronization are options. Copying a dataset between storage backends where different computations are possible is one major use case for the sync recipe. For instance:

transferring a file dataset to a SQL database for effective querying; transferring a SQL dataset to HDFS for use in Hive recipes; transferring a HDFS dataset to ElasticSearch for use in queries.

The transformation steps, or processing logic, that affect datasets or folders are contained in Dataiku recipes. They are symbolized by circles connecting the input and output datasets or folders in the Flow.

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In contrast to mobile work zones, stationary work zones have clearly defined boundaries.

According to the 2009 edition of the Manual on Uniform Traffic Control Devices (MUTCD), a short-term stationary work zone is "daytime work that occupies a location for more than one hour within a single daylight period."

The following are typical daytime work shift-length tasks:

paving the road, fixing broken underground water lines, fixing storm water catch basins, trimming trees along the road, and parking work vehicles for a long time on the side of the road. The minimum traffic control planning and devices that are required to safely direct motorists, bicyclists, and pedestrians around workers and work vehicles during daylight hours will be discussed in this bulletin. Night operations necessitate additional equipment and planning, which is not the subject of this bulletin.

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Answer:

Yes, it is true.

Where are your answer options?

Answer:

Implement a hazard communication program

Explanation: i took the quiz

Answer:

The heat flow in 24 hours through the refrigerator door is approximately 1,608.57 BTU

Explanation:

The given parameters are;

The duration of the heat transfer, t = 24 hours = 86,400 seconds

The area of the refrigerator door, A = 30.0" × 58.0" = 1,740 in.² = 1.122578 m²

The material of the insulator in the door = Cellulose fiber

The thickness of the insulator in the door, d = 2.0" = 0.0508 m

The temperature inside the fridge = 38° F = 276.4833 K

The temperature of the room = 78°F = 298.7056 K

The thermal conductivity of cellulose fiber = 0.040 W/(m·K)

By Fourier's law, the heat flow through a by conduction material is given by the following formula;

\(\dfrac{Q}{t} = \dfrac{k \cdot A \cdot (T_2 - T_1) }{d}\)

\(Q = \dfrac{k \cdot A \cdot (T_2 - T_1) }{d} \times t\)

Therefore, we have;

\(Q = \dfrac{0.04 \times 1.122578 \times (298.7056 - 276.4833 ) }{0.0508} \times 86,400 =1,697,131.73522\)

The heat flow in 24 hours through the refrigerator door, Q = 1,697,131.73522 J = 1,608.5705140685 BTU

or...................

Answer:

i believe it is true

Explanation:

Some network switches have a feature called Dynamic ARP Inspection (DAI) that can be used to detect faked ARP messages. DAI helps protect the network by validating ARP packets and ensuring the content loaded in them is accurate and legitimate.

On some network switches, a function known as "content loaded" can be used to recognise false ARP messages. With the use of this functionality, the switch can check for any anomalies or discrepancies in the contents of packets that are going through it, including ARP messages, that might point to a phoney or malicious message. The switch can protect the network's security and integrity by employing this capability to assist stop ARP spoofing attacks.In a network, Address Resolution Protocol (ARP) packets are verified by Dynamic ARP Inspection (DAI), a security feature. A network administrator can intercept, log, and delete ARP messages that have faulty MAC address to IP address bindings using DAI. With this feature, the network is shielded against some "man-in-the-middle" assaults.

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Modern cars' complex systems perform all the foregoing functions, with the exception of assisting in the preservation of resale value.

Therefore, the answer is "helping retain resale value".

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Answer:

represnt

Explanation: