The peak voltage rating of the transformer secondary for a voltage doubler that produces an output of 50 V is equal to 50 V 100 V 25 V 40.3 V 90.3 V 50.7 V 100.7 V

Answer:

The molecular weight of the gas mixture is 35.38 g/mol.

Explanation:

The molecular weight of the gas can be found using the following equation:

\( M = \frac{m}{n} \)

Where:

m: is the mass = 230 g

n: is the number of moles

First, we need to find the number of moles using Ideal Gas Law:

\( PV = nRT \)

Where:

P: is the pressure = 135 psi

V: is the volume = 15 L

R: is the gas constant = 0.082 L*atm/(K*mol)

T: is the temperature = 465 °R (K = R*5/9)

\(n = \frac{PV}{RT} = \frac{135 psi*\frac{1 atm}{14.6959 psi}*15 L}{0.082 L*atm/(K*mol)*465*(5/9) K} = 6.50 moles\)                

Finally, the molecular weight of the gas is:

\( M = \frac{m}{n} = \frac{230 g}{6.50 moles} = 35.38 g/mol \)

Therefore, the molecular weight of the gas mixture is 35.38 g/mol.

I hope it helps you!

Answer:a

Ieieksdjd snsnsnsnsksks

Housed at server farms, search engines use keywords to index data coming in from crawlers. Hence option b is correct.

Search engine is defined as a piece of software that uses keywords or phrases to assist users in finding the content they're looking for online. The vast amount of material that is accessible on the internet is effectively filtered by search engines.

A search engine is a piece of software used to conduct online searches. They carry out methodical searches of the Internet for certain data that is specified in a text-based web search query.

Thus, housed at server farms, search engines use keywords to index data coming in from crawlers. Hence option b is correct.

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Answer: The solar irradiance is measured in watt per square metre (W/m2) in SI units. Solar irradiance is often integrated over a given time period in order to report the radiant energy emitted into the surrounding environment (joule per square metre, J/m2) during that time period.

Explanation: hope that helped!

The values of h at the two internal boundaries are :

Given data :

Z₁ = Z₂ = Z₃ = 25 m

h top = 120 m

h bottom = 100 m

K₁ = 0.0001 m/s

K₂ = 0.0005 m/s

K₃ = 0.0010 m/s

we will apply the formula below since flow is perpendicular to the bedding plane

Keq = \(\frac{Z1 + Z2 + Z3 }{\frac{Z1}{K1}+\frac{Z2}{K2} + \frac{Z3}{K3} }\)  ----- ( 1 )

Insert values given above into equation 1

Therefore ; Keq = 2.307 * 10⁻⁴ m/s

Hydraulic gradient ( Ieq ) = head loss / length

                                          = ( 120 - 100 ) / 3 * 25

                                   Ieq  = 0.266

Given that the flow is perpendicular to bedding plane

q1 = q2 = q3

V₁ = V₂ = V₃ = V

K₁i₁ = K₂i₂ = K₃i₃ = Keq * ieq

Hence :

V = Keq* Ieq

   = 2.307 * 10⁻⁴ * 0.266

   = 6.15 * 10⁻⁵ m/s .

Also;

K₁i₁ =  Keq * ieq = K₂i₂ = K₃i₃

therefore :

  i₁ = 0.615

  i₂ =  0.123

  i₃ = 0.0615

Pressure at point 1 ( i.e. pressure between first two formations )

h₁ = h top - i₁L₁

   = 120 - 0.615 * 25

   = 104.625 m

Pressure at point 2 ( i.e. pressure between the 2nd and 3rd formation )

h₂ = h₁ - i₂L₂

    = 104.625 - 0.123 * 25

    = 101.55 m

Therefore we can conclude that The values of h at the two internal boundaries are :  h₁ = 104.625 m , h₂ = 101.55 m

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The question is missing some important details but I will guide you on how to solve for normal stress

The point in the beam has got a normal stress (σ) which can be calculated by taking the ratio of the bending moment (M) and section modulus (S):

σ = M/S

To ascertain the section modulus of a rectangular cross-section, the following equation is employed:

S = (b * h^2) / 6

In answer to the supplicated inquiry, within this example, b stands for the width of the beam (6 in), and h represents the height of the beam (8 in). Hence, by accounting for these dimensions, S can be calculated.

The effect of a uniformly distributed load (q) on an elicited bending moment (M) can be determined through utilization of the pertinent beam equations, that can be derived once the location of point C, as well as the length of the demonstrated beam is known.

Having notably acknowledged M and S, it is possible to estimate the normal stress (σ) at point C.

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The intrinsic carrier concentration in silicon and germanium increases with temperature.

a) ni = 1.05 x \(10^{10} cm^{-3}\) and ni = 2.31 x\(10^{12}cm^{-3}\)

b) ni = 1.45 x  \(10^{10} cm^{-3}\) and ni = 2.39 x \(10^{13} cm^{-3}\)

c) ni = 2.50 x  \(10^{10} cm^{-3}\) and ni = 6.76 x  \(10^{14} cm^{-3}\)

The intrinsic carrier concentration (ni) in silicon and germanium can be calculated as:

\(ni = (Nc \times Nv)^{0.5} exp^{-Eg/2kT}\)

where, Nc and Nv are the effective densities of states in the conduction and valence bands, respectively.

- Eg is the bandgap energy.

- k is the Boltzmann constant.

- T is the temperature in Kelvin.

For silicon:

- Nc = 2.8 x \(10^{19} cm^{-3}\)

- Nv = 1.04 x \(10^{19} cm^{-3}\)

- Eg = 1.12 eV

For germanium:

- Nc = 4.3 x \(10^{18} cm^{-3}\)

- Nv = 1.8 x \(10^{19} cm^{-3}\)

- Eg = 0.67 eV

(a) At T = 100K:

- For silicon:

T = 100K = 100°C - 273.15 = -173.15°C

ni = (2.8 x   \(10^{19} cm^{-3}\)* 1.04 x  \(10^{19} cm^{-3}\)\()^{0.5} exp^{-1.12/2k(-173.15)}\)

ni = 1.05 x \(10^{10} cm^{-3}\)

For germanium:

T = 100K = 100°C - 273.15 = -173.15°C

ni =\((4.3 \times 10^{18} * 1.8 \times10^{19})^{0.5 } exp^{(-0.67/2k(-173.15))}\)

ni = 2.31 x\(10^{12}cm^{-3}\)

(b) At T = 300K:

- For silicon:

T = 300K = 27°C

ni = \((2.8 \times 10^{19} * 1.04 \times 10^{19})^{0.5} * exp^{(-1.12/2k(27))}\)

ni = 1.45 x  \(10^{10} cm^{-3}\)

- For germanium:

T = 300K = 27°C

ni = 2.39 x \(10^{13} cm^{-3}\)

(c) At T = 500K:

- For silicon:

T = 500K = 227°C

ni = 2.50 x  \(10^{10} cm^{-3}\)

- For germanium:

T = 500K = 227°C

ni = 6.76 x  \(10^{14} cm^{-3}\)

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Answer:

Information technology is important in our lives because it helps to deal with every day's dynamic things. Technology offers various tools to boost development and to exchange information. Both these things are the objective of IT to make tasks easier and to solve many problems.

Answer:

Ashley.... deep drawing

Jack........ blow molding

see picture for the correct answer

The basic requirement of measurements is to have a standard or reference point against which to compare the quantity being measured. This standard or reference point should be well-defined and stable, and the measurement process should be repeatable and consistent. Additionally, it is important to ensure that the measurement equipment is calibrated and in good working condition.

Answer:

The most basic requirement for measurements is the presence of a standard or reference point against which the quantity being measured can be compared. The measurement process should be repeatable and consistent, and the standard or reference point should be well-defined and stable. Furthermore, ensure that the measurement equipment is calibrated and in good working order.

Explanation:

Answer:

Not having enough money to pay to get it fixed

Explanation:

Answer:

1) Not having enough money

2) Not having the transportation to get to the car fixer place

3) Having nobody to watch the kids at home while you go get the cat fixed

When the string of a helium balloon slips from your hand and rises into the air, the balloon rises until it reaches an altitude where its weight equals that of the same volume of air.

When a helium balloon is released, it rises until it reaches an altitude where its weight equals that of the same volume of air. This is due to the principle of buoyancy.

Helium gas is lighter than air, which causes the balloon to initially ascend. As the balloon rises, the surrounding air pressure decreases, and so does the density of the air. Eventually, the balloon reaches an altitude where the density of the surrounding air matches the density of the helium-filled balloon.

At this point, the upward buoyant force acting on the balloon becomes equal to the downward gravitational force (weight) acting on the balloon. This balance of forces causes the balloon to stop rising further and instead float at a relatively stable altitude.

Option c) accurately describes this behavior, where the balloon rises until it reaches an altitude where its weight equals that of the same volume of air.

The question should be:

The string of a helium balloon slips from your hand and rises into the air. when this happens

a) the balloon rises indefinitely because helium is lighter than air

b) the balloon rises until it reaches an altitude where the air and helium densities are equal.

c) the balloon rises until it reaches an altitude where its weight equals that of the same volume of air

d) the balloon rises continually but slows down to the effect of viscosity

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The correct answer is What happens to the average fluid velocity if the fluid's density drops to % of its input value? A) Because it must be, the velocity won't change.

Mean fluid velocity: This parameter is designed to offer the rate of mass flow through the tube, which is the flow of a mass through a surface per unit time (Bergman et al., 2011), when multiplied by the fluid density and the tube's cross-sectional area: (8.11) The analysis of fluid flows using numerical solution techniques is known as computational fluid dynamics (CFD). You can examine intricate issues involving fluid-fluid, fluid-solid, or fluid-gas interaction using CFD. The fluid's flow rate, v, is expressed as a number of metres per second (m/s). The cross-sectional area of the pipe through which fluid is flowing is denoted by the letter A. Typically, it is measured in square metres (m2)

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A pediatrician would use an ophthalmoscope for viewing the interior of the eyes.

Ophthalmoscope is an instrument used by pediatricians and other physicians to examine the interior of the eye.

The ophthalmoscope, an important diagnostic tool in ophthalmology, enables doctors to view the retina, optic disc, macula, and other parts of the eye in detail.

The ophthalmoscope is designed to allow physicians to view the interior of the eye through the pupil. With the help of an ophthalmoscope, doctors can diagnose and monitor a variety of eye disorders, such as glaucoma, cataracts, and macular degeneration.

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A pediatrician is a doctor who specializes in treating babies, toddlers, and children up to the age of 18. Pediatricians are well-equipped to diagnose, treat, and illnesses. Because they deal with such young patients, pediatricians must have access to a variety of specialized medical instruments,

One such instrument is an ophthalmoscope. An ophthalmoscope is a handheld instrument that is used to view the interior of the eye. It allows doctors to examine the retina, optic disc, and other structures of the eye to identify any signs of damage or disease.
Pediatricians might use an ophthalmoscope to diagnose a variety of eye conditions in children. For example, they might use it to look for signs of strabismus (a misalignment of the eyes), cataracts (cloudy areas on the lens of the eye), or glaucoma (increased pressure in the eye that can damage the optic nerve)
In addition to an ophthalmoscope, they might also use other specialized instruments to examine different parts of the eye.

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Bellows, flex pipes, exhaust hangers, and clamps, among other flexible parts, are used to facilitate installation and/or permit expansion and contraction of the exhaust system in response to temperature variations.

1. Slip joints: Slip joints provide a secure connection between the exhaust system's components while allowing the exhaust system to flex and move slightly.

2. Bellows: Bellows are adaptable, accordion-like parts that enable the exhaust system to expand and compress in response to temperature variations.

3. Exhaust hangers: Exhaust hangers are made to absorb vibration and support the exhaust system. They come in a variety of shapes and sizes to match the exhaust system and offer the required support.

4. Flex pipes: Flex pipes join two stiff exhaust components by allowing flexibility. They are made to absorb vibration, lessen noise, and permit exhaust system expansion and contraction.

5. Clamps: Exhaust connections are made using clamps.

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The maximum stresses of the section near the fixed end are Bending stress, -10.16 ksi and Shear stress, 1.89 ksi.

To determine the maximum stresses at a section near the fixed end of the beam, calculate the bending stress and the shear stress.

First, let's find the reactions at the fixed end of the beam. Since the beam is completely fixed, the reactions will be equal and opposite to the applied force, which means:

Rx = -Fx = -400 lb

Ry = -Fy = 300 lb

Rz = -Fz = 1200 lb

Next, calculate the bending moment caused by the applied force. Since the force passes through the centroid of the beam, we can assume that the moment arm is equal to half the depth of the beam, which is 4.055 inches. Therefore, the bending moment at the section near the fixed end is:

M = Fz × 4.055 in = -4875 lb·in

Using the moment of inertia about the x-axis (centroidal-longitudinal axis), calculate the bending stress:

σx = M × (H/2) / Ix = -10.16 ksi

Next, calculate the shear stress using the shear force caused by the applied force. Since there is no other load on the beam, the shear force at the section near the fixed end is equal to the reaction force in the y-direction, which is 300 lb. Using the area of the web, calculate the shear stress:

τ = V × (W × t) / (2 × Iy) = 1.89 ksi

where V is the shear force, W is the width of the web, t is the thickness of the web, and Iy is the moment of inertia about the y-axis (centroidal-vertical axis). Note that we assume the shear stress distribution is uniform across the thickness of the web.

Therefore, the maximum stresses at the section near the fixed end of the beam are:

Bending stress: σx = -10.16 ksi

Shear stress: τ = 1.89 ksi

The bending stress is compressive and larger in magnitude than the yield stress of the material, which means the beam will fail due to bending. The shear stress is relatively small and does not contribute significantly to the failure of the beam.

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Image transcribed:

[8] AW 8x15 I-beam is loaded through the centroid with a force that has the following components:

Fx = 400 lb

Fy=-300 lb

Fz=-1200 lb

The x-axis is the centroidal-longitudinal axis of the beam; the Y-axis is the centroidal-vertical axis along the web and the Z-axis is the centroidal axis parallel to the flanges. The beam is completely fixed at the other end, which is at a distance of 15 in from the point of load application in x- direction. Determine the maximum (critical) stresses at a section near the fixed end. (A W 8X15 beam is a wide flange thin-walled I-beam with the following properties: Area = 4.44 in²

Depth = 8.11 in width = 4.015 in flange thickness = 0.315 in

Web thickness = 0.245 in Ix = 48 in

Iy = 3.4 in¹)

Section has the following properties:

Area = 4.44 in² Depth (H) = 8.11 in

Width (W) = 4.015 in Length (L) = 15 in

Flange thickness = 0.315 in

Web thickness = 0.245 in

1-48 in 13.4 in

Fx=400 lb, Fy=-300 lb, F = -1200 lb

Answer:

class TriangleNumbers

{

public static void main (String[] args)

{

 for (int number = 1; number <= 10; ++number) {

  int sum = 1;

  System.out.print("1");

  for (int summed = 2; summed <= number; ++summed) {

   sum += summed;

   System.out.print(" + " + Integer.toString(summed));

  }

  System.out.print(" = " + Integer.toString(sum) + '\n');

 }

}

}

Explanation:

We need to run the code for each of the 10 lines. Each time we sum  numbers from 1 to n. We start with 1, then add numbers from 2 to n (and print the operation). At the end, we always print the equals sign, the sum and a newline character.

The maximum velocity (u_max) in the parabolic laminar flow is 12 cm/s.

In the problem statement, it is given that the incompressible steady flow is uniform with u = U0 = 8 cm/s in the inlet.

Downstream, the flow develops into a parabolic laminar profile with u = az(z0 - z). The fluid is SAE 30 oil at 20°C, and z0 = 4 cm.

First, we need to find the dynamic viscosity of SAE 30 oil at 20°C. SAE 30 oil has a kinematic viscosity (ν) of approximately 300 cSt (centistokes) at 20°C.

To convert this to dynamic viscosity (μ), we need to multiply by the density (ρ) of the oil:

μ = ν * ρ

The density of SAE 30 oil is approximately 0.89 g/cm³ (890 kg/m³). Since 1 cSt is equal to 1 × 10⁻⁶ m²/s, the kinematic viscosity in SI units is 300 × 10⁻⁶ m²/s.

Now, let's convert the density to SI units:

ρ = 890 kg/m³ = 0.89 g/cm³

Thus, the dynamic viscosity (μ) can be calculated as follows:

μ = (300 × 10⁻⁶ m²/s) * (890 kg/m³) = 0.267 kg/(m*s)

Now, we need to find the maximum velocity (u_max) in the parabolic laminar flow, which occurs at the center of the plates (z = z0/2):

u_max = a * z0/2 * (z0 - z0/2)

Since the flow is incompressible, the mass flow rate (Q) remains constant throughout. We can equate the mass flow rate at the uniform flow (Q_inlet) with the mass flow rate at the parabolic flow (Q_parabolic):

Q_inlet = Q_parabolic

ρ * U0 * A_inlet = ∫[ρ * a * z * (z0 - z) * A_parabolic] dz

The area A_inlet and A_parabolic both can be represented as A = b * z, where b is the width of the parallel plates, and z is the distance between the plates.

Therefore, the equation simplifies to:

U0 * b * z0 = ∫[a * z * (z0 - z) * b] dz, with integration limits 0 to z0

U0 * z0 = ∫[a * z * (z0 - z)] dz, with integration limits 0 to z0

8 cm/s * 4 cm = a * ∫[z * (4 cm - z)] dz, with integration limits 0 to 4 cm

32 cm²/s = a * ∫[4z - z²] dz, with integration limits 0 to 4 cm

Now we can integrate and apply the limits:

32 cm²/s = a * [2z² - (1/3)z³] | (0 to 4 cm)

32 cm²/s = a * [(2 * 4² - (1/3) * 4³) - 0]

32 cm²/s = a * (32 - 64/3)

32 cm²/s = a * (32 - 21.33)

32 cm²/s = a * 10.67 cm²

Now we can solve for 'a':

a = 32 cm²/s / 10.67 cm² = 3 cm/s

Finally, we can find the maximum velocity (u_max) at the center of the plates

Now that we have the value of 'a' (3 cm/s), we can find the maximum velocity (u_max) at the center of the plates (z = z0/2):

u_max = a * z0/2 * (z0 - z0/2)

u_max = 3 cm/s * (4 cm)/2 * (4 cm - 4 cm/2)

u_max = 3 cm/s * 2 cm * 2 cm

u_max = 12 cm/s

Thus, the maximum velocity (u_max) in the parabolic laminar flow is 12 cm/s.

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The capitalized cost of the permanent roadside historical marker is $116,386.30.

Capitalized cost

The capitalized cost is an assessment of the cost of the investment. Capitalized cost is a useful metric in cost accounting, particularly in the case of business assets. In the case of permanent roadside historical markers, we need to calculate the capitalized cost given the first cost and maintenance cost of $90,000 and $3,100 respectively that is done every 5 years.

Assuming the interest rate of 10% per year. We can use the following formula to calculate the capitalized cost.

C = P * (i / (1 - (1 + i)^(-n)))

Where,

C = Capitalized cost

P = First cost

i = Interest rate per year

n = Total number of years

To calculate the capitalized cost of the permanent roadside historical marker, we need to calculate the present value of the investment. We are given that the first cost of the historical marker is $90,000 and the maintenance cost of $3,100 is incurred once every 5 years at an interest rate of 10% per year.

The total number of years n = 20 years (4 maintenance cycles of 5 years each).

Therefore, using the formula, we have,

C = $90,000 + $3,100 * (PVIFA10%,20)

$3,100 * (PVIFA10%,20) = 8.513 (calculated using Excel or tables)

C = $90,000 + $3,100 * 8.513

C = $90,000 + $26,386.30 = $116,386.30.

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Answer:

Plain Sawn. At least 95 percent of all hardwood lumber commercially produced in the U.S. is flat or plain sawn. ...

Quarter Sawn. In this method, the log actually is cut into quarters, then sawn quarter by quarter. ...

Explanation:

He tried to purge the city of the disease-bearing rats.
He tried to purge the city of the disease-bearing rats.

The sentence suggests that the city is facing a problem of disease-bearing rats, and the subject is trying to eliminate them. The word "purge" means to cleanse or eliminate something unwanted, so it fits well in the sentence. An "instigator" is someone who initiates or incites something, such as a riot or a protest. "Refuge" refers to a place of safety or shelter. "Persecution" is the act of mistreating or harassing someone, usually due to their beliefs or opinions. "Tense" refers to a state of nervousness or anxiety, and "bitter" describes a strong and unpleasant taste or emotion.Therefore, the sentence would be correctly written as: "He tried to purge the city of the disease-bearing rats." This suggests that the subject is taking measures to eliminate the rats from the city, which could involve trapping, poisoning, or other methods to control the rat population.

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He tried to purge the city of the disease-bearing rats. The correct word to complete the sentence is "purge."

In this sentence, "purge" means to remove or eliminate something undesirable, in this case, the disease-bearing rats from the city.

The word purge means to get rid of whatever is impure or undesirable; to cleanse; to purify. An example of this word and how it can be used is: to purge a political party of disloyal members.

As a verb, it can be used in the following sentences:

High-ranking officials were purged from the company following the merger.

A day on which the faithful are expected to purge themselves of their sins through prayer and fasting

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Answer:

i play it

Explanation:

Answer:

The engineering design process is a common series of steps that engineers use in creating functional products and processes

The statement is false. Flat head and Phillips-head screwdrivers are not interchangeable with different types of screws. They are designed specifically for their corresponding screw types.

Flat head screwdrivers have a single flat blade, which fits into the single slot on flat head screws. On the other hand, Phillips-head screwdrivers have a cross-shaped tip that fits into the corresponding cross-shaped slot on Phillips-head screws.

Using the wrong type of screwdriver can result in damage to the screw or the screwdriver, making it difficult to properly fasten or remove the screw. It is important to use the appropriate screwdriver for each specific screw type to ensure a secure and effective connection.

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In general, fairness in resource allocation is a fundamental principle in operating systems to ensure equitable access and avoid undue disadvantage to any user or process.

The assertion that none of the disk-scheduling disciplines, except FCFS (First-Come-First-Serve), is truly fair is true because other disk-scheduling algorithms may result in starvation.

It's worth noting that these circumstances are exceptions and typically occur in specialized systems or under specific conditions.

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The network's new capacity is 0.129 m3/s, or 129,000 barrels per day.

In a network that carries fluid, pressure drop is the difference in total pressure between two sites. Pressure drop or pressure loss happens when a liquid material enters one end of a piping system and exits the other.

A fluid carrying network's pressure drop (commonly abbreviated as "dP" or "P") is the difference in total pressure between two sites in the network. When frictional forces brought on by the flow resistance act on a fluid as it passes through a conduit, a pressure decrease happens (such as a channel, pipe, or tube).

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True, General contracting businesses are looking into ways to speed up the building process by altering the way construction is done.

Construction is a broad phrase that refers to the art and science of creating systems, organizations, or items. Its origins are in the Latin construction and Old French construction. The noun construction refers to the process of building something, whereas the verb to construct refers to the act of building. Construction refers to the methods used to create buildings, infrastructure, industrial facilities, and related operations through to the end of their useful lives. Construction normally begins with planning, finance, and design and goes on until the asset is finished and ready for use. It also includes any repairs and maintenance, expansion, extension, and improvement work, as well as the asset's eventual deconstruction, decommissioning, and demolition.

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Answer: hello your question lacks the required diagram attached below is the diagram

answer :  29528.1  N/m^2

Explanation:

Given data :

dimensions of tank :

Length = 5-m

Width = 4-m

Depth = 2.5-m

acceleration of tank = 2m/s^2

Determine the maximum gage pressure in the tank

Pa ( pressure at point A )  = s*g*h1

    = 10^3 * 9.81 * 3.01

    = 29528.1  N/m^2

attached below is the remaining part of the solution