The radius of the Earth RE=6.378×10⁶m and the acceleration due to gravity at its surface is 9.81 m/s². a) Calculate the altitude above the surface of Earth, in meters, at which the acceleration due to gravity is g=2.6 m/s².

Answers

Answer 1

Answer: The altitude is 3.29 × 106 m below the surface of Earth.

The radius of the Earth RE=6.378×10⁶m

acceleration due to gravity at its surface is 9.81 m/s². The expression that relates the acceleration due to gravity with the distance from the center of Earth is given by:

g = (GM)/r²

Where g is the acceleration due to gravity, G is the universal gravitational constant (6.67 × 10-11 Nm²/kg²), M is the mass of Earth, and r is the distance from the center of Earth.

We can solve for r to find the distance from the center of Earth at which the acceleration due to gravity is 2.6 m/s²:

g = (GM)/r²r²

= GM/g

Let's plug in the given values to solve for r:

r² = (6.67 × 10-11 Nm²/kg² × 5.97 × 1024 kg)/(2.6 m/s²)

r² = 9.56 × 1012 m²

r = 3.09 × 106 m.

Now we can find the altitude above the surface of Earth by subtracting the radius of Earth from r:

Altitude = r - RE

Altitude = 3.09 × 106 m - 6.378 × 106 m.

Altitude = -3.29 × 106 m.

This is a negative value, which means that the acceleration due to gravity of 2.6 m/s² is found at a distance below the surface of Earth.

So, the altitude is 3.29 × 106 m below the surface of Earth.

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Related Questions

A transformer has a primary coil with 20 turns, and a secondary coil with 2000 turns. The
input voltage is 120 V, and it runs at 1800 W.

What is the transformer's power? :

A) 1000 W

B) 1800 W

C) 1200 W

D) 1500 W

Answers

A secondary and primary coil are present in a transformer. The transformer's power is 1800 V.

What is Transformer?

Primary coil turn = NP= 200

Secondary coil turn= 2000 turn.

Input voltage = 120 V

Input power = 1800 W.

Pi = Vi I i

1800 = 120 Vi

Ii = 15 A

Vs = 2000/ 200 * 120

    = 1200 V

Transformers work by inducing current in a second coil known as the secondary as the magnetic lines of force (flux lines) build up and contract in response to variations in current flowing through the primary coil.

IS/ Ii = NP/NS =

IS= 1.5 Ampere

Power = VI= 1200*1.5 = 1800 V.

Therefore, A secondary and primary coil are present in a transformer. The transformer's power is 1800 V.

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The ice record shows a period in Earth's history when there was an ice age and the global average temperature was much colder. During this time, the ice record shows the amount of carbon dioxide in the atmosphere decreased, but the

amount of energy from the sun did not change. How did the total amount of energy in the Earth system change, how did

this change happen, and how did it contribute to the ice age?

Answers

During the ice age, the total amount of energy in the Earth system decreased due to changes in orbital parameters (Milankovitch cycles), redistributing solar energy, while atmospheric CO2 levels decreased as a feedback mechanism, amplifying the cooling effect.

During the ice age, how did the total amount of energy in the Earth system change, how did this change happen, and how did it contribute to the ice age?

During the ice age, the total amount of energy in the Earth system decreased. This change occurred primarily due to changes in Earth's orbital parameters known as Milankovitch cycles. These cycles affect the distribution and intensity of solar radiation reaching the Earth's surface.

Milankovitch cycles involve variations in the Earth's eccentricity, axial tilt, and precession. These variations lead to changes in the amount and distribution of solar energy received by different parts of the Earth over long periods. However, it's important to note that the total amount of energy from the Sun did not change during the ice age.

The decrease in the total amount of energy in the Earth system resulted from the redistribution of solar energy due to Milankovitch cycles. These variations caused changes in the Earth's climate system, including the redistribution of heat through changes in the intensity and seasonality of sunlight.

The ice age was primarily triggered by a combination of Milankovitch cycles and the resulting changes in the Earth's climate. As solar radiation distribution shifted, it influenced temperature gradients and altered atmospheric circulation patterns. This led to changes in precipitation patterns and the formation of large ice sheets in regions where snowfall exceeded melting.

The decrease in atmospheric carbon dioxide (CO2) levels observed in the ice record during the ice age was a feedback mechanism rather than a direct cause. As the climate cooled, the capacity of cold water to dissolve and retain CO2 increased, leading to its absorption by the oceans. This caused a decrease in atmospheric CO2 levels, further amplifying the cooling effect.

In summary, the ice age was primarily caused by variations in Earth's orbital parameters (Milankovitch cycles), resulting in a redistribution of solar energy and changes in climate. The decrease in the total amount of energy in the Earth system was a consequence of these changes, while the decrease in atmospheric CO2 levels acted as a feedback mechanism, reinforcing the cooling effect.

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Which of these statements about electromagnetic waves is incorrect?

Answers

Answer:

The statement that "electromagnetic waves require a medium to travel through" is incorrect. Electromagnetic waves do not require a medium to travel through and can propagate through a vacuum. This was one of the key insights of James Clerk Maxwell's theory of electromagnetism.

EM waves form when energy is transferred through the field is incorrect

Please help me I have physics tomorrow and im so confused ​

Please help me I have physics tomorrow and im so confused

Answers

Answer:

trust the process

Explanation:

quadratic formula, use synthetic division also use the p-q method for the roots and factoring.

Have All existing elements have been discovered

Answers

Answer:

Not not all of the elements have been discovered.

g a 7-ft-diameter spherical tank completely submerged in freshwater is being towed by a ship at 11 ft/s. assuming turbulent flow, determine the required towing power. the drag coefficient for a sphere is cd

Answers

The required towing power for the 7-ft-diameter spherical tank completely submerged in freshwater being towed by a ship at 11 ft/s is 554.5 W.

To determine the required towing power, first we need to calculate the drag force acting on the tank. The drag force can be calculated using the drag equation, which states that the drag force is proportional to the velocity squared, the density of the fluid, the area of the object, and the drag coefficient.

Once we have the drag force, we can then calculate the power required to tow the tank at a constant speed of 11 ft/s. This power is simply the product of the drag force and the towing velocity.

The drag coefficient for a sphere is a dimensionless quantity that depends on the Reynolds number of the flow and the surface roughness of the sphere. For turbulent flow, the drag coefficient for a sphere is approximately 0.47. We can use this value to calculate the drag force and the required towing power.

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What do vibrations create?
A.sound waves
B.electricity
C.wavelengths
D.energy

Answers

Answer:

Sound

Explanation:

Answer:

When an object vibrates, it creates kinetic energy that is transmitted by molecules in the medium. As the vibrating sound wave comes in contact with air particles passes its kinetic energy to nearby molecules. As these energized molecules begin to move, they energize other molecules that repeat the process.

Explanation:

So sound waves

two similar conducting spheres are separated by a distance d. one sphere carries charge q and the other carries -q. they each feel an attractive force f. if two third of the charge on the negative sphere is transferred to the positive sphere, what is the magnitude of the new attractive force?

Answers

Using Coulomb's law again, the new attractive force between the spheres can be calculated as F' = k(q + 2q/3)(2q/3)/d² = 4kq²/9d². Therefore, the magnitude of the new attractive force is 4/9 times the initial force.

When two conducting spheres are separated by a distance d and carry opposite charges, they experience an attractive force due to their electrostatic interaction. The magnitude of this force is given by Coulomb's law, which states that the force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them.

In this case, the initial attractive force between the two spheres is F = kq²/d², where k is the Coulomb constant. If two-thirds of the charge on the negative sphere is transferred to the positive sphere, the new charges on the spheres will be q + 2q/3 and -2q/3, respectively. The net charge on the system remains q - 2q/3 = q/3.

Using Coulomb's law again, the new attractive force between the spheres can be calculated as F' = k(q + 2q/3)(2q/3)/d² = 4kq²/9d². Therefore, the magnitude of the new attractive force is 4/9 times the initial force.

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Describe the relationship between a moving object's mass and its kinetic energy.

Answers

Answer:

\(E=\dfrac{1}{2}mv^2\)

Explanation:

If m is the mass of the object and v is the velocity of the object. The kinetic energy is due to the motion of an object. It is given by the relation as follows :

\(E=\dfrac{1}{2}mv^2\)

The above formula is used to find the kinetic energy of an object.

A car can accelerate from rest to a speed of 28 m/s in 20 s. What is the average acceleration of the car

Answers

Formula for acceleration:

\(a=\dfrac{V^f-V^I}{t}\)

acceleration(measured in m/s^2) = Final velocity(measured in m/s) - Initial velocity(measured in m/s) / time(measured in seconds)

__________________________________________________________

Given:

\(V^I=0m/s\) (rest)

\(V^f=28m/s\)

\(t=20s\)

\(a=?\)

__________________________________________________________

Finding acceleration:

\(a=\dfrac{V^f-V^I}{t}\)

\(a=\dfrac{28-0}{20}\)

__________________________________________________________

Answer:

\(\boxed{a=1.4m/s^2}\)

find the weight of an astronaut whose mass is 75 kg on the moon

Answers

The formula for weight is always weight=mass X gravitational field strength.
We already know the mass is 75kg.
The gravitational field strength on the moon is 1.6N. To find out the weight, we can substitute these values in to the formula.
Weight=75 X 1.6
Weight= 120N
Weight is measured on Neutons as it is a force.

5. the location and gimbal limits of the flir sensor prevent the p* from seeing the terrain directly beneath the aircraft. what must the p* do prior to conducting a landing from a hover?

Answers

Your ability to land safely is the primary prerequisite in order to protect your passengers and people on the ground.

Explain about the gimbal?

In the same way as a tripod would if you were shooting a picture or remained in one place while taking it, a gimbal employs sensors and motors to stabilize and support your camera.

The majority of contemporary rockets, including the Space Shuttle and the Saturn V moon rocket, employ a technique known as gimbaled thrust. The rocket's exhaust nozzle can be moved in either direction when using a gimbaled thrust system. In relation to the rocket's centre of gravity, the thrust direction changes when the nozzle is moved.

When using Euler angles in applied mathematics, the gimbal lock problem arises; creators of 3D computer programmes, such as 3D modelling, embedded navigation systems, and video games, must take care to avoid it.

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A plane takes off at an angle of 30 degrees at a speed of 150 km/h. Determine the horizontal
and vertical components of this velocity vector.

Answers

Answer:

Horizontal Component = 129.9 km/h

Vertical Component = 75 km/h

Explanation:

When a vector is resolved on the x-axis and the y-axis, the components so formed are called its rectangular components. The component along y-axis is called the vertical component and the component along x-axis is called horizontal component. These components can be given by following formulae:

Horizontal Component = v Cos θ

Vertical Component = v Sin θ

where,

v = velocity = 150 km/h

θ =  angle = 30°

Therefore,

Horizontal Component = (150 km/h)(Cos 30°)

Horizontal Component = 129.9 km/h

Vertical Component = (150 km/h)(Sin 30°)

Vertical Component = 75 km/h

An object is launched from the base of an incline, which is at an angle of 30° If the launch angle is 60° from the horizontal and launch speed is 10m/s. What is the total flight time ?​

Answers

Answer:

4.6 s, because that is the time for the object to reach the top of the incline.

Explanation:
that at the top of the incline, the horizontal velocity will be equal to the launch velocity, because there is no longer any force acting on the object in the horizontal direction. The only force acting on the object is gravity, which is acting in the vertical direction. So the only velocity that will be changing is the vertical velocity. The vertical velocity will be changing because of the force of gravity, which is 9.8 m/s2. The equation for the vertical velocity is: vf = vi + a*t, where vf is the final velocity, vi is the initial velocity, a is the acceleration and t is the time. The final velocity in this case is 0 m/s, because the object has reached the top of the incline and is no longer moving in the vertical direction. The initial velocity is 10 m/s, because that is the launch velocity. The acceleration is 9.8 m/s2, because that is the force of gravity. So when you plug all of those values into the equation, you get: 0 = 10 + 9.8*t and you solve for t and you get t = 4.6 s.

Which describes the results of the double slit experiment? select 2 options. waves produced a diffraction pattern. results supported the wave theory of light. results demonstrated the relationship between electric and magnetic fields. beams of light separated as they passed through a prism. results supported the particle theory of light.

Answers

The results of young's double-slit experiment were

- Waves produced a diffraction pattern.

- Results supported the wave theory of light.

- Results supported the particle theory of light

Two coherent sources of light are employed in Young's double-slit experiment, which is often conducted at a distance that is only a few times greater than the wavelength of the light used. Young's double-slit experiment contributed to our knowledge of the diagrammed wave theory of light.

The act of bending of the light around edges such that it expands out and illuminates regions, where a shadow is anticipated, is known as the diffraction of light. In general, since both occur simultaneously, it is challenging to distinguish between diffraction and interference.

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Answer: A,B,E.

Explanation: doing the quiz on edge!

A 4.0 cm tall light bulb is placed a distance of 35.5 cm from a
convex mirror with a focal length of -12.2 cm. The image distance is determined to be -9.1 cm. What is the image size?
a 3.12 cm
b 5.78 cm
C 7.23 cm
d 1.02 cm

Answers

Answer:

D

Explanation:

Answer:

Image distance () = - 9.08 cm

Image height () = 1.02 cm

Given: (object distance) , (object height) , (focal length)

Required: image distance () and image size ()

Equations:

Eqn 01:  (mirror equation)

Eqn 02:  (magnification equation)

Solution:

Solving for the image distance:

Solving for the image height / size:

there are 3 significant figures (35.5 is 3, 4.00 is 3,  -12.2 is 3),  therefore,

Answer:

Image distance () = - 9.08 cm

Image height () = 1.02 cm

20 m
A projectile is fired from the origin (at y = 0 m) as shown in the diagram. The initial velocity components are Vox = 310 m's and Vov = 26 m s The
projectile reaches maximum height at point P. then it falls and strikes the ground at point Q which is 20 m below the launch point. What is the horizontal
distance that the projectile travels (labeled x in the diagram)?
O 1.3 km
700 m
O 32 km
O 870 m
O 1.9 km​

Answers

Answer:

  1.9 km​

Explanation:

The equation for vertical motion is ...

  h(t) = -4.9t^2 +26t +20

This will have a zero near t = 5.988 seconds.*

The horizontal distance traveled in that time is ...

  (310 m/s)(5.988 s) ≈ 1856 m ≈ 1.9 km

_____

* The root of a quadratic can be found numerous ways. We choose the quick and easy: let a graphing calculator show it to you.

20 mA projectile is fired from the origin (at y = 0 m) as shown in the diagram. The initial velocity

how does the hypothesis of inflation account for the existence of the seed of density from which galaxies and other large structures formed

Answers

Inflation would have caused random, microscopic quantum fluctuations to grow so large in size that they became the seeds of structure.

true or false: the effective resistance of two series resistors is always greater than that of either resistor.

Answers

The statement 'The effective resistance of two series resistors is always greater than that of either resistor' is true.

The effective resistance of two series resistors is the sum of their individual resistances. When two resistors are connected in series, the current flowing through both of them is the same, but the voltage across each resistor is different, depending on its resistance.

Since the voltage drop across each resistor is proportional to its resistance, the larger resistor will have a larger voltage drop. Therefore, the effective resistance of the two series resistors will be greater than that of either resistor alone.

When resistors are connected in series, their effective resistance (or total resistance) is the sum of their individual resistances. Since both resistors have positive resistance values, the total resistance will always be greater than the resistance of either individual resistor.

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Sean, who has a mass of 65-kg, is out roller blading with friends at a speed of 3 m/s. Not realizing he accidentally let the dog out as he was leaving, Sean finds his 12-kg pup at rest in the middle of the street. Sean gracefully scoops the dog up as he skates down the road and proceeds to carry the pup home. Calculate their final velocity.

Velocity: _ m/s

Answers

Answer:

2.53m/s

Explanation:

Initial momentum in a system= Final momentum in a system

65kg*3m/s+12kg*0m/s=(65kg+12kg)*v

195kgm/s=77kg*v

v=2.53m/s

Two infinite sheets of current flow parallel to the y-z plane. The left-hand sheet, which intersects the x-axis at x = 0, consists of an infinite array of wires parallel to the z-axis with a density n = 910 wires/m and a current per wire of IL = 0.17 A in the +z direction. The right-hand sheet, which intersects the x-axis at x = a = 12 cm, is identical to the left-hand sheet, except that it has a current per wire of IR = 0.17 A in the -z direction.
a) Calculate the y-components of the net magnetic field in the following places: x1 = -15 cm, x2 = 6 cm, and x3 = 24 cm. (The x- and z-components of the B-field are zero.)
B(x1)y = T
B(x2)y = T
B(x3)y = T
b) Suppose the above configuration of currents is unchanged except that the direction of the current IR is reversed so that now IR also flows in the +z direction. (The magnitude remains the same.) Calculate the y-components of the net magnetic field at the same positions as in part a).
B(x1)y = T
B(x2)y = T
B(x3)y = T
c) Return to the configuration of part a). Suppose you want to have the region 0 < x < a able to confine electrons (qe- = -1.60 x 10-19 C, me- = 9.11 x 10-31 kg) that have been accelerated from rest through a 66 V electrostatic potential. If the electrons are to be stacked in circular orbits parallel to the x-z plane with centers on the plane x = a/2, what is the minimum current per wire required if IL and IR are equal in magnitude but opposite in direction?
IL = A

Answers

Two infinite sheets of current flow parallel to the y-z plane. The left-hand sheet, which intersects the x-axis at x = 0, consists of an infinite array of wires parallel to the z-axis with a density of n = 910 wires/m and current per wire of IL = 0.14 A in the +zdirection.

The right-hand sheet, which intersects the x-axis at x = a = 12 cm, is identical to the left-hand sheet, except that it has a current per wire of IR = 0.14 A in the -z-direction.

(a) Calculate the y-components of the net magnetic field in the following places:

x1 = -15 cm, x2 =6 cm, and x3 = 24 cm. (The x- and z-components of the B-field are zero.)

B(x1)y = T

B(x2)y = T

B(x3)y = T

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Two infinite sheets of current flow parallel to the y-z plane. The left-hand sheet, which intersects
Two infinite sheets of current flow parallel to the y-z plane. The left-hand sheet, which intersects

A ball is rolled twice across the same level laboratory table and allowed to roll off
the table and strike the floor. In each trial, the time it takes the ball to travel from the
edge of the table to the floor is accurately measured. [Neglect friction.]
a) In trial A, the ball is traveling at 2.50 meters per second when it reaches
the edge of the table. The ball strikes the floor 0.391 second after rolling
off the edge of the table. Calculate the height of the table. (Organize your
given variables. Do not mix x-variables with the y-variables)

Answers

Answer:

Explanation:

To calculate the height of the table in this scenario, we can use the equations of motion. Let's define the variables first:

Initial velocity (u) = 2.50 m/s (given)

Time taken to reach the floor (t) = 0.391 s (given)

Acceleration due to gravity (g) = 9.8 m/s² (assuming the ball falls freely near the surface of the Earth)

Now, we can use the kinematic equation:

h = u * t + (1/2) * g * t²

Plugging in the given values, we have:

h = (2.50 m/s) * (0.391 s) + (1/2) * (9.8 m/s²) * (0.391 s)²

Simplifying the equation:

h = 0.97875 m + 0.07511 m

h = 1.05386 m

Therefore, the height of the table is approximately 1.05386 meters.

how does one adjust fuel and design parameters to efficiently create a small rocket that attains a maximum vertical launch?

Answers

To efficiently create a small rocket that attains a maximum vertical launch,  design parametres are ; desired altitude,Choose the right fuel, Calculate fuel amount,Optimize the rocket's mass,

1. Determine the desired altitude: Set a target altitude for the rocket's maximum vertical launch. This will help you choose appropriate fuel and design parameters.

2. Choose the right fuel: Research various types of rocket fuels to find the one with the best performance and efficiency for your rocket size. Consider factors such as energy density, specific impulse, and burn rate.

3. Calculate fuel amount: Use the rocket equation and your chosen fuel's specific impulse to determine the required fuel mass to reach the target altitude.

4. Optimize the rocket's mass: Design the rocket's structure to minimize its mass while maintaining strength and stability. Use lightweight materials and consider trade-offs between mass and other design parameters.

5. Design the nozzle: Adjust the nozzle's design parameters, such as throat diameter and expansion ratio, to maximize thrust and optimize the exhaust velocity for your specific fuel and altitude.

6. Optimize the stability: Design the rocket's fins and placement of the center of mass to ensure stability during the vertical launch. Proper stability will help the rocket maintain its desired trajectory.

7. Test and iterate: Perform tests on your rocket to measure its performance and make any necessary adjustments to the fuel and design parameters to improve its efficiency and achieve the maximum vertical launch.

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A transformer for a laptop computer converts a 220-V input to a 10-V output. Write down the equations that show that the primary coil has twenty two times as many turns as the secondary coil.

Answers

The transformer operates based on the principle of electromagnetic induction this equation shows that the primary coil has twenty-two times as many turns as the secondary coil.

Let's denote the number of turns in the primary coil as Np and the number of turns in the secondary coil as Ns.

The transformer operates based on the principle of electromagnetic induction, which states that the ratio of the number of turns in the primary coil to the number of turns in the secondary coil is equal to the ratio of the input voltage to the output voltage. Mathematically, this can be expressed as:

Np / Ns = Vin / Vout

In this case, the input voltage (Vin) is 220 V and the output voltage (Vout) is 10 V. Substituting these values into the equation, we get:

Np / Ns = 220 / 10

Simplifying further:

Np / Ns = 22

This equation shows that the primary coil has 22 times as many turns as the secondary coil.

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A diagram is provided.What is the volume of the block of metal?

Answers

Answer:

You need to add a picture:)

In your own words, describe conservation of mass. Use examples to support your answer.

Answers

Answer:

The law of conservation of mass or principle of mass conservation states that for any system closed to all transfers of matter and energy, the mass of the system must remain constant over time, as the system's mass cannot change, so quantity can neither be added nor be removed

Explanation:

Newton’s third law is the law of
a-inertia
b-interactive
c-definite proportions
d-acceleration

Answers

Answer:

B. interactive

Explanation:

newtons first law is inertia his second is acceleration and third is interactive.

Answer:Newtons third law is Interactive because his first was Inertia and his second

Particle q1 has a charge of 2.7 μc and a velocity of 773 m/s. if it experiences a magnetic force of 5.75 × 10–3 n, what is the strength of the magnetic field? t in the same magnetic field, particle q2 has a charge of 42.0 μc and a velocity of 1.21 × 103 m/s. what is the magnitude of the magnetic force exerted on particle 2? n

Answers

1)The strength of the magnetic field for particle 1 will be 2.8 T.

2)The magnitude of the magnetic force exerted on the particle will be 0.12 N.

What is a magnetic field?

It is the type of field where the magnetic force is obtained. With the help of a magnetic field. The magnetic force is obtained it is the field felt around a moving electric charge.

The given data in the problem is;

q₁ has a charge = 2.7 μc

v₁ is the velocity of particle 1 = 1 773 m/s.

F is magnetic force = 5.75 × 10–3 n,

q₂ has a charge of 42.0 μc

v₂ is the velocity of 1.21 × 103 m/s.

\(\rm F_{B2}\)   is the magnitude of the magnetic force exerted on particle 2=?

The megnetic force for case 1 is found as;

\(\rm F_{B1}= qvB SIN \alpha_1 \\\\ 5.75 \times 10^{-3} =2.7 \times 10^{-6}\times 773 \times B sin 90^0 \\\\ B=\frac{5.75 \times 10^{-3}}{2.7 \times 10^{-6} \timesd 773 \times sin 90^0} \\\\ B=2.8 \ T\)

The megnetic force for case 2 is found as;

\(\rm F_{B2} = q_2v_2bsin \alpha_2 \\\\ 42\times 10^{-6} \times 1.21 \times 10^3 \times 2.8 \times sin 55^0 \\\\ F_{B2}=0.12 T\)

Hence the value of the megnetic force exerted on particle 2 will be 0.00122 T.

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Answer:

last one and second one

Explanation:

Particle q1 has a charge of 2.7 μC and a velocity of 773 m/s. If it experiences a magnetic force of 5.75 × 10–3 N, what is the strength of the magnetic field?

2.8

T

In the same magnetic field, particle q2 has a charge of 42.0 μC and a velocity of 1.21 × 103 m/s. What is the magnitude of the magnetic force exerted on particle 2?

0.12

N

Can the sun explain global warming? ( 2 points) Suppose that the Earth has warmed up by 1 K in the last hundred years. i) How much would the solar constant have to increase to explain this? ii) Compare this to the observed fluctuation of the solar constant over the past 400 years (shown in class) For part (i), begin with the standard 'blackbody' calculation from class, that is: set α=0.30, and assume that the Earth acts as a blackbody in the infrared.

Answers

No, the sun cannot explain global warming. Global warming is a phenomenon in which the temperature of the Earth's surface and atmosphere is rising continuously due to human activities such as deforestation, burning of fossil fuels, and industrialization.

This increase in temperature cannot be explained only by an increase in solar radiation.There are several factors which contribute to global warming, including greenhouse gases such as carbon dioxide, methane, and water vapor. These gases trap heat in the Earth's atmosphere, which causes the planet's temperature to rise. The sun's radiation does contribute to global warming, but it is not the main cause.

i) To calculate the increase in solar radiation that would cause the Earth to warm up by 1 K, we can use the following formula:ΔS = ΔT / αWhere ΔS is the increase in solar constant, ΔT is the increase in temperature, and α is the Earth's albedo (reflectivity).α = 0.30 is the standard value used for the Earth's albedo.ΔS = ΔT / αΔS = 1 K / 0.30ΔS = 3.33 W/m2So, to explain the increase in temperature of 1 K over the last hundred years, the solar constant would need to increase by 3.33 W/m2.

ii) The observed fluctuation of the solar constant over the past 400 years has been around 0.1% to 0.2%. This is much smaller than the 3.33 W/m2 required to explain the increase in temperature of 1 K over the last hundred years. Therefore, it is unlikely that the sun is the main cause of global warming.

The sun cannot explain global warming. While the sun's radiation does contribute to global warming, it is not the main cause. The main cause of global warming is human activities, particularly the burning of fossil fuels, which release large amounts of greenhouse gases into the atmosphere.

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Sputnik I was launched into orbit around Earth in 1957. It had a perigee (the closest approach to Earth, measured from Earth's center) of 6.41 x 10^6 m and an apogee (the furthest point from Earth's center) of 7.13 x 10^6 m. What was its speed when it was at its perigee

Answers

In 1957, Sputnik I was propelled into orbit around the planet. Its speed when it was at its perigee was was approximately 7.935 x 10^3 m/s.

The speed of an object in orbit around Earth can be calculated using the vis-viva equation:

v = sqrt(GM/(r))

where v is the velocity of the object, G is the gravitational constant, M is the mass of the Earth, and r is the distance of the object from the center of the Earth.

Given the perigee distance of 6.41 x 10^6 m and the mass of the Earth being 5.972 x 10^24 kg, the velocity of Sputnik I at its perigee would be:

v = sqrt((6.67 x 10^-11 N*(m^2)/(kg^2) * (5.972 x 10^24 kg)) / (6.41 x 10^6 m))

v = 7.935 x 10^3 m/s

So, the speed of Sputnik I when it was at its perigee was approximately 7.935 x 10^3 m/s.

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