The linear equation y=-2 is a horizontal line and has an undefined slope true or false

Answer:

4x + 5y = 20

Step-by-step explanation:

It is parallel to y = -4/5x + 6

Answer: 1,400,000,000

Step-by-step explanation:

1.386 billion =  1,386,000,000

Now we want to round this to the nearest hundred million (it is the 9th digit counting from right to left).

To round, we need to look at the digit at the right ( the 8th in this case)

If that digit is equal or larger than 5, then we round up. (we add 1 to the 9th decimal in this case)

If that digit is smaller than 5, we round down.

In this case, the 8th digit is an 8, this is larger than 5, then we round up.

1,386,000,000 ≈ 1,400,000,000

Answer:

c. 4

Step-by-step explanation:

tan (30)/1 = x/7 *cross multiply*

x = 7 (tan(30))

x = 4.04

x = 4

On solving the provided question, we can say that Therefore, the function has an average rate of change of -1.

The subject of mathematics includes quantities and their variations, equations and related structures, shapes and their locations, and places where they can be found. The term "function" refers to the relationship between a set of inputs, each of which has an associated output. A connection between inputs and outputs in which each input leads to a single, distinct result is known as a function. Each function is given a domain and a codomain, or scope. Usually, f is used to denote functions (x). input is an x. There are four main types of functions accessible. based on the following factors: on functions, one-to-one functions, many-to-one functions, inside functions, and on functions.

The function has an average rate of change of -1.

R = 4-5/1-0

R = -1

Therefore, the function has an average rate of change of -1.

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the distance is 50 inch

now we convert it into the yards

we know that

1 inch = 0.0277 yards

so in 50 inches

50 x 0.0277 = 1.38 yards or

we can write the snail moved 1 yard. after rounding off 1.38

Answer:

3000

Step-by-step explanation:

100%-> 5000

60%->3000

tan D = 7/4

sin D = 0.864

cos D = 0.494

Tan ratio = opposite/adjacent

opposite = side opposite the angle D = 7

adjacent = base = 4

tan D = 7/4

sin ratio = opposite/hypotenuse

hypotenuse = 8.1

sin D= 7/8.1

sin D = 0.8642

To the nearest thousandth, sin D = 0.864

cosine ratio = adjacent/hypotenuse

cos D = 4/8.1

cos D = 0.4938

To the nearest thousandth, cos D = 0.494

The surface area of the cylinder is 113.04cm²

The surface area of a cylinder can be defined as the amount of space covered by the flat surface of the bases of the cylinder and the curved surface of the cylinder.

The total surface area of the cylinder includes the area of the 2 bases of the cylinder which are in the shape of a circle and the area of the curved surface.

Therefore the surface area of a cylinder is 2πr(r+h)

where r is the radius and h is the height

= 2×3.14×3(3+9)

= 18.84×12

= 226.08cm²

therefore the surface area of the cylinder is 226.08cm²

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The slope y is 3x - 10.When the line to be examined's slope is known, and the provided point also serves as the y intercept.

When the line to be examined's slope is known, and the provided point also serves as the y intercept, the slope intercept formula, y = mx + b, is utilized (0, b). B stands in for the y value of the y-intercept point in the formula.

According to question:-

In the equation of a line's slope-intercept form, y = mx + b, we get y = 3x + 2, m1 = m2 gives us y = 3x +2, and m = 3 gives us the point (2 -4) where x = 2 and y = -4.

4 6 + b deducts 6 from both sides.

-10 = b, b = -10

After all, y = 3x - 10.

The complete question is,

y=3x+2 via (2,-4) parallel to

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The expression for the volume of the cylinder is:

\(v = 3.14*(9in)^2*h\)

For a cylinder of radius r and height h, the volume is:

\(v = 3.14*r^2*h\)

Where 3.14 = π

Here we know that the diameter is 18 inches, then the radius is half of that, we will have:

r = 18in/2 = 9in

Then the volume equation is:

\(v = 3.14*(9in)^2*h\)

So the correct option is the first one.

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Answer:

first what the full question and if 25*16/2=200

Step-by-step explanation:

Answer:

¿Cuál es la probabilidad de aprobar un examen al azar?

Resultado de imagen para ¿Cuál es la probabilidad de adivinar correctamente al azar exactamente una respuesta correcta?

La probabilidad de acertar respondiendo al azar una pregunta es de una entre cuatro: 1/4 = 0.25. Normalmente decimos un 25% de probabilidad de acertar. La probabilidad de fallar sería tres entre cuatro: 3/4 = 0.75. O sea un 75%.

Step-by-step explanation:

this is the best ✔️ 5+(2-3)49_.56837659=0-9

Step-by-step explanation:

0 upto 9

Answer:

40x+24y-56=

8(5x+2y-7)

Step-by-step explanation:

Answer:

32

Step-by-step explanation:

To solve, simply put 4 in place of x. 8 times 4 is 32

Since means cannot be smaller than 0, the sampling distribution of the mean is always right skewed.

No matter the sample size, the form of the sampling distribution of means is always the same as the population distribution.

We require two assumptions in order to apply the sampling distribution model to sample proportions: The selected values must be independent of one another, according to the independence assumption. The Sample Size Assumption demands that the sample size, n, be sufficiently large.

While doing a t-test, it is typical to make the following assumptions: the measuring scale, random sampling, normality of the data distribution, sufficiency of the sample size, and equality of variance in standard deviation.

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the actual question is :

Which of the following is true about the sampling distribution of the mean?

a. It is an observed distribution of scores

b. It is a hypothetical distribution

c. It will tend to be normally distributed with a

standard deviation equal to the population

standard deviation

d. The mean will be estimated by the standard

error

e. Both (a) and (b)

Answer:

if you meant y^8*y^2 then y^10 if you meant 8y*2y then 16y^2

Yes, quadrilaterals ABCD and EFGH are similar because a translation of (x + 1, y + 3) and a dilation by the scale factor of 3 from point D′ map quadrilateral ABCD onto EFGH.

The properties of quadrilaterals are;

From the information given, we can see that;

ABCD and EFGH are similar because a translation of (x + 1, y + 3) and a dilation by the scale factor of 3

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Answer:

hewo

Step-by-step explanation:

well you need to multiply 1/4*114 and that should give you your answer

which would be 28.5

The required volume of the given rectangular prism is given as 240 in ³.

Volume is defined as the mass of the object per unit density while for geometry it is calculated as profile area multiplied by the length at which that profile is extruded.

Here,
From the data we have,
Length of the rectangle prism = 12 in
Width of the rectangle prism = 2 in
Height of the rectangle prism = 10 in

The volume of the rectangular prism = length × width × height
                                                 = 12 × 2 × 10
                                                 = 240 in ³

Thus, the required volume of the given rectangular prism is given as 240 in ³.

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The question is incomplete.
Complete question is," Calculate the volume of the prism of dimensions length, width and height are 12, 2, and 10 respectively. "

Answer:

b=0

Step-by-step explanation:

The weight on the inflation gap has increased from 0.5 to 0.75. The real interest rate is 16.86% and Nominal interest rate is 20%

a. In the base scenario, the real interest rate will be 20%, and the nominal interest rate will be 20%.

b. In scenario B, inflation rate will be higher (4%) compared to the base scenario (3.14%).

Output gap is 0% in both the scenarios, however, in the base scenario inflation gap is 0% (3.14 - 3.14) and in scenario B, inflation gap is 0.86% (4 - 3.14).

Now, let's calculate the real interest rate.

Real interest rate in base scenario = 20% - 3.14%

= 16.86%.

Real interest rate in scenario B = 20% - 3.14% + 1.5 + 0.5 (4-3.14) + 0.5 (0-0/0)

= 19.22%.

The real interest rate has moved in the direction to move inflation rate towards its target.

c. In scenario C, the output gap will be 20% compared to 0% in the base scenario.

Inflation gap is 0% in both the scenarios

Inflation rate is 3.14% and in scenario C, inflation rate is 2%.

Let's calculate the real interest rate. Real interest rate in the base scenario = 20% - 3.14%

= 16.86%.

Real interest rate in scenario C = 20% - 2% + 1.5 + 0.5 (3.14 - 3.14) + 0.5 (20-0/20)

= 20.15%.

Real interest rate in scenario C = 20% - 2% + 1.5 + 0.75 (3.14-3.14) + 0.25 (20-0/20) = 18.78%.

The new policy rule has changed the weight of the output gap in the Taylor Rule from 0.5 to 0.25.

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Answer:

-3/1

Step-by-step explanation:

Hope that helps :)

Answer:

Faye has $3,000 that she is going to deposit into each of the two accounts as shown:

•Account A: 5% simple interest for 5 years

•Account B: will earn $828.84 over 5 years

Assuming Faye does not make any additional deposits nor withdrawals, find t combined amount of her two accounts after 5 years.

Step-by-step explanation:

sub to sir sir bmgo ΔΔ

Answer:

\(\displaystyle \frac{\pi(5e^4+8e^2-1)}{2e^4}\approx9.526\)

Step-by-step explanation:

This can be solved with either the washer (easier) or the shell method (harder). For the disk/washer method, the slice is perpendicular to the axis of revolution, whereas, for the shell method, the slice is parallel to the axis of revolution.  I'll show how to do it with both:

Shell Method (Horizontal Axis)

\(\displaystyle V=2\pi\int^d_cr(y)h(y)\,dy\)

Radius: \(r(y)=2-y\) (distance from y=2 to x-axis)

Height: \(h(y)=2-(-\ln y)=2+\ln y\) (\(y=e^{-x}\) is the same as \(x=-\ln y\))

Bounds: \([c,d]=[e^{-2},1]\) (plugging x-bounds in gets you this)

Plugging in our integral, we get:

\(\displaystyle V=2\pi\int^1_{e^{-2}}(2-y)(2+\ln y)\,dy=\frac{\pi(5e^4+8e^2-1)}{2e^4}\approx9.526\)

Washer Method (Parallel to x-axis)

\(\displaystyle V=\pi\int^b_a\biggr(R(x)^2-r(x)^2\biggr)\,dx\)

Outer Radius: \(R(x)=2-e^{-x}\) (distance between \(y=2\) and \(y=e^{-x}\))

Inner Radius: \(r(x)=2-1=1\) (distance between \(y=2\) and \(y=1\))

Bounds: \([a,b]=[0,2]\)

Plugging in our integral, we get:

\(\displaystyle V=\pi\int^2_0\biggr((2-e^{-x})^2-1^2\biggr)\,dx\\\\V=\pi\int^2_0\biggr((4-4e^{-x}+e^{-2x})-1\biggr)\,dx\\\\V=\pi\int^2_0(3-4e^{-x}+e^{-2x})\,dx\\\\V=\pi\biggr(3x+4e^{-x}-\frac{1}{2}e^{-2x}\biggr)\biggr|^2_0\\\\V=\pi\biggr[\biggr(3(2)+4e^{-2}-\frac{1}{2}e^{-2(2)}\biggr)-\biggr(3(0)+4e^{-0}-\frac{1}{2}e^{-2(0)}\biggr)\biggr]\\\\V=\pi\biggr[\biggr(6+4e^{-2}-\frac{1}{2}e^{-4}\biggr)-\biggr(4-\frac{1}{2}\biggr)\biggr]\)

\(\displaystyle V=\pi\biggr[\biggr(6+4e^{-2}-\frac{1}{2}e^{-4}\biggr)-\frac{7}{2}\biggr]\\\\V=\pi\biggr(\frac{5}{2}+4e^{-2}-\frac{1}{2}e^{-4}\biggr)\\\\V=\pi\biggr(\frac{5}{2}+\frac{4}{e^2}-\frac{1}{2e^4}\biggr)\\\\V=\pi\biggr(\frac{5e^4}{2e^4}+\frac{8e^2}{2e^4}-\frac{1}{2e^4}\biggr)\\\\V=\pi\biggr(\frac{5e^4+8e^2-1}{2e^4}\biggr)\\\\V=\frac{\pi(5e^4+8e^2-1)}{2e^4}\approx9.526\)

Use your best judgment when deciding on what method you use when visualizing the solid, but I hope this helped!

\(\longrightarrow \sf 75+ 30(h-1) \)

Given that :-

\(\leadsto\)Remaining hours for which the job will last after first hour= (h-1)

Therefore,

Cost for subsequent hours = 30×(h-1)

= 30(h-1)

Total Cost for job = Cost for 1st hour + Cost for subsequent hours

\(\quad\quad\quad\quad\quad\quad\quad\quad\boxed{\sf{= 75+30(h-1)}}\)

Comparing the box-and-whisker plots for both data of each city, we have:

a. City B had more noon temperatures above 76°F

b. Both had the same interquartile range.

c. City B had a larger median noon temperature

d. City A had the largest noon temperature.

The box-and-whisker plot has the following values it displays about a data distribution:

Interquartile range = Q3 - Q1

Analyzing the box-and-whisker plots given above, we have the following to conclude:

a. City B had more noon temperatures above 76°F because about more than 50% of the data are above 76°F.

b. Interquartile range for City A = Q3 - Q1 = 75 - 68 = 7

Interquartile range for City B = Q3 - Q1 = 80 - 73 = 7

Both had the same interquartile range.

c. Median for City A = 70

Median for City B = 78

City B had a larger median noon temperature

d. City A had the largest noon temperature of 85.

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The 90% confidence interval estimate of the mean net change in LDL cholesterol after garlic, using the t-distribution, is of:

(-1.14, 8.14).

Since the lower bound of the interval is negative, there is no guarantee of the effectiveness of the method.

The t-distribution is used when the standard deviation for the population is not known, only for the sample.

The bounds of the confidence interval are given according to the rule presented below:

\(\overline{x} \pm t\frac{s}{\sqrt{n}}\)

In which the variables of the equation are described as follows:

The critical value, using a t-distribution calculator, for a two-tailed 90% confidence interval, with 43 - 1 = 42 df, is t = 1.6820.

The values of the other parameters are defined as follows:

\(\overline{x} = 3.5, s = 18.1, n = 43\)

Then the lower bound of the confidence interval is calculated as follows:

\(\overline{x} - t\frac{s}{\sqrt{n}} = 3.5 - 1.682\frac{18.1}{\sqrt{43}} = -1.14\)

The upper bound of the confidence interval is calculated as follows:

\(\overline{x} + t\frac{s}{\sqrt{n}} = 3.5 + 1.682\frac{18.1}{\sqrt{43}} = 8.14\)

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