The quantum mechanical approach to atomic structure permits the calculation of?

Answer:

Now, we have to determine the limiting reagent.

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g of

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2So, the limiting reactant is hydrogen.

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2So, the limiting reactant is hydrogen.Now, 4 g of H₂ forms 36 g of H₂O

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2So, the limiting reactant is hydrogen.Now, 4 g of H₂ forms 36 g of H₂O1 g of H₂ forms 36/4 g of H₂O. 3 g of H₂ forms 36/4 x 3 = 27 g of H₂O

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2So, the limiting reactant is hydrogen.Now, 4 g of H₂ forms 36 g of H₂O1 g of H₂ forms 36/4 g of H₂O. 3 g of H₂ forms 36/4 x 3 = 27 g of H₂OMaximum amount of water that can be formed is 27 g.

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2So, the limiting reactant is hydrogen.Now, 4 g of H₂ forms 36 g of H₂O1 g of H₂ forms 36/4 g of H₂O. 3 g of H₂ forms 36/4 x 3 = 27 g of H₂OMaximum amount of water that can be formed is 27 g.For, amount of oxygen left of unreacted, Only 24 g of oxygen will react.

Now, we have to determine the limiting reagent.4 g of H₂ reacts with 32 g of O₂ 1 g of H₂ reacts with 32/4 g of O₂ 3 g of H₂ reacts with 32/4 x 3 = 24 g ofBut according to the question, 29 g of O₂ is present. 2So, the limiting reactant is hydrogen.Now, 4 g of H₂ forms 36 g of H₂O1 g of H₂ forms 36/4 g of H₂O. 3 g of H₂ forms 36/4 x 3 = 27 g of H₂OMaximum amount of water that can be formed is 27 g.For, amount of oxygen left of unreacted, Only 24 g of oxygen will react.But 29 g is the given amount. Amount of oxygen unreacted = 29 - 24 = 5 g

The theoretical yield of the given chemical equation is 64 g and limiting reactant is oxygen.

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

As per the equation 4 g hydrogen reacts with 32 g oxygen thus 8 g hydrogen will react with 8×32/4=64 g oxygen.

Thus, the  theoretical yield of the given chemical equation is 64 g .

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Taking into account the definition of percentage composition, the percent composition of carbon in this sample is 62.17%.

The Percentage Composition is a measure of the amount of mass that an element occupies in a compound and indicates the percentage by mass of each element that is part of a compound.

Then, the percentage by mass expresses the concentration and indicates the amount of mass of solute present in 100 grams of solution.

In other words, the percentage by mass of a component of the solution is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.

The percentage by mass is calculated as the mass of the solute divided by the mass of the solution, the result of which is multiplied by 100 to give a percentage. This is:

\(percentageby mass= \frac{mass of solute}{mass of solution}x100\)

In this case, you know:

Replacing:

\(percentageby mass= \frac{46.63 g}{75 g}x100\)

Solving:

percentage by mass= 62.17 %

Finally, the percent composition of carbon in this sample is 62.17%.

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Answer:

D

Explanation:

I did it on a quiz.

The Group 2 alkaline earth metals include Beryllium, Magnesium, Calcium, Barium, Strontium and Radium and are soft, silver metals that are less metallic in character than the Group 1 Alkali Metals.

Answer:

KCl\(_{2}\), >  KBr\(_{2}\), > KI\(_{2}\)

Explanation:

KBr\(_{2}\),   KCl\(_{2}\),   KI\(_{2}\)

The equilibrium constant for the reaction between Alkene and Halogen to give Alkyl halide as a product

Keq = \(\frac{[C2H4X2 ]}{[C2H4 ][ X2]}\)

hence the order of equilibrium from the Largest to the smallest equilibrium

= KCl\(_{2}\), >  KBr\(_{2}\), > KI\(_{2}\)

The solubility of the gas at a pressure of 85 kPa is 0.456 g/L.

The relationship between pressure and a gas's solubility is straightforward. That is, it gets bigger as the strain gets bigger.

The combined gas law can be used to resolve this issue and says that:

(P1V1)/T1 = (P2V2)/T2

To solve for V2, which stands for the new volume at the reduced pressure, we can rearrange this equation as follows:

V2 = (P1V1T2)/(P2T1)

Since the temperature is held constant, T1 = T2, and this simplifies to:

V2 = (P1V1)/P2

Solubility2 = (Solubility1 x P2) / P1

where the solubility at greater pressure is denoted by Solubility1.

With numbers from the problem substituted, we obtain:

Solubility2 = (0.584 g/L x 85 kPa) / 109 kPa

Simplifying this expression, we get:

Solubility2 = 0.456 g/L.

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The mole fraction of carbon dioxide is the ratio of its partial pressure to the total pressure. The mole fraction carbon dioxide in the mixture is 0.37.

Mole fraction of a gas in a mixture of gases is the ratio of its number of moles to the total number of moles. According to Dalton's law of partial pressure, the mole fraction of the gas in a mixture is equal to its fraction of partial pressure.

Given that, partial pressure of nitrogen = 5 atm

partial pressure of carbon dioxide = 3 atm

mole fraction = 3 atm / (3 + 5 atm) = 0.37.

Therefore, the mole fraction of carbon dioxide in the gaseous mixture is 0.37.

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Answer:

Its soil depth

Explanation:

Answer:a mouse

Explanation:

Answer: a mouse

Explanation:

"One possibility is that the battle between the virus and your immune system can take as long as two weeks.

It could be the immune system holds the virus at bay,” said Tompkins.

Or, your immune system has to work so hard that after two weeks it’s inflamed and that’s what makes you feel bad.

The option d) is correct i.e. 1,2 - dimethyl cyclohexane which can exist as cis-trans isomers.

What are isomers?

Isomers are molecules that have the same chemical formula but different structures. This means that they contain the same number of atoms of each element, but they are arranged differently. Isomers can be divided into two categories: structural isomers, where the atoms are connected in different ways, and stereoisomers, where the atoms are connected the same way but arranged differently in space. An example of structural isomers is the difference between butane and isobutane, which are both made up of 4 carbons and 10 hydrogen atoms, but have different structures. An example of stereoisomers is the difference between D-glucose and L-glucose, which are both C6H12O6, but their atoms are arranged differently in space.

The compounds which same molecular formula and different connections are constitutional isomers.

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Answer:

When two different objects touch heat is always transferred from the warmer object to the colder object. If you touch something hot, energy is transferred from the hot object to you.

Explanation:

0.72M is the concentration of cl-1 ions when 10.0g of calcium chloride (Cacl2) is dissolved in a solution with a total volume of 250.0ml.

The key here is to realize that a solution of calcium chloride, CaCl2, will always contain twice as many chloride anions, Cl−, than calcium cations, Ca2+.

This means that one mole of calcium chloride, which contains one mole of formula units of calcium chloride, will have one mole of calcium cations, 1× Ca2+ two moles of chloride anions, 2×Cl−.

The sample given to you contains

10.0g ×mole CaCl2 /110.98g

= 0.0901 moles CaCl2

The solution will thus contain

{0.0901moles Ca2+, 2× 0.0901 moles Cl−}

The two ions' respective concentrations will be

[Ca2+]= Ca2+ 0.0901 moles/ 250× 10^-3

= 0.36M

[Cl−]=  Cl−2× 0.0901moles/ 250× 10^-3= 2× 0.36

M= 0.72M

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tje new preasure is 10.7l

Answer:

no pues nadie te pasa la pagina

The decaying leaves undergoing a chemical reaction to neutralize the pollutants. Therefore, the correct option is option A.

The introduction of dangerous substances is chemical pollution. Herbicides, herbicides, fertilizers, detergents, petroleum, industrial chemicals, as well as sewage are typical man-made contaminants that end up in the ocean. Further inland from coasts, a lot of ocean toxins are dumped into the ecosystem.

The movement of chemical pollutant in soil can be slowed by the presence of organic material, such as decayed leaves. The decaying leaves undergoing a chemical reaction to neutralize the pollutants.

Therefore, the correct option is option A.

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The frequency of this light in Hz is 3.5×10¹⁴

So, the correct answer is A.

The frequency of a certain kind of light with a wavelength of 850 nm can be determined using the formula f=c/λ, where f is the frequency, c is the speed of light and λ is the wavelength.

Substituting the given values, we get f = (2.998×10⁸ m/s)/(850×10⁻⁹m) = 3.53×10¹⁴ Hz.

Therefore, the correct answer is option a, 3.5×10¹⁴ Hz.

It is important to note that the speed of light is a constant value and is typically denoted by the letter "c".

The wavelength and frequency of electromagnetic radiation are inversely proportional, meaning that as the wavelength decreases, the frequency increases. This relationship is known as the wave-particle duality of light and is a fundamental concept in physics.

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4.316 mL of 0.417 M HCl is required to titration 11.9 mL of 0.151 M NaOH.

\(HCl(aq) + NaOH(aq) \rightarrow NaCl(aq) + H_2O(l)\)

To determine the volume of 0.417 M HCl required to titrate 11.9 mL of 0.151 M NaOH, we need to use the stoichiometry of the balanced equation.

First, we find the number of moles of NaOH:

\(\( \text{Moles of NaOH} = \text{Volume} \times \text{Concentration} \)\)

\(\( \text{Moles of NaOH} = 0.0119 \, \text{L} \times 0.151 \, \text{mol/L} \)\)

\(\( \text{Moles of NaOH} = 0.0017989 \, \text{mol} \)\)

According to the balanced equation, the molar ratio between NaOH and HCl is 1:1. Therefore, the number of moles of HCl required is also 0.0017989 mol.

Now, we can calculate the volume of 0.417 M HCl needed:

\(\( \text{Volume of HCl} = \frac{\text{Moles of HCl}}{\text{Concentration}} \)\)

\(\( \text{Volume of HCl} = \frac{0.0017989 \, \text{mol}}{0.417 \, \text{mol/L}} \)\)

\(\( \text{Volume of HCl} = 0.004316 \, \text{L} \) or \( 4.316 \, \text{mL} \)\)

Therefore, 4.316 mL of 0.417 M HCl is required to titration 11.9 mL of 0.151 M NaOH.

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Answer:

a. 0.02 moles  of NH₃, 0 moles of O₂, 0.08 moles of NO, 0.12 moles of H₂O

b. \(P_{NH_3}\) = 12,576.5 Pa, \(P_{NO}\) = 50,306.05 Pa, \(P_{H_2O}\) =  74,459.1 Pa

c. The total pressure is 138,341.64 Pa

Explanation:

a. NH₃ + O₂  → NO + H₂O

The balanced chemical equation is first found to be

4NH₃ + 5O₂  → 4NO + 6H₂O

Therefore, we have;

4 moles of NH₃ reacts with 5 moles of O₂ to form 4 moles of NO and 6 moles H₂O

Dividing by the reactant with the highest number of moles which is 5 moles of oxygen gives;

4/5 moles  of NH₃ reacts with 5/5 moles of O₂ to form 4/5 moles of NO and 6/5 moles H₂O

Which is the same as 4/5 moles  of NH₃ reacts with 1 mole of O₂ to form 4/5 moles of NO and 6/5 moles H₂O

Multiplying by 0.100 gives;

0.1×4/5 moles  of NH₃ reacts with 0.1 mole of O₂ to form 0.1×4/5 moles of NO and 0.1×6/5 moles H₂O

The quantity of each gas in the container upon completion of the reaction is therefore;

(0.1 - 0.1×4/5) = 0.02 moles  of NH₃

0 moles of O₂

0.08 moles of NO

0.12 moles H₂O

b. Given that the temperature = 105°C, we have;

PV = nRT

P = nRT/V

Where:

n = Total number of moles = 0.02 + 0.08 + 0.12 = 0.22 moles

R = Universal gas constant = 8.3145 J/(mol·K)

T = Temperature = 105°C = 378.15 K

V = Volume = 5 litre = 0.005 m³

P = 0.22×8.3145×378.15/0.005 = 138,341.64 Pa

From Dalton's law of partial pressure, we have;

Partial pressure Pₓ = Xₓ × P

Where:

Xₓ = Mole fraction

Which gives for ammonia NH₃ with 0.02 moles;

Mole fraction = 0.02/0.22 = 1/11

\(P_{NH_3}\) = 1/11 × 138,341.64  = 12,576.5 Pa

For the 0.08 moles of NO, we have

Mole fraction = 0.08/0.22 = 4/11

\(P_{NO}\) = 4/11 × 138,341.64  = 50,306.05 Pa

For the 0.12 moles H₂O

P = 0.12×8.3145×378.15/0.005 = 74,459.1 Pa

Mole fraction = 0.12/0.22 = 6/11

\(P_{H_2O}\) = 6/11 × 138,341.64  = 74,459.1 Pa

c. The total pressure = 12,576.5 Pa + 50,306.05 Pa + 74,459.1 Pa = 138,341.64 Pa.

Answer: The correct option is A) They have fixed energy values.

Explanation:

Electron is one of the sub-atomic particle present around the nucleus of an atom which is negatively charged.

In an atomic model, it is assumed that the electron revolves around the nucleus in discrete orbits having fixed energy levels.

These electrons when jumping from one energy level to another, some amount of radiation is either emitted or absorbed.

These fixed energy levels are given by the Bohr model and thus, the electrons are quantized.

Hence, the correct option is A) They have fixed energy values.

Answer: They have fixed energy values

Explanation: a pex

Answer:

Option (2)

Explanation:

Since the amount of each sample is the same, we are looking for the metal with the greatest density, which is copper.

Answer:

A.) 1:1

Explanation:

You can determine the mole ratio between substances by comparing their coefficients in the balanced equation. Both Cl₂ and Br₂ have coefficients of 1. Therefore, they have a 1 to 1 (1:1) relationship.

If you were comparing the mole ratio of Cl₂ and NaBr, they would have a 1:2 relationship because Cl₂ has a coefficient of 1 and NaBr has a coefficient of 2.

Answer:

11.2 moles of KNO3 will be required to prepare 8.0 L of 1.40 M KNO3

Explanation:

To answer this question, we need an understanding of the units of the term called molarity.

1.40M KNO3 means that there are 1.4 moles per dm^3 or per liter of the solution.

Now, since there are 1.4 moles in 1 liter

x moles will be present in 8.0 liters

Thus, mathematically;

x * 1 = 8 * 1.4

x = 11.2 moles

Answer:

the answer is 383.0

hope it is helpful

Barrier that must be overcome before products are formed in a spontaneous reaction is Activation energy barrier.

A spontaneous response is a response that favors the formation of products on the conditions underneath which the response is occurring. A roaring bonfire is an instance of a spontaneous response, in view that it is exothermic (there is a decrease inside the power of the system as energy is released to the environment as warmth).

Maximum spontaneous chemical reactions are exothermic - they release warmness and heat up their surroundings: for instance: burning wooden, fireworks, and alkali metals introduced to water. When a radioactive atom splits up, it releases strength: that is a spontaneous, exothermic nuclear reaction.

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I apologize, but there is no provided list or context for me to match the number of neutrons to the correct isotope.

To match the number of neutrons to the correct isotope, you need to study the atomic number and mass number of each isotope.

Step 1: Determine the number of protons.
The atomic number represents the number of protons in an atom.

Step 2: Determine the number of neutrons.
To find the number of neutrons, subtract the atomic number from the mass number: Number of neutrons = Mass number - Atomic number.


Isotope 1 (Correct4):
- Atomic number: __
- Mass number: __
- Neutrons: Mass number - Atomic number = 4

Isotope 2 (Correct5):
- Atomic number: __
- Mass number: __
- Neutrons: Mass number - Atomic number = 5

Isotope 3 (Correct8):
- Atomic number: __
- Mass number: __
- Neutrons: Mass number - Atomic number = 8

Isotope 4 (Correct9):
- Atomic number: __
- Mass number: __
- Neutrons: Mass number - Atomic number = 9

Isotope 5 (Correct10):
- Atomic number: __
- Mass number: __
- Neutrons: Mass number - Atomic number = 10

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Answer:

64.25

Explanation:

Average atomic mass = percentage × mass of all isotopes/ 100

Relative atomic mass = 80*64+15*65+5*66/100

=5120+975+330/100

=6425/100

64.25

The product of the hydration reaction of 2-butene is 2-butanol.The H+ from the water attach to one double bonded carbon and the OH group attaches to the second double bonded carbon atom as shown in the image.

Alkenes are unsaturated hydrocarbons with one or more double bonds between carbon atoms. They are highly reactive due to the electron deficient center.

When alkenes are treated with water, according to rule of Markonikoves, H+ will attach at the most substituted double bonded carbon and OH with least substituted one.

Here in 2- butene it is a symmetric alkene hence both double bonded carbon are singly occupied by one hydrogen. Then , the major product is 2- butanol.

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\({ \red{ \underline{ \tt{Langmuir \: adsorption \: isotherm:}}}}\)

The defect of Freundlich adsorption isotherm is that it fails at high pressure of the gas.

Langmuir derived the adsorption isotherm based on the theoretical considerations. It is generally applied to chemical adsorption.

It can be expressed as

\({ \blue{ \bold{ \frac{X}{m} = \frac{AP}{1+BP}}}}\)

where,

X = mass of the gas adsorbed

M = mass of the adsorbent

P = equilibrium pressure