The object that ends up with less electrons has a __________ charge.
A. Positive
B. Not enough info
C. Neutral
D. Negative
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Explanation:

I have a lot to say it was very nice to meet my parents are u doing well I dont want too its been so much I love you so I was like u know I am not a man but you are the auditions I have been in a long long long life is a triangle and a chair for me and my parents think about the way I

Answer:

P.E = 1234.8Joules

Explanation:

Given the following data;

Mass = 42kg

Distance = 3m

We know that acceleration due to gravity is equal to 9.8

To find the gravitational potential energy

P.E = mgh

P.E = 42*9.8*3

P.E = 1234.8Joules

The average speed you must run is 7.97 mph.

The average speed of an object is the ratio of total distance traveled by the object to

Average speed = total distance / total time of motion

Total time of motion = total distance / average speed

total time = (18.5 + 5.5) / (14.5)

total time = 1.66 hours

t1 = 18.5 / 19.1

t1 = 0.97 hour

t2 = 1.66 hr - 0.97 hr

t2 = 0.69 hr

v = 5.5 miles /0.69 hr

v = 7.97 mph

Thus, the average speed you must run is 7.97 mph.

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Answer:

Hello

I think the first one is correct.

Explanation:

Answer:

Inner planets rotate slowly and so they take more time to complete a rotation. Whereas, outer planets rotate faster and so they take less time to complete a rotation.

Explanation:

The inner planets are the ones that are much closer to the sun and as such they have much smaller orbits around them and take much less time to circle around it. These planets are much smaller, which enables them rotate slowly, so they take more time to complete a rotation..

Whereas, the outer planets differ from the inner planets in that they are much further from the sun and so take much more time for them to be able to make a single circle around the su and also, because they are much bigger, it takes them much more time to spin around their own axis, thus Outer planets rotate faster, so they take less time to complete a rotation

Answer:

65 miles per hour

Explanation:

Speed= Distance/Time

Following this formula, we just need to insert the values.

The distance is 125 miles and the time is 2 hours

125=2=65

65 miles per hour

The speed of the car was exactly 125 mi per 2 hours.

In a more familiar unit,  125mi/2hr = 62.5 mi/hr.

C) a bicyclist riding up a steep hill

The metaphor for a system with rising gravitational potential energy is "a bicyclist riding up a steep hill." Let's get into greater detail:

A cyclist faces resistance from gravity as they ride up a steep slope. The cyclist's elevation, or height above the ground, rises as they cycle and climb uphill. Gravity is pulling the cyclist down the hill by exerting downward force. The cyclist must apply force to the pedals in order to move forward and overcome the pull of gravity. In order to do this, the bicyclist must transform chemical energy from their body into mechanical energy. The distance of the cyclist from the centre of the Earth grows as they ride up the hill. The height and mass of an object affect its gravitational potential energy. In this scenario, as the bicyclist's height rises, their gravitational potential energy also rises.

     Due to the higher elevation, the energy input from the biker is stored as increased potential energy. When the bicycle descends the hill or does work, this potential energy can be transformed back into kinetic energy or other types of energy.

Answer:

The acceleration due to gravity at the location of the pendulum is 34.74 m/s².

Explanation:

Given that,

The length of a simple pendulum, l = 5.5 m

It makes 10.0 complete swings in 25 s.

Frequency of pendulum,

\(f=\dfrac{10}{25}\\\\f=0.4\ Hz\)

The time period of a simple pendulum is given by :

\(T=2\pi \sqrt{\dfrac{l}{g}}\)

Frequency,

\(f=\dfrac{1}{T}\\\\f=\dfrac{1}{2\pi \sqrt{\dfrac{l}{g}} }\\\\f=\dfrac{1}{2\pi}\sqrt{\dfrac{g}{l}}\)

g is the acceleration due to gravity at the location where the pendulum is placed. So,

\(f^2=\dfrac{g}{4\pi^2l}\\\\g=f^2\times 4\pi^2l\\\\g=0.4^2\times 4\pi^2\times 5.5\\\\g=34.74\ m/s^2\)

So, the acceleration due to gravity at the location of the pendulum is 34.74 m/s².

The time between when the bat emits the sound and when it hears the echo is 0.05 s

From the question given above, the following data were obtained:

Velocity of sound (v) = 343 m/s

Distance (x) = 8.42 m

We can obtain obtained the time as illustrated below:

v = 2x / t

343 = 2 × 8.42 / t

343 = 16.84 / t

Cross multiply

343 ×  t = 16.84

Divide both side by 343

t = 16.84/343

Thus, the time between  when the bat emits the sound and when it hears the echo is 0.05 s

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Answer:

0.0491

Explanation:

Answer:

Speed, Vfx = 7.619 m/s

Explanation:

Vertical distance, Dx = 5.4m

Horizontal distance, Dy = 8m

Acceleration due to gravity, g = 9.8m/s²

Initial speed, Vix = 0m/s²

To find the speed, we would use the second equation of motion to find the time, t;

Dx = Vixt + ½gt²

Substituting into the equation, we have;

5.4 = 0(t) + ½(9.8)*t²

5.4 =  0 + 4.9t²

Rearranging the equation, we have;

4.9t² = 5.4

t² = 5.4/4.9

t² = 1.1020

Taking the square root of both sides;

t = 1.050 secs.

For the speed;

Dy = Vfxt

Vfx = Dy/t

Vfx = 8/1.050

Vfx = 7.619 m/s

Therefore, the speed of the pelican is 7.619 m/s

The half-life of hypothetical element  technetium-99 is 210,936 years.

Half-life of the hypothetical element From the graph provided in the question, the half-life of the hypothetical element can be obtained by finding the time taken for the element to reduce to half its original quantity. Here, it can be seen from the graph that the quantity of the element reduces from 40 to 20 on day 4. Therefore, the half-life of the hypothetical element is 4 days.2. Time taken for a sample to decay from 100 grams to 25 gramsIf the half-life of a given substance is 65 days, then the quantity of the substance reduces to half every 65 days. From 100 grams to 50 grams, it takes one half-life cycle. From 50 grams to 25 grams, it will take another half-life cycle.

Therefore, it will take two half-life cycles, which is 2 × 65 = 130 days, for a 100-gram sample of the substance to decay until there is only 25 grams of the radioactive material remaining.3. Half-life of a sample that decays from 200 grams to 50 grams in 60 minutesIt is given that the sample of radioactive isotopes takes 60 minutes to decay from 200 grams to 50 grams. To find the half-life, we need to determine how many times the sample has lost half of its mass, which tells you how many half-life cycles have occurred.At 30 minutes, the sample reduces to half its original quantity, which is 100 grams. At 45 minutes, it reduces to 50 grams, which is half of 100 grams. Therefore, it takes two half-life cycles to reduce from 200 grams to 50 grams in 60 minutes. Hence, the half-life of the isotope is 15 minutes.4. Half-life of technetium-99 that decays from 500.0 g to 62.5 g in 639,000 yearsIt is given that a 500.0 g sample of technetium-99 decays to 62.5 g of technetium-99 remaining in 639,000 years. We can use the half-life formula to find the half-life of technetium-99.t1/2 = (t × log2) / log(N0 / Nt) Where,t1/2 = half-life of the substanceN0 = initial quantity of the substance Nt = quantity of the substance left after time t (in years)t = time (in years)From the given data,t1/2 = (639000 × log2) / log(500.0 / 62.5)t1/2 = 210,936 years.

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Answer:

be patent beacause sabar ka fal metha hota h

everyone knos it

Energy can neither be created nor destroyed. It can be converted from one form to another. The total energy before and after conversion remains the same. The Law of Conservation of Energy is universal.

The law of energy conservation says that energy can be transformed from one type to another type, for example, if a ball is thrown upward the kinetic energy as the ball goes upward decreases, and the potential energy increases.

Energy conversion is the process by which energy is changed from forms supplied by nature to forms used by people.

For this goal, a huge variety of tools and systems have been created over the years. A few of these energy converters are really straightforward. Early windmills, for instance, used wind's kinetic energy to drive machinery that pumped water and ground grain.

A body's kinetic energy was thought to be transformed into potential energy as it slowed down while moving upward against the pull of gravity.

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Option B

Explanation:

no distance was given only the acceleration due to the fact that it went up (10m/s/s)

s0 it is

0 m/s and 10m/s/s (option B)

Answer:

6768 Joules (J)

Explanation:

kinetic energy = 1/2mv^2

1/2 (94x12^2) = 6768

Answer:

Explanation:

2.0 × 10^3 is the correct form for writing any term in scientific notation form.

Comment for understanding anything.

Answer:

As in chemical formula? It's CH4.

1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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Answer:

138.6 megacalculations

Explanation:

This is a pretty straightforward one.

All it needs is to convert the degree of measurement.

Dimensions in physics are attributed names, which state the power to which they're are raised. Just as how

Kilo and Mega means the numbers are raised to the power of 3 and 6 respectively. There also exists the ones that indicates how small, such as milli and micro, which are to the powers of -3 & -6.

The question says the IBM computer calculates at an astonishing 136.8 teracalculations.

Tera in physics means it's raised to the power of 12. Thus, the IBM calculates at an astonishing rate of

136.8*10^12 calculations per second.

We're then asked how many calculations it does in 1 micro second. Like I had highlighted earlier, 1 micro second is 1 raised to the power of -6. Or succinctly put,

1 micro second = 1*10^-6.

If the IBM does

138.6*10^12 = 1 second,

Then it does

x = 1*10^-6 second.

When we cross multiply, we have

138.6*10^12 * 1*10^-6, and that is

138.6*10^6 calculations, or say, 138.6 megacalculations.

The IBM does 138.6 megacalculations in 1 micro second, which is still astonishing, by the way

The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.

Given:

Object height (h) = 5 cm

Focal length of the convex lens (f) = 10 cm

Object distance (u) = 15 cm (positive since it's on the same side as the incident light)

To determine the nature, position, and size of the image, we can use the lens formula:

1/f = 1/v - 1/u

Substituting the given values:

1/10 = 1/v - 1/15

To simplify the equation, we find the common denominator:

3v - 2v = 2v/3

Simplifying further:

v = 30 cm

The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.

To find the magnification (M), we use the formula:

M = -v/u

Substituting the values:

M = -30 / 15 = -2

The magnification is -2, indicating that the image is inverted and twice the size of the object.

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False, supposedly when a hurricane moves ashore, it quickly rises due to friction and a lack of warm, moist air.

Hurricanes are known as cyclones as well as typhoons in other tropical regions. Typhoons are one of the most disturbing types of natural disasters at the moment.

Scientifically, the cause of hurricanes from warm water, warm moist air, and light upper-level winds as the primary ingredients of their formation.

Typhoons have other terms, depending on where they occur. the scientific term for a hurricane is a tropical cyclone. Only tropical cyclones that form over the Atlantic Ocean or the eastern Pacific Ocean are called "hurricanes".

The cause of a hurricane occurs when a warm, moist air mass from the sea surface begins to rise rapidly and collides with a colder air mass. The friction pushes the warm water vapor to condense. During the condensation process, latent heat is emitted.

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Answer:

1 km

Explanation:

displacement =velocity ×time

displacement =40m/s ×25s

displacement =1000m equivalent to 1km

Answer:

ac = 204 [m/s²]

Explanation:

To solve this problem we must use the following equation that relates the tangential velocity to the radius of rotation.

ac = v²/r

where:

v = tangential velocity = 15 [m/s]

r = radius = 1.1 [m]

Now replacing we have:

ac = (15)²/1.1

ac = 204 [m/s²]

Answer:

e

Explanation:

From the given information:

Suppose Q = total charge of the sphere.

here, the electric field outside the sphere at distance R/2 can be expressed as:

\(E_1 = \dfrac{1}{4 \pi \varepsilon _o}* \dfrac{Q}{(R + \dfrac{R}{2})^2}\)

where:

\(k = \dfrac{1}{4 \pi \varepsilon _o}\)

\(E_1 = \dfrac{kQ}{(\dfrac{3R}{2})^2}\)

\(E_1 = \dfrac{4kQ}{9R^2}\)

For the electric field inside the sphere, we have:

\(E_2 = \dfrac{kQr}{R^3}\)

here:

r = distance of the point from the center = R/2

R = radius of the sphere

∴

\(E_2 = \dfrac{kQ * \dfrac{R}{2}}{R^3}\)

\(E_2 = \dfrac{kQ }{2R^2}\)

As such, the ratio of the electric field outside the sphere to the one inside is:

\(\dfrac{E_1}{E_2} = \dfrac{ \dfrac{4kQ}{9R^2}}{ \dfrac{kQ }{2R^2}}\)

\(\dfrac{E_1}{E_2} = \dfrac{4kQ}{9R^2} \times \dfrac{ 2R^2 }{kQ}\)

\(\mathbf{\dfrac{E_1}{E_2} = \dfrac{8}{9}}\)

For a solid uniformly charged sphere of radius R, the electric field at a distance R/2 outside the sphere, divided by the electric field at a distance R/2 inside the sphere is -  e) 8/9

field  \(E2= \frac{k(Q)}{(3R/2)^2}\)

=  \(\frac{4}{9} \frac{k(Q)}{R^2}\)

=

Thus, E2/E1

= (4/9)/(1/2)

= 8/9

Thus, the electric field at a distance R/2 outside the sphere, divided by the electric field at a distance R/2 inside the sphere is -  8/9

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Answer:

The dust does have any third charge.

Explanation:

                In the context, the glass rod gets positively charged and so it induces a negative charge on the dust particles which are neutral. Thus the face of the dust particle which is near to the rod becomes negative charge and the opposite face of the dust gets equal positive charge and hence it ensures the neutrality of the dust particle but still being attracted to the glass rod.

               And in the case of the negatively charged silk, the silk induces or gives positive charge to the dust particle which is neutral in charge. The face which is near to the silk gets positive charge and the other face becomes negative charge, again ensuring its neutrality and being attracted to the glass rod.

               This shows how both positive charged rod and negatively charged silk attracts the neutral dust particle.

Answer:

The answer is Less.

Explanation:

The further you are away from a light source, the less intense the light appears.

Answer: a or b can u pls give me brainlest

Explanation:A straight line is a curve with constant slope. Since slope is acceleration on a velocity-time graph, each of the objects represented on this graph is moving with a constant acceleration.