The population of insects in an experiment has
been increasing by 9% each week. If there were 16
insects at the beginning of the experiment, predict
how many insects there will be after 8 weeks.
First, complete the equation:
Future Amount = 16 (1 + 0.09)
8
Now solve. Round to the nearest whole number

Answers

Answer 1

There are 32 insects in the population after 8 weeks

How to complete the equation?

The given parameters are:

Initial value, a = 16Rate, r = 9% or 0.09

Let the number of weeks be x.

So, the future amount is

Future Amount = a * (1 + r)^x

This gives

Future Amount = 16 * (1 + 0.09)^x

At the 8th week, we have:

Future Amount = 16 * (1 + 0.09)^8

Evaluate

Future Amount = 32

Hence, there are 32 insects in the population after 8 weeks

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Related Questions

In 25 years, a bond that paid 7.75% simple interest earned $3,875 interest. What was the principal of the bond in dollars?

Answers

the interest the bond paid off is $7507.8125.

What is simple interest?

A quick and simple way to figure out interest on money is to use the simple interest technique, which adds interest at the same rate for each time cycle and always to the initial principal amount. Any bank where we deposit our funds will pay us interest on our investment. One of the different types of interest charged by banks is simple interest. Now, before exploring the idea of basic curiosity in further detail,

The formula for simple interest is:

S = p*t*r/100

where P is the principal amount of money, R is the interest rate as a decimal, T is the time.

a bond that paid 7.75% simple interest earned $3,875 interest.

S = (3875*7.75*25)/100 = $7507.8125

Hence the interest the bond paid off is $7507.8125.

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What is -20/2(7 2/3)

Answers

The simplified form of -20/2(7 2/3) is -230/3.

To solve the expression -20/2(7 2/3), we need to follow the order of operations, which states that we should perform the operations inside parentheses first, then any multiplication or division from left to right, and finally any addition or subtraction from left to right.

First, let's convert the mixed number 7 2/3 to an improper fraction.

7 2/3 = (7 * 3 + 2) / 3 = 23/3

Now, let's substitute the value back into the expression:

-20/2 * (23/3)

Next, we simplify the multiplication:

-10 * (23/3)

To multiply a fraction by a whole number, we multiply the numerator by the whole number:

-10 * 23 / 3

Now, we perform the multiplication:

-230 / 3

Therefore, the simplified form of -20/2(7 2/3) is -230/3.

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Order the numbers from least to greatest based on their absolute values.

|23|, |−37|, |−6|, |18|, |−24|, |2|

Answers

Answer:

/-37/, /-24/, /-6/, /2/, /18/, /23/

The expression 3^5 means to _____.

A) multiply 3 factors of 5
B) multiply 3 times 5
C) multiply 5 factors of 3
D) add 3 and 5

Answers

Answer:

C

Step-by-step explanation:

3^5 = 3*3*3*3*3

You are multiplying 5 3s

Answer:

multiply 3 factors of 5

Step-by-step explanation:

it means you're multiplying 3 five times

I WILL GIVE THE BRAINIEST

A high school class is planning a field trip to an art museum in their city. The class collected a total of $1259 from all of the students, which will go towards renting a bus, museum admission, and lunch
However, a week before the trip 9 students had to drop out and their portion of the collected money had to be given back to them. Due to this, the students that are all still going must contribute an
Now let a be the number of students who went on the trip and s9 be the original number of students who had planned to go on the trip
What equation can be written to determine the number of students that went on this trip?

I WILL GIVE THE BRAINIESTA high school class is planning a field trip to an art museum in their city.

Answers

An equation can be written to determine the number of students that went on this trip is: C. \(\frac{1259}{s} + 12=\frac{1259}{s+9}\)

How to write an equation to determine the number of students that went on this trip?

In order to write an equation to determine the number of students that went on this trip, we would have to assign a variable and an expression to the number of students who went on the trip and the original number of students who had planned to go on the trip as follows;

Let the variable s represent the number of students who went on the trip.Let the expression s + 9 represent the original number of students who had planned to go on the trip.

Since a total of $1259 was collected from all of the students with 9 students dropping out and their portion of the money collected given back to them while the students that are all still going must contribute an additional $12, an equation to determine the number of students that went on this trip is given by;

\(\frac{1259}{s} + 12=\frac{1259}{s+9}\)

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Complete Question:

A high school class is planning a field trip to an art museum in their city. The class collected a total of $1259 from all of the students, which will go towards renting a bus, museum admission, and lunch.

However, a week before the trip 9 students had to drop out and their portion of the collected money had to be given back to them. Due to this, the students that are all still going must contribute an additional $12 each to cover all of the cost.

Now let s be the number of students who went on the trip and s + 9 be the original number of students who had planned to go on the trip

What equation can be written to determine the number of students that went on this trip?

7.
(02.01 MC)

Six-year-old students at an elementary school were given a 20-yard head start in a race. The graph shows how far the average student ran in 30 seconds.

A line graph with Distance, in yards, on the x axis and Age of Runner on the y axis. The x axis has a scale from 0 to 80 in increments of 10. The y axis has a scale of 0 to 8 in increments of 2. A straight line connecting 20, 6 and 60, 6 is drawn.

Which statement best describes the domain of the function represented in the graph? (1 point)
6 ≤ x ≤ 60, or x is from 6 to 60
6 ≤ x ≤ 20, or x is from 6 to 20
0 ≤ x ≤ 20, or x is from 0 to 20
20 ≤ x ≤ 60, or x is from 20 to 60
HELP

7. (02.01 MC)Six-year-old students at an elementary school were given a 20-yard head start in a race.

Answers

The domain of the function represented in the graph will be 20 ≤ x ≤ 60, or x is from 20 to 60. Then the correct option is D.

What is a line segment?

A line segment in mathematics has two different points on it that define its boundaries.

A line segment is sometimes referred to as a section of a path that joins two places.

Six-year-old students at an elementary school were given a 20-yard head start in a race. The graph shows how far the average student ran in 30 seconds.

A line graph with Distance, in yards, on the x-axis and Age of the Runner on the y-axis. The x-axis has a scale from 0 to 80 in increments of 10. The y-axis has a scale of 0 to 8 in increments of 2. A straight line connecting 20, 6, and 60, 6 is drawn.

The domain of the function represented in the graph will be 20 ≤ x ≤ 60, or x is from 20 to 60. Then the correct option is D.

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Answer:

the correct option is D

Step-by-step explanation:

A tank contains 100 gallons of pure water. At time zero, a sugar-water solution containing 0.2 lb of sugar per gallon enters the tank at a rate of 3 gallons per minute. Simultaneously, a drain is opened at the bottom of the tank allowing the sugar solution to leave the tank at 3 gallons per minute. Assume the solution in the tank is kept perfectly mixed at all times. What will be the eventual sugar content in the tank as time goes to infinity?

Answers

Answer:

20 lbs of sugar per gallon as time goes to infinity

Step-by-step explanation:

Because of the statement ... as time goes to infinity...I am inclined to approach this problem using derivatives and limits

Let the amount of sugar in the tank at any time t(in minutes) be

\(S(t) \;lbs/gal\)

We have \(S(0) = 0\)  since the initial quantum of water has zero sugar

The inflow rate of sugar is given as 3  gal/min and each gallon contains 0.2 lbs of sugar
\therefore The rate of sugar increase in the tank n lbs/gal
= 0.2 lbs /gal \times 3 gal/min

=  0.6 lbs/min

Outflow rate = 3 gal/min
At any time t, the tank contains 100 gal
The amount of sugar at time t = \dfrac{S(t)}{100} lbs/gal

Therefore the outflow rate of sugar = 3 gal/min \times \dfrac{S(t)}{100} lbs/gal

= 0.03S(t) lb/min

The net rate is given by inflow rate - outflow rate

= 0.6 - 0.03S(t)

In calculus terms the net rate =  \(\dfrac{dS(t)}{dt}\)

Therefore
\(\dfrac{dS(t)}{dt} = 0.6 - 0.03S(t)\)

\(\dfrac{dS(t)}{dt} - 0.03S(t) = 0.6\\\\\)    (1)

A trick to solving differential equations of this type is to use the method of integrating factors

In general,  if we have a differential equation of the type
\(\dfrac{dy}{dx} + Py = Q\\\\\)
where P and Q are functions only of x

then the integrating factor is \(e^{\int\ {P} \, dx }\)

which you use to multiply both sides of the differential equation first

In equation (1) above,

y = S(t) which well simply write as S for convenience

Writing S' for \(\dfrac{dS(t)}{dt}\) for convenience we get equation (1) as

\(S' + 0.03S =0.6\)   (2)

From the above we see that P in the generalized differential equation corresponds to 0.03

Therefore the integrating factor is
\(\mbox {\large e^{\int 0.03dt} = e^{0.03t}}\)

Multiply equation (2) throughout by this integrating factor to get


\(\mbox{\large e^{0.03t} S' + 0.03S e^{0.03t} = 0.6 e^{0.03t} }\)

The left side is nothing but the first derivative of \(\mbox{\large (e^{0.03t}S) }\\\\\)
\(= \mbox{\large (e^{0.03t}S)'\\\\}}\)

Integrating both sides we get

\(\mbox{\large e^{0.03t}S = 0.06 \int e^{0.03t}dt}\\\\\)    (3)

\(\textrm{By using the fact that $\int e^{ax} dx = \dfrac{e^{ax}}{a} + C$}:\\\\\mbox{\large \int e^{0.03t}dt} = \dfrac{e^{0.03}}{ 0.03}} + C\\\\\)  

Therefore equation (3) becomes
\(e^{0.03t}S = 0.06 \cdot \dfrac{e^{0.03}}{0.03}} + C\\\\e^{0.03t}S = 0.06 \cdot 33.333 \cdot e^{0.03} + C\\\\e^{0.03t}S = 20 \cdot e^{0.03} + C\\\)

Dividing by \(e^{0.03} \textrm{ (same as multiplying by $e^{-0.03}$) both sides}\):

\(S = 20 + Ce^{-0.03t}\\\\\textrm{Plugging back S(t):}\\\\S(t) = 20 + Ce^{-0.03t}\\\)

We are asked to find the level of sugar content as t ⇒ ∞

At t = 0, S(t) = 0; there is no sugar content

S(0) = 0 = 20 + Ce⁰

0 = 20 + C
C = -20

\(S(t) = 20 -20e^{-0.03t}\\\\\)

As t ==>  ∞
we get

\(\lim _{x\to \infty }S\left(t\right)=\:\lim _{x\to \infty }\left(20\:-\:20e^{-0.03t}\right)=\:\:20\:-\:0\:=\:20\)

Therefore as time goes to infinity the eventual sugar content
= 20 lbs/gallon

round 11,406 to the nearest:tens ,ten thousand , hundred​

Answers

Answer:

Tens:11,410

Ten thousand :10,000

Hundred : 11,400

AY1008060Number of Bacteria4020X0103020Time (hours)Based on the graph, what is the approximate number of bacteria after 16 hours?

AY1008060Number of Bacteria4020X0103020Time (hours)Based on the graph, what is the approximate number

Answers

From the graph, if we look for the corresponding y-value for Time = 16 hours:

The approximate number of bacteria after 16 hours is 50

AY1008060Number of Bacteria4020X0103020Time (hours)Based on the graph, what is the approximate number

4 waiters can serve 250 dishes in 8 days by working 5 hours/day. for how many hours/day would 2 waiters have to work to serve 500 dishes in 20 days?

Answers

Answer:

8 hours/day is the answer.

The tread life of a particular brand of tire is a random variable best described by a normal distribution with a mean of 60,000 miles and a standard deviation of 8,300 miles. What proportion of these tires last between 40,000 and 45,000 miles

Answers

Answer:

P [ 40000 ≤ X ≤ 45000 ] =  0,02773    or  2,8 %

Step-by-step explanation:

P [ 40000 ≤ X ≤ 45000 ]  = ?

To find the probablity    P [ X ≤ 40000 ] =  ?

z(s)  = ( X - x ) / σ

z(s)= ( 40000 - 6000 )/ 8300

z(s) =  -20000/8300

z(s) ≈  - 2,41

Then

from z-table we find P [ X ≤ 40000] =  0,00820

Now again:

For  P [ X ≤ 45000 ]

z₂  = ( X - x ) / σ

z₂ =  ( 45000 - 6000 ) / 8300

z₂ = - 15000 / 8300

z₂ = - 1,8072

z₂ ≈ 1,81

From z - table

For  P [ X ≤ 45000 ] =   0,03593

Then:

P [ 40000 ≤ X ≤ 45000 ] = 0,03593 - 0,00820

P [ 40000 ≤ X ≤ 45000 ] =  0,02773    or  2,8 %

I need help quickly

I need help quickly

Answers

Using L'hopital we can see that the limit is equal to 1/22

How to solve the limit?

Here we want to take the limit of x tending to zero for x/sin(22x)

Notice that when x = 0, both numerator and denominator are zero, so we need to take the limit of the first derivatives, for:

y = x

y' = 1

And for:

y = sin(22x)

y' = 22*cos(22x)

Now taking the limit we will get:

\(\lim_{x \to 0} \frac{1}{22cos(22x)} = \frac{1}{22cos(0)} = 1/22\)

That is the value of the limit.

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ORDERED PAIRS
{(-1, 2), (0, 5), (2, 7)}
Domain:
Range:
Function?

Answers

The set of input values (x-coordinates): (-7, -3, 0, 5) and the set of output values (y-coordinates): (1, 2, -2, -5) make up the domain and range of this set of ordered pairs.

What are domain and range?

The range of values that we are permitted to enter into our function is known as the domain of a function.

The x values for a function like f make up this set (x).

A function's range is the collection of values it can take as input.

After we enter an x value, the function outputs this sequence of values.

So, we have the ordered pair:

{(-1, 2), (0, 5), (2, 7)}

Now, get the domain and range as follows:

The set of input values (x-coordinates): (-7, -3, 0, 5) ⇒ Domain

The set of output values (y-coordinates): (1, 2, -2, -5) ⇒ Range

Therefore, the set of input values (x-coordinates): (-7, -3, 0, 5) and the set of output values (y-coordinates): (1, 2, -2, -5) make up the domain and range of this set of ordered pairs.

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The 100th term of 50, 80, 110 is??

Answers

100th term will be 3020

lve for m.
-3 + m

9 = 10
A.
-30
B.
63
C.
87
D.
93

Answers

The value of m that satisfies the equation -3 + m = 9 is m = 12.

To solve the equation -3 + m = 9, we can isolate the variable m by moving the constant term -3 to the other side of the equation.

-3 + m = 9

To move -3 to the other side, we can add 3 to both sides of the equation:

-3 + 3 + m = 9 + 3

Simplifying, we have:

m = 12

Therefore, the value of m that satisfies the equation -3 + m = 9 is m = 12.

None of the provided answer options (A, B, C, D) match the correct solution.

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At an intersection in Normal, Illinois, there were 90 vehicle accidents with 168,199 vehicles passing through the intersection. Determine the accident rate per 1000 vehicles.

Answers

You can calculate this by dividing 90 by 168199. That is the accident rate per vehicle. Then you can multiply it by thousand and you got the accident rate per 1000 vehicles. So that will be 0,53

What two numbers add together to make negative 4 but subtract to make positive 8

Answers

The two numbers that add together to make -4 but subtract to make +8 are 2 and -6.

Two numbers that add together to make -4 but subtract to make +8, we can set up a system of equations.

Let's call the two numbers x and y.

We can set up the following equations:

Equation 1: x + y = -4

Equation 2: x - y = 8

To solve this system of equations, we can use the method of elimination. Adding Equation 1 and Equation 2 eliminates the variable y:

(x + y) + (x - y) = -4 + 8

2x = 4

x = 2

Now, we can substitute the value of x into either Equation 1 or Equation 2 to solve for y.

Let's use Equation 1:

2 + y = -4

y = -6

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23. Evaluate a(b + c) if a = 2, b = 3, and c = 4.
Simplify:

Answers

The value of the expression a(b + c) when a = 2, b = 3, and c = 4 is 14.

What is the value of the expression a(b + c) if a = 2, b = 3, and c = 4?

Given the expression in the question:

a( b + c )

Also, a = 2, b = 3, and c = 4

To evaluate the expression a( b + c ) when a = 2, b = 3, and c = 4, we substitute these values into the expression:

Hence:

a( b + c )

Plug in a = 2, b = 3, and c = 4

2( 3 + 4 )

First, we simplify the parentheses by adding 3 and 4:

2( 7 )

Next, we multiply 2 and 7:

14

Therefore, the value of a(b + c) is 14 .

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help pls look at the image

help pls look at the image

Answers

Answer: 6/4 In simplest form is 3/2

Step-by-step explanation:

Samuel can do 120 jumping jacks in two minutes.

What is the ratio?



How many jumping jacks can he do in one minute?

Answers

Answer:

The ratio of jumping jacks to minutes is 120:2 or 60:1. He can do 60 Jumping jacks in 1 minute

Step-by-step explanation:

Answer:

ratio: 2 to 120

He can 60 jumping jacks in one minute

Step-by-step explanation:

If you have a statistical calculator or computer, use it to find the actual sample mean and sample standard deviation. Otherwise, use the values Σx = 2769 and Σx2 = 132,179 to compute the sample mean and sample standard deviation. (Round s to four decimal places.)

Answers

By using a statistical calculator, the actual sample mean and sample standard deviation are:

Actual sample mean = 46.1500.

Actual ample standard deviation = 8.6256.

How to calculate the sample mean for the set of data?

In Mathematics and Geometry, the sample mean for any set of data can be calculated by using the following formula:

Mean = ∑x/(n - 1)

∑x represents the sum of all data values.(n - 1) represents the number of data contained in a sample.

In Mathematics and Geometry, the sample standard deviation for any set of data can be calculated by using the following formula:

Standard deviation, δx = √(1/N × ∑(x - \(\bar{x}\))²)

x represents the observed values of a sample.\(\bar{x}\) is the mean value of the observations.N represents the total number of of observations.

By using a statistical calculator, the actual sample mean and sample standard deviation are as follows;

Actual sample mean = 46.1500.

Actual ample standard deviation = 8.6256.

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

If you have a statistical calculator or computer, use it to find the actual sample mean and sample standard
If you have a statistical calculator or computer, use it to find the actual sample mean and sample standard

doors for for the small cabinets are 15.5 in Long doors for the large cabinets or 2.5 times as long as the doors for the small cabinets how many large doors can be cut from a board that is 10 ft long ​

Answers

answer: 3 large doors, because if you multiply 12.5 by 2.5 you get 38.75. then you calculate how many inches are in 10 feet which is 120. (10ftx12in) you divide 120 by 38.75 and you get 3.09 which can be rounded to 3.

A pyramid has a height of 5 inches and a volume of 60 cubic inches. Which of the following figures could be the base for this pyramid?
Select 3 answers that apply.
A a hexagon with an area of 36 square inches
11 a right triangle with one leg 5 inches and the hypotenuse 13 inches
ca circle with radius 4 inches
Da 4-inch by 9-inch rectangle
a 3-inch by 4-inch rectangle
a square with side length 6 inches
E

Answers

The 3 correct answers of the figures that could be the base for the pyramid that has a height of 5 inches and a volume of 60 cubic inches are:

A hexagon with an area of 36 square inches (option A)A 4-inch by 9-inch rectangle (option D)A 3-inch by 4-inch rectangle (option E)

How do we calculate?

The formula to find the base of a pyramid given its height and volume,

Volume of pyramid = (1/3) * Base area * Height

Substituting in the given values, we have:

60 = (1/3) * Base area * 5

Base area = 36 square inches

In conclusion, any figure with a base area of 36 square inches could be the base for this pyramid.

The following figures have a base area of 36 square inches:

A hexagon with an area of 36 square inches A 4-inch by 9-inch rectangle A 3-inch by 4-inch rectangle

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(5+6) + 7 =



28+ (9 + 3) =
3(10+ 2) + 5 =

Answers

Answer:

18

40

41

 

do the operations in parentheses first according to pemdas.

The figure above shows a store's supply-demand graph for coffee makers. If the store sells $600 worth of coffee makers, which of the following is a valid possible price for them?

A. $15

B. $30

C. $40

D. $55

The figure above shows a store's supply-demand graph for coffee makers. If the store sells $600 worth

Answers

The possible price for the items if the store sells $600 is (c) $40

How to determine the possible price for the items?

From the question, we have the following parameters that can be used in our computation:

The supply-demand graph

If the store sells $600, then there is a supply worth of $600

The equation of the supply line is calculated as

y = mx + c

Where

c = y = 0

i.e. c = 100

So, we have

y = mx + 100

Using another point on the graph, we have

30m + 10 = 400

So, we have

m = 13

This means that

y = 13x + 100

For a supply of 600, we have

13x + 100 = 600

So, we have

13x = 500

Divide by 13

x = 38.4

Approximate

x = 40

Hence, the possible price for the items is (c) $40

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Maitri and Aabhas do a work in 12 hours.

Aabhas and Kavya do the work in 15 hours.

Kavya and Maitri do
work in 20 hours.

In how many hours will they finish it together and separately?

Pls help me

Answers

Answer:

See below ~

Step-by-step explanation:

Given

Maitri and Aabhas do a work in 12 hoursAabhas and Kavya do the work in 15 hoursKavya and Maitri do the work in 20 hours

Solving

Take Maitri, Aabhas, and Kavya to be x, y, z respectivelyx + y = 12 (1)y + z = 15 (2)x + z = 20 (3)

Take Equation 1 and rewrite it so that it is equal to x.

x = 12 - y

Take Equation 2 and rewrite it so that it is equal to z.

z = 15 - y

Now, substitute these values in Equation 3.

x + z = 2012 - y + 15 - y = 20-2y + 27 = 202y = 7y = 7/2 = 3.5 hours [Aabhas]

Substitute the value of y in Equation 1.

x + 3.5 = 12x = 8.5 hours [Maitri]

Substitute the value of y in Equation 2.

3.5 + z = 15z = 11.5 hours [Kavya]

Add the values of x, y, and z together.

x + y + z8.5 + 3.5 + 11.512 + 11.523.5 hours [together]

A color printer uses four colors of ink cartridges to print images. The table
shows the remaining ink levels of each cartridge in the color printer.
&
O
Cyan, yellow, black, magenta
Color Printer Ink
Remaining
Ink Color
Ink Level
1
Cyan
3
&
Yellow, black, cyan, magenta
1 /
&
Magenta, black, yellow, cyan
Magenta
35%
Do
Magenta, cyan, black, yellow
Black
0.3
CLEAR ALL
Yellow
12 / 를
Which list shows the remaining ink levels in order from least to greatest?

A color printer uses four colors of ink cartridges to print images. The tableshows the remaining ink

Answers

Answer:

yellow, black, cyan, magenta

Step-by-step explanation:

Suppose y = sqrt 2x+1, where x and y are functions of t.
(a) If dx/dt = 9, find dy/dt when x = 4.
(b) If dy/dt = 3, find dx/dt when x = 40.

Answers

If y = √(2x + 1), then differentiating both sides implicitly with respect to t gives

dy/dt = 1/2 • 1/√(2x + 1) • 2 • dx/dt = 1/√(2x + 1) • dx/dt

(a) If dx/dt = 9 and x = 4, then

dy/dt = 1/√(2•4 + 1) • 9

dy/dt = 1/√(8 + 1) • 9

dy/dt = 1/√9 • 9

dy/dt = 9/3

dy/dt = 3

(b) If dy/dt = 3 and x = 40, then

3 = 1/√(2•40 + 1) • dx/dt

3 = 1/√(80 + 1) • dx/dt

3 = 1/√81 • dx/dt

3 = 1/9 • dx/dt

dx/dt = 27

Classify the polygon. Then determine whether it appears to be regular or not regular. A. stargon; regular B. hexagon; not regular C. pentagon; not regular D. pentagon; regular

Classify the polygon. Then determine whether it appears to be regular or not regular. A. stargon; regular

Answers

The answer to the question is c

Help!
What is the answer to this question?

Help!What is the answer to this question?

Answers

Answer:

Its perimeter is 23 units

Step-by-step explanation:

The perimeter of any figure is the sum of the lengths of its outline sides

The rule of the distance between two points is:

\(d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\)

In the given figure ABCD:

Its perimeter = AB + BC + CD + DE + EA

→ Find the length of each side using the rule above

A = (-4, -2), B = (-1, 2), C = (2, 2), D = (5, -1), E = (2, -4)

→ Substitute them in the rule above to find the lengths of its sides

\(AB=\sqrt{(-1--4)^{2}+(2--2)^{2}}=\sqrt{(-1+4)^{2}+(2+2)^{2}}\\\\=\sqrt{(3)^{2}+(4)^{2}}=\sqrt{9+16}=\sqrt{25}\)

AB = 5

\(BC=\sqrt{(2--1)^{2}+(2-2)^{2}}=\sqrt{(2+1)^{2}+(0)^{2}}\\\\=\sqrt{(3)^{2}+0}=\sqrt{9+0}=\sqrt{9}\)

BC = 3

\(CD=\sqrt{(5-2)^{2}+(-1-2)^{2}}=\sqrt{(3)^{2}+(-3)^{2}}\\\\=\sqrt{9+9}=\sqrt{18}\)

CD = \(\sqrt{18}\)

\(DE=\sqrt{(2-5)^{2}+(-4--1)^{2}}=\sqrt{(-3)^{2}+(-4+1)^{2}}\\\\=\sqrt{(-3)^{2}+(-3)^{2}}=\sqrt{9+9}=\sqrt{18}\)

DE = \(\sqrt{18}\)

\(EA=\sqrt{(-4-2)^{2}+(-2--4)^{2}}=\sqrt{(-6)^{2}+(-2+4)^{2}}\\\\=\sqrt{(-6)^{2}+(2)^{2}}=\sqrt{36+4}=\sqrt{40}\)

EA = \(\sqrt{40}\)

→ Add them to find the perimeter of the figure ABCDE

∴ Its perimeter = 5 + 3 + \(\sqrt{18}\) + \(\sqrt{18}\) +\(\sqrt{40}\) ≅ 22.8098

→ Round it to the whole number

Its perimeter = 23 units

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